The Density of rock=(6315 kg/m^3)
It is a universal fact that the mass of an object remains constant whether measured on earth or on the moon.
Mass of rock on moon/earth = 7.2
Loss in weight =7.02 - five.88 = 1.14 kg = 1140g
As we know that water has a density of 1g/cm^3 (1000kg/m^3)
The volume of water = volume of the rock
= Mass/density;
=1140 cm^3
density of rock = mass/extent = 7200/1140 = 6.315 g/cm^3
Density of rock=(6315 kg/m^3)
Density (volumetric mass density or particular mass) is the substance's mass in line with a unit of extent. The symbol most usually used for density is ρ (the decreased case Greek letter rho), despite the fact that the Latin letter D also can be used. Mathematically, density is described as mass divided with the aid of volume.
The density of fabric varies with temperature and stress. this variation is usually small for solids and drinks but a whole lot greater for gases. increasing the strain on an object decreases the quantity of the object and therefore will increase its density. increasing the temperature of a substance (with some exceptions) decreases its density via increasing its quantity. In most materials, heating the bottom of fluid outcomes in convection of the warmth from the bottom to the pinnacle, due to the lower density of the heated fluid, which motivates it to rise relative to denser unheated material.
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Complete question:
A geologist finds that a moon rock whose mass is 7.2 kg has an apprant mass 5.88kg when submerged in water what is the density of rock.
what is the charge of an electron in coulombs
Answer:
1.60217662 × 10(-19) coulombs
Ano ang mangyayari kung hindi mo gagamitin ang iyong talento?
Answer:
mas lalo kang tinatamaran magaral
PLEASE HELP
Which is not an accurate statement about Earth's gravitational pull?
A) Earth's gravitational pull helps keep it in orbit.
B) Earth's gravitational pull is the same as Jupiter's gravitational pull.
C) Earth's gravitational pull is 9.8 m/s2.
D) Earth's gravity helps keep people from floating outside of the planet.
The definition of agility
7. When the arm of force
the arm of resistance, the lever doesn't
conserve effort.
a. is shorter than b. is longer than c. equals d. (a) and (c)
Answer:it B
Explanation:I took the test
Is frictional force the only example of non-conservative force?
Answer: NO, there are many examples of non-conservative forces.
Explanation: Conservatives forces are special forces whose work is zero in a closed path.
Magnetic and Electric fields are Non- Conservative.Which one of the pulley systems below has the best force advantage?Select one:a. Pulley Ib. Pulley IIc. Pulley IIId. The force advantage is the same.
a. Pulley I
Explanation
A pulley system is a collection of one or more wheels which are used with a. rope or chain to make it easier to lift things, The main advantage in the use of pulleys is that the effort becomes less as compared to the normal lifting of the weights
the ideal mechanical advantage is equal to the number of rope segments pulling up on the object. The more rope segments that are helping to do the lifting work, the less force that is needed for the job.
so
Step 1
let's check the number of pulleys on each system
so, the firs system has the more rope segements pulling up (4)
therefore, the answer is
a. Pulley I
I hope this helps you
Two cars, one of mass 1400 kg, and the
second of mass 2300 kg, are moving at right
angles to each other when they collide and
stick together. The initial velocity of the first
car is 14 m/s in the positive r direction and
that of the second car is 20 m/s in the positive
y direction.
What is the magnitude of the velocity of the
wreckage of the two cars immediately after the
collision?
Answer in units of m/s.
es
Suppose that, in the x-y plane, the first car is moving to the right so that its velocity is given by the vector
v₁ = (14 m/s) i
and the second car is moving upward so that its velocity vector is
v₂ = (20 m/s) j
Then the total momentum of two cars before their collision is
m₁v₁ + m₂v₂ = (1400 kg) (14 m/s) i + (2300 kg) (20 m/s) j
= (19,600 i + 46,000 j) kg•m/s
Their momentum after the collision is
(1400 kg + 2300 kg) v = (3700 kg) v
where v is the velocity vector of the wreckage.
By conservation of momentum,
(19,600 i + 46,000 j) kg•m/s = (3700 kg) v
Let a and b be the horizontal and vertical components of v, respectively. Then
19,600 kg•m/s = (3700 kg) a ⇒ a ≈ 5.2973 m/s ≈ 5.3 m/s
46,000 kg•m/s = (3700 kg) b ⇒ b ≈ 12.4324 m/s ≈ 12 m/s
so that the final speed of the wreckage is
||v|| = √(a² + b²) ≈ 13.5139 m/s ≈ 14 m/s
A student makes the argument that light travels faster in the glass block than the air surrounding it. The student explains that the angle between the edge of the block and the ray of light is bigger in the glass than it is in the air, and a bigger angle is associated with a higher speed . Is he correct or not and why ?
Light travels faster in air than in glass because air is an optically rarer medium.
Speed of light?The term speed of light refers to the speed with which light travels through diverse materials. We know that light travels faster in air than in glass owing the the difference in the nature and composition of the two materials.
Hence, the explanation of the student concerning the differences in angles does not account for the differences in the speed of light in materials. Light travels faster in air than in glass because air is an optically rarer medium.
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when energy is transferred from one part of a system to another, some of the energy is lost during the transfer and cannot be used as it was intended. Which two sentences describes examples of this?
Sentences A and D describe examples of energy transformation.Heat is produced when a car's tires rub against the pavement and as electricity passes across power wires, they become hotter.
What is the law of conservation of energy?According to the law of conservation of energy, the energy of an isolated system stays unchanged throughout time.it is said to be conserved.
Energy cannot be created nor destroyed and can be transferred from one form to the other form.
The complete question is
"When energy is moved from one component of a system to another, some of the energy is lost and cannot be used as planned.
Which two statements provide examples?
A. Friction between a car's tires and the road produces heat.
B. Sunlight strikes a solar panel, generating electricity.
c. Stereo speakers emit a sound when powered by electrical energy,
D. Wind moves a turbine, generating electricity.
I E. Power lines heat up as electricity flows through them."
Some of the energy wasted during the movement of energy from one section of a system to another is heat is produced by friction between a car's tires and the road and as electricity passes via power lines, they heat up.
Hence, sentences A and D describe examples of energy transformation.
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What particles are considered to be the basic building blocks of elements?
Answer:
Atoms.
Explanation:
The fundamental structure obstructs that make matter are called molecules. What are the various particles found in iotas? (Reply: electrons, protons and neutrons) Where are they found? (Reply: Protons and neutrons are found in the core, and electrons are found in shells around the outside of the core.)
Really hope this helps! :D
Explanation:
The basic components of matter are called atoms. What are the various particles present in an atom?
(Answer: electrons, protons, neutrons) Where are they? (Answer: Protons and neutrons are in the nucleus, and electrons are in the shell around the nucleus.)
Find the acceleration due to gravity on planet Fergie which has a mass of 6.23 * 10^23 kg and a radius of 5.79* 10^7 m
Answer:
The acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.
Explanation:
We want to find the acceleration due to gravity on the planet Fregie. Let it be g m/s^2.
Now, the acceleration due to gravity is defined through the following equation:
\(mg = GMm/R^2\)
where m is the mass of an object on the surface of the planet, M is the mass of the planet, R is the radius of the planet, and G is the universal Gravitational constant.
Subsituting values for M = 6.23*10^23, R = 5.79*10^7, G = 6.67*10^(-11), we get
g = 0.0123 m/s^2.
Thus the acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.
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A 0.0400 kg meter stick is placed on a thin rod at the 30.0 cm mark. What is the minimum mass required to be placed on the 0.00 cm mark on the stick to maintain equilibrium?
Answer in kg
The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.
To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:
τ = r * F * sin(θ)
where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.
In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.
Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:
τ_M = r_M * F_M * sin(θ)
where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.
Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:
τ_M = τ_stick
r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)
Substituting the given values:
30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)
Solving for F_M:
F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)
F_M = 0.0264 kg * 9.8 m/s^2
F_M = 0.25872 N
Finally, we can convert the force into mass using the formula:
F = m * g
0.25872 N = M * 9.8 m/s^2
M = 0.0264 kg
Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.
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3,000 times , 1,000 times 300,000
3,000 x 1,000 x 3,000 =
FMultiply the whole numbers:
An object moving at a constant velocity of 5.4 m/s travels for 12 s. How far will it move during that time?x = xo + vo t + ½ a t 2 g = 9.8 m/s2 (downward)
An object moving at a constant velocity of 5.4 m/s travels for 12 s.
How far will it move during that time?
Recall that the velocity, distance, and time are related as
\(\begin{gathered} v=\frac{s}{t} \\ s=v\cdot t \end{gathered}\)Where s is the horizontal distance, v is the velocity, and t is the time.
Let us substitute the given values and find the distance (s)
\(\begin{gathered} s=5.4\cdot12 \\ s=64.8\; m \end{gathered}\)Therefore, the object will move 64.8 m during 12 s.
This glass of lemonade is sitting in the hot summer sun. As time passes, in which direction will heat transfer take place?
The heat transfer takes place from the Ice to lemonade (ice → lemonade).
What is heat transfer?The term “heat transfer” refers to the movement of heat. The flow of heat across a system's boundary is due to a temperature differential between the system and its surroundings.
When a temperature difference exists between states of matter, heat transfer happens solely in the direction of decreasing temperature, that is, from a hot object to a cold item.
The temperature of ice is increasing while the lemonade is decreasing. Heat transfer happens solely in the direction of decreasing temperature,
Hence, the heat transfer takes place from the Ice to lemonade (ice → lemonade.
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Answer: C
Explanation:
In order to train astronauts to get used to the accelerations they experience during space shuttle launches, they must ride around in a centrifuge to experience accelerations of up to 100 m/s2. If a centrifuge measures 20 m in radius, what is the rotational velocity of a centrifuge during testing?
The rotational velocity of the centrifuge is \(\sqrt{5}\) rad/s.
What is Centripetal force ?
Centripetal force is defined as the force that acts on a body moving in circular path which is directed towards the centre of the circular path.
Here,
The rotational acceleration attained by the astronauts, a' = 100 m/s²
The radius of the centrifuge, r = 20 m
From the equation of circular motion,
a' = rω²
So, ω² = a'/r
ω² = 100/20
ω² = 5
Rotational velocity, ω = \(\sqrt{5}\) rad/s
Hence,
The rotational velocity of the centrifuge, ω is \(\sqrt{5}\) rad/s
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A motorcycle, travelling cast, starts from rest, moves in a straight line with a constant acceleration and covers a distance of 64 m in 4 s.Calculate a) Its acceleration b) Its final velocity c) At what time the motorcycle had covered half the total distance d) What distance the motorcycle had covered in half the total time.
The motorcycle had covered a distance of 16 meters in half the total time.
a) To calculate the acceleration, we can use the formula:
a = (v - u) / t
where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.
Given:
u = 0 m/s (initial velocity)
v = ? (final velocity)
t = 4 s (time)
s = 64 m (distance)
Using the equation of motion:
s = ut + 1/2at^2
We can rearrange the equation to solve for acceleration:
a = 2s / t^2
a = 2(64) / (4)^2
a = 128 / 16
a = 8 m/s^2
Therefore, the acceleration of the motorcycle is 8 m/s^2.
b) To find the final velocity, we can use the formula:
v = u + at
v = 0 + (8)(4)
v = 32 m/s
Therefore, the final velocity of the motorcycle is 32 m/s.
c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:
s = ut + 1/2at^2
32 = 0 + 1/2(8)t^2
16 = 4t^2
t^2 = 4
t = 2 s
Therefore, the motorcycle had covered half the total distance at 2 seconds.
d) To calculate the distance covered in half the total time, we use the formula:
s = ut + 1/2at^2
s = 0 + 1/2(8)(2)^2
s = 0 + 1/2(8)(4)
s = 0 + 16
s = 16 m
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What are the differences between atoms, molecules, and compounds?
Answer:
Atoms are the thing that make up molecules and compounds. Molecule. Two or more atoms joined together with covalent bonds. Molecules contain two or more atoms and are held together by covalent bonds, whereas compounds are held together by ionic bonds. Compound. Two or more elements bonded together through ionic attraction.
Jupiter has a gravitational constant of 24.79 m/s^2. If a space probe is 25 meters above the planet's surface, it generates 25000 J (Joules) to escape. How much does the probe weigh?
Please answer quickly, and 50 points to whoever answers.
Ursula is a student of Kantian philosophy who argues that we should never use people as a means to an end unless
Answer: we embrace and are simultaneously respecting their rational autonomy
Explanation:
Ursula is a student of Kantian philosophy who argues that we should never use people as a means to an end unless we embrace and are simultaneously respecting their rational autonomy
A ball has a mass of 0.046kg. Calculate the change in gravitational potential energy when the ball is lifted through a vertical height of 2.05 m.
The mass of a ball is 0.046kg. The ball is released. Calculate the kinetic energy of the ball when the speed of the ball is 3.5 m/s
Answer:
PE=0.92414J and KE=0.28175J
Explanation:
Gravitational potential energy=mass*gravity*height
PE=mgh
Data,
M=0.046kg
H=2.05m
g=9.8m/s^2
PE=0.046kg * 9.8m/s^2 * 2.05m
PE =0.92414J
KE=1/2mv^2
M=0.046kg
V=3.5m/s
KE=[(0.046kg)*(3.5m/s)^2]\2
KE=0.28175J
how much work did the movers do horizontally pushing a 46 kg crate 10.3 across a rough floor without acceleration, if the effective coefficient of friction was 0.5
The work done is 2321 J.
What is the work that is done?We have to note that the acceleration has to do with the change in the velocity of the object with time. We are told that there is a movement of the crate as we can see. Let us note that the work that is done by the object subtracted from the work done by the friction. Thus we have that;
Work = (46 * 9.8 * 10.3) - (0.5 * 46 *9.8 * 10.3)
Work = 4643 - 2321
= 2321 J
The work that has been done is 2321 J. This is done in moving the object
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A person who weighs 614 N is riding a 85-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally by the two tires. If the gauge pressure in each tire is 9.00 x 10^5 Pa. What is the area of contact between each tire and the ground?
Answer:
3.88 × 10^-4 m
Explanation:
Given that a person who weighs 614 N is riding a 85-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally by the two tires. If the gauge pressure in each tire is 9.00 x 10^5 Pa. What is the area of contact between each tire and the ground?
The total weight = 614 + 85
The total weight = 699N
Let the total area of contact = A
Pressure = Force / A
Substitute all the parameters into the formula
900000 = 699 /A
A = 699 / 900000
A = 7.77 × 10^-4 m
The area of contact between each tire and the ground will be = A/2
That is, 7.77 / 2 = 3.88 × 10^-4 m
Therefore, the area of contact between each tire and the ground is 3.88 × 10^-4 m approximately.
What converts mechanical energy into kinetic energy?
A.Generator
B. motor
Please help me out with this.
True or False?
You are helping a friend push a couch across their living room floor.
Gravity is a field force acting downward on the couch.
Friction from the carpeted floor is a contact force acting against your push.
We have that Gravity a force acting down ward against any object and frictional force is a force acting a against movement, Hence
TrueTrueGravity and frictional forceGenerally, Gravity a force acting down ward against any object on earth at an acceleration of about 9.8m/s
and frictional force is a force acting a against the movement based on contact with another surface
Therefore
Gravity is a field force acting downward on the couch:
This is True
Friction from the carpeted floor is a contact force acting against your push.
This is True
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When converted to a household measurement, 9 kilograms is approximately equal to a
Answer:
D) 19.8 lbs
Explanation:
1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.
1kg is also equal to 2.205 lbs. 9*2.205=19.8416
9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system
a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.
This leaves us with 19.8 lbs
what will happen if a low massive main sequence star runs out of hydrogen fuel?
Answer:
Low mass stars are: hydrogen burning in the core while on the Main Sequence. As the hydrogen fuel runs out, extreme pressure raises the temperature to 100 million degrees, where helium burning becomes possible.
If 56.5 m3 of a gas are collected at a pressure of 455 mm Hg, what volume will the gas occupy if the pressure is changed to 632 mm Hg? *
Assuming ideal conditions, Boyle's law says that
P₁ V₁ = P₂ V₂
where P₁ and V₁ are the initial pressure and temperature, respectively, and P₂ and V₂ are the final pressure and temperature.
So you have
(455 mm Hg) (56.5 m³) = (632 mm Hg) V₂
==> V₂ = (455 mm Hg) (56.5 m³) / (632 mm Hg) ≈ 40.7 m³
you made $100,000 this year. you have $0 in adjustments, $11,500 in deductions and $7,300 in exemptions. What is your taxable increase?
The tax rate you will pay is displayed in tax brackets for each category of taxable income.
Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.
Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.
As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.
Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.
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