A gas stream containing n-hexane in nitrogen with a relative saturation of 0.58 (as a fraction, multiply by 100% if you prefer %) is fed to a condenser at 75 deg C and 3.0 atm absolute. The product gas stream and condensed hexane stream emerge at 20 deg C and 3.0 atm absolute. Calculate the amount of heat flow in kJ required per gmol of hexane condensed. Your answer will be negative.

Answer:

\(0.01molO_2\)

Explanation:

Hello there!

In this case, by considering the definition of molar solution as the moles of solute over volume in liters or cubic meters of solution, we can see that actually 10.0 L of the solution are equal to 10.0 dm³. In such a way, since the concentration is 0.001 mol / dm³, the moles of oxygen that are dissolved turn out to be:

\(0.001mol/dm^3 * 10.0dm^3\\\\0.01molO_2\)

Best regards!

Answer:

Explanation:

An element with 70 protons and a mass of 170 would be considered radioactive.

In general, an element with an atomic number (number of protons) greater than 82 tends to be radioactive. Since the element in question has 70 protons, which is less than 82, it does not fall into the category of naturally radioactive elements. However, it is important to note that the stability of an element also depends on the balance between protons and neutrons in the nucleus. Without information about the number of neutrons in the nucleus, we cannot determine the stability of this specific element definitively.

The density of ammonia gas in the 6.0 L container at a pressure of 820 mm Hg is approximately 0.805 g/L.

To determine the density of ammonia gas (NH3) in a 6.0 L container at a pressure of 820 mm Hg, we need to use the ideal gas law equation, which relates pressure, volume, number of moles, and temperature for a given gas.

The ideal gas law equation is:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Since we are given the pressure (820 mm Hg), volume (6.0 L), and assuming standard temperature and pressure (STP), we can use the values for R (0.0821 L·atm/(mol·K)) and convert the pressure to atm by dividing by 760 (1 atm = 760 mm Hg).

820 mm Hg / 760 mm Hg/atm = 1.08 atm

Now we can rearrange the ideal gas law equation to solve for density (d):

d = (P * M) / (RT)

Where M is the molar mass of ammonia (NH3), which is approximately 17.03 g/mol.

Substituting the values, we have:

d = (1.08 atm * 17.03 g/mol) / (0.0821 L·atm/(mol·K) * 298 K)

Simplifying the equation, we find:

d ≈ 0.805 g/L

Therefore, the density of ammonia gas in the 6.0 L container at a pressure of 820 mm Hg is approximately 0.805 g/L.

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The mass, in grams, of one atom of magnesium is 4.040 × 10^-23 g (to 4 significant figures).

Mass of 1 mole of magnesium = 24.32 g

Number of atoms in 1 mole of magnesium = 6.022 × 10²³

We are to calculate the mass of one atom of magnesium.

We can start by finding the mass of one mole of magnesium, which is given as 24.32 g.

1 mole of magnesium contains 6.022 × 10²³ atoms of magnesium, which means the mass of one magnesium atom is equal to the mass of one mole divided by the number of atoms in one mole.

Thus, the mass of one atom of magnesium can be calculated as follows:

Mass of one magnesium atom = mass of 1 mole of magnesium / number of atoms in 1 mole

= 24.32 g / (6.022 × 10²³)

= 4.04 × 10^-23 g

We can express this value in scientific notation to four significant figures as: 4.040 × 10^-23 g.

Therefore, the mass, in grams, of one atom of magnesium is :

4.040 × 10^-23 g (to 4 significant figures).

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Answer:

your answer is gonna most likely be b

The technique that wildlife photography experts use to put the focus on their subjects in the middle ground is called Deep Focus.

A narrow aperture is typically used to produce deep focus. Because a camera's aperture regulates how much light enters the lens, obtaining deep focus necessitates a bright picture or a lengthy exposure. A wide-angle lens also sharpens a bigger section of the image.

Deep focus in cinematography maintains a tight focus on all parts of an image, catching crucial actions in both the front and background.

Deep focus is used by directors for situations with significant movement in both the front and background of the frame. This type of staging is known as "deep space" or "deep staging" by directors because it involves the placing of performers, props, and set elements at tremendous depth.

A filmmaker must be able to capture a well-defined image for such a shot to succeed. Such sharpness is possible with a deep-focus photo.

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Answer:

All energy sources have some impact on our environment. Fossil fuels—coal, oil, and natural gas—do substantially more harm than renewable energy sources by most measures, including air and water pollution, damage to public health, wildlife and habitat loss, water use, land use, and global warming emissions

Answer:

Explanation: Fossil fuels—coal, oil, and natural gas—do substantially more harm than renewable energy sources by most measures, including air and water pollution, damage to public health, wildlife and habitat loss, water use, land use, and global warming emissions.

Answer:

d=m/

Explanation:

d is density, m is mass, v is volume

Given: m =10.4g, v=12.2mL

substituting in equation,

d=10.4/ 12.2

d=0.8524g/mL

To learn more about density:

The density of the liquid is 0.852 g/mL.

To calculate the density of the liquid, we need to use the formula:

Density = Mass / Volume

Given that the mass of the liquid is 10.4 g and the volume is 12.2 mL, we can substitute these values into the formula:

Density = 10.4 g / 12.2 mL

Simplifying this expression, we find:

Density = 0.852 g/mL

Density is a physical property of a substance and is defined as the amount of mass per unit volume. In this case, the density tells us that for every milliliter of the liquid, there is 0.852 grams of mass. The units of grams per milliliter (g/mL) indicate that the density is a ratio of mass to volume.It is important to note that the density of a substance can vary with temperature, so this value is only valid under the conditions at which the measurement was made. Additionally, the density can provide valuable information about the identity of a substance, as different substances have different densities.

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First, we write the reaction to solve this:

Al(NO₃)₃(aq) => Al³⁺(aq) + 3NO₃⁻(aq)

We need to calculate the concentration of the salt:

Molarity = moles of Al(NO₃)₃ / Volume of solution (L)

Molarity = 2.00 moles / 2.00 L = 1.00 mol/L

The salt is completely disociated, so the concentration of NO3- ion is:

Concentration NO3- = 3 x Concentration of the salt = 3 x 1.00 mol/L = 3.00 mol/L

Answer: 3.00 mol/L

Answer:

A on Edge

Explanation:

Person above me got it right.

If we add more magnesium to the reaction, the reaction speed will increase.

The chemical reaction shown is a single-displacement reaction, also known as a single-replacement reaction. In this type of reaction, one element replaces another element in a molecule, producing a new compound and a different element.

In the given reaction, magnesium (Mg) reacts with sulfuric acid (H₂SO₄) to produce magnesium sulphate (MgSO₄) and hydrogen gas (H₂). This can be represented by the following balanced chemical equation:

Mg + H₂SO₄ → MgSO₄ + H₂

This is because the amount of reactant determines the number of reactions that can occur. If the amount of magnesium is increased, more magnesium atoms are available for the reaction with sulfuric acid, leading to a higher rate of reaction.

However, this increase in reaction rate is only valid up to a certain point, after which further addition of magnesium will not lead to an increase in rate of reaction. This is because other factors such as the concentration of sulfuric acid and the temperature of the reaction may become limiting factors that can no longer be compensated by adding more magnesium.

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Answer:

Brazil

Explanation:

It is closest to the equator

Answer:

Dissociation, dispersion, and ionization.

Answer:

either A or D

Explanation:

but probably D

The given alkyne is Option A 3-heptyne

The hydrocarbon having at least one C-C triple bond is called an Alkyne.

It has the general formula of   \(\rm C_n H_{2n+2}\) .

In the question it is being mentioned that it is an alkyne so there will be a triple bond and not a double bond.

It has been asked in the question that

CH3CH₂C ≡  CCH₂CH₂CH3 is which alkyne from the given option.

The counting of the Carbon chain is done from the left side and the Triple bond is at the 3rd Carbon , so 3-heptyne .

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first step is to calcuate the how many mols are 6.20x10^22 atoms:

Let´s remember that 6.022x10^23 atoms are 1 mol, so:

Now all you need to do is to multiply the number of mols by the atomic mas of tungsten, which is 183.84 g/mol:

Answer:

See explaination

Explanation:

1. The addition of group 3A elements to group 4A semiconductors decreases the conductivity of the group 4A semiconductors: Wrong

The addition of 3A group elements inreases the conductivity and make them extrinsic semiconductors( p-type)

2. The conductivity of semiconductors can be increased by the doping process.: Correct

3.As the temperature increases, the conductivity of semiconductors decreases.. wrong

As the temperature increases, the conductivity of semiconductors increases.

4. The addition of group 5A elements to group 4A semiconductors increases the conductivity of the group 4A semiconductors: Correct : They will create n-type semicoductor.

5.Holes are charge carriers in p-type semiconductors: Correct

6. Electrons are charge carriers in n-type semiconductors: Correct

Answer:  Formula: Mass = (Volume)(Density)

Iron Density = 7.87 g/cm^3

Volume of Iron = 55.2 cm^3

Mass=(V)(D)

Mass= (55.2 cm^3) x (7.87 g/cm^3)

Mass=  434,42 g

Explanation:

Iron has a density of 7.87 g/cm³. 434,42 g is the mass of 55.2 cm³ of iron.

The term density is defined as the measurement of how closely a material is packed together.

It is also defined as the mass per unit volume. Density Symbol is D or ρ Density Formula is ρ = m/V, where ρ is the density, m is the mass of the object and V is the volume of the object.

Density is an important because it allows us to find out what substances will float and what substances will sink when placed in a liquid.

Formula:

Mass = (Volume)(Density)

Given:

Iron Density = 7.87 g/cm³

Volume of Iron = 55.2 cm³

Mass=(V)(D)

Mass= (55.2 cm³) x (7.87 g/cm³)

Mass= 434,42 g

Thus, Iron has a density of 7.87 g/cm³. 434,42 g is the mass of 55.2 cm³ of iron.

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Perhaps you like the appearance of rocks and boulders but prefer a material that stays cool in the desert heat. In this case, concrete or travertine should be your top picks. These materials have a high thermal mass and absorb the coolness of the earth below rather than the hot sun overhead

Sometimes you like how rocks and boulders look, but you'd rather have something that keeps cool in the hot desert. In this circumstance, limestone or concrete ought to be your top choices.

Deserts are incredibly arid places where well-adapted flora and animals can be found. Deserts may be divided into four basic categories are hot and dry, semi-arid, coastal, and cold.

The majority of specialists concur that a desert is any region of land with annual precipitation totals of less than 25 cm (10 inches). In a desert, evaporation frequently much outweighs yearly precipitation. Water is scarce for plants and other living things in all deserts.

Thus, Due to their large thermal mass, these materials absorb the cooling of the earth below rather than the heat from the sun above. Something that keeps cool in the hot desert.

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390 g KNO₃

Atomic Structure

Pre-Algebra

Order of Operations: BPEMDAS

Step 1: Define

2.3 × 10²⁴ formula units KNO₃

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of K - 39.10 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g.mol

Molar Mass of KNO₃ - 39.10 + 14.01 + 3(16.00) = 101.11 g/mol

Step 3: Convert

\(2.3 \cdot 10^{24} \ formula \ units \ KNO_3(\frac{1 \ mol \ KNO_3}{6.022 \cdot 10^{23} \ formula \ units \ KNO_3} )(\frac{101.11 \ g \ KNO_3}{1 \ mol \ KNO_3} )\) = 386.172 g KNO₃

Step 4: Check

We are given 2 sig figs. Follow sig fig rules and round.

386.172 g KNO₃ ≈ 390 g KNO₃

Jeremiah can arrange the materials in the following way to create a model that shows the processes by which water is cycled from a lake into the atmosphere and back to the lake

The following can be a representation of the water cycle;

Fill the glass jar with water to resemble the lake.

Put the lamp next to the jar to symbolize the sun.

Wrap the jar in plastic sheet to imitate the atmosphere.

Turn on the bulb to represent the sun warming the water.

When the water in the jar warms up and evaporates into water vapor, moisture will condense on the plastic wrap.

The water vapor will ascend and collect on the plastic wrap to represent the water vapor rising into the atmosphere.

Water vapor cools as it rises and condenses back into liquid form, as shown by the water droplets gathering on the plastic wrap.

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The valency of elements tends to decrease as we move down the periodic table of non-metal and metal.

The ability of an element to combine is referred to as valency. It is the number of electrons that an elemental atom loses, gains, or shares with another atom to form a stable configuration of electrons.

The occasional table is organized so that components with comparable valencies are set in a similar gathering. Components in a similar gathering have similar number of valence electrons, which decides their substance properties.

The valency of the elements tends to decrease as we move down a periodic table of metals and non-metals. This is because the number of electron shells, or energy levels, increases as we move down a group. The peripheral electrons in a particle are the valence electrons.

The expanded distance between the core and the peripheral electrons brings about more vulnerable fascination between them. As a result, the atom becomes more reactive and can lose or gain electrons more easily.

For instance, in bunch 1 of the occasional table, the valency of the components diminishes as we drop down the gathering. The valencies of lithium (Li), sodium (Na), and potassium (K) are, respectively, 1, 1, and 1.

This is due to the fact that each possesses one valence electron. Because the outermost electron is further from the nucleus and therefore more likely to be lost or gained, the valency decreases as we move down the group.

In conclusion, as we move down the periodic table, from non-metal to metal, the valency of elements tends to decrease. This is because the nucleus and the outermost electrons are less attracted to one another as the energy levels rise.

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Answer:

7.5 kcal

Explanation:

1.0 cal /g-C   * 100 g * (100- 25 C) = 7500 cal = 7.5 kcal

The amount of heat energy necessary to raise the temperature of 100 g of water at room temperature (25°C) to the boiling point (100°C) is 7.5 kcal.

Given to us the mass of water, the specific heat of water, and the change in temperature, we need to calculate the amount of heat energy.

m = 100 g

c = 1.0 cal/g°C

ΔT = (100 °C - 25 °C) = 75 °C

To calculate the amount of heat energy required, we can use the formula:

Q = m × c× ΔT

Where:

Q = heat energy (in calories)

m = mass of water (in grams)

c = specific heat of water (in cal/g°C)

ΔT = change in temperature (in °C)

Substituting the values into the formula:

Q = 100 g × 1.0 cal/g°C × 75 °C

Q = 7500 cal

7500 cal = 7.5 kcal

Therefore, the amount of heat energy required to raise the temperature of 100 g of water from 25 °C to 100 °C is 7500 calories, which is equivalent to 7.5 kcal.

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Answer:

iii) An anion is a positive ion.

cuz an anion is negatively charged ion

The INCORRECT statement is "An anion is a positive ion".

So, the correct option is iii.

An atom can lose and gain one or more electrons from outermost shell which is known valence shell and formed an ions.

An atom gain one or more electrons and form negative charged species called an anion.

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The mass of water produced when 9.60 g of butane reacts with excess oxygen is 14.85 gram.

The chemical reaction between substances, usually considering oxygen and usually accompanied by the generation of heat and light in the form of flame is called as combustion reaction.

C4H10(g) + 13 /2 O2(g) → 4CO2(g) + 5H2O(l)

Moles of butane = 9.60⋅g / 58.12⋅g⋅mol−1

= 0.165mol.

We assume complete combustion, and know that each mole of butane gives off 5 mol of water upon combustion.

Given that we know the molar quantity of butane, we simply perform the operation,

= 5 × 0.165 × 18.01

= 14.85 gram

Thus, the mass of water produced when 9.60 g of butane reacts with excess oxygen is 14.85 gram.

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