A freight train car has a mass of 2,000 kilograms and an acceleration of 1.8 m/s/s. ​What is the average force behind that train car?

A celestial sphere is a tool that allows us to study in detail the characteristics of the planet and its reference points.

The celestial sphere is an astronomical tool that allows individuals to study the planet Earth and other planets. This tool is an ideal sphere that is used as a model of the Earth. Additionally, it represents the locations of celestial objects, meridians, parallels, geographical locations, among others.

The meridians and parallels are imaginary lines that are located on the earth to be located geographically on the surface. These also distribute the terrestrial locations in four quadrants (cardinal points).

The zenith is a term that refers to the highest point in the sky relative to the observer and it is just above the observer's head (90°).

The nadir is a term that refers to the intersection between the observer's vertical and the celestial sphere. That is to say: if you imagine a line that passes through the center of the Earth and through our location on its surface, the nadir is on that line, below our feet.

Below is an image in which the zenith, nadir, cardinal points, meridians and parallels are referenced.

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The flow of electricity is referred to as current. Metals are generally excellent conductors, allowing current to flow freely. Insulators are materials that do not allow current to flow easily. Insulators include most nonmetal materials such as plastic, wood, and rubber.

Electrical insulators are materials that do not allow electricity to pass through them. Plastic, rubber, wood, and glass are examples of these materials. Air also acts as an insulator. To keep electrical objects safe, most are constructed with insulators.

Electrical insulators include plastic, wood, glass, and rubber. That is why they are used to covering electrically conductive materials. The plastic that surrounds wires acts as an electrical insulator.

Thus, Insulators include most nonmetal materials such as plastic, wood, and rubber.

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Answer:  A. He developed the world's first star catalogue.

Explanation: Gan De's contribution to astronomy was the development of the world's first star catalogue , along with his colleague Shi Shen. He also made observations of the planets, particularly Jupiter, and may have been the first to describe one of Jupiter's moons. Unfortunately, all of Gan De's writings have been lost, but fragments of his works' titles and quoted fragments are known from later texts.

The velocity of the object of charge Q₃ will be 8109.25 m/s.

The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.

The velocity of the object  of charge Q₃ will be =

√{(2/ 10.0 × 10⁻⁸)(9 × 10⁹) × 4 × 10⁻⁶(2.0 × 10⁻⁶(1/0.01 - 1/0.02) - 2.0 × 10⁻⁶(1/0.05 - 1/0.06))}

= 8109.25 m/s.

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Answer:(a) For the first time step, using Δt = 0.1s:

pf = m * vavg

vavg = pf/m

vavg = (<−0.02, −0.01, −0.02> kg · m/s) / 0.011 kg

To find the position at t = 0.1 s, we need to find the average velocity over the time interval, and multiply it by the time interval:

position = initial position + vavg * Δt

position = <−0.2, −0.61, 0> m + vavg * 0.1 s

(b) To find the position at t = 0.05s, repeat the same steps as in (a) but with Δt = 0.05s.

(c) To find the position at t = 0.1s, starting from the position and momentum at t=0.05s, repeat the same steps as in (a) and (b) with the new initial position and momentum value

Explanation:

The components of the net force on the cart is determined as 67.66 N.

The component of net force on the cart is determined by resolving the forces into x and y -components.

T1 = 30 N

T2 = 40 N

T1x = -30cos(0) = 30 N

T1y = 30sin(0) = 0

T2x = 40 x cos(30) = 34.64 N

T2y = 40 x sin(3) = 20 N

∑X = 30 N + 34.64 N = 64.64 N

∑Y = 0 + 20 N = 20 N

R = √(64.64² + 20²)

R = 67.66 N

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The % element x in the compound is option c.25%.

To find the percentage of element X in the compound, we need to calculate the ratio of the number of atoms of element X to the total number of atoms in the compound and then convert it to a percentage.

Given:

Total number of atoms = 44

Number of atoms of element X = 11

To calculate the percentage, we can use the following formula:

Percentage of element X = (Number of atoms of element X / Total number of atoms) * 100

Substituting the given values, we get:

Percentage of element X = (11 / 44) * 100

Simplifying the equation, we have:

Percentage of element X = 0.25 * 100

Percentage of element X = 25%

Therefore, the percentage of element X in the compound is 25%.

The correct answer is option C. 25%.

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1. The electric field pattern due to charged sphere A can be represented by lines radiating outward from the sphere.

2. The magnitude of the charge on sphere A is approximately 0.0833 Coulombs.

3. The electrostatic force experienced by sphere B when placed at point P is approximately 2.675 x 10^-4 Newtons.

1. These lines should be evenly spaced and symmetric around the sphere, indicating a radial field pattern. Since the electric field at point P is directed towards sphere A, the field lines should point inward towards the sphere. Thus, the electric field pattern would resemble a series of concentric circles with lines converging towards the center of sphere A.

2. To calculate the magnitude of the charge on sphere A, we can use the formula for the electric field strength (E) due to a point charge:

E = k * (Q / r^2)

where k is the electrostatic constant (approximately 9 x 10^9 N m^2/C^2), Q is the charge on the sphere, and r is the distance from the sphere to the point P.

From the given information, we have E = 3 x 10^7 N/C and r = 0.5 m. Plugging these values into the formula and solving for Q:

3 x 10^7 N/C = (9 x 10^9 N m^2/C^2) * (Q / (0.5 m)^2)

Simplifying the equation, we find:

Q = (3 x 10^7 N/C) * (0.5 m)^2 / (9 x 10^9 N m^2/C^2)

Q ≈ 0.0833 C (Coulombs)

Therefore, the magnitude of the charge on sphere A is approximately 0.0833 Coulombs.

3. When sphere E, which has an excess of 105 electrons, is placed at point P, it will experience an electrostatic force due to the interaction with sphere A. The electrostatic force between two charges can be calculated using Coulomb's law:

F = k * (|q1| * |q2|) / r^2

where k is the electrostatic constant, q1 and q2 are the charges on the spheres, and r is the distance between them.

Since each electron carries a charge of approximately -1.6 x 10^-19 C, the excess charge on sphere E is:

q2 = 105 electrons * (-1.6 x 10^-19 C/electron)

Plugging in the values and the given distance of 0.5 m, we have:

F = (9 x 10^9 N m^2/C^2) * (|0.0833 C| * |-1.6 x 10^-19 C|) / (0.5 m)^2

Simplifying the equation, we find:

F ≈ 2.675 x 10^-4 N (Newtons)

Therefore, the electrostatic force experienced by sphere E when placed at point P is approximately 2.675 x 10^-4 Newtons.

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Answer:

Explanation:

The law of reflection says that the reflected angle (measured from a vertical line to the surface  called the normal) is equal to the reflected angle measured from the same normal line.

All other properties of reflection flow from this one statement.

Answer:

The focal length of the mirror is 10.4 cm.

Explanation:

So substitute the values of object distance and image distance in the mirror equation,

1/f = 1/(-18cm) + 1/(-25.0cm)

1/f = -25cm/(-18cm x -25cm) - 18cm/(-18cm x 25cm)

1/f = ( -25cm - 18cm)/(18cm x 25cm)

1/f = -43.0/450.0

f = -10.4651 cm.

The focal length of the mirror is approximately -10.4 cm.

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Explanation:

use the formula and substitute the value

The resistance of the electric device using a power of 650 watts is approximately 27.7 ohms.

Ohm’s law states that the potential difference between two points is directly proportional to the current flowing through the resistance.

Hence

V = IR

R = V/I

Where V is the voltage or potential difference, potential difference, I is the current and R is the resistance.

We need to first find the electric current I.

Note:

Power = Voltage × Current.

Hence:

Current I = Power/Votage

Plug in the values

I = 650 / 120

I = 13/3 A

Substituting the values of voltage and current intio the above formula, we can calculate the resistance:

R = V/I

R = 120 / (13/3)

R = 27.7 ohms

Therefore, the resistance is approximately 27.7 ohms.

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Answer:

Mass = 30kg

Acceleration = 0m/s/s

Explanation:

The weight of an object is its mass multiplied by the gravitational field strength. On Earth the value often used for gravity is 10N/kg. This means there is 10N of force per kg of mass, so the weight of an object will be 10x its mass. Here we are given a weight of 300N, so to find its mass we simply need to divide it by 10. 300/10 = 30kg. The mass of the box is 30kg.

Because the box is being slid across the floor at a constant speed, the velocity is not changing, therefore the acceleration is 0.

Hope this helped!

Answer:

Mass = 30 kg

Acceleration = 0 m / s²

Explanation:

Gravity = 10 N / kg

Thus the mass = 30 kg

We know that the box slide in a constant speed

Thus it doesn't have any acceleration.

Hopefully this answer helps you :)

Answer:

A) should be able to complete daily tasks without being physically taxed

Explanation:

B) you dont need to run that fast to have good physical fitness

C) you dont need to workout four times a week

D) you should always eat healthy as diet contributes to health

In order to have good physical fitness, you should be able to complete daily tasks without being physically taxed.

Physical fitness is the ability to be fit to do work without getting tired easily.

Exercise and workouts are necessary to build and improve physical fitness.

Exercises required include jogging and running.

Therefore, in order to have good physical fitness, you should be able to complete daily tasks without being physically taxed.

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Answer:

B. They do not provide explanations for why they are true.

C. They are considered to be proven facts.

Explanation:

edge 2021

The statements describe scientific laws but not theories or hypotheses are they do not provide explanations for why they are true and they are considered to be proven facts.

The law given by the experimenters or scientists after years of observations and experiments based on the scientific reasons are called scientific laws.

The laws are not the proven facts. They even don't explain why the scientific laws are true.

Thus, the correct option is B and C.

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Answer:

a) On the Moon, where the acceleration due to gravity is 0.258g:

First, we need to find the acceleration due to gravity on the Moon:

g_Moon = 0.258g_Earth

g_Moon = 0.258(12.3 m/s^2)

g_Moon = 3.17 m/s^2

Now we can use the range formula for projectile motion to find the distance he could jump:

R = (v^2/g) sin(2θ)

Assuming the same initial velocity and angle of jump, we can rearrange the formula to solve for R:

R = (v^2/g) sin(^2/g_Earth) sin(2θ) * (g_Moon/g_Earth)

R = (1.31 m)^2/ (212.3 m/s^2) * sin(2θ) * (3.17 m/s^2) / (12.3 m/s^2)

R = 0.191 m

Therefore, he could jump approximately 0.191 m on the Moon.

!

a) On the Moon, where the acceleration due to gravity is 0.258g:

First, we need to find the acceleration due to gravity on the Moon:

g_Moon = 0.258g_Earth

g_Moon = 0.258(12.3 m/s^2)

g_Moon = 3.17 m/s^2

Now we can use the range formula for projectile motion to find the distance he could jump:

R = (v^2/g) sin(2θ)

Assuming the same initial velocity and angle of jump, we can rearrange the formula to solve for R:

R = (v^2/g) sin(

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^2/g_Earth) sin(2θ) * (g_Moon/g_Earth)

R = (1.31 m)^2/ (212.3 m/s^2) * sin(2θ) * (3.17 m/s^2) / (12.3 m/s^2)

R = 0.191 m

Therefore, he could jump approximately 0.191 m on the Moon.

b) On Mars, where the acceleration due to gravity is 0.293g:

Similarly, we need to find the acceleration due to gravity on Mars:

g_Mars = 0.293g_Earth

g_Mars = 0.293(12.3 m/s^2)

g_Mars = 3.61 m/s^2

Using the same formula and rearrangement as in part a, we can find the distance he could jump on Mars:

R = (1.31 m)^2/ (212.3 m/s^2) * sin(2θ) * (3.61 m/s^2) / (12.3 m/s^2)

R = 0.223 m

Therefore, he could jump approximately 0.223 m on Mars.

Answer:

Condensation can also produce water droplets on the outside of soda cans or glasses of cold water. When warm air hits the cold surface, it reaches its dew point and condenses. This leaves droplets of water on the glass or can.

Explanation:

Answer:

A capacitor is formed from two square plates of edge length a and separation d, with d <

Explanation:

A capacitor is formed from two square plates of edge length a and separation d, with d <

19.56m is the common height from which the rocks were released.

Formula used for calculating the height(s) is

s = ut + 1/2gt²

where

s = Common height from which the rocks were released

u = Initial velocity

g = acceleration

t = time period taken

For Wes

Initial velocity(u) = 0

So, s = 1/2gt² .... (1)

For Lindsay

Initial velocity = 27m/s

Time (t) = t - 1.35

So, s = 27(t - 1.35) + 1/2g(t - 1.35)² ..... (2)

From equation (1) and (2)

1/2gt² = 27(t-1.35) + 1/2g(t - 1.35)²

On solving we get

t = 1.998 seconds

Now By putting the calculated value of (t) in equation (1)

s = 1/2 × 9.8 × (1.998)²

s = 19.56 m

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Answer:

The object has to have mass and speed

Explanation:

You can increase both speed and mass to increase the kinetic energy, hope this answers your question.

Happy Halloween!

Answer:

83.33% of the roof area will be occupied by the PV cells

Explanation:

Given the data in the question;

time-averaged lighting requirement \(P_{lighting\) = 10 W/m²

the annual average solar irradiance \(q_{solar\) = 150 W/m²

the PV efficiency η\(_{pv\) = 10% = 0.1

battery charging/discharging efficiency η\(_{battery\) = 80% = 0.8

we know that; Annual average power to the light = \(P_{lighting\) × A\(_{roof\)

Now, the electrical power delivered by the solar cell battery system will be;

⇒  \(q_{solar\) × A\(_{pv\) × η\(_{pv\) × η\(_{battery\)

\(P_{lighting\)A\(_{roof\) = \(q_{solar\) × A\(_{pv\) × η\(_{pv\) × η\(_{battery\)

Such that;

A\(_{pv\) = \(P_{lighting\)A\(_{roof\) / \(q_{solar\) × A\(_{pv\) × η\(_{pv\) × η\(_{battery\)

A\(_{pv\) / A\(_{roof\) = \(P_{lighting\) /  \(q_{solar\) × η\(_{pv\) × η\(_{battery\)

so we substitute

A\(_{pv\) / A\(_{roof\) = 10 W/m² / [ 150 W/m² × 0.1 × 0.8 ]

A\(_{pv\) / A\(_{roof\) = 10 W/m² / 12 W/m²

A\(_{pv\) / A\(_{roof\) = 0.8333

A\(_{pv\) / A\(_{roof\) = (0.8333 × 100)%

A\(_{pv\) / A\(_{roof\) = 83.33%

Therefore, 83.33% of the roof area will be occupied by the PV cells.

The tax rate you will pay is displayed in tax brackets for each category of taxable income.

Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.

Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.

As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.

Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.

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Answer:

The forces acting on an asteroid include gravity from the Sun and other celestial bodies, radiation pressure from the Sun, and the pressure from interplanetary gas and dust. The gravitational forces will act to pull the asteroid towards the Sun, while the radiation pressure and interplanetary gas and dust will act to push it away. The net force acting on the asteroid will determine its path and velocity through the solar system.

Explanation:

Answer:

To find the net charge on the sphere using electric flux, we can use the formula:  

Φ = Q/ε0

Where Φ is the electric flux, Q is the charge, and ε0 is the permittivity of free space.  

Given that the electric field 20 cm from the center of the sphere is N/C and points radially inwards, we can use the formula for electric field due to a charged sphere to find the charge on the sphere:

E = kQ/r^2  

Where E is the electric field, k is Coulomb's constant, Q is the charge, and r is the distance from the center of the sphere.  

Substituting the given values, we get:  

20 = (1/4πε0)(Q)/(0.2)^2  

Solving for Q, we get:  

Q = (20)(0.2)^2(4πε0)  

Q = 0.64πε0 C  

Now, substituting this value of Q in the formula for electric flux, we get:  Φ = Q/ε0 = (0.64πε0)/(ε0) = 0.64π C  

Therefore, the net charge on the sphere is 0.64π C.

For the second spanner, the torque is: Torque = 20 N x 10 cm = 200 N.cm Therefore, the first spanner produces the greatest torque.

The torque applied to the fastener rises as the lever arm extends when a torque wrench with an extension (such as a crow foot or a dog bone) is used. The calculator will determine what setting you need to make on the wrench to attain the necessary fastener torque. M1 = M2 x L1 / L2 has been used as the solution.

We must apply the algorithm to determine the torque generated by each spanner:

Force x perpendicular separation from the centre point equals torque.

Assuming that each spanner's pivot point is in its center, the perpendicular distance from the pivot to the spot at which the force is applied is equal to half of the spanner's length.

For the first spanner, the torque is:

Torque = 30 N x 7.5 cm = 225 N.cm

For the second spanner, the torque is:

Torque = 20 N x 10 cm = 200 N.cm

Therefore, the first spanner produces the greatest torque.

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The force actually being used to push the mower along the ground is 191 N.

When the physics student exerts a force of 250 N along the handle of the push mower, it's important to consider the components of this force that contribute to the actual force used to push the mower along the ground.

To determine the force used to push the mower along the ground, we need to find the horizontal component of the applied force. The angle of 40° indicates that the applied force can be broken down into two components: the horizontal component and the vertical component. The vertical component of the force is perpendicular to the direction of motion and does not contribute to pushing the mower forward.

To find the horizontal component, we can use trigonometry. The horizontal component is given by the formula:

Horizontal component = Applied force * cos(angle)

Plugging in the values, we get:

Horizontal component = 250 N * cos(40°)

Calculating this value, we find that the horizontal component of the applied force is approximately 191 N.

Therefore, the force actually being used to push the mower along the ground is 191 N. This is the component of the applied force that contributes to the forward motion of the mower, while the remaining vertical component is directed perpendicular to the ground and does not assist in pushing the mower forward.

By exerting a force of 250 N along the handle at a 40° angle, the student effectively applies 191 N of force to push the mower along the ground, ensuring efficient use of their effort while considering the environmental impact.

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The height that will illustrate the distance will be d = 6.36m

Based on the information given, the length of the vine will be:

L = ✓(16² + 27.7)²

L = 32m

The velocity of Jane when she reaches position B will be:

V = ✓2gh

V = ✓(2 × 9.8 × 4.3)

V = 9.18m/s

We will apply the conversation of momentum. This will be:

50 × 9.18 = (50 + 80)V1

V1 = 3.53m/s

Therefore, the height that will illustrate the distance will be:

31.36² + d² = 32²

d² = 32² - 31.36²

d = 6.36m

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