Explanation:
SI LA PRESIÓN ES LA MISMA ENTONCES:
P = 2500 N/\(0.060 m^{2}\) = 41667 Pa
F2 = 41667 Pa(\(0.18 m^{2}\)) = 7500 N
The force is exerted on a second piston will be 7500N.
What is pressure?The pressure is the amount of force applied per unit area.
Pressure p = Force/Area
Given is a force of 2500 N is exerted on a piston that has an area of 0.060 m². Area of the second piston is 0.18m².
The pressure will be same for both the piston
P1 =P2
F1/A1 = F2/A2
Put the values, we get
2500 /0.060 = F2/0.18
F2 = 7500 N
Hence, force exerted on the second piston is 7500 N.
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A certain quantity of a liquid has a volume of 10cm at 20°C. Calculate its volume at 50°C, if it’s cubic expansivity is 10^(-3) K^(-1)
Answer:
10.3 cm³
Explanation:
From the question given above, the following data were obtained:
Original volume (V₁) = 10 cm³
Initial temperature (θ₁) = 20 °C
Final temperature (θ₂) = 50 °C
Cubic expansivity (γ) = 10¯³ K¯¹
Final volume (V₂) =?
γ = V₂ – V₁ / V₁(θ₂ – θ₁)
10¯³ = V₂ – 10 / 10( 50 – 20)
10¯³ = V₂ – 10 / 10(30)
10¯³ = V₂ – 10 / 300
Cross multiply
10¯³ × 300 = V₂ – 10
0.3 = V₂ – 10
Collect like terms
0.3 + 10 = V₂
10.3 = V₂
V₂ = 10.3 cm³
Thus, the volume at 50 °C is 10.3 cm³
water flows in a pipe of a terminal of A1=0.02 m2 with a speed of V1=2 m/s. At the second end of the pipe A2=0.04 m2, the speed of flow is V2=_______m/s
A series circuit consists of a 0.55 H inductor with an internal resistance of 8.0 Ω connected in series with a 4-Ω resistor, a switch, and a 12 V battery.(a) When the switch is closed, what is the initial current through the 4-Ω resistor?(b) After the switch has been closed, what is the maximum current in the 4-Ω resistor?
Resist are in series, so the total resistance R= 8Ω+4Ω=12Ω
Therefore, the maximum current in the 4Ω resistors is I = E/R
I = 12V/12Ω = 1A I = 1A
But
When the switch is closed, initially. The inductor behaves as an open. Circuit. Therefore, the current in the 4Ω resistor is zero
Hence,
(a) At initial, I = OA
(b) after a very long time, I = 1A
A practical electrical energy source that is a linear circuit can be represented as an ideal voltage source in series with an impedance according to Thévenin's theorem. This impedance is called the internal resistance of the source. Internal resistance refers to the resistance to current flow provided by the cells and the battery itself, resulting in heat generation.
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What is the period of a satellite in a circular orbit just above the surface of the Moon? The Moon’s mass is 7.36 × 1022 kilograms and its radius is 1.738 × 106 meters.
Answer:
F / m = a = G M / R^2 formula for gravitational attraction
a = ω^2 R formula for centripetal force for an object with radius R
G M / R^2 = ω^2 R equating accelerations
ω = (G M / R^3)^1/2
ω = 2 pi f = 2 pi / P for circular motion
P = 2 pi (R^3 / (G M))^1/2
R^3 / (G M) = (1.738E6)^3 / (6.67E-11 * 7.36E22) = 1.07E6
P = 6.28 * 1034 sec = 6500 sec = 1.80 hrs
Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.
No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.
This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.
i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.
ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.
The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.
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Which describes the spacing of the magnetic field lines near a long straight wire carrying current?
a) The spacing increases as the distance from the wire increases.
b) The spacing decreases as the distance from the wire increases.
c) The spacing is uniform.
The spacing of the magnetic field lines near a long straight wire carrying current is B, The spacing decreases as the distance from the wire increases,
A magnetic field is a field of energy that surrounds a magnet and allows it to attract or repel other magnets. Electrically charged particles create a magnetic field. Magnetic fields are used in many different applications, including medical equipment, power plants, and communication technology.Along the length of the wire carrying a current, the magnetic field lines form concentric circles around it. Because the field lines are uniformly spaced, the field lines are said to be uniform.
The direction of the magnetic field lines surrounding the wire is given by the right-hand rule, with the direction being determined by the direction of the current flowing through the wire. The spacing of the magnetic field lines near a long straight wire carrying current decreases as the distance from the wire increases.
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A relief plane flying horizontally at 65.0 m/s is delivering a
food package to people stranded on an island. If the
island is a horizontal distance of 789 m away,
how high is the plane?
(Unit = m)
22000
Ay (m)
mily
The height of the plane delivering a food package to people stranded on an island is 722.2 m.
Time of motion of the food package
The time taken for the food package to hit the ground level is calculated as follows;
X = vt
where;
X is horizontal distance traveled by the food packagev is horizontal distancet is time of motiont = X/v
t = 789/65
t = 12.14 seconds
Height of the planeh = ¹/₂gt²
where;
h is height of fall of the food package which is height of the planet is time of motion of food packageg is acceleration due to gravityh = (0.5)(9.8)(12.14²)
h = 722.2 m
Thus, the height of the plane delivering a food package to people stranded on an island is 722.2 m.
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Answer:
722.2
Explanation:
Question 3 of 5What could you do to increase the electric force between two chargedparticles by a factor of 16?A. Reduce one particle's charge by a factor of 16.B. Reduce one particle's charge by a factor of 4.C. Increase one particle's charge by a factor of 16.O D. Increase one particle's charge by a factor of 4.
Explanation
the force between 2 charges is given by the formula:
\(\begin{gathered} F=\frac{Kq_1q_2}{r^2} \\ where \\ q_i\text{ is the charge on object i} \\ r\text{ is the distance between the charges} \\ K=Coulomb\text{ constant=8.9875*10}^9N*\frac{m^2}{c^2} \end{gathered}\)then,we can check every option and compare the result to the original, hence
Step 1
a)option A
reduce one particle's charge by a factor of 16
so
\(q^{\prime}_1=\frac{q_1}{16}\)now, replace
\(\begin{gathered} F=\frac{Kq_1q_2}{r^2} \\ F_A=\frac{K\frac{q_1}{16}q_2}{r^2}=\frac{1}{16}\frac{Kq_1q_2}{r^2} \\ F_A=\frac{1}{16}(original) \\ F_A=\frac{1}{16}\frac{Kq_1q_2}{r^2} \end{gathered}\)therefore, option A works
Step 2
hii i am satyam from India and i m having doubt in this question according to me answer should be 20 % but in answer key it's 21 % how??
The formula relating kinetic energy and momentum of a particle is expressed as
KE = p^2/2m
let the actual momentum be p. Since the error measurement is 10%, the measurement of the momentum would be
p + 0.1p = 1.1p
Percentage error in the measurement of the kinetic energy is obtained by the formula,
% error = (KEf - KEi)/KEi x 100
where
KEf is the final kinetic energy measured error
KEi is the initial kinetic energy measured without error
Thus,
% error = [(1.1p)^2/2m - p^2/2m)]/p^2/2m x 100
% error = p^2/2m(1.1^2 - 1)/(p^2/2m) x 100
% error = 100(1.1^2 - 1)
% error = 21%
write at least 5 sentences answering the question, "How does the height of a ramp affect the speed of an object rolling down that ramp?"
Newton's second law allows us to find the effect of the height of the ramp on the movement of the block.
When the height increases the acceleration of the body increases Tthere is a minimum height for which the block does not slide down the ramp
Newton's second law says that force is proportional to the product of mass and the acceleration of bodies
F = m a
Where F is the net force, m and a are the mass and acceleration of the body, the bold letters indicate vectors.
To use this expression we must set a reference frame and apply Newton's second law to each axis.
The free body diagram is a method to visualize the forces in a problem without the details of the shape of the objects, in the attached we can see a free body diagram, the x axis is placed parallel to the ramp with the positive direction in the direction of motion and the y-axis in the vertical direction
Let's write Newton's second law for each axis
y-axis
\(N - W_y\) = 0
N = mg cos tea
Let's write the expression for the force
x-axis
\(W_x - fr = ma\)
mg sin θ - fr = m a
The friction force is the macroscopic sum of all the microscopic forces between the two surfaces and can be written
fr = μ N
fr = μ mg cos θ
We substitute
a = g (sin θ - μ cos θ
This expression gives the form of the block's acceleration as it descends the ramp
The height of the ramp can be found with trigonometry
sin θ = h / L
h = L sin θ
Let's write our equations
a = g ( sin θ - μ cos θ)
h = L sin θ
We substitute
a = g (h / L - μ cos θ )
Let's analyze this expression;
It is observed that the acceleration increases with the height of the ramp
When the height increases, the angle of the ramp must increase, therefore the second term, which is a cosine function, decreases, so the acceleration also increases.
The angle decreases so much the height of the ramp decreases with the second term it increases to the point where the acceleration becomes zero
Consequently, using Newton's second law we can find the effect of the height of the ramp.
When the height increases the acceleration of the body increases There is a minimum height for which the block does not slide down the ramp
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Why is it necessary to use oil in conjunction with the 100x lens but not the other objectives?
Because the refractive indexes of the immersion oil and the glass microscope slide are the same; the oil prevents the refraction of the incoming light rays.
An invisible space is present between the slide and the lens that contains air.
When the light rays fall on the slide and lens they might get refracted due to air present between them.
If the rays get refracted then the diameter of the objective lens will expand further.
So in order to prevent the refraction of light, it is very important to lubricate the surface of the lens because glass and oil have same refractive index and without oil the light rays refract from their original path.
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im confused on number one
Explanation:
v=?, u=0, a=?, S=22m.
Using the formula, S=ut+½at²
22={0×5}+(½.a.5²)
22=½.a.5²
a=44/25 = 1.76m/s².
Therefore, net force = work done = ma = 48×1.76 = 84.48N.
therefore, power = work done/time = 84.48/5 = 16.896W.
hope this helps you.
PLS HELP I WILL GIVE BRAINLYEST!!!
Given the equation P2 = A3, what is the orbital period, in days, for the planet Venus? (Venus is located 0.72 AU from the sun?) (2 points)
Group of answer choices
72 days
225 days
500 days
5,375 days
Answer:
225
Explanation:
Answer:
I am doing the test now let me make sure then I tell you ok, just a second..
225 is correct
Explanation:
HELP PLEASE!!! I HAVE TO GET THIS IN QUICK!!
How many layers of the Earth are there, and what are these layer's names in order from centermost, to outermost, Brainliest for best answer.
A 24 kg object, initially moving at 20 m/s, is slowed by an applied force of 20 N to a final velocity of 16 m/s. How much time did this take?
Answer:
Explanation:
Turtle ba lls
Answer:
4.8 seconds
Explanation:
Ft=change in momentum
Initial momentum=mv=24*20=480 kg*m/s
new momentum=mv=24*16=384 kg*m/s
change in momentum=96 kg*m/s
Ft=change in momentum
20(t)=96
t=4.8 seconds!
Consider that water is pumped 27 mi from a reservoir (Reservoir A) at elevation 200ft to a second reservoir (Reservoir B ) at elevation 367ft. The pipeline connecting the reservoirs has a diameter of 58 in and is constructed of concrete with an (f=0.015 ). If the flow is 27 , what is the head developed by the pump (Hp)?
The head developed by the pump is 194.69 ft. Given that the diameter of the pipeline connecting Reservoir A to Reservoir B is 58 inches and constructed of concrete having an f value of 0.015 and flow is 27.
To calculate the head developed by the pump, the following formula is used:
\(Hp = (Q × H × ρ) / (3.14 × d^5 × f)\)
where
\(Q = Flow of water in the pipeline = 27H = Total head developed in the pipeline = Head at Reservoir A - Head at Reservoir\)
\(Bρ = Density of water = 62.4 lb/ft3d = Diameter of the pipeline = 58 in = 4.83 ftf = Friction factor = 0.015.\)
Substituting the values in the formula, we get
\(Hp = (27 × (200 - 367) × 62.4) / (3.14 × (4.83)^5 × 0.015)\)
\(Hp = - 190,567.8 / - 1.576Hp = 120,940.34/1000Hp = 194.69 ft .\)
Hence, the head developed by the pump is 194.69 ft.
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in the absence of friction, how much work would a child do while pulling a 12 k g wagon a distance of 1.2 m with a 22 n force? a) 18 j b) 30 j c) 14 j d) 26 j
The work done by the child while pulling the 12 kg wagon a distance of 1.2 m with a 22 N force, in the absence of friction, is 26 J (joules).
The work done is calculated using the formula:
Work = Force × Distance × cos(θ)
Where:
Force is the applied force (22 N)
Distance is the displacement (1.2 m)
θ is the angle between the force and the direction of displacement (assuming it is 0 degrees, as there is no information provided regarding the angle)
Plugging the given values into the formula:
Work = 22 N × 1.2 m × cos(0) = 26 J
Therefore, the child would do 26 joules of work while pulling the wagon.
In conclusion, the correct answer is d) 26 J. The child would do 26 joules of work when pulling the 12 kg wagon a distance of 1.2 m with a 22 N force in the absence of friction. The calculation is based on the work formula, taking into account the given values.
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Which of the following most likely describes a Group 10 element?
O Good conductor of heat
O Gas at room temperature
O A member of the carbon group
O Poor conductor of electricity
Answer:
A. Good conductor of heat
Explanation:
The group 10 elements are a group of chemical elements as part of VIII elements and they include nickel, platinum, palladium etc. These group of chemical elements are all d-block transition metals, highly ductile and lustrous and are mostly white to light grey in color.
The statement which most likely describes a Group 10 element is that they are good conductor of heat because they have some of the chemical and physical properties of metals.
if a river has an average width of 15 m, an average depth of 5 m, and is flowing with a velocity of 2 m/s, what is its discharge?
According to the given statement a river has an average 3 * 10⁵ W is its discharge.
What is velocity definition with example?The scalar metric of speed and direction of motion is known as velocity. The speed that an object goes in one side is known as its velocity. Speed may be used to calculate both the vehicle speed traveling north just on main freeway and the velocity of a explosion bursting in space.
Briefing:Water's speed is 2 m/s.
Flow area = 5m x 15m = 75m²
Water has a density of 1000 kg/m³
The volume of water flowing per second in the continuity equation is written as v=Av.
Hence, mass of water m=vρ=Avρ
K.E. = 1/2 mv² = 1/2 Avρ²
K.E. = 1/2 Avρ³
ρ = 1/2 Avρ³
ρ = 1/2 * 75 * (2)³ * 1000
ρ = 3 * 10⁵ W
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Which one is it i need this for my credit recovery
The mass of the train is 450000 kg.
Calculate the maximum possible speed of the train at the end of the first 4.0km of the
journey.
The maximum possible speed of the train at the end of the first 4.0 km of the journey is 0 m/s.
To calculate the maximum possible speed of the train at the end of the first 4.0 km of the journey, we can apply the principle of conservation of energy.
Assuming there are no external forces like friction or air resistance, the initial potential energy of the train will be converted into kinetic energy.
The potential energy (PE) of the train at the beginning of the journey can be calculated as PE = mgh, where m is the mass of the train, g is the acceleration due to gravity (approximately \(9.8 m/s^2\)), and h is the height difference (in this case, we assume it to be zero).
The kinetic energy (KE) of the train at the end of the 4.0 km journey can be calculated as \(KE = (1/2)mv^2\), where v is the velocity of the train.
Since the potential energy is converted into kinetic energy, we can equate the two expressions:
PE = KE
\(mgh = (1/2)mv^2\)
Simplifying and canceling out the mass:
\(gh = (1/2)v^2\)
Substituting the values, \(g = 9.8 m/s^2\)and h = 0, we get:
\((9.8 m/s^2)(0) = (1/2)v^2\)
Simplifying further:
\(0 = (1/2)v^2\)
This equation tells us that the maximum possible speed of the train at the end of the first 4.0 km of the journey is 0 m/s.
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please help! need a answer as quick as possible please. i need help with questions 1 and 2 ! thank you
Answer:
1.)When you arrive from school and you smell cookies baking in the kitchen your brain will tell you that you are hungry and that you should go to the kitchen at that point your sense organs like your nose helps you to detect that something is baking(cookies)and your nervous system (brain)will tell you that you are hungry and it will command/direct your brain to go to the kitchen then for you to eat the cookies and drink the milk the digestive system is going go help you to chew,swallow and digest the food which has been taken and when you also run to the kitchen at the beginning your brain will direct your skeletal and muscular system because the skeletons and muscles work hand in hand,and when you finish your meal the body will circulate some nutrients or minerals from the food or snack taken to other parts of the body for energy.
2.)When you sleep the whole body is asleep except the heart which needs to continue circulating blood around the whole system and sometimes the brain may not rest when you are sleeping it may continue to do it's work that's why some people usually sleep walk or sleep talk,it means the brain is not at rest and still doing some things....Thank you for the question I hope it is very useful to you.
A ball has 200 J of potential energy when it is on a shelf. Explain what happens to the potential energy and the kinetic energy as the ball falls, and find the amount of kinetic energy the ball has at the instant it hits the floor.
Answer:
0
Explanation:
Potential energy of the body is converted to kinectic enery as it falls thus the formula massx gravity x height at the instant it hits the ground the height is 0 putting this into the equation the potential energy is 0 since the potential energy is converted to kinectic energy potential energy is equal to kinectic energy then the kinectic energy at the instant it hits the ground is 0
As the ball falls, its potential energy starts to change into kinetic energy. When the ball hits the floor, its kinetic energy will be 200J.
What is energy?A body's capacity for work is measured in terms of energy. It cannot be produced or eliminated. There are numerous types of energy, including thermal, electrical, fusion, electrical, and nuclear. Energy has the ability to change its forms.
Given parameters:
Potential energy of the ball when it is on a shelf, V = 200 J.
When the ball starts to fall, its potential energy due to gravity starts converting into kinetic energy. And as much the ball goes down, its kinetic energy will increase and potential energy will decrease.
At the instant the ball hits the floor, its potential energy due to gravity becomes zero and totally converted to kinetic energy.
Hence, the amount of kinetic energy the ball has at the instant it hits the floor is 200 J.
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A body on the surface of the earth weichs 400 Ib. The radius of the earth is about 4,000 miles. If this same body were placed on a 4,000 mile high tower, its weight would be a. 100 lbs b. 200 lbs c. 400 lbs d. 800 lbs e. 16,000 lbs
Option a is correct.
F=GMm/R²
where F is the gravitational force or weight
G is the universal constant of gravitation
M is the mass of Earth
m is the mass of the object
R is the distance between the center of the earth and the object
Given,
initial distance R =4000miles
weight at surface of the earth F=400lb
Let the force be F' for a distance R' from earth's center.
Here R' = radius+ height of the tower = R+4000 miles = 4000 + 4000 = 8000 miles.
Since the other terms in the formula remain constant, the new weight F' can be calculated as follows:
F'/F = R²/R'(otherwise the inverse square law in gravitation)
F'/400=(4000)²/(8000)²
F' = 100 lb
Thus option a is correct.
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The weight of the body on a 4000-mile high tower would still be 400 lbs.
Explanation:The weight of an object depends on the gravitational acceleration at its location. On the surface of the Earth, the gravitational acceleration is approximately 32 ft/s2. Therefore, a 400 lb body on the Earth's surface would weigh 400 lbs. If the body were placed on a 4000-mile high tower, it would be much farther from the center of the Earth and experience a weaker gravitational pull. The weight of the body would decrease as the square of the ratio of the radii of the tower and the Earth. So, the weight on the tower would be:
Weight on the tower = (400 lb) * (4000 mi/4000 mi)2 = 400 lb * 1 = 400 lb
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A 7. 50g-bullet has a speed of 555 m/s as it leaves the muzzle of a rifle. If the barrel of the rifle is 0. 950 m, what is the average force exerted on the bullet by the ammunition?.
The average force exerted on the bullet by the ammunition is 1215.88N
From the question above, It is given that,
Mass of the bullet, m = 7.50 g
Initial speed of the bullet, u = 0
Final speed of the bullet, v = 555 m/s
We need to find the force exerted on the bullet while it was traveling down the 0.950m length of the barrel of the rifle. Let:
a is the acceleration of the bullet. So,
v² - u² = 2ad
v² = 2ad
a = v²/2d
a = 555²/2*0.950
a = 162118.42m/s²
Let F be the force exerted. It is given by:
F = Ma
F = 7.5 * 10⁻³ * 162118.42
F = 1215.88N
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F = 1590.87 N
So, the constant force exerted on the bullet is 1590.87 N. Hence, this is the required solution.
Most limited slip differentials transfer torque through (A) the differential gears or (B) one or two clutch stacks. Which is correct?
Select one:
a. A only
b. B only
c. Both A and B
d. Neither A nor B
The correct answer is (b) B only. Most limited slip differentials transfer torque through one or two clutch stacks.
The correct answer is (b) B only. Most limited slip differentials transfer torque through one or two clutch stacks. These clutch stacks engage and limit the speed difference between the two wheels, allowing torque to be distributed to the wheel with more traction. Differential gears, on the other hand, are used in open differentials and do not provide torque transfer to the wheel with more traction. Most limited slip differentials use one or two clutch stacks to transfer torque. By engaging and reducing the speed differential between the two wheels, these clutch stacks enable torque to be directed to the wheel with better grip.
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What is the velocity of an object that is falling to Earth for 8 seconds? 1.225 m/s b. 9.8 m/s2 c. 78.4 m/s d. 0.816 m/s2
Answer:
Explanation:
Just use the acceleration equation here:
\(a=-\frac{v}{t}\) where a = -9.8; velocity is also negative because it's falling down and down is negative. Filling in:
\(-9.8=-\frac{v}{8}\) so
-9.8(8) = -v and
v = 78.4 m/s downward (the word "downward" takes place of the negative sign)
Two microphones are connected to a
computer. The microphones are held 2.0 m
apart. Harold rings a bell, and the computer
shows that it took the sound 0.0058 seconds
to travel from one microphone to the other.
What is the velocity of the sound wave?
Round your answer to one decimal place.
Answer:
344.8 m/s
Explanation:
Looking for speed of sound = meters / sec
2 meters / .0058 seconds = 344.8 m/s
The velocity of the sound wave is 344.8 meter/second.
What is sound?A sound is a vibration that travels as a mechanical wave across a medium. It can spread through a solid, a liquid, or a gas as the medium. Solids carry sound the quickest, liquids somewhat more slowly, and gases the least slowly.
According to physics, sound is described as a vibration that travels through a material like a gas, liquid, or solid as an audible wave of pressure.
Given parameters:
The microphones are held 2.0 m apart.
it took the sound 0.0058 seconds to travel from one microphone to the other.
Hence, the velocity of the sound wave is = distance travelled/time taken
= 2.0 meter / 0.0058 second
= 344.8276 meter/second.
Hence, the velocity of the sound wave is 344.8 meter/second ( after rounding answer to one decimal place.).
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a block of mass m containing a net positive charge q is placed on a smooth horizontal table which terminates in a vertical wall as shown in figure (29-e2). the distance of the block from the wall is d. a horizontal electric field e towards right is switched on. assuming elastic collisions (if any) find the time period of the resulting oscillatory motion. is it a simple harmonic motion ?
In conclusion, the time period of the resulting oscillatory motion is T = 2d/v, and the motion is not simple harmonic.
When the electric field is switched on, the charged block will experience a force in the direction of the electric field, i.e., towards the right. This force will cause the block to move towards the wall. If the block collides elastically with the wall, it will rebound with the same speed but in the opposite direction.
Let the velocity of the block just before collision with the wall be v. The time taken by the block to travel a distance d to reach the wall is given by t = d/v. The time taken by the block to return to its initial position is also t, as the block moves with the same speed v during the rebound. Therefore, the time period of the oscillatory motion is T = 2t = 2d/v.
Now, let's analyze whether the motion is simple harmonic or not. For simple harmonic motion, the restoring force should be proportional to the displacement from the equilibrium position and should be directed towards the equilibrium position. In this case, the restoring force is provided by the electric field, which is always directed towards the right. Therefore, the motion is not simple harmonic as the restoring force is not proportional to the displacement from the equilibrium position.
In conclusion, the time period of the resulting oscillatory motion is T = 2d/v, and the motion is not simple harmonic.
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