A force f is applied horizontally to block A of mass m1 which is in contact with a block B of mass m2. If the surfaces are frictionless, the force exerted by A on B is given by?

Explanation:

When a large rolling boulder hits a smaller rolling boulder, momentum is conserved. According to the law of conservation of momentum, the total momentum of a system remains constant if there are no external forces acting on it. In this case, the system consists of the two boulders.

During the collision, the larger boulder transfers some of its momentum to the smaller boulder, causing it to move forward. However, the larger boulder also continues to move forward with some of its original momentum. Therefore, the total momentum of the system before and after the collision remains the same.

remember that momentum is a vector quantity, meaning it has both magnitude and direction. The direction of momentum for each boulder will depend on their respective velocities and massez.

Answer:

The larger boulder transfers some of its momentum to the smaller boulder, but it keeps going forward, too. Therefore, option 5 is the correct response.

Explanation:

According to the law of conservation of momentum, the total momentum of a closed system remains constant before and after the collision, as long as no external forces are acting on it. When a large rolling boulder collides with a smaller rolling boulder, conservation of momentum takes place in the system.

During the collision, the larger boulder transfers some of its momentum to the smaller boulder through the force of the impact. This transfer of momentum causes the smaller boulder to gain some momentum and start moving in the direction of the collision

However, the larger boulder also retains some of its momentum and continues moving forward after the collision. Since the larger boulder typically has greater mass and momentum initially, it will transfer some momentum to the smaller boulder while still maintaining its own forward momentum.

Therefore, in the collision between the large rolling boulder and the smaller rolling boulder, momentum is conserved as both objects experience a change in momentum.

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The frequency of radiation is inversely proportional to the wavelength. The wavelength of the light with the frequency 9.3 × 10¹⁸ Hz is 3.22 × 10³⁷ pm.

The number of oscillations or repeats of a cycle is defined as the frequency of light. All light waves travels at the same speed no matter its frequency. The light with a smaller frequency has a longer wavelength.

The equation connecting the frequency and wavelength of the light is given as:

c = νλ

ν - Frequency of radiation

λ - Wavelength of radiation

λ = 3.00 × 10⁸ / 9.3 × 10¹⁸

= 3.22 × 10²⁵ m

1 pm = 10⁻¹² m

So 3.22 × 10²⁵ m = 3.22 × 10²⁵ / 10⁻¹²

λ =  3.22 × 10³⁷ pm

Thus the wavelength of light is 3.22 × 10³⁷ pm.

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Given:

ratio of energy is 2√2 : √3

Apply:

Where:

q = charge of proton

v= speed of proton

r= radius of circular path

T= time period of revolution

Kinetic energy (K)

K= 1/2mv^2

From both equations:

Tα1/k

K1:K2 = 2√2 : √3

T1:T2 = √3:2√2

Answer: √3:2√2

At the instant where the cart leaves the ramp, the velocities of the ramp and the cart are relative to the ground as \((mgh/m+M)^{1/2}\) and \((2gh(m+M)/3m)^{1/2}\) respectively.

The velocities of the ramp and cart relative to the ground at the instant the cart leaves the ramp can be calculated using conservation of energy and momentum. The velocity of the cart relative to the ground can be found using conservation of energy as follows:

mgh = 1/2mv² + 1/2Iw²

where m is mass of cart, g is acceleration due to gravity, h is height of ramp, v is velocity of cart relative to ground, I is moment of inertia of ramp about its center of mass and w is angular velocity of ramp about its center of mass.

The velocity of ramp relative to ground can be found using conservation of momentum as follows:

mv = (m+M)V

where M is mass of ramp and V is velocity of ramp relative to ground.

Solving these equations simultaneously gives:

\(V = mgh/(m+M)^{1/2}\)

\(v = 2gh(m+M)/(3m)^{1/2}\)

where h = height of ramp.

Therefore, at the instant when cart leaves the ramp, velocity of cart relative to ground will be \((2gh(m+M)/(3m))^{1/2}\) and velocity of ramp relative to ground will be \((mgh/(m+M))^{1/2}\).

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Answer:

Circuit

Explanation:

because a roughly circular line, route, or movement that starts and finishes at the same place.

This question can be solved by using the concepts of electrical energy, electricity, circuit, and electric current.

The flow of electricity from one place to another is called "Electrical Energy".

The electric current or electricity is defined as the rate of flow of electric charges from one point to another point, along a path known as a circuit. Electrical energy is caused by the movement of electric charges or the electric current from one point to another point of the circuit.

Therefore, this flow of electricity or electric current from one place to another place is termed Electrical Energy.

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The attached picture shows examples of electrical energy.

Answer:

2970dB

Explanation:

30 x99=2970

Answer:

Gravitational Energy

Answer:

newton's first law of motion

Explanation:

this is because newton's first law of motion states that every object will continue in its state of rest or uniform motion in a straight line unless a resultant force acts on it so...

isn't this similar to the law of inertia?

yes it is

hope this helps

Answer:

Please find attached the plot of distance against time created with Microsoft Excel

Explanation:

The table of the information about the train journey is presented here as follows;

\(\begin{array}{ccc}Station&Distance \ travelled/\,km&Time \taken \, / \, minutes \\Ayton&0&0\\Beeston&20&30\\Seatown&28&45\\Deeville&36&60\\Eton&44&70\end{array}\)

From the table data, the distance against time plot can be created by entering the data into a spreadsheet such as Microsoft Excel, then selecting a Chart option in the Ribbon under the Insert Menu after selecting the data

The average acceleration vector of the ball is approximately 9.8 m/s² downward.

When the ball is thrown upward, it experiences a constant acceleration due to gravity pulling it downward. This acceleration is equal to 9.8 m/s², which is the acceleration due to gravity near the surface of the Earth. Since the ball reaches the same speed in the downward direction when it returns to the hand, we can conclude that its average acceleration vector is also 9.8 m/s² downward.

When the ball is thrown upward, it moves against the force of gravity. As it moves upward, the gravitational force slows it down until it reaches its highest point. At this point, the ball momentarily stops before reversing direction and falling back downward.

The force of gravity then acts in the same direction as the ball's motion, causing it to accelerate downward. The acceleration due to gravity remains constant throughout the ball's motion, regardless of its direction.

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Answer:

A.  It is zero.

Explanation:

D Later in the day, more power is developed in lifting each box. 12 A manometer is used to indicate the pressure in a steel vessel, as shown in the diagram. What value does the liquid manometer give for the pressure in the vessel? It is zero

Answer:

Copper is the best conductor

Suppose we see the spectral lines to a distant star doppler shifted to smaller wavelengths. This tells us that the star is moving toward the observer.

The Doppler effect, also known as the Doppler shift, is a phenomenon in which waves, such as sound or light waves, shift in frequency when their source and observer are moving relative to one another. As a result, the wavelength appears to be altered when the source of the waves approaches or recedes from the observer.

In this situation, if we see the spectral lines to a distant star Doppler shifted to smaller wavelengths, it suggests that the star is moving towards the observer. It is caused by the Doppler effect, which alters the frequency of light when its source is moving relative to the observer.

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To determine the velocity at which a 300 W motor will pull a mass when applying a force of 13.9 N, we need to consider the relationship between power, force, and velocity.

Power (P) is defined as the rate at which work is done or energy is transferred. It can be calculated using the formula:

P = F * v,

where P is power, F is force, and v is velocity.

Given that the power of the motor is 300 W and the force applied is 13.9 N, we can rearrange the formula to solve for velocity:

v = P / F.

Substituting the given values, we have:

v = 300 W / 13.9 N.

Calculating this expression gives us the velocity at which the motor will pull the mass.

v = 21.58 m/s.

Therefore, the velocity at which the 300 W motor will pull the mass when applying a force of 13.9 N is approximately 21.58 m/s.

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Hello!

a = 3 m/s²

Use the equation F = m · a (Newton's Second Law) to solve.

We are given the force and mass, so plug these values into the equation:

60 = 20 · a

60 = 20a

Divide both sides by 20:

60/20 = 20a/20

a = 3 m/s²

The minimum number of cycles required for the engine to lift the 500 kg rock through a height of 100 m is 1 cycle.

To determine the minimum number of cycles, we can use the work-energy principle. The work done on an object is equal to the product of the force applied and the distance over which the force is applied. In this case, the work done on the rock is equal to the gravitational potential energy gained.

The gravitational potential energy (PE) can be calculated using the formula PE = mgh, where m is the mass of the rock, g is the acceleration due to gravity, and h is the height.

In this scenario, the work done in each cycle is equal to the change in potential energy, which is mgh. Therefore, the total work done by the engine is equal to the product of the work done in each cycle and the number of cycles (W = mgh × N).

We can rearrange the equation to solve for the number of cycles (N):

N = W / (mgh)

N = (mgh) / (mgh)

N = 1

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The scenario best matched by the velocity-time graph shown is:

d. The object has a constant speed.

What is Velocity ?

Velocity is a vector quantity that describes the rate of change of an object's position with respect to time, in a particular direction. It is a measure of how fast and in which direction an object is moving. Velocity is typically measured in meters per second (m/s) or other units of distance per unit of time, such as feet per second (ft/s) or kilometers per hour (km/h).

In physics, velocity is often used in the context of describing the motion of objects, such as cars, airplanes, and planets. It is also an important concept in calculus and other areas of mathematics, where it is used to describe the rate of change of a function with respect to its input.

The reason for this is that the velocity-time graph shows a straight line with a constant slope, which means that the velocity (speed and direction) of the object is not changing over time. In other words, the object is moving at a constant speed.

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Seasonal changes impact the environment. is There are only two factors that affect your environment.

Seasonal affective disorder, a clinically diagnosed syndrome, is believed to represent the morbid extreme of a spectrum of seasonality. Two types of seasonality have been clinically described: one characterized by a winter pattern and a second by a summer pattern of depressive mood disturbance.

Seasonality is a characteristic of a time series in which the data experiences regular and predictable changes that recur every calendar year. Any predictable fluctuation or pattern that recurs or repeats over a one-year period is said to be seasonal.

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Answer:

9miles average speed and 23 seconds

Answer:

r = 1.999m

Explanation:

E = kq/r²

10 = 9*10^9*q/1²

q = 10/9*10^9

q = 1.11*10^-9

then at what distance

r² = kq/E

r² = 9*10^9*1.11*10^-9/2.5

r² = 9.99/2.5

r² = 3.996

r = √3.996

r = 1.999m

Answer:

22.777777777777 m/s

Explanation:

Since 1 kilometer is 1000 meters, then 82 km is 82000 meters. Since one hour is the same as 3600 seconds, then the answer is pretty simple: 82000/3600 or 820/36. That gets you 22.77777 or 22.78. Hope this helps

Answer:

False.

Explanation:

The plants rely on animals to spread their seeds, thats why they make fruits so the animals eat em, the seeds are strong enough to survive the animals stomach and come out the other end.

The number of photons in the pulse is 1.21 × 1022.

The energy of a photon can be calculated using the equation:

E = hf, where

E is the energy of a photon,

h is the Planck's constant, and

f is the frequency of the light.

Then, using the equation c = λf, where

c is the speed of light,

λ is the wavelength of the light and

f is the frequency of the light, the frequency of the light can be determined.

Planck's constant (h) is a fundamental constant in quantum mechanics that relates the energy of a photon to its frequency.

Its value is 6.626 × 10-34 joule seconds (J·s).

The frequency of the light is:

f = c / λ

= 3.00 × 108 / 480 × 10-9

= 6.25 × 1014 Hz

The energy of the photon can be calculated:

E = hf

= 6.626 × 10-34 × 6.25 × 1014

= 4.14 × 10-19 J

The number of photons can be determined by dividing the energy of the pulse by the energy of a photon:

n = E / E_photon

= 5.0 × 103 / 4.14 × 10-19

= 1.21 × 1022 photons

Therefore, the number of photons in the pulse is 1.21 × 1022.

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Answer: If the mass of the object is 178 kg: k = 9.44*10^-5 N/m

Answer for the mass being 82 kg is not complete, because G was not given.

Explanation:

If the mass of the object is 178 kg:

The mass of object (m) = 178 kg

Length of tunnel (l) = 2640 km

***The minimum displacement (its amplitude) of object from its mean position,

A = 2640/2 = 1320 km = 1.320 * 10^6 m

Mass of planet (M) = 4.48 * 10^24 kg

Its Radius (R) = 8.26 * 10^6 m

Gravitational constant (G) = 6.67259 * 10^-11 Nm^2/kg^2

Now, restoring force for given hormonic motion will be

Vector of F = -((GMm)/R^3) * x

Comparing with, vector of F = -k*x, we get

k = (GMm)/R^3

k = (((6.67259*10^-11)*(4.48*10^24)*178)/(8.26*10^6)^3)

k = ((5320.99017*10^(-11+24))/(563.559976*10^18))

k = 9.44*10^(13-18)

k = 9.44*10^-5 N/m

If the mass of the object is 82 kg:

The mass of object (m) = 82 kg

Length of tunnel (l) = 2430 km

***The minimum displacement (its amplitude) of object from its mean position,

A = 2430/2 = 1215 km = 1.215*10^6 m

Mass of planet (M) = 4.16 * 10^24 kg

Its Radius (R) = 7 * 10^6 m

Gravitational constant (G) not given in the photo

Now, restoring force for given hormonic motion will be

Vector of F = -((GMm)/R^3) * x

Comparing with, vector of F = -k*x, we get

k = (GMm)/R^3

k = ((G*(4.16*10^24)*82)/(7*10^6)^3)

Remember that when multiplying two values with exponents, you add the exponents together!

k = ((3.4112*10^26 * G)/(3.43*10^20))

Insert G to solve!

Lets find

\(\\ \sf\longmapsto Modulus\:of\:elasticity=\dfrac{Stress}{Strain}\)

\(\\ \sf\longmapsto \dfrac{\left[ML^{-1}T^{-2}\right]}{\left[M^0L^0T^0\right]}\)

\(\\ \sf\longmapsto \left[ML^{-1}T^{-2}\right]\)

Answer:

direction

size

Explanation:

Vectors are physical quantities with both magnitude or size and direction.

Scalars are physical quantities with only size but not direction.

When describing a vector, on must specify its magnitude and direction.

Only the size of scalar quantities are needed to describe them.

Magnetic force on an electron is  2 X 10⁻¹⁹ N,the electric field in the rod is 1.25 V/ m,potential difference between the ends of the rod  0.3 1 V and peed of the rod if the potential difference is 1.0 V is 16m.

By using the formula of motional

Here ,

E Induced emp B - magnetic field,

L Is length of conductor V- velocity

Also, the force Son a positive charge moving in magnetic field is given ask

F = QV*B - -> 2

Here

f - force acting on positively charged

particle V - velocity, 9 7 charge

and B - magicbe freed

(a) The velocity of elections and lode is

same .

By using Eg (2, ie f = q vB sung

by putting the Given value, INengel

f = ( 1 .6022 x 10 ).( 5 * 0.25 ).

= 2 X 10⁻¹⁹ N

(b) In the Equilibrium system the electric force is equals to Magnetic force by putting the values-

E = ( 5 . 0 ) ( 0 25 ) = 1.25 V/ m

( c) By using - E= (0 25 m ) (5m/s )

e = 0. 3 1 V

d )

Again By using EQ1

V=E/BL

=1/( 0 . 25 ) ( 0. 25 )= 16m

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To solve this problem, you can use the equations of motion for rotational motion under constant acceleration:

ωf = ωi + αt --(1)

θ = ωit + 0.5αt^2 --(2)

where ωi is the initial angular velocity, ωf is the final angular velocity, α is the angular acceleration, t is the time elapsed, and θ is the angular displacement.

Using equation (1), we can find the angular acceleration of the wheel:

α = (ωf - ωi)/t

= (30.0 rad/s - 10.0 rad/s)/20.0 s

= 1.0 rad/s^2

Using equation (2), we can find the total angular displacement of the wheel during the 20.0 seconds:

θ = ωit + 0.5αt^2

= 10.0 rad/s × 20.0 s + 0.5 × 1.0 rad/s^2 × (20.0 s)^2

= 400.0 rad

To find the time at which the wheel has undergone half of this angular displacement, we can use equation (2) again:

θ/2 = ωit + 0.5αt^2

Rearranging and solving for t, we get:

t = [(-ωi) ± sqrt(ωi^2 + 2αθ)]/α

Since we are looking for a positive time, we take the positive root:

t = [(-10.0 rad/s) ± sqrt((10.0 rad/s)^2 + 2 × 1.0 rad/s^2 × 400.0 rad)]/1.0 rad/s^2

≈ 12.4 s

Therefore, the answer is B, 12.4 s.