A fish is swimming around the 720-meter perimeter of her pond. If she swims 10 laps in 120 minutes, what is her average speed in m/min

The personality trait which helps you to use straightforward and confident communication with others is referred to as Assertive and is therefore denoted as option D.

This is defined as the process in which information is passed or exchanged from one person or place to another through various means and forms.

Assertiveness is a personality which is characterized by self assuredness without exhibiting aggressiveness in making points clear to other people.It is also known as a straightforward and confident communication with others.

This is therefore the reason why option D was chosen as the most appropriate choice.

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Answer: assertive

Explanation:

Answer:

Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces.

Explanation:

About Jupiter's winds at different heights, the following statements is not correct is option b) The measurements from the Galileo Probe suggest that winds never change in the vertical direction on Jupiter.

The Galileo Probe, which descended into Jupiter's atmosphere in 1995, did conduct wind measurements at different heights on Jupiter (Option A). It provided valuable data on the composition, temperature, and winds of the Jovian atmosphere.

Tracking clouds at different heights can indeed provide information about the vertical structure of winds on Jupiter (Option C). By observing cloud movements and their patterns at various altitudes, scientists can infer the dynamics and circulation of the planet's atmosphere.

The thermal wind equation, which relates the horizontal temperature gradient to the vertical wind shear, is a useful tool for studying the vertical structure of winds on Jupiter (Option D). It helps scientists understand how temperature variations influence the atmospheric circulation and wind patterns.

However, the notion that winds never change in the vertical direction on Jupiter is incorrect. Jupiter's atmosphere is known for its complex and dynamic weather patterns, including powerful jet streams and storms.

The Galileo Probe's measurements and subsequent observations from Earth-based telescopes and other spacecraft have revealed vertical variations in wind speeds and directions, indicating the presence of vertical wind shear and atmospheric disturbances.The correct answer is option b.

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In a non degenerate germanium sample maintained under thermal equilibrium condition near room temperature it is known that ni=1013 cm, no=2po, and Na=0.the majority carrier concentration (n0) is approximately 1.43 x 10^13 cm-3 and the donor concentration (Nd) is 0 since Na = 0.

In a non degenerate germanium sample maintained under thermal equilibrium conditions near room temperature, we have the following information:

ni = 1013 cm^-3 (intrinsic carrier concentration)

n0 = 2p0 (majority carrier concentration)

Na = 0 (acceptor concentration)

Since Na = 0, it means that there are no acceptor impurities present in the germanium sample.

In an intrinsic semiconductor, the product of the majority and minority carrier concentrations is equal to the square of the intrinsic carrier concentration, ni:

n0 × p0 = ni^2

Given that n0 = 2p0, we can rewrite the equation as:

2p0 × p0 = ni^2

Simplifying the equation:

2p0^2 = ni^2

Taking the square root of both sides:

p0 = sqrt(ni^2 / 2)

Substituting the value of ni = 1013 cm-3:

p0 = sqrt((1013 cm-3)^2 / 2)

p0 ≈ 7.17 x 10^12 cm-3

Since n0 = 2p0:

n0 ≈ 2 × 7.17 x 10^12 cm-3

n0 ≈ 1.43 x 10^13 cm-3

Therefore, the majority carrier concentration (n0) is approximately 1.43 x 10^13 cm-3 and the donor concentration (Nd) is 0 since Na = 0.

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The question should be:

In a nondegenerate germanium sample maintained under thermal equilibrium condition near room temperature it is known that ni=1013 cm, no=2po, and Na=0. Determine n and Nd.

Centripetal acceleration ac is the acceleration experienced while in uniform circular motion. It always points toward the center of rotation. It is perpendicular to the linear velocity (tangential speed) v and has the magnitude:

\(a_c = \dfrac{v^2}{R}\)

Solving for v:

\(v = \sqrt{a_c R} = \sqrt{(250\;m/s^2)(0.50\;m)} = 5\sqrt{5}\;m/s \approx 11.18\;m/s\)

The yo-yo’s tangential speed 11.18 m/sec.

The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.

Centripetal acceleration ac is the acceleration experienced while in uniform circular motion. It always points toward the center of rotation. It is perpendicular to the linear velocity (tangential speed) v and has the magnitude:

\(a_{c} = v^2/r\)

Solving for v

\(v = \sqrt{a_{c}r }\) = 11.18 m/sec

The yo-yo’s tangential speed 11.18 m/sec.

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A 1500-kg car moving around 25 m/s collides with a horizontal spring that is initially uncompressed but has a spring stiffness of 2.0?106 n/m as well as a max compress of x = 0.68 meters.

Compress, constrict, contract, inflate, and shrink are a few words that frequently replace the word compress. While all of these phrases refer to "decreasing in bulk or area," compress indicates squeezing over resistance into a constricted area with a certain shape.

Considering that,

The automobile weighs 1500 kg.

Vehicle speed, v = 25 m/s

spring's spring constant, k=2×10⁶ N/m

Let x be the greatest distance the spring may compress before breaking,

1/2mv²=1/2kx²

1/2mv²=1/2kx²

x=\(\sqrt{mv^{2} /k}\)

x=\(\sqrt{1500*25x^{2} /2*10^{6} }\)

x = 0.68 meters

The spring is thereby compressed by 0.68 meters.

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Answer:

Nuclear to radiant to thermal

Explanation:

The Sun works on nuclear fusion, hence the nuclear energy, to radiant the type of energy given off the sun that is absorbed by the solar panel, to thermal, thermal energy is spread through the release of heat from the solar panel

The semi-major axis of an ellipse is half the length of the longest diameter of the ellipse.

The semi-major axis of an ellipse is a fundamental parameter that determines its shape and size. It is defined as half the length of the longest diameter of the ellipse. The diameter of an ellipse is any line segment that passes through the center and has endpoints on the boundary of the ellipse. The longest diameter, also known as the major axis, is the diameter that has the largest length among all possible diameters of the ellipse.

To find the semi-major axis, we take half the length of the major axis. The major axis passes through the center of the ellipse and is the longest distance between any two points on the ellipse. By halving the length of the major axis, we obtain the semi-major axis, which represents the distance from the center to either focus of the ellipse.

The foci of an ellipse are two fixed points located on the major axis, equidistant from the center. The semi-major axis is indeed the distance between these two foci, as it is half the length of the longest diameter, which connects them. Thus, the semi-major axis provides a concise measure of the size and shape of an ellipse.

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Answer:

the answer is true they actually do

Answer:

\(F_{g}=7.4704\times10^{-5}\)

Explanation:

Givens: d = 1.0 × \(10^{4}\)  \(m_{1} = 4.0 x 10^{8}\)  \(m_{2} = 2.8\)×\(10^{5}\)

Required: \(F_{g}=?\)

Formula:  \(F_{g}= \frac{(6.67x10^{-11})(m_{1})(m_{2}) }{d^{2}}\)    (6.67x10^-11  is the gravitational constant)

\(F_{g}=\frac{\left(6.67\cdot10^{-11}\right)\left(4.0\cdot10^{8}\right)\left(2.8\cdot10^{5}\right)}{\left(1.0\cdot10^{4}\right)^{2}}\)

\(F_{g}=7.4704\times10^{-5}\)

Sydney McLaughlin's average speed during the 400-meter hurdles race was 7.77 m/s.

The average speed of Sydney McLaughlin during the 400-meter hurdles race is calculated as follows;

Average speed = distance / time

The distance is 400 meters, and the time is 51.46 seconds.

The average speed of Sydney McLaughlin during the 400-meter hurdles race is calculated as;

Average speed = 400 / 51.46

Average speed = 7.77 m/s

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Answer:

0.0124 AU

Explanation:

Ganymede takes 7.15 Earth days to orbit Jupiter. Ganymede is measured to be 7.1 X 10⁻³ AU from Jupiter’s center.

We need to find how far away is Callisto from the center of Jupiter if a second moon of Jupiter, Callisto, takes 16.69 Earth days to orbit Jupiter. Let it is r₂. Using third law of Kepler.

\(T^2\propto r^3\)

i.e.

\((\dfrac{T_1}{T_2})^2=(\dfrac{r_1}{r_2})^3\\\\\dfrac{r_1}{r_2}=(\dfrac{T_1}{T_2})^{2/3}\\\\r_2=\dfrac{r_1}{(\dfrac{T_1}{T_2})^{2/3}}\\\\r_2=\dfrac{7.1\times 10^{-3}}{(\dfrac{7.15}{16.69})^{2/3}}\\\\r_2=0.0124\ \text{AU}\)

So, Callisto is 0.0124 AU from the center of the Jupiter.

Answer: mechanical waves are caused by the disturbance of vibration in matter, whether solid, gas, liquid, or plasma.

Explanation:

Pulse type of modulation is applied to radio-controlled toys, therefore the correct answer is option D.

It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.

Toys controlled by remote control operate by emitting infrared radiation. These infrared rays have a frequency of 34–48 kilo Hertz.

Different types of modulations, such as frequency and amplitude modulation for transmitting and receiving video and music, are employed for other reasons.

Thus, the Pulse-type of modulation is applied to radio-controlled toys, therefore the correct answer is option D.

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The magnitude will be twice the initial velocity, as it has traveled back to its starting point in the opposite direction. The magnitude of the electron's velocity when it returns to its starting point in the opposite direction of its initial velocity can be calculated using the conservation of energy principle. When the electron reaches its maximum displacement from its starting point, it has maximum potential energy and zero kinetic energy.

Assuming the initial velocity of the electron is v, the maximum displacement from the starting point is d, and the electric potential energy of the electron is E, we can write the conservation of energy equation as:
E = (1/2)mv^2 + qVmax = (1/2)mvmax^2
Where m is the mass of the electron, q is its charge, Vmax is the maximum electric potential difference between the starting point and the maximum displacement point, and vmax is the velocity of the electron when it reaches its starting point.
Solving for vmax, we get:
vmax = sqrt(2qVmax/m)
Since the electron returns to its starting point in the opposite direction of its initial velocity, its final velocity will be -v.
|-v| = |-(sqrt(2qVmax/m))| = sqrt(2qVmax/m)
The magnitude of an electron's velocity when it returns to its starting point in the opposite direction of its initial velocity can be calculated using the formula:
v = 2 * u

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The  value in terms of 1m of oil is 1.25

To convert the pressure at a point from 1 meter of water to its equivalent value in meters of oil, we can use the following formula:

Pressure = height × density × gravity

Let's first find the pressure exerted by 1 meter of water.

1 g x 0.8 = 0,8

1 x g x 1m = 0.8 x g * h2

We are to solve for h2

h2 = 1 / 0.8

= 1.25

Hence tghe  value in terms of 1m of oil is 1.25

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The process of filtration of swamp water using a filtering material such as neat clothes will make the water clearer and remove any bad smell.

Filtration is a separation technique used to separate insoluble solids from a liquid.

Filtration is employed in water purification.

Water purification is done in water purification plants.

A locally designed purification process for swamp water will involve using materials such as:

The T-shirt is used filter out mud and sediments.

Repeated filtrations will make the water clearer and remove any bad smell.

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Answer:

If a body does 1j work in 1 sec time then the power of that body is called 1watt power

Explanation:

1 watt power can be defined as the rate of doing 1 joule work in one second time.

Answer:

Explanation:

The mass of the object can be found by using the formula

\(m = \frac{p}{v} \\ \)

p is the momentum

v is the velocity

From the question we have

\(m = \frac{10}{20} = \frac{1}{2} \\ \)

We have the final answer as

Hope this helps you

Given :

Actual mass , \(m_e=436.8\ g\) .

Three observations 460.9 g, 461.4 g, 459.0 g .

To Find :

The percent error of the student.

Solution :

Percent error is given by :

\(\%error=\sum \dfrac{|approx\ value -actual\ value |}{exact\ value}\times 100\\\\\%error=\dfrac{|460.9-436.8|+|461.4-436.8|+|459-436.8|}{436.8}\times 100\\\\\%error=\dfrac{70.9}{436.8}\times 100\\\\\%error=16.23\%\)

Therefore , the percent error of the student is 16.23 % .

Hence , this is the required solution .

Answer:

A

Explanation:

r= 5100m

acceleration of center=g= \(\frac{v^{2} }{r}\)

v= rw, Which is angular velocity X radius

put this in acceleration of center equation

= \(\frac{(rw)^{2} }{r} =g\)

= \(rw^{2} =g\)

= \(5100 . w^{2} = 9.8\)

\(w^{2} = 0.0019\)

=\(\sqrt{0.0019} = 0.0438\)

which is approximately A.

The control in the experiment is option B. The group that is given no shock.

The method utilized by the researcher in scientific study to reduce the impact of unimportant factors is known as experimental control. The power of the independent variable to alter the dependent variable is further strengthened by experimental control. 9 Nov 2021

A controlled experiment is a scientific test carried out under predetermined circumstances in which only one (or a small number of) variables are altered at a time while all other variables are maintained constant.

Researchers use experimental controls to reduce the impact of unrelated experience and environmental factors, as well as to strengthen the conclusion that changes in the dependent variable are caused by the independent variable (the ability to infer causality).

Hence, option B is correct as it is not receiving any special treatment in the experiment.

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The true azimuth of the AB alignment is 91º 52' (east of north), the magnetic azimuth is 100º 22' (east of north), and the grid azimuth is 108º 52' (east of north).

To find the true azimuth, magnetic azimuth, and grid azimuth of the AB alignment, we need to consider the magnetic declination. The magnetic declination indicates the angle between true north and magnetic north at a specific location. In this case, the magnetic declination is 8º 30' E, which means that the magnetic north is 8º 30' east of the true north.

To calculate the true azimuth, we subtract the magnetic declination from the grid azimuth. The grid azimuth is given as 100º 22', so subtracting the magnetic declination of 8º 30' E gives us a true azimuth of 91º 52' (east of north).

The magnetic azimuth remains the same as the grid azimuth, which is 100º 22' (east of north).

The grid azimuth is calculated by adding the magnetic declination to the true azimuth. Since the magnetic declination is east, we add it to the true azimuth. Adding 8º 30' E to the true azimuth of 91º 52' gives us a grid azimuth of 108º 52' (east of north).

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Answer:

5.00 × 10^14 Hz

Explanation:

The wavelength of the light in the medium can be calculated by using the formula:

λ = v / f

Where;

λ = wavelength (m)

v = speed of light

f = frequency (Hz)

From the provided information, λ = 600 nm (600 × 10^-9m), v = 3 × 10^8m/s.

λ = v / f

λ = 3 × 10^8/600 × 10^-9

λ = 0.005 × 10^(8+9)

λ = 0.005 × 10^17

λ = 5.00 × 10^14 Hz

The frequency of the light in the medium is 5.00 × 10^14 Hz

Answer:

Parallel Circuits

Explanation:

Loads can be operated on their own. If you had a series circuit, adding another light would dim the rest!

Answer:

0.119 s is the correct answer to this question.

Explanation:

As mentioned in the question

U=3.89\ m/s

a=-1.44\ m/s^2

S=4.8\ m

Consider the final speed of the softball covering the distance of 4.8m is v

Now using the equation

\(v^2=U^2+2aS\)

Putting the value of U, A, S in the previous equation we get

\(V^2=3.89^2-2\times 1.44\times 4.8\\V=3.7\ m/s\\\)

Now again using the equation

v=U+at

where U=intial velocity, t= time

Substituting the value of v, U, a

\(3.7=3.89-1.44\times t\\t=0.119\ s\\\)

Hence the slide time is 0.119 s

Answer:

C. It redirects the force

The purpose of the helical structure in a traveling-wave tube is to (d) enhance the bunching effect that occurs for the positive charge carriers in the electron beam.

The helical structure in a traveling-wave tube serves as an interaction circuit between the electron beam and the electromagnetic wave. The interaction between the beam and the wave leads to a phenomenon known as bunching, where the electrons in the beam are grouped together in a more compact manner. Bunching is crucial for efficient energy transfer from the electron beam to the electromagnetic wave.

The helical structure plays a key role in enhancing this bunching effect. As the electron beam travels through the helix, the helical structure provides a periodic electric field that interacts with the beam. This interaction causes the electrons to experience a force that synchronizes their motion with the electromagnetic wave. The synchronized motion results in the formation of electron bunches or density modulations within the beam.

By enhancing the bunching effect, the helical structure increases the efficiency of energy transfer from the electron beam to the electromagnetic wave. The bunches of electrons in the beam interact more effectively with the electromagnetic wave, leading to greater amplification and modulation of the signal carried by the wave.

It's important to note that the other options mentioned, such as (a) forming a helical resonator, (b) serving as an inductor, or (c) reducing the speed of the electromagnetic wave, are not the primary functions of the helical structure in a traveling-wave tube. While resonators and inductors can be present in the design of a traveling-wave tube, their functions are separate from the role of the helical structure in enhancing bunching and facilitating efficient energy transfer.

Therefore, in a traveling-wave tube, the primary purpose of the helical structure is to enhance the bunching effect for positive charge carriers in the electron beam, leading to improved energy transfer and amplification of the signal carried by the electromagnetic wave.

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Explanation:

hope this helps you

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The stroking method of magnetization is a technique used to magnetize ferromagnetic materials. It is based on the principles of domain theory, which helps us understand the behavior of magnetic materials at the atomic and microscopic level.

In domain theory, a ferromagnetic material is composed of many tiny regions called magnetic domains. Each domain consists of a large number of aligned atomic magnetic moments, creating a net magnetic field within the domain.
However, the magnetic moments in different domains can be randomly oriented, resulting in a lack of overall magnetization in the material.

The stroking method takes advantage of the fact that magnetic domains can be influenced and aligned by an external magnetic field. When a ferromagnetic material is subjected to an external magnetic field, the field causes the magnetic moments in the domains to align in the direction of the applied field. As a result, the domains merge and grow in size, leading to an overall magnetization of the material.

To apply the stroking method, a non-magnetized ferromagnetic material, such as a piece of iron, is taken and a strong permanent magnet is brought close to it.
The magnet is then repeatedly stroked along the length of the material in the same direction. The stroking motion ensures that the external magnetic field from the permanent magnet is consistently applied to the material.

As the magnet is stroked, the aligned magnetic domains within the material start to merge and grow. This process continues with each stroke, gradually increasing the overall magnetization of the material. Eventually, after several strokes, the material becomes fully magnetized, with the majority of the magnetic domains aligned in the direction of the stroking.

The stroking method is effective because the repeated application of the external magnetic field helps overcome the resistance of domain boundaries within the material.
These boundaries are regions where magnetic moments change orientation between adjacent domains, and they can hinder the alignment process.
By stroking the material, the external field continuously acts on the domains, encouraging them to overcome these barriers and align more uniformly.

It's important to note that the stroking method is a relatively simple and basic technique for magnetizing materials. In practical applications, more sophisticated methods, such as using electromagnets or specialized machinery, are often employed to achieve precise and controlled magnetization. However, the underlying principle of domain alignment remains a fundamental concept in magnetism.

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