A firm sells a good to both UK and EU customers. The demand function is the same for both markets and is given by 20P, + Q = 5000 where the subscript, i, takes the values 1 and 2 corresponding to the UK and EU, respectively. Although the variable and fixed costs are the same for each market, the EU now charges a fixed tariff of $50 per unit, so the joint total cost function is TC = 400. + 90Q. + 2000 Find the maximum total profit.

Answer:

31

Step-by-step explanation:

Answer: 31

Step-by-step explanation:

1. Multiply 28+6-12/4

2. Divide 28+6-3

3. Add 34-3

4. Subtract 31

Answer:

59400

Step-by-step explanation:

Answer:

999,960

Step-by-step explanation:

let x be a multiple of 120

120x ≤ 999,999

999,999 / 120 = 8333.325

8333 ≤ x ≤ 8334

8333(120) = 999,960

8334(1200) = 1,000,080  this is a 7-digit number

Therefore, the largest 6-digit number that is exactly divisible by 120 is 999,960

Answer:

The median will stay about the same.

The mean will increase.

Step-by-step explanation:

yeh

If the analyst decides to include the upper outlier in the calculations then the effects are likely;

1. The median will stay about the same.

4. The mean will increase.

The mean is the average value which can be calculated by dividing the sum of observations by the number of observations

Mean = Sum of observations/the number of observations

Median represents the middle value of the given data when arranged in a particular order.

It is given that an analyst for an online shopping site discarded an upper outlier and calculated that the mean number of minutes customers spent on the site was 23 and the median was 26.

If the analyst decides to include the upper outlier in the calculations then the effects are likely;

1. The median will stay about the same.

4. The mean will increase.

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To determine whether the number of customers, which is expected to be 15 each day, follows a uniform distribution, a chi-square test for goodness of fit should be performed with a specified significance level (alpha).

The chi-square test for goodness of fit is used to determine if observed data follows an expected distribution. In this case, we want to test whether the number of customers each day, which is expected to be 15, follows a uniform distribution.

To perform the test, we need to collect data on the number of customers over a period of time and compare it to the expected uniform distribution. The observed frequencies for each category (e.g., the number of days with 0 customers, 1 customer, 2 customers, etc.) would be obtained.

Then, the chi-square test statistic can be calculated based on the observed and expected frequencies. The test statistic measures the discrepancy between the observed and expected distributions.

To interpret the test results, we compare the calculated chi-square value to the critical chi-square value at the chosen significance level (alpha). If the calculated chi-square value exceeds the critical value, we reject the null hypothesis and conclude that the number of customers does not follow a uniform distribution. Conversely, if the calculated chi-square value does not exceed the critical value, we fail to reject the null hypothesis, indicating that the number of customers can be considered to follow a uniform distribution.

Please note that the specific calculations and decision-making process require additional data and the use of statistical software or tables to obtain the critical chi-square value.

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The 30% of the students withdraw, then, the expected number of withdrawals is the 30% of 20 which is 6.

Given that, a university set up that 30 of its scholars withdraw without completing the introductory statistics course.

Assume that 20 scholars registered for the course. cipher the probability that 2 or smaller will withdraw ( to 4 numbers).

cipher the probability that exactly 4 will withdraw( to 4 numbers).

cipher the probability that further than 3 will withdraw( to 4 numbers).

We've to cipher the anticipated number of recessions.

cipher the probability that 2 or smaller will withdraw,

a) To determine, given 2 scholars from the 20. Which is the probability of those 2 to withdraw and all others to complete the course. This is given by

0.3) ²(0.7) ¹⁸

also, multiply this volume, we get

Which is the number of ways to choose 2 scholars from the aggregate of 20. thus, the probability that exactly 2 scholars withdraw is = 190(0.3)²(0.7)¹⁹

Following an process determine that

The probability that exactly 1 pupil withdraw is(0.3) ²(0.7) ¹⁹

The probability that exactly none scholars withdraw is 20 c0(0.7) = (0.7)²⁰

Eventually, the probability that 2 or smaller scholars will withdraw is0.355

b) cipher the probability that exactly 4 will withdraw.

Following the process explained in a), the probability that 4 pupil withdraw is given by0.1304

c) cipher the probability that further than 3 will withdraw,

First cipher the probability that exactly 3 scholars withdraw, which is given by0.07

also, using a) the probability that 3 or smaller scholars withdraw is0.03550.0716 = 0.1071.

thus the probability that further than 3 will withdraw is 1-0.1071 = 0.8929.

d) cipher the anticipated number of recessions.

Hence, The 30 of the scholars withdraw, also, the anticipated number of recessions is the 30 of 20 which is 6.

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Answer:

10 hours to readm240

Step-by-step explanation:

Answer:

10 hours.

Step-by-step explanation:

If you divide 96 by 4, you get 24. Then divide 240 by 24, and you get 10.

When describing the central tendency for qualitative data, the measure that is commonly used is the mode.

Unlike quantitative data, where measures such as the mean or median can be used to describe central tendency, qualitative data consists of categories or labels rather than numerical values.

Therefore, the mode is the most appropriate measure for central tendency in this context.

The mode can be useful in summarizing qualitative data by identifying the most common category or response. It provides insight into the most prevalent characteristic or attribute among the data, allowing for a better understanding of the distribution and patterns within the dataset.


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The inequality of (2x1)2x5x4x can be solved by determining that x>0.

In mathematics, a statement of the order connection between two integers equivalent algebraic expressions that is greater than, equal to or greater to, less than, or lower than or equal to is referred to as an inequality.

(2x−1)2x−5x<4x +2−x

To multiply 2x-1 by 2, use the distributive property.

(4x−2)x−5x<4x + 2 −x

multiplying 4x-2 to x using the distributive property.

4x + 2 −2x−5x<4x + 2 −x

-2x and -5x together provide 7x.

4x + 2 −7x<4x + 2 −x

Subtract 4x + 2 by both sides.

4x + 2 −7x−4x + 2 <−x

Combine 4x + 2 and −4x + 2 to obtain 0.

−7x<−x To both sides, add x.

−7x+x<0

7x and x together yield 6x.

−6x<0

The product is 0 if any of the two numbers in it is greater than 0 and the other is 0 as well. 6 > 0, indicating that x would have to be greater than 0.

x>0

The Inequality of (2x−1)2x−5x<4x is x>0

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Answer:

36

Step-by-step explanation:

75/2700=36

To determine the number of odd 4-digit integers with distinct digits, we can consider the following:

1. The thousands digit: It cannot be zero since the number should be a 4-digit integer.

2. The units digit: It must be an odd number (1, 3, 5, 7, or 9) to make the entire number odd.

3. The hundreds and tens digits: They can be any digit from 0 to 9, excluding the digits used for the thousands and units digits.

Let's break down the cases:

Case 1: Thousands digit

There are 9 options for the thousands digit (1 to 9) since it cannot be zero.

Case 2: Units digit

There are 5 options for the units digit (1, 3, 5, 7, or 9) since it must be an odd number.

Case 3: Hundreds digit

There are 8 options for the hundreds digit (0 to 9 excluding the digits used for thousands and units).

Case 4: Tens digit

There are 7 options for the tens digit (0 to 9 excluding the digits used for thousands, units, and hundreds).

Now, we can calculate the total number of possibilities by multiplying the number of options for each digit:

Total number of possibilities = 9 × 5 × 8 × 7 = 2520

Therefore, there are 2520 odd 4-digit integers with distinct digits in the range of 1,000 to 9,999.

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Answer: C

Because if you put then in order(1,3,3,4,9) you will see that once you cross them off the last one will be 3 which would be the median and the answer.

Answer:

From what I know there is no q.

p=0 I put a slight explanation below.Hope it helps

Step-by-step explanation:

Ax^2+bx+c-p=x

Ax^2+bx+c-p-x=x-x

Ax^2+(b-1)x+c-p=0

Answer:

d/dx f(x)f(x) = d/dx f(x) + d/dx f(x)

Step-by-step explanation:

An example of the product rule is the following:

d/dx u*v = du/dx u + dv/dx v

Another way of interpreting this is that the product rule states that the derivative of a product is the derivative of the sum of the products with respect to their terms.

The length of US in the rhombus is 16 units

The complete question is added as an attachment

From the question, we have the following parameters that can be used in our computation:

RT = 6x + 4

SO = 7x - 6

By the properties of rhombus, we have

RT = 2 * SO

So, we have

6x + 4 = 14x - 12

Evaluate the like terms

8x = 16

So, we have

x = 2

This means that

US = 6 * 2 + 4

US = 16

Hence, the length is 16 units

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Answer:

m=4b and b=4m

Step-by-step explanation:

this is the right answer

Answer:

Heyyy. Glad to see someone from malaysia taking add maths hete. Hope this helps

The calculated radius of the cylidner when approximated is 8.0 meters

The formula for the volume of a cylinder is V = πr^2h, where V is the volume, r is the radius, h is the height, and π is a constant approximately equal to 3.14.

To find the radius of a cylinder with volume 1607 m³ and height 8 m, we can rearrange the formula as:

r^2 = V / (πh)

Substituting the given values, we get:

r^2 = 1607 / (3.14 x 8)

r^2 ≈ 63.973

Taking the square root of both sides, we get:

r ≈ 8.0

Therefore, the radius of the cylinder is approximately 8.0meters.

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Answer:

try 3 i need 20 more letters

Answer:

f(x) = 2x^2 + 12x +10

Step by step solution:

x = 1 x = 5 y = 10

f(x) = a(x+1)(x+5)

f(0) = a(1)(5) = 10

5a = 10

Divide by 5

a = 2

f(x)= 2(x+1)(x+5)

f(x) = 2(x^2 +6x +5)

f(x) = 2x^2 + 12x +10

brainliest much appreciated!

Answer:

h = 3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Define

2/3(6h - 9) = 6

Step 2: Solve for h

To determine if there was a significant difference in perceived intelligence between attractive photos and unattractive photos, we will conduct a two-tailed t-test at the .05 level of significance. Here's a step-by-step explanation:

1. State the null hypothesis (H0) and alternative hypothesis (H1):
H0: There is no significant difference in perceived intelligence between attractive and unattractive photos (MD = 0).
H1: There is a significant difference in perceived intelligence between attractive and unattractive photos (MD ≠ 0).

2. Determine the level of significance (α):
α = 0.05 for a two-tailed test.

3. Calculate the t-value:
For this test, we have the sample size (n = 25), the average difference between the two scores (MD = 2.7), and the standard deviation (s = 2.00). The formula for the t-value is:

t = (MD - 0) / (s / √n)

t = (2.7 - 0) / (2.00 / √25)
t = 2.7 / (2.00 / 5)
t = 2.7 / 0.4
t = 6.75

4. Determine the critical t-value:
Using a t-distribution table or calculator for a two-tailed test with α = 0.05 and 24 degrees of freedom (n - 1 = 25 - 1 = 24), the critical t-value is approximately ±2.064.

5. Compare the calculated t-value with the critical t-value:
Since our calculated t-value (6.75) is greater than the critical t-value (2.064), we reject the null hypothesis (H0).

In conclusion, the data are sufficient to conclude that there is a significant difference in perceived intelligence between attractive and unattractive photos, supporting the alternative hypothesis (H1). The attractive photos were rated higher in perceived intelligence compared to the unattractive photos at the .05 level of significance.

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The total time taken by the elevator for the entire trip is 45 s + 15 s + 15 s + 15 s + 45 s = 135 seconds i.e., it takes the elevator 135 seconds to complete the entire trip.

The remote control car travels forward for 4 seconds at a speed of 2.0 m/s, then stops for 3 seconds, and finally travels backward for 3 seconds at a speed of 1.5 m/s.

The elevator travels from the lobby to the 36th floor in 45 seconds, stops for 15 seconds, descends to the 28th floor, stops for 15 seconds again, and returns to the lobby.

The total time taken by the elevator to complete this trip is calculated by adding up the times for each segment.

For the remote control car, it travels forward at 2.0 m/s for 4 seconds, covering a distance of 2.0 m/s * 4 s = 8 meters.

It then stops for 3 seconds, and finally travels backward at 1.5 m/s for 3 seconds, covering a distance of 1.5 m/s * 3 s = 4.5 meters.

Therefore, the total distance covered by the car is 8 m + 4.5 m = 12.5 meters.

For the elevator, it takes 45 seconds to go from the lobby to the 36th floor, and it stops for 15 seconds to let people off.

Similarly, it takes 15 seconds to go from the 36th floor to the 28th floor, and another 15 seconds to let people off.

Finally, it takes 45 seconds to return from the 28th floor to the lobby.

Therefore, the total time taken by the elevator for the entire trip is 45 s + 15 s + 15 s + 15 s + 45 s = 135 seconds.

In conclusion, it takes the elevator 135 seconds to complete the entire trip, including stops at different floors, based on the given information.

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The exact solutions of the equation sec(x)= \(\frac{2}{\sqrt{3} }\) in the interval [0,2π) are \(x=\frac{\pi}{6},\frac{5\pi}{6},\frac{7\pi}{6},\frac{11\pi}{6}\).

To find the solutions of the equation sec(x)= \(\frac{2}{\sqrt{3} }\) in the interval [0,2π), we need to determine the values of x that satisfy this equation.

The secant function is the reciprocal of the cosine function, so we can rewrite the equation as cos(x)= \(\frac{\sqrt{3} }{2}\) .

In the interval [0,2π), the cosine function is positive in the first and fourth quadrants, where its value is \(\frac{\sqrt{3} }{2}\).

In the first quadrant (where 0≤x<π/2), the solution is x=π/6.

In the fourth quadrant (where 3π/2≤x<2π), the solution is x=11π/6.

Since the cosine function has a period of 2π, we can add multiples of 2π to the solutions to find all the solutions in the interval [0,2π).

Adding 2π to each solution, we get x=5π/6 and x= 7π/6.

Therefore, the exact solutions of the equation sec(x)= \(\frac{2}{\sqrt{3} }\) in the interval [0,2π) are \(x=\frac{\pi}{6},\frac{5\pi}{6},\frac{7\pi}{6},\frac{11\pi}{6}\).

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A power of 3 equation is called as cubic equation.

The term equation in math is known as a mathematical statement with an 'equal to' symbol between two expressions that have equal values.

Here we need to find the term that has been used for power of 3 equation.

Here we have to know that the power of 3 equation is known as cubic equation.

in other terms the polynomial equation which has a degree of three is called a cubic polynomial equation or trinomial polynomial equation.

As we all know that the power of the variable is the maximum up to 3, therefore, we get three values for a variable, say x.

The general form of the power of 3 equation is written as

=> ax³ + bx² + cx + d = 0

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There is No statisti-cally signi-ficant evidence against the teacher's-claim that Charlie is just guessing because the probability is very low.

The total number of True-false questions are = n = 201.

The probability of getting a correct answer by guessing is = p = 0.5,

Charlie answered 53.7% = 0.537 of the questions correctly,

So, P(p' ≥ 0.537)

⇒ P(z ≥ (0.537 - 0.5)/√(0.5×0.5)/201,

⇒ P(z ≥ 1.05) = 1 - P(z < 1.05)

⇒ 0.1469

Since, the probability is very low,

Therefore, there is not any significant evidence against the teachers claim.

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Answer:

use the slope formula y2-y1/x2-x1 and you should get -5-0/-2+3= -5 which means the rate of change should be 5

Answer:

5

Step-by-step explanation:

Answer:

2.449

Step-by-step explanation:

the square root of 6 is about 2.449