The frequency heard by the car traveling to the right is also 400 hertz due to the Doppler effect.
The frequency of the siren heard by the car traveling to the right, which is 800 meters away from the fire truck, can be calculated using the Doppler effect.
The Doppler effect describes the change in frequency of a wave as perceived by an observer moving relative to the source of the wave. In this scenario, the fire truck is moving to the left and emitting a siren sound at a frequency of 400 hertz. The car, traveling to the right, is located 800 meters away from the fire truck. To determine the frequency heard by the car, we can use the formula for the Doppler effect:
f' = f * (v + v_obs) / (v + v_src)
where f is the source frequency (400 Hz), v is the speed of sound (approximately 343 meters per second), v_obs is the velocity of the observer (car) relative to the medium (which is positive because the car is moving towards the source), and v_src is the velocity of the source (fire truck) relative to the medium (which is negative because the fire truck is moving away from the car).
Plugging in the given values, we have:
f' = 400 * (343 + 0) / (343 - 0) = 400 Hz
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A 5.0-c charge is 10 m from a small test charge. What is the magnitude of the force experienced by a 1.0 nc charge placed at the location of the test charge?
The magnitude of the force experienced by a 1.0 nc charge placed at the location of the test charge is 5*\(10^{-11}\)N
Given,
k=5c
r=10m
q=1*\(10^{-9}\)
E=kq/\(r^{2}\)=\(\frac{5*1*10^{-9} }{10^{2} }\)=5*\(10^{-11}\)
ForceAn effect that can alter an object's motion is called a force. An object with mass can change its velocity, or accelerate, in response to a force by moving away from rest, for example. Intuitively, pushing or pulling can be used to describe force. As a vector quantity, a force is one that has both magnitude and direction. It is expressed as a newton in the SI system (N). F is a symbol that stands for force (formerly P).
The net force exerted on an object is equal to the rate at which its momentum varies over time, according to the original formulation of Newton's second law.
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Jack plays floor hockey. He moves with a velocity of 7.5 m/s [East] for 2.25 seconds. What is his displacement during this time? show your work below.
Answer:
16.875 m [East]
Explanation:
In a velocity time displacement problems
displacement is given by
displacement of moving body = velocity of the that body * time
displacement will be in the direction of velocity of body.
Given
velocity = 7.5 m/s [East]
time = 2.25 seconds
displacement = 7.5 m/s [East] *2.25 seconds
displacement = 16.875 m [East]
Thus, displacement of jack is 16.875 m [East].
A 8.0\,\text {kg}8.0kg8, point, 0, start text, k, g, end text box is released from rest at a height y_0 =0.25\,\text my 0 =0.25my, start subscript, 0, end subscript, equals, 0, point, 25, start text, m, end text on a frictionless ramp. The box slides from the ramp onto a rough horizontal surface. The box slides 2.0\,\text m2.0m2, point, 0, start text, m, end text horizontally until it stops.
Answer:
μ = 0.125
Explanation:
To solve this problem, which is generally asked for the coefficient of friction, we will use the conservation of energy.
Let's start working on the ramp
starting point. Highest point of the ramp
Em₀ = U = m h y
final point. Lower part of the ramp, before entering the rough surface
\(Em_{f}\) = K = ½ m v²
as they indicate that there is no friction on the ramp
Em₀ = Em_{f}
m g y = ½ m v²
v = \(\sqrt{2gy}\)
we calculate
v = √(2 9.8 0.25)
v = 2.21 m / s
in the rough part we use the relationship between work and kinetic energy
W = ΔK = K_{f} -K₀
as it stops the final kinetic energy is zero
W = -K₀
The work is done by the friction force, which opposes the movement
W = - fr x
friction force has the expression
fr = μ N
let's write Newton's second law for the vertical axis
N-W = 0
N = W = m g
we substitute
-μ m g x = - ½ m v²
μ = \(\frac{v^{2} }{2 g x}\)
Let's calculate
μ = \(\frac{2.21^{2}}{2\ 9.8\ 2.0}\)
μ = 0.125
A 8.0 kg box is released from rest at a height y0 = 0.25 m on a frictionless ramp. The box slides from the ramp onto a rough horizontal surface. The box slides 2.0 m horizontally until it stops.
What is the friction coefficient of the horizontal surface?
Answer: 0.125
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you ran out of gas and are trying to push your car to a gas station, once you get the car moving, what force opposes your push?
The moves your car forward is the effect of static friction. The power needed to move the tires, which would in turn pushes the vehicle backward against the road, comes from the engine.
What is force example?Force is the term used to describe a body's tendency to alter or alter its state as a result of an external cause. When force is applied, the body could also alter its size, shape, and direction. hitting a football, pushing and pulling on the door, or kneading dough are a few examples.
What causes force?A push in pull that an object experiences as a result of interacting with another item is known as a force. Every time two items interact, a force is exerted on all of the materials. The force is no longer felt by the two surfaces when the interaction ends.
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A car travels at 15.0 m/s for 10.0 s. It then speeds up with a constant acceleration of 2.0 m/ 2 for 15.0 s. At the end of this time, what is its velocity?
The velocity of the car travelling at 15 m/s for 10 second speeding up with constant acceleration of 2m/s^2 for 15 second is 45 m/s.
What is velocity and how it is calculated out to be 45 m/s?Velocity as studied earlier is a quantitative quantity which describes the relation between displacement and time as velocity equals displacement per unit time.Here in this question is given the velocity with which the car is travelling for the 10 seconds and then the car speeds up.The speed up speed of the car was at a constant acceleration of 2m/s^2 for 15 seconds.That means Vo = 15 m/s , a = 2m/s^2, and t = 15 seconds, using the relation V = Vo + at .Then putting the values, V= 15 + 2x15 = 15+30 = 45 m/s , hence the velocity of the car would be 45 m/s.To know more about velocity visit:
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Part C
Just like in the diagram, when Earth was primarily liquid, it separated into layers. What prediction can you make about the
densities of Earth's different layers?
When the Earth was primarily liquid, it separated into layers. The density of Earth's different layers may be predicted. For instance, it is assumed that the outermost layer, or crust, is less dense than the inner layers.
The Earth's crust is mostly composed of silicates (such as quartz, feldspar, and mica) and rocks, which are less dense than the mantle, core, or outer core.
The mantle is composed of solid rock, which is denser than the Earth's crust.
The core is the most dense layer, and it is composed of a liquid outer core and a solid inner core.
Most of the Earth's layers are composed of different types of rock and minerals.
The layers were formed from the molten material that cooled and solidified.
The Earth's layers are divided into four groups, or spheres, that represent different levels of density.
The lithosphere is the outermost layer, which includes the crust and upper mantle.
The asthenosphere is the soft layer beneath the lithosphere.
The mantle is a solid layer that surrounds the core.
The core is the Earth's central layer, consisting of a liquid outer core and a solid inner core.
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Use your knowledge of chemical reactions, metals, and acids to determine which one of the following procedures is the LEAST hazardous?
I WILL GIVE 100 POINTS PLUS BRAINLIST:)
Answer:
I would say metals
Ok so let's start off by saying that chemicals take a big part in our life, right? Nevertheless, many of these chemicals may, especially if not appropriately used, endanger our health and poison our environment. Some reactions may result in death and injury to people, damage to physical property, and severe effects on the environment.
Next, let's talk about metals.
Metals are often good conductors of electricity and heat, shiny and pliable. The metals we use day-to-day are converted from metallic ores to their final form. Toxic metals sometimes imitate the action of an essential element in the body, interfering with the metabolic process resulting in illness.
Last, acids.
Acids can react violently with water and are harmful in the presence of moisture in the mouth or eyes or in proximity with other aqueous solutions
I hope this helps :)
Answer:
metals i think
Explanation:
Describe what it means to view something from a frame of reference. Give an example to illustrate your explanation. (4 points)
Un globo es inflado hasta obtener 1.5 atm, con un volumen de 500 cm³ a 273 K. Luego, es colocado en el frezzer ¿Cuál será su temperatura, con 1.2 atm y 300 cm³?
Respuesta: T2 = 131.04K
Explicación: Dado lo siguiente:
Presión, P1 = 1.5 atm = 1.5 × 760 = 1140 mmHg
Presión, P2 = 1.2 atm = 1.2 × 760 = 912 mmHg
Volumen, V1 = 500cm3 Volumen, V2 = 300cm3
Temperatura, T1 = 273K Temperatura, T2 =?
Usando la fórmula de gas combinada:
P1V1 / T1 = P2V2 / T2
Ingresando nuestros valores:
(1140 × 500) / 273 = (912 × 300) / T2
T2 × (1140 × 500) = 912 × 300 × 273
T2 = 74692800/570000 T2 = 131.04K
What is the kinetic energy of a 0.150 kg
object moving at a velocity of 100m/s?
Answer:
750J
Explanation:
Given parameters:
Mass of the object = 0.15kg
Velocity of the object = 100m/s
Unknown:
Kinetic energy of the body = ?
Solution:
The kinetic energy is the energy due to the motion of a body. It is mathematically expressed as;
K.E = \(\frac{1}{2}\) m v²
m is the mass of the body
v is the velocity
Now insert the parameters and solve;
K.E = \(\frac{1}{2}\) x 0.15 x 100² = 750J
While working out, a man performed 500 J of work in 8 seconds. What washis power?A. 4000 WB. 62.5 WC. 500 WD. 38.5 W
Given:
The work done by the man is W = 500 J
The time taken by the man is t = 8 s
To find the power.
Explanation:
The power can be calculated by the formula
\(P=\frac{W}{t}\)On substituting the values, the power will be
\(\begin{gathered} P=\text{ }\frac{500}{8} \\ =\text{ 62.5 W} \end{gathered}\)Thus, the power is B. 62.5 W
what is the ratio of the magnitude of the acceleration of an electron to that of a proton, when the electric field acting on each has the same strength?
At a point x distance from a point charge Q, the ratio between the strength of the electric field and the strength of the electric potential will be 1/x.
From an electric field's electric potential, how can you determine its size?The electric field can be calculated from the electric potential if it is known at all points in a given area of space. The electric field is represented in vector calculus notation as E = grad V, where grad V is the electric potential's gradient.
How can you determine a magnetic field's strength?The equation specifies how much force will be exerted on a wire carrying current I and having length L in a magnetic field. is the angle formed by the wire and the magnetic field in the equation F=ILBsin. Considering that the field and curve are perpendicular to the force,
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After about 30 seconds the elvator begins to decelerate at 2m/s^2 downwards because its is coming up on the 21st floor.Your mass is 50kg
What is the gravitational force and normal force?
Gravitational force on body = 500N
Normal force acting on the body = 400N
What is force?Force is an external agent capable of changing a body’s state of rest or motion. It has a magnitude and a direction.
Given,
Acceleration a = 2m/s²
mass m = 50kg
Acceleration due to gravity g = 10 m/s²
Gravitational force = mg = 500N
Using Newton’s second law of motion, the equation of motion can be written as
R+mg = ma
R = m (g – a) = 50 (10 – 2) = 400 N
Hence, gravitational force is 500N, normal force on body is 400N.
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The conductivity of water can be increased by adding .
Explanation:
The conductivity of water can be increased by adding any solute that increases the number of ions in solution.
Hope this helps you.. Good luck
The conductivity of water can be incrased by adding to it anything that disolves and ionizes in it.
Examples:
-- sugar
-- coffee
-- tea
-- artificial sweetener
-- baking soda
-- orange juice
-- corn starch
-- salt
emptying a half-full cylindrical tank suppose the water tank in exercise 36 is half full of water. determine the work required to empty the tank by pumping the water to a level 2 m above the top of the tank. answer
The work required to empty the cylindrical tank that is half full of water by pumping the water to a level 2 m above the top of the tank is 19695.61897 J.
To determine the work required to empty the cylindrical tank that is half full of water by pumping the water to a level 2m above the top of the tank, the following steps can be followed:
Find the volume of the water in the tank as follows:
V = (πr²h)/2, where V is the volume of water, r is the radius of the cylindrical tank, and h is the height of water in the tank.
Substituting the values given in the question,
V = (π × (0.8 m)² × 1 m)/2 = 1.00530965 m³
Now find the mass of the water as follows:-
The density of water = 1000 kg/m³
Mass = Density × Volume = 1000 kg/m³ × 1.00530965 m³ = 1005.30965 kg
Next, find the potential energy of the water:-
PE = m*g*h, where m is the mass of the water, g is the acceleration due to gravity, and h is the height of the water above the top of the tank.
Substituting the values given in the question,
PE = 1005.30965 kg × 9.81 m/s² × 2 m = 19695.61897 J
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If we know the size of an asteroid, we can determine its density by A) comparing its reflectivity to the amount of light it reflects. B) looking for brightness variations as it rotates. C) determining its mass from its gravitational pull on a spacecraft, satellite, or planet. D) radar mapping. E) spectroscopic imaging.
Option C) is correct in determining its mass from its gravitational pull on a spacecraft, satellite, or planet. Knowing the mass and size of an asteroid allows us to calculate its density.
Option A) is incorrect because reflectivity only tells us about the asteroid's surface properties, not its density. Option B) is incorrect because brightness variations during rotation do not give us enough information to determine density. Option D) and E) are methods of studying asteroids but are not directly related to determining density.
Knowing the size of an asteroid alone is not enough to determine its density, as different materials can have different densities at the same size. By measuring the gravitational pull of the asteroid on a spacecraft, satellite, or planet, we can determine its mass. Once we have the mass and the size, we can calculate the asteroid's density. Methods such as radar mapping and spectroscopic imaging can provide additional information about the asteroid's composition, but they are not directly used to determine its density.
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C) calculating its mass based on the gravitational attraction it exerts on a satellite, planet, or spacecraft.
We can determine an asteroid's mass by observing the gravitational pull it has on a neighbouring body, like a planet, satellite, or spacecraft. We can determine the asteroid's density once we know its mass and size. The gravitational force of an object will be stronger the denser it is. As a result, an asteroid must be denser the more massive it is for a given size.
The density of an asteroid can be determined using this method, which is especially helpful for small or erratic-shaped asteroids that are challenging to see using other techniques like radar mapping or spectroscopic imaging. Additionally, it can offer crucial details on the asteroid's makeup and structure, which can aid researchers in understanding the asteroid's formation and evolution.
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Any planet that you have NOT crossed out above should have a Magnetic Field. Circle any planet above that yoa have NOT crossed out. Do the data in Table 7.3 support your choice(s)? lio 1 No (circle one) TUTORIAL REVIEW QUESTIONS 1. What is (are) the main factor(s) that affect(s) the amount and duration of geological activity on a terrestrial planet? 2. What is (are) the main factor(s) that affect(s) atmospheric conditions on a terrestrial planet? 3. The moons of the giant Jovian planets are small rocky-metal bodies that are, at the largest, about the size of Mercury (but most are smaller). Based on this and what you have learned about the factors that affect geologic activity and atmospheres on similar objects (Terrestrial planets), what geologic and atmospheric conditions would you expect to find on the surface of a typical Jovian moon?
The main factor that affects the amount and duration of geological activity on a terrestrial planet is its internal heat. This heat is generated through various processes such as radioactive decay and residual heat from planetary formation.
The presence of a molten core and active mantle circulation contributes to geological activity, including tectonic plate movements, volcanic eruptions, and mountain building. Other factors like the planet's size, composition, and distance from the Sun can also influence geological activity to some extent.
The main factors that affect atmospheric conditions on a terrestrial planet are its distance from the Sun, the composition of its atmosphere, and the presence of greenhouse gases. The proximity to the Sun determines the amount of solar energy received, which affects temperature and weather patterns. The composition of the atmosphere, including the presence of gases like oxygen, nitrogen, carbon dioxide, and water vapor, determines the planet's climate and the ability to support life. Greenhouse gases trap heat in the atmosphere, contributing to the greenhouse effect and influencing temperature regulation.
Based on what we know about the factors that affect geologic activity and atmospheres on terrestrial planets, we can expect that typical Jovian moons, being small rocky-metal bodies, would have limited geological activity and thin atmospheres, if any. The smaller size of these moons compared to terrestrial planets means that they have a lower heat-producing capability and less internal energy. Additionally, their lower gravitational forces make it challenging to retain substantial atmospheres. While some Jovian moons may have evidence of geological activity, such as cryovolcanism or tidal heating, they generally exhibit less dynamic geologic and atmospheric conditions compared to larger terrestrial planets.
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why does a typhoon hit a location twice?
How does temperature change from planets to planets in our solar system?
The further a planet is from the Sun, the colder its surface temperatures tend to be. Venus is an exception, since it has the highest surface temperature in our solar system due to its close closeness to the Sun and its thick atmosphere.
What was the temperature of the solar system when the planets first formed?The inner planets are rocky, whereas the outer planets are gaseous, which can be attributed to the early solar system's temperature. The solar system's temperature increased as the gases came together to create a protosun. Temperatures in the inner solar system reached 2000 K, whilst in the outer solar system, it was only 50 K.
The quantity of heat received is just one of many intricate aspects that go into determining the temperature.
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how much heat energy is required to melt 520.5 g of hbr ? the molar heat of fusion of hbr is 2.41 kj/mol .
The amount of heat energy required to melt 520.5 g of HBr is 15,670 J or 6.88 kJ
The amount of heat energy required to melt 520.5 g of HBr would be 6.88 kJ. The molar heat of fusion of HBr is given as 2.41 kJ/mol.
Mass of HBr = 520.5 g
Molar mass of HBr = 80 g/mol
Number of moles = (mass/molar mass) = 520.5/80 = 6.50625 mol
Heat energy required to melt = Molar heat of fusion × Number of moles
Heat energy required to melt = 2.41 kJ/mol × 6.50625 mol = 15.67 kJ
But we have to convert kJ to J.
15.67 kJ = 15.67 × 1000 = 15,670 J
So, the amount of heat energy required to melt 520.5 g of HBr is 15,670 J or 6.88 kJ (rounded off to two decimal places).
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What is the frequency of an electron?
An electron's frequency is determined by its energy and the wavelength of its accompanying wave. Every frequency Very particle in quantum mechanics may be connected with a wave function.
Which can be characterised by a wavelength and a frequency. The following equation may be used to calculate an electron's energy: E = hf where E denotes the electron energy, h denotes Planck's constant (6.626 x 10-34 J s), and f is the of the electron's associated wave. Rearranging this equation yields the frequency of an electron: f = E/h An electron's energy is determined by its momentum and mass, which can change based on its velocity and the potential energy it encounters in a given system. As a result, the frequency of an electron cannot be given a single value without specifying its energy state and the context in which it is being measured.
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A 7 kg mass traveling at speed 12 m/s strikes a stationary 7 kg mass head-on, and the two masses stick together.
(a) What was the initial total kinetic energy? K= (b) What is the final speed? m/s Vf= (c) What is the final total kinetic energy? ] Kp= (d) What was the increase in internal energy of the two masses?
The initial total kinetic energy of the system can be calculated by summing the individual kinetic energies of the two masses.
The final speed of the system can be found using the principle of conservation of momentum. The final total kinetic energy is determined by calculating the kinetic energy of the combined mass. The increase in internal energy can be obtained by subtracting the final total kinetic energy from the initial total kinetic energy.
(a) The initial total kinetic energy (K) is the sum of the individual kinetic energies of the two masses. Since both masses have the same mass (7 kg) and the same speed (12 m/s), their individual kinetic energies are equal. Therefore, the initial total kinetic energy is:
K = 2 * (1/2 * m * v^2) = 2 * (1/2 * 7 kg * (12 m/s)^2) = 1008 J.
(b) The final speed (Vf) of the system can be found using the principle of conservation of momentum. The momentum before the collision is zero since one mass is stationary and the other has a velocity of 12 m/s. After the collision, the two masses stick together, so their combined momentum is zero. Therefore, the final speed of the system is zero.
(c) The final total kinetic energy (Kp) is the kinetic energy of the combined mass. Since the final speed is zero, the final total kinetic energy is also zero.
(d) The increase in internal energy is the difference between the initial and final total kinetic energies:
Increase in internal energy = K - Kp = 1008 J - 0 J = 1008 J.
Therefore, the increase in internal energy of the two masses is 1008 J
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The gravitational force is 2336 N for an object that is 4.15 x 10^6 m above the surface of the Earth? The radius of the Earth is 6.378 x 10^6 m. (Earth's mass is 5.97 x 10^24 kg) What is the mass of the object above earth?
Answer:
34kg
Explanation:
A rope is run over a massless pulley. The left-hand side of the rope is attached to a 3 kg mass, which rests on the ground. The right side of the rope is attached to a 5 kg mass, which is some unknown height above the ground. The system is released from rest. What is the magnitude of the instantaneous acceleration of the system when it is released from rest?
Given:
Mass attached to the left-hand side = 3 kg
Mass attached to the right-hand side = 5 kg
Let's find the magnitude of the instantaneous acceleration of the system when it is released from rest.
Apply the formula:
\(\begin{gathered} a=\frac{net\text{ pulling force}}{total\text{ mass}} \\ \\ a=\frac{(m_2\times g)-(m_1\times g)}{m_1+m_2} \end{gathered}\)Where:
m1 = 3 kg
m2 = 5 kg
g = 9.8 m/s^2
Thus, we have:
\(\begin{gathered} a=\frac{(5\times9.8)-(3\times9.8)}{3+5} \\ \\ a=\frac{49-29.4}{8} \\ \\ a=\frac{19.6}{8} \\ \\ a=2.45m/s^2 \end{gathered}\)The magnitude of the instantaneous acceleration is 2.45 m/s².
ANSWER:
2.45 m/s²
Transverse waves are to radio waves as longitudinal waves are to.
Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.
No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.
This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.
i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.
ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.
The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.
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What percentage of maximum heart rate should be the target in doing vigorous-intensity workout?
A. 77% and 93% C. 75% and 90%
B. 77% and 95% D. 77% and 100%
Your ideal heart rate for vigorous intensity physical activity should be between 77% and 93% of your maximum heart rate. here option A is correct.
You should feel like you can do the activity for a longer period of time while the intensity is still low. You can educate your body to exercise for extended periods of time in this zone, which is all about increasing your endurance. Active Intensity. In general, you won't be able to speak for more than a few words without pausing to take a breath if you're engaging in vigorous-intensity activities. Running, jogging, or race walking. The American Heart Association recommends working at 70 to 85 percent of your maximal heart rate for a vigorous activity. Running is an example of a rigorous workout. at least 10 mph when cycling. carrying a large bag while moving quickly uphill.
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If you eat cheese are you 1 percent cheese?
Answer:
No. Exactly what you eat doesn’t make up your internal structure.
:)
Answer:
Explanation:
Light cheeses are less than 20 %, low fat cheeses are 20 to 30%, fat cheeses are 50 to 60%, double-cream cheeses are at least 60% and triple-cream cheeses are at least 75 %.
What pattern did you observe when the tape was at
different distances from the Van de Graaff machine?
PLS HELP