(a) Find the vertical and horizontal asymptotes. (b) Find the intervals of increase or decrease. (c) Find the local maximum and minimum values. (d) Find the intervals of concavity and the inflection points. (e) Use the information from parts (a)-(d) to sketch the graph of f. 1 1 37. f(x) = 1 + 38. f(x) 7 (x - 2)² x2 e 39. f(x) = x2 + 1 - x 20 . 40. f(x) 1- e = 42. f(x) = x - x? - Inx - 41. f(x) = e = - 43. f(x) = ln(1 – In x) 44. f(x) = ett

Answer:

B

Step-by-step explanation:

(Slant height)^2= (Radius)^2+(Height)^2

(20)^2= (12)^2+(Height)^2

Height=16

Answer:

B. pls mark me at brainliest and like my answer.

Step-by-step explanation:

⩥ɓeŋʝ⩤

Answer:

11\(\pi\)

Step-by-step explanation:

To find the circumference of a circle, the formula is:

d * \(\pi\) = c

We already know the diameter, so we just plug that in:

11 * \(\pi\) = c

11\(\pi\) = c

Let me know if you have any questions.

Answer:

a + b + c = P

Step-by-step explanation:

The fractions to show the value of each 9 in the decima 0.999 are 9/10, 9/100, 9/1000.

To write the fraction that shows the value of each 9 in the decimal 0.999, we can use the following method

The digit 9 in the tenths place represents 9/10 or 0.9.

The digit 9 in the hundredths place represents 9/100 or 0.09.

The digit 9 in the thousandths place represents 9/1000 or 0.009.

Thus, the fractions are

0.9 = 9/10

0.09 = 9/100

0.009 = 9/1000

The value of the 9 on the left is related to the value of the 9 in the middle by a factor of 10.

The value of the 9 on the right is related to the value of the 9 in the middle by a factor of 10, so the 9 on the right is one-tenth the value of the 9 in the middle.

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The correct statement is: A. P(E) = 0.3. The probability of event E, denoted as P(E), is equal to 0.3.

To determine the correct answer, let's analyze the given information.

We know that events D and E are independent, which means that the occurrence of one event does not affect the probability of the other event happening.

Given:

P(D) = 0.6

P(D and E) = 0.18

Since events D and E are independent, the probability of both events occurring (P(D and E)) can be calculated as the product of their individual probabilities:

P(D and E) = P(D) * P(E)

Substituting the given values:

0.18 = 0.6 * P(E)

To find the value of P(E), we can rearrange the equation:

P(E) = 0.18 / 0.6

P(E) = 0.3

Therefore, the correct answer is A. P(E) = 0.3.

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Answer:

it is AD l l DC so ots B

Step-by-step explanation:

Answer

If the line segment AB is parallel to the line segment DC then, m∠1=m∠D by corresponding angles.

Congruence and similarity tests in geometry involve comparing corresponding sides and angles of polygons.

Each side and angle in one polygon is paired with a side or angle in the second polygon, with the order of adjacency preserved.

One is an exterior angle (beyond the parallel lines), while the other is an interior angle (inside the parallel lines).

Corresponding angles and transversal lines are defined. Corresponding angles are a subset of angle pairs. Angles on the opposite side of the transversal are referred to as alternate angles.

If line segment AB is parallel to line segment DC,

m∠1=m∠D, by corresponding angles

If line segment AD is parallel to line segment BC,

m∠3=m∠B, by corresponding angles

Thus, this can be concluded regarding the given scenario.

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Answer:

(x+6)*(x+2)

step-by-step explanation:

To find the possible values of k, we need to calculate the determinant of matrix D and set it equal to 1024.

Given matrix D:

D = | k 0 0 |

| 3 k² k³ |

| 0 kª k³ kº |

| k k k |

| 0 0 0 |

| k¹⁰ |

The determinant of D can be calculated by expanding along the first row or the first column. Let's expand along the first row:

det(D) = k(det | k³ k k |

| 0 k³ kº |

| 0 0 k¹⁰ |)

- 0(det | 3 k² k³ |

| 0 kª k³ |

| k k k |)

+ 0(det | 3 k² k³ |

| k k k |

| k k k |)

Simplifying further, we have:

det(D) = k(det | k³ k k |

| 0 k³ kº |

| 0 0 k¹⁰ |)

Now, we can calculate the determinant of the 3x3 submatrix:

det | k³ k k |

| 0 k³ kº |

| 0 0 k¹⁰ |

This determinant can be found by expanding along the first row or the first column. Expanding along the first row gives us:

det = k(k³(kº) - 0(k)) - 0(0(k¹⁰)) = k⁴kº = k⁴+kº

Now, we can set det(D) equal to 1024 and solve for k:

k⁴+kº = 1024

Since we are looking for all possible values of k, we need to solve this equation for k. However, solving this equation may require numerical methods or approximations, as it is a quartic equation.

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Step 1: Group this into two groups:

    \(h^3 + 2h^2-9h-18=(h^3 + 2h^2)+(-9h-18)\)

When you  do that, be sure to group the "–" into the group with the 9 and make sure there's "+" between the groups.

Step 2: Factor out the GCF from both individual groups:

    \((h^3 + 2h^2)+(-9h-18) = h^2 (h+2) -9(h+2)\)

Step 3: Notice both groups have that (h+2)?  That's a new GCF between the two groups, so factor that out:

    \(h^2 (h+2) -9(h+2) = (h+2)(h^2-9)\)

Step 4: That \((h^2-9)\) piece can be factored further, since it's a difference of squares:

    \((h+2)(h^2-9) = (h+2)(h+3)(h-3)\)

Now it's factored.

Answer:

1/15

Step-by-step explanation:

1/5+3+2        all of the marbles

2/10              odds of drawing an orange marble(bc 2 orange marble)

3/9                 because to get 3 green and 1 marble is removed and 9 is total          marbles left

2/10*3/9=1/15  muliply  odds because 2 draws of marbles    

Answer as a mixed number = 5 & 1/3 gallons

That rounds up to 6 full gallons assuming s/he cannot buy a fractional amount of a gallon.

=======================================

Explanation:

We multiply the two numbers given

8*(2/3) = 16/3

Then we can convert this to a mixed number if we wanted

16/3 = (15+1)/3 = 15/3 + 1/3 = 5 + 1/3 = 5 & 1/3

The teacher needs to buy 5 full gallons plus an additional 1/3 of a gallon of paint.

Assuming the teacher cannot buy a fractional amount of paint, s/he will need to bump that value to the nearest whole number. So the art teacher will need to buy 6 gallons of paint. He or she will have leftovers but it's better than coming up short.

Answer:Objective: Solve systems of equations with three variables using addition/elimination.

Solving systems of equations with 3 variables is very similar to how we solve systems with two variables. When we had two variables we reduced the system down

to one with only one variable (by substitution or addition). With three variables

we will reduce the system down to one with two variables (usually by addition),

which we can then solve by either addition or substitution.

To reduce from three variables down to two it is very important to keep the work

organized. We will use addition with two equations to eliminate one variable.

This new equation we will call (A). Then we will use a different pair of equations

and use addition to eliminate the same variable. This second new equation we

will call (B). Once we have done this we will have two equations (A) and (B)

with the same two variables that we can solve u

Step-by-step explanation:

sorry my answer was wrong

Answer:

-1/2x

Step-by-step explanation:

We know point (-10, 0) and point (0,-5)

So, the slope would be -5/10 or simplified at -1/2

y= -1/2x

Answer: -1/2

Step-by-step explanation:

Use two points on the graph and plug it into the formula

y2-y1 divided by x2-x1

A. can be used to test joint hypotheses.

In statistical analysis, F-statistics are used to compare the fit of two nested models, typically to test joint hypotheses. Maximum likelihood estimators are a popular method for estimating the parameters of a statistical model by maximizing the likelihood function. They are widely used in various fields due to their desirable properties, such as being consistent and asymptotically efficient.

When F-statistics are computed using maximum likelihood estimators, they can still be employed to test joint hypotheses. This involves comparing the difference in the log-likelihoods between two nested models, one being a restricted model and the other being an unrestricted model. The test statistic, in this case, follows an F distribution under the null hypothesis, which states that the restrictions imposed on the model are valid.

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Answer:

the second choice or B would be the answer

The function that has a domain where x ≠ 3 and a range where y ≠ 2  are:

f(x) = 2 (x + 5) / (x - 3)

f(x) = 2 (x + 5) / (x - 3)

A function has an input and an output.

A function can be one-to-one or onto one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

The domain of a function consists of all the possible values of x for which the function is defined, and the range of a function consists of all the possible values of y that the function can take.

Now,

f(x) = 2 (x + 5) / (x - 3)

The denominator x - 3 cannot be equal to zero, so x cannot be equal to 3.

Therefore,

The domain of the function is all real numbers except x = 3,

or (-∞, 3) U (3, ∞).

To find the range, we need to consider what values of y the function can take for different values of x.

As x approaches 3 from either side, the value of the function becomes increasingly large (positive infinity for x approaching 3 from the right, and negative infinity for x approaching 3 from the left).

This means that the function has a vertical asymptote at x = 3, and the range of the function is all real numbers except y = 2, or (-∞, 2) U (2, ∞).

And,

f(x) = 2 (x + 5) / (x - 3)

The only value of x that makes the denominator x - 3 equal to zero is x = 3. Therefore,

The domain of the function is all real numbers except x = 3, or

(-∞, 3) U (3, ∞).

To find the range, we again consider what values of y the function can take for different values of x.

As x approaches 3 from either side, the value of the function approaches positive or negative infinity (depending on the sign of x - 3).

This means that the function has a vertical asymptote at x = 3, and the range of the function is all real numbers except y = 2, or (-∞, 2) U (2, ∞).

Therefore,

Both functions have the same domain and range, and both satisfy the conditions of having a domain where x is not equal to 3 and a range where y is not equal to 2.

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Answer:

The answer is B

Step-by-step explanation:

This is because when you distribute the -4 to 9^6 and 7^-24 you will get 9^-24 and 7^36. Then, you can move the 7^-24 to the denominator because of the negative exponent rule.

PS: ^ means to the power of

The critical t-value is approximately 1.753.

To find the critical value for a 96% confidence interval with a sample size of 15, we need to determine the t-value from the t-distribution table. The t-distribution table is a statistical tool used to determine the probability of a t-value given the degrees of freedom (df) and the desired level of significance (α).

In this case, we have a sample size of 15, which means our degrees of freedom are 14 (n - 1). Looking at a t-distribution table for 14 degrees of freedom and a 96% confidence interval.

This means that if we were to construct a confidence interval from a sample size of 15, the margin of error would be calculated by multiplying the critical t-value of 1.753 by the standard deviation of the sample and dividing by the square root of the sample size. The resulting interval would contain the population mean with 96% confidence.

It's essential to note that the critical value will change as the sample size and confidence level change. Therefore, it's crucial to use the correct table to find the corresponding critical values for a given dataset's sample size and confidence level.

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the control limits for the x-bar chart are 9.7439 minutes (LCL) and 11.0561 minutes (UCL), and the control limits for the R chart are 0 minutes (LCL) and 2.0529 minutes (UCL).

To compute the control limits for the x-bar (mean) and R (range) charts, we'll use the following formulas:

For the x-bar chart:

Upper Control Limit (UCL) for x-bar = x-double-bar + A2 * R-bar

Lower Control Limit (LCL) for x-bar = x-double-bar - A2 * R-bar

For the R chart:

Upper Control Limit (UCL) for R = D4 * R-bar

Lower Control Limit (LCL) for R = D3 * R-bar

Where:

x-double-bar = Overall mean of the sample means

R-bar = Overall mean of the sample ranges

A2 = Constant from the control chart constants table

D4 = Constant from the control chart constants table

D3 = Constant from the control chart constants table

For sample sizes of 4, the control chart constants are as follows:

A2 = 0.729

D4 = 2.281

D3 = 0

Given the information you provided:

Overall mean (x-double-bar) = 10.4 minutes

Average range (R-bar) = 0.9 minutes

Let's calculate the control limits:

For the x-bar chart:

UCL for x-bar = 10.4 + 0.729 * 0.9

             = 10.4 + 0.6561

             = 11.0561 minutes

LCL for x-bar = 10.4 - 0.729 * 0.9

             = 10.4 - 0.6561

             = 9.7439 minutes

For the R chart:

UCL for R = 2.281 * 0.9

         = 2.0529 minutes

LCL for R = 0

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Answer: The answer is B.

Step-by-step explanation:

as you can see, all you need to do is divide 5 into getting 2 equal parts which is 2.23  and then the negative sign is added to that answer which is: -2.23

Answer:

$99

Step-by-step explanation:

100 - (100 x .10)  = 90

90 + (90 x .10) = 99

An unnormalized relation refers to a table in a relational database that contains more than one row. This means that there are duplicate rows in the table, which violates the rules of normalization.

Normalization is a process in database design that aims to eliminate data redundancy and ensure data integrity. It involves breaking down a database into multiple tables and defining relationships between them. By doing so, we can efficiently store and retrieve data while minimizing inconsistencies.

In an unnormalized relation, duplicate rows can lead to various problems. For example, it can result in data inconsistencies, as updating one instance of a row may not reflect changes in other duplicate rows. Additionally, it can cause unnecessary storage and maintenance overhead.

To normalize an unnormalized relation, we need to identify the functional dependencies in the table and create separate tables for related data. This helps organize the data and reduces redundancy.

In summary, an unnormalized relation is a table in a relational database that has duplicate rows. It is important to normalize such relations to ensure data integrity and efficiency.

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A 2x2x3 fully-crossed factorial design means that there are 3 independent variables, each with 2 levels, 2 levels, and 3 levels, respectively. Therefore, it is not true that the experiment has 2 independent variables or 3 dependent variables. It also does not have any extraneous variables because all variables are manipulated and measured.

The experiment has a total of 12 conditions, which is calculated by multiplying the levels of each independent variable together (2x2x3=12). This means that each participant in the experiment will be exposed to all 12 conditions, which can be time-consuming and may require a large sample size.

In summary, the only statement that is definitely true is that one of the variables in the experiment has 2 levels, another has 2 levels, and the third has 3 levels. The experiment has 3 independent variables, 12 conditions, and no extraneous variables.

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Answer:

shorter leg = 8

longer leg = 8√3

Step-by-step explanation:

If the hypotenuse of the 60-90-30 triangle is 16, we can use the ratios of the sides to find the lengths of the other two sides. Here's how we can solve for the missing sides:

The length of the shorter leg (opposite the 60-degree angle) is half the length of the hypotenuse:

shorter leg = (1/2) * hypotenuse

= (1/2) * 16

= 8

The length of the longer leg (opposite the 30-degree angle) can be found using the ratio of the sides in a 30-60-90 triangle:

longer leg = shorter leg · √3

= 8√3

So, the missing side of the triangle are 8 and 8√3

the answer is D

300/6 = x/10

once solved, it will be proportional

Answer:

13

Step-by-step explanation:

1) Rounding those number to 4 significant digits

a. 431,801 = 431,800

b. 10,235.0 = 10240

c. 1.0348 = 1.035

d. 0.004384010 = 0.0040

e. 0.00078100 =0.0008

f. 0.0098641​ =0.009

The criteria are rounding up to those numbers greater than or equal to 5, and considering the how low is the number or how great it is.