The velocity of a particle at time t is 4t³- 7, at time t = 3 is 101 ft/sec, and at rest is ∛7/4 sec.
The position of a particle at time t is
s(t) = t⁴ - 7t + 22, where t > 0
(A) Velocity at time t is
V(t) = s'(t)
Or, V(t) = 4t³ - 7 × 1 + 0
Or, V(t) = 4t³- 7
Hence, the velocity at time t is 4t³- 7.
B) Velocity ar time t = 3 is
V(3) = 4(3)³- 7
Or, V(3) = 101 ft/sec
Hence, the velocity at time t = 3 is 101 ft/sec.
(C) When particle is at rest, V(t) = 0
Then, 4t³ - 7 = 0
Or, t³ = 7/4
Or, t = ∛7/4 sec
Therefore, the velocity at rest is ∛7/4 sec.
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Place thermometers near the edge of the table for easy retrieval. True or False
Answer:
This depends on the type of the thermometer, but when working with glass thermometers, (Hg especially) you should not put them near the edge of the table.
This is because it will easier to accidentally touch it and throw it into the ground, breaking the thermometer.
This is bad not only for the material loss of the lab instrument, but also because the mercury inside the thermometer is dangerous, so you really want to keep the thermometers in a safe place.
Then this would be false, do not leave the thermometers near the edge of the table (or in any place where it can fall and break)
both father and mother are white but the baby born with black colour.the father does not accept the baby and mother claim to the court and child and court prove that the baby born from same parents. justify the statements.
Three 10-12 resistors are connected in parallel. What is their equivalent resistance?"
The equivalent resistance of the three 10^12 ohm resistors connected in parallel is approximately 3.33 x 10^11 ohms.
The formula for calculating the equivalent resistance (R_eq) of resistors connected in parallel is given by:
\(\frac{1}{R_{\text{eq}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \ldots\)
In this case, we have three resistors connected in parallel, each with a resistance of 10^12 ohms. Substituting the values into the formula, we can calculate the equivalent resistance:
\(\frac{1}{R_{\text{eq}}} = \frac{1}{10^{12}} + \frac{1}{10^{12}} + \frac{1}{10^{12}}\)
Simplifying the equation, we get:
\(\frac{1}{R_{\text{eq}}} = \frac{3}{10^{12}}\)
Taking the reciprocal of both sides, we find:
\(R_{\text{eq}} = \frac{10^{12}}{3}\)
Thus, The equivalent resistance (R_eq) of three 10^12 ohm resistors connected in parallel is approximately 3.33 x 10^11 ohms.
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A 1250 kg car has four 12 kg wheels. When the car is moving, what fraction of its total kinetic energy is due to rotation of the wheels about their axles? Assume that the wheels have the same rotational inertia as uniform disks of the same mass and size.
Answer:
The total kinetic energy of the car can be divided into two parts: translational kinetic energy, due to the car's motion as a whole, and rotational kinetic energy, due to the rotation of the wheels about their axles.
The translational kinetic energy of the car is given by:
KE_translational = (1/2)mv^2
where m is the mass of the car and v is its speed.
The rotational kinetic energy of each wheel can be calculated as:
KE_rotational = (1/2)Iω^2
where I is the moment of inertia of a wheel and ω is its angular velocity.
The moment of inertia of a uniform disk is given by:
I = (1/2)mr^2
where m is the mass of the disk and r is its radius.
The mass of each wheel is given as 12 kg, so the moment of inertia of each wheel is:
I = (1/2)(12 kg)(0.5 m)^2 = 1.5 kg·m^2
Assuming that the wheels are rolling without slipping, the angular velocity of each wheel can be related to the speed of the car by:
v = rω
where r is the radius of the wheel.
Solving for ω, we get:
ω = v/r
Substituting this expression into the equation for KE_rotational, we get:
KE_rotational = (1/2)(1.5 kg·m^2)(v/r)^2
Simplifying, we get:
KE_rotational = (3/8)mv^2
So the rotational kinetic energy of each wheel is (3/8) of the translational kinetic energy of the car.
The total rotational kinetic energy of all four wheels is therefore:
KE_total_rotational = 4 KE_rotational = (3/2)mv^2
The total kinetic energy of the car is:
KE_total = KE_translational + KE_total_rotational = (5/2)mv^2
So the fraction of the total kinetic energy of the car that is due to the rotation of the wheels about their axles is:
KE_total_rotational / KE_total = (3/5) = 0.6
Therefore, 60% of the car's total kinetic energy is due to the rotation of the wheels about their axles.
a tire with an angular velocity of 17 m/s has a centripetal acceleration of 1200 m/s2. what is the radius of the tire?
The radius of the tire is approximately 24 centimeters.
a = (v^2) / r
where a is the centripetal acceleration, v is the velocity, and r is the radius.
We are given that the tire has an angular velocity of 17 m/s. To convert this to linear velocity, we can use the formula:
v = r * ω
where ω is the angular velocity in radians per second. Since we are given the angular velocity in meters per second, we need to divide by the radius to get the angular velocity in radians per second:
ω = v / r
Substituting the given values, we get:
ω = 17 / r
Now we can substitute this expression for ω into the formula for centripetal acceleration:
a = (v^2) / r
a = (r * ω^2) / r
a = ω^2 * r
Substituting the given values, we get:
1200 = (17^2) / r
r = (17^2) / 1200
r = 0.2375 meters or approximately 24 centimeters
Therefore, the radius of the tire is approximately 24 centimeters.
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help me please!!!!!..............
Answer:
The car took 3 hours to travel 180 miles
Explanation:
Constant Speed Motion
An object travels at constant speed if the ratio of the distance traveled by the time taken is constant.
Expressed in a simple equation, we have:
\(\displaystyle v=\frac{d}{t}\)
Where
v = Speed of the object
d = Distance traveled
t = Time taken to travel d.
From the equation above, we can solve for t:
\(\displaystyle t=\frac{d}{v}\)
The car travels at v=60 mi/h for a distance of d=180 miles. The time taken is:
\(\displaystyle t=\frac{180\ mi}{60\ mi/h}\)
t = 3 hours
The car took 3 hours to travel 180 miles
A student hits a hockey puck with a hockey stick and the puck speeds up. Another student claims that the student broke the law of conservation of momentum because the puck gained momentum.
The student did not break the law of conservation of linear momentum because the final momentum of the hockey puck will be equal to the initial momentum of the hockey stick.
What is the law of conservation of linear momentum?
The law of conservation of linear momentum states that the total momentum of an isolated system is always conserved.
That is the sum of initial momentum is equal to the sum of the final momentum of the object.
Mathematically, the law of conservation of linear momentum is given as;
Pi = Pf
m₁u₁ = m₂u₂
where;
m₁ is the mass of the first objectm₂ is the mass of the second objectu₁ is the initial velocity of the first objectu₂ is the initial velocity of the second objectThe hockey puck speeds up because it gained momentum from the hockey stick and hockey stick will slow down to maintain the law of conservation of linear momentum.
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I have no clue what to do, please hep
Can somebody please help?!
Answer:
I believe the answer is d
what happens if that charge is replaced by a 0.4 μcμc charge?
The original charge is replaced by a 0.4 μC charge, the force experienced by it due to the 2 C charge is 7.2 * 10^-4 N.
Electrostatic force is proportional to the magnitude of the charge. This means that if the charge on a body is increased or decreased, the force experienced by it will change too. In other words, force changes with a change in the charge. The magnitude of the electrostatic force between two point charges is given by Coulomb's law. It states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them. Let's consider an example:
Suppose there are two charges A and B. The magnitude of charge A is 1 C and that of charge B is 2 C. Let the distance between them be 1 meter. The electrostatic force experienced by charge A is given by:
F = k * (q1*q2)/d² where k = Coulomb's constant = 9 * 10^9 Nm²/C², q1 = 1 C, q2 = 2 C and d = 1 m.
Putting all these values in the formula, we get:
F = 9 * 10^9 * (1*2)/(1²)N
Therefore, the electrostatic force experienced by charge A due to charge B is 18 N.
Now, suppose that the charge on body A is replaced by a 0.4 μC charge. We have to calculate the force experienced by this charge due to the 2 C charge (body B). The distance between them is still 1 meter. So, let's calculate the electrostatic force:
F = k * (q1*q2)/d²k = 9 * 10^9 Nm²/C², q1 = 0.4 * 10^-6 C, q2 = 2 C and d = 1 m
Putting all these values in the formula, we get:
F = 9 * 10^9 * (0.4 * 10^-6 * 2)/(1²)NF = 7.2 * 10^-4 N
Therefore, when the original charge is replaced by a 0.4 μC charge, the force experienced by it due to the 2 C charge is 7.2 * 10^-4 N.
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a vertical spring launcher is attached to the top of a block and a ball is placed in the launcher. while the block slides at constant speed to the right across a horizontal surface with negligible friction between the block and the surface, the ball is launched upward. when the ball reaches its maximum height, what will be the position of the ball relative to the launcher?
The ball's initial speed decreases as it moves upward from the vertical spring launcher. At its maximum height, the ball has zero speed and begins to fall back down. Since the block is sliding at a constant speed with negligible friction, the position of the launcher relative to the ground remains unchanged.
Since the block is sliding at a constant speed across a horizontal surface with negligible friction, it means the block is moving at a steady pace without being slowed down by the surface. Meanwhile, the ball is launched vertically upward from the launcher.
When the ball reaches its maximum height, it will momentarily have zero vertical speed before starting to descend due to gravity. However, during its upward and downward journey, the ball maintains the same horizontal speed as the block, since there is negligible friction between the block and the surface.
As a result, the position of the ball relative to the launcher will remain the same horizontally when it reaches its maximum height. The ball will be vertically above the launcher at the maximum height, maintaining the same horizontal position throughout its motion.
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Chapter 08, Chapter 09 & Chapter 10 (Electricity section) Figure Q1 +1.0 nC (i) +10 nC 1.0 cm 1.0 cm +10 nC (ii) +10 nC 1.0 cm 1.0 cm -10 nC 1. Two +10 nC (nC = nanocoulomb) charged particles are 2.0 cm apart on the x-axis. (a) What is the net force on a +1.0 nC charge midway between them? [2 marks] (b) What is the net force on this same +1.0 nC charge (in the middle) if the charged particle on the right is replaced by a-10 nC charge? [3 marks] Figure Q2 9.0 Ω 3.0 Ω IT итти 20.0 V 10.0 Ω 3.0 Ω 2. Refer to Figure Q2 and answer the following questions: (a) Find the equivalent resistance of the numerous resistor's combination in Figure Q2. (b) Find the total current, Ir as supplied by the battery. (c) Find voltage across the 10.0 2 resistor. (d) Find voltage across the 4.0 resistor. +1.0 nC 4.0 Ω x-axis x-axis [1 mark] [2 marks] [2 marks] [2 marks]
The electric force between two charges can be determined by using Coulomb's law. Coulomb's law states that the magnitude of the electric force, F, between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance, r, between them, as shown below:F ∝ (q1q2)/r²The electrostatic force is attractive if the two charges are opposite in sign and repulsive if they are like-signed.
The distance between the two charges is 2 cm, and the charge is midway between them. The distance between the charges and the charge midway is 1 cm.The electric force due to +10 nC is to the right and that due to +10 nC is to the left. The two forces have the same magnitude; thus, the net force is zero.(b) What is the net force on this same +1.0 nC charge (in the middle) if the charged particle on the right is replaced by a-10 nC charge?In the presence of a -10 nC charge, the forces on the +1 nC charge are no longer the same. The force due to the +10 nC charge is still to the left, but the force due to the -10 nC charge is to the right, as shown below:q1 = +10 nC, q2 = -10 nC, and q3 = +1 nCThe net force acting on the +1 nC charge is the vector sum of the force due to the +10 nC charge and the force due to the -10 nC charge. The direction of the net force is to the left, and its magnitude is calculated as follows:Fnet = F1 + F2 = [(9 × 10⁹ Nm²/C²) × (1.0 × 10⁻⁹ C) × (10.0 × 10⁻⁹ C) / (0.010 m)²] - [(9 × 10⁹ Nm²/C²) × (1.0 × 10⁻⁹ C) × (1.0 × 10⁻⁹ C) / (0.010 m)²]Fnet = 1.6 × 10⁻⁶ NThe net force acting on the +1 nC charge is 1.6 × 10⁻⁶ N to the left. Thus, the answer is 1.6 × 10⁻⁶ N to the left.
Req = R1 + R2 + R3The equivalent resistance of the numerous resistors combination is:Req = (10 Ω) + (3 Ω + 9 Ω) || (4 Ω + 3 Ω)Req = (10 Ω) + [(3 Ω × 9 Ω) / (3 Ω + 9 Ω) + (4 Ω × 3 Ω) / (4 Ω + 3 Ω)]Req = (10 Ω) + (27/4 Ω)Req = 37/4 ΩThe equivalent resistance of the numerous resistor's combination in Figure Q2 is 9.25 Ω.The total current, Ir, supplied by the battery can be calculated using Ohm's law, given as follows:V = IR, where V is the voltage, I is the current, and R is the resistance.The voltage of the battery is given as 20 V, and the equivalent resistance of the circuit is 9.25 Ω.Ir = V/ReqIr = (20 V) / (37/4 Ω)Ir = (20 V) × (4/37 Ω)Ir = 80/37 AIr = 2.16 AThe total current, Ir as supplied by the battery is 2.16 A.(c) Find voltage across the 10.0 Ω resistor.The voltage across the 10.0 Ω resistor can be calculated using Ohm's law, given as follows:V = IRThe current passing through the 10 Ω resistor is 2.16 A; thus, the voltage across the resistor isV = IR = (2.16 A) (10.0 Ω)V = 21.6 VThe voltage across the 10.0 Ω resistor is 21.6 V.The current passing through the 4 Ω resistor is the same as the current passing through the 3 Ω resistor. The current through the 3 Ω resistor can be calculated as follows:I3 = (Vr - V)/R3I3 = (20 V - 21.6 V)/(3 Ω)I3 = -0.533 AThe voltage across the 4 Ω resistor can be calculated as follows:V = IRV = (-0.533 A)(4 Ω)V = -2.13 VThe voltage across the 4.0 Ω resistor is -2.13 V.
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Place the follow in increasing order of impedance, which order is correct?
A. PZT, matching layer, gel, skin
B. matching layer, gel, PZT, skin
C. PZT, gel, skin, matching layer
D. skin, gel, matching layer, PZT
The correct order of increasing impedance is:
C. PZT, gel, skin, matching layer
Impedance is a measure of the opposition to the flow of sound waves in a medium. It depends on the density and speed of sound in the material. In the given options, the order of increasing impedance can be determined by considering the properties of the materials involved.
PZT (lead zirconate titanate) has a higher impedance than gel, skin, and the matching layer. PZT is a piezoelectric material commonly used in ultrasound transducers and has a higher density and speed of sound, leading to higher impedance.
Gel has a lower impedance compared to PZT but higher impedance than skin and the matching layer. Gel is used as a coupling medium between the transducer and the skin to enhance acoustic coupling and minimize impedance mismatch.
Skin has a lower impedance than both gel and the matching layer. It is the outermost layer and acts as an interface between the transducer and the biological tissue.
The matching layer has the lowest impedance among the given options. It is designed to match the impedance of the PZT to the impedance of the tissue being imaged, facilitating efficient sound transmission.
Therefore, the correct order is C.
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The primary coil of a transformer has 800 turns and the secondary coil has 8 turns. It is connected to a 220 volt a.c. supply. What will be the output voltage??
Don't Spam ^_^
-_+
Given :-
Primary voltage = 220 voltNo. of turns secondary turns = 8No. of primary turms = 800\( \\ \\ \)
To find :-
Secondary voltage.\( \\ \\ \)
We know:-
\( \boxed{ \rm\dfrac{E_s}{E_p}=\dfrac{N_s}{N_p}}\)
where :-
E_s = Secondary voltageE_p = primary voltageN_s = No. of turns secondary turnsN_p = No. of primary turms\( \\ \\ \)
So:-
\( \\ \)
\( \dashrightarrow\sf\dfrac{E_s}{E_p}=\dfrac{N_s}{N_p}\)
\( \\ \\ \)
\( \dashrightarrow\sf\dfrac{E_s}{220}=\dfrac{8}{800}\)
\( \\ \\ \)
\( \dashrightarrow\sf\dfrac{E_s}{220}=\dfrac{8}{8 \times 100}\)
\( \\ \\ \)
\( \dashrightarrow\sf\dfrac{E_s}{220}=\dfrac{\cancel8}{\cancel8 \times 100}\)
\( \\ \\ \)
\( \dashrightarrow\sf\dfrac{E_s}{220}=\dfrac{1}{100}\)
\( \\ \\ \)
\( \dashrightarrow\sf\dfrac{E_s}{1}=\dfrac{220}{100}\)
\( \\ \\ \)
\( \dashrightarrow\sf{E_s}=\dfrac{220}{100}\)
\( \\ \\ \)
\( \dashrightarrow\sf{E_s}=\dfrac{22\cancel0}{10\cancel0}\)
\( \\ \\ \)
\( \dashrightarrow\sf{E_s}=\dfrac{22}{10}\)
\( \\ \\ \)
\( \dashrightarrow\bf{E_s}=2.2 \: volt\)
review |constants one day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a small patch of light on the far wall. having recently studied optics in your physics class, you're not too surprised to see that the patch of light seems to be a circular diffraction pattern. it appears that the central maximum is about 2 cm across, and you estimate that the distance from the window shade to the wall is about 5 m .Estimate the average wavelenght of the sunlight: A.350 mm B.450 mm C.550 mm D.650 mm D.750 mm
"Estimate the average wavelength of the sunlight," the correct answer is: C.550 mm.
Explanation: Given, The diameter of the diffraction pattern is 2 cm.
Distance, d=5 m Wavelength, λ=?
We know that,
dλ=dy/D Where, y=D/2d is the diameter of diffraction and D is the distance between the window shade and wall.
Substituting the given values, We get,λ=d.y/Dλ=5x10^(-1) x 2 / 5λ= 0.2λλ=λ (10^3) mmλ= 200 / 3 mmλ= 66.7 mm.Average Wavelength of sunlight, λ= 550 mm. Therefore, the correct option is C.550 mm.
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HELP I NEED THIS QUICK PLEASE
First let's see what the funny letters in the equation they gave us means.
F = Gravitational Force
G = Gravitational Constant
m1 = Mass of one of the spheres
m2 = Mass of the other sphere
r = Distance between the two spheres
Ok, now implement it.
\(\frac{9.8 x 10^{2} 1.96 x 10^{2} }{4^{2} }\)
To make it simpler
F = 980 x 196 = 192,080
192,080 ÷ 4²
192,080 ÷ 16
= 12005
F = 12,005N
In the 1986 Olympic Games abdon pamich of Italy won the 50km walk, in 4h 11min 11.2s. Find his average speed
Becky just watched a video of a child hitting a doll. According to Albert Bandura's research, Becky will now
Large muscle movements are required for gross motor skills, which include autonomous sitting, crawling, walking, and running.
Does running help you lose tummy fat?However, the good news is that running is one of the finest kinds of exercise to lose belly fat, and there are even a few minor adjustments you can make to your regular running program to offer a continuous fat burning boost.
How healthy is running?One of the great cardio exercises is running or jogging. Your risk of developing cardiovascular disease can be considerably reduced by running for at minimum ten minutes every day. Running cuts the chance that you will die from disease in half.
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If you are given force and distance, you can determine power if you know
A. joules
B. energy
C. time
D. watts
Answer:
C. Time
Explanation:
Answer: time because i am so good
Explanation:
How much net force is required make a 10 kg box accelerate at a rate of 5 m/s2?
O2N
0 50 N
0 15 N
0 100 N
The cricket player while catches the ball wears gloves and why
Answer:
the ball is travelling very fast and the player can get injured if he doesn't wear gloves
Explanation:
An object that weighs 75 N is pulled on a horizontal surface by a horizontal pull of 50 N to
the right. The friction force on this object is 30 N to the left. What is the acceleration of the
object?
Using the Newton Laws, the acceleration of the object is 2.67m/s²
Based on the problem, we can draw the diagram as below to help our understanding.
From the information provided we know that:
F = 50 N (horizontal pull)
W = 75 N
f = 30 N (friction force)
From the picture, we could focus first on the X-axis, where the horizontal force and the friction force work on the object. We would apply the second law of Newton for this axis since there is movement happening within this axis.
∑Fx = m.a
F - f = m.a
50 - 30 = m.a
m.a = 20N ... (i)
Next, we will focus on the Y-axis. In this axis neutral force and weight are working but not resulting to any movement within the axis. ence, we will be applying the first law of Newton:
∑F = 0
N - W = 0
N = W
N = 75N ... (ii)
Since we know that weight is the result of multiply between mass and gravity, we could find the mass of the object by assuming the gravity is 10m/s²
W = m.g
75 = m (10)
m = 7.5kg ... (iii)
We could subtitute the equation (iii) into equation (i) to find the acceleration of the object:
m.a = 20N
(7.5) a = 20N
a = 2.67m/s²
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Which scenario displays the corporate responsibility of a business toward a community?
A.
paying the correct amount of taxes on time
B.
contributing supplies to charities to help in disaster relief
C.
fair return of profits and arranging training programs
D.
serving customers to the best of their potential
Answer:
A.
Explanation:
Because you are working in the buisnes, you can make a good impression by paying the exact amount or more in taxes.
why is copper (relative conductivity =0.945) a better conductor than aluminum (relative conductivity =0.575), which happens to be cheaper and more malleable?
Copper is a better conductor than aluminum due to its higher electrical conductivity. The electrical conductivity of a material depends on the mobility of the electrons in the material. Copper has more free electrons available for conduction, and these electrons are more mobile in copper than in aluminum.
This means that a given voltage applied across a length of copper wire will result in a larger current than the same voltage applied across the same length of aluminum wire. Copper is therefore more efficient in transmitting electrical energy, making it a better choice for many electrical applications, especially those where low resistance is critical.
While aluminum is cheaper and more malleable than copper, its lower conductivity means that more aluminum must be used to achieve the same level of electrical conductivity as copper. This can offset the cost savings of aluminum in some applications.
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Taylor's car broke down and he exerted a force of 8,000 newtons trying to push it before giving up and calling the tow truck. How much work did he accomplish
He accomplished no job. When Taylor's car broke down, he attempted to push it with 8,000 newtons of force before giving up and calling a tow truck.
The amount that indicates how many times a machine multiplies a force is known as what?The mechanical advantage is how many times a machine can multiply the force of the effort. The mechanical advantage of the machine increases when the effort force is exerted across a bigger distance.
Please describe force multiplier machines and provide two instances.Force multipliers are tools that lessen the force required to move an object. Force multipliers come in handy when lifting heavy objects or performing other actions that call for a lot of force.
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For the following six questions, match the descriptions to the below people (A-J)
A) Eratosthenes B) Aristarchus C) Isaac Newton D) Aristotle E) Ptolemy F) Galileo G) Hipparchus H) Kepler I) Nicolaus Copernicus J) Tycho Brahe
23. Discovered the phases of Venus using a telescope.
24. First to consider ellipses as orbits.
25. Foremost ancient Greek philosopher.
26. Ancient Greek who believed in a sun-centered universe.
27. First to measure the size of the Earth to good accuracy.
28. Developed the first predictive model of the solar system.
The correct match of the descriptions to the below people are 23 - F, 24 - H, 25 - D, 26 - I, 27 - A, 28 - B.
23 - F Galileo: Galileo Galilei is credited with discovering the phases of Venus using a telescope. Through his observations, he observed that Venus went through a series of phases similar to those of the Moon, which supported the heliocentric model of the solar system.
24 - H Kepler: Johannes Kepler was the first to consider ellipses as orbits. He formulated the laws of planetary motion, known as Kepler's laws, which stated that planets move in elliptical paths with the Sun at one of the foci. Kepler's work revolutionized our understanding of celestial mechanics.
25 - D Aristotle: Aristotle, the ancient Greek philosopher, is considered one of the foremost thinkers in history. While his contributions span various fields, including philosophy and natural sciences, his views on astronomy were geocentric. He believed that the Earth was the center of the universe and that celestial bodies moved in perfect circles around it.
26 - I Nicolaus Copernicus: Nicolaus Copernicus was an astronomer who proposed the heliocentric model of the solar system, in which the Sun, rather than the Earth, was at the center. Copernicus's revolutionary idea challenged the prevailing geocentric view and laid the foundation for modern astronomy.
27 - A Eratosthenes: Eratosthenes was an ancient Greek mathematician and astronomer who made significant contributions to geography and astronomy. He is known for his accurate measurement of the Earth's circumference. By measuring the angle of the Sun's rays at two different locations, he estimated the Earth's circumference with remarkable accuracy.
28 - B Aristarchus: Aristarchus of Samos is credited with developing the first predictive model of the solar system. He proposed a heliocentric model centuries before Copernicus, suggesting that the Sun was at the center of the universe, with the Earth and other planets orbiting it. Aristarchus's model was a significant departure from the prevalent geocentric view of the time.
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30. You should allow more space in front of your vehicle when following large trucks because: A. You need the extra room to see around the truck B. Their heavier weight allows them to stop more quickly than you C. If you follow too closely, you will get caught in the wind draft caused by the truck
You should allow more space in front of your vehicle when following large trucks because: A. You need the extra room to see around the truck.
What is a traffic rule?A traffic rule is an accepted and enforceable law or guideline established by a road safety agency, so as to give warnings and instructions to road users such as the following:
PedestriansDriversIn accordance with national traffic rules and regulations, it is very important and essential for the drivers of small vehicles to allow more space in front of them when they are behind large trucks in order to give extra room to see around the truck.
In conclusion, it is very important for a driver to ensure that his or her blind spot is clear at all times.
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10 Waves Question 2 of 10 A wave travels at a speed of 74 m/s. If the distance between crests is 12 m, what is the frequency of the wave? Use j A. 0.16 Hz B. 6.2 Hz C. 890 Hz D. 62 Hz SUBMIT
Answer: B 6.2 Hz
Explanation: Equation for waves v = λf.
Frequency = speed / wavelength f = v/λ
f = 74 m/s / 12 m = 6.166... Hz
Answer:
Rounding is necessary: the answer is 6.2 Hz
Explanation:
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My Science teacher is absolutely no help!!
2. A baseball pitcher throws a pitch at a speed of 90 mph. The baseball has a mass of 0.15 kg and a radius of 0.03 m. Calculate the angular momentum of the baseball.
The angular momentum of the baseball, given that the baseball has a mass of 0.15 kg and a radius of 0.03 m is 0.181 Kgm²/s
How do I determine the angular momentum?Angular momentum is simply defined as the product of mass, velocity and radius as shown by the following formula:
Angular momentum = mass × velocity × radius
With the above formula, we can obtain the angular momentum of the baseball as illustrated below:
The following data were obtained from the question:
Velocity = 90 mph = 90 × 0.447 = 40.23 m/sMass = 0.15 KilogramsRadius = 0.03 mAngular momentum =?Inputting the variables into the above formula, we have:
Angular momentum = mass × velocity × radius
Angular momentum = 0.15 × 40.23 × 0.03
Angular momentum = 0.181 Kgm²/s
Thus, from the above calculation, we can conclude that the angular momentum of the baseball is 0.181 Kgm²/s
Learn more about angular momentum:
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What can chemical formulas represent?
A.) mixtures
B.) elements
C.) compounds
D.) atoms
Answer:
A chemical formula identifies each constituent element by its chemical symbol and indicates the proportionate number of atoms of each element. In empirical formulae, these proportions begin with a key element and then assign numbers of atoms of the other elements in the compound, by ratios to the key element.
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