A few years ago, the legal speed limit on the Turner Turnpike between Tulsa and Oklahoma City was changed from 55.0 mi/h to 75.0 mi/h. How much time was saved on the 86.0 mile trip for someone traveling at the legal speed limit? May I have help solving this?

Explanation:

it has no energy when considered with respect to earth ,as it has neither height (i e potential energy) nor velocity (i.e kinetic energy).

Answer:

D. Conclusion.

Explanation:

Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 95 × 25

We have the final answer as

Hope this helps you

Answer:

v = 50 ms^1

Explanation:

We know:

F = 10N

m = 2kg

t = 10 sec

F=ma

10 = 2*a

5=a

a = 5 ms^2

Now,

a=v/t

5 = v/10

50 = v

v = 50 ms^1

Differentiate the components of position to get the corresponding components of velocity :

\(v_x = \dfrac{\mathrm dx}{\mathrm dt} = \left(1.5\dfrac{\rm m}{\mathrm s^3}\right) t^2 - \left(4\dfrac{\rm m}{\mathrm s^2}\right)t\)

\(v_y = \dfrac{\mathrm dy}{\mathrm dt} = \left(1\dfrac{\rm m}{\mathrm s^2}\right)t-2\dfrac{\rm m}{\rm s}\)

At t = 5.0 s, the particle has velocity

\(v_x = \left(1.5\dfrac{\rm m}{\mathrm s^3}\right) (5.0\,\mathrm s)^2 - \left(4\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s) = 17.5\dfrac{\rm m}{\rm s}\)

\(v_y = \left(1\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)-2\dfrac{\rm m}{\rm s} = 3.0\dfrac{\rm m}{\rm s}\)

The speed at this time is the magnitude of the velocity :

\(\sqrt{{v_x}^2 + {v_y}^2} \approx \boxed{17.8\dfrac{\rm m}{\rm s}}\)

The direction of motion at this time is the angle \(\theta\) that the velocity vector makes with the positive x-axis, such that

\(\tan(\theta) = \dfrac{3.0\frac{\rm m}{\rm s}}{17.5\frac{\rm m}{\rm s}} \implies \theta = \tan^{-1}\left(\dfrac{3.0}{17.5}\right) \approx \boxed{9.73^\circ}\)

An electric iron is marked 120 volts and 500 Watts. The units consumed by it in using it for 24 hours can be calculated using the formula:Power (in watts) = Voltage (in volts) x Current (in amperes)P = V x I

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Work done on an object by a constant force is known as Constant Work, whereas the work done on an object by variable force is known as Variable Work.

In constant work or work done by constant force, the magnitude and direction of the force are constant or they do not change. Therefore, constant work is simply calculated by force acting on the object multiplied by displacement of the object.

But in case of variable work, things are not so easy. In this scenario, the force's magnitude and direction may alter at any point while the job is being done. The majority of the work we do on a daily basis is an instance of variable force work. The same calculation involves integration and is fairly difficult.

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A 7 kg mass moving across the table at an acceleration of 25 m\(/s^2\)requires a force of 175 N.

To determine the force required to cause the acceleration of a 7 kg mass moving across the table at 25\(m/s^2\), we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.

Given:

Mass (m) = 7 kg

Acceleration (a) = 25 \(m/s^2\)

We can substitute these values into the equation:

Force (F) = mass (m) * acceleration (a)

F = 7 kg * 25 \(m/s^2\)

F = 175 kg·\(m/s^2\)

Therefore, the force required to cause the acceleration of the 7 kg mass is 175 kg·\(m/s^2\).

To understand the calculation, we need to know that force is a measure of how much an object accelerates when a certain amount of mass is acted upon by that force. In this case, the mass of the object is 7 kg, and it is experiencing an acceleration of 25\(m/s^2\).

By multiplying the mass and acceleration together, we find that the force required is 175 kg·\(m/s^2\). This unit, also known as a Newton (N), represents the force required to accelerate a 1 kg mass at a rate of 1 \(m/s^2\)

In summary, the force required to cause the acceleration of the 7 kg mass across the table at 25 \(m/s^2\) is determined to be 175 kg·\(m/s^2\). This calculation follows Newton's second law of motion and shows the relationship between mass, acceleration, and force.

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The formula for centripetal acceleration within the spacecraft is: ac =The outside radius of a spacecraft's doughnut-shaped body is 440 metres. The people are standing with thier feet on an outer rim and their heads .

Earth's crust is made of igneous, metamorphic, or sedimentary rocks, which range in composition from mud or clay to diamonds or coal. Igneous rocks, which are created as magma cools, are the most prevalent types of rocks in the crust. Igneous rocks like granite and basalt are abundant in the crust of the Earth.

The distance between any two places on a circle's circumference is in fact its radius. R or r are frequently used to denote it. Almost all calculations involving circles take this quantity into account. The radius of a circle can be used to determine a circle's circumference and surface area.

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To determine the resultant electric field strength at point X, we need to calculate the individual electric field strengths created by each point charge and then add them as vectors.

The electric field strength created by a point charge is given by the equation:

E = k * |q| / r^2

where E is the electric field strength, k is the electrostatic constant (k ≈ 8.99 × 10^9 N m^2/C^2), q is the magnitude of the charge, and r is the distance from the charge.

For charge 1 (q1 = +2.0) at point X, the distance is 40 units:

E1 = (8.99 × 10^9 N m^2/C^2) * |2.0 C| / (40 m)^2

E1 = 11243750 N/C

For charge 2 (q2 = -3.0) at point X, the distance is also 40 units:

E2 = (8.99 × 10^9 N m^2/C^2) * |3.0 C| / (40 m)^2

E2 = 16865625 N/C

To determine the resultant electric field at point X, we need to add the two electric field vectors:

EResultant = E1 + E2

EResultant = 11243750 N/C + 16865625 N/C

EResultant = 28109375 N/C

Therefore, the resultant electric field strength at point X is 28109375 N/C.

To determine the electric force on a point charge (q3 = 0.50) placed at point X, we can use the equation:

F = q3 * EResultant

F = (0.50 C) * (28109375 N/C)

F = 14054687.5 N

Therefore, the electric force acting on the point charge at point X is 14054687.5 Newtons.

The student measured the length of a wire four times and the total length from the reading is 18.55 m.

From the given,

The length of the wire measured by the student using a meter rule is :

l₁ = 18.6 m

l₂ = 18.5m

l₃ = 18.6m

l₄ = 18.5 m

The total length of the wire is obtained from the average values of length.

Total length (L) = (l₁ + l₂ + l₃ + l₄)/4

                     L  = (18.6 + 18.5 + 18.6 + 18.5) / 4

                         = 74.2 /4

                         = 18.55

Hence, the actual length of the wire = 18.6 m.

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The value of the rate constant at 457 K is 0.478 M/s.

The rate constant, k, at a given temperature can be related to the activation energy, Ea, and the gas constant, R, through the Arrhenius equation:

\(k = Ae^{(-Ea/RT)}\)

where A is the pre-exponential factor and T is the temperature in Kelvin.

Given k1 = 0.178 M/s at T1 = 280 K, and Ea = 37.8 kJ/mol, we can calculate the rate constant, k2, at T2 = 457 K as:

k2 = A * \(e^{(-Ea/R * T2)}\) = 0.178 * \(e^{(-37.8 kJ/mol / (8.314 J/mol K) * 457 K)}\) = 0.478 M/s.

This means that the reaction will proceed faster at 457 K than it does at 280 K, due to the increase in temperature leading to an increase in the rate constant, k.

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The sound from a tuning fork is not a transverse wave but a longitudinal wave

A common example of longitudinal waves is sound waves, which are pressure waves or vibrations that travel through air or other materials, like water. Tuning forks produce a single note, or a specific sound, when struck by making the arms move in and out very rapidly (hundreds or thousands of times a second).

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The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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The density of the liquid as measured by the student is 1.9473 g/ml

Definition of density: A material's density is determined by how closely it is packed. As the mass per unit volume, it has that definition. Symbol for Density: D or Density

Given Data

Mass = 2.22g ± 0.05g

Volume = 1.14 ± 0.04 ml

We know that the expression for density is given as

Density = Mass/Volume

Substituting our given data into the expression above, we have

Density = 2.22/1.14

Density = 1.9473 g/ml

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Answer:

e

Explanation:

Answer:

i Believe the correct answer is "An open circuit being changed into a closed circuit"

Explanation:

1a) Energy is absorbed, and the reaction is endothermic.

1b) The products have higher potential energy, the enthalpy change is positive, indicating an endothermic reaction.

1c) The peak of the potential energy diagram.

2a) The activation energy labeled as the difference between the reactants and the peak

2b) The activation energy can be determined by calculating the difference between the reactants.

2c) The enthalpy change can be calculated by finding the difference between the energy of the reactants and the energy of the products.

2d) The reaction is exothermic. In terms of the graph's shape.

3a) A decrease in potential energy as the products form.

3b)This indicates that a small amount of energy from the spark is needed to overcome the activation energy barrier

Part 1:

1a. To determine if the reaction is endothermic or exothermic, we need to analyze the potential energy diagram. If the products have lower potential energy than the reactants, it indicates that energy is released, and the reaction is exothermic. Conversely, if the products have higher potential energy than the reactants, it suggests that energy is absorbed, and the reaction is endothermic.

1b. The enthalpy change (ΔH) for the reaction can be calculated by comparing the potential energy of the products and the reactants. If the products have lower potential energy, the enthalpy change is negative, indicating an exothermic reaction. If the products have higher potential energy, the enthalpy change is positive, indicating an endothermic reaction.

1c. The activation energy (Ea) can be determined by examining the energy difference between the reactants' potential energy and the peak of the potential energy diagram.

Part 2:

2a. Since the energy of the reactants is 30 kJ, the energy of the products is 5 kJ, and the maximum energy of the system is 40 kJ, we can sketch a potential energy diagram with the reactants at 30 kJ, the products at 5 kJ, the activation energy labeled as the difference between the reactants and the peak, and the enthalpy change as the difference between the reactants and products.

2b. The activation energy can be determined by calculating the difference between the reactants' energy and the peak of the potential energy diagram.

2c. The enthalpy change can be calculated by finding the difference between the energy of the reactants and the energy of the products.

2d. Based on the energy values, if the energy of the products is lower than the energy of the reactants, the reaction is exothermic. In terms of the graph's shape, if the potential energy decreases from reactants to products, it indicates an exothermic reaction.

Part 3:

3a. The potential energy diagram for the striking and burning of a match can be sketched to show the initial potential energy of the reactants, a peak representing the activation energy, and a decrease in potential energy as the products form.

3b. The potential energy diagram would show an initial higher potential energy for the reactants, a peak representing the activation energy required for the reaction to occur, and a decrease in potential energy as the products form. This indicates that a small amount of energy from the spark is needed to overcome the activation energy barrier, leading to the release of a greater amount of energy during the burning process.

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Answer:

Star characteristics consider physical characteristics such as stellar mass, size, surface temperature, and luminosity .

Answer:

They are made of gases.

Explanation:

Edg 2020

Without falling off the merry-go-round, the guy can stand up to a distance of roughly 1.42 m from the axis of rotation.

This equation demonstrates how the square of the angular velocity and the moment of inertia are inversely related to the kinetic energy of a spinning rigid body.

The sources of the centrifugal force are:

F = m r ω²

The formula for static friction's force is

F_friction = μ_s N

The weight of a man is equal to the normal force N, which is determined by:

N = m g

The centrifugal force equals the static friction force at the point where the man is about to slide, hence we have:

F = F_friction

m r ω² = μ_s N

Substituting N = m g, we get:

r = (μ_s g) / ω²

Substituting μ_s = 0.35, g = 9.81 m/s², and ω = 2.5 rad/s, we get:

r = (0.35 x 9.81 m/s²) / (2.5 rad/s)² ≈ 1.42 m

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Answer:

C

Explanation:

An object in motion will stay in motion unless acted on by a net positive or negative force.

For answer A. If the object were to be in an orbit, it would inevitably accelerate due to it being acted on by the gravitational force from the object it is orbiting. At different points in the orbit, the object will move at different speeds and continuously transfer between kinetic and potential energy.

For answer B. The object would would not stop their motion. In order for the object to lose energy, it would have to transfer it through friction or through its interaction with a gravitational field.

For answer D. No energy is "required" to maintain constant motion unless the object is willingly fighting against a resistive force like friction or a graviational well.

Answer:

Explanation:

Reduce the fan speed (to lower the power required).

Clean the fan blades to reduce the weight of the fan blades (and reduce the work required to move the blades).

Dehumidify the air to reduce the weight of the air the fan has to move.

Place a bucket of ice in front of the fan as a homemade AC unit.  Cold air is less dense than warm or hot air and requires less work from the fan to circulate it.

An example of a time a Christmas movie modeled acceleration on incline with friction (physics) is:

It is not uncommon for movies, including Christmas movies, to depict characters moving up or down inclines or hills. In such cases, the motion of the characters can be analyzed using the principles of physics, including acceleration and friction.

In continuation of the story above:

Therefore, By applying the laws of motion to these forces, we could calculate Buddy's acceleration as he runs up the hill.

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Answer:

~4%

Explanation:

% = |(7.6 - 7.9)|/7.9

= 0.3/7.9 ≈ 0.04 = 4%

Answer: The scenario violates the second law of thermodynamics.

Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.

The momemtum is not conserved in scenario d.

Momentum of an object is the product of its mass and velocity.

To determine in which of the conditions in which momentum is not conserved, we need to know the law of conservation of momentum.

The law of conservation of momentum states that as long as no external force acts on a system, the total momentum of the system of two colliding objects is conserved.

If we consider scenarios a, b and c, we see that no external force acts on the system of two objects in the three instances so, the total momentum is conserved.

In scenario d, an external force acts on the system, so total momentum is not conserved since according to the law of conservation of momentum, total momentum is only conserved when there is no external force acting on a system.

So, the momemtum is not conserved in scenario d.

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Answer:

1. Distance travelled = 12 km.

2. Displacement = 8.6 km

Explanation:

From the question given above, the following data were obtained:

Distance 1 (d₁) = 7 km

Distance 2 (d₂) = 5 km

Total distance =?

Displacement =?

1. Determination of the distance travelled.

Distance 1 (d₁) = 7 km

Distance 2 (d₂) = 5 km

Total distance (dₜ) =?

dₜ = d₁ + d₂

dₜ = 7 + 5

dₜ = 12 km

2. Determination of the displacement.

In the attached photo, R is the displacement.

We can obtain the value of R by using the pythagoras theory as illustrated below:

R² = 7² + 5²

R² = 49 + 25

R² = 74

Take the square root of both side

R = √74

R = 8.6 km

In relation to their orbits, all of the planets are substantially too big. According to Kepler's first law, the Sun is at one focus of each planet's elliptical orbit.

It specifies three requirements for a planet: It must revolve around the Sun, a planet in our solar system. It must be large enough for gravity to pull it in a spherical direction. It must have been large enough that any nearby objects of a similarly sized were removed by its gravitational pull.

The interior planets are all solid rocky, dense planets The moons of the inner planets are either absent or limited to one Earth or three Mars. The inner planets don't have any rings. The planets orbits have smaller orbits all around Sun than the outer planets, but they all rotate more slowly.

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Answer: 12 ounce steak on venus

Explanation: venus = closer to the sun. The sun = more potential gravity, which would make it heavier than a quarter pound hamburger on jupiter.

Grouping data refers to the process of categorizing or organizing data based on specific criteria or attributes.

It involves grouping similar data points together to gain a better understanding of patterns, relationships, and trends within the dataset. By grouping data, you can simplify complex information and derive meaningful insights from large amounts of data. The purpose of grouping data is to create subsets or clusters that share common characteristics.

This enables easier analysis, summarization, and comparison of data within each group. Grouping can be performed on various types of data, such as numerical, categorical, or time-based data. Grouping data allows for the exploration of data at different levels of granularity.

For example, you can group sales data by region to analyze regional performance, or group customer data by demographics to identify specific customer segments. This process helps in identifying outliers, detecting patterns, and making data-driven decisions.

Common techniques for grouping data include using functions like GROUP BY in SQL or utilizing data visualization tools to create charts or graphs that illustrate the grouped data. Grouping can be applied in various fields, such as marketing, finance, healthcare, and research, to uncover insights and support decision-making processes.

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