A farmer pushes a 50 kg wheel barrow from rest to a speed of 5.0 m/s through a distance of 8.0 m. There is no friction acting between the ground and the wheel barrow, and the farmer is pushing the wheel barrow in the same direction it moves, the work done by the farmer on the wheel barrow is ___ J.

2. A 1400 kg roller coaster begins at a speed of 7.0 m/s and a height of 30 m above the ground. It rolls down the track to ground level. When the roller coaster is one-third of the way down the track (20 m above the ground), it is travelling at _____ m/s.

3. In order to slow a 76.0 kg rider (and bike) from 13.0 m/s to 4.00 m/s, what amount of work must be done?

In physics, there are certain properties that are considered absolute and independent of frame of reference. These properties include the speed of light, the laws of thermodynamics, and the principle of conservation of energy.

The speed of light is an absolute property because it remains constant regardless of the observer's motion or frame of reference. This was first demonstrated by the famous Michelson-Morley experiment, which showed that the speed of light is the same in all directions and at all times. This property forms the basis of Einstein's theory of relativity, which has revolutionized our understanding of the universe.

The laws of thermodynamics are also considered absolute because they describe fundamental principles of nature that hold true under all conditions. These laws govern the behavior of energy in all physical systems and are essential for understanding everything from the behavior of atoms to the workings of the universe itself.

Finally, the principle of conservation of energy is another absolute property that is independent of frame of reference. This principle states that energy cannot be created or destroyed, only transformed from one form to another. This principle has been extensively tested and confirmed in countless experiments, and forms the basis of our understanding of energy and its role in the physical world.

Overall, these absolute properties are fundamental to our understanding of physics and the natural world, and form the basis of many of our most important scientific theories and discoveries.

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The angular velocity of a bicycle with initial angular velocity of 1.5 rad/s and  angular acceleration of 0.2 rad/s² can be expressed as ω(t) = 1.5 + 0.2 t

Angular velocity tells us how fast an object rotates about an axis. The formula for the angular velocity at time t, with a constant angular acceleration, is:

ω(t) = ω(0) + α . t

Where:

ω(0) = initial angular velocity

α = angular acceleration

t = t period

Parameters given in the problem:

ω(0) = 1.50 rad/s

α = 0.200 rad/s²

Plug these parameters into the formula:

ω(t) = 1.5 + 0.2 t

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Answer:

Ton 618

Explanation:

Ton 618 is considered to be one of the largest known black holes, with an estimated mass of 66 billion times that of our sun. On the other hand, Phoenix A, also known as MRC 1138-262, is not a black hole but a galaxy cluster that contains a supermassive black hole at its center.

So, in terms of black hole size, Ton 618 is larger than Phoenix A since Phoenix A does not refer to a black hole but to a galaxy cluster.

black hole ton 618 is larger than phounex.

Both Phoenix A and Ton 618 are quasars that are powered by supermassive black holes, but their black holes themselves have not been directly measured. Therefore, it is not currently possible to determine which black hole is larger based on direct observations.

However, the mass of the black holes in Phoenix A and Ton 618 can be estimated indirectly by studying the motion of stars and gas around them, among other methods. According to some estimates, the black hole in Ton 618 has a mass of around 66 billion times the mass of the Sun, while the black hole in Phoenix A has a mass of around 20 billion times the mass of the Sun. Therefore, based on these estimates, the black hole in Ton 618 is larger than the black hole in Phoenix A.

It is important to note that these estimates are subject to some uncertainty and may be revised as more data becomes available.

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Answer:

Distance from the moon= dm= 384,403km

A quarter diameter= dq= 2.3 cm= 0.000023km

No of quarters= 16,713,173, 913

To convert cm into km divide cm by 100 and then by 1000

as

1m= 100cm

1km= 1000m

Therefore

2.3/100= 0.023 m

And

0.023/1000= 0.000023 km

Dividing the distance from the moon by the diameter of the quarter laid end to end would give the number of the quarters needed.

No. of quarters= Distance from the moon/ Diameter of the quarter

                             = 384,403km/0.000023 km

                             =       16,713,173,913.043

Rounding  16,713,173,913.043 gives 16,713,173,913 quarters

Explanation:

Brainliest, please!

Based on the given information, we know that there is an unknown planet with two moons in circular orbits. The table provides hypothetical data about the moons, which we can use to make calculations. To start, we need to look at the table and see what information is given. We have the masses of both moons (m1 and m2), as well as their distances from the planet (r1 and r2). We also have the gravitational constant, which is g = 6.67 × 10^-11 nm^2/kg^2.

Using this information, we can calculate the gravitational force between each moon and the planet using the formula F = G(m1m2)/r^2, where G is the gravitational constant, m1 and m2 are the masses of the moons, and r is the distance between the moon and the planet. Let's start by calculating the gravitational force between the first moon and the planet. We have m1 = 8.0 x 10^22 kg and r1 = 4.0 x 10^5 nm. Plugging these values into the formula, we get:
F1 = (6.67 x 10^-11)(8.0 x 10^22)(5.0 x 10^5)^2
F1 = 1.34 x 10^32 N
Now, let's calculate the gravitational force between the second moon and the planet. We have m2 = 5.0 x 10^22 kg and r2 = 3.0 x 10^5 nm. Plugging these values into the formula, we get:
F2 = (6.67 x 10^-11)(8.0 x 10^22)(4.0 x 10^5)^2
F2 = 4.45 x 10^31 N

Next, we can use the gravitational forces to calculate the orbital velocities of the moons. We can do this using the formula v = (GM/r)^0.5, where G is the gravitational constant, M is the mass of the planet, and r is the distance between the moon and the planet. To calculate the orbital velocity of the first moon, we need to know the mass of the planet. Unfortunately, this information is not given in the table, so we can't make this calculation. However, we can still calculate the orbital velocity of the second moon. Let's assume that the mass of the planet is 5.0x 10^24 kg (which is roughly the mass of Earth). Plugging in the values for F2, G, and r2, we get:
v2 = (GM/r2)^0.5
v2 = ((6.67 x 10^-11)(5.0 x 10^24)/(3.0 x 10^5))^0.5
v2 = 1.98 x 10^3 m/s
So the orbital velocity of the second moon is approximately 1.98 x 10^3 m/s.
Overall, without knowing the mass of the planet, we cannot fully determine the orbital velocities of both moons. However, we were able to calculate the gravitational forces between the planet and each moon using the given data in the table.

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Option A is the correct answer: The rings of the outer planets consist of sheets of ice that stretch in round planes millions of miles wide around each planet.

The rings of the outer planets consist of small particles, ranging in size from micrometers to meters. These particles are made up of water ice, rock, and other materials. The rings are thought to have been formed from the debris of moons or comets that were destroyed by tidal forces or impacts with other objects. The particles are held in orbit by the planet's gravitational field and are constantly colliding with each other, creating a collisional cascade that produces smaller particles.

The rings are not solid sheets, but rather a collection of individual particles that orbit the planet in circular paths. They are very thin, only a few meters thick in some cases, and can extend outwards for millions of kilometres. The particles in the rings are also subject to a number of forces, including gravity from the planet and other nearby moons, as well as radiation pressure from the sun.

The structure of the rings can be very complex, with gaps and divisions between different sections of the ring. These gaps are thought to be caused by the gravitational influence of nearby moons, which can cause the particles in the rings to either clump together or disperse. Some moons are even responsible for creating entire rings themselves, such as Saturn's moon Phoebe, which is thought to have contributed material to Saturn's E ring. Overall, the rings of the outer planets are fascinating and complex structures that have puzzled astronomers for centuries.

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The rings of the outer planets are composed of billions of small icy fragments orbiting around the equator of each planet. These rings display complex structures influenced by the planet's gravitational force and interactions with their moons. The exact origin and age of these rings are still unknown.

The rings of the outer planets such as Saturn, Uranus, Neptune and Jupiter are made up of billions of small particles orbiting around the equator of each planet. These rings are flat and nearly continuous, with a few gaps. Each ring is composed of huge collections of icy fragments which primarily consist of water ice. The size of these fragments varies, but typical dimensions range from a few centimeters like the size of ping-pong balls, tennis balls, or basketballs.

The structure of these rings is influenced by the gravitational forces of the planets which could have broken apart larger pieces or prevented small pieces from gathering together. Interactions between the ring particles and the moons that also orbit these giant planets add to their complex structures. The exact origin and age of these ring systems, however, remains a mystery.

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From Rutherford  and Marsden scattering experiment, we can conclude that the particle shown in red will come straight back from the foil because it is deflected by the charge in the gold nucleus.

Rutherford proposed Planetary model atom, which visualized an atom to consists of a positively charged heavy core called the nucleus around which negatively charged electrons circle in orbits much as planets move round the sun

Thus, from Rutherford  and Marsden scattering experiment, we can conclude that the particle shown in red will come straight back from the foil because it is deflected by the charge in the gold nucleus.

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the answer is reflected or u can say repelled

If one object has a greater speed than a second object, the first not necessarily have a greater acceleration.

Acceleration is the rate of change of velocity. An object can have a greater speed but with zero acceleration if the velocity is constant.

For example, Consider a driver A driving his car at a constant speed of 60 Kmph. and crosses another driver B. Consider driver B at rest the moment the driver A crosses him. But the driver B drives faster than the driver A and catches up with driver A even though the driver A was driving at 60 Kmph when the driver B just started driving from 0 Kmph.

Therefore, if one object has a greater speed than a second object, the first not necessarily have a greater acceleration.

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Its speed when it is half-way down is 7.1 m/s.

To determine the speed of the roller coaster car when it is halfway down the hill, we can use the principle of conservation of mechanical energy. At the top of the hill, the car possesses only potential energy, which is converted into kinetic energy as it descends.

Since the roller coaster car starts at rest at the top, all of its initial potential energy is converted into kinetic energy at the bottom of the hill. Therefore, we can equate the potential energy at the top to the kinetic energy at the bottom:

mgh = (1/2)mv²

Where m is the mass of the car, g is the acceleration due to gravity, h is the height of the hill, and v is the velocity at the bottom.

Since the velocity at the bottom is given as 10 m/s, we can solve for the height h using the above equation. Once we have the height, we can find the speed when the car is halfway down by finding the potential energy at that point and equating it to the kinetic energy:

(1/2)mv² = mgh/2

Since the mass and gravitational acceleration are constant, the height cancels out, and we are left with:

(1/2)v² = gh/2

Simplifying, we find:

v = √(gh/2)

Since we are halfway down the hill, the height h is halved. Thus, the speed when the car is halfway down is:

v = √(g(h/2)/2) = √(5gh/8)

Therefore, the speed when the car is halfway down the hill is given by the square root of 5/8 times the speed at the bottom.

In this case, since the speed at the bottom is 10 m/s, the speed halfway down the hill is:

v = √(5/8 * 10²) = √(500/8) ≈ 7.1 m/s

Therefore, the correct answer is 7.1 m/s.

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Answer:

A

Explanation:

ap3x

Answer:

A. Refraction

Explanation:

<3

For the 4-volt, 0.5-watt lamp to receive the proper power, R1 should be 48 ohms.

To find the required resistance of R1, we need to use Ohm's law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R), i.e., I = V/R.

First, we need to determine the current that the lamp requires. The power (P) of the lamp is given by P = IV, where I is the current flowing through it, and V is its voltage rating. We know that the power of the lamp is 0.5 watts and its voltage rating is 4 volts. Substituting these values, we get:

0.5 = I * 4

Solving for I, we get:

I = 0.5/4 = 0.125 amps

Now, we can use the current value to determine the resistance of R1 using Ohm's law. We know that the voltage drop across R1 is 6 volts (the total voltage of the battery minus the voltage of the lamp). Substituting the values of I and V into the formula, we get:

R1 = V/I = 6/0.125 = 48 ohms

Therefore, R1 should be 48 ohms to supply the correct current to the 4-volt, 0.5-watt lamp.

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Answer:

At \(t = (70 / 3) \; {\rm s}\) (approximately \(23.3 \; {\rm s}\).)

Explanation:

Note that the acceleration of the car between \(t = 0\; {\rm s}\) and \(t = 20\; {\rm s}\) (\(\Delta t = 20\; {\rm s}\)) is constant. Initial velocity of the car was \(v_{0} = 0\; {\rm m\cdot s^{-1}}\), whereas \(v_{1} = 35\; {\rm m\cdot s^{-1}}\) at \(t = 20\; {\rm s}\!\). Hence, at \(t = 20\; {\rm s}\!\!\), this car would have travelled a distance of:

\(\begin{aligned}x &= \frac{(v_{1} - v_{0})\, \Delta t}{2} \\ &= \frac{(35\; {\rm m\cdot s^{-1}} - 0\; {\rm m\cdot s^{-1}}) \times (20\; {\rm s})}{2} \\ &= 350\; {\rm m}\end{aligned}\).

At \(t = 20\; {\rm s}\), the truck would have travelled a distance of \(x = v\, t = 20\; {\rm m\cdot s^{-1}} \times 20\; {\rm s} = 400\; {\rm m}\).

In other words, at \(t = 20\; {\rm s}\), the truck was \(400\; {\rm m} - 350\; {\rm m} = 50\; {\rm m}\) ahead of the car. The velocity of the car is greater than that of the truck by \(35\; {\rm m\cdot s^{-1}} - 20\; {\rm m\cdot s^{-1}} = 15 \; {\rm m\cdot s^{-1}}\). It would take another \((50\; {\rm m}) / (15\; {\rm m\cdot s^{-1}}) = (10/3)\; {\rm s}\) before the car catches up with the truck.

Hence, the car would catch up with the truck at \(t = (20 + (10/3))\; {\rm s} = (70 / 3)\; {\rm s}\).

The mechanism that is responsible for the formation of snowflakes is the nucleation of ice crystals.

This is defined as a piece of snow which falls from the sky as a result of an extremely cold climate condition and is common in the arctic regions of the world.

Snow flakes are formed when ice crystals stick together to form the flakes which usually has a dust or pollen being formed around the area being talked about.

This is also regarded as a type of precipitation such as rain etc and is therefore the most appropriate choice.

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The actual direction of the light rays from the sun is at an angle of incidence of 70.48°

The Sun appears to be at an apparent angle from vertical to the scuba diver at this instance. The incident sunlight rays are bent at the air-water contact and eventually reach the diver's eyes.

The angle of refraction is what the scuba diver perceives as the apparent angle.

Refractive index of air, n₁ = 1.00029

Refractive index of water, n₂ = 1.33

Angle of refraction, r = 45°

According to the Snell's formula,

n₁ sin i = n₂ sin r

sin i = n₂ sin r/n₁

sin i = 1.33 x 0.71/1.00029

sin i = 0.94

Therefore, the angle of incidence of light rays from the sun is,

i = sin⁻¹(0.94)

i = 70.48°

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Momentum = (mass) x (speed)

When it's parked, it has no speed.

So the momentum when it's parked is

(303 kg) x (zero)  =  Zero

The answer is:Area=1/2×b×h

Answer:

A= b×h ÷ 2

Explanation:

The Area of a triangle formula is the Base multiplied by the Height, then divided by 2

Answer:

1-state what the lab is about, that is, what scientific concept (theory, principle, procedure, etc.) you are supposed to be learning about by doing the lab. You should do this briefly, in a sentence or two. If you are having trouble writing the opening sentence of the report, you can try something like: "This laboratory experiment focuses on X…"; "This lab is designed to help students learn about, observe, or investigate, X…." Or begin with a definition of the scientific concept: "X is a theory that…."

2-give the necessary background for the scientific concept by telling what you know about it (the main references you can use are the lab manual, the textbook, lecture notes, and other sources recommended by the lab manual or lab instructor; in more advanced labs you may also be expected to cite the findings of previous scientific studies related to the lab). In relatively simple labs you can do this in a paragraph following the initial statement of the learning context. But in more complex labs, the background may require more paragraphs.

Explanation:

Answer:

long stapler

Explanation:

Solar nebula flattening is a natural consequence of collisions between particles in a spinning cloud. therefore, option B is correct.

When a solar nebula collapses under its own gravity, it begins to spin due to the conservation of angular momentum. As the cloud spins, particles within it collide and interact. These collisions cause the cloud to flatten into a disk shape rather than remaining spherical.

Angular momentum plays a crucial role in this process. The initial slight asymmetry or irregularity in the nebula's shape leads to variations in the speeds and directions of the particles' motions. As particles collide and transfer momentum, their motion tends to align along the rotational axis of the cloud, promoting the formation of a flattened disk structure.

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The correct answer is true.

The algebraic sum of the inverses of the individual resistances is then the inverse of the equivalent resistance of two or more resistors linked in parallel.

The total or equivalent resistance, RT, is equal to half the value of one resistor if the two parallel resistances or impedances are equal and of the same value. That is equivalent to R/2, R/3, etc., for three parallel resistors of identical value.

The total resistance, RT, will always drop when more parallel resistors are added since the equivalent resistance is always smaller than the smallest resistor in the parallel network.

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Northern American Emergency Response Guide.The main goal of the ERG Handbook is to help first responders immediately identify any unique or general risks associated with the material(s) at issue.

There is also Guide 111, which is for "hazardous" materials.When using generic information, make sure to replace it with more detailed instructions as soon as new information becomes available.

The orange panel next to the diamond-shaped sign or on the extremities and sides of the a cargo tank, vehicle, or rail car may also display the 4-digit ID Number.

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Answer: False

Explanation:

A subtype discriminator is the attribute in the supertype entity that determines to which entity subtype each supertype occurrence is related. Option (a) is correct.

The entity supertype is a concept in a database schema that represents a group of entities that share the same attributes or characteristics. A subtype is a subset of entities that possess specific distinguishing characteristics or attributes that are not present in the supertype. A subtype will have at least one different attribute or relationship, apart from all of the characteristics that the supertype contains.

A subtype is a refinement of a supertype entity. An entity type, known as the supertype, has multiple subtypes that can be derived from it. Subtypes may be exclusive (disjoint) or nonexclusive (overlapping). Exclusive subtypes contain nonoverlapping entities, whereas nonexclusive subtypes have overlapping entities.

Supertype and subtype entities can be used in conjunction with the entity-relationship model. A subtype is a distinct entity that has one or more attributes that are specific to it but not present in its supertype. The subtype of an entity is said to be derived from its supertype by extension or specialization.

Therefore, option (a) is correct.

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Answer:

C. Increasing the vertical height from which the ball is thrown.

Explanation:

In this case, we understand that ball experiments a parabolical motion, which is the combination of horizontal uniform motion and vertical uniform accelerated motion, due to gravity. Equations of motion for the ball are described below:

\(x = x_{o}+v_{o,x}\cdot t\) (Eq. 1)

\(y = y_{o} + v_{o,y}\cdot t +\frac{1}{2}\cdot g\cdot t^{2}\) (Eq. 2)

Where:

\(x_{o}\), \(x\) - Initial and final horizontal positions, measured in meters.

\(y_{o}\), \(y\) - Initial and final vertical positions, measured in meters.

\(v_{o,x}\), \(v_{o,y}\) - Initial horizontal and vertical velocities, measured in meters per second.

\(g\) - Gravitational acceleration, measured in meters per second.

\(t\) - Time, measured in seconds.

Now we get (Eq. 2) and solve the expression for the time:

\(\frac{1}{2}\cdot g\cdot t^{2}+v_{o,y}\cdot t + (y_{o}-y) = 0\)

\(t = \frac{-v_{o,y}\pm\sqrt{v_{o,y}^{2}-2\cdot g \cdot (y_{o}-y)}}{g}\)

If \(v_{o,y} > 0\), \(g < 0\) and \(y_{o} -y < 0\), then maximum time occurs when:

\(t = \frac{-v_{o,y}+ \sqrt{v_{o,y}^{2}-2\cdot g \cdot (y_{o}-y)}}{g}\)

And,

\(v_{o,y}^{2}-2\cdot g\cdot (y_{o}-y)\geq 0\).

If \(y_{o}\) is increased, then \(y_{o} - y\) goes closer to zero and \(v_{o,y}^{2}-2\cdot g\cdot (y_{o}-y)\) becomes greater and time increased. Hence, we conclude that correct answer is C.

Specific heat is quantity of heat required to increase the temperature of a substance by one degree celsius.

The formula to calculate heat energy is

Q=mc∆T

We know, Q=mc∆T

Where Q = heat energy

m = mass

c= specific heat capacity

∆T= change in temperature

Thus,

According to above formula

c= Q/m∆T

Here m= 2 kg

∆T= 5 degrees

Q= 2000 joules

c= 2000/2×5

c= 200

Thus, the specific heat capacity of the block is 200.

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Answer:

A. Good conductor of heat

Explanation:

The group 10 elements are a group of chemical elements as part of VIII elements and they include nickel, platinum, palladium etc. These group of chemical elements are all d-block transition metals, highly ductile and lustrous and are mostly white to light grey in color.

The statement which most likely describes a Group 10 element is that they are good conductor of heat because they have some of the chemical and physical properties of metals.

Answer:

4 J

Explanation:

As I guess,

From the equation,

work done = force × distance travelled

                   =  2        ×    2

                   = 4 J

There are no conversions since all are given in the standard form.