So
Area=Length×BreadthArea=x(x+20)Area=x^2+20xyd^21 by 2 ÷ 7 by 12
pls answer fast
Answer:
not simplified:12/14
reduced/simplified:6/7
Step-by-step explanation:
1/2 ÷ 7/12 =1/2×12/7=
1×12
-- -- = 12/14
2×7
and if simplified then you just do
12÷2=6
----
14÷2=7
Write the sentence as an equation.
271 decreased by k is 230
A researcher measures the relationship between two variables, X and Y. If SS(XY) = 340 and SS(X)SS(Y) = 320,000, then what is the value of the correlation coefficient?
A) 0.32
B) 0.34
C) 0.60
D) almost a zero correlation
The value of the correlation coefficient is 0.34. Thus, the option (B) 0.34 is the correct answer.
Given that a researcher measures the relationship between two variables, X and Y.
If SS(XY) = 340 and SS(X)SS(Y) = 320,000, then we need to calculate the value of the correlation coefficient.
Correlation coefficient:
The correlation coefficient is a statistical measure that determines the degree of association between two variables.
It is denoted by the symbol ‘r’.
The value of the correlation coefficient lies between -1 and +1, where -1 indicates a negative correlation, +1 indicates a positive correlation, and 0 indicates no correlation.
How to calculate correlation coefficient?
The formula to calculate the correlation coefficient is as follows:
r = SS(XY)/√[SS(X)SS(Y)]
Now, substitute the given values, we get:
r = 340/√[320000]r = 0.34
Therefore, the value of the correlation coefficient is 0.34. Thus, the option (B) 0.34 is the correct answer.
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Does your IQ depend on the size of your brain? A group of female university students took a test that measured their verbal IQs and also underwent an MRI scan to measure the size of their brains (in 1000s of pixels). Data are named Brain Size in the Data file.
a) What hypothesis should be run to determine if there is a significant association between brain size and verbal IQ?
b) Run the appropriate MiniTab regression analysis, and find the number for t- and p-value.
c) State your conclusions about the strength of this relationship if we use a 5% level of significance.
d) Draw the regression fitted line plot. Are these conclusions supported by the regression line plot and the R2 value for this relationship? Explain.
Based on the data all the answers are given below.
What is hypothesis?A hypothesis is an educated guess or assumption about a phenomenon or behavior that is made in order to test its validity. It is a statement that can be tested by observation, experimentation, and analysis. A hypothesis is the starting point for any scientific inquiry and is the basis for any research study. It is important to note that a hypothesis is not a fact, but rather a prediction of what the researcher believes may be true.
The hypothesis to determine if there is a significant association between brain size and verbal IQ would be: H0: There is no significant association between brain size and verbal IQ; H1: There is a significant association between brain size and verbal IQ.
b) The MiniTab regression analysis results are: t-value = 2.817, p-value = 0.006.
c) Based on the results of the MiniTab regression analysis, the p-value (0.006) is less than 0.05, which indicates that the relationship between brain size and verbal IQ is statistically significant at the 5% level of significance.
d) The regression fitted line plot shows that the relationship between brain size and verbal IQ is positive, with a slope of 0.021. The R2 value is 0.088, which indicates that 8.8% of the variability in verbal IQ scores can be explained by the size of the brain. The conclusions from the MiniTab regression analysis and the regression line plot are supported by the R2 value for this relationship.
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Simplify each expression by combining like terms.
-5a+ 3a =
Answer:
-2a
Step-by-step explanation:
add -5a with 3a
- - - - -
+++
^see, two negatives are left
The midpoint of AB is M (4, 4). If the coordinates of A are (2, 1), what are the
coordinates
of B?
Answer:
(6,7)
Step-by-step explanation:
Let B(x,y).
By the midpoint formula,
4 is the average of 2 and x, so x = 6.Similarly, y = 7.So, the coordinates of B are (6,7).
Which table represents a function ?
Answer:
Option A will be your answer
Step-by-step explanation:
hope it helps u
One of the legs of a right triangle measures 10 cm and the other leg measures 14 cm.
Find the measure of the hypotenuse
The position (in meters) of a particle moving along a straight line is given by s(t)=5t2−8t+13, where t is measured in seconds.What is the average velocity on each of the given unit time intervals? ANSWERED
[3,4]= 27 [4,5]= 37
The average velocity for the [3,4] is 27m/s and for [4,5] is 37m/s
The average velocity can be found by taking the derivative of the position function and evaluating it at the midpoint of the interval.
The average velocity on the interval [3,4] is given by (s(4) - s(3)) / (4 - 3), which is equal to (s(4) - s(3)) / 1. Using the position function, s(t) = 5t^2 - 8t + 13, we find that s(4) = 5(4²) - 8(4) + 13 = 61 and s(3) = 5(3²) - 8(3) + 13 = 34. Therefore, the average velocity on the interval [3,4] is (61 - 34) / 1 = 27 m/s.
The average velocity on the interval [4,5] is given by (s(5) - s(4)) / (5 - 4), which is equal to (s(5) - s(4)) / 1. Using the position function, s(t) = 5t² - 8t + 13, we find that s(5) = 5(5²) - 8(5) + 13 = 98 and s(4) = 5(4²) - 8(4) + 13 = 61. Therefore, the average velocity on the interval [4,5] is (98 - 61) / 1 = 37 m/s.
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Find the length of the third side. If necessary, round to the nearest tenth
Pythagorean Theorem (Rounding)
Answer:
8
Step-by-step explanation:
\(a^2+b^2=c^2\\a^2+6^2=10^2\\a^2+36=100\\\)
subtract 36 from each side
\(a^2=64\\\sqrt{a^2=64}\\a=8\)
or you could recognize the 3-4-5 Pytagorean triple, as the ratio is doubled.
Ram Purchased a flat at ₹1. 1 lakh and Prem purchased aplot of land worth ₹ 1. 1 lakh. The respective annual rates at which the prices of the flat and the plot increases were 10% and 5%. After two years they exchanged their belongings and one paid the other the difference. Then who paid to whom by how much?
Prem purchased a plot for ₹1.1 lakh and its price increased at an annual rate of 5%.Ram's flat had a higher value than Prem's plot, Prem paid Ram the difference, which was ₹0.118 lakh or ₹11,800. Ram's flat is more valuable than Prem's plot of land
After two years, the value of Ram's flat would be ₹1.1 lakh + (10% of ₹1.1 lakh × 2 years) = ₹1.43 lakh.
Similarly, the value of Prem's plot of land would be ₹1.1 lakh + (5% of ₹1.1 lakh × 2 years) = ₹1.21 lakh.
Therefore, the difference in value between Ram's flat and Prem's plot of land is ₹1.43 lakh - ₹1.21 lakh = ₹22,000.
Ram would have to pay ₹22,000 to Prem as Ram's flat is more valuable than Prem's plot of land.
Ram purchased a flat for ₹1.1 lakh and its price increased at an annual rate of 10%. After two years, the flat's value would be:
1.1 lakh * (1 + 0.1)^2 = 1.1 lakh * 1.21 = ₹1.331 lakh
Prem purchased a plot for ₹1.1 lakh and its price increased at an annual rate of 5%. After two years, the plot's value would be:
1.1 lakh * (1 + 0.05)^2 = 1.1 lakh * 1.1025 = ₹1.213 lakh
After exchanging their properties, the difference in value is:
₹1.331 lakh (flat) - ₹1.213 lakh (plot) = ₹0.118 lakh
Since Ram's flat had a higher value than Prem's plot, Prem paid Ram the difference, which was ₹0.118 lakh or ₹11,800.
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Convert 3.9m^2 into cm^2
I will leave good review!
Answer:
Step-by-step explanation:
To convert square meters to square centimeters, we need to multiply by the conversion factor (100 cm / 1 m)^2.
So,
3.9 m² = 3.9 × (100 cm / 1 m)²
3.9 m² = 3.9 × 10,000 cm²
3.9 m² = 39,000 cm²
Therefore, 3.9 square meters is equal to 39,000 square centimeters.
Supplier X offers a mechanic a part at 35% off the retail price of $68.20. Supplier Y offers him the same part at 20% over the wholesale cost of $37.50. Which is the better deal, and by how much?A. Supplier Y offers the better deal by $_____B. Supplier X offers the better deal by $_____
Given:
There are given two suppliers X and Y.
Where,
X offers a mechanic a part of 35% off the retail price of $68.20 and Y offers at 20% over the wholesale cost of $37.50.
Explanation:
To find the best offers, we need to find their percentages one by one.
So,
First, find the offer amount from supplier X.
So,
\(X=68.20-68.20\times35\%\)Then,
\(\begin{gathered} X=68.20\times35\operatorname{\%} \\ X=23.87 \\ X=23.87 \end{gathered}\)Now,
For the Y suppliers:
\(Y=37.50-37.50\times20\%\)Then,
\(\begin{gathered} Y=37.50\times20\operatorname{\%} \\ Y=7.5 \\ Y=7.5 \end{gathered}\)So,
The best deal for supplier Y is because they offer $23.87.
Final answer:
Hence, the correct option is B with $23.87
Hi can you please help me
The probability that student chosen at random is 16 years is 0.28.
How to find the probability of the student chosen?The table shows the distribution of student by age in a high school with 1500 students. Therefore, the probability that randomly chosen student is 16 years can be found as follows:
Therefore,
probability = number of favourable outcome to age / total number of possible outcome
Hence,
probability that student chosen at random is 16 years = 420 / 150
probability that student chosen at random is 16 years = 0.28
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can you help me with number nine it says find the slope of the line that passes through each pair of points
How to find slope?
Slope is represented as mIf two point are
(x_1,y1)(x2,y2)Slope is given by
\(\\ \sf\longmapsto Slope=m=\tan\Theta=\dfrac{y_2-y_1}{x_2-x_1}\)
Help me asap pleaseee
In conclusion the mean score is 73.5.
How to find?
To find the mean of the scores, we need to add up all the scores and divide by the total number of students.
To make this calculation easier, we can multiply each score by the corresponding number of students, add up these products, and then divide by the total number of students.
So, let's calculate:
(70 x 2) + (74 x 1) + (79 x 2) + (75 x 1) + (80 x 1) + (85 x 1) + (90 x 1) + (95 x 1) + (100 x 4) = 1029
The total number of students is:
2 + 1 + 2 + 1 + 1 + 1 + 1 + 1 + 4 = 14
So, the mean score is:
1029 / 14 = 73.5 (rounded to the nearest 10th)
Therefore, the mean score is 73.5.
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if x=4 what is y when y=-2x-4
(6x10^6) / (2x10^3) solve?
Answer:
3x^999000
Explantiotn
Define the relation O on Z as follows: ᵾm, n € z, m O n <----> ⱻk € z |(m – n) = 2k +1 Which one of the following statements about the relation O is true? a. The relation is reflexive, symmetric, and transitive. b. The relation is not reflexive, not symmetric, and transitive. c. The relation is not reflexive, symmetric, and not transitive. d. The relation is reflexive, not symmetric, and transitive.
The relation O is not reflexive, symmetric, and not transitive is one of the following statements that is true about the relation O. which is option (C).
Given, \(\forall m, n \in Z, m O n \longleftrightarrow \exists k \in Z \mid(m-n)=2 k+1\)
Let's verify for the following relations :
Reflexive relation:
\(\forall a\in Z, a O a \longrightarrow \exists k\in Z \mid (a-a)= 2k+1\)
\(0\neq 2k+1\) for all k \(\in\) Z
Since 2k+1 can never be zero for any k \(\in\) Z, hence we conclude that the relation O is not reflexive.
Symmetric relation:
Suppose a, b \(\in\) Zsuch that a O b i.e. (a-b)=2k+1, where k\(\in\) Z.
Now, we need to check whether b O a is true or not i.e. (b-a)=2j+1 for some j\(\in\) Z
We have,
\((a-b) = 2k+1 \longrightarrow (b-a) = -2k-1 = 2(-k) - 1\)
Let j=-k-1, then we have j\(\in\) Z and 2j+1 = -2k-1
Hence, (b-a) = 2j+1, and we conclude that the relation O is symmetric.
Transitive relation:
Suppose a, b, c\(\in\) Z such that a O b and b O c.
Now, we need to check whether a O c is true or not.
We have,
(a-b)=2k_1+1 and (b-c)=2k_2+1 for some k_1,k_2\(\in\) Z
(a-b)+(b-c) = 2k_1+1 + 2k_2+1
a-c = 2k_1+2k_2+2
Let j=k_1+k_2+1, then we have j\(\in\) Z and a-c=2j
Hence, (a-c) is even and we conclude that the relation O is not transitive.
Therefore, the relation O is not reflexive, symmetric, and not transitive. Hence, option (C) is the correct answer.
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Can I get help with these three
Answer:
b is the answer
Step-by-step explanation:
1km= 1000m
1hr =60sec
plz help me i need help
Answer:
it's the last one it always helps me the way my teacher told me the short hand is the hour and the long one is the minutes. if you write the words down and draw a line under them it tells you which hand is which.
Alyssa is 1.65 meters tall. At 11 a.m., she measures the length of a tree's shadow to be 27.75 meters. She stands 23.5 meters away from the tree, so that the tip of her shadow meets the tip of the tree's shadow. Find the height of the tree to the nearest hundredth of a meter.
Using the concept of similar triangles, the height of the tree is approximately 2.10 meters, given Alyssa's height of 1.65 meters and the measurements of their shadows.
To find the height of the tree, we can use the concept of similar triangles. The ratio of the length of Alyssa's shadow to her height should be the same as the ratio of the length of the tree's shadow to its height.
Let's denote the height of the tree as 'h'. According to the given information, Alyssa's height is 1.65 meters, and the length of her shadow is 27.75 meters. The distance between Alyssa and the tree is 23.5 meters.
Using the similarity of triangles, we can set up the following proportion:
h/1.65 = (h + 27.75)/(23.5)
Cross-multiplying the proportion, we get:
23.5h = 1.65(h + 27.75)
Expanding the equation, we have:
23.5h = 1.65h + 45.74
Combining like terms, we find:
21.85h = 45.74
Dividing both sides by 21.85, we get:
h = 2.095 (rounded to the nearest hundredth)
Therefore, the height of the tree is approximately 2.10 meters.
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On the math exam,5 tasks were given. 25% of students solved at least two tasks. Prove that there was at least one task that no more than 12 students solved if 32 students wrote that test
Given that 25% of students solved at least two tasks and there were 32 students who wrote the test, we can prove that there was at least one task that no more than 12 students solved.
There was at least one task that no more than 12 students solved, we can use a proof by contradiction.
Assume that all five tasks were solved by more than 12 students. This means that for each task, there were at least 13 students who solved it. Since there are five tasks in total, this implies that there were at least 5 * 13 = 65 students who solved the tasks.
However, we are given that only 25% of students solved at least two tasks. If we let the number of students who solved at least two tasks be S, then we can write the equation:
S = 0.25 * 32
Simplifying, we find that S = 8.
Now, let's consider the remaining students who did not solve at least two tasks. The maximum number of students who did not solve at least two tasks is 32 - S = 32 - 8 = 24.
If all five tasks were solved by more than 12 students, then the total number of students who solved the tasks would be at least 65. However, the maximum number of students who could have solved the tasks is 8 (those who solved at least two tasks) + 24 (those who did not solve at least two tasks) = 32.
This contradiction shows that our initial assumption is false. Therefore, there must be at least one task that no more than 12 students solved.
Hence, we have proven that there was at least one task that no more than 12 students solved if 32 students wrote the test.
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The optimal amount of x1, x2, P1, P2 and income are given by the
following:
x1= 21/ 7p1 x2= 51 / 7p2
The original prices are: P1=10 P2=5 The original income is: I
=4189 The new price of P1 is the foll
The total change in the consumed quantity of x₁ as per given price and income is equal to 213.
x₁ = (21/7)P₁
x₂ = (51/7)P₂
P₁ = 10
P₂ = 5
P₁' = 81
To calculate the total change in the quantity consumed of x₁ when the price of P₁ changes from P₁ to P₁',
The difference between the quantities consumed at the original price and the new price.
Let's calculate the quantity consumed at the original price,
x₁ orig
= (21/7)P₁
= (21/7) × 10
= 30
x₂ orig
= (51/7)P₂
= (51/7) × 5
= 36.4286 (approximated to 4 decimal places)
Now, let's calculate the quantity consumed at the new price,
x₁ new
= (21/7)P1'
= (21/7) × 81
= 243
x₂ new
= (51/7)P2
= (51/7) × 5
= 36.4286
The total change in the quantity consumed of x₁ can be calculated as the difference between the new quantity and the original quantity,
Change in x₁
= x₁ new - x₁ original
= 243 - 30
= 213
Therefore, the total change in the quantity consumed of x₁ is 213.
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The above question is incomplete, the complete question is:
The optimal amount of x1, x2, P1, P2 and income are given by the following:
x1= 21/ 7p1 x2= 51 / 7p2
The original prices are: P1=10 P2=5 The original income is: I =4189 The new price of P1 is the following: P1'=81 Assume that the price of x1 has changed from P1 to P1'. What is the total change in the quantity consumed of x1?
Please answer step by step
Jacob is a plumber, and his coworker Hector is an electrician. Jacob charges customers a fee
of $60 just to come to their houses and then $1 per minute that he is there. Hector also
charges a fee of $50 for a home visit, plus an additional $2 per minute. Last week the
coworkers went to a job site together, spent the same amount of time working, and earned
the same amount. How much time did each one spend working?
Write a system of equations, graph them, and type the solution.
Answer:50 dollars an hour
Step-by-step explanation:
50x4/2
The graph of the parent function y = x3rd power is horizontally stretched by a factor of 1/5 and reflected over the y-axis. What is the
equation of the transformed function?
('
O y=(5x)3
Oy=(-5x)3
Oy=(1/5x)3
Oy=(-1/5x)3
Step-by-step explanation:
The graph of y = √x is reflected in the y-axis, is horizontally stretched by a factor of 2, shifted 3 units up and 1 unit left. What is the equation of the transformed graph?
Original: y = √(x)
Reflected in the y-axis: y = √(-x)
Horizontally stretched by a factor of 2: y = √(-x/2)
Shifted 3 units up: y = 3 + √(-x/2)
And 1 unit left: y = 3 + √(-(x+1)/2)
The equation of the transformed function is y = (-5x)³.
What is Translation?A translation moves a shape up, down, or from side to side, but it has no effect on its appearance. A transformation is an example of translation. A transformation is a method of modifying a shape's size or position.
we have, Function
y = x³
Scale factor = 1/5
Now, stretch the function horizontally by factor 1/5 then
y = (5x)³
Now, reflection of graph about y axis result change x to -x.
y = (-5x)³
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Prove that the maximum number of edges in a bipartite subgraph of the Petersen graph is ≤13. (b) Find a bipartite subgraph of the Petersen graph with 12 edges.
(a) Maximum edges in bipartite subgraph of Petersen graph ≤ 13.
(b) Example bipartite subgraph of Petersen graph with 12 edges.
(a) To prove that the maximum number of edges in a bipartite subgraph of the Petersen graph is ≤13, we can use the fact that the Petersen graph has 10 vertices and 15 edges.
Assume that we have a bipartite subgraph of the Petersen graph. Since it is bipartite, we can divide the 10 vertices into two sets, A and B, such that all edges in the subgraph are between vertices from set A and set B.
Now, let's consider the maximum number of edges that can exist between the two sets, A and B. The maximum number of edges will occur when all vertices from set A are connected to all vertices from set B.
In the Petersen graph, each vertex is connected to exactly three other vertices. Therefore, in the bipartite subgraph, each vertex in set A can have at most three edges connecting it to vertices in set B. Since set A has 5 vertices, the maximum number of edges from set A to set B is 5 * 3 = 15.
Similarly, each vertex in set B can have at most three edges connecting it to vertices in set A. Since set B also has 5 vertices, the maximum number of edges from set B to set A is also 5 * 3 = 15.
However, each edge is counted twice (once from set A to set B and once from set B to set A), so we need to divide the total count by 2. Therefore, the maximum number of edges in the bipartite subgraph is 15 / 2 = 7.5, which is less than or equal to 13.
Hence, the maximum number of edges in a bipartite subgraph of the Petersen graph is ≤13.
(b) To find a bipartite subgraph of the Petersen graph with 12 edges, we can divide the 10 vertices into two sets, A and B, such that each vertex in set A is connected to exactly two vertices in set B.
One possible bipartite subgraph with 12 edges can be formed by choosing the following sets:
- Set A: {1, 2, 3, 4, 5}
- Set B: {6, 7, 8, 9, 10}
In this subgraph, each vertex in set A is connected to exactly two vertices in set B, resulting in a total of 10 edges. Additionally, we can choose two more edges from the remaining edges of the Petersen graph to make a total of 12 edges.
Note that there may be other valid bipartite subgraphs with 12 edges, but this is one example.
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Brenda had 3/4 of a pizza. Her sister ate 1/2 of her pizza. How
much pizza did Brenda's sister eat?
her sister are two slices of pizza,
you multiply 1/2 to make it equivalent to 3/4 so once you multiply it should turn out to be 2/4 which means her sister ate 2 slices,lmk if 2 was an option.
A school has 109 students signed up for a science workshop. The school will buy every student attending the workshop a pencil, a folder, and an eraser. A package of 12 erasers is $0.75. Only whole packages of erasers can be bought. Folders are $0.10 each. A package of 8 pencils is $0.50. Only whole packages of pencils can be bought. How much will the school spend?
Answer:
The amount is $25.4
Step-by-step explanation:
There are 109 students to attend the science workshop.
Number of erasers needed is 109, but whole packages of erases can be bought which consist 12 erasers. The total packages of erasers needed would be 10.
The cost of 10 packages of erasers = $0.75 x 10
= $7.5
The cost of 109 folders = 109 x $0.10
= $10.9
Number of pencils needed is 109, but whole packages of pencils can be bought which consist 8 pencils. The total packages of pencils needed would be 14.
The cost of 14 packages of pencils = $0.50 x 14
= $7.0
Total cost = $7.5 + $10.9 + $7.0
= $25.4
The amount that would be spent by the school is $25.4
Answer:
25.4
Step-by-step explanation:
Solve for w-39=4w+7(w-3)Simplify your answer as much as possible
Given the equation:
-39 = 4w + 7(w-3)
Let's solve the equation for w.
To solve take the following steps.
• Step 1.
Apply distributive property
\(\begin{gathered} -39=4w+7(w)+7(-3) \\ \\ -39=4w+7w-21 \end{gathered}\)• Step 2.
Combine like terms
\(-39=11w-21\)• Step 3.
Add 21 to both sides
\(\begin{gathered} -39+21=11w-21+21 \\ \\ -18=11w \end{gathered}\)Step 4.
Divide both sides by 11
\(\begin{gathered} \frac{-18}{11}=\frac{11w}{11} \\ \\ -1.63=w \\ \\ w=-1.63 \end{gathered}\)ANSWER:
w = -1.63