a farmer hires 110 workers to harvest apples from his trees .it's takes the 12 days to harvest the farmers entire crop .how long will it take 440farmes to harvest the crop​

Answer:

"w" (and any subsequent words) was ignored because we limit queries to 32 words.

w = 0.33 so, w lies before A, B, and C.

Option A is the correct answer.

It is the representation of numbers in real order.

The difference between the consecutive numbers in a number line is always positive.

We have,

Average weight.

w = Sum of all the weight / 3

w = (0.5 + 0.3 + 0.2) / 3

w = 1/3

w = 0.33

Now,

A = 3, B = 6, and C = 7 on the number line.

0.33 lies before A, B, C

Thus,

w lies before A.

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The equation of logarithm are solved and

a) A = 2 + 3 log x + 4 log b

b) B = ( 36 + x + y ) ( log 6 )

c) C = ( 1/2 )x log 5

d) D = ln ( x⁴ / y² )

Given data ,

Let the logarithmic equation be represented as A

Now , the value of A is

a)

A = 2 log 10 + 3 log x + 4 log b

The base of the logarithm is 10 , so

A = 2 + 3 log x + 4 log b

b)

B = log 6³⁶ + log 6ˣ - log 6^ ( y )

From the properties of logarithm , we get

log A + log B = log AB

log A − log B = log A/B

log Aⁿ = n log A

B = 36 log 6 + x log 6 + y log 6

On taking the common term , we get

B = ( 36 + x + y ) ( log 6 )

c)

C = ( 1/2 )log 5ˣ

From the properties of logarithm , we get

C = ( 1/2 )x log 5

d)

D = 4 ln x - 2 ln y

From the properties of logarithm , we get

D = ln x⁴ - ln y²

On further simplification , we get

D = ln ( x⁴ / y² )

Hence , the logarithmic equations are solved

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The asymptotes of the graph of \(f(x) = \frac{5}{x - 1}\) are as follows:

In this problem, the function is:

\(f(x) = \frac{5}{x - 1}\)

For the vertical asymptote, we have that:

\(x - 1 = 0 \rightarrow x = 1\).

For the horizontal asymptote, we have that:

\(y = \lim_{x \rightarrow \infty} f(x) = \frac{5}{\infty - 1} = 0\).

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Answer:

12 meters = 472.441 inches

~Hope this helps~

Answer:

  22

Step-by-step explanation:

The segment addition theorem tells us the whole is the sum of the parts. We can use this to write an equation relating the expressions for segment length.

  OQ = OP +PQ . . . . . segment addition theorem

  4x +2 = (3x -3) +(4x -10) . . . . substitute given expressions

  15 = 3x . . . . . . add 13 -4x to both sides

  5 = x . . . . . . . divide by 3

  OQ = 4x +2 = 4(5) +2 = 22

The length of OQ is 22 units.

Answer:

A=pq2 is the answer i think

Answer:

okay so the circumference is 40.82m

\(circumference = 2\pi \: \times r \\ = 2 \times 3.14 \times 6.5 \\ = 40.82m\)

the diameter will be divided by 2 to give 6.5

Answer: I put 50,000 ft^3

Step-by-step explanation: You have to multiply 50, 80, 250 then divide by 20 because you’re looking for the floors only and not the roof and floor

Answer:

Step-by-step explanation:

Answer:

\((i) \quad\;\;\; \left(3^0 + 4^{-1}\right) \times 2^2=5\)

\((ii) \quad \;\;\left(2^{-1} \times 4^{-1}\right) \div 2^{-2}=\dfrac{1}{2}\)

\((iii) \quad \left(\dfrac{1}{2}\right)^{-2}+\left(\dfrac{1}{3}\right)^{-2}+\left(\dfrac{1}{4}\right)^{-2}=29\)

\((iv) \quad \;\: \left(3^{-1}+4^{-1}+5^{-1}\right)^0=1\)

\((v) \quad \;\;\left\{\left(\dfrac{-2}{3}\right)^{-2}\right \}^2=\dfrac{81}{16}\)

Step-by-step explanation:

To evaluate the given expressions, we can use the following exponent rules:

\(\boxed{\begin{minipage}{6cm}\underline{Exponent Rules}\\\\$a^0=1$ \qquad \qquad \qquad \qquad $1^n=1$\\\\\\$a^b \times a^c=a^{b+c}$ \qquad \;\;$a^b \div a^c=a^{b-c}$\\\\\\$\left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}$ \qquad \qquad $\left(\dfrac{a}{b}\right)^{-c}=\left(\dfrac{b}{a}\right)^{c}$\\\\\\$a^{-n}=\dfrac{1}{a^n}$\qquad \qquad \qquad$\dfrac{1}{a^{-n}}=a^n$\\\\\\$(a^b)^c=a^{bc}$\\\end{minipage}}\)

   \(\left(3^0 + 4^{-1}\right) \times 2^2\)

\(=\left(1 + (2^2)^{-1}\right) \times 2^2\)

\(=\left(1 + 2^{-2}\right) \times 2^2\)

\(=2^2 + 2^2\times 2^{-2}\)

\(=2^2 + 2^{2-2}\)

\(=2^2 + 2^{0}\)

\(=4+1\)

\(=5\)

   \(\left(2^{-1} \times 4^{-1}\right) \div 2^{-2}\)

\(=\left(2^{-1} \times (2^2)^{-1}\right) \div 2^{-2}\)

\(= \left(2^{-1} \times 2^{-2}\right) \div 2^{-2}\)

\(=\left(2^{-1-2}\right) \div 2^{-2}\)

\(=2^{-3} \div 2^{-2}\)

\(=2^{-3-(-2)}\)

\(=2^{-3+2}\)

\(=2^{-1}\)

\(=\dfrac{1}{2^1}\)

\(=\dfrac{1}{2}\)

  \(\left(\dfrac{1}{2}\right)^{-2}+\left(\dfrac{1}{3}\right)^{-2}+\left(\dfrac{1}{4}\right)^{-2}\)

\(=\dfrac{1^{-2}}{2^{-2}}+\dfrac{1^{-2}}{3^{-2}}+\dfrac{1^{-2}}{4^{-2}}\)

\(=\dfrac{1}{2^{-2}}+\dfrac{1}{3^{-2}}+\dfrac{1}{4^{-2}}\)

\(=2^2+3^2+4^2\)

\(=4+9+16\)

\(=13+16\)

\(=29\)

  \(\left(3^{-1}+4^{-1}+5^{-1}\right)^0\)

\(=1\)

   \(\left\{\left(\dfrac{-2}{3}\right)^{-2}\right \}^2\)

\(=\left(\dfrac{-2}{3}\right)^{-2\times 2}\)

\(=\left(\dfrac{-2}{3}\right)^{-4}\)

\(=\left(\dfrac{3}{-2}\right)^{4}\)

\(=\dfrac{3^4}{(-2)^4}\)

\(=\dfrac{81}{16}\)

Answer:

y=2/3

Step-by-step explanation:

2y+4y=6-3y

⇔ 2y+4y+3y=6

⇔ 9y=6

⇔ y=6/9=2/3

The answer is:

y = 2/3

Work/explanation:

For now, I focus on the left side and combine the like terms:

\(\bf{2y+4y=6-3y}\)

\(\bf{6y=6-3y}\)

Add 3y to each side

\(\bf{6y+3y=6}\)

Combine like terms

\(\bf{9y=6}\)

Divide each side by 9

\(\bf{y=\dfrac{6}{9}}\)

\(\bf{y=\dfrac{2}{3}}\)

Hence, the answer is 2/3.

Answer:

2202.75

Step-by-step explanation:

calculator

Answer: $35,000

so The answer is B

hope i helped

Step-by-step explanation:

35,000.

The wage after years experience is shown in this graph.  At x = 10, the output is approximately 35k

Hope this helps,

Jeron

:- )

(p.s., maybe brainliest if I really helped??  :))))    )

Answer:

xsqrt(2)

Step-by-step explanation:

sqrt(a) / sqrt(b) = sqrt(a/b)

sqrt(22x^6) / sqrt(11x^4)

sqrt(22x^6/11x^4)

sqrt(2x^2)

We know sqrt(ab) = sqrt(a) sqrt(b)

sqrt(x^2) sqrt(2)

xsqrt(2)

Answer:

144/169

Step-by-step explanation:

There are 52 cards, 4 are aces, so the probability of not getting ace is 48/52, so we square it, or multiply it by itself to get 144/169

Answer:

19

Step-by-step explanation:

38 - 50% = 19

Answer:

10.25, 15.25,30.5

x + (x+5) + 2 (x+5)=56

4× +15=56

x=10.25

Thus, probability that the one drawn penny is from 1977 dated pennies is 6/25.

The probability about an occurrence in an experiment is the likelihood that the event will occur. Any event's probability is a number between (including all) "0" and "1".

If an event's probability is represented by P(E), then we get

Given data:

Total pennies = 50

number of 1977 dated pennies = 12

probability = favourable outcome / total outcome

probability(1977 dated pennies) = number of 1977 dated pennies/ Total pennies

probability(1977 dated pennies) = 12/50

Divide numerator and denominator by 2.

probability(1977 dated pennies) = 6/25

Thus, probability that the one drawn penny is from 1977 dated pennies is 6/25.

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Answer: Henrik grew 147 more potatoes than Derek

Step-by-step explanation:

Answer:

  3 times the second equation, plus the first

Step-by-step explanation:

You want a strategy for eliminating x-terms in the system of equations ...

You can eliminate x-terms by making their coefficients opposites. We observe that the coefficient of x in the first equation is -3 times the coefficient of x in the second equation.

Multiplying the second equation by 3 will make the x-coefficient -9, the opposite of that in the first equation. Doing that makes the system ...

Adding these two equations together will eliminate the x-terms:

  (9x -7y) +(-9x +15y) = (-3) +(27)

  8y = 24 . . . . . . . simplify; x-terms are gone

You can eliminate x-terms by multiplying the second equation by 3, then adding the two equations together.

Answer:

This is decay. The exponent has a negative sign. The reciprocal of 2 is 0.5. So N(t) can be rewritten as 0.5^(t/8). The base is fraction less than 1, which is decay.

Step-by-step explanation:

sample response on edgen 2022

Answer:

Simple Linear Regression Correlation

Step-by-step explanation:

When it snows normally the schools continue .But constant snowing affects the schools continuity. As more and more snow falls more schools are closed.

There may be a situation where all the schools are closed at a certain temperature.

So it is a simple linear regression correlation because in it there are two variables and one variable is dependent on the other. In this example the schools are dependent on the average snowfall.

If there's a snow blizzard or extreme weather all the schools are definitely closed .

It can be represented by a graph.

Answer:

  (c)  5.00×10^-5 kg

Step-by-step explanation:

The mass and energy are related by Einstein's formula E = mc².

__

Solving for mass in kg, we find it to be ...

  m = E/c² . . . . . . . . where E is in joules, and c is in meters/second

  m = (4.50×10^12 J)/(3×10^8 m/s)² = 5.00×10^-5 kg

The lost mass was about 5.00×10^-5 kg.

Answer:

5.00×10^−5 kg

Step-by-step explanation:

I took the test and it was correct! PLEASE LIKE  and have a wonderful day!

The time period of the animals life cycles are,

⇒ Beluga whole = 35 years

⇒ Bengal tiger = 10 years

⇒ Elephant = 20 years

⇒ Giraffe = 25 years

⇒ Orangutan = 40 years

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

There are some animals and there ages.

Now,

Since, There are some animals and there ages are given.

Hence, The correct ages of the animals are,

⇒ Beluga whole = 35 years

⇒ Bengal tiger = 10 years

⇒ Elephant = 20 years

⇒ Giraffe = 25 years

⇒ Orangutan = 40 years

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Answer:

20x+32

Step-by-step explanation:

4(5x+8)

4*5x + 4*8

20x+32

Answer:

BOYS = 30.

GIRLS = 12.

Step-by-step explanation:

Boys: B

Girls: G

B = (2/5)G

B + G = 42.

(2/5)G + G = 42

2G + 5G = 210

7G = 210

G = 210/7

G = 30.

B = (2/5)G

B = (2/5)(30)

B = 60/5

B = 12.

Answer:

\(\Huge \boxed{\bold{\text{12 Boys}}}\)

\(\Huge \boxed{\bold{\text{30 Girls}}}\)

Step-by-step explanation:

Let the number of girls be \(g\) and the number of boys be \(b\).

According to the problem: \(b = \frac{2}{5} \times g\)

We also know that the total number of students is 42, so \(b + g = 42\).

Now, we have two equations with two variables:

We can solve these equations to find the values of \(b\) and \(g\).

Step 1: Solve for \(\bold{b}\) in terms of \(\bold{g}\)

From the first equation, we have\(b = \frac{2}{5} \times g\)

Step 2: Substitute the expression for \(\bold{b}\) into the second equation

Replace \(b\) in the second equation with the expression we found in step 1.

\(\frac{2}{5} \times g + g = 42\)

Step 3: Solve for \(\bold{g}\)

Now, we have an equation with only one variable, \(g\):

\(\frac{2}{5} \times g + g = 42\)

To solve for \(g\), first find a common denominator for the fractions:

\(\frac{2}{5} \times g + \frac{5}{5} \times g = 42\)

Combine the fractions:

\(\frac{7}{5} \times g = 42\)

Now, multiply both sides of the equation by \(\frac{5}{7}\) to isolate \(g\):

Step 4: Find the value of \(\bold{b}\)

Now that we have the value of \(g\), we can find the value of \(b\) using the first equation:

So, there are 12 boys and 30 girls in the class.

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Answer:

 $18,760.76

Step-by-step explanation:

16000 * 0.0545 = 872

16000 + 872 = 16872

16872 * 0.0545 = 919.52

16872 + 919.52 = 17791.52

17791.52 * 0.0545 = 969.64

17791.52 + 969.64 = 18760.76

hope this helps. if you need more help lmk. Happy Holidays!

Answer:$18,929.34

Step-by-step explanation: This is the correct answer.

Answer:

Step-by-step explanation: