Answer:
goat= 45 birr
sheep = 50 birr
Answer:
Goats =45
sheep =50
Step-by-step explanation:
3 sheep ÷375=7
looking to open the Naeem:
looking to open the Naeem
looking to open the Naeem:
how ❓️ ❓️,
The movies has 4 bathrooms in 16 theaters what is the bathroom to theaters ratio?
Answer:
1 bathroom to 4 theaters
Step-by-step explanation:
Find the length of the third side of the right triangle. Give an exact answer and anapproximation to three decimal places if needed.(Simplify your answer. Type an integer or a decimal.)
By pythagorus theorem we know that in a right triangle
\(\text{hypotenuse}^2=perpendicular^2+base^2\)Now in our question we have :-
Hypotenuse=17 and perpendicular =15
So
\(\begin{gathered} 17^2=15^2+b^2 \\ b^2=289-225 \\ b^2=64 \\ b=\sqrt[]{64} \\ b=8 \end{gathered}\)So the third side of the triangle would be 8 units
How many oranges does Heidi need to make one large orange
juice? Show your work.
Answer:
Heidi needs to make 9 oranges to make one large orange juice, give me brainliest answer:)
Find the LCM of A= 3^2 x 5^4 x 7 and B= 3^4 x 5^3 x 7 x11
The LCM of A = 3² × 5⁴ × 7 and B = 3⁴ × 5³ × 7 × 11 is 3898125 using Prime factorization.
Given are two numbers which are showed in the prime factorized form.
A = 3² × 5⁴ × 7
B = 3⁴ × 5³ × 7 × 11
Prime factorization is the factorization of a number in terms of prime numbers.
In order to find the LCM of these two numbers, we have to first match the common primes and write down vertically when possible and then bring down the primes in each column.
A = 3² × 5³ × 5 × 7
B = 3² × 3² × 5³ × 7 × 11
Bring down the primes in each column.
LCM = 3² × 3² × 5³ × 5 × 7 × 11
= 3898125
Hence the LCM is 3898125.
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What is the range of this function?
Raj’s bathtub is clogged and is draining at a rate of 1.5 gallons of water per minute. The table shows that the amount of water remaining in the bathtub, y, is a function of the time in minutes, x, that it has been draining.
A 2-column table with 4 rows. The first column is labeled x with entries 0, 0.5, 1, 1.5. The second column is labeled y with entries 40, 39.25, 38.5, 37.75.
If the Raj’s bathtub is draining at rate of 1.5 gallons of water per-minute, then the range will be (c) all real numbers such that 0 ≤ y ≤ 40.
The "Range" of function is defined as the set of all possible "output-values'.
The amount of water remaining in the bathtub is decreasing as it drains, so the range of the function is bounded below by 0 (because we cannot have negative water in the bathtub) and above by 40 (the initial amount of water in the bathtub).
Looking at the given values of y, we can see that the value of "y" lies between 0 and 40.
Therefore, the correct option is (c).
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The given question is incomplete, the complete question is
Raj’s bathtub is clogged and is draining at a rate of 1.5 gallons of water per minute. The table shows that the amount of water remaining in the bathtub, y, is a function of the time in minutes, x, that it has been draining.
x y
0 40
0.5 39.25
1 38.5
1.5 37.75
What is the range of this function?
(a) all real numbers such that y ≤ 40
(b) all real numbers such that y ≥ 0
(c) all real numbers such that 0 ≤ y ≤ 40
(d) all real numbers such that 37.75 ≤ y ≤ 40.
Question 5 of 5
Evaluate -(5-4)(52)
O A. -25
O B. - 2
O C.
O D. 25
Answer:
-52
Step-by-step explanation:
5 - 4 = 1Plug 1 in: -(1)(52)Simplify: -1 × 52-1 × 52 = -52I hope this helps!
To investigate whether there is a significant difference between two regions of a state in the percent of voters who intend to vote for the incumbent governor in the next election, a polling agency interviewed 300 randomly selected voters from the north of the state and 400 randomly selected voters from the south of the state. Of those interviewed, 200 from the north and 325 from the south indicated they intended to vote for the incumbent governor in the next election. Which of the following is the most appropriate method for analyzing the results?
A one-sample z-test for a sample proportion
A one-sample z-test for a population proportion
A two-sample z-test for a sample proportion
A two-sample z-test for a difference in sample proportions
A two-sample z-test for a difference in population proportions
A two-sample z-test for a difference in population proportions is the appropriate method for analyzing the results.
Z-test is a statistical test often utilizes to find the difference in mean. It is coupled with variances and sample size to find the appropriate results. It is a hypothetical test where normal distribution is seen.
z-test holds numerous advantages such as it indicates difference in small size groups making it more usable. Moreover, it is also reliable in non-normal distribution of data and is efficient while taking multiple groups in a single analysis. The question has two different popular proportion and hence the two sample z-test will suitable to compare the means.
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Al lanzar un dado determinar la probabilidad de que salga un número primo o un número mayor que 3
The probability of a prime number or a number greater than 3 coming up is given as follows:
5/6.
How to calculate a probability?The parameters that are needed to calculate a probability are listed as follows:
Number of desired outcomes in the context of a problem or experiment.Number of total outcomes in the context of a problem or experiment.Then the probability is calculated as the division of the number of desired outcomes by the number of total outcomes.
When a dice is thrown, there are six possible outcomes, ranging from 1 to 6, and the desired outcomes are given as follows:
Prime numbers: 2, 3, 5.Non-prime greater than 3: 4 and 6.Hence the probability is given as follows:
5/6.
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Choose the most reasonable Celsius temperature for a snowy day.
17°C 26°C -6°C
Choose the most reasonable Celsius temperature for a snowy day.
O A. 26°C
OB. 17°C
C. -6°C
The most reasonable temperature for a snowy day is given as follows:
C. -6°C
How to obtain the most reasonable temperature?Considering that it snows, the temperature is either negative or very low positive, as snow only happens on temperatures close to freezing (like 2º C) or negative.
17ºC and 26ºC are far from cold enough to generate snow, hence the most reasonable temperature for a snowy day is given as follows:
C. -6°C
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What is the area of the figure? In Units
Answer:
Area = 40
Perimeter = 26
Step-by-step explanation:
length = 8
width = 5
Area = 8 x 5 = 40
Perimeter = 2(8 + 5) = 26
how much is root of five by root of five
Answer
5^5=25
Step-by-step explanation
Subtract the sum of a^2 − 2ab + b^2 and 2a^2 + 2ab + b^2 from the sum of a^2 − b^2 and a^2 + ab + 3b^2
Answer:
-a^2 + ab
Step-by-step explanation:
(a^2 - 2ab +b^2) + (2a^2 + 2ab + b2) = 3a^2 + 2b^2
(a^2 - b^2) + (a^2 + ab + 3b^2) = 2a^2 + 2b^2 + ab
subtract the first part from the second part:
(2a^2 + 2b^2 + ab) - (3a^2 + 2b^2) = -a^2 + ab
I will give brainliest out please help me answer the unsolved ones
For the given triangles:
(1) x = 5.4
(2) x = √23
(3) θ = 25.84 degree
(4) x = 9.5
(5) n = 41
(1) In the given triangle,
One angle = 16 degree
Perpendicular = x
Hypotenuse = 20
Since we know that
Sinθ = opposite side of θ/hypotenuse
Therefore,
⇒ sin 16 = x/20
⇒ 0.27 = x/20
⇒ x = 5.4
(2) In the given triangle,
Hypotenuse = 12 km
Base = 11 km
perpendicular = x
We know that the Pythagoras theorem for a right angled triangle:
⇒ (Hypotenuse)²= (Perpendicular)² + (Base)²
⇒ (12)²= (x)² + (11)²
⇒ 144 = (x)² + 121
⇒ x² = 23
Taking square root both sides we get,
Hence,
⇒ x = √23
(3) In the given,
Base = 20
Perpendicular = 42
We know that the Pythagoras theorem for a right angled triangle:
⇒ (Hypotenuse)²= (Perpendicular)² + (Base)²
⇒ (Hypotenuse)² = (42)² + (20)²
⇒ (Hypotenuse)² = 2164
Taking square root both sides,
⇒ (Hypotenuse) = 46.51
⇒ cosθ = Adjacent/hypotenuse
= 42/46.51
= 0.90
Taking inverse of cosθ,
⇒ θ = 25.84 degree
(4) In the given triangle,
One angle = 30 degree
Base = x
Hypotenuse = 11
Since we know that
cosθ = Adjacent/hypotenuse
Therefore,
⇒ cos 30 = x/11
⇒ √3/2 = x/11
⇒ x = 9.5
(4) In the given triangle,
Base = 40
Perpendicular = 9
Hypotenuse = n
We know that the Pythagoras theorem for a right angled triangle:
⇒ (Hypotenuse)²= (Perpendicular)² + (Base)²
⇒ n² = 9² + 40²
⇒ n² = 81 + 1600
⇒ n² = 1681
⇒ n = 41
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(G1) The distance from Flagstaff Arizona to
Tucson Arizona is 260 miles. Express this
distance in meters.
A. 418,418 meters
B. 419,000 meters
C. 126,200 meters
D. 260,000 meters
Answer:
A. 418, 418
Step-by-step explanation:
The formula to convert miles to meters is the following:
1 = 1,609.34
so for every 1 mile, you have 1,609.34 meters
so you take your distance in miles and multiply it by 1,609.34
d= 260 x 1,609.34
d = 418, 428.4
HURRY!!!!!!!!!!!!!!!
The table shows the proportional relationship between the number of tickets required per game at a carnival. Games 4 7 10 Tickets 20 35 50 Determine the constant of proportionality.
Correct answer will get brainiest
Answer:
Therefore, the constant of proportionality for the given proportional relationship is 5.
Step-by-step explanation:
To determine the constant of proportionality in the given proportional relationship, we can use the formula:
Constant of Proportionality = Tickets / Games
Let's plug in the values from the table:
For the first set of values (4 games and 20 tickets):
Constant of Proportionality = 20 / 4 = 5
For the second set of values (7 games and 35 tickets):
Constant of Proportionality = 35 / 7 = 5
For the third set of values (10 games and 50 tickets):
Constant of Proportionality = 50 / 10 = 5
In all three cases, the constant of proportionality is equal to 5.
Therefore, the constant of proportionality for the given proportional relationship is 5.
54 divided by u = 9.
Answer:
6 = u
Step-by-step explanation:
54 / u = 9
We have to isolate "u" all by itself;
54 = 9*u
54 / 9 = u
6 = u
Hope this helps!
Answer:
6
Step-by-step explanation:
We need to find of u value such that , 54 divided by u = 9. Converting it into equation ,
Equation :-
→ 54/u = 9
→ 1/u = 9 × 1/54
→ 1/u = 1/6
→ u = 6
Hence the required answer is 6.According to a Human Resources report, a worker in the industrial countries spends on average 419 minutes a day on the job. Suppose the standard deviation of time spent on the job is 30 minutes.
a. If the distribution of time spent on the job is approximately bell shaped, between what two times would 68% of the figures be?
enter the lower limit for the interval where 68% of the values would fall
to enter the upper limit for the interval where 68% of the values would fall
b. If the distribution of time spent on the job is approximately bell shaped, between what two times would 95% of the figures be?
enter the lower limit for the interval where 95% of the values would fall
to enter the upper limit for the interval where 95% of the values would fall
c. If the distribution of time spent on the job is approximately bell shaped, between what two times would 99.7% of the figures be?
enter the lower limit for the interval where 99.7% of the values would fall
to enter the upper limit for the interval where 99.7% of the values would fall
d. If the shape of the distribution of times is unknown, approximately what percentage of the times would be between 360 and 478 minutes?
At least enter percentages rounded to 1 decimal place
% (Round the intermediate values to 3 decimal places. Round your answer to 1 decimal place.)
e. Suppose a worker spent 400 minutes on the job. What would that worker’s z score be, and what would it tell the researcher?
z score = enter the z score rounded to 3 decimal places
(Round your answer to 3 decimal places.)
This worker is in the lower half of workers but within select the distance from the mean
standard deviation of the mean.
Step-by-step explanation:
Ah statistics
68-95-99.7
a. 68% is between -1 and 1 standard deviation, which is between 389 and 449 minutes
b. 95% is between -2 and 2 standard deviations, which is between 359 and 479 minutes
c. 99.7% is between -3 and 3 standard deviations, which is between 329 and 509 minutes
d. Use table A with a z-score of (360-419)/30 = -1.96666667
and with a z-score of (478-419)/30 = 1.96666667
NOTE THESE ARE NOT THE ANSWERS, but use the z-scores to find the percentage on table A
e. (400-419)/30 = -0.633333333 as his z-score
now find that value on table A
We are given the mean and the standard deviation. If the distribution is normal(bell-shaped), the Empirical Rule is used, otherwise, if the distribution is unknown, Chebyshev's Theorem is used.
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
Chebyshev Theorem
The Chebyshev Theorem can also be applied to non-normal distribution. It states that:
At least 75% of the measures are within 2 standard deviations of the mean.
At least 89% of the measures are within 3 standard deviations of the mean.
An in general terms, the percentage of measures within k standard deviations of the mean is given by \(100(1 - \frac{1}{k^{2}})\).
In this question:
Mean of 419, standard deviation of 30.
Question a:
Within 1 standard deviation of the mean, so:
419 - 30 = 389.
419 + 30 = 449.
Between 389 and 449 minutes.
Question b:
Within 2 standard deviations of the mean, so:
419 - 60 = 359
419 + 60 = 479
Between 359 and 479 minutes.
Question c:
Within 3 standard deviations of the mean, so:
419 - 90 = 329
419 + 90 = 509
Between 329 and 509 minutes.
Question d:
Have to find how many standard deviations it is from the mean:
(478 - 419)/30 = 1.97
(360 - 419)/30 = -1.97
Considering \(k = 1.97\)
\(100(1 - \frac{1}{1.97^{2}}) = 74.2\)
At least 74.2% of the times would be between 360 and 478 minutes.
Question e:
The z-score is:
\(Z = \frac{X - \mu}{\sigma}\)
In which X is the measure, \(\mu\) is the mean and \(\sigma\) is the standard deviation.
For this question, X = 400, \(\mu = 419, \sigma = 30\)
So
\(Z = \frac{X - \mu}{\sigma}\)
\(Z = \frac{400 - 419}{30}\)
\(Z = -0.633\)
This worker is in the lower half of workers but within 0.633 standard deviations of the mean.
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The height of a right triangular prism is 1 5/6 inches each side of the triangular base measures 10 inches and the height of the bases eight2 over 3 inches the triangular prism is place to top of cube whose side measures 10 inches so that one of the triangular prisms bases lies completely on one side of the cube what is the surface area of the solid formed
The surface area of the solid formed is approximately, 598.3 in².
What is the Surface Area of a Right Triangular Prism?Surface area of the solid is the area covered by the solid all round.
The given parameters are:
Height of the prism (L) = 1 5/6 = 1.83 in.Side of base (s1) = 10 in.Side of base (s2) = 10 in.Side of base (s3) = 8 2/3 = 8.67 in.base (b) = 10Height (h) = 8.67 in.a = 10 in.Surface area of the solid formed = 5(10×10) + (0.5×10×8.67) + 3(10×1.83) = 598.3 in²
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Which ex press ion shows the perimeter of the quadrilateral below?
A: 6x+4
B: 7x +11
C: -7x+11
D: -7x +12
option B. 7x+11 is the correct answer
Answer:
ur answer is c) -7x+12
Step-by-step explanation:
2x+3+x-1+3x+5+x+4=perimeter
2x+x+3x+x+3-1+5+4=perimeter
7x+11=perimeter
did u got what i had done message on this ans
What is the equation in point slope form of the line that is perpendicular to the given line and passes through the point(2,5)?
Answer:
Step-by-step explanation:
To find the equation of a line that is perpendicular to a given line and passes through a specific point, we need to follow a few steps:
Find the slope of the provided line.
The point-slope form of a line is given by: y - y1 = m(x - x1), where (x1, y1) represents the given point.
Substituting the values, the equation of the perpendicular line becomes:
y - 5 = (-1/m)(x - 2)
Simplifying the equation further, we can rewrite it in point-slope form:
y - 5 = (-1/m)x + (2/m)
Write 16+32 as a product of two factors using the GCT and 5e distributive property
9514 1404 393
Answer:
16·(1 +2)
Step-by-step explanation:
Both 16 and 32 are divisible by 16, so we can factor that out of the sum.
16 +32 = 16·1 +16·2 = 16·(1 +2)
An angle with an initial ray pointing in the 3-o'clock direction measures θ radians (where 0≤θ<2π). The circle's radius is 3 units long and the terminal point is located at (−2.69,−1.33)
a. The terminal point is how many radius lengths to the right of the circle's vertical diameter. H=____ radians
B.When we evaluate cos−1(h) using a calculator or computer, the value returned is
____ radians
c.Therefore, θ=
a) The terminal point is 0.896 radius length.
b) The value returned is -0.896.
We have,
The circle's radius is 3 units long and the terminal point is located at (−2.69,−1.33)
a. Since the circle's radius is 3 units long, we divide the x-coordinate by 3:
x-coordinate of terminal point: -2.69
Number of radius lengths to the right: -2.69 / 3 ≈ -0.896
However, since the angle is measured from the 3-o'clock direction, we consider it to be in the clockwise direction.
Thus, the number of radius lengths to the right is
Number of radius lengths to the right: -(-0.896) = 0.896
Therefore, the terminal point is 0.896 radius length.
b. Using Trigonometry
cos(h) = x-coordinate of terminal point / radius length
cos(h) = -2.69 / 3 ≈ -0.896
c. As, θ = h. From the given information, we have:
θ ≈ -0.896 radians
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A population of values has a normal distribution with �=189.7 and �=96.7. You intend to draw a random sample of size �=62.
Find the probability that a single randomly selected value is between 189.7 and 213.
P(189.7 < X < 213) =
Find the probability that a sample of size �=62 is randomly selected with a mean between 189.7 and 213.
P(189.7 < M < 213) =
Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
The probability that a sample of size n = 62 is randomly selected with a mean between 189.7 and 213 is approximately 0.9702.
To find the probability that a single randomly selected value is between 189.7 and 213, we can use the standard normal distribution.
Step 1: Calculate the z-scores for the given values using the formula:
z = (x - μ) / σ
For 189.7:
z1 = (189.7 - 189.7) / 96.7 = 0
For 213:
z2 = (213 - 189.7) / 96.7 ≈ 0.2417
Step 2: Utilize a standard typical conveyance table or number cruncher to find the probabilities comparing to the z-scores.
P(189.7 < X < 213) = P(0 < Z < 0.2417) ≈ 0.0939
Therefore, the probability that a single randomly selected value is between 189.7 and 213 is approximately 0.0939.
To find the probability that a sample of size n = 62 is randomly selected with a mean between 189.7 and 213, we use the central limit theorem. Under specific circumstances, the testing dispersion of the example mean methodologies a typical conveyance
Step 1: Calculate the standard error of the mean (σ_m) using the formula:
σ_m = σ / sqrt(n)
σ_m = 96.7 / sqrt(62) ≈ 12.2878
Step 2: Convert the given qualities to z-scores utilizing the equation:
z = (x - μ) / σ_m
For 189.7:
z1 = (189.7 - 189.7) / 12.2878 = 0
For 213:
z2 = (213 - 189.7) / 12.2878 ≈ 1.8967
Step 3: Utilize a standard typical conveyance table or mini-computer to find the probabilities relating to the z-scores.
P(189.7 < M < 213) = P(0 < Z < 1.8967) ≈ 0.9702
Therefore, the probability that a sample of size n = 62 is randomly selected with a mean between 189.7 and 213 is approximately 0.9702.
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The value of coins in the pockets of several students is recorded. What is the mean
mean of the values: 10, 20, 35, 35, 35, 40, 45, 45, 50, 60
Answer:
The mean would be 37.5.
Step-by-step explanation:
First, we add all the numbers in the data set together.
10 + 20 + 35 + 35 + 35 + 40 + 45 + 45 + 50 + 60 = 375
Next, we divide by the amount of numbers in the data set.
375 / 10 = 37.5.
Therefore, the mean (average) is 37.5.
To rent a stereo for a
party you pay a one-
time fee of $75 plus
$10 per day.
8. Write a paragraph proof.
Proof Given: In a plane, a is perpendicular to b, b id perpendicular to c, and c || d.
Prove: a || d
To prove that line segment a is parallel to line segment d, based on the given information, we can utilize the properties of perpendicular and parallel lines.
Given that a is perpendicular to b and b is perpendicular to c, we know that angles formed between a and b, as well as between b and c, are right angles. Let's denote these angles as ∠1 and ∠2, respectively.
Now, since c is parallel to d, we can conclude that the corresponding angles ∠2 and ∠3, formed between c and d, are congruent.Considering the fact that ∠2 is a right angle, it can be inferred that ∠3 is also a right angle.
By transitivity, if ∠1 is a right angle and ∠3 is a right angle, then ∠1 and ∠3 are congruent.Since corresponding angles are congruent, and ∠1 and ∠3 are congruent, we can deduce that line segment a is parallel to line segment d.
Thus, we have successfully proven that a is parallel to d based on the given information and the properties of perpendicular and parallel lines.
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5. For f(x) = 5x + 1, find 4). (1 pnt)
-19
1
-21
21
Answer:
f(x) = 5x – 1
to find the inverse equate f(x) to y
That will be
f(x) = y
>>>>
Interchange the terms >>>
x = 5y - 1
then make y the subject
then we have
5y = x + 1
then if you divide both sides by 5
y = x+1/5
therefore f^-1(x)= x + 1/5
hope this helps you
(Brainliest?)
Step-by-step explanation:
Can someone plz plz plz help will give u brainlest
Please help !! I don’t know what x is !
Answer:
x = √65
Step-by-step explanation:
You are given a right triangle with leg lengths 4 and 7, and you are asked for the length of the hypotenuse, x.
Pythagorean theoremThe Pythagorean theorem relates the lengths of the sides of a right triangle. It tells you the square of the hypotenuse (x²) is the sum of the squares of the other two sides.
x² = 4² +7² . . . . . . . . . Pythagorean relation
x² = 16 +49 = 65 . . . evaluate the expression
x = √65 . . . . . . . . . . take the square root
6 + 2 to the 3rd power times 3
DONE?