Answers
Answer:
the average speed of the car is 170 mph.
Explanation:
Given;
initial speed, u = 70 mph
time of motion, t₁ = 3 hours
final speed, v = 20 mph
time of motion, t₂ = 2 hours
The average speed of the car is calculated as;
\(v' = \frac{70(3) - 20(2)}{3-2} \\\\v' = 170 \ mph\)
Therefore, the average speed of the car is 170 mph.
Related Questions
Can any wan help pls
Answers
Answer:
b
Explanation:
because of bonds and the bowl is used for heating purpose
Answer:
I think b not sure but I hope its right and is that the nwea test??
You hold a 5 lb bag of sugar in your hand, you must push upwards on it with a force of 5 lb. Is this an example of Newton's Law?
Answers
Newton's laws of motion describe the behaviour of objects when they are at rest or in motion.
The three laws of motionAn object at rest will remain at rest, and an object in motion will remain in motion at a constant velocity, unless acted upon by an external force. The acceleration of an object is directly proportional to the force applied to it, and inversely proportional to its mass. For every action, there is an equal and opposite reaction.First law of motion in this scenarioThe 5 lbs bag of sugar is at rest in this situation, and you are exerting a 5 lbs upward force on it. The sugar bag will continue to be at rest unless an outside force acts upon it, in accordance with the first law of motion. It is being subjected to an external force that you are applying.
Second law of motion in this scenarioAccording to the second law of motion, theforce exerted on the bag of sugar will have a direct proportional effect on how fast it accelerates. The mass of the bag of sugar is 5 pounds, and the force you are exerting on it is 5 lbs. Because\(\textsf{$\frac{\textsf{5 lbs (force)}}{\textsf{ 5 lbs (mass)}}$ = 1 (unit of accleration)}\), the bag of sugar will accelerate by 1 (unit of acceleration).
Third law of motion in this scenarioThe third law of motion states that there is an equal and opposite reaction to every action. In this case, the sugar bag pushes down on your hand with a 5 lb force when you push up on it with a 1 lb force. The force you are providing to the bag of sugar will have an equal and opposite reaction here.
Therefore, this scenario illustrates all three of Newton's laws of motion
----------------------------------------------------------------------------------------------------------
Yes, this is an example of Newton's Third Law of Motion. Newton's Third Law of Motion states that for every action, there is an equal and opposite reaction. In this example, when you push upwards on the 5 lb bag of sugar with a force of 5 lb, the bag of sugar also pushes downwards on you with a force of 5 lb.In other words, the action is you pushing upwards on the bag of sugar and the reaction is the bag of sugar pushing downwards on you with the same amount of force. So, this is an example of Newton's Third Law of Motion.
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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Select the following that are true of cell walls in plants.
1. They give support and shape to the overall plant.
2. They contain very small holes.
3. They give the plant a deep green color.
4. They take the energy from the sun and turn it into carbon dioxide.
5. They measure the amount of water in a plant.
Answers
Answer:
1,3
Explanation:
that's all I know for sure i recommend looking for other answers to compare to :) hope this helps
A plane is traveling horizontally at a speed u = 40 m/s at a height h =
100m above ground when it drops a package, as shown in the figure.
How long it takes the dropped package to reach the ground and where?
Answers
Answer:
First get the time in the air from
h = gt2/2 ⇒
t = √(2h/g)
Plug in
h = 100 m
g = 9.8 m/s2
and get t in seconds. Then multiply t by the constant horizontal speed.
x = vt
Plug in
v = 40 m/s
t = ? (result from above)
and get x in meters.
(b)
Vertical speed:
v(t) = v0 + gt
Plug in
v0 = 0
g and t from above
and get v(t) in m/s.
(c) It is the same as the initial velocity when released, which is 40 m/s.
(d) The horizontal component is the same as the answer for part (c). The vertical component is the result for part (b), in the downward direction.
SP1. A railroad engine moves forward along a straight section of track for a distance of 70 m due west at a constant speed of 5 m/s . It then reverses its direction and travels 32 m due east at a constant speed of 4 m/s . The time required for this deceleration and reversal is very short due to the small speeds involved. a. What is the time required for the entire process? b. Sketch a graph of average speed versus time for this process . Show the deceleration and acceleration upon reversal as occurring over a very short time interval . c. Using negative values of velocity to represent reversed motion, sketch a graph of velocity versus time for the engine ( see fig. 2.15 ). d. Sketch a graph of acceleration versus time for the engine (see fig . 2.16).
Answers
The relationships between average speed (s), velocity (v), and acceleration can be shown shown graphically by plotting their values with time
a. The time required for the entire process is 22 seconds
The required graphs to question b, c, and d are attached
The reasons the above value for time and the attached graph are correct are given as follows:
The given parameters are;
The distance due west travelled by the train = 70 m
The speed in the western direction = 5 m/s
The distance due east the train then travelled = 32 m
The speed of the train while travelling east = 4 m/s
a. The time required for the entire process, t, is given as follows;
\(Time = \dfrac{Distance}{Velocity}\)
Therefore, the total time, t = (70 m/(5 m/s)) + (32 m/(4 m/s)) = 22 s
The time required for the entire process is 22 seconds
b. The table of values (obtained with MS Excel) are as follows;
Time: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22
Avg. Speed: 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 4.9, 4.875, 4.8, 4.78, 4.74, 4.7, 4.67, 4.64
Please find attached the required graph of average speed versus time
c. The table of values are as follows;
Time: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22
Velocity: 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, -4, -4, -4, -4, -4, -4, -4, -4
Please find attached the required graph of velocity versus time
d. The table of values are as follows;
Time: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22
Acceleration: DNE, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, -9, 0, 0, 0, 0, 0, 0, 0
Please find attached the required graph of acceleration versus time
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if the net force of F is applied to half the mass (m/2), write the acceleration of the mass in terms of a.
Answers
The acceleration of the mass in terms of {m} is -
a = 2F/m.
What is the formula to calculate the force acting on a body?The force acting on a body is given by -
Force {F} = mass {m} x acceleration {a}
Given is that a net force of {F} is applied to half the mass {m/2}.
We know that -
Force {F} = mass {m} x acceleration {a}
F = {m/2} x a
a = 2F/m
Therefore, the acceleration of the mass in terms of {m} is -
a = 2F/m.
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A laboratory measurement finds 200 μg of hemoglobin per μL of blood. Hemoglobin, the blood protein that transports oxygen, has a molecular weight of 64 kDa or 64,000 u , where 1 dalton ( Da ) = 1 atomic mass unit ( u ) = 1.66×10^−24g . Estimate the number of hemoglobin proteins in one red blood cell. Express your answer in hemoglobin per red blood cell.
Answers
One red blood cell contains an estimated 251 molecules of haemoglobin, according to our estimation.
What size does a red blood cell typically have?The average red blood cell has a diameter of 6 to 8 micrometres, according to the American Society of Haematology, and a volume of 113-268 μm³ or 113-268x10⁻¹² L.
Let's first change the haemoglobin concentration from grammes per litre to grammes per litre so that it has the same units as the molecular weight:
200 μg/μL x 1 g/1000 μg x 10⁶ μL/L = 0.2 g/L
Next, let's translate hemoglobin's molecular weight from kDa to grammes per molecule:
64 kDa x 1000 Da/kDa x 1.66x10⁻²⁴ g/Da = 1.06x10⁻²⁰ g/molecule
Using Avogadro's number, we can now determine how many haemoglobin molecules are present in a single litre of blood (\(6.022*10^{23}\) molecules/mol): 0.2 g/L x 1 mol/1.06x10⁻²⁰ g x \(6.022*10^{23}\) molecules/mol = 1.13x10¹⁵ molecules/L.
Divide the total number of molecules in 1 litre of blood by the volume of red blood cells to get the amount of haemoglobin molecules per red blood cell. The typical red blood cell count range, according to the American Society of Haematology, is between 4.5-5.5 million cells/L, which translates to 4.5-5.5x10¹² cells/L.
When we divide the quantity of red blood cells in 1 L by the quantity of haemoglobin molecules, we get:
1.13x10¹⁵ molecules/L / 4.5x10¹² cells/L = 251 Red blood cell haemoglobin molecules, rounded to the closest integer.
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Melvina has a mass of 70 kg and is about to jump from the window ledge of a burning building.
The ledge is 80 m above the ground. What is Melvina's potential energy?
Answers
Melvina's potential energy is 54,880 Joules.
To calculate Melvina's potential energy, we need to use the formula for gravitational potential energy:
Potential energy = mass × gravitational acceleration × height
Potential energy is a measure of the energy an object possesses due to its position relative to other objects. In this case, Melvina's potential energy is a result of her height above the ground. As she stands on the ledge of the burning building, her potential energy is stored and can be converted into other forms of energy if she were to jump or fall. The potential energy will decrease as she descends, and it will be converted into kinetic energy (energy of motion).
Given that Melvina has a mass of 70 kg and the ledge is 80 m above the ground, we can substitute the values into the formula:
Potential energy = 70 kg × 9.8 m/s² × 80 m
Calculating this, we find:
Potential energy = 54,880 Joules
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(TIMED) Sally Diamond observes that light striking a sheet of material at 26.7 degree angle to the surface is bent to an angle of 36 degrees relative to the normal as it passes through the material. Through what material is the light passing?
Pyrex
Ruby
Water
Crown glass
Answers
Answer:
Crown glass
Explanation:
We can use Snell's Law to determine the material through which the light is passing.
Snell's Law states that n1 sinθ1 = n2 sinθ2, where n1 and n2 are the indices of refraction of the two materials, θ1 is the angle of incidence, and θ2 is the angle of refraction.
In this case, we know that the angle of incidence is 26.7 degrees, and the angle of refraction is 36 degrees. We also know that air has an index of refraction of approximately 1.
Using Snell's Law, we can solve for the index of refraction of the material:
1 sin 26.7 = n2 sin 36
n2 = (1 sin 26.7) / (sin 36)
n2 ≈ 1.52
The index of refraction of the material is approximately 1.52. This corresponds to the index of refraction of crown glass, which is a common optical material used in lenses and prisms. Therefore, the light is most likely passing through crown glass.
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According to "Patterns of Change," select the ways that rocks are changed naturally over time. Choose three answers. O A. water O B. location O C. animals D. wind O E. people O F temperature
Answers
Answer: A , D & F
Explanation:
2. For electric circuit shown in Figure find currents in each resistor.
Answers
The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.
What is the current flowing in each resistor?The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;
The total voltage in loop 1 is calculated as;
2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0
6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0
The current flowing in loop 2 is calculated as;
I = V/R
I₂ = ( 6 V - 4 V ) / (3 + 4)
I₂ = 0.286 A
The value of the current flowing in loop 1 is calculated as;
6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0
6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0
6 - 3I₁ - 3₁ + 0.858 = 0
-6I₁ = -6.858
I₁ = 6.858 / 6
I₁ = 1.14 A
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math
Determine if the function below is continuous.
graph of a piecewise function, with 2 pieces. The first piece is a line that starts at negative infinity and goes through point (-4,5) and ends with an open dot at (1,0). The second piece is a line that starts with a closed dot at (1,-1), goes through point (2,1) and continues to infinity.
A. not continuous at x = 1
B. not continuous at x = 0
C. not continuous at x = -1
D. continuous
Answers
The function is not continuous at x=1, so the answer is A.
At x=1, the two pieces of the function meet. The first piece ends with an open dot at (1,0), meaning that the function is not defined at $x=1$. The second piece starts with a closed dot at (1,-1), meaning that the function is defined at x=1 and takes the value -1 there.
Since the function is not defined at x=1, it cannot be continuous at that point. Therefore, the function is not continuous overall.
a fixed mass of gas occupies 1000cm² at 0 degree celcius if it heated at constant pressure to 100 degree celcius. calculate it new volume
Answers
The new volume of the gas, when heated at constant pressure from 0°C to 100°C, is approximately 1372 cm³.
The new volume of the gas can be calculated using the ideal gas law, assuming the gas behaves ideally. The ideal gas law equation is given by PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.
In this case, the problem states that the pressure is constant. Therefore, we can rearrange the ideal gas law equation to solve for the new volume:
V1/T1 = V2/T2
Where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature, respectively.
Given that the initial volume (V1) is 1000 cm² and the initial temperature (T1) is 0 degrees Celsius, we can convert these values to Kelvin:
V1 = 1000 cm² = 1000 cm³ (since 1 cm³ = 1 mL)
T1 = 0°C + 273.15 = 273.15 K
The problem states that the gas is heated to 100 degrees Celsius, so the final temperature (T2) is:
T2 = 100°C + 273.15 = 373.15 K
Now, we can solve for V2:
V2 = (V1 * T2) / T1 = (1000 cm³ * 373.15 K) / 273.15 K ≈ 1372 cm³
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A 1400-N crate rests on the floor.
How much work is required to move it at constant speed 5.0 m
vertically.
Express your answer to two significant figures and include the appropriate units.
Answers
The work required to move the crate vertically at a constant speed of 5.0 m is approximately 7000 Joules (J).
To determine the work required to move the crate vertically, we need to calculate the gravitational potential energy change. The work done is equal to the change in potential energy.
The formula for gravitational potential energy is given by:
Potential energy = mass * acceleration due to gravity * height
In this case, the mass of the crate is not provided, but we can use the given weight of the crate to find the mass. Weight is equal to mass multiplied by the acceleration due to gravity (W = mg).
Given:
Weight of crate (W) = 1400 N
Acceleration due to gravity (g) = 9.8 m/s^2
Vertical distance (height) = 5.0 m
First, calculate the mass of the crate:
1400 N = m * 9.8 m/s^2
m = 1400 N / 9.8 m/s^2 ≈ 143 kg
Now we can calculate the work:
Work = Potential energy = mass * g * height
Work = 143 kg * 9.8 m/s^2 * 5.0 m ≈ 7000 J
Therefore, the work required to move the crate vertically at a constant speed of 5.0 m is approximately 7000 Joules (J).
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7. A motorcycle accelerates from rest at a rate of 4 m/s2 while traveling 60m. What is the motorcycle's velocity at
the end of this motion, to the nearest whole number?
A. 240 meters/second
B. 22 meters/second
c. 15 meters/second
D. O meters/second
Answers
Answer: C
Explanation: 60 divided by 4 =15
Velocity can be defined as the rate of change of distance with time
Given data
Acceleration = 4/ms^2
Distance = 60m
Initial Velocity U= 0
Final Velocity V= ?
The expression for velocity is given by
V^2= U^2+2as
Let us substitute our given data into the expression
V^2 = 0^2 + 2*4*60
V^2 = 480
Square both sides
V= √480
V= 21.9 meters/second
V= 22 meters/seconds Approx.
The correct answer is option B
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what exercises most beneficial for your overall health
Answers
Answer:
Endurance, or aerobic
Strength, or resistance training
Balance
Flexibility
Explanation:
Answer:
Walking. Walking is simple, yet powerful. It can help you stay trim, improve cholesterol levels, strengthen bones, keep blood pressure in check, lift your mood, and lower your risk for a number of diseases (diabetes and heart disease, for example).
A car traveling at 11.6 meters per second crashes into a barrier and stops in 0.287 meters. What force must be exerted on a child of mass 21.2 kilograms to stop him or her in the same time as the car? Answer must be in 3 significant digits.
Answers
The equation to obtain the final speed of car is,
\(v^2=u^2+2as\)Substitute the known values,
\(\begin{gathered} (0m/s)^2=(11.6m/s)^2+2a(0.287\text{ m)} \\ a=\frac{-134.56m^2s^{-2}}{2(0.287\text{ m)}} \\ \approx-234.4m/s^2 \end{gathered}\)The negative sign of acceleration indicates that the car is deaccelerating.
The force required to stop the car is,
\(F=ma\)Substitute the magnitude of known values,
\(\begin{gathered} F=(21.2kg)(234.4m/s^2)(\frac{1\text{ N}}{1kgm/s^2}) \\ =4969.28\text{ N} \\ \approx4970\text{ N} \end{gathered}\)Thus, the force required to stop the car is 4970 N.
An air jet is flying with a constant speed at an angle of 30° above the horizontal as indicated in the figure below. The weight ⃗ of jet has magnitude W = 86 500 N and its engine provide a forward thrust ⃗ of magnitude T = 103 000 N. In addition, the lift force ⃗ (directed perpendicular to the wings) and the force ⃗ of air resistance (directed opposite to the motion) act on the jet. Determine the magnitude of ⃗ and ⃗ . (5)
Answers
To determine the magnitude of the lift force ⃗ and the force of air resistance ⃗ acting on the jet, we need to resolve the weight ⃗ and the forward thrust ⃗ into their horizontal and vertical components.
The weight ⃗ can be resolved into two components:
- the vertical component, Wsin(30°), acting downward
- the horizontal component, Wcos(30°), acting to the left
The forward thrust ⃗ can also be resolved into two components:
- the vertical component, Tsin(30°), acting upward
- the horizontal component, Tcos(30°), acting to the right
Since the jet is flying at a constant speed, the lift force ⃗ must be equal in magnitude to the weight component acting downward, Wsin(30°). Therefore, the magnitude of ⃗ is 86,500 Nsin(30°) = 43,250 N.
The force of air resistance ⃗ is equal in magnitude to the horizontal component of the weight, Wcos(30°), minus the horizontal component of the forward thrust, Tcos(30°). Therefore, the magnitude of ⃗ is (86,500 Ncos(30°)) - (103,000 Ncos(30°)) = -8,715 N, where the negative sign indicates that the force of air resistance is acting in the opposite direction to the motion of the jet.
Therefore, the magnitude of the lift force ⃗ is 43,250 N and the magnitude of the force of air resistance ⃗ is 8,715 N.
Four heavy elements (A, B, C, and D) will fission when bombarded by neutrons. In addition to fissioning into two smaller elements, A also gives off a beta particle, B gives off gamma rays, C gives off neutrons, and D gives off alpha particles. Which element would make a possible fuel for a nuclear reactor
Answers
Answer:
Element C will be best for a nuclear fission reaction
Explanation:
Nuclear fission is the splitting of the nucleus of a heavy atom by bombarding it with a nuclear particle. The reaction leads to the the atom splitting into two smaller elements and a huge amount of energy is liberated in the process. For the reaction to be continuous in a chain reaction, the best choice of element to use as fuel for the reaction should be the element whose nucleus also liberates a neutron particle after fission. The neutron that is given off by other atoms in the reaction will then proceed to bombard other atoms of the element in the reaction, creating a cascade of fission and bombardment within the nuclear reactor.
Select the correct answer.
Object A attracts object B with a gravitational force of 5 newtons from a given distance. If the distance between the two objects is reduced in half, what will
be the changed force of attraction between them?
O A.
B.
C.
D.
O E.
2.5 newtons
10 newtons
15 newtons
20 newtons
25 newtons
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Answers
The distance between the two objects is reduced in half, that will be the changed force of attraction between them is option (E) 2.5 newtons.
According to Newton's law of universal gravitation, the force of attraction between two objects is inversely proportional to the square of the distance between them.
If the distance between Object A and Object B is reduced to half, the force of attraction will increase by a factor of 2² = 4. This means that the new force of attraction will be one-fourth of the original force.
Given that the original force of attraction is 5 newtons, the changed force of attraction between Object A and Object B, when the distance is reduced in half, will be 5 newtons / 4 = 1.25 newtons, which can be rounded to 2.5 newtons.The correct answer is option e.
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if I have two forces pushing on an object 5n to the left and 10 N to the right, is this object balanced? why or why not?
Answers
Answer:
It is unbalanced
Explanation:
There are 5 more newtons of force being exerted toward the right.
Asset questions below fill in the blanks
Answers
Acceleration is defined as the change in velocity per unit time. Its unit is m/s².
Distance is the amount of space, or the actual length of the path travelled.
Displacement is the difference between the initial and final positions of the object.
Speed is the rate at which an object covers a certain distance.
Velocity is defined as the speed with a direction.
An object is said to have a positive velocity, if it is moving in the positive direction. And an object moving in negative direction has a negative velocity.
Acceleration is the change in velocity per unit time.
For freely falling objects, gravity is the only thing acting on the object.
The acceleration due to gravity on the earth is 9.8 m/s².
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If My mom is 40 and my goldfish died what is my favorite color ?
Answers
Answer:
square
Explanation:
+=-=
Answer:
SɴOWʙʟØWɘR
Explanation:
In the above example, the 9.012 represents the
Answers
The medium in which electromagnetic waves and mechanical waves travel is one of their primary distinctions. Light and other electromagnetic waves, including radio waves, can move through void space without the aid of a physical medium.
They may move through vacuum, air, or other materials and are made up of oscillating electric and magnetic fields. The propagation of mechanical waves, such as sound or water waves, on the other hand, depends on a physical medium.
To transport energy, they rely on particle interactions and displacements in the medium. Since mechanical waves need a physical medium to carry their energy, they cannot move through a vacuum.
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What type of tv uses a VfL for backlighting
Answers
A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.
LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.
The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.
Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.
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how do i turtle answer fast
Answers
Answer:
Take your TIme maaaaaan
Explanation:
Chillax
Here's a question for you Care to go bowling?
Answer:
By taking it Slow.
Don't go too fast
•What is the gravitational potential energy of a girl
who has a mass of 40 kg and is standing on the
edge of a diving board that is 5 m above the water?
Answers
Answer:
1960 joule
Explanation:
The substance that is formed in a chemical reaction is called the
Answers
Answer:
The substance formed is the product. A chemical reaction is the process in which atoms present in the starting substances rearrange to give new chemical combinations present in the substances formed by the reaction. These starting substances of a chemical reaction are called the reactants, and the new substances that result are called the products.
Answer:
product
Explanation:
educere
1. Name three ways you were able to change the green sum of forces arrow.
Answers
Changing the green sum of forces arrow involves manipulating applied forces, frictional forces, and normal forces, allowing for adjustments in magnitude and direction through various means.
To change the green sum of forces arrow, you can employ the following three strategies:
Adjusting Applied Forces: By modifying the magnitude or direction of the applied forces, you can alter the green sum of forces arrow. If the applied forces are increased or directed in a different way, the green sum of forces arrow will change accordingly. For instance, increasing the magnitude of a pushing force will result in a larger green sum of forces arrow in that direction.
Modifying Frictional Forces: Frictional forces play a crucial role in determining the green sum of forces. By changing the coefficient of friction or applying lubricants, you can affect the magnitude of frictional forces acting on an object. Reducing friction will decrease the green sum of forces arrow, while increasing friction will have the opposite effect.
Varying Normal Forces: The green sum of forces arrow can be influenced by adjusting the normal forces acting on an object. Normal forces are perpendicular to the surface and counteract the weight of an object. By changing the angle or surface on which an object rests, you can modify the normal forces. This alteration will subsequently impact the green sum of forces arrow.
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