A drive is driving a car at 36 km per hour. When he applies brake they cause a deceleration of 3 ms-2. If he takes 1s to apply the brakes ______is the distance travelled by the car during this period
A)16.67m
B)16m
C)21.75m
D)15

Answers

Answer 1

Answer:

I would say 16m because of the power some brakes have say if you were to be going at 100 miles it would stop in about 3 seconds.


Related Questions

The density of gold is 19.3 g/cm3. What is the volume of a 13 g gold nugget? (Density: D = m/v)

Answers

Answer:

Formula = D = m/v

Given value of D = 19.3 and m = 13g

19.3 = 13/v

V × 19.3 = 13

v = 13/19.3

v = 0.67

Can you please help me?
You just walked up the tallest mountain in the United States and are sitting down at the top. How much work are you doing?

A. lot
B. none
C. a little bit

Answers

Answer: lot

Explanation: because you just climbed a mountain

( Just answer 1 & 2) Please help! This is the last thing I have to do. I will mark brainliest asap!!

( Just answer 1 & 2) Please help! This is the last thing I have to do. I will mark brainliest asap!!

Answers

Answer:

1. Formula = distance/time

D= 112.0 meters, time =4 secs

Speed = d/t =112.0/4

= 28m/s

2.Formula = distance/time

D= 1/4 x 16093.44 m

= 402.35m

Time = 15secs

Speed= d/t

= 402.35/15

=26m/s

1. A simplified energy level system is given for a particular four-level laser system. Electrons are
pumped (by means of infra-red radiation) from the ground state to level P, and drop to U, setting
up a population inversion.
level P
level U
level L
ground state
0.820 eV
. 0.051 eV
0
(a) (i) Calculate the wavelength of radiation emitted in the transition from level U to
level L.
[3]

Answers

The wavelength emitted in the transition from level U to level L is 1615 A°, a four-level laser system.

The energy level between the energy levels U 0.820 eV to level L 0.051 eV,

E = E₂ - E₁

  = 0.820 - 0.051

 = 0.769 eV

The difference between energy levels, E is 0.769 eV.

The energy,

E = hc / λ

Energy (E) = 0.769 eV

h (Planck's constant) = 6.626 ×10⁻³⁴

c (speed of the light) = 3×10⁸ m/s

λ (wavelength) =?

λ = hc / E

 = (6.626 ×10⁻³⁴ × 3×10⁸ m/s) / 0.769 eV

 = (6.626 ×10⁻³⁴ × 3×10⁸ m/s) / (0.769×1.6×10⁻¹⁹)

 = (1.9878×10⁻²⁵) / (1.2304×10⁻¹⁹)

 = 1.6155×10⁻⁶

= 1615 ×10⁻¹⁰

= 1615 A°

The wavelength of radiation emitted in the transition from level U to

level L, 1615 A°.

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a measuring cylinder contains 30cm3 of a liquid some more of the liquid is added until the liquid level reaches the 50cm3 mark the reading on the balance increases by 30g what is the density of liquid?

Answers

Answer:

1.5g/cm³

Explanation:

Given parameters:

Initial volume of the liquid  = 30cm³

Final volume of the liquid  = 50cm³

Mass of the liquid  = 30g

Unknown:

Density of the liquid  = ?

Solution:

Density is the mass per unit volume of a substance.

  Density  = \(\frac{mass}{volume}\)  

volume of the liquid  = final volume - initial volume  =  50cm³  -  30cm³

 volume of the liquid  = 20cm³

Density  = \(\frac{30}{20}\)   = 1.5g/cm³

A scooter is running at a constant speed of 15 m/s . how much distance will it cover in 45 seconds ? a. 610 m b. 620 m c. 675 m ​

Answers

Question :-

A Scooter is Running at a Constant Speed of 15 m/s . How much Distance will it cover in 45 sec ?

610 meter620 meter675 meter

Answer :-

Distance covered by the Scooter in 45 seconds is 675 meter .

Explanation :-

As per the provided information in the given question, we have been given that the Speed of scooter is 15 m/s . And, we have been asked to calculate the Distance , covered by the scooter in 45 seconds .

For calculating the Distance , we will use the Formula :-

\( \bigstar \: \: \boxed{ \sf{ \: Distance \: = \: Speed \: \times \: Time \: }} \)

Therefore , by Substituting the given values in the above Formula :-

\( \dag \: \: \: \sf { Distance \: = \: Speed \: \times \: Time \: } \)

\( \longmapsto \: \: \: \sf { Distance \: = \: 15 \: \times \: 45 \: } \)

\( \longmapsto \: \: \textbf {\textsf { Distance \: = \: 675 meter}} \)

Hence , 3 Option is correct !

\( \underline {\rule {180pt} {4pt}} \)

What types of media can S-waves travel through

Answers

Answer:

The second type of body wave is the S wave or secondary wave, which is the second wave you feel in an earthquake. An S wave is slower than a P wave and can only move through solid rock, not through any liquid medium.

The Coulomb force between two charges q1 and q2 at separation r in air is F. If half of the separation is filled with medium of dielectric constant 9, what will be the value of new coulomb force?

Answers

Answer:

The new Coulomb force is q₁q₂/9πε₀r²

Explanation

The coulomb force between the two charges q₁ and q₂ at a distance r in air is given by F = q₁q₂/4πε₀r².

Now, let us assume the material of dielectric constant κ = 9 is placed between them on the side of the q₁ charge. The value of its effective charge is now q₃ = q₁/κ at a distance of d = r/2 from the q₂ charge.

Since we have air between q₂ and q₃, the coulomb force between them is

F' = q₂q₃/4πε₀d²

= q₂(q₁/κ)/4πε₀(r/2)²

=  4q₂q₁/κ4πε₀r²

= 4/κ(q₂q₁/4πε₀r²)

= 4/9 × (q₂q₁/4πε₀r²)

= q₁q₂/9πε₀r²

So, the new Coulomb force is q₁q₂/9πε₀r²

A 1.5-m length of wire carrying 4.5 A of current is oriented horizontally. At that point on the Earth's surface, the dip angle of the Earth's magnetic field makes an angle of 38° to the wire. Estimate the magnitude of the magnetic force on the wire due to the Earth's magnetic field of 5.5x105T at this point.

Answers

The magnitude of the magnetic force on the wire due to the Earth's magnetic field at this point is estimated to be 8.4 x \(10^{-3}\) N if A 1.5-m length of wire carrying 4.5 A of current is oriented horizontally

The magnitude of the magnetic force on the wire due to the Earth's magnetic field of 5.5x105 T at this point can be estimated using the formula F = BILsinθ, where F is the magnetic force, B is the magnetic field strength, I is the current in the wire, L is the length of the wire, and θ is the angle between the wire and the magnetic field vector.  

This formula is known as the Lorentz force equation.In this case, the magnetic field strength B is given as 5.5x105 T, the current I is 4.5 A, the length L is 1.5 m, and the angle θ is 38°. Hence, substituting the values into the formula we have:F = BILsinθF = (5.5x105 T) x (4.5 A) x (1.5 m) x sin(38°)F = 8.4 x 10^-3 N

This force is directed perpendicular to both the current direction and the magnetic field vector direction, according to the right-hand rule for the direction of the magnetic force. The magnitude of the magnetic force on the wire depends on the current in the wire, the length of the wire, the strength of the magnetic field, and the angle between the wire and the magnetic field vector.

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A 5.00 kg crate is on a 21.0 hill. Using X-Y axes tilted down the plane, what is the x component of the weight?

Answers

Answer:

17.56N

Explanation:

Wx=mgsin(21)=5*9.8*sin21=17.56N

Why does an astronaut weigh less on the moon than on Earth?

Answers

Answer:

Hope I Helped

Explanation:

gravitational attraction on the Moon is much less than it is here on Earth, and a person weighs less on the Moon. This weaker gravity is why we have the famous images of the Apollo astronauts taking “one giant leap for mankind” on the Moon's surface.

I am pushing a wheelbarrow. I do 35J of work on the wheelbarrow to increase its speed. Have I done positive or negative work on the wheelbarrow? How do you know?

Answers

The work accomplished is positive if you are pushing the wheelbarrow in the direction of its motion.

What is work?

Work is the application of a force over a distance to transfer energy from one system to another.

The International System of Units' Joule (J) is commonly used as the unit of work (SI).

How to determine it?

When an object is being moved and a force is being applied, work is being done. Given that you are pushing the wheelbarrow, the force you are exerting is in a direction that corresponds to the displacement (increase in speed) of the wheelbarrow, so the effort you have done is beneficial.

Work is created by multiplying force by displacement as a scalar. Work is accomplished when the directions of force and displacement are identical. Negative work is done when the forces of force and displacement are in conflict. As a result, work accomplished is positive if you are pushing the wheelbarrow in the direction of its motion, and negative if you are not.

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If a 15 kg object has a 22 n friction force acting on it. What is the friction coefficient?.

Answers

The coefficient of friction is the ratio of frictional force to the normal force. The normal force acting on 15 Kg object is 147 N and the coefficient of friction is 0.149.

What is friction?

Friction is a kind of resistive force acting on a body that resist it from motion. Thus, frictional force will be always opposite to the applied force for the displacement of an object.

The normal force acting on a body of mass m is mg. Where, g is the acceleration due to gravity. Normal force acting on 15 kg object is :

N = mg

   = 15 × 9.8 m/s²

   = 147 N.

The coefficient of friction = Normal force / frictional force

                                          = 22 N/147 N

                                          = 0.149

Therefore, the coefficient of friction for an object with 15 kg and 22 N frictional force is 0.149.

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Help pls I’ll mark as brainless

Help pls Ill mark as brainless

Answers

The marking on the scale is 4.79 cm

A crucial numeracy skill is the ability to read scales. Additionally, it supports theories about the density of the number line. Students require a firm grasp of decimal notation in order to make readings between labeled points on a scale. If it's a scale, such as a bathroom scale, it effectively tells you how much pressure is exerted on it. A weight or mass might be the reading since they are proportionate. However, since your weight would be lower there, if you used that scale on the surface of the moon, it would read lower. Scale factor = Dimension of the new shape Dimension of the original shape is the fundamental formula used to calculate it.

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1 A Copper bar is 120m long at 0°c What is the increase in length when it is heated at 40°c The Linear expansion for Copper is 1.7x10^-5/℃​

Answers

The increase in length of the copper with original length of 120 m is  8.16×10⁻² m.

What is increase in length?

A change in length ΔL is produced when a force is applied to a wire or rod parallel to its length L0, either stretching it (a tension) or compressing it.

To calculate the increase in length of the copper, we use the formula below

Formula:

ΔL = αLΔT..................... Equation 1

Where:

ΔL = Increase in length α = Linear expansion of copperΔT = Change in TemperatureL = Original Length

From the question,

Given:

α = 1.7×10⁻⁵/°CL = 120 mΔT = 40-0 = 40 °C

Substitute these values into equation 1

ΔL = 1.7×10⁻⁵×120×40ΔL = 8.16×10⁻² m

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The image above shows a crash test dummie's head traveling at -1.005 m/s while striking a headrest from a car traveling 4.524 m/s with a mass of 2005.6 kg. If the crash test dummie's head head bounces off the headrest with a 9.965 m/s and the car continues traveling at 4.487 m/s, calculate the mass of the crash test dummie's head?

Answer:

Answers

From the calculation, the mass of the dummies head is 1647.44 Kg

What is the mass of the crash test dummies head?

We know that the momentum after collision is equal to the momentum before collision.

Mass of the headrest = 2005.6 kg

Initial velocity of the head rest = 4.524 m/s

Final velocity of the head rest =  4.487 m/s

Mass of the dummy = m

Initial velocity of the dummy = -1.005 m/s

Final velocity of the dummy = 9.965 m/s

Then;

(m *  -1.005) + (2005.6 * 4.524 ) = (2005.6 *   4.487) + (m * 9.965)

-1.005m + 9073.33 = 8999.13 + 9.965m

9073.33 - 8999.13  = 9.965m + 1.005m

18072.46 = 10.97m

m = 18072.46/ 10.97

m = 1647.44 Kg

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Consider this situation: A baseball travels upward and
rightward through the air. Of the forces listed, identify which
act upon the baseball.
Tap to select the forces that are present.

Answers

The forces acting on the baseball are air resistance, and force of gravity.

What are forces present during the upward motion of an object?

The forces which act on an object moving upward will either oppose the motion of the object or help to speed up the object.

The forces present during upward motion include;

force of air resistanceforce of gravityapplied force

The forces acting on a baseball thrown upwards which also travels rightward include the following;

force of air resistance which oppose the upward motion of the baseballforce of gravity acting downwards due to the weight of the ball.

Thus, the forces acting on the baseball are air resistance, and force of gravity.

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The complete question is below:

Consider this situation: A baseball travels upward and

rightward through the air. Of the forces listed, identify which

act upon the baseball. (force of air resistance, force of gravity, weight of the ball, frictional force).

q101 is a local radio station operating at 101.7 mhz. a. what is the wavelength of their radio waves?

Answers

The wavelength of q101 is equal to 2.946 meters.  

The wavelength of a radio wave is determined by the frequency, and for q101 the frequency is 101.7 MHz.

The formula for calculating wavelength is: wavelength = speed of light (3 x 10^8 m/s) divided by the frequency (101.7 MHz).



The wavelength of a radio wave is the distance from the crest of one wave to the crest of the next, and the frequency is the number of waves passing a point in a second.

As the frequency increases, the wavelength decreases, and vice versa.

Since q101 is operating at 101.7 MHz, its wavelength is much shorter than a station operating at a lower frequency, such as the FM station 88.3 MHz, which has a wavelength of 3.41 meters.

The wavelength is also important in antenna design. An antenna needs to be designed according to the specific wavelength of the station in order to pick up the signal. In the case of q101, a 2.946 meter antenna is needed.

q101 is a local radio station operating at 101.7 MHz, and its wavelength is 2.946 meters. The wavelength is determined by the frequency, and is also important in antenna design.

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Worked examples on energy
(2) An express train of mass 600kg is
moving with a velocity of 180km per
hour.
Calculate its kinetic energy.

Answers

The kinetic energy of the moving express train with the given value of mass and velocity is 7.5 × 10⁵Joules.

What is Kinetic Energy?

Kinetic energy is simply a form of energy a particle or object possesses due to its motion.

It is expressed as;

K = (1/2)mv²

Where m is mass of the object and v is its velocity.

Given the data in the question;

Mass of the train m = 600kgVelocity of the train V = 180kmh = 50m/sKinetic energy of the train K = ?

To determine the kinetic energy of the train, we substitute our given values into the above expression.

K = (1/2)mv²

K = (1/2) × 600kg × (50m/s)²

K = 0.5 × 600kg × 2500m²/s²

K = 750000kgm²/s²

K = 7.5 × 10⁵J

Therefore, the kinetic energy of the moving express train with the given value of mass and velocity is 7.5 × 10⁵Joules.

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A 2.0-cm-tall object is 70 cm in front of a converging lens that has a 35 cm focal length.
Calculate the image position.
Calculate the image height. Type a positive value if the image is upright and a negative value if it is inverted.

Answers

Therefore, the image is formed at a distance of -70 cm from the lens and it is an inverted image with a height of 2.0 cm.

Given data:

Object height (h) = 2.0 cm, Object distance (u) = -70 cm, Focal length (f) = 35 cm

Lens formula is given as follows:

`1/f = 1/u + 1/v`

where, f = focal length of the lens, u = object distance from the lens, v = image distance from the lens

By using the lens formula,

the image distance (v) can be calculated as

:1/f = 1/u + 1/v1/35 = 1/-70 + 1/v1/v = 1/-70 - 1/35 = -3/210 = -1/70v = -70 cm

The negative sign indicates that the image is formed on the same side of the lens as the object.

Therefore, it is an inverted image.

The image height can be calculated using the magnification formula which is given as follows:

`m = -v/u`

where, m = magnification

v = image distance from the lens, u = object distance from the lens

Substituting the values, we get:

`m = -v/u`

`m = -(-70)/(-70)

`m = 1

The positive value of magnification indicates that the image is an upright image.

The height of the image can be calculated as:

`m = -v/u``1 = -v/(-70)`v = -70 cm

`h_i = m × h_o`

`h_i = 1 × 2.0 = 2.0 cm

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Problem 6. 40. Temperature dependence of the pressure
(a) Start from the classical pressure equation of state, PV = NkT , replace N by Neff for an ideal
Bose gas, and give a qualitative argument why P ∝ T^5/2 at low temperatures. (b) Show that the ground state contribution to the pressure is given by
P0 =kT/V ln(N0 + 1). Explain why P0 can be regarded as zero and why the pressure of an Bose gas for T < Tc is
independent of the volume

Answers

When the temperature is low,\(P \alpha T^{5/2}\) as the particles are in their ground state and have no kinetic energy.  P0 can be regarded as zero because the number of particles in the ground state (N0) is very small.

a.) Given the ideal gas law equation is: PV = NkT where (N) Neff is the effective number of particles. At low temperatures, the particles occupy mostly the ground state, and the number of particles in higher energy states is negligible. Hence, their energy is entirely due to quantum mechanical effects, which means that the pressure is proportional to the number of particles, Neff. Thus the pressure of an ideal Bose gas is proportional to the fifth power of the temperature at low temperatures, \(P \alpha T^(5/2).\)

b.) Given the ground state contribution to the pressure is:

\(P0 = kT/V ln(N0 + 1)\) where N0 is the number of particles in the ground state. Here pressure is proportional to the number of particles and temperature. As number of particles is small and constant P0 can be regarded as zero.

Also at temperatures below the critical temperature (Tc), the Bose gas enters a condensate phase, where a large fraction of the particles occupy the ground state. In this state, the pressure of the Bose gas is independent of the volume because the number of particles in the ground state is unaffected by the volume. Thus, the pressure of the Bose gas is determined solely by the temperature and number of particles in the system, and is independent of the volume.

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1. A wave with a frequency of 10 Hz has a wavelength of 3 meters. At what
wave speed will this wave travel?

Answers

Answer:

30 m\ s Ans .....

Explanation:

Data:

f = 10 Hz

w = 3 m

v = ?

Formula:

v = fw

Solution:

v = ( 10)(3)

v = 30 m\ s Ans ........

Anita drives for 3 hours at a speed of 60 km/h. How far will she travel?

Answers

Answer:

She will travel 180 kilometers.

Explanation:

You take the time and multiply it by your distance, and you get your total distance.

d = v.t

d = 60 km/h x 3 h

d = 180 km

If an electron (with a charge of 1.6 x10−19c) Experiences a force of 500 N at a certain point in an electric field, then find the strength of the electric field in that location

Answers

Answer:

3.125×10²¹ N/C

Explanation:

Electric Field: This can be defined as the force experienced per unit charge. The S.I unit of electric Field is N/C

Applying,

E = F/q.................. Equation 1

Where E = Electric Field, F = Force experienced, q = Charge of an electron.

From the question,

Given: F = 500 N, q = 1.6×10⁻¹⁹ C

Substitute these values into equation 1

E = 500/(1.6×10⁻¹⁹)

E = 312.5×10¹⁹

E = 3.125×10²¹ N/C

What is the net force on an object with a mass of 2.5 kg if it accelerates at 6.4 m/s^2 when pushed?

Answers

ANSWER:

16 N

STEP-BY-STEP EXPLANATION:

The force is given by the multiplication of the mass and the acceleration, like this:

\(\begin{gathered} f=m\cdot a \\ m=2.5\text{ kg} \\ a=6.4\frac{m}{s^2} \end{gathered}\)

We repalce and calculate the force, like this:

\(\begin{gathered} f=2.5\cdot6.4 \\ f=16\text{ N} \end{gathered}\)

The force is 16 newtons

Reese rides her bike 10 kilometers in 5 hours.Avery rides her bike 15 kilometers in 5 hours. Which girl rides her bike faster?​

Answers

The answer is Avery.

Answer:

Avery

Explanation:

15 Kilometers is faster than 10 Kilometers

because of the release of the neurotransmitter dopamine, people who express that they are madly in love are likely to report that they feel

Answers

people who express being madly in love are likely to report feeling intense emotions such as euphoria, happiness, excitement, and a strong desire for closeness. However, it's essential to recognize that the experience of love is complex and involves multiple neurochemical processes.

Because of the release of the neurotransmitter dopamine, people who express that they are madly in love are likely to report feeling a range of intense emotions. Dopamine is associated with feelings of pleasure, reward, and motivation, and its release in the brain can contribute to the euphoric sensations commonly experienced in the early stages of romantic love.

Individuals who are madly in love often describe feeling a sense of exhilaration, happiness, and an overall heightened state of well-being. They may experience increased energy levels, a sense of excitement and anticipation, and a general feeling of being "on top of the world." Additionally, the release of dopamine can enhance feelings of attraction and attachment, leading to an intense desire to be close to the person they love.

However, it is important to note that while dopamine plays a significant role in the initial stages of romantic love, long-term love and attachment involve other neurotransmitters and hormones, such as oxytocin and vasopressin. These chemicals contribute to feelings of trust, bonding, and long-term commitment.

In conclusion, people who express being madly in love are likely to report feeling intense emotions such as euphoria, happiness, excitement, and a strong desire for closeness. However, it's essential to recognize that the experience of love is complex and involves multiple neurochemical processes.

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What can always be said about a negatively-charged ion?
A negatively-charged ion always has more neutrons than protons
A negatively-charged ion always has more electrons than protons
A negatively-charged ion always has more protons than electrons
A negatively-charged ion always has more protons than neutrons

Answers

Answer: A negatively-charged ion always has more electrons than protons

Explanation:

First, we know that the elementary negative charge is the electron, while the positive one is the proton. Such that both have the same charge in magnitude, but a different sign. Such that if we have the same number of electrons and protons in an atom, the charge of this atom will be neutral.

And an ion is an atom with a different number of electrons and protons, so the charge of the atom is not neutral.

Then if we have a negatively-charged ion, the charge of this atom is negative. Then we must have a larger number of electrons (the negative ones) than protons (the positive ones)

Then the correct option is:

A negatively-charged ion always has more electrons than protons

at electrical synapse conduction of current on the postsynaptic
neuron by means of:
a. binding of an enzyme to the receptor
b. saltatory conduction
c. action potential between muscle fibers

Answers

The conduction of current on the postsynaptic neuron in an electrical synapse occurs through direct flow of ions between the presynaptic and postsynaptic neurons.

In electrical synapses, the conduction of current on the postsynaptic neuron occurs through direct flow of ions between the presynaptic and postsynaptic neurons. These synapses are formed by specialized structures called gap junctions, which create channels between the cells, allowing ions to pass through. The channels are formed by connexin proteins that span the plasma membranes of adjacent neurons.

When an action potential reaches the presynaptic neuron, it depolarizes the cell membrane and triggers the opening of voltage-gated ion channels. This results in the influx of positively charged ions, such as sodium (Na+), into the presynaptic neuron. As a result, the electrical potential of the presynaptic neuron becomes more positive.

Due to the direct connection provided by the gap junctions, these positive ions can flow through the channels into the postsynaptic neuron. This movement of ions generates an electrical current that spreads across the postsynaptic neuron. The current causes depolarization of the postsynaptic membrane, leading to the initiation of an action potential in the postsynaptic neuron.

The strength of the electrical synapse is determined by the size of the gap junctions and the number of connexin proteins present. The larger the gap junctions and the more connexin proteins, the more ions can pass through, resulting in a stronger electrical coupling between the neurons.

at electrical synapses, the conduction of current on the postsynaptic neuron occurs through the direct flow of ions between the presynaptic and postsynaptic neurons via specialized gap junctions. This direct electrical coupling allows for rapid and synchronized transmission of signals. Electrical synapses are particularly important in neural circuits that require fast and coordinated communication, such as in reflex arcs or the synchronization of cardiac muscle cells.

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a student uses a string to pull her 2.0 kg physics book, starting from rest, across a 2.0- m -long lab bench. the coefficient of kinetic friction between the book and the lab bench is 0.15. if the book's final speed is 4.0 m/s , what is the tension in the string? a student uses a string to pull her 4.0 kg physics book, starting from rest, across a 2.0- m -long lab bench. the coefficient of kinetic friction between the book and the lab bench is 0.15. if the book's final speed is 4.0 m/s , what is the tension in the string? a student uses a string to pull her 4.0 kg physics book, starting from rest, across a 4.0- m -long lab bench. the coefficient of kinetic friction between the book and the lab bench is 0.15. if the book's final speed is 8.0 m/s , what is the tension in the string? a student uses a string to pull her 2.0 kg physics book, starting from rest, across a 4.0- m -long lab bench. the coefficient of kinetic friction between the book and the lab bench is 0.15. if the book's final speed is 4.0 m/s , what is the tension in the string?

Answers

The calculated tension is 500 N. The direction of pulling is pull and is named tension. Therefore, tension points away from the mass in the direction of the cord/rope.

In hanging weights, the string/rope exerts an upward force on the weight as the string pulls the weight upwards. This is the force generated when a load is applied to the edge of an object, usually its cross section. Also called tensile force, tension, or tension. This type of force is only applied when the cable and object are in contact. Tension also allows power to be transmitted over relatively long distances.

mg= 50 *10

=500 N

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