The pump at the base of the drinking fountain needs to provide a gauge pressure of approximately 12.4 kPa.
How is the gauge pressure calculated for the pump in the drinking fountain?The gauge pressure for the pump in the drinking fountain is determined by considering the height to which the water is lifted and the diameter of the supply pipe. The pressure can be calculated using the hydrostatic pressure formula: P = ρgh
where P is the pressure, ρ is the density of water, g is the acceleration due to gravity, and h is the height of the water column.
In this case, the pump needs to lift the water about 1.1 m (from the base to the nozzle), and the diameter of the supply pipe is given. By substituting these values into the formula and considering the density of water, the gauge pressure required for the pump is approximately 12.4 kPa.
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The law of____suggests that the orbit of planets is not circular but____.
if the length of the centrifuge arm is 15.0 m m , at what speed is the rider moving when she experiences 10 g's?
The rider is moving at a speed of 12.2 meters per second when she experiences 10 g's.
The speed at which a rider experiences 10 g's (10 times the acceleration due to gravity) on a centrifuge can be calculated using the formula:
speed = (g * r)
Where g is the acceleration due to gravity (9.8 m/s^2) and r is the radius of the centrifuge arm (in this case, 15.0 m).
Plugging in the numbers, we get:
speed = (9.8 * 15.0) = (146) = 12.2 m/s
It's important to note that high g-forces can have serious health effects, and centrifuges are often used to simulate conditions experienced by pilots, astronauts, and other people who are subjected to high g-forces.
The g-forces experienced on a centrifuge can be used to determine the limits of human tolerance and to develop measures to protect people from the harmful effects of high g-forces.
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how to tell the difference between a start capacitor and a run capacitor
A start capacitor is designed to provide a burst of energy to start the motor, while a run capacitor is used to maintain the motor's running power. Run capacitors are usually larger and have a lower capacitance rating than start capacitors. To determine which capacitor is which, check the wiring diagram of the motor or appliance or consult the manufacturer's documentation.
To tell the difference between a start capacitor and a run capacitor, consider the following factors:
1. Function:
- Start Capacitor: Provides an initial boost of power to start the motor.
- Run Capacitor: Helps the motor maintain a consistent voltage and torque while running.
2. Time of operation:
- Start Capacitor: Operates only during the motor's startup phase.
- Run Capacitor: Operates continuously during the motor's operation.
3. Construction:
- Start Capacitor: Generally has a higher capacitance value (usually above 70 μF) and a lower voltage rating.
- Run Capacitor: Has a lower capacitance value (usually between 1 to 70 μF) and a higher voltage rating.
4. Appearance:
- Start Capacitor: Usually cylindrical, black, and larger than a run capacitor.
- Run Capacitor: Typically cylindrical, silver, and smaller than a start capacitor.
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at which point (or points) is the electric field zero n/c for the two point charges shown on the x axis?
Assuming that the two point charges are of equal magnitude and opposite sign, the electric field will be zero at a point on the x-axis that is equidistant from the two charges. This point is known as the midpoint between the two charges.
To see why this is the case, consider the electric field produced by each individual charge. Each charge produces an electric field that points away from it and decreases in strength with distance. At a point on the x-axis that is closer to one charge than the other, the electric field produced by the closer charge will be stronger than the electric field produced by the farther charge. This will result in a net electric field that points away from the closer charge and toward the farther charge.
However, at the midpoint between the two charges, the distances to the two charges are equal, and so the electric fields produced by the two charges will be equal in magnitude and opposite in direction. These two electric fields will cancel each other out, resulting in a net electric field of zero at this point.
It's worth noting that if the two point charges are not of equal magnitude and opposite sign, or if they are arranged in a different configuration, the point(s) at which the electric field is zero may be different.
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How is the answer D?
The graph that corresponds to 0.1 s in one complete cycle is graph D.
option D is the correct answer.
What is the period of a wave?The period of a wave is the time for a particle on a medium to make one complete vibrational cycle. Period, being a time, is measured in units of time such as seconds, hours, days or years.
Also, the period of a wave is the amount of time it takes for a wave to complete one wave cycle or wavelength.
From the given parameter, the coil rotates 10 times in one second. The period of the coil is calculated as;
Period = 1 s / 10
Period = 0.1 s
From the graphs, the only option that has one complete cycle in one second is option D.
Check option D, half cycle is 0.05 s and one full cycle is 0.1 s.
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A pring of force contant 120 N/m i acted up by a contant force of 240n. Calculate the elatic potential tored in the pring
A spring of force constant 120 N/m acted up by a constant force of 240N. Then, the elastic potential energy stored in the spring is 240 Nm.
The elastic potential energy stored in the spring is formulated as follows
PE = ½kx²
Where PE is the elastic potential energy, x is the displacement of the spring from its equilibrium position, and k is the spring force constant.
In this question, the spring force constant is 120 N/m, and the constant force acting on the spring is 240 N. To find the spring displacement, we can use the formula:
F = kx
Where F is the force acting on the spring, x is the displacement, and k is the force constant,
So that:
F = kx
240 N = 120 N/m . x
x = 240 N/120 N/m
x = 2 m
Once x is known, then we can calculate the potential energy of the spring:
PE = ½kx²
PE = ½ (120) (2²)
PE = 60 x 40
PE = 240 Nm
So, the elastic potential energy stored in the spring is 240 Nm.
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what maximum current is delivered by an ac source with δvmax = 52.6 v and f = 76.0 hz when connected across a 3.70-µf capacitor?
An ac source with δvmax = 52.6 v and f = 76.0 hz when connected across a 3.70-µf capacitort the maximum current delivered by the AC source across the 3.70 µF capacitor is approximately 7.931 Amperes.
To calculate the maximum current delivered by an AC source connected across a capacitor, we can use the formula
Imax = δvmax * 2πf * C
where:
Imax is the maximum current
δvmax is the peak voltage (in volts)
f is the frequency (in hertz)
C is the capacitance (in farads)
Let's plug in the given values:
δvmax = 52.6 V
f = 76.0 Hz
C = 3.70 µF = 3.70 × 10^(-6) F
Imax = (52.6 V) * (2π * 76.0 Hz) * (3.70 × 10^(-6) F)
Imax = (52.6 V) * (2 * 3.14159 * 76.0 Hz) * (3.70 × 10^(-6) F)
Imax = (52.6 V) * (150.796 * 10^(-3) F)
Imax = 7.931 A
Therefore, the maximum current delivered by the AC source across the 3.70 µF capacitor is approximately 7.931 Amperes.
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you are using a 50-mm-focal-length lens to photograph a tree. if you change to a 100-mm-focal-length lens and refocus, the image height on the detector changes by a factor of
The image height on the detector will change by a factor of 2 if you change from a 50-mm-focal-length lens to a 100-mm-focal-length lens and refocus.
The magnification of a lens is given by the ratio of the image height to the object height. Since the object height remains the same, the change in magnification is solely determined by the change in focal length.
The magnification of a lens is given by the formula:
Magnification = - (image distance / object distance).
Since we are only interested in the ratio of image heights, we can ignore the negative sign.
For the 50-mm lens, the magnification is:
Magnification1 = 50 mm / object distance.
For the 100-mm lens, the magnification is:
Magnification2 = 100 mm / object distance.
Taking the ratio of the two magnifications:
Magnification2 / Magnification1 = (100 mm / object distance) / (50 mm / object distance) = 100 mm / 50 mm = 2.
Therefore, the image height on the detector changes by a factor of 2 when switching from a 50-mm-focal-length lens to a 100-mm-focal-length lens and refocusing.
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Why are temperatures in the thermosphere not strictly comparable to those experienced near earth's surface?
Temperatures in the thermosphere are not strictly comparable to those experienced near Earth's surface because the gases of the thermosphere are moving at very high speeds, and the temperature is very high.
The thermosphere lies among the exosphere and the mesosphere. “Thermo” way warmness and the temperature in this layer can reach as much as 4,500 tiers Fahrenheit. in case you have been to hang around inside the thermosphere, though, you'll be very cold because there are not sufficient fuel molecules to transfer the warmth to you.
The thermosphere is the outer layer of the Earth's surroundings, extending from about 53 miles to greater than 370 miles above the surface. The temperature increases rapidly in this layer due to the absorption of huge quantities of incoming excessive electricity sun radiation by using atoms of nitrogen and oxygen.
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Ok soo idk what question to ask but one of my friends said tht she was dressing as Harley Quinn and she said i should dress as her too but then i said no i dont rlly dress up of those kind of people but then she started to flip out because i couldnt dress as her?? Should I tell her that not all people can dress the same even if they want to or not? What should I say so she can stop saying things that are rude just bc she is mad and thats not my fault??
Answer:
You should tell her in a nice way that that's just not your style and if she doesnt accept that then maybe you should just not talk to her for a while and let her cool down
Explanation:
Hope this helps
Which unseen force causes a golf ball to roll faster on concrete than on grass? *
Answer:Most physics and biomechanics studies of a golf swing are concerned with the motion of a ... The top surface of the concrete was much smoother than the ball, ... The ball will then roll like a coin on its edge or like a ball used in lawn bowls. ... centre of the club head then the force of the ball pushing against the face
Explanation:
SOMEONE HELP ME PLEASE
Answers:
20m/s/s
Explanation:
we know,
a = v-u/t
= 30- 0/1.5
= 20m/s/s
Strong x-ray beams can be produced when
A) cathode rays strike a metal anode.
B) gamma rays move through a magnetic field.
C) alpha rays pass through a thin metal foil.
D) beta rays are absorbed by bones
Strong x-ray beams can be produced when cathode rays strike a metal anode.
This process is known as the production of bremsstrahlung radiation. When high-speed electrons, also called cathode rays, are accelerated and then collide with a metal target, they are abruptly decelerated, and the kinetic energy lost is converted into X-ray photons.
The resulting X-ray beam produced can be strong and intense, and its properties depend on the energy of the incident electrons and the material of the target.
Gamma rays moving through a magnetic field, alpha rays passing through a thin metal foil, or beta rays being absorbed by bones do not directly produce strong X-ray beams.
In summary, the correct answer is A) cathode rays striking a metal anode can produce strong X-ray beams.
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Virtual images exist where no light rays actually can be found.
O A. True
B. False
Answer:
its true
Explanation:
ape x
Which dwarf planet orbits the Sun far beyond Pluto, taking 560 years per orbit?
Answer:
Eris
Explanation:
The object, temporarily designated 2003UB313 and later named Eris, orbits the sun about once every 560 years, its distance varying from about 38 to 98 AU.
Answer:
me
Explanation:
Which of Galileo's theories drew fire from the Catholic Church and led to his
house arrest?
Answer:
imma have to come back to you on that one
Answer:
The Sun is at the center of the solar system and the planets move around it.
Explanation:pluto/edmentum
A ball is projected 125 meters straight upward and then falls the same distance back to its starting point. Neglecting air resistance, its total time in the air is about.
The ball that is projected 125 meters straight upward has a total time in the air of: 10.1 s
The formulas for the vertical launch upward and the procedures we will use are:
y max = v₀²/(2*g)t max = v₀/ gt(of)=2*t maxWhere:
v₀ = initial velocityg = gravityy max = maximum heightt max = time to reach maximum heightt(of) = time of flightInformation about the problem:
g = 9.8 m/s²y max= 125 mv₀ = ?t max =?t(of) =?Applying the maximum height formula and clearing the initial velocity we get:
y max = v₀²/(2*g)
v₀ = √(y max * (2*g))
v₀ = √( 125 m * (2 * 9.8 m/s²))
v₀ = √( 125 m * 19.6 m/s²)
v₀ = √2450 m²/s²
v₀ = 49.497 m/s
Applying the maximum time formula we get:
t max= v₀ / g
t max= 49.497 m/s / 9.8 m/s²
t max = 5.050 s
Applying the time of flight formula, we get:
t(of) =2 * t max
t(of) =2 * 5.050 s
t(of) = 10.1 s
What is vertical launch upwards?In physics vertical launch upwards is the motion described by an object that has been launched vertically upwards in which the height and the effect of the earth's gravitational force on the launched object are taken into account.
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The time spent in the air by the ball is 10.01 seconds.
What is the total time in the air by the ball?The total time spent in the air by the ball is the sum of the time it spends moving up and the time it spends falling down.
The time spent by the ball moving up - time spent by the ball travelling down.
Time spent by the ball traveling down a distance of 125 meters is calculated using the formula given as follows:
t = √2h/g
Total time spent = 2 * √2h/g
where:
h = 125 m
g = 9.81 m/s²
T = 2 * √(2 * 125/9.81)
T = 10.01 s
Therefore, the time spent in the air by the ball is the sum of the time spent moving up and the time it spends falling down which are both equal.
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How does the work done on the cart by the spring compare to its change in kinetic energy? Does this agree with your prediction? Is there a loss due to friction? How much?
The work done on the cart by the spring is equal to the change in kinetic energy of the cart. This agrees with our prediction.
The work done on the cart by the spring can be calculated by multiplying the force applied by the spring with the distance the cart moves. This work is stored as potential energy in the spring. When the cart is released, this potential energy is converted into kinetic energy. Therefore, the work done on the cart by the spring is equal to the change in kinetic energy of the cart. This agrees with our prediction.
However, in real-life scenarios, there are always some energy losses due to friction. Frictional forces can cause a decrease in the mechanical energy of the system. This decrease in mechanical energy is called the energy loss due to friction. The amount of energy loss due to friction depends on various factors such as the surface characteristics of the cart and the track, the force applied, and the speed of the cart.
To determine the exact amount of energy loss due to friction, we need to conduct experiments and measure the mechanical energy of the system before and after the cart has been released. By comparing these values, we can calculate the energy loss due to friction.
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What is a hypothesis?
A. A piece of information gathered during an experiment
OB. A source that summarizes a primary source
O C. Something that a scientist intentionally changes during an
experiment
O D. An educated guess about the outcome of an experiment
Answer:
D!!!!!
Explanation:
A hypothesis is a supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation.
Answer:
D. An educated guess about the outcome of an experiment.
Explanation:
Hypothesis is an educated guess about the outcome of an experiment.
Hope this helps ;) ❤❤❤
five words that comes to your mind whenever you hear the word energy
Answer: power, renewable, extinct, solar, wind
Would appreciate brainliest <3
Answer:
chemical
mechanical
electrical
nuclear
thermal
brainliest ?
viewed from pluto, the sun would appear more than a thousand times fainter than on earth. True or False
( True ) Pluto is the farthest planet from the sun in our solar system. Its average distance from the sun is about 3.7 billion miles. Due to this vast distance, the intensity of sunlight reaching Pluto is significantly weaker than on Earth. From Pluto's perspective, the sun appears as a very bright star in the sky, rather than a massive glowing ball.
The sun's apparent magnitude, which is a measure of its brightness as seen from Earth, is about -26.7. However, when viewed from Pluto, the sun's apparent magnitude drops to about -19.5, which is more than a thousand times fainter. This is because the intensity of sunlight decreases with distance, following the inverse-square law. Therefore, the sun would appear much dimmer to an observer on Pluto than on Earth.
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A car carrying a 75-kg test dummy crashes into a wall at 25 m/s and is brought to rest in 0.1 s. Show that the average force exerted by the seat belt on the dummy is 18,750 N.
By considering the relationship between impulse and momentum, we can show that the average force exerted by the seat belt on the dummy is 18,750 N.
Newton's 2nd Law of Motion
The law state that the rate of change of momentum is directly proportional the force applied.
Given that a car carrying a 75-kg test dummy crashes into a wall at 25 m/s and is brought to rest in 0.1 s. The impulse of the car will be equal to its momentum. That is,
Ft = mv
Where
Force F = ?mass m = 75 kgvelocity v = 25 m/stime t = 0.1 sSubstitute all the parameters into the equation given above.
0.1 F = 75 × 25
0.1F = 1875
F = 1875/0.1
F = 18750 N
Therefore, It is shown that the average force exerted by the seat belt on the dummy is 18,750 N.
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In Eric's planning to take photos of the Plato Crater, Copernicus Crater and Rupes Cauchy Crater, he is trying to
figure out if the craters are always facing the earth. He knows that the moon spins on its axis. Doesn't that mean the
craters will be facing away from the earth at some point in the moon/lunar cycle as the moon orbits the earth?
Are the carters always facing the earth as the moon orbits the earth?
Please help!!!
Answer:
Yes, the carters are always facing the Earth as the moon orbits.
Explanation:
If the mass delivered by a rocket, m f , is separated into useful payload m u and the power-producing system mass m p =αP, show that Eq. (1.6) takes the form m 0 m u =e −Δv/u e − 2ηΔt αu e 2 (1−e −Δv/u e ) Where Δt is the thrusting time and η is the conversion efficiency. What is the optimum u e for this mission? (note Eq. 1.6 is m 0 m f =e −Δv/u e )
The optimum ue for this mission is u_e_opt = u_e ln(m0/mu)/(1 - αP/m0).
The rocket equation in the case where the mass delivered by a rocket, mf, is separated into useful payload mu and the power-producing system mass mp = αP, takes the form
m0mu = e−Δvue−2ηΔtαue2(1−e−Δvue),
Where Δt is the thrusting time, and η is the conversion efficiency.
This information is given in the question.
The optimum ue for this mission is the one that maximizes the payload mass mu for a given launch mass m0.
The rocket equation gives the relation between the initial mass of the rocket m0 and the final mass mf and the velocity change Δv it produces.
The rocket equation can be written as follows:
m0mf = e−Δvue,
Where Δv = ue ln(m0/mf)
The mass of the rocket that is consumed in a given time interval Δt is given by mp = αP Δt
The mass of the useful payload is given by
mu = mf - mp
Substituting for mf and mp, we get
mu = (1 - αP/m0)mf
Substituting the above equation in the rocket equation, we get
m0(1 - αP/m0)mf = e^(-Δv/ue)
mf = m0 e^(-Δv/ue)/(1 - αP/m0)
Substituting for mf, we get
mu = (1 - αP/m0) m0 e^(-Δv/ue)/(1 - αP/m0)
mu = m0 e^(-Δv/ue)
Multiplying both sides of the equation by m0/mu, we get
m0/mu = m0 e^(Δv/ue)
Taking the natural logarithm of both sides of the equation, we get ln(m0/mu) = Δv/ue
ue = Δv/ln(m0/mu)
Substituting the value of Δv from the rocket equation, we get
ue = u_e_opt
= u_e ln(m0/mu)/(1 - αP/m0)
Therefore, the optimum ue for this mission is u_e_opt = u_e ln(m0/mu)/(1 - αP/m0).
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What are the different forms of potential energy
Answer:
Gravitational potential energy.
Chemical energy.
Nuclear energy.
Elastic potential energy
Electrical potential energy
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A figure skater rotating at 5.00 rad/s with arms extended has a moment of inertia of 2.25 kg•m2. if the arms are pulled in so the moment of inertia decreases to 1.80 kg•m2, what is the final angular speed?
A) 2.25 rad/s
B) 6.25 rad /s
C) 0.81 rad/s
D) 4.60 rad/s
Suppose you drive an average of 25 miles a day, for a total of 60 years in a lifetime. The total distance you would have covered is equivalent to going around the earth _____ times. Take the circumference of the earth as 25,000 mile
The total distance you would have covered is equivalent to going around the earth 22 times.
Total distance traveledThe total distance traveled at a given speed and time of motion is calculated as follows;
Distance = speed x time
\(Distance = \frac{25 \ miles}{day} \times \frac{365 \ days}{1 \ year} \times 60 \ years\\\\Distance = 547, 500 \ miles\)
Distance round the EarthThe distance round the earth or circumference of the earth of the earth has been given as 25,000 miles
Number of times round the earth\(n = \frac{547,500}{25,000} \\\\ n = 21.9 \ times \ \approx 22 \ times\)
Thus, the total distance you would have covered is equivalent to going around the earth 22 times.
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1. How many laws of motion did Newton develop?
Answer:
Three laws
Explanation:
Three laws of motion that Newtown developed.
Why is a flower not a good blackbody radiator?
Answer:
A flower emits only visible light
A flower reflects much of the light that hits it
Why is red the last color seen at sunset?
A. It is bent by raindrops.
B. It is bent the most by the air.
C. It is scattered the least by the air.
D. It reflects off the atmosphere.
Answer: Within the visible range of light, red light waves are scattered the least by atmospheric gas molecules. So at sunrise and sunset, when the sunlight travels a long path through the atmosphere to reach our eyes, the blue light has been mostly removed, leaving mostly red and yellow light remaining.
Explanation: