The dog's acceleration running at 5.5 m/s then comes to a complete stop in 1.5 seconds is 8.25m/s²
HOW TO CALCULATE ACCELERATION:
The acceleration of a moving object can be calculated by multiplying the velocity of the object by the time taken. That is;Acceleration (m/s²) = speed (m/s) × time (s)According to this question, a dog is running at 5.5 m/s then comes to a complete stop in 1.5 seconds. The acceleration can be calculated as follows:Acceleration = 5.5 × 1.5Acceleration = 8.25m/s²Therefore, the dog's acceleration running at 5.5 m/s then comes to a complete stop in 1.5 seconds is 8.25m/s².Learn more at: https://brainly.com/question/19573976?referrer=searchResults
What type of energy occurs when watching tv?
ANSWER:
Light, heat and sound energy.
STEP-BY-STEP EXPLANATION:
When a television is in operation, several different types of energy transformation occur at the same time. The electrical signals leave the base station towards the device itself and the electricity is converted into light, heat and sound energy.
An RC circuit consists of a resistor with resistance 1.0 kΩ, a 120-V battery, and two capacitors, C1 and C2, with capacitances of 20.0 μF and 60.0 μF, respectively. Initially, the capacitors are uncharged; and the switch is closed at t = 0 s. How much charge will be stored in eah capacitor after a long time has elapsed (capacitor one 2.4 x 10^-3 C) (capacitor 2 7.2 x 10^-3 C) and what will the total charge on both capacitors two time constants after the switch is closed? (8.3 x 10^-3)
Answer:
\(Q_t= 8.3 * 10^3 C\)
Explanation:
From the question we are told that:
Resistor \(R=1000ohms\)
Voltage \(v=120_V\)
Capacitance of c_1 \(c_1=20 \mu F\)
Capacitance of c_2 \(c_2=60 \mu F\)
Time \(t=0\)
Generally the equation for charges is mathematically given by
\(For C_1\\Charge\ on\ C_1 = CV = 20*120 = 2400 μC = 2.4 x 10^-3 C\\Charge\ on\ C_1 = 2400 μC = 2.4 x 10^-3 C\\Charge\ on\ C_1 = 2.4 x 10^-3 C\\\)
\(ForC_2\\Charge on C_2 = 60*120 =7200 μC = 7.2 x 10^-3\\Charge on C_2 = 7.2 x 10^-3\)
Generally the equation for voltage across capacitors is mathematically given by
\(V_c(t)=V(1-e^{-t/RC})\)
\(C=C_1+C_2=80 \mu f\\t=2RC=>160000s\)
\(V_c(t)=120(1-e^{-(160000)/1000*(80)})\)
\(V_c(t)=103.7598\)
Generally the equation for charges is mathematically given by
\(Q1(t) = C1Vc(t)\\Q1(t) = 20*103.7598\\Q1(t) = 2075.196\\\\Q2(t) = 60*103.7598\\Q2(t) = 6225.6\\\)
Generally the equation for total charges \(Q_t\) is mathematically given by
\(Q_t=Q1(t)+Q2(t)\)
\(Q_t= 8.3 * 10^3 C\)
87) Determine the equivalent resistances for the following circuits.
Answer:
15 and 11 ohms
Explanation:
First one = For the parallel resistors 1 / (1/6 + 1/6 + 1/6) = 1/ (3/6 ) = 6/3 = 2 ohms then add the 3 and the 10 = 15 ohms
second one for the parallel portion equiv = (10+2)*24 / ( (10+2 + 24) = 8
then add the 3 in series = 11 ohms
if a ball is kicked from the ground such that it has an initial vertical velocity of 10 m/s and an initial horizontal velocity of 3.0 m/s, how far away will it be when it hits the ground for the first time after the kick?
The ball will go till a distance of 0.066 meters before hitting the ground for the first time.
The initial vertical velocity of the ball is 10m/s and the initial horizontal velocity of the ball is 3m/s.
The path of the ball will be a projectile.
The horizontal range of the projectile is given by,
R = u²2cosAsinA/g
u is the initial velocity,
g is acceleration due to gravity,.
tanA = 10/3
Perpendicular = 10
Base = 3
Hypotenuse = 10.44
sinA = 10.44/10
cosA = 3/10
u = √(10)²+(3)²
u = 10.44m/s.
Putting the values,
R = 10.44 x 2 x 10.44/10 x 3/10 x 1/9.8
R = 0.066 meters.
The ball goes 0.066 meters far.
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A. -2 m/s 2
B. -1 m/s 2
C. 0 m/s 2
D. 2m/s 2
What is the kinetic energy of a 3 kg ball that is rolling at 3 m/s?
Answer:
\(\Huge \boxed{\mathrm{13.5 \ Joules}}\)
Explanation:
\(\sf Kinetic \ energy \ (J)=\frac{1}{2} \cdot mass \ (kg) \cdot (velocity \ (m/s)) ^2\)
\(\mathrm{KE=\frac{1}{2} mv^2}\)
The mass of the ball is 3 kg.
The velocity of the ball rolling is 3 m/s.
\(\mathrm{KE=\frac{1}{2} \cdot 3 \cdot 3^2}\)
Evaluating and solving for kinetic energy.
\(\mathrm{KE=\frac{1}{2} \cdot 3 \cdot 9}\)
\(\mathrm{KE=\frac{1}{2} \cdot 27}\)
\(\mathrm{KE} =13.5\)
The kinetic energy of the ball is 13.5 Joules.
Answer:
Kinetic energy =1/2mv^2.
1/2×3×3^2.
1/2×27=13.5 or 13 whole number 1/2.
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Why is there more heat in an iceberg than in a pot of boiling water?
Icebergs contain many more molecules than pots of water.
Water does not hold heat very well.
Most icebergs are fairly warm to the touch.
The pot insulates the heated molecules.
Answer: There is more energy in the iceberg.
Explanation:
Just compare the size of a pot to an iceberg. Even though the boiling water is hotter, there is less total energy due to size. Therefore there is more heat(energy) in an iceberg.
which statment is correct to calculate moment if f is defined as the force and d is defined as the distance.
A force's moment is determined by its magnitude and distance from the rotational axis. force at a moment is F × d.
The applied force is F. The distance between the support and the applied load is called d. The moment of a force around a point measures the force's strength (the perpendicular distance of the line of action of the force from the point). The turning effect of a force is known as its moment. The force multiplied by the distance between the force's line of action and the pivot point or point at which the object will turn gives the result. Force at a moment equals F x d. where F is the applied force and d is the distance from the fixed axis.
Which statement, if f is defined as the force and d is defined as the distance, is valid to calculate the moment?
F × dF . dd . Fd × Fto know more about moment please visit.
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Mass of a car is given as 6000 kg is moving with a velocity of 40 m/s. Calculate the momentum of the car
try mass by velocity and Ur answer will come
Answer:
Explanation:
given
m = 6000kg
v = 40 m/
p = ?
solution
p = mv
p = 6000kg × 40m/
p =240000kg.m/
Which two elements have the most similar chemical properties?
A.
Cl and Ar
B.
Be and Mg
C.
Na and P
D.
Ca and Br
Answer:
B
Explanation:
same group
40 POINTS HELPP
The Anthropocene is still considered an informal designation because International Union of Geological Sciences (IUGS), the international organization that names and defines epochs, has not officially designated it an epoch. Their criteria for the designation of a new epoch are that there should be evidence of human impacts and change in the rock record.
What activities and impact could humans be responsible for that might be reflected in the rock record and thus determine the beginning of the Anthropocene?
(Minimum of two sentences please)
Answer:
One example of an activity that could be reflected in the rock record and contribute to the beginning of the Anthropocene is the widespread use of fossil fuels, which has led to an increase in atmospheric carbon dioxide concentrations and a corresponding shift in the Earth's climate. Another potential contributor to the Anthropocene is the proliferation of plastic and other synthetic materials, which are becoming ubiquitous in the geologic record and may persist for thousands of years.
If a car has a speed of 36m/s how long will it take to go 100 m
________ is/are a kind of matter that doesn't interact with visible light, but exerts a gravitational pull on other matter. It is hypothesized to exist in great quantities in the universe.
Dark matter is a kind of matter that doesn't interact with visible light, but exerts a gravitational pull on other matter.
It is hypothesized to exist in great quantities in the universe, as its gravitational effects can be observed in the rotation of galaxies and the large-scale structure of the universe. Dark matter is thought to make up about 85% of the total matter in the universe, but its exact nature and composition are still unknown. Many experiments are currently underway to try to detect and study dark matter particles.
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how can nutons first law apply to football
Answer:
As newton's 1st Law states that " A body tends to be at rest or in motion until an external force is applied "
Explanation:
so football will remains at rest until you kick it or stop it with your hands
desde lo alto de una antena de telefono se lanza una peloota de tenis, la antena mide 150 metros. se mide el alcance horizontal y cae a unos 70 metros de su base. Calcular: a)La velocidad horizontal inicial con a que fue lanzada la pelota. b) La velocidad vertical con la cual llega la pelota al piso
Explanation:
las respuestas están en la foto de arriba
An astronaut lands on a new, recently discovered planet in a different star system. The astronaut measures the acceleration due to gravity on the planet to be 12m/s2, and the mass of the planet is measured to be 7. 5E23kg. What is the radius of the new planet?
Answer:
The radius of the new planet is ~2.04 * 10⁶ m, or 2,041,752 m.
Explanation:
We can use Newton's Law of Universal Gravitation:
\(\displaystyle F_g=G\frac{Mm}{r^2}\)Let's look at Newton's 2nd Law:
\(F=ma\)We can set these equations equal to each other:
\(\displaystyle G\frac{Mm}{r^2} =ma\)The mass of the second mass (astronaut) cancels out. We are left with:
\(\displaystyle G\frac{M}{r^2} =a\)We are solving for the radius of the new planet, so we can rearrange the equation:
\(\displaystyle r=\sqrt{\frac{GM}{a} }\)Substitute in our known values given in the problem (G = 6.67 * 10⁻¹¹ ; M = 7.5 * 10²³ ; a = 12).
\(\displaystyle r =\sqrt{\frac{(6.67\times 10^{-11})(7.5 \times 10^{23}}{12} }\)\(r=2.04 \times 10^6\)The radius of the new planet is ~2.04 * 10⁶ m.
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The isotope of an atom containing 40 protons and 51 neutrons suddenly has two neutrons added to it.
What isotope is created?
Zirconium-53
Zirconium-93
Antimony-93
Antimony-53
Answer:
Hey, the answer is Zirconium-93
Explanation:
Im very positive about this question, so i hope I helped you ;p
Answer:
Zirconium-93
Explanation:
when we add up the 40 protons and 53 neutrons it gives 93 and a protons and neutron 93 gives a Zirconium-93
Thanks theres your answer
what is the direction of the electric field at any point on the z axis? view available hint(s)for part a what is the direction of the electric field at any point on the z axis? parallel to the x axis parallel to the y axis parallel to the z axis in a circle parallel to the xy plane
The direction of electric field at any point of z axis is always positive because of the symmetry property.
ELECTRIC FIELD - It is a force that fills the space around every charge in space.
It is a physical quantity. It represents the vector field that is generated by a charge in the area around that charge. It is defined as the electric force per unit test charge that placed at distance from the charged that generate the electric field.
the electric field is outward from the positive charge and inward negative point charge.
The direction of electric field at any point of z axis is always positive because of the symmetry property.
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When plug fuses are used on all new installations such as in a disconnect switch for a clothes dryer, the fuses must be ___.
When plug fuses are used on all new installations such as in a disconnect switch for a clothes dryer, the fuses must be type S.
What is type S fuse?
Type S fuses are also called tamper proof fuses because each fuse size has a different base and thread size.
These fuses also require the use of a special adapter which is screwed into the standard Edison base of the fuse holder.
Thus, when plug fuses are used on all new installations such as in a disconnect switch for a clothes dryer, the fuses must be type S.
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A rock is dropped from a height of 3,245 m. If we ignore air resistance, how fast will it be travelling after it falls for 3.4 s?
Answer:
954.4m/s
Explanation:
For a free falling object,it has constant acceleration and a changing velocity.
By using the velocity-time formula, the velocity can be obtained.
The height the rock travelled is the distance.
From,
Velocity (v) = Distance (d) / Time(t)
v = 3245m/3.4s
v = 954.4m/s
That js the answer I got. Hope it's right.
Drag each tile to the correct box.
Arrange the images in order to show how lake-effect snow occurs.
The images below demonstrate how lake effect snow occurs:
Cold Arctic air is passing over warm lake waters.
The surface of the lake adds heat and water vapour to the cold air mass.
Water vapour condenses in rising air to form clouds.
Snow blankets the lake and the downwind shore.
Where does lake effect snow most commonly occur?Lake effect snow most commonly occurs in the Great Lakes region of North America, which includes parts of the United States and Canada. The Great Lakes generate significant amounts of moisture, and when cold air passes over the relatively warm water, it picks up moisture and heat, leading to the formation of clouds and precipitation. As the air moves over land, it can release large amounts of snowfall in areas downwind of the lakes. This phenomenon is most common during the winter months and can produce heavy snowfalls that can impact transportation, infrastructure, and daily life in affected areas.
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Gamma rays have long wavelengths and high energy. True or false?
False. Gamma rays actually have short wavelengths and high energy. In the electromagnetic spectrum, gamma rays have the shortest wavelength and the highest frequency, which means they have a lot of energy.
This is why gamma rays are used in medical imaging, radiation therapy, and even in the sterilization of medical equipment. Despite their short wavelength, gamma rays can still penetrate through dense materials, making them very useful in these applications. So, to clarify, gamma rays do not have long wavelengths, but rather they have short wavelengths and high energy.
The highest frequency and shortest wavelength are both attributes of gamma rays. We also know that frequency and energy are directly proportional to one another (that is, they are the same), and that the wavelength is the polar opposite of frequency and energy. If frequency and energy are high, the wavelength will be short, and the converse will be true if they are low. Since X-rays are the antithesis of gamma rays, the third option—less energy and long wavelengths—is the proper response.
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What mass of aluminum can be plated onto an object in 728 minutes at 5. 94 A of current?
To determine the mass of aluminum plated onto an object, we need to use Faraday's law of electrolysis, which states that the amount of substance deposited at an electrode is directly proportional to the quantity of electricity passed through the electrolyte.
First, we need to calculate the total charge passed in coulombs (C):
Charge (C) = Current (A) × Time (s)
Since the time is given in minutes, we need to convert it to seconds:
Time (s) = 728 minutes × 60 seconds/minute = 43,680 seconds
Charge (C) = 5.94 A × 43,680 s = 259,315.2 C
Next, we need to convert the charge to moles of electrons using Faraday's constant (F), which is the charge of one mole of electrons:
Moles of electrons = Charge (C) / Faraday's constant (F)
Faraday's constant (F) = 96,485 C/mol (approximately)
Moles of electrons = 259,315.2 C / 96,485 C/mol ≈ 2.687 mol
Since the balanced equation for the deposition of aluminum is 2 Al³⁺ + 6 e⁻ → 2 Al, it tells us that 6 moles of electrons are required to deposit 2 moles of aluminum.
Therefore, the moles of aluminum deposited = Moles of electrons / 6 = 2.687 mol / 6 ≈ 0.448 mol
The molar mass of aluminum is approximately 26.98 g/mol. Therefore, the mass of aluminum plated onto the object is:
Mass = Moles × Molar mass = 0.448 mol × 26.98 g/mol ≈ 12.08 g
Hence, approximately 12.08 grams of aluminum can be plated onto the object in 728 minutes at a current of 5.94 A.
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An object increases vert its velocity from 22M/S 236M/S and five seconds. What is the acceleration of the object
Answer:
\(\boxed {\boxed {\sf a=42.8 \ m/s^2}}\)
Explanation:
Acceleration can be found by dividing the change in velocity by the time.
\(a=\frac{v-u}{t}\) (v is the final velocity, u is the initial velocity, t is the time).
The velocity increased from 22 m/s to 236 m/s in 5 seconds. Therefore:
\(v=236 \ m/s\\u=22 \ m/s\\t= 5 \ s\)
Substitute the values into the formula.
\(a=\frac{236 \ m/s - 22 \ m/s}{5 \ s}\)
Subtract in the numerator.
236 m/s-22 m/s=214 m/s\(a=\frac{214 \ m/s}{5 \ s}\)
Divide.
\(a=42.8 \ m/s^2\)
The acceleration of the object is 42.8 meters per square second.
A 10.0-kg mass is on the 30o incline connected to a cable that passes over a pulley fastened to a hanging mass 20.0 kg. If the coefficient of friction between the 10.0-kg mass and the incline is 0.2, find the acceleration of each mass and the tension in the cable.
Once we have calculated the accelerations of both masses, we can use the relationship between the two masses and the tension in the cable to find the tension.
To find the acceleration of each mass and the tension in the cable, we can start by breaking down the forces acting on each object.
For the 10.0-kg mass on the incline:
- The force of gravity acting vertically downward can be calculated as F_gravity = m * g, where m is the mass (10.0 kg) and g is the acceleration due to gravity (9.8 m/s^2).
- The normal force (N) acting perpendicular to the incline can be calculated as N = m * g * cos(theta), where theta is the angle of the incline (30o).
- The force of friction (F_friction) can be calculated as F_friction = coefficient of friction * N.
Using the equation F_net = m * a, where F_net is the net force acting on the object and a is the acceleration:
- The net force acting on the 10.0-kg mass is F_net = m * g * sin(theta) - F_friction.
- Setting this equal to m * a, we can solve for the acceleration of the 10.0-kg mass.
For the 20.0-kg hanging mass:
- The force of gravity acting vertically downward is F_gravity = m * g.
- The tension in the cable (T) is acting vertically upward.
Using the equation F_net = m * a:
- The net force acting on the 20.0-kg mass is F_net = T - F_gravity.
- Setting this equal to m * a, we can solve for the acceleration of the 20.0-kg mass.
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an electron at point p feels an electric force in the -z direction. the electron is now removed and all other charges in the system remain at the same position as before. what is the direction of the electric field at point p?
The direction of the electric field at point P is still in the -z direction, even after the electron is removed.
If an electron at point P feels an electric force in the -z direction, it means that there is an electric field at point P in the -z direction. The electric field at any point in space is defined as the force that a positive test charge would experience if it were placed at that point. In this case, the negative charge of the electron experiences a force in the opposite direction to the electric field because it has a negative charge.
When the electron is removed from point P, the electric field at that point does not change because the other charges in the system remain at the same position as before. This is because the electric field at a point in space is determined by the distribution of charges in the vicinity of that point, and not by the presence or absence of a particular charge at that point.
Therefore, the direction of the electric field at point P is still in the -z direction, even after the electron is removed.
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How does surfactant work to decrease surface tension
Surfactants (surface-active agents) are compounds that lower the surface tension of a liquid.
They work by accumulating at the liquid-gas interface and preventing water molecules from forming strong hydrogen bonds with each other, resulting in a decrease in surface tension.
A surfactant, or surface active agent, is a substance that reduces the surface tension of a liquid by altering the properties of the surface of the liquid. They typically contain both hydrophilic and hydrophobic elements, allowing them to interact with both water and oil.
The way surfactants work to reduce surface tension is explained below:Surfactants have a hydrophilic head (attracted to water molecules) and a hydrophobic tail (repelled by water molecules). When surfactants are added to water, they orient themselves at the surface between the water and the air.The hydrophobic tails of the surfactant molecules attach themselves to the air, while the hydrophilic heads face the water.
Because the tails are being pulled in two directions by the opposing forces of water and air, the surface tension of the water decreases.The greater the concentration of surfactants in the water, the more surfactant molecules there are at the surface of the water, and the lower the surface tension.
As a result, surfactants are used in a variety of applications to lower surface tension and modify wetting, emulsifying, and foaming characteristics.
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An astronaut with a mass of 100 kg is at rest outside a space capsule when the tether line breaks. To return to the capsule, the astronaut throws a 1.0 kg wrench away from the capsule at a speed of 10 m/s. At what speed does the astronaut move toward the space capsule?
the speed of the astronaut can be obtained from the calculation as 0.09 m/s.
What is the speed of the astronaut?We know that here we need to use the principle of the moments so as to obtain the speed of the astronaut. We have been told that an astronaut with a mass of 100 kg is at rest outside a space capsule when the tether line breaks.
Knowing that;
Momentum before collision = Momentum after collision
We can now be able to assert that;
(100 * 0) + ( 1 * 10) = (100 + 10) v
v = speed of the astronaut coming back
Thus we have;
v = 10/110
v = 0.09 m/s
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Calculate the magnitude of F and find the tension between A and B
(a) The magnitude of force F is 9 N.
(b) The tension between block A and B is 11.76 N.
What is the magnitude of force F?
Since the blocks are identical and the strings are all the same length, we can assume that the tension in the string between blocks A and B and between blocks B and C are the same.
Let's call this tension T.
To find the magnitude of force F, let's first consider the forces acting on block C.
The tension in the string between blocks B and C is 3 N, and there is no friction, so the net force on block C is 3 N to the right.
Since all the blocks are connected, the same force is acting on block B, and therefore the net force on block B is also 3 N to the right.
Similarly, the net force on block A is 3 N to the right. Since there are no other forces acting on the system, the net force on the entire system (the three blocks and the strings) must be equal to F.
Therefore, we can write:
F = 3 N + 3 N + 3 N = 9 N
Since the mass of each block is 0.4 kg, we can use Newton's second law (F = ma) to relate the net force on each block to its acceleration. Since the blocks are connected, they all have the same acceleration.
Let's call this acceleration a.
For block A, we have:
T = ma
For block B, we have:
T = ma
Since the tensions are the same, we can set these two equations equal to each other and solve for a:
ma = ma
Dividing both sides by m, we get:
a = a
This means that the acceleration of the blocks is the same as the acceleration due to gravity, which is approximately 9.8 m/s^2. Now we can use this value of a to find the tension T:
For block A, we have:
T - mg = ma
where;
g is the acceleration due to gravity (9.8 m/s^2).Substituting a = g, we get:
T - (0.4 kg)(9.8 m/s^2) = (0.4 kg)(9.8 m/s^2)
T = (0.4 kg)(9.8 m/s^2) + (0.4 kg)(9.8 m/s^2)
T = 7.84 N + 3.92 N
T = 11.76 N
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the free body diagram shown above is for a 5 kg box on a rough surface being pulled to the right at a constant speed by a string that is at an angle of 30° above the horizontal. the coefficient of kinetic friction between the box and the surface is 0.30. the tension in this string is most nearly:
The tension in the string pulling the box is most nearly 17 N.
The given parameters;
mass of the box, m = 5 kginclination of the string, θ = 30°coefficient of kinetic friction, μ = 0.3The tension on the string is calculated by applying Newton's second law of motion as follows.
\(\Sigma F = ma\)
at constant speed, acceleration, a, = 0
\(\Sigma F = 0\\\\T_x - \mu F_n = 0\\\\Tcos(\theta) - \mu F_n = 0\\\\Tcos(\theta)= \mu F_n\\\\T = \frac{\mu F_n}{cos(\theta)} \\\\T = \frac{0.3 \times 5 \times 9.8}{cos(30)} \\\\T = 16.97 \ N\\\\T \approx 17 \ N\)
Thus, the tension in the string pulling the box is most nearly 17 N.
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