Answers
Answer:
The volume of the bubble when it reaches the surface is 1,186.2mL.
Explanation:
The data of the initial state of the bubble is:
• V1= 250mL
,• P1= 2.42atm
,• T1= 15°C
The data of the final state of the bubble is:
• V2= this is what we are going to calculate.
,• P2= 0.95atm
,• T2=28°C
Now, with the ideal gas formula we can calculate the final volume of the bubble:
\(\begin{gathered} \frac{P_1*V_1}{T_1}=\frac{P_2*V_2}{T_2} \\ \frac{2.42atm*250mL}{15°C}=\frac{0.95atm*V_2}{28°C} \\ 40.33\frac{atm*mL}{°C}=0.034\frac{atm}{°C}*V_2 \\ \frac{40.33\frac{atm*mL}{°C}}{0.034\frac{atm}{°C}}=V_2 \\ 1,186.2mL=V_2 \end{gathered}\)So, the volume of the bubble when it reaches the surface is 1,186.2mL.
Related Questions
5. What is the mass of nitrogen in 125 g NH3? (find % composition first!)
Answers
The mass of nitrogen in 125 g NH3 is 102.9375g
Showing the calculation of mass in a chemical equationTo start by finding the percentage composition of nitrogen in NH3, we find the molar mass of NH3:
1N + 3H = 1(14) + 3(1) = 14 + 3 = 17g/mol
The percent composition of nitrogen in NH3 is:
mass of nitrogen in 1 mol NH3 / molar mass of NH3 x 100%
= (14/17 )x 100
= 82.35%
So, 82.35% of the mass of NH3 comes from nitrogen.
To find the mass of nitrogen in 125 g NH3, we can set up a proportion:
mass of nitrogen / 125 g NH3 = 82.35 / 100
mass of nitrogen = (125 g NH3) x (82.35 / 100)
mass of nitrogen = 102.9375 g
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Ferrous sulfate (FeSO4) was used in the
manufacture of inks, most notably iron gall ink,
which was used from the middle ages until the end
of the eighteenth century. It can be obtained during
the reaction of aqueous ferric sulfate, Fe2(SO4)3,
with gaseous sulfur dioxide and water to form
aqueous sulfuric acid (H2SO4) and aqueous
ferrous sulfate.
Answers
Ferrous sulfate (FeSO4) is obtained by the reaction of aqueous ferric sulfate with gaseous sulfur dioxide and water according to the equation below:
Aqueous ferric sulfate = \(Fe_2(SO_4)_3_{(aq)}\)
Gaseous sulfur dioxide = \(SO_2_{(g)}\)
Water = \(H_2O_{(l)}\)
Aqueous sulfuric acid = \(H_2SO_4_{ (aq)}\)
Aqueous ferrous sulfate = \(FeSO_4_{ (aq)}\)
Thus, the balance equation becomes:
\(Fe_2(SO_4)_3_{(aq)}\) + \(SO_2_{(g)}\) + \(2H_2O_{(l)}\) \(--->\) \(2 H_2SO_4_{ (aq)} + 2 FeSO_4_{ (aq)}\)
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How long would it take for the amount of U-235 to reach 1/8 of its initial amount?
t= _______million years
Answers
Why would someone abuse steroids?
Answers
Answer:
Because steroids can increase strength with little effort, however this is illegal to do without medical need, and it comes with many side effects.
Explanation:
173Lu has how many protons and neutrons
Answers
Answer:
71 protons
102 neutrons
Explanation:
Step 1: Find atomic number of Lu
Lu - Element number 71
So we know that Lu has 71 protons.
Step 2: Identify Lu - 173
173 is the atomic mass number, meaning the combined number of protons AND neutrons.
173 - 71 = 102 neutrons
A group of students is in the laboratory performing an experiment on the effect of adding salt to water. Which observation are students likely to make as they increase the molality of the saltwater solution?
Answers
As the molality of the saltwater solution increases, the students are likely to observe that the freezing point of the solution decreases. Molality is a measure of the concentration of a solute in a solvent, and it is defined as the number of moles of solute per kilogram of solvent. Increasing the molality of a saltwater solution means adding more salt to a given amount of water, which increases the concentration of the solute and therefore lowers the freezing point of the solution.
The reactant concentration in a zero-order reaction was 8.00×10−2 M
after 140 s and 4.00×10−2 M after 400 s
. What is the rate constant for this reaction?
Answers
The rate constant for the reaction is either 7.14×10−3 s−1 or 2.50×10−3 s−1, depending on which rate was used to calculate it.
Determining the rate constantThe rate of the reaction is given by the equation:
Rate = -k[A]
where k is the rate constant and [A] is the concentration of the reactant.
Rate at t=140 s:
Rate = (8.00×10−2 M - 0 M) / (140 s - 0 s)
= 5.71×10−4 M/s
Rate at t=400 s:
Rate = (4.00×10−2 M - 0 M) / (400 s - 0 s)
= 1.00×10−4 M/s
Since this is a zero-order reaction, the rate of the reaction is constant, and we can use either rate to calculate the rate constant:
k = Rate / [A]
Using the rate at t=140 s:
k = 5.71×10−4 M/s / 8.00×10−2 M = 7.14×10−3 s−1
Using the rate at t=400 s:
k = 1.00×10−4 M/s / 4.00×10−2 M
= 2.50×10−3 s−1
The rate constant for the reaction is either 7.14×10−3 s−1 or 2.50×10−3 s−1.
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HELP ASAP!!!
To find the formula mass of a molecule, the number of moles from the formula is multiplied by the atomic mass of each _______, and then all those masses are added together.
A) electron
B) molecule
C) particle
D) atom
Answers
Answer:
Did you figure out what it was?
Explanation:
Answer:
D) atom
Explanation:
Given its formula and Avogadro's Number (6.02 x 10^23 molecules/mol), deduce how many molecules are present in 3 x 10^-16 grams of TCDD. Type in only a number without using scientific notation.
Answers
Answer:
5 × 10⁵ molecules (500,000 molecules)
Explanation:
Step 1: Convert 3 × 10⁻¹⁶ g to moles
We will use the molar mass of TCDD (321.97 g/mol).
3 × 10⁻¹⁶ g × 1 mol/321.97 g = 9 × 10⁻¹⁹ mol
Step 2: Convert 9 × 10⁻¹⁹ mol to molecules
The required conversion factor is Avogadro's number (6.02 × 10²³ molecules/mol).
9 × 10⁻¹⁹ mol × 6.02 × 10²³ molecules/1 mol = 5 × 10⁵ molecules
How many grams of CO2 is released when 35 grams of C5H12 is burnt in excess oxygen.
Answers
Answer:
The reaction will give off 140 kJ of heat.
Explanation:
Nitrogen and hydrogen combine at a high temperature, in the presence of a catalyst, to produce ammonia.
N2(g)+3H2(g)⟶2NH3(g)
There are four molecules of nitrogen and nine molecules of hydrogen present in the diagram.
When the reaction is complete, how many molecules of NH3 are produced?
What is the limiting reactant?
How many molecules of each reactant are remain after the reaction is complete?
Answers
After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.
In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.
So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.
To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.
Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol
Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.
The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.
Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.
Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.
To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.
The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol
Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.
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How many liters of oxygen are needed to exactly react with 17.5 g of methane, CH4, at
STP? (Hint: you must calculate the number of moles of CH4 and look at the reaction
stoichiometry first)
CH4(g) + 2 O₂(g) → CO₂(g) + 2 H₂O(l)
Answers
You have 109 g of benzene (C6H6). The density of benzene is 0.879 g/mL. What is the volume of benzene (in mL)?
Answers
The volume of the benzene, given that it has a mass of 109 g and a density of 0.879 g/mL is 124 mL
How do I determine the volume of the benzene?Density of a substance is defined as follow:
Density = mass / volume
Cross multiply
Density × volume = mass
Divide both sides by density
Volume = mass / density
With the above formula, we can obtain the volume of the benzene. Details below:
Mass of benzene = 609 gramsDensity of benzene = 0.879 g/cm³ Volume of benzene = ?Volume = mass / density
Volume = 109 / 0.879
Volume = 124 mL
Thus, we can conclude that the volume of the benzene is 124 mL
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POSSIBLE POINTS: 1Dryice is carbon dioxide in the solid state. 1.28 moles of dry ice is placed in a 5.00 L chamber that is maintained at 35.10C. What is the pressure in thechamber after all of the dry ice has subiimed (atm)?O 6.5 atmO 6.0 atmO 6.8 atmO 5.8 atm
Answers
6.5atm
Explanations:According to the ideal gas equation:
\(PV=nRT\)where:
• P is the ,pressure ,of the gas
,• V is the ,volume
,• n is the ,number of moles
,• R is the ,gas constant
,• T is the, temperature
Given the following parameters
V = 5.00L
n = 1.28moles
T = 35.10 + 273 = 308.1K
R = 0.08205Latm/molK
Substitute the given parameters into the formula
\(\begin{gathered} P=\frac{nRT}{V} \\ P=\frac{1.28\times0.08205\times308.1}{5.0} \\ P=\frac{32.3579}{5.0} \\ P\approx6.5atm \end{gathered}\)Hence the pressure in the chamber after all of the dry ice has sublimed is 6.5atm
Think about it: Gold is one of the densest substances known, with a density of 19.3 g/cm3. If the gold in the crown was mixed with a less-valuable metal like bronze or copper, how would that affect its density?
Answers
Answer:
If gold has a rare, high density then it would sink quickly. If mixed substances that are less-valued, are added to the gold crown (remember that gold is rare and very dense which makes it special) then we can assume the cheap substances are less dense, thus making the crown FLOAT more rather than sink (I say more, because unless the crown was extremely mixed with cheap material then it could possibly float but it depends on how much is in the crown). Summary: The crown would either be lighter and float, or barely be sunken due to the less-dense substance.
*Hint to think about: People consider cheaper things lighter such as plastic ring/less dense for example, compared to a silver ring which is heavier/more dense (btw heavy does not always mean high density, it depends on the liquid density )
Hope this actually helps!
Explanation:
High-Desnity=Sink
Low Density=Float
What is the difference between the normal boiling point of water and the temperature at which water might boil?
Answers
Answer:
Normal boiling point is a standard boiling point at sea level highet that is 100 c°
but the temperature at which water boils may vary with different factors like increasing pressure in pressure cooker.
And it decreases with increase in height.
Explanation:
The boiling point of a liquid is the temperature at which its vapor pressure is equal to the pressure of the gas above it. The normal boiling point of a liquid is the temperature at which its vapor pressure is equal to one atmosphere (760 torr).
Normal boiling point is a standard unit and the highest is 100 c° at sea level but the temperature at which water boils and the temperature may vary with respect to different factors.
what is boiling point ?The boiling point is defined as the temperature at which the liquid vapor pressure is equal to the external pressure surrounding the liquid.
The boiling point of a liquid depend on atmospheric pressure.
When external pressure is reduced, the boiling point will be lowered. For example at sea level the boiling point of water is 100 C but when we go to 6,600 feet the boiling point become 93.4 C
The standard boiling point is defines as the temperature of boiling under 1 bar of pressure.
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What volume, in milliliters, of water is needed to make an 8.40 M solution of HCl acid using 180. grams of HCI ?
0 603 mL
O 41.4 mL
0 587 ml
0 24.1 mL
Answers
Answer:
0 587 mL
Explanation:
First we convert 180 grams of HCl into moles, using its molar mass:
180 g ÷ 36.46 g/mol = 4.94 mol HClNow we can use the number of moles and the given concentration to calculate the required volume, applying the definition of molarity:
Molarity = moles / litersLiters = Moles / molarity4.94 mol / 8.40 M = 0.588 LFinally we convert liters into milliliters:
0.588 L * 1000 = 588 mLThe closest answer is option C, 587 mL.
The volume needed to make an 8.40 M solution of HCl is 0.587 ml.
The correct option is C.
What is HCl?HCl is a strong acid. It is present in our stomach to help in digesting food.
Step1: covert 180 grams into moles
Molar mass of HCl is 36.46 g
\(\dfrac{180 g}{36.46 g/mol } = 4.94\; mol\; HCl\)
Step2: calculate the molarity
\(\rm Molality = \dfrac{mol}{L}\\\\\rm L = \dfrac{4.94 mol }{8.40 M} = 0.588 L\\\)
Covert the liters into ml
\(\dfrac{0.588 L}{1000} = 588 mL\)
Thus, the volume of the solution is 588 ml., nearest is option C, 587 ml.
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HELP PLS WILL NAME BRANLIEST BUT No LiNkS jUsT helP No LiNkS
Answers
Answer:
I think it's A and C. Please tell me if I am wrong.
Explanation:
Answer:
Alright so I did this quiz a while ago it's A and C now could i have brainliest?
Explanation:
How many grams of calcium chloride would you add to water for a total volume of 500 ml to make a 16% (weight/volume) solution?
Answers
The mass in grams of calcium chloride required to prepare a 16% weight/volume solution is 80 g.
What is the mass of calcium chloride required to prepare a 16% weight/volume solution?The concentration of a solution is the amount of solute present in a given volume of solution.
Concentration can be expressed as:
mass concentrationmolar concentration concentration- weight/ weight/, weight/volume/, or volume/volumeThe unit of percentage weight/volume concentration is g/mL
The mass of calcium chloride required to prepare a 16% weight/volume solution = 16% * 500 mL * 1g/mL
The mass of calcium chloride required = 80 g
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How does the availability of WATER affect the growth of plants and animals?
Answers
Answer:
all living things need water. no water, no life.
Write the complete balanced equation for the neutralization reaction that occurs when aqueous hydroiodic acid,HI, and sodium hydrogen carbonate, are combined.
Answers
The reaction equation can be shown as;
HI + 2H2CO3 → HIO + H2C2O4 + H2O
What is a balanced reaction equation?A chemical reaction that adheres to the rule of conservation of mass is represented by a balanced reaction equation, sometimes referred to as a balanced chemical equation. The stoichiometric coefficients, which show the proportions of each component involved, are also shown, along with the reactants and products of the reaction.
A balanced reaction equation has an equal number of each element's atoms on both sides. This indicates that the total mass of the reactants and products is equal.
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____O2 → ____O3
Type of reaction: ____
Answers
When \(O_2\) is converted to \(O_3\), the kind of reaction that takes place is oxidation.
What is oxidation?Oxidation is a type of reaction that can be defined in several ways. These include:
Addition of oxygenRemoval of hydrogenIncrease in oxidation numberAddition of electronegative elementsRemoval of electropositive elementsOxidation is the reverse of reduction, which can be defined as:
removal of oxygenaddition of hydrogendecrease in oxidation numberaddition of electropositive elementsremoval of electronegative elementsThe conversion of \(O_2\) to \(O_3\) requires the addition of oxygen. Thus, it is an oxidation reaction.
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how many grams of mgcl2 are contained in 500 grams of a 1.0% solution
Answers
The mass percentage of the solution that we have in the question is 5 g.
What is percent w/w concentration?Percent w/w (weight/weight) concentration is a way to express the concentration of a solute in a solution as a percentage by mass. It represents the mass of the solute in grams per 100 grams of the solution.
Percent w/w concentration is commonly used in industries such as pharmaceuticals, food and beverage, and cosmetics to measure the concentration of active ingredients or additives in their products.
We know that;
%w/w = weight of the solute/Weight of the solution
Let the weight of the solute be x
1 = x/500 * 100/1
1 = 100x/500
500 = 100x
x = 5 g
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Given the following equation: Mg + 2HCI → MgCl₂ + H₂
How many moles of H₂ can be produced by reacting 2 moles
of HCI?
Answers
Taking into account the reaction stoichiometry, 1 mole of H₂ can be produced by reacting 2 moles of HCI.
Reaction stoichiometryIn first place, the balanced reaction is:
Mg + 2 HCl → MgCl₂ + H₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Mg: 1 moleHCl: 2 molesMgCl₂: 1 moleH₂: 1 moleMoles of H₂ producedBy reaction stoichiometry 2 moles of HCl form 1 mole of H₂.
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60 points!! Look at picture please don’t troll
Answers
pH of a buffer solution prepared from 0.155 mol of phosphoric acid, 0.250 mole of KH2PO4, and enough water to make 0.500 L of solution.
Answers
The pH of the buffer solution would be 7.11.
pH calculationPhosphoric acid, H3PO4, can donate three protons (H+) in a stepwise manner to form dihydrogen phosphate (H2PO4-) and mono hydrogen phosphate (HPO4^2-) ions. The chemical equation for the reaction is as follows:
H3PO4 + H2O ⇌ H2PO4^- + H3O^+
H2PO4^- + H2O ⇌ HPO4^2- + H3O^+
HPO4^2- + H2O ⇌ PO4^3- + H3O^+
The pKa values for these reactions are 2.15, 7.20, and 12.35, respectively.
To prepare a buffer solution, we need to mix a weak acid and its conjugate base or a weak base and its conjugate acid. In this case, we have a mixture of H3PO4 and KH2PO4, which is a weak acid and its conjugate base, respectively.
The Henderson-Hasselbalch equation for a buffer solution is:
pH = pKa + log([base]/[acid])
where [base] and [acid] are the molar concentrations of the conjugate base and weak acid, respectively.
Using the given values:
[acid] = 0.155 mol / 0.500 L = 0.310 M (molarity of H3PO4)
[base] = 0.250 mol / 0.500 L = 0.500 M (molarity of KH2PO4)
We can calculate the pKa value for the first dissociation of H3PO4 using the given Ka value:
Ka = 10^(-pKa) = 7.52 x 10^(-3)
pKa = -log(Ka) = 2.12
Now, substitute the values into the Henderson-Hasselbalch equation:
pH = 2.12 + log(0.500/0.310)
pH = 7.11
Therefore, the pH of the buffer solution is approximately 7.11.
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A 75.0- mL
volume of 0.200 M
NH3
( Kb=1.8×10−5
) is titrated with 0.500 M
HNO3
. Calculate the pH
after the addition of 17.0 mL
of HNO3
.
Answers
Answer:
ok, here is your answer
Explanation:
i am going to solve this problem by using the ICE table method which is an easy method to determine the pH of a weak base with the given data of the problem.Given:Initial volume of NH3 solution (Vi) = 75.0 mLInitial concentration of NH3 solution (Ci) = 0.200 MInitial moles of NH3 solution (Ni) = Ci x Vi = 0.200 M x 75.0 mL = 0.0150 molesKb = 1.8 x 10^-5Moles of HNO3 added (n) = 0.500 M x 17.0 mL = 0.00850 molesVolume of NH3 solution after the addition of HNO3 (Vf) = 75.0 mL + 17.0 mL = 92.0 mLConcentration of NH3 solution after the addition of HNO3 (Cf) = Ni / Vf = 0.0150 moles / 92.0 mL = 0.163 MTo find the pH after the addition of 17.0 mL of HNO3, we need to use the ICE table method.ICE table method:Initial: NH3 + H2O ⇌ NH4+ + OH-Change: -x 0 +x +xEquilibrium: 0.0150 - x 0 x xKb = [NH4+][OH-] / [NH3]1.8 x 10^-5 = x^2 / 0.163Solving for x, x = 0.00171 M[OH-] = 0.00171 M[OH-] = Kw / [H3O+] = 1.0 x 10^-14 / [H3O+][H3O+] = 5.85 x 10^-12pH = -log[H3O+]pH = -log(5.85 x 10^-12)pH = 11.23Therefore, the pH after the addition of 17.0 mL of HNO3 is approximately 11.23.
mark me as brainliestWhat is a genome?
A) rare type of geode
B) A human
C) All the genetic information in an organism
D) A collection of genetic information located in the Smithsonian
Answers
The total collection of DNA instructions present in a cell makes up the genome.
What is Genome?The human genome is made up of 23 sets of chromosomes that are found within the cell's core and one modest chromosome that's found within the mitochondria. Everything a individual should develop and work is encoded in their genome.
All living things have DNA as their essential source of data. The term "genome" alludes to an organism's entire DNA.
Whereas a few genomes, like those of infections and microbes, are inconceivably little, a few genomes, like those of a few plants, can be nearly inconceivably huge.
All of an organism's genetic information is included in its genome. It is made up of DNA (or RNA within the case of RNA infections) nucleotide arrangements. The atomic genome contains administrative groupings (see non-coding DNA), non-coding qualities.
Therefore, The total collection of DNA instructions present in a cell makes up the genome.
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Explain how flame tests could be used to perhaps identify, which metal ions are present in an unknown solution.
Answers
An unknown metal is exposed to flame by chemists during a flame test. Based on the type of metal present in the substance, the flame will change color. Once the chemical is identified, the scientists can proceed.
Which metals can be identified by flame test?The simplest method for determining whether group 1 metal ions are present in the chemical is a flame test. There are several effective methods for other metals, but a flame test will give you a better idea of what to look for.
Chemists place an unidentified metal under a flame as part of a flame test. Depending on whatever metal is present in the substance, the flame will take on a variety of colors. Thus, the mystery material can be identified by the scientists.
Metals have observable characteristics that are particular to each one, much like all other elements, such as density, boiling temperature, melting point, and specific heat. These characteristics can be utilized to identify unknown metal samples since they are special.
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How many moles are in 59.6 grams of BaSO4
Answers
Answer:
0.2553669915026199 BaSO4
Explanation:
hi, give brainliest?