A cylindrical container is filled with oil to a depth of 32cm. If the pressure exerted at the base is 2560pa , how much is the density of the oil?

The decibel level of the sound noise that we will hear is the sum of the decibel level of the two speakers. Thus the sound power will be 190 dB.

The formula for sound power is:

Sound Power (P) = I * A

Where,

I = intensity

A = the surface area of the sphere (A = 4πr²)

The formula for decibels is:

D = 10 * log(P₁/P₂)

Where,

P₁ is the initial power

P₂ is the final power

Therefore,

Sound Power of the first speaker (P₁) = 0.625 Watts

Sound Power of the second speaker (P₂) = 0.258 Watts

Distance from the first speaker = 7.8 meters

Distance from the second speaker = 4.3 meters

Radius of the first sphere (r₁) = 7.8 meters

Radius of the second sphere (r₂) = 4.3 meters

Surface Area of the first sphere (A₁) = 4π(7.8)²

= 1928.61 m²

Surface Area of the second sphere (A₂) = 4π(4.3)²

= 232.83 m²

Using the formula of intensity above,

The intensity of the sound for the first speaker (I₁) = P₁ / A₁= 0.625 / 1928.61

= 0.000324 watts/m²

The intensity of the sound for the second speaker (I₂) = P₂ / A₂

= 0.258 / 232.83

= 0.001107 watts/m²

Using the formula for decibels,

The decibel level of the first speaker (D₁) is,

D₁ = 10 * log(I₁ / (1E-12))

= 10 * log(0.000324 / (1E-12))

= 89.39 dB

The decibel level of the second speaker (D₂) is,

D₂ = 10 * log(I₂ / (1E-12))

= 10 * log(0.001107 / (1E-12))

= 100.37 dB

Therefore, the decibel level of the sound noise that we will hear is the sum of the decibel level of the two speakers, i.e.,D = D₁ + D₂= 89.39 + 100.37= 189.76 ≈ 190 dB

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Answer:

true

Explanation:

please mark this answer as brainlist

Answer: calculate the free fall distance and velocity without air resistance from, the free fall.

Explanation:

To find out something's speed (or velocity) after a certain amount of time, you just multiply the acceleration of gravity by the amount of time since it was let go of. So you get: velocity = -9.81 m/s^2 * time, or V = gt. The negative sign just means that the object is moving downwards

Ms. Tacher's diagnosis and treatment plan incorporate right-sided facial droop and weakening.

A proper diagnosis is used to locate, count, and gather clinical data that is pertinent and accountable for a certain illness condition. The text claims that Mrs. Tacher's facial characteristics have grown more asymmetrical over the previous ten years, and there is sagging on the right side of the face. However, the text says nothing about how Ms Tacher's voice changed. It is crucial that she brings her pictures since they may aid in the diagnosis and treatment of her ailment and allow the doctor to observe how her face has altered over time.  Additionally, the text doesn't mention any additional health issues she could be experiencing.

Ms. Tacher has a right-sided facial droop, weakness, and partially closed right eye, Mr. Khalid discovers through Mrs. Teacher's medical examination. An electromyography test was performed as a diagnostic procedure to detect the electrical activity in her facial muscles. Her facial nerve's right side performance was shown to be impaired by the tests. The EMG test identified the particular issue.  The following stage in her therapy will be to begin a course of steroid medication to minimise inflammation and enhance function of her facial nerve. In order to retrain her facial muscles, she will also undergo physical therapy.

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Answer:

I really think it's Chinese

Explanation:

hope this helps

Answer:

46.2m/s²

Explanation:

Given parameters:

Acceleration  = 18.2m/s²

Original force  = F

Decrease factor = 3.9

Unknown:

New acceleration = ?

Solution:

Let the original force  = F

            new force  = \(\frac{F}{0.39}\)

        Original acceleration = 18.2m/s²

         new acceleration  = ?

According to newton's second law of motion;

       Force = mass x acceleration

  So,

        mass = \(\frac{Force}{Acceleration}\)

   So; initial mass = final mass

                \(\frac{F }{18.2}\)  = \(\frac{\frac{F}{0.39} }{acceleration}\)

             \(\frac{F}{0.39}\) x 18.2 = F x acceleration

            Acceleration = 46.2m/s²

Answer:

Explanation:

The mass of the object can be found by using the formula

\(m = \frac{p}{v} \\ \)

p is the momentum

v is the velocity

From the question we have

\(m = \frac{10}{20} = \frac{1}{2} \\ \)

We have the final answer as

Hope this helps you

Answer:   2.03259656 × 10^8

Explanation:

1.5 x 10 = 15

√(15) = 3.87

put this to the side until we sum everything up..

3.5 × 10 = 35

35 ^ 5 = 52521875

So, now lets sum it all up....

(3.87) x (52521875) = 203259656.25

but in scientific notation it is:  2.03259656 × 10^8

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Stopping distance of the car, as measured from the point where the driver first sees the red light, is 43.95 meters We can use distance-time formula.

To calculate the stopping distance of the car, we need to determine the distance traveled during the driver's reaction time and the distance traveled while the car is decelerating.

During the driver's reaction time, the car will continue to move forward at its initial speed of 15.5 m/s. The distance traveled during this time is:

\(d_reaction = v_initial * t_reaction = 15.5 m/s * 0.321 s = 4.98 m\)

After the driver reacts, the car begins to decelerate at a rate of \(6.2 m/s^2\). Use equation:

d =\(v_initial * t + (1/2) * a * t^2\)

where d: distance traveled, v_initial: initial velocity, t: time, a: acceleration, and final velocity = 0 (since car stops).

We need to find the distance traveled during the deceleration period, so we can rearrange the equation to solve for d:

d = \((v_initial^2) / (2a)\)

Put values:

\(d_deceleration = (15.5 m/s)^2 / (2 * -6.2 m/s^2) = 38.97 m\)

Note that we used a negative value for acceleration, since the car is decelerating (slowing down) rather than accelerating (speeding up).

The total stopping distance is the sum of the distance traveled during the driver's reaction time and the distance traveled while decelerating:

\(d_total = d_reaction + d_deceleration = 4.98 m + 38.97 m = 43.95 m\)

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The volume of the block is 1.6%

The box’s measurements are:

length = 50 cm, width = 25 cm, and height = 25 cm.

The measurements of the block in given data

length = 10 cm, width = 10 cm, and height = 5 cm.

The stone struck the block 32 times out of 100 drops or shoots.

volume of the box =

50 × 25 × 25 = 31250 cm^3

volume of the block

= 10 × 10 × 5 = 500 cm^3

Ratio = 500/31250

= 0.016 × 100 = 1.6%

The volume of the block is 1.6%

Ratio = 32 hits/100 shots

= 0.32 × 100 = 32%

A 32%of the time, the block was struck.

The percentages will be comparable and both quite modest.

A liquid, solid, or gas's volume is the amount of three-dimensional space it occupies. Although there are many different units that may be used to indicate volume, the most common ones are liters, cubic meters, gallons, milliliters, teaspoons, and ounces.

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(a) The moment of inertia of the system about the axis can be calculated using the formula for the moment of inertia of a point mass rotating about an axis.

(b) The angular momentum of the system about the axis can be determined by multiplying the moment of inertia by the angular speed.

(c) If the masses are pulled into a smaller radius, the moment of inertia will change, resulting in a new angular momentum for the system.

(d) The new angular speed of each mass can be calculated using the principle of conservation of angular momentum.

(e) The change in energy of the masses can be determined by comparing the initial and final kinetic energies of the system.

(a) To calculate the moment of inertia of the system about the axis, we consider the two point masses rotating at a given radius. The moment of inertia for each point mass is given by the formula I = m * r², where m is the mass and r is the radius.

Since there are two masses, we can calculate the total moment of inertia by summing the individual moments of inertia.

(b) The angular momentum of the system is determined by multiplying the moment of inertia by the angular speed. Using the formula L = I * ω, where L is the angular momentum, I is the moment of inertia, and ω is the angular speed, we can find the angular momentum of the system.

(c) If the masses are pulled into a smaller radius, the moment of inertia will change. We can calculate the new moment of inertia using the same formula as in (a) but with the new radius. With the new moment of inertia, we can determine the new angular momentum of the system.

(d) To find the new angular speed of each mass, we apply the principle of conservation of angular momentum. The initial angular momentum of the system is equal to the final angular momentum. By rearranging the equation L = I * ω and solving for ω, we can calculate the new angular speed.

(e) The change in energy of the masses can be determined by comparing the initial and final kinetic energies of the system. The initial kinetic energy is given by (1/2) * I * ω², where I is the initial moment of inertia and ω is the initial angular speed.

Similarly, the final kinetic energy can be calculated using the new moment of inertia and angular speed. The difference between the initial and final kinetic energies represents the change in energy of the masses.

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Answer:

B. Luminosity

Explanation:

The luminosity of a star is a measure of its brightness.

Have a good day and stay safe!

Answer:

8.89 m/s

Explanation:

rate = distance/time

40m/4.5 sec = 8.8888889 m/s

Answer:

0.125

Explanation:

acellus

Answer: Here this will help you..

Explanation:

1 kg-m/s to kilogram-force meter/second = 1 kilogram-force meter/second

5 kg-m/s to kilogram-force meter/second = 5 kilogram-force meter/second

10 kg-m/s to kilogram-force meter/second = 10 kilogram-force meter/second

20 kg-m/s to kilogram-force meter/second = 20 kilogram-force meter/second

30 kg-m/s to kilogram-force meter/second = 30 kilogram-force meter/second

40 kg-m/s to kilogram-force meter/second = 40 kilogram-force meter/second

50 kg-m/s to kilogram-force meter/second = 50 kilogram-force meter/second

75 kg-m/s to kilogram-force meter/second = 75 kilogram-force meter/second

100 kg-m/s to kilogram-force meter/second = 100 kilogram-force meter/second

The range of speeds the object can have before the string breaks is approximately 4.63 m/s to 9.77 m/s.

To determine the range of speeds, we need to consider the tension in the string. At maximum speed, the tension in the string is equal to the centripetal force required to keep the object moving in a circle. This can be calculated using the formula: T_max = m * v_max² / r, where T_max is the maximum tension, m is the mass of the object, v_max is the maximum speed, and r is the radius of the circle.

Since the tension in the string cannot exceed the breaking strength of 250 N (25.0 kg × 9.8 m/s²), we can set up the following inequality: m × v_max² / r ≤ 250 N. Simplifying the inequality, we have v_max² ≤ 250 N × r / m.

Taking the square root of both sides, we get v_max ≤ √(250 N × r / m). Plugging in the given values (r = 0.800 m, m = 3.00 kg), we can calculate the maximum speed: v_max ≤ √(250 N × 0.800 m / 3.00 kg) ≈ 9.77 m/s.

Similarly, we can calculate the minimum speed by considering the tension at minimum speed, which is zero. Using the same formula, we get v_min ≤ 0 m/s. Therefore, the range of speeds is approximately 0 m/s to 9.77 m/s.

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Complete question:

A light string can support a stationary hanging load of 25.0 kg before breaking. An object of mass m = 3.00 kg attached to the string rotates on a frictionless, horizontal table in a circle of radius r = 0.800 m, and the other end of the string is held fixed. What range of speeds can the object have before the string breaks?

Answer:

The correct answer is: A HARD DISK

Explanation:

Magnetic Disc stores data of different types and formats that can always be edited or erased at any time. An example of a Magnetic Disc is a Hard Disk.

A hard disk is a type of magnetic storage device inside a computer that store data magnetically usually for the long-term and it could store a large volume of data, though that depends on the size, because it comes in various size. However, it generally allows stored data to be retrieved easily.

For the right block to balance the forces and remain steady, it needs to weigh 7.9 kg.

The force is an external agent which is applied to the body or an object to move it or displace it from one position to another position.

When there is no net force acting on the system, the two blocks stay in place. In this instance, the strain in the rope holding the two blocks together balances the pull of gravity on them. The sine of the angles, along with the masses of the blocks, can be used to calculate the tension in the rope.

\(T= (m_1 \times g) \times sin(\theta_1) + (m_2\times g) \times sin(\theta_2)\)

Substituting the known values:

\(T = (10 \times 9.8 )\times sin(23^o) + (m_2\times 9.8 )\times sin(40^o)\)

Solving for m₂:

\(m_2= \dfrac{(T- (10 \times 9.8 )\times sin(23^o)} { (9.8\times sin(40^o))}\)

The mass of the right block must be 7.9 kg for the two blocks to remain stationary.

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The question is -

Two blocks in the Figure below are at rest on frictionless surfaces What must be the mass of the right block so that the two blocks remain stationary? 4.9kg 6.1kg 7.9kg 9.8kg

To launch a 60 kg human at the given speed, the spring constant needed is 1500 N/m.

This is the proportion of a spring's extension to the force applied to it. Utilizing the energy conservation principle, the spring's spring constant is determined. The human will transform the elastic potential energy of the spring into kinetic energy in order to launch at the desired speed.

U = K.E

¹/₂kx² = ¹/₂mv²

k = mv²/x²

where;

m is mass of the human

v is the speed of the cannon

x is the extension of the spring

k is the spring constant

Substitute the given parameters and solve for the spring constant.

k = (60x 15²) / (3²)

k = 1500 N/m

A spring constant of  1500 N/m is need to maintain the law of conservation of energy, from elastic potential energy of the spring to kinetic energy of the human,

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The complete question is -

In order To launch a 60 kg human so that he leaves a cannon moving at a speed of 15 m/s, you need a spring with an appropriate spring constant. This spring will be compressed 3.0 m from its natural length to launch the person. The cannon oriented at an angle of 37⁰ above the horizontal?

a) Which spring constant should the spring have so that the cannon functions as desired?

Answer:

The correct answer is C. they have fewer electron shells to shield the protons from the electrons.

Ionization energy is the energy required to remove an electron from an atom or ion in the gaseous state. Elements in the same group of the periodic table have the same number of valence electrons, which are the outermost electrons involved in chemical bonding. However, as we move up the group, the ionization energy increases. This is because the elements at the top of the group have fewer electron shells, which means that the valence electrons are closer to the nucleus and experience a stronger attraction to the protons in the nucleus.

The valence electrons are shielded from the attractive force of the protons by the inner electrons in the atom. Therefore, as we move down the group, the increasing number of electron shells provides more shielding and reduces the effective nuclear charge experienced by the valence electrons. This makes it easier to remove an electron from the outer shell, resulting in a lower ionization energy.

Therefore, elements at the top of the periodic table have higher ionization energies because they have fewer electron shells to shield the protons from the electrons. This results in a stronger attraction between the valence electrons and the nucleus, making it more difficult to remove an electron from the outer shell.

Option A is incorrect because fewer layers of electron shells actually mean less shielding, which leads to a higher ionization energy. Option B is incorrect because electronegativity is a measure of an atom's ability to attract electrons, not its ionization energy. Option D is incorrect because atomic radius also affects ionization energy, but it is not the primary reason why ionization energy increases up a group.

In a 5.0 L container at 373 K and 203 KPa there is 0.327 mol of a gas sample.

The number of moles of a gas sample in a container can be calculated using the ideal gas law, which is represented by the equation PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature.

Given the volume (V) of the container as 5.0 L, the temperature (T) as 373 K, and the pressure (P) as 203 kPa, we can rearrange the ideal gas law equation to solve for the number of moles (n) as follows:
n = PV/RT

Substituting the given values into the equation, we get:

n = (203 kPa)(5.0 L)/ (8.314 L*kPa/K*mol)(373 K)

n = 1015 kPa*L / (8.314 L*kPa/K*mol)(373 K)

n = 0.327 mol

Therefore, the number of moles of the gas sample in the 5.0 L container at 373 K and 203 kPa is 0.327 mol.

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Strong x-ray beams can be produced when cathode rays strike a metal anode.

This process is known as the production of bremsstrahlung radiation. When high-speed electrons, also called cathode rays, are accelerated and then collide with a metal target, they are abruptly decelerated, and the kinetic energy lost is converted into X-ray photons.

The resulting X-ray beam produced can be strong and intense, and its properties depend on the energy of the incident electrons and the material of the target.

Gamma rays moving through a magnetic field, alpha rays passing through a thin metal foil, or beta rays being absorbed by bones do not directly produce strong X-ray beams.

In summary, the correct answer is A) cathode rays striking a metal anode can produce strong X-ray beams.

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Answer:

Water gains energy during evaporation and releases it during condensation in the atmosphere

Explanation:

In the water cycle, heat energy is gained or lost by water as it undergoes various processes in the cycle.

In evaporation, water molecules gains energy because the molecules of water vibrate faster and become more energetic. Hence they are able to escape into the atmosphere from the surface of the liquid.

In condensation, the molecules of gaseous water looses energy and becomes liquid.

Hence, water gains energy during evaporation and releases it during condensation in the atmosphere.

Answer:

K12 HE HE

Explanation:

C. They are probably the same temperature. it is likely that both the red book and the blue book are at the same temperature.

The color of an object does not inherently determine its temperature. The perceived color of an object is based on the wavelengths of light it reflects or absorbs. While different colors may have different abilities to reflect or absorb light, this does not necessarily indicate differences in temperature. Without additional information about the books or their exposure to external heat sources, it is reasonable to assume that both books sitting on the table would be at the same ambient temperature. In the absence of any specific heating or cooling mechanisms acting on the books, they would equilibrate with the surrounding environment and reach the same temperature over time.

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