Answer: v = 112in/s
a = 896.05in/s²
Explanation: Angular velocity is the arc traveled per change in time or:
\(\omega=\frac{v}{r}\)
For the pedal, it will be:
\(\omega_{p}=\frac{v_{p}}{r_{p}}\)
\(\omega_{p}=\frac{26}{6.5}\)
\(\omega_{p}=4\) rad/s
Angular velocity of the pedal is equal to the angular velocity of the chain:
\(\omega_{p}d_{p}=\omega_{s}d_{s}\)
where
\(d_{p}\) is diameter of the pedal
\(d_{s}\) is diameter of the small circle at the rear wheel
\(\omega_{s}=\frac{7}{3.5}.4\)
\(\omega_{s}\) = 8 rad/s
Velocity at the point D at the bottom othe rear wheel:
\(v_{D}=\omega_{s}r_{D}\)
\(v_{D}=\) 8.14
\(v_{D}\) = 112in/s
Velocity at point D is 112 in/s.
Acceleration in circular motion is the vectorial sum of normal and tangential acceleration.
Angular acceleration is also known as centripetal acceleration, due to its direction pointing towards the center. It is "responsible" for changing the object direction. It is calculated as \(a_{c}=\omega^{2}.r\)
Tangential acceleration is the change in magnitude of the circular motion and is calculated as
\(a_{t}=r.\frac{\Delta \omega}{\Delta t}\) or \(a_{t}=r.\alpha\)
Angular and tangential accelerations are directly proportional.
Tangential Acceleration of the pedal is:
\(\alpha_{p}=\frac{a_{t}}{r}\)
\(\alpha_{p}=\frac{2.2}{6.5}\)
\(\alpha_{p}\) = 0.34 rad/s²
Tangential acceleration at the pedal is equal to angular acceleration at the rear wheel:
\(r_{w}.\alpha_{w}=r_{p}.\alpha_{p}\)
\(r_{w}\) is radius of the small circle at the rear wheel
\(r_{p}\) is radius of the pedal
\(\alpha_{w}=\frac{3.5}{1.75}.0.34\)
\(\alpha_{w}\) = 0.68 rad/s²
At the point D, tangential acceleration will be:
\(a_{t,D}=\alpha_{w}.r_{D}\)
\(a_{t,D}=0.68*14\)
\(a_{td,D}\) = 9.52 in/s²
Centripetal acceleration at point D is:
\(a_{c,D}=\omega_{D}^{2}.r_{D}\)
\(a_{c,D}=8^{2}.14\)
\(a_{c,D}\) = 896 in/s²
Net acceleration:
\(a_{D}=\sqrt{a_{t,D}^{2}+a_{c,D}^{2}}\)
\(a_{D}=\sqrt{9.52^{2}+896^{2}}\)
\(a_{D}\) = 896.05 in/s²
Acceleration of point D at the bottom of rear wheel is 896.05 in/s²
I need help on this what in the world is this
The net force on charge 3 is 1.8 N.
What is the net force on charge 3?
The net force on charge 3 is calculated by applying Coulomb's law as shown below;
F = kq₁q₂/r²
where;
q₁ is the charge 1q₂ is the charge 2r is the distance between the chargesThe net force on charge 3 is calculated as;
F (net) = F₁₂ + F₂₃
F (net) = ( 9 x 10⁹ x 5 x 10⁻⁶ x 5 x 10⁻⁶ ) / (0.5²) + ( 9 x 10⁹ x 5 x 10⁻⁶ x 5 x 10⁻⁶ ) / (0.5²)
F (net) = 0.9 N + 0.9 N
F (net) = 1.8 N
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What is the magnitude of the net displacement of a point on the rim of the blade during the deceleration?.
The correct answer is net displacement of a point on the rim of the blade during the deceleration is 10.0 in or 0.254 m 10.0 i n o r 0.254 magnitude .
Magnitude in physics is simply described as "distance or quantity." It shows the size or direction that an object moves in either an absolute or relative sense. It is a way of expressing something's size or scope. Magnitude in physics often describes a length or a size. A scalar is used to indicate a force's magnitude, which is the amount to which the body it is acting on will be accelerated by the force (a single number). The force's strength can also be considered in terms of its magnitude. An attribute of a mathematical object that indicates whether it is bigger or smaller than other things of the same kind is its magnitude or size.
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Hey does anyone know the answer?
Answer:
C
Explanation:
The law of conservation of energy determines that energy cannot be created or destroyed.
8. How much power is used if you use a 20 N force to push a shopping cart 3.5 m in 2 s?
The power used, given that a force of 20 N is used to push the shopping cart 3.5 m in 2 seconds is 35 W
How do i determine the power used?First, we shall determine the work done in pushing the cart. Details below:
Force used (F) = 20 NDistance (d) = 3.5 mWork done (Wd) = ?Wd = Fd
Wd = 20 × 3.5
Wd = 70 J
Finally, we shall determine the power used in pushing the cart. Details below:
Work done (Wd) = 70 JTime (t) = 2 secondsPower used (P) = ?P = Wd / t
P = 70 / 2
P = 35 W
Thus, we can conclude that the power used is 35 W
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1. Which of the following does not affect the resistance of a wire?
a) Length
b) Temperature
c) Usage time
d) Cross-sectional area
2. If a 12V battery is passing current through a resistor with a current of 2A, what is the value of the resistor?
a 24resistance
b) 14resistance
c) 10resistance
d) 6resistance
3. Describe the differences between series and parallel circuits.
4. A circuit contains resistors of 8resistance and 4resistance,what is combined resistance if the resistors are combined:
a) In series
b) In parallel
5. A 0.5A current is passing across three resistors of 8resistance, 4resistance and 12resistance that are linked in series.
What is the potential difference of the circuit?
6. Wire A has a resistance of 24resistance. If wire B is double the length and has a diameter four times as large as wire A, what is the resistance of wire B?
A sample of The halflife of the substance is 21 minutes the number of atoms remaining underway. radioactive Substances has 812X1020 atom Determine the number of atoms remaining
After 42 minutes, there are 203 x \(10^{20\) atoms remaining of the radioactive substance.
To determine the number of atoms remaining after a certain amount of time has passed, we can use the formula for radioactive decay:
N(t) = N0 * \((1/2)^{(t / T)\),
where:
N(t) = number of atoms remaining at time t,
N0 = initial number of atoms (812 x \(10^{20\) atoms),
T = half-life of the substance (21 minutes), and
t = time that has passed.
Let's calculate the number of atoms remaining after a given time.
Suppose the time passed is t = 42 minutes (twice the half-life).
N(t) = 812 x \(10^{20\) * \((1/2)^{(42 / 21)\)
N(t) = 812 x \(10^{20\) * \((1/2)^2\)
N(t) = 812 x \(10^{20\) * 1/4
N(t) = 203 x \(10^{20\) atoms.
So, after 42 minutes, there are approximately 203 x \(10^{20\) atoms remaining of the radioactive substance.
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Your paragraph should answer the following questions:
Reflect on your data/records from Step 1. Consider both of the times of day you recorded
the Sun's location. Which of those times do you think the angle of incidence of sunlight
would provide the highest concentration of solar energy in your location? Explain your
answer.
Again, reflect on the times of day that you recorded the Sun's location. When the Sun is
hovering over the Tropic of Cancer, how might you expect your observations to change?
What about if the Sun was hovering over the Tropic of Capricorn? Why?
• Did parallax play a role in your observations? Explain.
• What were your reflections about your moon measurements? What did you notice about
the changes you observed both in the daytime and nighttime measurements?
• How did the experience with moon measurements (and the associated readings) help you
understand new vocabulary and concepts important to the sun measurements?
I think the highest concentration of solar energy would occur when the Sun is directly overhead, as the angle of incidence is at its highest.
What is concentration?Concentration is the ability to focus on a certain task or activity, while blocking out distractions or other competing activities. It is an important skill to possess in order to be successful in both academic and professional settings. Concentration involves the ability to pay attention to a specific task or activity, while still being able to remember the details and information associated with it.
I think the highest concentration of solar energy would occur when the Sun is directly overhead, as the angle of incidence is at its highest. When the Sun is hovering over the Tropic of Cancer, the angle of incidence would be lower as the Sun is further from the zenith. Similarly, when the Sun is hovering over the Tropic of Capricorn, the angle of incidence would be even lower as the Sun is further from the zenith. Parallax did play a role in my observations as it affected the angle of the Sun's position relative to my location. When making my moon measurements, I noticed that the readings changed depending on the time of day and the phase of the moon. This experience helped me to understand the concepts of azimuth and altitude, as well as how they relate to the angle of incidence of sunlight.
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How much current is in a circuit with a 1.5 V battery and three
2-ohm resistances (bulbs) in series?
Answer: 0.25A
Explanation: To calculate the current in the circuit, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R):
I = V / R
In this case, the total resistance of the circuit is the sum of the individual resistances of the three bulbs in series, which gives us:
R = 2 + 2 + 2 = 6 ohms
The voltage of the battery is given as 1.5V.
So, using Ohm's Law, we can calculate the current in the circuit as:
I = V / R = 1.5 / 6 = 0.25 amps
Therefore, the current in the circuit is 0.25 amps.
The current in the circuit is 0.25 A.
Voltage across the circuit, v = 1.5 V
Resistance in each resistors, R = 2Ω
Since, the resistors are connected in series combination, their effective resistance,
R' = 3R
R' = 3 x 2
R' = 6Ω
According to Ohm's law, if the temperature and all other physical factors remain constant, the voltage across a conductor is directly proportional to the current that is flowing through it.
So, according to Ohm's law,
V = IR
Therefore, current flowing through the given circuit,
I = V/R
I = 1.5/6
I = 0.25 A
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Question 16 of 17
Figure (a) shows a wire that forms a rectangle (W = 23.0cm, H = 31.0cm) and has a resistance of 4.00 mOhm. Its interior is split into three equal areas, with magnetic fields B₁, B₂, and B. The fields are uniform within each region and directly out of or into the page as indicated. Figure (b) gives the change in the z components B, of the three fields with time t; the vertical axis scale is set by B, = 3.00 μT
and B-2.50B, What are the
(a) the magnitude and
(b) direction of the current induced in the wire?
For the magnetic fields:
(a) 53.8 A(b) The induced current will flow counterclockwise.How to determine magnitude and direction?From Faraday's law of electromagnetic induction, the emf induced in the wire is given by:
emf = -dΦ/dt
where Φ is the magnetic flux through the wire. The negative sign indicates that the induced emf opposes the change in magnetic flux.
The magnetic flux through each of the three regions can be calculated as follows:
Φ₁ = B₁WH/3
Φ₂ = B₂WH/3
Φ₃ = BWH/3
The total magnetic flux through the wire is:
Φ = Φ₁ + Φ₂ + Φ₃ = (B₁ + B₂ + B)WH/3
Taking the time derivative of the magnetic flux:
dΦ/dt = (B₁ + B₂ + B)(WH/3)(dB/dt)
Substituting the given values:
dΦ/dt = (3.00 μT + 2.50(3.00 μT))(0.23 m)(0.31 m)(1.00 m)/(3)(0.010 s) = 0.215 V
The induced emf is equal to the product of the current and the resistance of the wire:
emf = IR
Solving for I:
I = emf/R = 0.215 V / 4.00 mΩ = 53.8 A
The direction of the induced current can be determined using Lenz's law, which states that the direction of the induced current is such that it opposes the change in magnetic flux that produced it. In this case, the induced current will produce a magnetic field that opposes the change in the magnetic field through the wire.
As the magnetic field increases in the downward direction, the induced current will produce a magnetic field in the upward direction to oppose the increase. As the magnetic field decreases in the downward direction, the induced current will produce a magnetic field in the downward direction to oppose the decrease.
Therefore, the direction of the induced current will be counterclockwise.
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relationship beetween image distance,focal length ,power magnification, for both concave and convex lens.
Answer:
Object distance means what is the distance between pole and object. Image distance means when image is formed then the distance between pole and image is called image distance. Focal length is the distance between pole and the principal focus of the mirror.
A lens is a clear object, usually made of glass or plastic, which is used to refract, or bend light. Lenses can concentrate light rays (bring them together) or spread them out. Common examples of lenses include camera lenses, telescope lenses, eyeglasses, and magnifying glasses. Lenses are often double lenses, meaning they have two curved sides. A convex lens is rounded outward, while a concave lens curves inward. (A great way to remember this is that a concave lens creates an indent like a cave!)
The image distance can be calculated with the knowledge of object distance and focal length with the help of lens formula. In optics, the relationship between the distance of an image (i), the distance of an object (o), and the focal length (f) of the lens are given by the formula known as Lens formula. Lens formula is applicable for convex as well as concave lenses. These lenses have negligible thickness. It is an equation that relates the focal length, image distance, and object distance for a spherical mirror. It is given as,
1/i + 1/o = 1/f
i= distance of the image from the lens
o= distance of the object from the lens
f= focal length of the lens
Explanation:
Hope it is helpful....
Explanation:
image distance is the image between the pole and the image
A train moves from rest to a speed of 25 m/s in 30.0 seconds. What is its
acceleration? (Answer in number only and round to 2 places after the
decimal.) *
Your answer
Answer:
0.83 m/s
Explanation:
25-0÷30=0.83 m/s
Calculate the wavelength (in m) of a 589 Hz sound in air at room temperature and pressure where the velocity of sound is 344 m/s.
Answer:
just use the formula λ = v/f
Explanation:
v = velocity
f = frequency
90 V
R₁
60
R2
30
R3
30
Based on the circuit above, what would be the current through the R3 resistor?
In the parallel combination, the current through R3 is 3 A. In the series combination, the current through R3 is 0.75 A.
To determine the current through resistor R3 in both the parallel and series combinations, we need to apply Ohm's Law and the appropriate formulas for calculating total resistance and current in each configuration.
First, let's consider the parallel combination:
In a parallel combination, the voltage across each resistor is the same. Therefore, the voltage across R3 is also 90 V.
Using Ohm's Law (V = I × R), we can calculate the current flowing through R3 in the parallel combination:
I_parallel = V / R3
= 90 V / 30 Ω
= 3 A
So, in the parallel combination, the current through R3 is 3 A.
Now, let's consider the series combination:
In a series combination, the total resistance is the sum of the individual resistances:
R_total = R1 + R2 + R3
= 60 Ω + 30 Ω + 30 Ω
= 120 Ω
To find the current through the series combination, we can use Ohm's Law:
I_series = V / R_total
= 90 V / 120 Ω
= 0.75 A
Therefore, in the series combination, the current through R3 is 0.75 A.
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Note the complete questions is User
90 V R₁=60 R2= 30, R3 = 30
Based on the circuit above, what would be the current through the R3 resistor in parallel and in series combinantion.
Many curves have banked turns, which allow the cars to travel faster around the curves than if the road were flat. Acutally, cars could also make turns on these banked curves if there were no friction at all. Explain this statement using the free-body diagram shown in the figure.
Answer:
the normal force that is perpendicular to the surface has a component towards the center of the curve.
Explanation:
When curves with superelevation or inclination, the normal force that is perpendicular to the surface has a component towards the center of the curve. This component is what maintains the vehicle and gives it centripetal acceleration.
Consequently, the vehicle does not need the friction force since it does not have a tendency to slide and this is zero.
A particle of mass 2unit moves along space curve defined by ~r(t) = (4t 2 − t 3 )ˆi − 5tˆj + (t 4 − 2)ˆk. Find the force acting on it at any time to work out
The force acting on the particle at t = 1 s is 24.4 N.
Mass of the particle, m = 2 units
Distance of the curve, r(t) = (4t²- t³)i - 5tj + (t⁴- 2)k
The velocity of the particle,
v = d[r(t)]/dt = (8t - 3t²)i - 5j + 4t³k
The acceleration of the particle,
a = d²[r(t)]/dt² = (8 - 6t)i + 12t²k
Let the time for which the force is acting be 1 second.
Therefore, acceleration at t = 1 is,
a₁ = 2i + 12k
Hence, the magnitude of acceleration,
|a₁| = √(2²+ 12²)
|a₁| = √148
|a₁| = 12.2 unit/s²
Therefore, the force acting on the particle at t = 1 s is,
F₁ = m x |a₁|
F₁ = 2 x 12.2
F₁ = 24.4 N
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An object with a kinetic energy of 250j has a mass of 32 kg what is the velocity of the object?
Taking into account the definition of kinetic energy, the velocity of the object with a kinetic energy of 250 J and a mass of 32 kg is 3.95 m/s².
Deinition of Kinetic energyKinetic energy is the energy possessed by a body or system due to its movement.
Kinetic energy is defined as the amount of work necessary to accelerate a body of a certain mass and in a position of rest, until it reaches a certain speed. Once the final speed is reached, the amount of kinetic energy accumulated will remain constant, that is, it will not vary, unless another force acts on the body again.
Kinetic energy is represented by the following expression:
Ec = 1/2×m×v²
Where:
Ec is kinetic energy, which is measured in Joules (J).m is mass measured in kilograms (kg).v is velocity measured in meters over seconds (m/s).Velocity of the objectIn this case, you know:
Ec= 250 Jm= 32 kgv= ?Replacing in the definition of kinetic energy:
250 J = 1/2× 32 kg×v²
Solving:
250 J÷ (1/2× 32 kg) = v²
15.625 J÷kg = v²
√15.625 J÷kg = v
3.95 m/s² = v
Finally, the velocity of the object is 3.95 m/s².
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Classify the different devices as to first-, second-, or third-class levers.%0D%0A%0D%0A %0D%0A broom
According to the question, the different devices as to broom is a first-class lever.
What is broom?Broom is an implement used for sweeping. It consists of a set of bristles attached to a long handle. Brooms have been used for centuries to keep floors and other surfaces clean. The bristles are usually made from plant fibers or plastic. They are also sometimes made from metal or wire. Brooms can be used to sweep up dirt and dust, collect small particles, and even push larger items. They are perfect for quick cleanups and can be used on almost any type of floor or surface. They are also great for removing cobwebs and other debris from corners and other hard-to-reach places. Brooms are a convenient and easy-to-use tool that can help keep your home or workspace clean.
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*69. ssm A 1.0 x 10-kg spider is hanging vertically by a thread that
has a Young's modulus of 4.5 X 10 N/m² and a radius of 13 x 10 m.
Suppose that a 95-kg person is hanging vertically on an aluminum wire.
What is the radius of the wire that would exhibit the same strain as
the spider's thread, when the thread is stressed by the full weight of the
spider?
The radius of the wire that would exhibit some strain the same strain as a spider is 0.06m.
How to calculate the radius?The strain in a wire is given by the change in length divided by the original length, and is equal to the force applied divided by the cross-sectional area times the Young's modulus.
The force applied to the spider's thread is the weight of the spider, which is 1.0 x 10⁻³ kg x 9.8 m/s² = 9.8 x 10⁻³N.
The original length of the spider's thread is L = h, where h is the height of the spider.
The change in length is given by ΔL = FL/AY, where F is the force applied, L is the original length, A is the cross-sectional area, and Y is the Young's modulus.
Solving for the cross-sectional area, A = FL/ΔL = FL/ (FY/Y) = FLY/F = LY/F = πr²
We can now substitute the known values into the equation and solve for the radius, r:
πr² = LY/F = hY/F = 4.5 x 10 N/m² x (13 x 10⁻⁶ m) / (9.8 x 10⁻³ N)
r = sqrt(hY/Fπ) = sqrt(4.5 x 10 N/m² x (13 x 10⁻⁶ m) / (9.8 x 10⁻³ Nπ))
The radius of the aluminum wire that would exhibit the same strain as the spider's thread is the same as the calculated radius, 0.06m.
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why pet cats are not called Panthera Cantus.
Panthera is a genus within the family Felidae that was named and described by Lorenz Oken in 1816 who placed all the spotted cats in this group.
HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?
Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.
To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.
In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.
To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.
Total cost covered by the five friends = Total cost - Cost of one person's meal
= (£12 x 6) - £12
= £72 - £12
= £60
Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).
Amount each friend needs to pay = Total cost covered by the five friends / Number of friends
= £60 / 5
= £12
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how can heat be transferred from one object to another
Answer: Hope this helps!!!!
Explanation:
What could we call the
grocery store?
A. Linear motion
B. Reference point
C. Rotary
Reference point
Explanation:
I am not sure
Using a light microscope, a student identified the following characteristics of four organisms found in a sample of pond water. Based on the observations of the student,
which organisms most likely belong to the taxonomic group for bacteria?
Pond-Water Organisms
Organism 1 Single-celled, nucleus, large vacuole
Organism 2 Single-celled, no nucleus, cell wall
Organism 3 Single-celled, no nucleus
Organism 4 Single-celled, nucleus
Organism 1 and 4
Organism 1 and 2
Organism 3 and 4
Organism 2 and 3
Answer:
Organisms 2 and 3
Explanation:
A ranger in a national park is driving at 15.0 m/s when a deer jumps into the road 60 m ahead of the vehicle. After a reaction time, t, the ranger applies the brakes to produce an acceleration of a = -3.00 m/s2. What is the maximum reaction time allowed if she is to avoid hitting the deer?
Answer:
t = 5 s
Explanation:
In uniform rectilinear movement, the equation for final speed is:
vf = v₀ + a*t
In this case we need that the car stops just before 60 m after applied the brakes, then
vf = v₀ - a*t
vf = final speed = 0
v₀ = initial speed = 15 m/s
And negative acceleration is 3 m/s²
0 = 15 (m/s) - 3 ( m/s²)*t
t = 15 / 3 (m/s /m/s²)
t = 5 s
The point is that with that value ranger will hit the deer so in order to not to hit the deer that time should be smaller than 5 seconds
Rock X is released from rest at the top of a cliff is on earth. A short time later, Rock y is released from rest from the same point as rock X. Both rocks fall for several seconds before landing on the ground directly below the cliff. Frictional forces are considered to be negligible.
Which of the following graph correctly shows the vertical velocity of rock X as a function of time? Take the positive direction to the upward.
The graph of the velocity and the time can be shown by option D.
What is the correct graph?We know that the movement of an object as it is falling under gravity would have a constant acceleration. The constant acceleration means that the velocity of the object is also held a constant.
We now have to look at the graphs as we have them here. The graph as it has been shown has the the velocity on the vertical axis and it has the time on the horizontal axis. The gradient of the slope is what we would refers to as the acceleration of the body.
We also need to recall that the acceleration has to be a constant since tje tow object would have to reach the ground at the same time if they are released from the same height at the same time.
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3. Observe: An organelle is a cell structure that performs a specific function. Observe the samples below under the highest magnification. Click the Show labels checkbox to label the organelles. List the organelles and approximate size of the cells in each sample.
Organelles are specialized structures within cells that perform specific functions, such as energy production, protein synthesis, and waste removal.
Some examples of organelles include mitochondria, which produce energy for the cell, and ribosomes, which are involved in protein synthesis.
The size of cells can vary widely depending on the organism and the type of cell. For example, human cells can range from 10 to 30 micrometers in diameter, while bacterial cells are typically much smaller, ranging from 1 to 5 micrometers in diameter.
In summary, organelles are specialized structures within cells that perform specific functions, and the size of cells can vary widely depending on the organism and the type of cell.
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Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.760 m2 , separated by a layer of air with a thickness of 1.65 cm . The temperature on one side of the window is 0.00 ∘C; the temperature on the other side is 23.0 ∘C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.65 cm of air with a temperature difference of 23.0 ∘C . (The exact result for the complete window is 24.4 J/s .)
The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.
First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.
Next, we calculate the effective thermal conductivity of the air layer as:
k_eff = (k_air * L_air) / (L_air + k_glass)
Substituting the given values, we have:
k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air
Now, we can calculate the heat flow per second through the air layer using the formula:
Q = (k_eff * A * ΔT) / L_air
Substituting the given values, we get:
Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s
Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
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Which statement describes a situation with a displacement of zero check all tha apply
Why do charged particles interact with each other?(1 point)
because they are small
because they are small
because they are in the same molecule
because they are in the same molecule
because of their electric and magnetic fields
because of their electric and magnetic fields
because they have opposite charges
Answer:
because they have opposite charges
Explanation:
If you're talking about magnetism and electricity, the laws are that like charges attact and and unlike charges repel.
Charged particles interact with each other because they have opposite charges.
How charged particles interact with each other?When charged particles are close to each other, their electric fields interact. So particles with opposite charges attract each other whereas particles with similar charges repel each other.
So we can conclude that Charged particles interact with each other because they have opposite charges.
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8. Two resistors (110 Ω, 115 Ω) are connected in parallel with a 220-V supply. What is the total voltage?A. 55 V B. 110 V C. 220 V D. 330 V
ANSWER
\(C.\text{ }220V\)EXPLANATION
We want to identify the total voltage for the resistors connected in parallel.
When resistors are connected in parallel, they have the same entry and exit points or junctions. This implies that each resistor has the same voltage as the voltage of the source applied to it.
In other words, the total voltage is:
\(220V\)The correct answer is option C.