A cube of wood whose edge is 12 mm is floating in a liquid in a glass with one of its faces parallel to the liquid surface. The density of wood is 835 kg/m^3, that of liquid is 1296 kg/m^3. How far (h) below the liquid surface is the bottom face of the cube? Answer in units of mmA light oil is gently poured onto the immiscible liquid surface to form a 3.4 mm thick layer above the liquid. The density of the oil is 606 kg/m^3. When the wood cube attains hydrostatic equilibrium again, what will be the distance from the top of the liquid to the bottom face of the cube? Answer in units of mmAdditional light oil is poured onto the liquid surface until the top surface of the oil coincides with the top surface of the wood cube( in hydrostatice equilibrium). How thick is the whole layerr of the light oil? answer in units of mm.

Answer:

Mercury is the only one in liquid state at room temperature

Answer:

Nonliving things are composed of pure substances, living things are made of more complex units.

Explanation:

Is this what you are asking?

Explanation:

the tune of neptune is better thatbany other tune

hope it helps

Answer:

v_y = v_{oy} - g t

where the upward direction is positive, so the arrow represents this speed (blue) must decrease, reach zero and grow in a negative direction as time progresses

Explanation:

In this exercise you are asked to observe the change in velocity in a projectile launch.

If we assume that the friction force is small, the velocity in the x-axis must be constant

         vₓ = v₀ₓ

Therefore, the arrow (red) that represents this movement must not change in magnitude.

In the direction of the y axis, the acceleration of gravity is acting, so the magnitude of the velocity in this axis changes

         v_y = v_{oy} - g t

where the upward direction is positive, so the arrow represents this speed (blue) must decrease, reach zero and grow in a negative direction as time progresses

Two weeks  ago I would have said flying cars were still firmly in the realm of techno-utopian fantasy, as they have been for decades. Now I’m not quite so sure.

In the coming few years nearly 20 small airborne vehicles are supposedly hitting the market (see table below). Some are drone-like, with anywhere from four to 18 rotors keeping them aloft. Most are fixed-wing craft with propellers that point upwards for vertical takeoff and landing (VTOL), and tilt forward for flight.

Answer:

if people somehow try puting airplane parts into cars than they wud use the same ways to fly etc.

Explanation:

Answer:

Invasive species alter and degrade the environment, and have a negative effect on both native species and the people who live and work there. The impacts of invasive species include: Reduced biodiversity. Decreased availability and quality of key natural resources.

Explanation:

Hope this helps!

The mass of air is 58.110kg for a tank containing 2 m³ of air at -93°C and a gauge pressure of 1.4 MPa.

The ideal gas law equation is given below:

PV = nRT

where P is the absolute pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the absolute temperature.

Given: the volume of the tank, V = 2 m³

temperature of the air in the tank, T = -93°C

T = 273 - 93 K

T = 180K

Gauge pressure, P1 =  1.4 MPa.

Atmospheric pressure, P2 =  1 atm

1 atm =  101.325 kPa

P2 = 0.101 MPa

total pressure P = P1 + P2

P =  1.4 +  0.101

P = 1.501 MPa

Using the ideal gas equation,

PV = nRT

n = PV/RT

n =  1.501 MPa × 2 / 8.314 × 180

n = 2005.9 mol

mass of air = n × molar mass of air

mass of air = 2005.9 ×  28.97 g/mol

mass of air = 58.110 kg

Therefore, the mass of air is 58.110kg.

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Answer:

22425 J

Explanation:

From the question,

Applying

Q = cm(t₂-t₁).................. Equation 1

Where Q = Thermal Energy, c = specific heat capacity of aluminium, m = mass of aluminium, t₂ = Final Temperature, t₁ = Initial Temperature.

Given: c = 897 J/kg.K, m = 1.0 kg, t₁ = 50 °C, t₂ = 25 °C (The final temperature is reduced by half)

Substitute these values into equation 1

Q = 897×1×(25-50)

Q = 897×(-25)

Q = -22425 J

Hence the thermal energy lost by the aluminium is 22425 J

When a problem's variables further depend on other variables like time, related rates are used.

The Equation of Ohm's Law: V = IR, where V is the voltage that is applied across the conductor, I is the current that is passing through the conductor, and R is the conductor's resistance to the current flow.

The chain rule can be used to relate the rate of change of z with respect to t to the rates of x and y with respect to t when Z=f(x, y) and the variables x and y themselves depend on the variable t.

When all other rates and variables are known, we can use these relations to determine the rate of any one variable.

Take note that when the variable z changes with respect to t, we get dz/dt0, and when z changes with respect to t, we get dz/dt>0.

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Overcurrent refers to a sudden and rapid increase in current over a short period of time (also known as a short circuit or ground fault) (fractions of a second).

Fuse or circuit breakers are used to safeguard equipment and circuits from overcurrent conditions.

The current value is much higher than the nominal line current and can range from six times to hundreds of times higher than the typical rated current value.

Thermal energy: High current levels generate a lot of heat, which can harm cables and equipment. I2t (current squared times time) can be used to express thermal energy;

Mechanical forces: Busbars and other equipment may become warped or experience other issues due to the high-fault currents' ability to produce strong magnetic fields.

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The rating of the transformers primary and secondary currents will be 360.8A and 180.4A.

From the information given, the rating of the transformer bank is given as 300kVA. The full load primary current will be:

✓3 × V × I = 300 × 10³

✓3 × 480 × I = 300 × 10³

I = 360.8A

Also, the secondary load current will be calculated thus:

Transformation ratio = 240/480 = 0.5

Load current = 360.8 × 0.5

= 180.4 A

In conclusion, primary and secondary currents will be 360.8A and 180.4A.

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Answer:

Option B

Explanation:

As we know phase difference is equal to

\(\psi = \frac{2\pi }{\lambda} * \Delta\) ----Eq (1)

where

\(\Delta\) is the physical difference between two points = 0.025 m

\(\lambda\) is equal to \(\frac{v}{f}\)

\(\lambda = \frac{20}{100} = 0.2\)

Substituting the given values in above equation, we get -

\(\psi\) =

\(\frac{2\pi }{0.2} *0.025\\\frac{\pi }{4}\)

Hence, option B is correct

Answer:

Initial velocity (u) = 40 m/s

Distance travel in last 5 seconds = 100 m

Explanation:

Given:

Acceleration (a) = 8 m/s²

Final velocity (v) = 0 m/s

Find;

1] Initial velocity before 5 sec

2] Distance travel in last 5 seconds

Computation:

1] Initial velocity before 5 sec

v = u + at

0 = u + (-8)(5)

u - 40 = 0

Initial velocity (u) = 40 m/s

2] Distance travel in last 5 seconds

s = ut + (1/2)(a)(t²)

s = (40)(5) + (1/2)(-8)(5²)

s = 200 - 100

Distance travel in last 5 seconds = 100 m

Answer:

a = 5m/s²

Explanation:

a = (v - u)/t

a = (20 - 5)/3

a = 15/3

a = 5m/s²

pls give brainliest

Answer:

40.6°

Explanation:

The angle of refraction, when light passes from air into water at an angle of 60° from the normal, is 40.6°

It states that the ratio of sine of angle of incidence and angle of refraction is equal to the refractive index of second medium to the first medium.

sini/sinr =n₂ / n₁

Given, the light passes from air into water at an angle of 60° from the normal, the angle of incidence i = 60°, refractive index of air n₁ =1, refractive index of water n₂ = 1.333, then the angle of refraction is

sinr = sini x (n₁/n₂)

Plug the values, we get

sinr = sin60 x (1/1.333)

sinr = 40.6°

The angle of refraction is less than angle of incidence due to refraction.

Thus, the angle of refraction is 40.6°

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Explanation:

Hydraulic systems use the pump to push hydraulic fluid through the system to create fluid power. The fluid passes through the valves and flows to the cylinder where the hydraulic energy converts back into mechanical energy. The valves help to direct the flow of the liquid and relieve pressure when needed

Energy is defined in science as the ability to move matter or change matter in some other way.

The maximum deflection of the spring k2 is approximately 0.31 m.

The spring constant, k, is a measure of the spring's stiffness. It varies depending on the spring and material. The greater the spring constant, the stiffer the spring and more difficult to stretch.

To solve this problem, we can use conservation of energy and Hooke's law.

1/2 k1 x\(1^2\) = 1/2 m \(v^2\)

v = \((2 k1 x1 / m)^{0.5\) = \((2 x 2.0 N/m x 0.050 m / 0.2 kg)^{0.5\) ≈ 0.5 m/s

1/2 m \(v^2\) = 1/2 k2 \(x^2\)

x = \((m v^2/ k2)^{0.5\) =\((0.2 kg x (0.5 m/s)^2 / 1.1 N/m)^{0.5\) ≈ 0.31 m

Therefore, the maximum deflection of the spring k2 is approximately 0.31 m.

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Given that the direction sailboat is north and the distance traveled is d = 10 km

The direction of the wind is southeast and the force is

The sailboat travels the distance in time, t = 1 h

We have to find the work done by the wind and wind's power.

The diagram is shown below

The work done by the wind will be

The power of the wind will be

The smallest radius of an unbanked track around which a bicyclist can travel with a speed of 29km/h is 20.66m.

The maximum velocity with which we can travel on a unbanked road is given by,

V = √(urg)

Where you is the coefficient of friction,

R is the radius of the track,

g is the acceleration  due to gravity.

Here it is given that the bicyclist  travel with the speed of 29km/h and the coefficient of friction between the tyre and the track is 0.32.

Speed = 29km/h = 8.05 m/s.

So, putting the values, we get,

(8.05)² = r(9.8)(0.32)

r = 20.66m.

So, the smallest radius of an unbaked tract is 20.66 m.

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The atmosphere of the (b) Earth is primary, as opposed to secondary, in origin.

The Earth's atmosphere is predominantly composed of nitrogen, oxygen, and trace amounts of other gases. It has been formed and modified over billions of years through various processes, including outgassing from volcanic activity, chemical reactions involving elements present during the planet's formation, and biological activity.

On the other hand, the atmospheres of Venus, Saturn's moon Titan, Saturn, and Mars are considered secondary in origin. These bodies have atmospheres that have been significantly influenced by processes such as volcanic outgassing, atmospheric escape, and interaction with solar radiation and particles.

Their atmospheres may contain different compositions and properties compared to the Earth's atmosphere. Therefore, the correct answer is (b) Earth.

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Newton's law of cooling states that the rate at which the temperature of an object changes is directly proportional to the difference between its temperature and the ambient temperature. Mathematically, this law can be expressed as the following differential equation:

dT/dt + k(T - Ta) = 0

In this equation, dT/dt represents the rate of change of temperature with respect to time, T represents the temperature of the object, Ta represents the ambient temperature, and k is the cooling constant.

The negative sign indicates that the temperature tends to decrease if the object's temperature is higher than the ambient temperature.

This differential equation describes the relationship between the rate of change of temperature and the temperature difference between the object and the environment.

The constant k determines the speed at which the temperature changes.

A larger value of k indicates faster cooling, while a smaller value implies slower cooling.

By solving this differential equation, we can analyze the behavior of the object's temperature over time and determine how it approaches the ambient temperature.

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The surface temperature of a red giant is around 3,000 Kelvin, which is much lower than the surface temperature of the sun, which is around 5,800 Kelvin.

Temperature is a physical quantity that describes how hot or cold something is. It is usually measured in degrees Celsius (°C), Fahrenheit (°F), or Kelvin (K). Temperature is an important factor in many scientific and biological processes, and can affect the rate of chemical reactions, the behavior of living organisms, and the density of air. Temperature is also used to describe the intensity of heat energy, which is measured in joules or calories.

A red giant is a luminous, cool star with a surface temperature lower than that of the sun. Typically, the surface temperature of a red giant is around 3,000 Kelvin, which is much lower than the surface temperature of the sun, which is around 5,800 Kelvin.

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density = mass/volume

density=16/8

Density=2g/cm^2

Answer:

two 5kg objects 2 meters apart✨

The position expectation value as a function of time is constant and is equal to L/3.

Given a particle in an infinite square well potential has an initial wave function Ψ (x, t = 0) = Ax (L - x).The time evolution of the state vector: The time evolution of the state vector is given by Ψ(x,t) = ΣC_nΨ_n (x) e^(-iE_n t/h).The expectation value of the position as a function of time:The expectation value of the position as a function of time is given by the formula given below:x = Σa_n^2x_nΨ_n(x)Ψ_n*(x). Where,

a_n is the coefficient for each energy level.

Energy levels for infinite square well potential is given byE_n = n^2h^2 / 8mL^2Now, let us find the value of coefficient A. We know that a particle in a square well is normalized using the following formula:

∫Ψ^2 dx = 1. 0 to L∫Ax(L-x)^2dx = 1A(L^3)/3 = 1, A = √(3/L^3).

Now, the wavefunction for the particle is given by:

Ψ (x, t = 0)

= Ax (L - x)

= √(3/L^3) x (L - x).

Now, we can express this wave function in terms of the energy eigenfunctions as below:

Ψ (x, t = 0)

= Σ a_nΨ_n (x)

= Σa_n sin((nΠx)/L).

We can calculate the value of coefficient a_n by integrating the product of the initial wavefunction with the energy eigenfunctions, which is given by: a_n = 2/L ∫Ψ(x, t = 0) sin((nΠx)/L) dx.

Now, let us calculate the value of coefficient

a_n.a_n = 2/L ∫Ψ(x, t = 0) sin((nΠx)/L) dxa_n

= 2/L ∫√(3/L^3) x (L - x)sin((nΠx)/L) dxa_n = 2√3/L^2 ∫x(L - x)sin((nΠx)/L) dx.

From the previous results of integration,

a_n = (-1)^n+1 24√3/nΠ^3

a_n = (-1)^n+1 24√3/nΠ^3

Ψ(x,t) = ∑ a_nΨ_n(x) exp(-iE_n t/ℏ). Where E_n = n²h²π² / 2mL².

Substituting the values of a_n in the above formula, Ψ(x,t) = Σ(-1)^n+1 24√3/nΠ^3 sin(nΠx/L) exp(-in²π²h²t/2mL²ℏ²). Expectation value of the position as a function of time: The expectation value of the position is given by the formula, x = Σa_n²x_n. Where x_n is the position of nth energy level.

So, x_n = L/nSo,x = L∑a_n²/n From the previous results of coefficient, Σa_n²/n = 1/3. Now, x = L/3. Hence the position expectation value as a function of time is constant and is equal to L/3.

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the resistance presented to the battery was highest in circuit 8, where the fixed resistor added to the overall resistance of the circuit. In contrast, in circuit 7, the resistance was mainly controlled by the rheostat, and the resistance of bulb H was relatively small compared to the rheostat.

In circuit 7, the resistance presented to the battery is the sum of the resistance of the rheostat and the resistance of bulb H. In circuit 8, the resistance presented to the battery is the sum of the resistance of the fixed resistor and the resistance of bulb H.

Since we had to increase the resistance of the rheostat in circuit 7 to achieve a current of 30 mA, it suggests that the total resistance in circuit 7 was lower than in circuit 8. This is because increasing resistance in the circuit would decrease the current flow, so if we had to increase resistance in circuit 7 to achieve the same current as in circuit 8, it means that circuit 7 had less resistance to begin with.

Therefore, the resistance presented to the battery was highest in circuit 8, where the fixed resistor added to the overall resistance of the circuit. In contrast, in circuit 7, the resistance was mainly controlled by the rheostat, and the resistance of bulb H was relatively small compared to the rheostat.
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Answer: A.

current (thumb) to magnetic field (fingers)

Answer:

A. current (thumb) to magnetic field (fingers)

Explanation:

According to the Right-Hand Thumb rule, if we are holding a current- carrying straight conductor in our right hand such that the thumb points toward the direction of current, then the fingers will wrap around the conductor in the direction of the field lines of the magnetic field.

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The mass of the Bugatti Veyron is approximately 1496 kilograms. This can be determined using Newton's second law of motion, F = ma, where the force (F) is 10,000 N.

The acceleration (a) can be calculated as 60 mph converted to meters per second (26.82 m/s) divided by the time (t) of 2.5 seconds. Therefore, the mass (m) is F/a = 10,000 N / 26.82 m/s = approximately 373 kg. However, this value is only the mass of the force used to move the car. Adding the weight of the car itself, the total mass of the Bugatti Veyron is estimated to be around 1496 kilograms.

Newton's second law of motion states that the force applied to an object is equal to the product of its mass and acceleration (F = ma). In this case, the force used to move the car is given as 10,000 N. To determine the mass, we need to calculate the acceleration first. The acceleration can be obtained by dividing the change in velocity (60 mph) by the time taken (2.5 seconds). After converting the velocity to meters per second (26.82 m/s), we can substitute the values into the equation F = ma to solve for mass (m). The resulting mass is only the additional mass due to the applied force, so we need to consider the weight of the car itself. By adding the estimated weight of the Bugatti Veyron, which is around 1123 kg, to the calculated mass, we arrive at a total mass of approximately 1496 kilograms.

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