A crocus finish on the blade of a razor is also known as:

Answer:

Hi, there your answer is hydraulics

Explanation:

functionality required of the system, Quality characteristics that aren't useful, like performance or security, features that cater to consumer demands For the system to function, there are network, hardware, and software requirements.

The minimum and/or maximum hardware and software criteria that a system or application must meet in order to operate effectively are known as system requirements.

System requirements are a list of the features that a system must have in order to fulfill the needs of the customer. [1] System requirements are a broad and specific topic that can be applied to many different objects.

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Normal and shear strains describe an object’s deformations. This is a true statement.
Normal and shear strains describe an object’s deformations.A strain occurs when a solid material is subjected to a force that results in a change in its size or shape. In other words, deformation is the term used to describe a material's alteration in shape and size as a result of a stress or load being applied to it. Normal and shear strains are two types of deformations that occur in a material.
Normal strain is a measure of how much a solid's length changes due to a force acting on it perpendicular to its cross-sectional area. Strain is the ratio of the change in length to the original length of the material, and it is typically represented by the Greek letter epsilon. The normal strain can be either positive (tensile) or negative (compressive), depending on whether the material is being stretched or compressed.
Shear strain, on the other hand, is a measure of how much a solid's shape changes due to a force acting parallel to its cross-sectional area. The shear strain is defined as the change in angle between two originally perpendicular lines in the material, divided by the angle between them before the stress was applied. Shear strain is typically represented by the Greek letter gamma.
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Answer:

1211 N.

Explanation:

Okay, we are given the following data or parameters or information in the question above;

=> "aluminum (E = 70 GPa) tube of length 8-m.

=> "The aluminum is used as a simply supported column carrying a 1.2 kN axial load"

The axial load to provide a factor of safety of 2 against buckling =[ (22/7)^2 × 224348 × 1000 × 70] ÷ (8 × 1000)^2 × 2.

The axial load to provide a factor of safety of 2 against buckling = 1211 N.

The correct answer is option 1011 0010 1100.To convert 0B2C (base 16) to binary.

We need to perform the following steps:Step 1: Convert each hexadecimal digit to its binary equivalent Write the binary equivalents of the four hexadecimal digits together to form the binary equivalent of the whole number.

0B2C can be split into four hexadecimal digits as follows:0 B 2 CThe binary equivalents of these hexadecimal digits are\(:0B2C (base 16) = 0000 1011 0010 1100\) (base 2) option C) 1011 0010 1100 is the correct answer.

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The required MTBF (in hours) for the new generator (assuming exponential and 8760 hours/year) will be 8760 hours.

7. Total test hours should be allocated for the new generator (assuming 1 failure is allowed) at 50% confidence should be 688 hours.

8. The demonstrated MTBF (ΘL) at 50% confidence if no failures were observed will be 43,800 hours. Yes, the requirement was demonstrated.

9. The static reliability of the system for this situation can be determined by calculating the probability of no failure. The probability of no failure will be 0.85 * 0.95 * 0.98 * 0.99 = 0.764. Therefore, the static reliability of the system for this situation will be 0.764.10.

Probability of the top-level event (system failure) can be calculated by adding the probabilities of all the paths leading to the top-level event. The probability of the top-level event (system failure) will be:

P(system failure) = P(Gen A failure) + P(Gen B failure) + P(Gen C failure) + P(Tie Bus failure) * P(No load shedding) + P(Tie Bus failure) * P(Load shedding)

P(Gen A failure) = 1 - e^(-8760/30000) = 0.215

P(Gen B failure) = 0.85 * (1 - e^(-8760/18000)) = 0.37

P(Gen C failure) = 0.95 * (1 - e^(-8760/30000)) = 0.276

P(Tie Bus failure) = 0.98

P(No load shedding) = 0.99

P(Load shedding) = 0.01

P(system failure) = 0.215 + 0.37 + 0.276 + 0.98 * 0.99 + 0.98 * 0.01 * (1 - P(Gen A failure)) * (1 - P(Gen B failure)) * (1 - P(Gen C failure)) * P(Tie Bus failure)P(system failure) = 0.215 + 0.37 + 0.276 + 0.98 * 0.99 + 0.98 * 0.01 * (1 - 0.215) * (1 - 0.37) * (1 - 0.276) * 0.98P(system failure) = 0.9644

Therefore, the probability of the top-level event (system failure) will be 0.9644.

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The following two file transfer protocols use SSH to provide confidentiality during the transfer: SFTPSCP

Explanation: SFTP and SCP are the two file transfer protocols that use SSH to provide confidentiality during the transfer. The Secure Shell (SSH) protocol is a secure communication protocol that can be used to communicate with networked devices or servers. SFTP stands for Secure File Transfer Protocol, whereas SCP stands for Secure Copy Protocol. Both of these protocols use SSH as their underlying protocol to provide secure and confidential transfer of files between servers or devices. HTTPS stands for HyperText Transfer Protocol Secure.

It is a protocol that uses encryption to provide confidentiality during data transfer. HTTPS is used to secure web browsing, and it is a popular protocol used to secure websites that require authentication or that deal with sensitive information. FTP, FTPS, and HTTP are file transfer protocols that don't use SSH to provide confidentiality during the transfer. FTP stands for File Transfer Protocol, while FTPS stands for File Transfer Protocol Secure. HTTP stands for Hypertext Transfer Protocol.

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Answer:

The average thickness of the blubber is 0.077 m

Explanation:

Here, we want to calculate the average thickness of the Walrus blubber.

We employ a mathematical formula to calculate this;

The rate of heat transfer(H) through the Walrus blubber = dQ/dT = KA(T2-T1)/L

Where dQ is the change in amount of heat transferred

dT is the temperature gradient(change in temperature) i.e T2-T1

dQ/dT = 220 W

K is the conductivity of fatty tissue without blood = 0.20 (J/s · m · °C)

A is the surface area which is 2.23 m^2

T2 = 37.0 °C

T1 = -1.0 °C

L is ?

We can rewrite the equation in terms of L as follows;

L × dQ/dT = KA(T2-T1)

L = KA(T2-T1) ÷ dQ/dT

Imputing the values listed above;

L = (0.2 * 2.23)(37-(-1))/220

L = (0.2 * 2.23 * 38)/220 = 16.948/220 = 0.077 m

According to the Tuckman model, the stage they are in is norming stage. The correct option is b.

Bruce Tuckman, a psychologist, originally put forth Tuckman's idea in 1965. Teams would go through five stages of development, according to the document: forming, storming, norming, performing, and adjourning.

The norming stage is the third one in team development after forming and storming stages. Members become more focused on the team's objectives and exhibit a rise in productivity throughout the Norming stage, both in their individual and group work.

Therefore, the correct option is b-norming.

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The question is incomplete. Your most probably complete question is given below:

a-storming

b-norming

c-swarming

d-performing

Answer:

  48.00 microamps

Explanation:

The base voltage is limited by the zener to 5.5 V. If we assume the B-E voltage drop is 0.7 V, then the voltage across RE is 5.5-0.7 = 4.8 volts. That means the emitter current is 4.8/2.0k = 2.4 mA.

The base current is that amount divided by (1+β), so is 2.4 mA/(1+49) = 48 μA.

Answer:

I am in Eight Grade

Explanation:

The unknown capacitor in arm CD must have a value of 330 microfarads, and the unknown resistor must have a value of 100 kilo-ohms.

To solve the problem, use the following formula:
Cseries = C1 x C2 / (C1 + C2)

Where C1 is the value of the capacitor in arm AB (47 microfarads) and C2 is the value of the capacitor in arm BC (330 microfarads).

Therefore, Cseries = 330 microfarads.

Also, the total resistance of arms CD is the sum of the resistance of the resistor (R) and the reciprocal of the capacitive reactance of the capacitor (1/Xc).

Using the following formula:
Rtotal = R + 1/Xc

Where Xc = 1/2πfC,

f is the frequency and C is the capacitance.

For this problem,

Xc = 1/2π(50)(330 x 10-6)

=> 100 kilo-ohm.

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The angular velocity of the carrier in a bevel gear differential used to drive the rear wheels in an automobile will be zero if both wheels rotate at the same speed.

This is because the carrier's purpose is to allow the wheels to rotate at different speeds (i.e. when turning), and therefore its angular velocity is directly related to the difference in speed between the two wheels. It is important to note that while speed refers to the rate at which an object travels, velocity refers to the rate at which it travels in a specific direction.

Angular velocity is a measure of the rate at which an object rotates or spins around a central axis. It is expressed in units of radians per second and is used to describe the speed and direction of rotation. The angular velocity of an object can be calculated by dividing the angular displacement by the time taken to complete the rotation. It is a vector quantity, meaning it has both magnitude and direction. Angular velocity is an important concept in physics and is used to describe various phenomena, such as the rotation of celestial bodies, the motion of gears and wheels, and the movement of particles in a centrifuge. It is also used in engineering applications, such as in the design of turbines, engines, and other rotating machinery.

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Answer: To initialize an ArrayList called inventory that stores Car objects in Java, you can use the following code:

import java.util.ArrayList;

public class CarTracker

{

   public static void main(String[] args)

   {

       // Initialize your ArrayList here:

       ArrayList<Car> inventory = new ArrayList<>();

   }

}

The ArrayList is initialized using the ArrayList<Car> syntax, where Car is the type of objects that will be stored in the ArrayList. The ArrayList is then instantiated using the new ArrayList<>() syntax. You can then add Car objects to the ArrayList using the add method. For example, the following code adds a Car object with the name "Ford", model "Fiesta", and cost $15,000 to the inventory ArrayList:

// Add a Car object to the inventory ArrayList

Car car1 = new Car("Ford", "Fiesta", 15000);

inventory.add(car1);

You can add as many Car objects to the inventory ArrayList as you need. To retrieve a Car object from the ArrayList, you can use the get method and specify the index of the Car object you want to retrieve. For example, the following code retrieves the first Car object in the inventory ArrayList:

// Get the first Car object in the inventory ArrayList

Car car = inventory.get(0);

You can then access the fields of the Car object using the dot notation, as shown in the following code:

// Print the name, model, and cost of the Car object

System.out.println("Name: " + car.name);

System.out.println("Model: " + car.model);

System.out.println("Cost: $" + car.cost);

This code would output the name, model, and cost of the Car object.

The method of joints is a powerful tool for analyzing truss structures. It allows you to determine the forces in each member and ensure that the structure is in equilibrium. By following the steps outlined above, you can apply the method of joints to each letter/joint and solve for the unknown forces.

The method of joints is a popular technique used to analyze truss structures. It is based on the equilibrium of forces at each joint in the truss.

To apply the method of joints, you need to follow these steps:
1. Draw the free-body diagram of the entire truss structure.
2. Label each joint and assign unknown forces to each member.
3. Write the equations of equilibrium for each joint.
4. Solve the equations simultaneously to find the forces in each member.

For each letter/joint, you need to identify the forces acting on it. These forces can be tension or compression depending on whether the member is in tension or compression. You can use the method of joints to find the magnitude and direction of these forces.

For example, if you have a truss structure with joint A, you can apply the method of joints to find the forces in the members connected to joint A. You would need to identify the forces acting on joint A and write the equations of equilibrium for that joint. Then, you can solve the equations to find the forces in each member connected to joint A.

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Explanation:

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The "Wheel of Quality" is a graphical representation that encapsulates the essential elements of contemporary quality management.

It encompasses various interconnected components that collectively contribute to achieving high-quality products or services. Here are eight examples of key elements commonly found in the "Wheel of Quality":Leadership: Effective leadership establishes a clear quality vision, sets quality objectives, and fosters a culture of continuous improvement. For instance, a CEO who promotes quality initiatives and supports employees in achieving quality goals.

Customer Focus: Placing the customer at the core of quality efforts involves understanding their needs, preferences, and expectations. For example, an online retailer conducting customer surveys to enhance the shopping experience.

Process Management: Efficiently managing processes is vital for maintaining quality standards. This entails analyzing and improving processes to minimize errors and waste. For instance, a software development company implementing agile methodologies for iterative improvement.

Employee Involvement: Engaging employees and empowering them to contribute to quality improvement fosters ownership and collaboration. For example, a healthcare organization encouraging frontline staff to participate in quality improvement projects.

Continuous Improvement: Emphasizing ongoing improvement enables organizations to adapt, innovate, and stay competitive. For instance, an automobile manufacturer conducting regular quality audits and implementing corrective actions.

Data-Driven Decision Making: Making informed decisions based on reliable data is crucial. Collecting and analyzing relevant data helps identify trends and measure performance. For example, a call center tracking key metrics like average handling time and customer satisfaction scores.

Supplier Relationships: Collaborating with suppliers ensures quality throughout the supply chain. Building strong relationships and monitoring supplier performance is essential. For instance, a food processing company conducting quality audits and setting stringent requirements for ingredient suppliers.

Innovation and Adaptation: Embracing innovation and adapting to market dynamics is vital for long-term success. Investing in research and development helps organizations stay competitive. For example, a software company continuously improving its products through innovation and updated features.

These examples illustrate how each element contributes to the overall quality management framework, fostering continuous improvement and customer satisfaction.

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Answer:

immediately

Explanation:

Answer:

\(V_2=46mL\)

Explanation:

From the question we are told that:

Pressure over Water \(P=698 Torr\)

Temperature   \(T= 30.1 \textdegree C\)

Pressure of Water   \(P(H2O) = 19.8 torr.\)

Volume of O2  \(O_2=56.3\)

Pressure of Dry O2  \(P_(0)=755torr\)

Generally the equation for Total Pressure is mathematically given by

\(P_t = P_O + P_H\)

Therefore

\(P_O=P_t-P_H\)

\(P_O=638-19.8\)

\(P_O=618.2torr\)

Generally the equation for Ideal gas is mathematically given by

\(P_1*V_1 = P_2*V_2\)

\(V_2=\frac{P_1*V_1}{P_2}\)

Therefore

\(V_2=\frac{ 618.2*56.3}{755}\)

\(V_2=46mL\)

Hence,The  volume would the dry O2 occupy at 755 torr

\(V_2=46mL\)

If diverse current-bearing conductors are integrated into a raceway, the ampacity of the conductors must be altered to accommodate the elevated amount of heat released due to their close contact.

The recalculation factor relies on the kind of raceway, the number of victuals, and the caliber of the victuals.

As an illustration, per the National Electrical Code (NEC), if five flow conductors inhabit a metal tube, the adjustment portion for 90°C rated cables is fifty percent. This implies that the ampacity of the lines ought to be multiplied by 0.5 or thinned out by half.

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Answer: B.Idle relearn

Explanation:

When replacing an intake manifold gasket due to a vacuum leak, using a scan tool for idle relearn is a crucial step to complete the job. The Option B.

The scan tool is used to reset the idle control system and allow the engine's computer to relearn the correct idle speed and air/fuel mixture. This is important because the replacement of the intake manifold gasket can affect the engine's idle characteristics.

By using the scan tool to perform an idle relearn procedure, the engine management system can recalibrate and optimize the idle control parameters, ensuring smooth and stable idle operation. This step helps to restore the engine's performance and maintain proper combustion efficiency after the intake manifold gasket replacement.

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To minimize the maximum absolute value of the bending moment in the beam, the counterweight should be positioned in such a way that it counteracts the effects of the distributed load on the beam.

This can be achieved by placing the counterweight at a location where the moment caused by the distributed load is maximum. The value of the counterweight can be determined by equating the moment due to the distributed load and the moment due to the counterweight. Mathematically, this can be represented as:
\(moment_{distributed load}\) = \(moment_{counterweight}\) Once you have calculated the value of the counterweight, the maximum absolute value of the bending moment (|M|max) can be determined by analyzing the beam's bending moment diagram and finding the point where the bending moment is minimum or maximum.
Please note that to provide a specific answer, more information about the beam, such as its length, material, and the magnitude of the distributed load, is required.

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Answer:

The angles are missing in the question.

The angles are :

45,     30,    60,     90,    -34,     -56,      20,     -42,  -65,    -15

P=10, P=5,  P=25, P=54, P=65, P=95, P=250, P=8, P=35, P=150

Explanation:

1. P = 10,   θ = 45°  rectangular coordinates

x = r cosθ  ,   y = r sinθ

So, rectangular form is x + iy

x = P cosθ = 10 cos 45°

  = 7.07

y =P sinθ = 10 sin 45°

  = 7.07

Therefore, rectangular form

x + iy = 7.07 + i (7.07)

2. P = 5 , θ = 30°

x = 5 cos  30° = 4.33

y = 5 sin  30° = 2.5

So, (x+iy) = 4.33 + i (2.5)

3. P = 25 , θ = 60°

x = 25 cos  60° = 12.5

y = 25 sin  60° = 21.65

So, (x+iy) = 12.5 + i (21.65)

4. P = 54 , θ = 90°

x = 54 cos  90° = 0

y = 54 sin  90° = 54

So, (x+iy) = 0+ i (54)

5. P = 65 , θ = -34°

x = 65 cos  (-34°) = 53.88

y = 65 sin  (-34°) = -36.34

So, (x+iy) = 53.88 - i (36.34)

6. P = 95 , θ = -56°

x = 95 cos  (-56)° = 53.12

y = 95 sin  (-56)° = -78.75

So, (x+iy) = 53.12 - i (78.75)

7. P = 250 , θ = 20°

x = 250 cos  20° = 234.92

y = 250 sin 20° = 85.5

So, (x+iy) = 234.92 + i (85.5)

8. P = 8 , θ = (-42)°

x = 8 cos  (-42)° = 5.94

y = 8 sin  (-42)° = -5.353

So, (x+iy) = 5.94 - i (5.353)

9. P = 35 , θ = (-65)°

x = 35 cos  (-65)° = 14.79

y = 35 sin  (-65)° = -31.72

So, (x+iy) = 14.79 - i (31.72)

10. P = 150 , θ = (-15)°

x = 150 cos  (-15)° = 144.88

y = 150 sin  (-15)° = -38.82

So, (x+iy) = 144.88 - i (38.82)

Answer:

a) the maximum tensile stress due to the weight of the wire is 1361.23 psi

b) the maximum load P that could be supported at the lower end of the wire is 624.83 lb

Explanation:

Given the data in the question;

Length of wire L = 400 ft = ( 400 × 12 )in = 4800 in

Diameter d = 3/16 in

Unit weight w = 490 pcf

First we determine the area of the wire;

A = π/4 × d²

we substitute

A = π/4 × (3/16)²

A = 0.0276 in²

Next we get the Volume

V = Area × Length of wire

we substitute

V = 0.0276 × 4800

V = 132.48 in³

Weight of the steel wire will be;

W = Unit weight × Volume

we substitute

W = 490 × ( 132.48 / 12³ )

W = 490 × 0.076666

W = 37.57 lb

a) the maximum tensile stress due to the weight of the wire;

σ\(_w\) = W / A

we substitute

σ\(_w\) = 37.57 / 0.0276

= 1361.23 psi

Therefore, the maximum tensile stress due to the weight of the wire is 1361.23 psi

b) the maximum load P that could be supported at the lower end of the wire. Allowable tensile stress is 24,000 psi

Maximum load P that the wire can safely support its lower end will be;

P = ( σ\(_{all\) - σ\(_w\) )A

we substitute

P = ( 24000 - 1361.23  )0.0276

P = 22638.77 × 0.0276

P = 624.83 lb

Therefore, the maximum load P that could be supported at the lower end of the wire is 624.83 lb

Answer:

This statement is False.

Explanation:

It doesn't matter how much batteries get stacked.

May I have Brainliest please? My next rank will be the highest one: A GENIUS! Please help me on this journey to become top of the ranks! I only need 6 more brainliest to become a genius! I would really appreciate it, and it would make my day! Thank you so much, and have a wonderful rest of your day!

Answer:

the correct answer is option B. W

Answer:

it is b and w

Explanation:

pls mark as brainlist

Answer:

\(C_v= 24.942\) J / mol K

Explanation:

Molar Heat Capacity

using the equipartition, the equation :

\($C_v=\frac{d}{2} R$\)

Here, \(C_v\) = molar heat capacity

          d = degree of freedom

          R = Universal gas constant

Degree of freedom, d is 6          

Universal gas constant, R = 8.317 J/ mol K

Therefore, the molar heat capacity is :

\($C_v=\frac{d}{2} R$\)

\($C_v=\frac{6}{2} \times 8.314$\)

\(C_v= 24.942\) J / mol K

A crawl space or underfloor space must contain C) a disconnecting means for HVAC equipment.

Major HVAC equipment includes heaters, air handling units, and chillers or air conditioners. The central HVAC system is located away from the central equipment room building and supplies conditioned air through the duct system.

The air conditioner circuit breaker (ACD) is located between the road center and the air conditioner. ACDs provide a visible disconnecting means when performing maintenance and are commonly referred to as circuit breakers, extractors, or air conditioning switches.

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