A crate is pulled with a force of 165 N at an angle 30°
northwest. What is the resultant horizontal force on the crate?
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The formula for the distance covered by a body moving with an initial velocity u and accelerating at a rate a for a time t is s = ut + ¹/₂at².

To derive the formula for the distance covered by a body moving with an initial velocity u and accelerating at a rate a for a time t, we can use the basic equations of motion.

The first equation of motion states that the final velocity v of a body after time t is given by:

v = u + at

where;

We can rearrange this equation to give:

at = v - u

The second equation of motion states that the distance s covered by a body in time t is given by:

s = ut + ¹/₂at²

Substituting for at from the first equation of motion, we get:

s = ut + ¹/₂(v - u)t

simplifying gives:

s = ut + ¹/₂vt - ¹/₂ut

s = ¹/₂(v + u)t

Substituting the expression for v from the first equation of motion, we have:

s = ¹/₂(u + at + u)t

simplifying gives:

s = ut + ¹/₂at²

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As a result, from the homes of the shoppers to the restaurant, the distance is 12 km, and the direction is 80° north.

As the name implies, questions based on direction and/or distance are also known as Direction and Distance questions. Candidates must calculate the distance traveled between the starting location and the final / end point based on the provided starting point and direction. The position of one point and person with regard to another point and person and the distance among them must be determined for the Direction & Distance reasoning part.

Declare the terms "right" and "left." Ask the kids to tell you what these terms imply or mean when they are translated, then write their answers on the board with arrows pointing in the appropriate directions. Show the class how to pronounce the words once their meanings are obvious. Relative terminology, such as up, down, in, out, left, right, forward, backward, or sideways, can be used to define direction. You can also depict direction using the four cardinal directions: north, south, east, & west.

7km = 30 Degree of NE

5km = 50 degree of N

Therefore distance = 7km+5km

=12km

thus, direction = 50+30

=80° N

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Answer:

0.882 m/s average velocity and 1.71 m/s average speed

Explanation:

The dog travels a total of 35 m west and 110 m east.

110-35 = 75 m east of the starting position. Since velocity is a vector you must consider its first and final position and not the total distance traveled.

75 m / 85 s = 0.882 m/s average velocity

Speed is not concerned with direction so we instead add the total distance traveled which is 35+110 = 145 m. We then perform the same operation as before and divide by the time it took to run this distance.

145 m / 85 s = 1.71 m/s average speed

Answer:

439.6 THz

Explanation:

The kinetic energy of the firework when it is launched is,

At the minimum height the potential energy of the firework is,

At the height the kinetic energy is converted into potential energy therefore, according to conservation of energy,

Plug in the known values,

Substituting values,

Therefore, the launch speed of the firework is 153.7 mph.

As the launch speed is approximately equal to 160 mph therefore, the firework can be launched safely with speed 160 mph.

Answer: Wet barometer - The tool works by measuring atmospheric pressure to predict incoming weather. Since the glass is only filled halfway with water, the other half is exposed to the atmosphere. When the outdoor atmospheric pressure rises, the pressure in the glass decreases, and causes the water to move down the spout.

Dry barometer - A Torricellian barometer (sometimes called a mercury barometer) is an inverted (upside-down) glass tube standing in a bath of mercury. Air pressure pushes down on the surface of the mercury, making some rise up the tube. The greater the air pressure, the higher the mercury rises.

I hope this helps!

The wet barometer can be used to measure the pressure of incoming weather where as dry barometer was used to measure the air pressure for sealed bellows.

Barometer

The instrument barometer can be used to measure the pressure in the atmosphere or the environment. Thus, this pressure can be also known to be Barometric pressure.

Wet barometer

A water barometer or a wet barometer is a device that are used measure barometric pressure. This device can be used with the force of gravity, combined with pressure in the air, to create a vacuum, to have a value of the pressure that can be described as with the barometric pressure. The procedure of the wet barometer can be, the glass is only filled halfway with water, the other half is exposed to the atmosphere. When the outdoor atmospheric pressure rises, the pressure in the glass decreases, and causes the water to move down the spout.

Dry barometer

A Dry barometer or a Torricellian barometer or a mercury barometer which can be the inverted glass tube standing in a bath of mercury not the water. Air pressure will pushes down on the surface of the mercury, and makes some rise up the tube. If we give more pressure on the barometer, the mercury will gets increased. Only by this way the value of pressure in the dry barometer can be determined.

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In general, option c - warming it up on the stove - is often an effective method to increase the reaction rate.

Increasing the temperature of a reaction generally leads to faster reaction rates. This is because higher temperatures provide more thermal energy to the reactant particles, causing them to move faster and collide more frequently. The increased collision frequency and energy lead to more successful collisions and a higher likelihood of effective molecular interactions, which speeds up the reaction. On the other hand, options a and b - putting it in the fridge where it is cold or covering it with a blanket to make it dark - are unlikely to have a significant effect on the reaction rate. While temperature can influence reaction rates, cooling the reaction or making it dark typically reduces the kinetic energy of the particles, resulting in slower reaction rates. Option d - there is nothing you can do to change the speed of the reaction - is not accurate. The reaction rate can be influenced by various factors such as temperature, concentration, catalysts, and surface area, among others. By manipulating these factors, it is often possible to control and change the speed of a reaction. Hence option c, is correct

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Stochastic impacts of radiation allude to those that happen arbitrarily and are not reliant upon the portion got. These impacts are related to the likelihood of events and incorporate disease and hereditary changes. Non-stochastic impacts, then again, have a limit, and their seriousness increments with expanding portions.

Models incorporate radiation consumption and intense radiation conditions. Understanding the qualification among stochastic and non-stochastic impacts of radiation is significant in fields like radiation security, atomic medication, and radiobiology.

It assists in setting radiation with dosing limits, creating well-being rules, and carrying out suitable radiation safeguarding measures. By separating these impacts, experts can evaluate and deal with the dangers related to openness to ionizing radiation all the more successfully.

This information guides choices in regard to radiation wellbeing conventions, word-related openness limits, and the improvement of radiation therapy systems in medication.

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The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;

Take moment about the joint to determine the magnitude of the force along part BC.

120 kN x 750 mm  =  F x 1000 mm

F = ( 120 kN x 750 mm ) / ( 1000 mm )

F = 90 kN

Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.

Stress in AB = 2 times stress in BC

P/A₁  = 2F/A₂

where;

A₁ =  πd²/4  =  π(50 x 10⁻³)²/4

A₁ = 1.96 x 10⁻⁵ m²

A₂ = πd²/4  =  π(75 x 10⁻³)²/4

A₂ = 4.42 x 10⁻³ m²

P/A₁ = 2F/A₂

P = (2F x A₁) / (A₂)

P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = 798.2 N

P = 0.798 kN

P ≈ 0.8 kN

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Answer:

Am doing well am fine thank you

Answer:

Mass = 56.83 Kg

Explanation:

\(PE = mgh\\9094 J = 16m*10 m/s^2*mass\\mass = \frac{PE}{g*h} \\mass = \frac{9094 J}{16*10} = 56.83 kg\)

No. The potential of a non-uniform charged sphere cannot be the same as that of a point charge.

The potential at any point in space is determined by the distribution of charge within the system, and a non-uniform charged sphere has a different charge distribution than a point charge.

A point charge has all of its charges concentrated at a single point, while a non-uniform charged sphere has charge distributed throughout its volume.

As a result, the electric field and potential will be different for these two systems, even if they have the same total charge. Therefore, the potential of a non-uniform charged sphere cannot be the same as that of a point charge.

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The magnitude of the magnetic force on a proton is 1.68 ✕ 10^−16 N, directed towards the negative y-direction. The magnitude of the magnetic force on an electron is also 1.68 ✕ 10^−16 N, but directed towards the positive y-direction.

Begin by using the formula for the magnetic force on a charged particle moving in a magnetic field:

F = q * v * B * sin(θ)

where F is the magnetic force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength, and θ is the angle between the velocity vector and the magnetic field vector.

For a proton, the charge is +e, where e is the elementary charge (1.6 ✕ 10^−19 C). The velocity of the proton is given as 3.99 ✕ 10^5 m/s in the positive x-direction. The magnetic field strength is 2.93 ✕ 10^−8 T in the positive z-direction.

The angle θ between the velocity vector and the magnetic field vector is 90 degrees since the velocity is perpendicular to the magnetic field.

Substituting the values into the formula, we get:

F_proton = (+e) * (3.99 ✕ 10^5 m/s) * (2.93 ✕ 10^−8 T) * sin(90°)

F_proton ≈ 1.68 ✕ 10^−16 N

Since the proton has a positive charge, the magnetic force is directed opposite to the direction of electron flow, which is in the negative y-direction.

Repeat the steps for an electron, but note that the charge is -e. The direction of the force on an electron will be opposite to that of a proton.

F_electron = (-e) * (3.99 ✕ 10^5 m/s) * (2.93 ✕ 10^−8 T) * sin(90°)

F_electron ≈ -1.68 ✕ 10^−16 N

The force on an electron is also 1.68 ✕ 10^−16 N, but directed towards the positive y-direction.

Remember to consider the proper units and take into account the directions of charge, velocity, and magnetic field when calculating the magnetic force on a charged particle.

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The top surface moves relative to the bottom surface by 1.167 x 10⁻⁶ m.

The distance the top surface move relative to the bottom surface is calculated as follows;

shear strain = F/(αx)

where;

shear strain = (14 )/(1.2 x 10⁷ x 0.00117 m)

shear strain = 0.000997

The movement of the top surface;

top surface movement = shear strain x thickness

= 0.000997  x 0.00117 m

= 1.167 x 10⁻⁶ m

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Answer:

The answer is C.

Explanation:

Answer: C

Explanation:

Answer: 7327 n

Explanation: Simple

Answer:

A

Explanation:

electric force

The electrostatic force between the moon and the planet can be neglected. Hence, option (A) is correct.

The given problem is based on the comparison between the gravitational force and electrostatic force. Consider the two bodies as moon and a planet such that the force exerted between the moon and the planet is given as,

\(F_{g}=\dfrac{G\times M \times m}{r^{2}}\) ..................................................(1)

Here, G is the gravitational constant, M is the mass of moon, m is the mass of planet and r is the distance between the moon and the planet.

And the electrostatic force is the force between the two charged entities on moon and the planet. So, it is given as,

\(F_{e}=\dfrac{k \times Q \times q}{r^{2}}\) ....................................................(2)

Here, k is the Coulomb's constant, Q is the charge entity at moon and q is the charged entity on planet.

The forces obtained in equation (1) and (2) depends on the masses and charges, which clearly signifies that the masses have more numerical value than charges, hence the electrostatic force will leave much lesser influence than gravitational force. So, it can be neglected.

Thus, we conclude that the electrostatic force between the moon and the planet can be neglected. Hence, option (A) is correct.

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Answer:

FRANZ REULEAUX

Late 19th century kinematics and the theory of machines as seen through the contributions of the German engineering scientist, Franz Reuleaux (1829-1905), often called the "father of kinematics". Extremely famous in his time and one of the first honorary members of ASME, Reuleaux was largely forgotten in much of modern mechanics literature in English until the recent rediscovery of some of his work. In addition to his contributions to kinematics, we review Reuleaux's ideas about design synthesis, optimization and aesthetics in design, engineering education as well as his early contributions to biomechanics. A unique aspect of this review has been the use of Reuleaux's kinematic models at Cornell University and in the Deutsches Museum as a tool to rediscover lost engineering and kinematic knowledge of 19th century history of machine.

The water flow rate from the faucet, assuming a steady flow, is approximately 0.0001608 cubic meters per second.

The phenomenon of a water stream "necking down" as it falls can be explained by the principle of conservation of mass. According to this principle, the flow rate of water remains constant throughout the system.

In the given figure, the water stream emerges from a faucet with an initial cross-sectional area of 1.8 cm² (Area one). As the water falls, it narrows down to a smaller cross-sectional area of 0.3 cm² (Area two) at a height of 25 cm.

To calculate the water flow rate assuming steady flow, we can use the formula:

Flow rate = A₁√(2gh) / A₁² - A₂²

Where A₁ and A₂ are the initial and final cross-sectional areas, respectively, g is the acceleration due to gravity, and h is the height of the water column.

Plugging in the given values, we have:

Flow rate = 1.8 cm² √(2 × 9.8 m/s² × 25 cm) / (1.8 cm²)² - (0.3 cm²)²

Converting the units to match, we get:

Flow rate = 0.018 m² √(2 × 9.8 m/s² × 0.25 m) / (0.018 m²)² - (0.003 m²)²

Simplifying the expression, we find:

Flow rate ≈ 0.0001608 m³/s

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The volume of the rock with a density of 45 g/mL and a mass of 855 grams is 19 ml

We know that,

ρ = m / V

where,

ρ = Density

m = Mass

V = Volume

Given that,

ρ = 45 g / ml

m = 855 g

V = 855 / 45

V = 19 ml

Density is the measure of amount of molecules present in substance. It is denoted by ρ. Its unit is usually g / ml.

Therefore, the volume of the rock with a density of 45 g/mL and a mass of 855 grams is 19 ml

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Answer:

If it has more electrons than protons it has a net negative charge and is known as an anion.

Answer:

Matter can exist in one of several different states, including a gas, liquid, or solid state

Explanation:

Answer:

energy is stored is 2.2 × 10⁻¹³ J

Explanation:

The capacitance  of the cell is given with the expression

C = (KE₀A) / d

k is the dielectric constant, A is the area of the cell, d is the thickness of the cell.

Now given that; the diameter is 50,

Area A = 4πR²

A = 4π × ( 25 × 10⁻⁶ m)²

A = 7850×10⁻¹² m²

our capacitance C = (KE₀A) / d

C = [9 ( 8.85 × 10⁻¹² C²/N.m²  × 7850×10⁻¹² m² )] / 7×10⁻⁹ m

C = 8.93 × 10⁻¹¹ F

Now Energy stored

E = 1/2 × CV²

E = 1/2 × (8.93 × 10⁻¹¹ F) × ( 70 × 10⁻³ V)²

E = 2.2 × 10⁻¹³ J

Therefore energy is stored is 2.2 × 10⁻¹³ J

The energy that should be stored in the electric field should be 2.2 × 10⁻¹³ J.

Since

The capacitance  of the cell should be

C = (KE₀A) / d

Here,

k is the dielectric constant,

A is the area of the cell,

d is the thickness of the cell.

Now the diameter is 50,

So,

Area A = 4πR²

A = 4π × ( 25 × 10⁻⁶ m)²

A = 7850×10⁻¹² m²

Now

our capacitance C = (KE₀A) / d

C = [9 ( 8.85 × 10⁻¹² C²/N.m²  × 7850×10⁻¹² m² )] / 7×10⁻⁹ m

C = 8.93 × 10⁻¹¹ F

Now Energy stored should be

E = 1/2 × CV²

E = 1/2 × (8.93 × 10⁻¹¹ F) × ( 70 × 10⁻³ V)²

E = 2.2 × 10⁻¹³ J

Therefore energy is stored is 2.2 × 10⁻¹³ J.

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Answer:

the bigger stars tend to be hotter and burn through their fuel more quickly than smaller stars they also tend to ether be turned into a black hole or a huge nebula with a neutron star the smaller stars have a tendency to go through their fuel slower and don't get as hot as big stars until the red giant stage.

Explanation:

A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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Disaster recovery and cooperation are both benefited by cloud storage. It makes file sharing simple and guarantees that data is backed up and retrievable in the event of loss or damage.

Your documents and data are kept in a safe data centre off-site by a cloud provider. You are no longer required to update software, maintain the servers, or make sure the hardware is working properly.

To store data, including files, business data, videos, or photographs, cloud storage uses remote servers. Users use an internet connection to upload data to servers, where it is stored on a virtual machine on a physical server.

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Answer:

There would be more hours of sunlight at the equator