a couple plans to have 6 children because they want 3 boys and 3 girls. a statistician friend tells them this is not a very good idea as their desired outcome is unlikely. is their friend correct? question 1 options: yes. random events only approach their expected outcome with consistency over many repititions. yes. the probability of each outcome is not known, and you can only use random events to make predictions if the probability of each event is known in advance. no. with 6 children, it is reasonably safe to assume that they will have 3 boys and 3 girls. question 2 (1 point)

Answer:

-1.75

Step-by-step explanation:

This should be it, but you didn't provide options although you put "Which of the following.."

Answer:

-1.75 thatis the answer thank you HAHAHAHAHAHA

For toss 21 it is 2 dollars, for toss 41 it is 4 dollars, for toss 63 it is 6.

Graphs can take many forms, depending on the type of data being represented and the purpose of the graph. Some common types of graphs include:

Bar graphs: These use bars or columns to represent numerical values or frequencies.

Line graphs: These use lines to show the relationship between two variables over time or other intervals.

Pie charts: These use slices of a circle to represent parts of a whole.

Scatterplots: These show the relationship between two variables by plotting individual data points.

Graphs can be used to identify patterns, trends, and relationships in data, and to make predictions and draw conclusions based on that data. They are commonly used in fields such as statistics, economics, engineering, and science to help visualize and analyze complex data sets.

TOSS              DOLLARS

21                    2

42                   4

63                   6

Plotting the points on the coordinate axes, we have:

 |

7 -

 |

6 -

 |

5 -

 |

4 -         • (21,2)

 |               \

3 -                • (42,4)

 |                       \

2 -                        • (63,6)

 |________________________________

   0   20   40   60   80   100

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9514 1404 393

Answer:

  x = -7, x = 9

Step-by-step explanation:

We presume your equation is ...

  x² -2x -63 = 0

Factors of -63 that have a sum of -2 are -9 and +7. Then the factored equation is ...

  (x -9)(x +7) = 0

Solutions make the factors zero.

  x -9 = 0   ⇒   x = 9

  x +7 = 0   ⇒   x = -7

The solutions to the quadratic equation are x = -7 and x = 9.

Answer:

(-4, 1) is the coords of the final point

Step-by-step explanation:

First do the translation: (3,1) to the right 1 unit is (4,1).
Now the reflection: (4,1) reflected over the y-axis is (-4, 1)

this should be correct... please tell me if its not! hope this helps!!

Answer:

x = 2 + √10

    -------------

           3

x =  2 - √10

     ------------

            3

Step-by-step explanation:

3x² - 3x - 1 = x + 1

         -x - 1  -x  -  1

3x² - 4x - 2 = 0

-b +/- √b² - 4ac              -(-4) +/- √(-4)² - 4(3)(-2)         4 +/- √16 + 24

         ------------------    =            ----------------             =   -----------------

               2a                                 2(3)                                  6

4+/-√40        4 + √ 4 × 10         4 +2√10         2 + √10

------------  =      -------------     =     ------------    =   ------------

     6                       6                        6                  3

                     4 - √ 4 × 10           4 - 2√ 10           2 - √10

                      ----------------    =   -----------------   =    ---------------

                               6                         6                        3

I hope this helps!

Answer:

1/49 it is the equal to that

Step-by-step explanation:

I

Answer: The general form for an equation that models a wave is this: (+/-) a (sin/cos) (2π(x-p)/T), where a is your amplitude, p is your phase shift, and T is your period. The (+/-) becomes + if the graph is to start in the positive direction, and - if it is to start in the negative direction. The (sin/cos) becomes sine if the graph is to start at 0 before being shifted, while it becomes cosine if the graph is to start at the amplitude.

In this case, our graph starts out negative, and at the amplitude with no phase shift, so the (+/-) becomes -, (sin/cos) becomes cos, and p is zero. Substituting in the values given in the problem, a = 9 and T = 7, we find this equation: d = -9cos(2πt/7).

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

Answer:

32

Step-by-step explanation:

x          

 (— -  6) -  2  = 0

  4          

6     6 • 4

   6 =  —  =  —————

        1       4

x - (6 • 4)     x - 24

———————————  =  ——————

     4            4

 (x - 24)    

 ———————— -  2  = 0

    4        

        2     2 • 4

   2 =  —  =  —————

        1       4

(x-24) - (2 • 4)     x - 32

————————————————  =  ——————

       4               4

 x - 32

 ——————  = 0

   4  

x-32

 ———— • 4 = 0 • 4

  4  

x-32

Answer:

Step-by-step explanation:

From table 1,

f(x) = bˣ

For x = -1,

f(-1) = 0.5

0.5 = (b)⁻¹

b = \(\frac{1}{0.5}\)

b = 2

For x = 1.585,

f(1.585) = 3

3 = \(2^{1.585}\)

3 = \(2^{1}\times2^{0.585}\)

\(2^{0.585}=\frac{3}{2}\)

\(2^{0.585}=1.5\)

For x = 2.585,

f(2.585) = \(2^{2.585}\)

             = \(2^{2}\times 2^{0.585}\)

             = 4 × 1.5 [Since, \(2^{0.585}=1.5\)]

             = 6

From table 2,

g(x) = \(\text{log}_b(x)\)

For x = 0.5,

g(0.5) = -1

-1 = \(\text{log}_b(0.5)\)

b⁻¹ = 0.5

b = 2

For x = 2,

g(2) = 1

1 = \(\text{log}_2(2)\)

For x = 6,

g(6) = 2.585

2.585 = \(\text{log}_2(6)\)

2.585 = \(\text{log}_2(2\times 3)\)

2.585 = \(\text{log}_2(2)+\text{log}_2(3)\)

2.858 - 1 = \(\text{log}_2(3)\)

\(\text{log}_2(3)=1.585\)

For x = 3,

g(3) = \(\text{log}_2(3)\)

g(3) = 1.585

The safe load, l, of a wooden beam of width w, height h, and length l, then the nearest integer is, L = 4607.7 pounds.

Based on the given conditions,

The safe load = L

A wooden beam of width = w

Height = h

Length = l

The safe load L, of the beam varies directly as the product of the width and the square of the height.

L∝ (w × h²)

And varies inversely as the length of the wooden beam.

L∝ (w × h²)/l

L = \(\frac{k*w*h^{2} }{l}\)       (Equation-1)

Where k = proportionality constant

If w = 4 inches, h = 7  inches, l = 240 inches and L = 2540 pounds

Then,

We can substitute values in equation-1,

L = \(\frac{k*w*h^{2} }{l}\)  

2540 = (k*4*\(7^{2}\))/240

2540 = (k*4*49)/240

2540 = (k*196)/240

2540*240 = k*196

609600 = k*196

609600/196 = k

3110.20 = k

If w = 5 inches, h = 8 inches and l = 216 inches

L = \(\frac{k*w*h^{2} }{l}\)  

L = ( 3110.20 * 5 * \(8^{2}\) )/216

L = ( 3110.20 * 5 *64 )/216

L = 995264/216

L = 4607.7 pounds

Therefore,

The safe load, l, of a wooden beam of width w, height h, and length l, then the nearest integer is, L = 4607.7 pounds.

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When testing the safety of cars using crash tests, a sample of one or two cars is used because multiple cars are destroyed.

Crash tests involve subjecting cars to controlled collisions in order to assess their safety performance and measure the effects of impact forces on the vehicle and its occupants.

These tests often involve high-speed impacts and result in significant damage to the vehicles being tested.

Due to the destructive nature of crash tests, it is not feasible or practical to test a large number of cars from the population.

Instead, a sample of one or two cars is used to represent the larger population of vehicles.

These samples are carefully selected to be representative of the various models, makes, and designs of cars in circulation.

By selecting a diverse sample, researchers can gather valuable data on the safety performance of different types of cars without the need to test each individual car.

Using a sample also allows for cost and time efficiency.

Crash tests can be expensive and time-consuming, involving extensive preparations, equipment, and safety measures.

Testing a single or a small number of cars reduces the resources required while still providing valuable insights into safety performance.

Therefore, the primary reason for using a sample of one or two cars in crash tests is that multiple cars are destroyed during the testing process.

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Answer:

solution given :

side1[S1]=17cm

side2[S2]=21cm

side3[S3]=10cm

height[H]=8cm

we have .

perimeter of triangle[P]= sum of all sides

=S1+S2+S3=17+21+10=48cm is your answer

In point-slope form, the equation of the line passing through the points (-1, -4) and (2, 1) is

D. (y+4) = (5)/(3)(x+ 1)

To find the equation of a line in point-slope form, we need the slope of the line and a point that lies on the line.

Given the two points on the line: (-1, -4) and (2, 1), we can calculate the slope using the formula:

slope = (y₂ - y₁) / (x₂ - x₁)

slope = (1 - (-4)) / (2 - (-1))

= 5 / 3

choose one of the points, say (-1, -4), and use the point-slope form to write the equation of the line

y - y₁ = m(x - x₁)

y - (-4) = (5/3)(x - (-1))

y + 4 = (5/3)(x + 1)

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Answer:

x = greater than or equal to 3.5         x = 3≥

Step-by-step explanation:

any number that is greater than or is 3.5 will make 2x greater than 5 + 2 which equals 7

Answer A is the only one that seems to make sense to me id choose A

a and d are true statement

ok as know to me

The type of sampling being used when 5% of the registered voters from each county in a state are drawn at random separately is a stratified sampling.

Stratified sampling is the type of probability sampling that is used when the population being sampled has different groups or strata with varying characteristics. A sample is then drawn from each group to make sure that each stratum or group is represented.The samples can be of equal sizes or can be proportionate to the size of the group. The idea behind stratified sampling is to increase the representativeness of the sample by reducing the variability of the data obtained from the sample.

The advantages of using stratified sampling are that it reduces the variability of the data obtained and ensures that every group or stratum is represented. It also makes it possible to identify any differences between the groups and analyze them independently of the others.In summary, when 5% of the registered voters from each county in a state are drawn at random separately, it is an example of a stratified sampling.

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(a) To find the rate of change of the area when r = 12 centimeters, we need to use the formula for the area of a circle, which is A = πr^2. We can then take the derivative of both sides with respect to time t, which gives us:
dA/dt = 2πr(dr/dt)

Substituting in the given values, we get:
dA/dt = 2π(12)(5) = 120π
Therefore, the rate of change of the area when r = 12 centimeters is 120π square centimeters per minute.
(b) To find the rate of change of the area when r = 32 centimeters, we can use the same formula and approach as in part (a), but with r = 32:
dA/dt = 2πr(dr/dt)
dA/dt = 2π(32)(5) = 320π
Therefore, the rate of change of the area when r = 32 centimeters is 320π square centimeters per minute.

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The values of x = 10√3 derived using the trigonometric ratio of cosine.

The trigonometric ratios involves the relationship of an angle of a right-angled triangle to ratios of two side lengths. Basic trigonometric ratios includes; sine cosine and tangent.

Considering the larger acute angle, if we represent it by θ then for the bigger right triangle with adjacent x and hypotenuse 30;

cosθ = x/30

for the smaller right triangle with adjacent 30 - 20 = 10 and hypotenuse x

cosθ = 10/x

x/30 = 10/x

x² = 300 {cross multiplication}

x = √300 {take square root of both sides}

x = √100 × √3

x = 10√3.

Therefore, the values of x = 10√3 derived using the trigonometric ratio of cosine.

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Answer:

3x square-30x +29=0. i think thats the equatiom

Rounding off to two decimal places, the selling price of organic bananas is $2.12/kg.

The selling price of non-organic bananas can be determined as follows:

Selling Price of Non-Organic Bananas = Cost of Non-Organic Bananas + MarkupAmount of Non-Organic BananasMarkup of Non-Organic Bananas = 55% * Cost of Non-Organic Bananas = 55/100 * $0.81/kg = $0.45/kg

Cost of Non-Organic Bananas = $0.81/kg

Therefore, Selling Price of Non-Organic Bananas = $0.81/kg + $0.45/kg = $1.26/kg

Rounding off to two decimal places, the selling price of non-organic bananas is $1.26/kg.

The selling price of organic bananas can be determined as follows:

Selling Price of Organic Bananas = Cost of Organic Bananas + MarkupAmount of Organic Bananas Markup of Organic Bananas = 75% * Cost of Organic Bananas = 75/100 * $1.21/kg = $0.91/kg

Cost of Organic Bananas = $1.21/kg

Therefore, Selling Price of Organic Bananas = $1.21/kg + $0.91/kg = $2.12/kg

Rounding off to two decimal places, the selling price of organic bananas is $2.12/kg.

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Answer: He was given 50 for his birthday

Answer:

It's b

Step-by-step explanation:

This was the first answer I gave. So I am going with it.

Answer:

y=5

Step-by-step explanation:

y+6=-35+26 (+ 3y)

4y+6=26 (-6)

4y=20 (/4)

y=5

The first vector field F is a constant vector field with components (2, -3, 4). The second vector field F is obtained by taking the gradient of the scalar function f(x, y, z) = x^2 + y^2 + z^2. The components of the vector field F are obtained by differentiating each component of the scalar function with respect to the corresponding variable. The resulting vector field is F = (2x, 2y, 2z).

For the first vector field F = (2, -3, 4), the components of the vector field are constant. This means that the vector field has the same value at every point in space. The vector field does not depend on the position (x, y, z) and remains constant throughout.

For the second vector field F = (Fx, Fy, Fz), we are given a scalar function f(x, y, z) = x^2 + y^2 + z^2. To find the vector field F, we take the gradient of the scalar function.

The gradient of a scalar function is a vector that points in the direction of the greatest rate of change of the scalar function at each point in space. The components of the gradient vector are obtained by differentiating each component of the scalar function with respect to the corresponding variable.

In this case, we have f(x, y, z) = x^2 + y^2 + z^2. Taking the partial derivatives, we get:

Fx = 2x

Fy = 2y

Fz = 2z

These partial derivatives give us the components of the vector field F = (2x, 2y, 2z).

Therefore, the second vector field F = (2x, 2y, 2z) is obtained by taking the gradient of the scalar function f(x, y, z) = x^2 + y^2 + z^2.

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Answer:

Sorry for the late notice but I was just checking in to see if you had

Answer:

H; (3,3)

I: (4,3)

J: (4,1)

K:(3,1)

this one confused me alot. so I'm sorry if u get this wrong

If the production is limited to at most 1800 hammers, then the maximum revenue that can be generated is $50,400.

The given problem is about finding the maximum revenue for a hammer manufacturing company based on a given total revenue function. The total revenue function for a hammer is given as R = 56x − 0.01x^2, where x is the number of hammers sold. To find the maximum revenue, we need to differentiate the total revenue function with respect to x and equate it to zero.

dR/dx = 56 - 0.02x = 0

Solving the above equation for x, we get x = 2800.

Therefore, the sale of 2800 hammers will maximize the total revenue in dollars.

To find the maximum revenue, we need to substitute the value of x in the total revenue function.

\(R = 56(2800) -0.01(2800)^2\)

R = $78,400

Therefore, the maximum revenue that can be generated by selling 2800 hammers is $78,400.

Now, let's consider the second part of the question. If the production is limited to at most 1800 hammers, then the maximum revenue can be found by substituting x = 1800 in the total revenue function.

\(R = 56(2800) -0.01(1800)^2\)

R = $50,400

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Answer: \(y=\frac{2}{5}, \frac{6}{5}\)

Step-by-step explanation:

When answering a problem like this, you first isolate the absolute value.  TO do this, first subtract 8 from both sides, to get –2|4–5y|=-4.  Then divide both sides of the equation to get |4–5y|=2.  The next thing you do is split the equation into 4-5y=2 and 4-5y=-2, because the contents of the absolute value could be negative or positive, and simplifying both into y = 2/5, and y = 6/5y.

Hope it helps <3

The probability that m balls is P(m balls in first compartment) = (nCm) * ((n-1)^(n-m)) / (n^n).

The total number of possible arrangements of distributing n balls into n compartments is given by n^n. Each ball has n choices for which compartment to fall into, and since there are n balls, we multiply n by itself n times.

Now, let's consider the number of ways m balls can fall into the first compartment. We can choose m balls out of the n balls to go into the first compartment in nCm ways, which is the binomial coefficient.

The remaining (n-m) balls can go into any of the remaining (n-1) compartments in (n-1)^(n-m) ways. Therefore, the probability that m balls will fall into the first compartment is given by:

P(m balls in first compartment) = (nCm) * ((n-1)^(n-m)) / (n^n)

This formula calculates the ratio of favorable outcomes (m balls in the first compartment) to the total number of possible outcomes (all possible arrangements of distributing n balls into n compartments).

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The probability that the coordinates of the 3 points selected will all be positive is given as follows:

0.1 = 10%.

To obtain a probability, we must identify the number of desired outcomes and the number of total outcomes, and then the probability is given by the division of the number of desired outcomes by the number of total outcomes.

The number of ways to choose 3 numbers from a set of 5 is given as follows:

C(5,3) = 5!/[3! x 2!] = 10 ways.

There is only one way to choose 3 positive numbers from a set of 3, hence the probability is given as follows:

p = 1/10

p = 0.1.

The coordinates A and B are negative, while C, D and E are positive.

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Answer:

15% off

Step-by-step explanation:

You take your 975 and divide it

Answer:

The percentage markdown is 15 % .