A copper wire loop is initially at rest in a uniform magnetic field. Between times i=t, and t=tv+delta t the loop is rotated about a vertical axis as shown. Will current flow through the wire of the loop during this time interval? If so, indicate the direction of the induced current and explain your reasoning. If not, explain why not.

Answers

Answer 1

The force acting on the coil must also act parallel to the magnetic field if it is being accelerated parallel to the field.

A fundamental requirement that must be satisfied for current to be induced in a coil is that the magnetic field and force (acceleration) directions must be perpendicular to one another. As a result, current is induced in a path that is perpendicular to the directions in which the force acting on the coil and the magnetic field are moving. The coil would conduct this current either in a clockwise or anticlockwise direction. We may recast the change in fux as shown above because B is constant due to the constant magnetic Feld. Since A is a positive number, there will be a.

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Related Questions

1. What is the function of a lightning rod?
2. How is charge build-up reduced on airplanes?
3. Why is a ground strap a necessary safety feature when transferring fuel?
4. What are three different methods for reducing charge build-up in clothes dryers?
5. What are four different methods for reducing charge build-up in a computer room with a carpet?​

Answers

Answer:  1. The function of a lightning rod is to protect buildings, structures, and people from lightning strikes by providing a path of least resistance for the electrical current to follow, directing it safely into the ground instead of through the structure or people.

2. Charge build-up is reduced on airplanes through various methods, such as using conductive materials in the airplane's structure, applying anti-static coatings on the airplane's surface, and installing static discharge wicks or similar devices on the airplane's trailing edges, which provide a way for any accumulated charge to safely dissipate into the air.

3. A ground strap is a necessary safety feature when transferring fuel because it provides an electrical connection between the fuel container and the receiving container, allowing any static charge to safely dissipate into the ground. Without a ground strap, the static charge could build up and potentially ignite the fuel.

4. Three different methods for reducing charge build-up in clothes dryers are: (1) using dryer sheets or fabric softeners, which can help neutralize static charges on the clothes, (2) adding a damp cloth to the dryer, which can help dissipate static charges, and (3) using metal dryer balls, which can physically separate clothes and prevent them from rubbing against each other and creating static charges.

5. Four different methods for reducing charge build-up in a computer room with a carpet are: (1) using conductive flooring or carpet tiles that can help dissipate static charges, (2) using anti-static mats or wrist straps for personnel who work in the room, (3) using air ionizers or humidifiers, which can help neutralize static charges in the air, and (4) grounding all equipment and devices in the room to prevent the buildup of static charges.

Explanation:

I hope this helps!

Two cars collide head-on and stick together.
Car A, with a mass of 2000 kg, was initially
moving at a velocity of 10 m/s to the east. Car
B, with an unknown mass, was initially at rest.
After the collision, both cars move together at
a velocity of 5 m/s to the west. What is the
mass of Car B?
OF

Answers

The mass of Car B is -6000 kg.

To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Therefore, we can write the equation for the conservation of momentum as:

(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision

Let's substitute the given values into the equation:

(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)

Simplifying the equation:

20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)

Dividing both sides by -5 m/s:

-4000 kg = 2000 kg + mass of Car B

Subtracting 2000 kg from both sides:

mass of Car B = -4000 kg - 2000 kg

mass of Car B = -6000 kg

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The space station Babylon 5 has a diameter of 1 miles, and rotated around its long axis to produce artificial gravity for its inhabitants. It completes 1 revolutions/min. Calculate the effective gravitational strength at the outer rim of the station, in units of g. (use g = 9.81 m/s^2)

Answers

This question involves the concept of artificial gravity.

The effective gravitational strength at outer rims is "0.9 g".

Artificial Gravity

The effective gravitational strength at the outer rims can be given by the following formula:

\(v=\frac{1}{2\pi}\sqrt{\frac{a_c}{r}}\\\\a_c=4\pi^2v^2r\)

where,

\(a_c\) = effective gravitational strength = ?v = rotational speed = 1 rev/min = 0.0167 rev/sr = radius = diameter/2 = 1 mile/2 = 0.5 miles = 804.672 m

Therefore,

\(a_c = 4\pi^2(0.0167\ rev/s)^2(804.672\ m)\\a_c =8.82\ m/s^2\\\\In\ terms\ of\ g:\\\\a_c=(8.82\ m/s^2)(\frac{g}{9.81\ m/s^2})\\\\a_c = 0.9g\)

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True or false quarterbacks should not expect to have bad passes

Answers

Answer:

false

Explanation:

False ..................

Mathew has a filtration kit, which consists of a funnel, a flask, and filter papers. Which of these mixtures can he separate using filtration?

Answers

Answer:

C. Muddy Water

1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point. What is the heat of fusion of the substance?

Answers

1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point ,  the heat of fusion of the substance is 548 joules .

What is heat of fusion ?

Heat of fusion, also known as enthalpy of fusion or latent heat of fusion, is the amount of energy required to melt or freeze a substance under constant pressure conditions. When it comes to chemistry, "fusion" is basically synonymous with "melting." In the classroom, heat of fusion is typically used when a substance is at its melting or freezing point. In such instances, most people consider heat of fusion to be a constant.

Water, for example, has a heat of fusion of 334 J/g at its melting point of 0°C. At 0°C, one grams  of liquid water requires 334 Joules of energy to completely freeze into ice. In addition, one grams of ice requires 334 Joules of energy to melt entirely.

q = m×∆Hf

q: Total change in heat energy (in Joules)

∆Hf: Heat of fusion of substance (in Joules per gram)

m: Mass of substance (in grams)

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The compass of an airplane indicates that the airplane is heading north. The airplane is moving at an airspeed of 230 km/h. The wind is blowing east at 55 km/h.

1.What is the speed of the plane with respect to the ground?
2.How many degrees east of north is the plane’s velocity with respect to the ground?

Answers

Answer:

Explanation:

airspeed is speed with respect to air .

Let speed of airplane with respect to ground be V .

wind is blowing east at 55 km/h

airplane is heading north with speed V

Resultant of V and 55 km /h is 230 km/h

V² + 55² = 230²

V² = 52900 - 3025

V = 223.32 km/h

Let θ be the required angle

Tanθ = 55 / 223.32 = .246

θ = 14⁰ .

Which one of the following statements concerning weight and energy balance is most accurate?

A. People generally need the same amount of physical activity to maintain weight stability.

B. Regular physical activity doesn’t impact the percentage of body fat in children and adolescents.

C. It’s possible to achieve weight stability by doing the equivalent of 60–120 minutes a week of moderate-intensity walking.

D. The optimal amount of physical activity needed to maintain weight is unclear.

Answer: D. I took the test and got it right

Answers

The correct answer choice concerning weight and energy balance which is most accurate is the optimal amount of physical activity needed to maintain weight is unclear.

What is energy balance?

Energy balance refers to the way in balance is achieved when intake of energy is equal to energy expended.

Energy refers to the impetus behind all motion and all activity. If is also the capacity to do work. Energy is measured in a unit dimensioned in mass × distance²/time² (ML²/T²) or the equivalent.

So therefore, the correct answer choice concerning weight and energy balance which is most accurate is the optimal amount of physical activity needed to maintain weight is unclear.

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Which of the following objects requires the MOST power to lift?
A) 2 kg box lifted 2 m in 1 s.
B) A 2 kg box lifted 1 m in 1 s.
C)A 2 kg box lifted 2 m in 2 s.
D) A 2 kg box lifted 1 m in 2 s.

Answers

Answer:

A

Explanation:

Work = F * d

Power = work/time   or    f *d / t          

  '  A '     gives the highest amount of power

how does mass relates to latent heat?​

Answers

The mass of a substance is not directly related to latent heat. Instead, latent heat is a parameter that describes the amount of energy required or released during a phase shift of a substance.

What is latent heat?​

Latent heat can be thought of as hidden energy that is supplied or extracted to change the state of a substance without changing its temperature or pressure.

Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process—typically a first-order phase transition.

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Explain the light detection technique of photovoltaic detection​

Answers

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

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An impulse of 200 N.s is applied horizontally by a soccer player of mass 74 kg at the start of a sprint (initial velocity= 0). What is the player’s change in momentum and velocity reached

Answers

The velocity reached by the soccer player is 2.7 m/s.

Impulse applied by the soccer player = 200 Ns

Mass of the soccer player = 74 kg

According to impulse-momentum theorem, the average net external force multiplied by the time it takes for that force to take effect equals the impulse, which is equal to the change in momentum.

Impulse = Fnet × t

Fnet x t = ma × t = m × v

mv = ΔP

where ΔP is the change in momentum.

So,

The change in momentum of the player, ΔP = 200 Kgm/s

So, velocity reached, v = 200/74

v = 2.7 m/s

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If these results were published in a lab report, which of the following would most likely followthis table?a. A hypothesisb. A statement of the problemc. A conclusiond.An experiment

If these results were published in a lab report, which of the following would most likely followthis

Answers

The given table is the table of result. In a lab report, discussions/conclusions usually follow result. Thus, the correct option is

c. A conclusion

A monkey is chained to a stake in the ground. The stake is 3.00 m from a vertical pole, and the chain is 4.28 m long. How high can the monkey climb up the pole?

Answers

Answer:

  3.05 m

Explanation:

The Pythagorean theorem tells you the other leg of this right triangle is ...

  a^2 +b^2 = c^2

  a^2 +3^2 = 4.28^2

  a = √(4.28^2 -3^2) = √9.3184

  a ≈ 3.053

The monkey can climb about 3.05 meters up the pole.

A laser source is replaced by a laser of the same color that is more powerful. How does the light of the second laser compare with the original laser?

Answers

The light of the second laser compare with the original laser in the following way: the light in the second laser absorbs more optical radiation.

What is a laser?

A laser is device that produces a monochromatic, coherent beam of light.

A laser is created when electrons in the atoms in optical materials like glass, crystal, or gas absorb the energy from an electrical current or a light.

Therefore, it can be said that light of the second laser compare with the original laser in the following way: the light in the second laser absorbs more optical radiation.

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If you have a mass of 0.9kg and a velocity 12 m/s what is your momentum?

Answers

Momentum
= mass x velocity
= 0.9 x 12
= 10.8 kgm/s.

please, question 1.4 and 1.5​

please, question 1.4 and 1.5

Answers

Answer:

I cant really see the imagine

Explanation:

A 150 pound man runs up a stairway 20 feet above ground level in 15s. How much work did the man do?

Answers

Given:

h = height = 20 ft = 6.096 m

m = 150 pound = 68.0389 kg

time = 15 s

g= 9.8 m/s^2

Potential energy = mgh = (68.0389 ) (9.8 ) (6.096 ) = 4,064.7 J

Work done = 4,064.7 J

Details
A 70 kg student rides the Gravitron at a carnival. The
Gravitron has a radius of 2.75 meters. The student feels
a centripetal force of 2100 N. How fast is the Gravitron
spinning?

Answers

I believe the answer your looking for is A

Answer:

1400 math quiz

Explanation:

40s n shorty's

joanne drives her car at a speed of 20 m/s. when she applied her breaks, a frictional force of 2000 N brought her car to a complete stop in 10 seconds. what is the mass of her car

A) 1000 Kg
B) 1300 Kg
C) 20,000 Kg
D) 800 Kg​

Answers

Answer:

A) 1000 kg

Explanation:

vf = vi + at

0 = 20 + (a)(10)

a = -2.0 m/s^2

F = ma

2000 = (m)(2)

m = 1000 kg

1.) A roller coaster travels on a frictionless track as shown in the illustration.
a.) If the speed of the car at Pt A is 5.0 m/s, what is the speed at Pt B

(More in the photo provided)

1.) A roller coaster travels on a frictionless track as shown in the illustration. a.) If the speed of

Answers

For the roller coaster on a frictionless track:

a. The speed at Point A is 5.0 m/s, the speed at Point B will also be 5.0 m/s.b. The height between Points A and B where kinetic energy equals potential energy is 5.0 m.c. For the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m.d. For the car to reach Point C, the height at Point A must be greater than or equal to 8.0 m.

How to solve speed and height?

a. The speed of the car at Point B can be determined using the principle of conservation of energy. The total mechanical energy (sum of kinetic energy and potential energy) remains constant in the absence of external forces like friction. Therefore, if there is no energy loss, the kinetic energy at Point A is equal to the kinetic energy at Point B.

Given that the speed at Point A is 5.0 m/s, the speed at Point B will also be 5.0 m/s.

Answer: A. 5.0 m/s

b. To find the height at which kinetic energy equals potential energy, we can set the equations for kinetic energy and potential energy equal to each other.

At Point A, the roller coaster has both kinetic energy and potential energy. The total mechanical energy is the sum of these two:

Initial mechanical energy at Point A = Kinetic energy at Point A + Potential energy at Point A

At Point B, the roller coaster will have kinetic energy and potential energy, but we want to find the height at which kinetic energy equals potential energy. Let's call this height "h."

Mechanical energy at Point B = Kinetic energy at Point B + Potential energy at Point B

Since the speed at Point B is the same as the speed at Point A (5.0 m/s), the kinetic energy at both points is the same.

Equating the mechanical energy at Point A to the mechanical energy at Point B:

Initial mechanical energy at Point A = Mechanical energy at Point B

Kinetic energy at Point A + Potential energy at Point A = Kinetic energy at Point B + Potential energy at Point B

Since the kinetic energy is the same at both points, simplify the equation:

Potential energy at Point A = Potential energy at Point B

The potential energy at any point is given by the formula mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.

Therefore, at the height h between Points A and B, the potential energy equals the potential energy at Point A:

mgh = mghA

Since the mass and acceleration due to gravity are the same, cancel them out:

h = hA

This means that the height where kinetic energy equals potential energy is the same as the height at Point A.

Answer: The height between Points A and B where kinetic energy equals potential energy is 5.0 m.

c. To determine if the car will reach Point C, compare the potential energy at Point B with the potential energy at Point C. If the potential energy at Point B is greater than or equal to the potential energy at Point C, the car will reach Point C.

Potential energy at Point B = mghB

Potential energy at Point C = mghC

Given that the height at Point C is 8.0 m, compare the potential energies:

Potential energy at Point B ≥ Potential energy at Point C

mghB ≥ mghC

Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:

hB ≥ hC

Therefore, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m.

d. The minimum speed needed at Point A for the car to reach Point C can be determined by comparing the potential energy at Point A with the potential energy at Point C. If the potential energy at Point A is greater than or equal to the potential energy at Point C, the car will have enough energy to reach Point C.

Potential energy at Point A = mghA

Potential energy at Point C = mghC

Given that the height at Point A is 5.0 m, compare the potential energies:

Potential energy at Point A ≥ Potential energy at Point C

mghA ≥ mghC

Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:

hA ≥ hC

Therefore, for the car to reach Point C, the height at Point A must be greater than or equal to 8.0 m.

To summarize, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m, and the height at Point A must also be greater than or equal to 8.0 m.

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(i) The coefficient of linear expansion for Copper is 17 x 10-6 m/°C. A length of copper pipe measures 32 metres at 15 °C. The flow of hot water through the pipe increases its temperature to 95°C; determine the total length of the pipe at this temperature.

Answers

The coefficient of linear expansion for Copper is 17 x 10-6 m/°C. A length of copper pipe measures 30 metres at 15 °C. The flow of hot water through the pipe increases its temperature to 90°C; determine the total length of the pipe at this temperature. (ii) A measuring tape made of aluminium measures 5.0 m at a temperature of 288 K. Calculate the percentage error in measurement when the temperature has increased to 313 K. Take the coefficient of linear expansion of aluminium as 23x10-6 K-1

How did earth change about 2.5 billion years ago when many organisms began using photosynthesis to make food

A. The amount of oxygen in the atmosphere increased

B. Mass extinctions occurred

C. The oceans became larger

D. Rainfall increased

Answers

The amount of oxygen in the air was increased

difference between concave and convex lens​

Answers

Answer:

convex lens:converging lens

focal length:positive

magnification; positive

concave lens:diverging lend

focal length:negative

magnification :negative

types:concavoconcave,planoconcave

A convex lens or converging lens focuses the light rays to a specific point whereas a concave lens or diverging lens diverges the light rays. A lens is a transparent material (either curved or flat surface) based on the principles of refraction. Concave lenses and convex lenses are often used together which is known as the Concave – Convex lens. When these lenses are combined, they produce sharper images. Most of the eyeglass lenses use combinations of convex and concave lenses. Cameras, telescopes and microscopes use different lens, helping us to see the world in a better

Read it and make it as table.

An RV is traveling 60 km/h along a highway at night. A boy sitting near the driver of the RV turns a flashlight on and shines it at another boy at the back end of the RV.

Answers

Answer:

300,000,000 and the second question is the same.

Explanation:

Edge

Answer:

What is the speed of the light relative to the boys?

✔ 300,000,000

What is the speed of light relative to a stationary observer on the side of the road?

✔ 300,000,000

Explanation: MARK ME BRAINLIEST CUHZZZZZ DA*N (cant say dam or they gone banned me again)

Two vectors A and B are such that A =1,B=2,A.B=1 find angle

Answers

Answer:\(60^{\circ}\)

Explanation:

Given

\(\mid\Vec{A}\mid=1\)

\(\mid\Vec{B}\mid=2\)

And \(A\cdot B=1\)

We know \(\vec{A}\cdot \vec{B}=\mid\Vec{A}\mid\mid\Vec{B}\mid\cos \theta\)

Where \(\theta\) is the angle between them

Substituting the values

\(1=1\times 2\cos \theta\)

\(\cos \theta =\dfrac{1}{2}\)

\(\theta =60^{\circ}\)

Thus the angle between \(A\) and \(B\) is  \(60^{\circ}\)

¿Cuál es el trabajo neto en J que se necesita para acelerar un auto de 1500 kg de 55 m/s a 65 m/s?

What is the net work in J required to accelerate a 1500 kg car from 55 m/s to 65 m/s?

Answers

The net work done (in J) required to accelerate a 1500 kg car from 55 m/s to 65 m/s is 3127500 J

How do i determine the net work done?

First, we shall obtain the initial kinetic energy. Details below:

Mass (m) = 1500 Kginitial velocity (u) = 55 m/sInitial kinetic energy (KE₁) =?

KE₁ = ½mu²

= ½ × 1500 × 55²

= 41250 J

Next, we shall final kinetic energy. Details below:

Mass (m) = 1500 KgFinal velocity (v) = 65 m/sFinal kinetic energy (KE₂) =?

KE₂ = ½mv²

= ½ × 1500 × 65²

= 3168750 J

Finally, we shall determine the net work done. Details below:

Initial kinetic energy (KE₁) = 41250 JFinal kinetic energy (KE₂) = 3168750 JNet work done (W) =?

W = KE₂ - KE₁

= 3168750 - 41250

= 3127500 J

Thus, the net work done is 3127500 J

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A car is parked on a cliff overlooking the ocean on an incline that makes an angle of 23.0° below the horizontal. The negligent driver leaves the car in neutral, and the emergency brakes are defective. The car rolls from rest down the incline with a constant acceleration of 3.67 m/s2 for a distance of 50.0 m to the edge of the cliff, which is 35.0 m above the ocean.
(a) Find the car's position relative to the base of the cliff when the car lands in the ocean.

Incorrect: Your answer is incorrect.
m

(b) Find the length of time the car is in the air.

Incorrect: Your answer is incorrect.
s

Answers

Answer:

a) the car lands in the ocean 85.1 meters away from the base of the cliff.

b) the length of time the car is in the air is 2.50 seconds.

Explanation:

Let's start with part (a) of the problem.

First, we need to find the car's velocity at the bottom of the incline using the kinematic equation:

v^2 = u^2 + 2as

where v is the final velocity, u is the initial velocity (which is 0 m/s), a is the acceleration (which is 3.67 m/s^2), and s is the distance traveled down the incline (which is 50.0 m).

Plugging in these values, we get:

v^2 = 0^2 + 2(3.67 m/s^2)(50.0 m)

v^2 = 367 m^2/s^2

v = 19.1 m/s (rounded to one decimal place)

Next, we can use the vertical motion equations to find the time it takes for the car to fall from the cliff to the ocean. We'll use the equation:

h = ut + (1/2)at^2

where h is the height of the cliff (35.0 m), u is the initial vertical velocity (which is 0 m/s), a is the acceleration due to gravity (-9.81 m/s^2), and we're solving for t.

Plugging in these values, we get:

35.0 m = 0 m/s * t + (1/2)(-9.81 m/s^2)t^2

19.9 = t^2

t = 4.46 s (rounded to two decimal places)

Therefore, the car is in the air for 4.46 seconds.

Finally, to find the car's position relative to the base of the cliff when it lands in the ocean, we can use the horizontal motion equation:

s = ut + (1/2)at^2

where s is the horizontal distance the car travels (which is what we're solving for), u is the horizontal velocity (which is the same as the velocity at the bottom of the incline, 19.1 m/s), a is the horizontal acceleration (which is 0 m/s^2), and t is the time the car is in the air (which is 4.46 s).

Plugging in these values, we get:

s = 19.1 m/s * 4.46 s + (1/2)(0 m/s^2)(4.46 s)^2

s = 85.1 m (rounded to one decimal place)

Therefore, the car lands in the ocean 85.1 meters away from the base of the cliff.

I NEED HELP ASAPPPP PLEASE

I NEED HELP ASAPPPP PLEASE

Answers

I think it’s c i’m not sure tho

Which two elements make up most of the Sun’s mass?

Question 4 options:

Hydrogen and oxygen


Carbon and nitrogen


Oxygen and carbon


Hydrogen and helium

Answers

Hydrogen and helium

Answer:

hydrogen and helium

Explanation:

i got it 100 percent. Hope this Helps!

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