The chemical reaction between 8.0 mol of O2 and 189 g of C2H4 (ethylene) can be represented as shown below:C2H4 + 3O2 → 2CO2 + 2H2OThe balanced equation for the combustion of C2H4 (ethylene) in oxygen is:C2H4 + 3O2 → 2CO2 + 2H2O.
According to the chemical equation above, 1 mol of C2H4 reacts with 3 mol of O2 to produce 2 mol of CO2 and 2 mol of H2O. Hence, the amount of O2 required for the complete combustion of 8.0 mol of C2H4 will be:3 moles of O2 for 1 mole of C2H48.0 moles of C2H4 require:8.0 mol C2H4 x 3 mol O2/mol C2H4 = 24 mol O2Therefore, 8.0 mol of O2 is sufficient for the combustion reaction.
Therefore, the limiting reagent is C2H4 and the excess reactant is O2. Now, we will calculate the amount of C2H4 used. The molar mass of C2H4 is 28.05 g/mol. So, 189 g of C2H4 is:189 g / 28.05 g/mol = 6.74 mol of C2H4Since the 8.0 mol of C2H4 given in the problem is greater than 6.74 mol of C2H4 calculated above, C2H4 is in excess. Thus, all the C2H4 will not be used up in the reaction, and there will be some C2H4 remaining after the combustion reaction has completed. Hence, some C2H4 will remain after the completion of the reaction.
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Which property is conserved in both nuclear reactions and chemical
reactions?
A. Total number of protons and neutrons
O B. Number of atoms
C. Total mass of atoms
O D. Type of atoms
Answer:
A. Total number of protons and neutrons
Explanation:
In both nuclear reactions and chemical reactions, the total number of protons and neutrons are conserved.
It implies that the starting number of protons and neutrons in both reactions must be the same.
Chemical reactions involves, loss, gain or sharing electrons between two atoms.
Nuclear reactions deals with the nucleus of an atom.
It must be ensured that the mass and atomic number in nuclear reactions is conserved.
Answer:
Total number of protons and neutrons
Explanation:
Ap3x
Rain that containing excess of acid is called
Answer:
The rain containing excess of acid I called acid rain
Answer:
acid rain
Explanation:
Thats literally what its called
Calculate the mass of CuO which can react with 39,2 grams of orthophosphate acid.Please Help!!3CuO+ 2H3PO4 = Cu3(PO4)2 + 3H20
Answer
47.73 g CuO
Explanation
Given:
Chemical equation: 3CuO+ 2H3PO4 = Cu3(PO4)2 + 3H20
mass of orthophosphate acid (Cu3(PO4)2) = 39.2 g
Required: The mass of CuO
Solution:
\(\begin{gathered} 39.2g\text{ H}_3PO_4\text{ x }\frac{1\text{ mol H}_3PO_4}{97,994g\text{ H}_3PO_4}\text{ x }\frac{3\text{ moles CuO}}{2\text{ moles H}_3PO_4}\text{ x }\frac{79,545g\text{ CuO}}{1mole\text{ CuO}} \\ \\ =\text{ 47.73 g CuO} \end{gathered}\)Second method:
Step 1: Find the moles of H3PO4
n = m/M where m is the mass and M is the molar mass of H3PO4
n = 39.2g/97.994g.mol^-1
n = 0.400 mol
Step 2: Use the stoichiometry to find the moles of CuO
The molar ratio between CuO and H3PO4 is 3:2
Therefore the moles of CuO = 0.400 mol x (3/2) = 0.600 mol
Step 3: Find the mass of CuO, now that we have moles
m = n x M m is the mass, n is the moles and M is the molar mass
m = 0.600 mol x 79,545 g/mol
m = 47.73 g
the part of our energy expenditure that we have direct control over is voluntary physical activity.a. trueb. false
The statement is true. Voluntary physical activity is a type of energy expenditure that we can directly control through our conscious decisions to engage in physical activities such as exercise, sports, or any form of physical movement.
This type of energy expenditure is known as "discretionary physical activity" and it contributes to our daily energy expenditure along with other components such as basal metabolic rate, thermic effect of food, and non-exercise activity thermogenesis. By increasing our level of voluntary physical activity, we can increase our overall energy expenditure and potentially achieve weight loss or maintenance goals. It is important to note that engaging in physical activity has many health benefits beyond just managing body weight, such as improving cardiovascular health, increasing muscle strength and endurance, and reducing the risk of chronic diseases. Therefore, it is highly recommended to incorporate regular physical activity into our daily routine for overall health and wellness.
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The solubility of a gas is 2 g/L at 50 kPa of pressure. What is the solubility of a gas
at 10 kPa of pressure? Assume the temperature is constant. *
This problem is providing us with the initial solubility and pressure of a gas and asks for the solubility once the pressure is changed to 10 kPa. At the end, the answer is found to be 0.4 g/L.
Ideal gasesIn chemistry, the concept of ideal gas provides us first approach to the understanding of gases, as a model with no interactions and perfectly spherical-shaped molecules, however, this is not an actual a fact in nature.
Thus, we can relate pressure, volume, temperature and moles (or grams) by using the widely-known ideal gas equation:
PV = nRT
Which in the case of the solubility of the gas, can be written as:
P=Sol*RT*MM
Which at constant temperature can be just:
\(\frac{P}{Sol} =k\)
Since R, T and MM (molar mass of the gas) are constants, and for two states:
\(\frac{P_1}{Sol_1} =\frac{P_2}{Sol_2}\)
In such a way, one can calculate the solubility when the pressure changes as follows:
\(Sol_2=\frac{Sol_1*P_2}{P_1}\)
Finally, we plug in the numbers to obtain:
\(Sol_2=\frac{2g/L*10kPa}{50kPa} =0.4g/L\)
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How many control(s) are in an experiment
Cordell bought new tires for his bicycle. As he rode his bike on the hot street, the temperature of the air in the tires increased. If the volume of the air stayed the same, what happened to the pressure inside the tires?
A. It decreased. B. It increased. C. It stayed the same. D. It was inversely proportional to the temperature
Answer: The answer is B. The pressure inside the tires increased.
Explanation:
The relationship between the pressure, volume, and temperature of a gas is described by the ideal gas law, which is usually written as:
\($$PV = nRT$$\)
where:
- \(\(P\)\) is the pressure,
- \(\(V\)\) is the volume,
- \(\(n\)\) is the number of moles of gas,
- \(\(R\)\) is the ideal gas constant, and
- \(\(T\)\) is the temperature (in Kelvin).
In this case, the volume \(\(V\)\) and the number of moles \(\(n\)\) of air in the tires stay the same. The temperature \(\(T\)\) is increasing. Therefore, for the equation to remain balanced, the pressure \(\(P\)\) must also increase.
So, the answer is B. The pressure inside the tires increased.
Is it illegal for fracking companies to let water that has been used for fracking deep back into the ground ?
Answer:
It is illegal
Explanation:
Fracking involves drilling deep into the earth crust in which a water mixture with high pressure is directed at the rock with the purpose of releasing the gas inside. This process is common in the exploration of natural gas and other hydrocarbons.
It is however illegal because the water are mostly contaminated due to the hydrocarbons present and harmful to life. It is advisable and the best to remove the water and recycle them in treatment plants
1. What can you conclude about the figure?
a. The arrow locations represent precision.
b. The arrow locations represent both high accuracy and
good precision.
c. The arrows have been thrown accurately toward the
bulls-eye.
d. The arrow locations represent neither accuracy
nor precision.
Answer : The correct option is, (d) The arrow locations represent neither accuracy nor precision.
Explanation :
Precision : It is defined as the closeness of two or more measurements to each other.
For Example: If we measure a length 4 times and we get 5.8 m each time. Then the measurement is very precise.
Accuracy : It is defined as the closeness of a measured value to a standard or known value.
For Example: If the weight of the substance is 40 kg and one person measures 39.9 kg and another person measures 39.8 kg. Then, the weight measured by first person is more accurate.
Hence, we from this we conclude that the arrow locations represent neither accuracy nor precision.
Answer : The correct option is, (d) The arrow locations represent neither accuracy nor precision.
Explanation :
Precision : It is defined as the closeness of two or more measurements to each other.
For Example: If we measure a length 4 times and we get 5.8 m each time. Then the measurement is very precise.
Accuracy : It is defined as the closeness of a measured value to a standard or known value.
For Example: If the weight of the substance is 40 kg and one person measures 39.9 kg and another person measures 39.8 kg. Then, the weight measured by first person is more accurate.
Hence, we from this we conclude that the arrow locations represent neither accuracy nor precision.
What is the limiting reactant?
3. 0.20mol AsCl, react with 0.25mol H.O
Answer:
Explanation:
0.20/4 = 0.05 for arsenic trichloide.
0.25/6 = 0.04 for water.
This means that water is the limiting reactant.
4. A cube has a length of 6 cm on one side. What would be the cube's densit
if it has a mass of 4,169 grams? What substance is it?
I really need help
Describe wildfires. How is climate change impacting wildfires ?
Answer:
Hey mate.......
Explanation:
This is ur answer......
Climate change has been a key factor in increasing the risk and extent of wildfires in the Western United States. Research shows that changes in climate create warmer, drier conditions. Increased drought, and a longer fire season are boosting these increases in wildfire risk. But global warming has changed some of the underlying variables that make wildfires more or less likely to occur every year. Warmer temperatures increase the likelihood that fires will burn more intensely. They also cause snow to melt sooner, and lead to drier soils, forests, and plants, which act as kindling.
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gnoring electron repulsion, the ground state energy of helium is related to that of hydrogen by a factor:
Ignoring electron repulsion, the ground state energy of helium can be related to that of hydrogen by a factor of 4.
This is due to the fact that the ground state energy of an atom is determined by the total energy of its electrons, which is primarily determined by their positions and motions around the nucleus. In the case of hydrogen, the ground state energy is determined by the electron's interaction with the positively charged nucleus. This interaction results in a specific energy level that the electron can occupy.
However, in the case of helium, there are two electrons that occupy the same space and interact with the same nucleus. This results in the phenomenon known as electron repulsion, which makes the energy level of helium higher than that of hydrogen. To ignore electron repulsion means to assume that the two electrons in helium do not interact with each other, which allows us to treat helium as if it had only one electron.
By doing this, the energy level of helium becomes comparable to that of hydrogen, and we can relate them by a factor of 4, which is the ratio of the charge of the helium nucleus to that of the hydrogen nucleus. In summary, ignoring electron repulsion allows us to relate the ground state energy of helium to that of hydrogen by a factor of 4, which is a useful approximation in certain situations.
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What is the name for this molecule? a skeletal model of an 8-carbon zig zag chain. there is a double bond between the first and second carbons. nonene nonane 1-octyne 1-octene
The name of the compound by using the IUPAC nomenclature of organic compounds is 1 -octene. The correct option is the last option - 1-octene.
Nomenclature of Organic compoundsFrom the question, we are to determine the name of the given molecule.
To name the compound, we will follow the IUPAC rules.
Some of IUPAC rules are
Find the longest continuous carbon chain. Determine the root name for this parent chain.For Alkenes (organic compounds with double bond), number the chain of carbons that includes the C=C so that the C=C has the lower position number. Change “ane” to “ene” and assign a position number to the first carbon of the C=C.The given compound has 8 carbons and a double bond. The root name of the compound is octane.
By IUPAC rules, the compound is an Octene.
Since the double bond is between carbon-1 and carbon-2. The compound becomes 1-octene.
Hence, the name of the compound by using the IUPAC nomenclature of organic compounds is 1 -octene. The correct option is the last option - 1-octene.
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The diagram for the compound is attached below.
How much energy does it take to boil 100 mL of water? (Refer to table of constants for water. )
A. 100 mL × 1g divided by 1mL × 1mol divided by 18. 02g × 6. 03 kJ/mol = 33. 5 kJ
B. 100 mL × 1g divided by 1mL × 1mol divided by 18. 02g × (–285. 83 kJ)/mol = –1586 kJ
C. 100 mL × 1g divided by 1mL × 1mol divided by 18. 02g × 40. 65 kJ/mol = 226 kJ
D. 100 mL × 1g divided by 1mL × 1mol divided by 18. 02g × 4. 186 kJ/mol = 23. 2 kJ
Therefore, it takes approximately 23.2 kJ of energy to boil 100 mL of water.
The correct answer is D. 100 mL × 1g divided by 1mL × 1mol divided by 18.02g × 4.186 kJ/mol = 23.2 kJ
To calculate the energy required to boil 100 mL of water, we need to use the specific heat capacity of water, which is approximately 4.186 J/g·°C. The molar mass of water is 18.02 g/mol.
First, we convert the volume of water from milliliters to grams:
100 mL × 1 g/1 mL = 100 g
Then, we calculate the number of moles of water:
100 g × 1 mol/18.02 g = 5.548 mol
Finally, we multiply the number of moles by the molar heat of vaporization of water, which is approximately 40.65 kJ/mol:
5.548 mol × 4.186 kJ/mol = 23.2 kJ
Therefore, it takes approximately 23.2 kJ of energy to boil 100 mL of water.
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how many moles of alpha pinene oxide are in 0.25 ml
There are number of moles of alpha-pinene oxide in 0.25 mL.
To determine the number of moles of alpha-pinene oxide in 0.25 mL, we need to know the density and molecular weight of alpha-pinene oxide.
Density of alpha-pinene oxide = 0.926 g/mL
The molecular weight of alpha-pinene oxide = 152.24 g/mol
First, we need to convert the volume from mL to L:
0.25 mL = 0.00025 L
Next, we can use the density to find the mass of alpha-pinene oxide in 0.25 mL:
Mass = Volume × Density
Mass = 0.00025 L × 0.926 g/mL
Mass = 0.0002315 g
Finally, we can use the molecular weight to find the number of moles:
Moles = Mass / Molecular Weight
Moles = 0.0002315 g / 152.24 g/mol
Moles = \(1.52 \times 10^{-6} mol\)
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How do you draw a Lewis dot diagram?
The entire number of valence electrons should be known. Step 2: Outline the molecule's skeletal structure. Step 3: Form each bond in the skeletal structure using two valence electrons Lewis.
The element symbol for an atom is covered in dots that represent the electrons in its valence shell, which is known as the Lewis dot structure or electron-dot symbol. A single dot represents the unpaired electron in the valence shell, whereas a pair of dots represents the paired electrons.
The number of valence e- atoms that each atom contributes to the molecule is counted when designing Lewis dot structures.
With the exception of H, which is only encircled by two electrons, place electron pairs around each atom so that there are eight electrons around each atom (octet rule).
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How much energy does a wave with a frequency of 3.78 x 1010 Hz have?
The energy of the wave of frequency 3.78×10¹⁰ Hz is 2.5×10⁻²³ J.
What is energy?Energy is the ability or the capacity to perform work.
To calculate the energy of the wave, we use the formula below.
Formula:
E = hf......... Equation 1Where:
E = Energy of the waveh = Planck's constantf = Frequency of the waveFrom the question,
Given:
f = 3.78×10¹⁰ Hzh = 6.63×10⁻³⁴ J/HzSubstitute these values into equation 1
E = 3.78×10¹⁰×6.63×10⁻³⁴ E = 2.5×10⁻²³ JHence, the energy of the wave is 2.5×10⁻²³ J.
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Moving to another question will save this response. Question 7 140 Ba has a half-life of 283.2 hours. How long would it take for 35 mg of 140 OA. 1452.6 hours OB. 9912.0 hours OC. 1006.9 hours D. 3.6 hours Ba in a sample to decay to 1.0 mg? TY NA
The total time required for the decay is approximately 1416.0 hours, which is closest to the given option C. 1006.9 hours.
Option (C) is correct.
To calculate the number of half-lives required for the decay. The half-life of 140 Ba is given as 283.2 hours.
First, we calculate the fraction of the original amount remaining after each half-life. Since the half-life represents the time it takes for half of the substance to decay, the fraction remaining after each half-life is 1/2.
To find the number of half-lives required to decay from 35 mg to 1.0 mg, we can set up the following equation:
(35 mg) * (1/2)ⁿ = 1.0 mg
Where 'n' is the number of half-lives.
Now, let's solve for 'n':
(1/2)ⁿ = 1.0 mg / 35 mg
(1/2)ⁿ = 0.02857
To find 'n', we can take the logarithm (base 1/2) of both sides:
n = log base 1/2 (0.02857)
Using the logarithmic property, we know that log base a (b) = log base c (b) / log base c (a):
n = log (0.02857) / log (1/2)
Using a calculator, we can find:
n ≈ 4.243
Since 'n' represents the number of half-lives, and we usually round up to the nearest whole number for half-life calculations, we get:
n ≈ 5
Therefore, it would take approximately 5 half-lives for the 35 mg sample of 140 Ba to decay to 1.0 mg.
To calculate the total time required, we multiply the half-life by the number of half-lives:
Total time = 283.2 hours * 5
Total time ≈ 1416 hours
Rounding to one decimal place, the total time required for the decay is approximately 1416.0 hours, which is closest to the given option C. 1006.9 hours.
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A constant voltage rectifier is normally adjusted by changing
A) primary transformer taps
B) series resistor
C) parallel resistor
D) secondary transformer taps
E) third transformer taps
A constant voltage rectifier is normally adjusted by changing the secondary transformer taps. Therefore the correct option is option D.
The secondary transformer taps control the rectifier circuit's output voltage. The voltage level of the output of the transformer can be changed to a desired value by choosing various taps on the secondary winding.
The output voltage is unaffected by changing the primary transformer taps, which are utilised to match the input voltage to the rectifier circuit. Although they do not directly affect the output voltage level, series and parallel resistors are employed to manage the current flow and the ripple in the output voltage.
In rectifier circuits, the third transformer taps are not frequently employed. Therefore the correct option is option D.
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The n = 5 to n = 3 transition in the bohr hydrogen atom corresponds to the __________ of a photon with a wavelength of __________ nm.
The n = 5 to n = 3 transition in the bohr hydrogen atom corresponds to the emission of a photon with a wavelength of 1280 nm.
Why is Bohr's model limited to hydrogen?Because it does not account for forces owing to inter-electronic attractions, Bohr's atomic model is only valid for single electron species.
The Bohr Model of the Hydrogen Atom presented the planetary model initially, but an assumption about electrons was subsequently established. The premise was that the structure of atoms could be quantized. Bohr hypothesised that electrons orbited the nucleus in fixed-radius orbits or shells.
Electrons orbit the nucleus in fixed-size, fixed-energy orbits. The orbit's energy is proportional to its size. The smallest orbit has the lowest energy. When an electron travels from one orbit to another, it absorbs or emits radiation.
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Question 8
Using Henry's Law: Sz/P1-S2/P2
To increase the solubility of a gas at constant temperature and 202kPa pressure from
0.85g/L to 5.1g/L, the pressure would have to be increased to:
A.505kPa
B.17.2kPa
C.606kPa
D.1212kPa
Answer:
D
Explanation:
plug the numbers
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calculate the van't hoff factor (i) for kbr at this concentration.
1. When frequency increases energy:
a) Increase and wavelength increases
b) Increases and wavelength decreases
c) decreases and wavelength decreases
d) decreases and wavelength increases
What was the function for this procedure: Addition of ethanol to filtered extract
The function of this procedure, which involves the addition of ethanol to a filtered extract, is to precipitate and separate compounds of interest from the mixture. Ethanol serves as a precipitating agent, causing specific substances to become insoluble and form solid particles.
The filtered extract refers to the mixture obtained after removing solid impurities. The procedure can be broken down into the following steps:
1. Obtain a filtered extract by separating solid impurities from a liquid mixture.
2. Add ethanol to the filtered extract. The ethanol induces precipitation of the desired compounds.
3. Allow the mixture to settle, and the precipitated compounds will form solid particles.
4. Separate the solid particles from the liquid by methods such as centrifugation or filtration.
The reason for this procedure is that ethanol promotes the separation of specific compounds from the mixture, making it easier to isolate and study them. This is important in various fields such as chemistry, biology, and pharmaceutical research.
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More than one-third of all accidental fires in food-service operations are caused by
Fire is a risk in all commercial kitchens. Open flames, grease, poor house-keeping practices, electrical hazards and flammable materials are common causes of restaurant fires.
What is an accidental fire?
Accidental fires are those in which the proven cause does not involve any deliberate human act to ignite or spread the fire.
Open flames, grease, poor house-keeping practices, electrical hazards and flammable materials are common causes of restaurant fires. Employers must implement effective administrative controls to protect employees and the business from the dangers of fire.
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In two or more complete sentences, compare the four different types of organic molecules in living organisms. Write
your answer in the essay box below.
(SCIENCE)
Answer:
The four different types of organic molecules in living organisms are carbohydrates, lipids, proteins, and nucleic acids. Carbohydrates are composed of carbon, hydrogen, and oxygen atoms and are a source of energy for the body. Lipids are composed of carbon, hydrogen, and oxygen atoms and are important for energy storage, insulation, and cell membrane structure. Proteins are composed of amino acids and are involved in various biological functions, such as enzyme catalysis, muscle contraction, and immune response. Nucleic acids are composed of nucleotides and store genetic information. All four types of organic molecules are essential for life and work together to maintain biological processes.
Given the density of ethanol (0.785 g/mol), the Kb value (1.22), molality of 10.5, and 14 mL of ethanol, determine the mass and molecular weight of 1.5 grams of an unknown solute in 1 kg of solvent.
The molar mass of the unknown solute is 0.15 g/mol.
What is the molecular mass of the compound?We know that the boiling point is one of the colligative properties thus it depends on the amount of the substance. Then we can be able to recall that;
Molality of the solute = Number of moles/ mass of the solvent
We have that;
Molality = 10.5 m
Number of moles of the solute = 1.5 g/M
Where M is the molar mass of the solute
Mass of the solution = 1Kg'
Then;
10.5 = 1.5 g/M/1
10.5 = 1.5 g/M
M = 1.5 g/10.5
M = 0.15 g/mol
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what percentage will have heterozygous genotype?
Answer:
In another example (shown below) if the parent plants both have heterozygous (YG) genotypes, there will be 25% GG offspring in average. These percentages are determined based on the fact that each of the 4 offspring boxes in a Punnett square is 25% (1 out of 4)
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