A company is started by 4 friends. The company was Erica’s idea, so she wants to fill 70% of the orders. Jen, Heather, and Tonya each agree to fill 10% of the orders. After a successful first year, Erica wants to determine if the distribution of the number of orders filled is adhering to the agreed-upon percentages. To do so, she selects a random sample of 100 orders from the large number of orders that were filled and determines who filled the order. What is the value of the chi-square test statistic and the P-value of this test?

Find the chi-square table here.

χ2 = 8.53, P-value is between 0.025 and 0.05
χ2 = 8.53, P-value is between 0.05 and 0.10
χ2 = 11.20, P-value is between 0.01 and 0.02
χ2 = 11.20, P-value is between 0.025 and 0.05

The correct answer is d. Wilson.

In the novel "The Red Badge of Courage" by Stephen Crane, Henry, the protagonist, forms a close bond with a character named Wilson. Wilson is introduced as a loud and confident soldier who becomes Henry's comrade and fights alongside him throughout the battle.

They share moments of fear, doubt, and camaraderie on the battlefield, facing the horrors of war together. Wilson plays a significant role in Henry's journey, providing support and friendship until the end of the battle. Their bond symbolizes the connection forged between soldiers in the midst of the chaos and adversity of war. Thus, the character Wilson fights beside Henry until the end of the battle in the novel.

To learn more about Protagonist - brainly.com/question/1103269

#SPJ11

Answer:

y>-2x-3

Step-by-step explanation:

I think, not sure.

Answer:

first discount for Q7 is $54.3915

the next discount is $48.95235

for Q8 is

Step-by-step explanation:

you are a very nice person for helping your mom. good luck for this!

ok let's work on question 7 first.

$63.99 is the cost of a skateboard.

  15% of 63.99 = 10% + 5%

  10% of 63.99 = 6.399          (move the decimal one place to the left)

   5% of 63.99 = 1/2 of 6.399

     1/2 x 6.399 = 3.1995

6.399 + 3.1995 = 9.5985

ok, so that's 15% of 63.99

now we need to take away 9.5985 from 63.99

63.99 - 9.5985 = 54.3915

the discount price of the skateboard is $54.3915

a further 10% is $5.43915

so take off that from the discount,

54.3915 - 5.43915 = 48.95235

the final price is $48.95235

QUESTION 8

         shop A = 6.95 x 40

     6.95 x 40 = $278

         shop B = 20% of 325

20/100 * 325 = 65

      325 - 65 = 260

therefore, shop B is cheaper.

hope this helped, good luck!

Answer:

i think its to late to answer... sorry i didnt see it sooner.

Step-by-step explanation:

ill take that brainliest

When \($a < 1$\)\($\delta=-1 \pm j \sqrt{2 a} \rightarrow$\) Here two solutions oscillate when a is negative, the system has repeated eigen value when \($a=0$\), when \($a=0$\\\), then both solutions decay exponentially without oscillating,

The given Vector equation, When a is negative real number then both solutions grow exponentially with system oscillating.

\($$\left.\begin{array}{l}y^{\prime}=\text { Ay } \\A=\left(\begin{array}{cc}-1 & a \\2 & -1\end{array}\right)\end{array}\right\}\)

Now we will solve 2-

           \($$|A-\delta I|=\left|\begin{array}{cc}-1-\lambda & a \\2 & -1-\lambda\end{array}\right|=0$$\)

Now multiply, we get.

\($$\begin{aligned}& (-1-\lambda)(-1-\lambda)-2 a=0 \\& 1+2 \lambda^2-2 a=0 \\& s^2+2 \lambda+1-2 a=0 \text { (1) }\end{aligned}$$\)

Now we will find both 2 values of d.

\($\left(\begin{array}{c}\text { if } a x^2+b x+c=0 \\ d=\frac{-2 \pm \sqrt{(2)^2-(4)(1)(1-2 a)}}{2(1)} \leftarrow\left(x=\frac{-b \pm \sqrt{b^2-4-a c}}{2 a}\right.\end{array}\right)$$$\)

\(& =-1 \pm \frac{1}{2} \sqrt{4-4+8 a} \\\lambda & =-1 \pm \sqrt{2 a} .\end{aligned}$$\)

(a) when \($a < 1$\)\($\delta=-1 \pm j \sqrt{2 a} \rightarrow$\) Here two solutions oscillate when a is negative.

(b) put \($a=0$\)

\($$\begin{aligned}& d=-1 \pm \sqrt{2 a} \\& d=-1 \pm \sqrt{2 \times 0} \\& d=-1 \pm 0 \\& r=-1\end{aligned}$$\)

mean \($s_1=\sqrt{2}_2=-1$\), here system has repeated eigen value when \($a=0$\)

(c) when \($a=0$\\\), then both solutions decay exponentially without oscillating.

(d) Now, when use put \($a=2$.\)

\($$\begin{aligned}& \delta=-1 \pm \sqrt{2 a} \\& \text { when } \\& a=2 \\& \delta=-1 \pm \sqrt{2 \times 2} \\& s_1=-1 \pm 2 \\& \delta_1=1\end{aligned}$$\)

In the one of the solution decay exponentially and the other Grow exponentially.

(e). When a is negative real number then both solutions grow exponentially with system oscillating.

Therefore,When \($a < 1$\)\($\delta=-1 \pm j \sqrt{2 a} \rightarrow$\) Here two solutions oscillate when a is negative, the system has repeated eigen value when \($a=0$\), when \($a=0$\\\), then both solutions decay exponentially without oscillating,

The given Vector equation, When a is negative real number then both solutions grow exponentially with system oscillating.

For more such questions on Vector equation:

https://brainly.com/question/18848864

#SPJ4

Answer:

\((-1) \times (-2) \times (-3) \times (-4) \times (-5) = - 120\)

Step-by-step explanation:

By the rule of Integer multiplications,

\((-1) \times (-2) \times (-3) \times (-4) \times (-5) = [ (-1) \times (-2) ] \times [(-3) \times (-4)] \times (-5)\)

                                                      \(= [2] \times [12] \times (-5)\)

                                                      \(= -120\)

Learn more about Integer here,

brainly.in/question/54087058

Given the following parameters

To find the mean of the data, we will have to use

Using the confidence interval formula of

Substitute for all values to find the confidence interval.

Hence, the confidence interval is

The critical value is

The standard error of the mean is

The confidence interval is

The minimum wage set by the government at $7.50 per hour does not result in a pay cut for unskilled workers, as it is below the equilibrium wage of $8.00 per hour.

The wage rate remains unchanged, and the labor market remains in balance.

The statement is false.

False.

The equilibrium wage in the market for unskilled labor is $8.00 per hour, which means that the market naturally sets the wage rate at this level, based on the forces of supply and demand.

The government then sets a minimum wage at $7.50 per hour.

Since the minimum wage is below the equilibrium wage, it does not directly impact the wage rate for unskilled workers.
The equilibrium wage represents the point at which the supply of labor (the number of workers willing to work at a given wage) equals the demand for labor (the number of workers that employers are willing to hire at a given wage).

In this case, both workers and employers are satisfied with the $8.00 per hour wage, and the labor market is balanced.
The government sets a minimum wage below the equilibrium wage, it essentially sets a wage floor that is not binding. Employers are still willing to pay the equilibrium wage of $8.00 per hour, and workers are still willing to accept this wage.

The wage for unskilled workers remains at $8.00 per hour, and there is no pay cut of 50 cents per hour.

For similar questions on Wages

https://brainly.com/question/29251394

#SPJ11

Answer:

28.125

Step-by-step explanation:

A bar weights 3 ounces, she has a box of 150 so you multiply

150 times 3 = 450

well one pound equals 16 ounces, so you divide

450 divide by 16 = 28.125

There is no pair of nonzero integers such that both the sum and the difference of their squares are perfect squares.

Let's assume that there exist a pair of nonzero integers (m, n) such that the sum and the difference of their squares are also perfect squares. We can write the equations as:

m^2 + n^2 = p^2

m^2 - n^2 = q^2

Adding these equations, we get:

2m^2 = p^2 + q^2

Since p and q are integers, the right-hand side is even. This implies that m must be even, so we can write m = 2k for some integer k. Substituting this into the equation, we have:

p^2 + q^2 = 8k^2

For k = 1, we have p^2 + q^2 = 8, which has no solution in integers. Therefore, k must be greater than 1.

Now, let's assume that k is odd. In this case, both p and q must be odd (since p^2 + q^2 is even), which implies p^2 ≡ q^2 ≡ 1 (mod 4). However, this leads to the contradiction that 8k^2 ≡ 2 (mod 4). Hence, k must be even, say k = 2l for some integer l. Substituting this into the equation p^2 + q^2 = 8k^2, we have:

(p/2)^2 + (q/2)^2 = 2l^2

Thus, we have obtained another pair of integers (p/2, q/2) such that both the sum and the difference of their squares are perfect squares. This process can be continued, leading to an infinite descent, which is not possible. Therefore, we arrive at a contradiction.

Hence, there is no pair of nonzero integers such that both the sum and the difference of their squares are perfect squares.

Learn more about nonzero integers

https://brainly.com/question/29291332

#SPJ11

Answer: 1. infinitely many solutions

2. no solution

3. one solution

4. no solution

5. infinitely many solutions

Step-by-step explanation:

1. infinitely many solutions - when it is consistent and the number of variables is more than the number of nonzero rows

2. no solution - would mean that there is no answer to the equation. It is impossible for the equation to be true no matter what value we assign to the variable.

3. one solution - which is when one variable equals one number

4. no solution

5. infinitely many solutions

Answer:

I'm pretty sure it's C I may be wrong though

Step-by-step explanation:

Answer:

It is 59,275.74 grams

Step-by-step explanation:

• Molecular mass of carbon dioxide

\( = (12 \times 1) + (16 \times 2) \\ = 12 + 32 \\ = 44 \: g\)

[ molar masses: C = 12 g, O = 16 g ]

• From avogadro's number, it says 1 mole contains 6.02 × 10^23 molecules or atoms.

But 1 mole is equivalent to its molar mass in terms of weight, therefore;

\({ \sf{6.02 \times {10}^{23} \: molecules = 44 \: g }}\\ { \sf{8.11 \times {10}^{26} \: molecules =( \frac{8.11 \times {10}^{26} }{6.02 \times {10}^{23} } \times 44) \: g}} \\ \\ = { \boxed{ \boxed{ \bf{59275.7 \: \: g}}}}\)

Answer:

a) Low: 45 Q1=80 Q2=89 Q3=94 High=100 b) Look at attached image

Step-by-step explanation:

Organized numbers: 45,70,72|,80,|82,85,88|,89,|90,92,92|,94,|98,100,100

mark medians

Graph created in Desmos

Interactions involving dummy variables can provide insights into the different effects of independent variables across categories.

1. Dummy variables are binary variables that represent categorical variables in a regression analysis. When interactions are included between dummy variables and other independent variables, it allows for differential effects of the independent variables based on the different levels of the categorical variable.

For example, let's consider a regression model to predict income based on education level and gender. We can include an interaction term between education level (represented by dummy variables for different levels) and gender. This interaction term allows us to examine whether the effect of education level on income differs between males and females. It helps capture any gender-specific differences in the relationship between education and income.

1.2 The linear probability model (LPM) is a common approach to estimate the probability of an event occurring using a linear regression framework. However, it has several problems:

1. The predicted probabilities from the LPM can fall outside the [0, 1] range: Since the LPM does not impose any restrictions on the predicted probabilities, they can sometimes exceed the valid probability range. This violates the assumption of probabilities being bounded between 0 and 1.

2. Heteroscedasticity: The LPM assumes constant error variance across the range of the predictors. However, in practice, the variability of the error term may change with different levels of the predictors, resulting in heteroscedasticity. This violates the assumption of homoscedasticity.

3. Non-linearity: The LPM assumes a linear relationship between the predictors and the probability of the event. However, this may not always be the case, and using a linear model can result in misspecification.

To remedy these problems, an alternative to the LPM is to use logistic regression or probit regression models. These models explicitly model the probability of an event occurring and address the issues mentioned above. They provide predicted probabilities that fall within the valid range of 0 to 1, account for heteroscedasticity, and allow for non-linear relationships between the predictors and the probability of the event.

Learn more about LPM here:

https://brainly.com/question/30890632

#SPJ4

For any positive integer n, the theorem states that the integer 8^n + 13 is divisible by 7. This means that when we raise 8 to any positive power and add 13, the resulting number will always be divisible by 7.

To understand why 8^n + 13 is divisible by 7 for any positive integer n, we can use the concept of modular arithmetic. Modular arithmetic deals with remainders when dividing numbers. In this case, we are interested in divisibility by 7.

Let's examine the pattern when we raise 8 to different powers and add 13:

- For n = 1: 8^1 + 13 = 8 + 13 = 21, which is divisible by 7.

- For n = 2: 8^2 + 13 = 64 + 13 = 77, which is divisible by 7.

- For n = 3: 8^3 + 13 = 512 + 13 = 525, which is divisible by 7.

We can observe that for each value of n, 8^n + 13 results in a number that is divisible by 7. This pattern continues for any positive integer n.

To provide a more formal explanation, we can use modular arithmetic notation. The statement can be expressed as: 8^n + 13 ≡ 0 (mod 7). This notation means that 8^n + 13 leaves a remainder of 0 when divided by 7, or in other words, it is divisible by 7.

This theorem can be proven using mathematical induction, where we show that the statement holds for n = 1, and assuming it holds for a particular value of n, we prove that it also holds for n + 1. The proof involves manipulating the expression 8^n + 13 using the properties of modular arithmetic.

Learn more about mathematical induction here:

https://brainly.com/question/31244444

#SPJ11

Complete question:

Main theorem. Assume that n is any positive integer. Then the integer \(8^{n}\)+13 is divisible by 7.

Answer:

No

Step-by-step explanation:

For 3 to be factor your finale number has to be divisible by 3, so with that information all you have to do is subtract 245-16 which is 229, and if you divide 229 by 3 it does not equal a whole number so 3 cannot be a factor.

I hope this helps, and have a great day! :D

Answer:

\(log_{12} \text{ } 60 + 3=x\)

Step-by-step explanation:

For some exponential equation \(a^{x} =y\)  the logarithmic form becomes \(x=log_a \text{ } y\)

The base of the exponent or power becomes the base of the logarithm

so,

\(12^{(x-3)} =60\)  becomes,  \(x - 3=log_{12} \text{ } 60\)  or  \(log_{12} \text{ } 60 = x -3\)

We simplify by getting x on the one side, to get:

\(log_{12} \text{ } 60 + 3=x\)

The simplification of the expression 3(x + 3y) - 5(x -y) is  -2x + 14y.

According to the given question.

We have an expression

3(x + 3y) -5(x -y)

As we know that, the simplification of an expression means to write an equivalent expression which contains no similar terms.

Therefore, the simplificantion of the expression  3(x + 3y) - 5(x -y) is given by

3(x + 3y) - 5(x -y)

= 3x + 9y - 5x + 5y     (by distributive rule)

= 3x - 5x + 9y + 5y

= -2x + 14y                    (adding and subtracting the like terms)

Hence, the simplification of the expression 3(x + 3y) - 5(x -y) is  -2x + 14y.

Find out more information about expression here:

https://brainly.com/question/14083225

#SPJ4

The probability she makes at least 65 is 0.0139.

What is probability?

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a proposition is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.

\(\begin{aligned}P(x \geq 65) & =1-P(x < 65) \\& =1-P\left(\frac{x-\mu}{n} < \frac{65-56}{4.0988}\right) \\& =1-P(z < 2.1958) \\& =1-0.9861 \\& =0.0139\end{aligned}\)

To learn more about probability  visit:https://brainly.com/question/11234923

#SPJ4

Answer:

Step-by-step explanation:

What variable are you solving for?

The inverse function of f(x) = 7x and verifying that it satisfies the properties of inverse function.

The inverse function of f(x), we need to solve for x in terms of f(x). Starting with f(x) = 7x,

we can divide both sides by 7 to get x = f(x)/7.

So the inverse function of f(x) is:

f^(-1)(x) = x/7

This inverse function satisfies the properties of inverse functions.

The first property is that f(f^(-1)(x)) = x for all x in the domain of f^(-1).

Plugging in f^(-1)(x) = x/7 into f(x), we get:

f(f^(-1)(x)) = f(x/7) = 7(x/7) = x

So f(f^(-1)(x)) does indeed equal x.

The second property is that f^(-1)(f(x)) = x for all x in the domain of f.

Plugging in f(x) = 7x into f^(-1)(x), we get:

f^(-1)(f(x)) = f^(-1)(7x) = (7x)/7 = x

So f^(-1)(f(x)) also equals x.

We have successfully found the inverse function of f(x) and verified that it satisfies the properties of inverse functions.

To learn more about Inverse function

https://brainly.com/question/15066392

#SPJ11

49 and 64 are perfect squares, while 23 and 41 are not.

-If we are asked to identify a statement that is true for all of the integers 23, 41, 49, 64, one possible correct statement is: All of the integers are greater than 20.

-If we are asked to identify a statement that is false for all of the integers 23, 41, 49, 64, one possible correct statement is: All of the integers are perfect squares.

-If we are asked to identify a statement that is true for some of the integers 23, 41, 49, 64 and false for others, one possible correct statement is: Only one of the integers is a prime number. In this case, 23 and 41 are prime, while 49 and 64 are not.

-If we are asked to identify a statement that is true for any two of the integers 23, 41, 49, 64 and false for the other two, one possible correct statement is: Exactly two of the integers are perfect squares. In this case, 49 and 64 are perfect squares, while 23 and 41 are not.

To know more about "Perfect squares" refer here:

https://brainly.com/question/1746559#

#SPJ11

The probability that at least one of the pets selected is a puppy is approximately 0.7887 or 78.87%.

To calculate the probability that at least one of the pets is a puppy, we can find the probability of the complement event (none of the pets being a puppy) and subtract it from 1.

The total number of pets in the store is 6 puppies + 9 kittens + 4 lizards + 5 snakes = 24.

The probability of selecting a pet that is not a puppy on the first selection is (24 - 6) / 24 = 18 / 24 = 3 / 4.

Similarly, on the second selection, the probability of selecting a pet that is not a puppy is (24 - 6 - 1) / (24 - 1) = 17 / 23.

For the third selection, it is (24 - 6 - 1 - 1) / (24 - 1 - 1) = 16 / 22.

For the fourth selection, it is (24 - 6 - 1 - 1 - 1) / (24 - 1 - 1 - 1) = 15 / 21.

For the fifth selection, it is (24 - 6 - 1 - 1 - 1 - 1) / (24 - 1 - 1 - 1 - 1) = 14 / 20 = 7 / 10.

To find the probability that none of the pets is a puppy, we multiply the probabilities of not selecting a puppy on each selection:

(3/4) * (17/23) * (16/22) * (15/21) * (7/10) = 20460 / 96840 = 0.2113 (approximately).

Finally, to find the probability that at least one of the pets is a puppy, we subtract the probability of the complement event from 1:

1 - 0.2113 = 0.7887 (approximately).

Know more about probability here:

https://brainly.com/question/30034780

#SPJ11

The appropriate critical value for constructing a confidence interval in this setting is 1.88.

To find the appropriate critical value for constructing a confidence interval at a 94% confidence level, we can use a standard normal distribution table or a calculator.

First, we need to find the value of alpha, which is the significance level, which is equal to 1 - the confidence level. In this case, alpha is equal to 1 - 0.94 = 0.06.

Next, we need to find the critical value z* from the standard normal distribution table or calculator, which corresponds to the area to the right of z* being equal to alpha/2 = 0.03.

Using a standard normal distribution table or calculator, we can find that the critical value z* is approximately 1.88.

Learn more about critical value here

brainly.com/question/28233701

#SPJ4

Answer:

2' 11'

Step-by-step explanation:

Answer:

1.83333333333

Step-by-step explanation:

i dunno if these were supposed to be fractions

During the 1920s, buying stock on credit was called buying on margin or margin trading. Hence, option C is correct.

An act of buying shares or securities of a company without the actual need of having funds in the account, is known as margin trading. A credit facility is granted by the broker to the trader to do margin trading.

In case the trader generates a profit while buying on margin, he or she would get only an amount of the profit made by him or her over such trade. In case of losses, the balance amount became the liability of the trader.

Hence, option C states about margin trading.

Learn more about margin trading here:

https://brainly.com/question/23130387

#SPJ2