A company charges $300 for every 2 pounds of oranges sold plus a $3.00 shipping fee,
Based on this information, which graph best shows this relationship between the cost of oranges, y, and the number of pounds,

Answer:

Therefore, the correct statements are A, B, and E.

Explanation:

Based on my knowledge, a vector is a quantity that has both magnitude and direction. A scalar is a quantity that has only magnitude. When a vector is multiplied by a scalar, the magnitude of the vector is multiplied by the absolute value of the scalar, and the direction of the vector is either preserved or reversed depending on the sign of the scalar.

To answer your question, we need to find the component form, magnitude, and direction of the scalar product –4⇀

.

- The component form of −4⇀

is obtained by multiplying each component of ⇀

by –4. Therefore, −4⇀

= ⟨–8, –12⟩. This means that statement A is true.

- The magnitude of −4⇀

is obtained by multiplying the magnitude of ⇀

by 4. The magnitude of ⇀

is √(2^2 + 3^2) = √13. Therefore, the magnitude of −4⇀

is 4√13. This means that statement B is true.

- The direction of −4⇀

is opposite to the direction of ⇀

because the scalar –4 is negative. This means that statement C is false.

- The vector −4⇀

is in the third quadrant because its components are both negative. This means that statement D is false.

- The direction of −4⇀

is 180° greater than the inverse tangent of its components because it is opposite to ⇀

. The inverse tangent of its components is tan^(-1)(–12/–8) = tan^(-1)(3/2). Therefore, the direction of −4⇀

is 180° + tan^(-1)(3/2). This means that statement E is true.

Therefore, the correct statements are A, B, and E.

The expression of "The difference of -10 and the product of p and q" in algebraic notation is pq + 10

From the question, we have the following parameters that can be used in our computation:

The difference of -10 and the product of p and q

The numbers are given as

p and q

The product of p and q means pq

So, we have the following

The difference of -10 and pq

The difference of -10 and pq means

pq + 10

Hence, the expression is pq + 10

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Answer: Yes, this is a linear function between P and M.

Step-by-step explanation:

We can define a function as a relation between two or more variables, like y = f(x).

This function, maps the elements x (the input) into elements y (the output).

We have a rule for a function: Each input x can be mapped into only one output y.

In this case, we have:

P = 0.15*M + 20.

Let's prove that each value of M is related to only one value of P.

Suppose that, for a given M0, we have:

0.15*M0 + 20 = p1

and also for M0, we have:

0.15*M0 + 20 = p2

This means that p1 = p2, so we can not have different outputs for the same input.

This is a linear relation, so each value of M is related to only one value of P.

Then this is a function P(m) = 0.15*M + 20.

Answer:

+4

Step-by-step explanation:

F(x,y)   = 3x+y      and y <= -2x+ 4     sub in for 'y'

          = 3x  + (-2x+4)

          = x + 4

If you look at the graph for   y <= - 2x+4   ( see below)

    you will see that the domain (x values ) can only go from 0 to 4 and the max value is +4     ( rememeber too that y is restricted to >= 0  as is x )

The sum of expected marks is given as follows:

9375.

Each question has four choices, hence the probability of choosing the correct choice is given as follows:

p = 1/4 = 0.25.

Then the expected number of correct answers is given as follows:

E(X) = 0.25 x 150

E(X) = 37.5.

Then the expected grade for a single student is given as follows:

37.5 - 0.25(150 - 37.5) = 9.375.

The expected sum for the 1000 students is then given as follows:

1000 x 9.375 = 9375.

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Answer:

Step-by-step explanation:

10

Ws

The reading that separates the rejected thermometers from the others is given as follows:

1.175 ºC.

The z-score of a measure X of a normally distributed variable that has mean represented by \(\mu\) and standard deviation represented by \(\sigma\) is obtained by the equation presented as follows:

\(Z = \frac{X - \mu}{\sigma}\)

The mean and the standard deviation for this problem are given as follows:

\(\mu = 0, \sigma = 1\)

The 12% higher of temperatures are rejected, hence the 88th percentile is the value of interest, which is X when Z = 1.175.

Hence:

1.175 = X/1

X = 1.175 ºC.

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Answer:

y - 9 = 7(x - 1)

Step-by-step explanation:

The given equation is in Point Slope Form:  y - y₁ = m(x - x₁)

m is the slope, and parallel lines have the same slope (7)

x₁ and y₁ are the coordinates of a point on the line

The angle measures for this problem are given as follows:

The sum of the measures of the internal angles of a triangle is of 180º.

The triangle in this problem is ABC, hence the measure of a is obtained as follows:

a + 68 + 50 = 180

a = 180 - (68 + 50)

a = 62º.

c and d are corresponding angles to angle a, as they are on the same position relative to parallel lines, hence their measures are given as follows:

Angle b is a corresponding interior angle with angle a, hence they are supplementary and it's measure is given as follows:

a + b = 180

62 + b = 180

b = 118º.

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Answer:

The Combined Volume is 9000 Cubic Inches

Step-by-step explanation:

First, volume is the multiplacation of the 3 measurements. So we just need to multiply the 3 sides then add the solution to itself to get the doubled value. This gives you 9000 cubic inches for the 2 coolers.

Answer:

-1.333333

Step-by-step explanation:

:)

have a very nice day

Fraction = 1/1

decimal = 1.0 or 1

percentage = 100%

If \(f(x) = x^2 + 3\), then

\(x = 1.1 \implies y = f(1.1) = 1.1^2 + 3 = 4.21 \\\\ \implies m_{\rm sec} = \dfrac{4.21-1}{4-1} = \dfrac{3.21}3 = \boxed{1.07}\)

\(x=1.01 \implies y = f(1.01) = 4.0201 \\\\ \implies m_{\rm sec} = \dfrac{3.0201}3 = \boxed{1.0067}\)

\(x=1.001 \implies y=f(1.001) = 4.002001 \\\\ \implies m_{\rm sec} = \dfrac{3.002001}3 \approx \boxed{1.0007}\)

\(x=1.0001 \implies y = f(1.0001) = 4.00020001 \\\\ \implies m_{\rm sec} = \dfrac{3.00020001}3 \approx \boxed{1.0001}\)

The slopes of the secant lines are listed below:

Herein we know a quadratic equation and the x-coordinates associated to line secant to the curve, of which we are supposed to determine the measure of the slope of that line by using the following expression:

m = [f(x + Δx) - f(x)] / [Δx]          (1)

If we know that f(x) = x² + 3 and x = 1, then the slopes of the secant lines are, respectively:

Δx = 0.1

f(1) = 1² + 3

f(1) = 4

f(1.1) = 4.21

m = (4.21 - 4) / 0.1

m = 2.1

Δx = 0.01

f(1.01) = 1.01² + 3

f(1.01) = 4.0201

m = (4.0201 - 4) / 0.01

m = 2.01

Δx = 0.001

f(1.001) = 1.001² + 3

f(1.001) = 4.002

m = (4.002 - 4) / 0.001

m = 2

Δx = 1.0001

f(1.0001) = 1.0001² + 3

f(1.0001) = 4.0002

m = (4.0002 - 4) / 0.0001

m = 2

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Answer:

19 players

Step-by-step explanation:

If the team raises $1396.75 and the bus costed $850.50 then the remaining budget is = 546.75

If each meal is $28.75 then you could buy 19 meals for 19 players to take to the tournament.

Assuming x - a = y - a and x + 7 = y + 7

Original Point P (4, -2)

Translated to Point P' (x + 3, y - a) = (4 + 3, -2 - a) = (7, -2 - a)

Translated to next point P'' = (x - b, y + 7) = (7 - b, -2 - a + 7) = (7 - b, 5 - a) = (-5, 8)

From the above changes, we can see that 7 - b = -5 and 5 - a = 8. Therefore:

The value of a = -3 and b = 12.

The point P' (7, -2 - a) = (7, -2 - (-3)) = (7, 1). Point P' is at (7, 1).

To check if this is right, let's look at the original point again and its transformations.

P (4, -2) translated to (x + 3, y - a) = (4 + 3, -2 - (-3)) = (7, 1).

P' (7, 1) is then translated to ( x - b, y + 7) = (7 - 12, 1 + 7) = (-5, 8).

As mentioned in the question, P'' is indeed found at (-5, 8).

Answer:x=2y=3

Step-by-step explanation: I did this before

Using Maxwell's equations, we can determine the magnetic flux density. One of the Maxwell's equations is:

\(\displaystyle \nabla \times \mathbf{H} = \mathbf{J} + \frac{\partial \mathbf{D}}{\partial t}\),

where \(\displaystyle \nabla \times \mathbf{H}\) is the curl of the magnetic field intensity \(\displaystyle \mathbf{H}\), \(\displaystyle \mathbf{J}\) is the current density, and \(\displaystyle \frac{\partial \mathbf{D}}{\partial t}\) is the time derivative of the electric displacement \(\displaystyle \mathbf{D}\).

In this problem, there is no current density (\(\displaystyle \mathbf{J} =0\)) and no time-varying electric displacement (\(\displaystyle \frac{\partial \mathbf{D}}{\partial t} =0\)). Therefore, the equation simplifies to:

\(\displaystyle \nabla \times \mathbf{H} =0\).

Taking the curl of the given magnetic field intensity \(\displaystyle \mathbf{R} =2\cos( 10^{10} t-600x)\hat{a}_{z}\, \text{Am}\):

\(\displaystyle \nabla \times \mathbf{R} =\nabla \times ( 2\cos( 10^{10} t-600x)\hat{a}_{z}) \, \text{Am}\).

Using the curl identity and applying the chain rule, we can expand the expression:

\(\displaystyle \nabla \times \mathbf{R} =\left( \frac{\partial ( 2\cos( 10^{10} t-600x)) \hat{a}_{z}}{\partial y} -\frac{\partial ( 2\cos( 10^{10} t-600x)) \hat{a}_{z}}{\partial z}\right) \mathrm{d} x\mathrm{d} y\mathrm{d} z\).

Since the magnetic field intensity \(\displaystyle \mathbf{R}\) is not dependent on \(\displaystyle y\) or \(\displaystyle z\), the partial derivatives with respect to \(\displaystyle y\) and \(\displaystyle z\) are zero. Therefore, the expression further simplifies to:

\(\displaystyle \nabla \times \mathbf{R} =-\frac{\partial ( 2\cos( 10^{10} t-600x)) \hat{a}_{z}}{\partial x} \mathrm{d} x\mathrm{d} y\mathrm{d} z\).

Differentiating the cosine function with respect to \(\displaystyle x\):

\(\displaystyle \nabla \times \mathbf{R} =-2( 10^{10}) \sin( 10^{10} t-600x)\hat{a}_{z} \mathrm{d} x\mathrm{d} y\mathrm{d} z\).

Setting this expression equal to zero according to \(\displaystyle \nabla \times \mathbf{H} =0\):

\(\displaystyle -2( 10^{10}) \sin( 10^{10} t-600x)\hat{a}_{z} \mathrm{d} x\mathrm{d} y\mathrm{d} z =0\).

Since the equation should hold for any arbitrary values of \(\displaystyle \mathrm{d} x\), \(\displaystyle \mathrm{d} y\), and \(\displaystyle \mathrm{d} z\), we can equate the coefficient of each term to zero:

\(\displaystyle -2( 10^{10}) \sin( 10^{10} t-600x) =0\).

Simplifying the equation:

\(\displaystyle \sin( 10^{10} t-600x) =0\).

The sine function is equal to zero at certain values of \(\displaystyle ( 10^{10} t-600x) \):

\(\displaystyle 10^{10} t-600x =n\pi\),

where \(\displaystyle n\) is an integer. Rearranging the equation:

\(\displaystyle x =\frac{ 10^{10} t-n\pi }{600}\).

The equation provides a relationship between \(\displaystyle x\) and \(\displaystyle t\), indicating that the magnetic field intensity is constant along lines of constant \(\displaystyle x\) and \(\displaystyle t\). Therefore, the magnetic field intensity is uniform in the given medium.

Since the magnetic flux density \(\displaystyle B\) is related to the magnetic field intensity \(\displaystyle H\) through the equation \(\displaystyle B =\mu H\), where \(\displaystyle \mu\) is the permeability of the medium, we can conclude that the magnetic flux density is also uniform in the medium.

Thus, the correct expression for the magnetic flux density in the given medium is:

\(\displaystyle B =6\cos( 10^{10} t-600x)\hat{a}_{z}\).

Answer:

C- 100 values

Step-by-step explanation:

Answer:

102

Step-by-step explanation:

118-17+1 = 102

Answer:

Question 1:

\({ \tt{(f +G)(x) = ( {x}^{2} + 2x - 3) + (3 {x}^{2} - x + 7)}} \\ \\ { \tt{ = ( {x}^{2} + 3 {x}^{2}) + (2x - x) + ( - 3 + 7) }} \\ \\(f + G)(x) = { \tt{4 {x}^{2} + x + 4 }}\)

Question 2:

\({ \tt{(f - G)(x) = ( {x}^{2} + 2x - 3) - (3 {x}^{2} - x + 7) }} \\ \\ = { \tt{( {x}^{2} - 3 {x}^{2} ) + (2x - ( - x)) + ( - 3 - 7)}} \\ \\ (f - G)(x) = { \tt{ - {2x}^{2} + 3x - 10 }}\)

Answer:

Hello,

Step-by-step explanation:

Focus (4,0)

Directrix: x=-4

See picture.

Answer:

Based on the information given, we know that angles 3 and 4 are supplementary (they add up to 180 degrees) and angles 2 and 4 are vertical angles (they are congruent). Therefore, we can write:

m∠4 + m∠3 = 180 (since angles 3 and 4 are supplementary)

m∠4 = m∠2 (since angles 2 and 4 are vertical angles)

Substituting m∠4 = m∠2 into the first equation, we get:

m∠2 + m∠3 = 180

Now we can solve for m∠2 and m∠3:

m∠3 = 43 (given)

m∠2 = 180 - m∠3 = 180 - 43 = 137

Since angles 1 and 2 are also supplementary, we can find m∠1 by subtracting m∠2 from 180:

m∠1 = 180 - m∠2 = 180 - 137 = 43

Therefore, m∠1 = 43 degrees and m∠2 = 137 degrees.

Answer:

737 747 4

Step-by-step explanation:

74747747

Answer:

no

Step-by-step explanation:

We can relate angles and sides using trigonometric ratios.

In this case, we know So we can write:

Answer: EF = 126.5 ft

Therefore, the rate of change, in cm per minute, of the height when the height is 6 cm is approximately -6 cm/min.

Given,The width of the box = 10 cm Length of the box = 17 cmThe volume of the box = 527 cubic cm/minWe need to find the rate of change, in cm per minute, of the height when the height is 6 cm.We know that the volume of the box is given as:V = l × w × h where, l, w and h are length, width, and height of the box respectively.It is given that the width and length are being held constant.

Therefore, we can write the volume of the box as

:V = constant × h Differentiating both sides with respect to time t, we get:dV/dt = constant × dh/dtNow, it is given that the volume of the box is decreasing at a rate of 527 cubic cm per minute.

Therefore, dV/dt = -527.Substituting the given values in the above equation, we get:

527 = constant × dh/dt

We need to find dh/dt when h = 6 cm.To find constant, we can use the given values of length, width and height.Substituting these values in the formula for the volume of the box, we get:

V = l × w × hV = 17 × 10 × hV = 170h

We know that the volume of the box is given as:V = constant × hSubstituting the value of V and h, we get:

527 = constant × 6 cm

constant = 87.83 cm/minSubstituting the values of constant and h in the equation, we get

-527 = 87.83 × dh/dtdh/dt = -6.0029 ≈ -6 cm/min

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The real GDP in 1984 and 2005 were both $5,000.

A. The GDP price index for 1984, using 2005 as the base year, can be calculated as follows:
- First, we need to find the nominal GDP for 1984 and 2005. Nominal GDP is the total output of an economy multiplied by the price of the output.
- In 1984, nominal GDP = 10,000 buckets of chicken x $10 = $100,000
- In 2005, nominal GDP = 25,000 buckets of chicken x $20 = $500,000
- Next, we need to calculate the GDP price index for 1984, using 2005 as the base year. The formula for the GDP price index is: (nominal GDP / real GDP) x 100
- Since we are using 2005 as the base year, the real GDP for 2005 is the same as the nominal GDP for 2005, which is $500,000.
- Therefore, the GDP price index for 1984 = ($100,000 / $500,000) x 100 = 20

B. To find the percentage increase in the price level between 1984 and 2005, we can use the formula: [(GDP price index in 2005 - GDP price index in 1984) / GDP price index in 1984] x 100
- The GDP price index in 2005 is 100, since we are using 2005 as the base year.
- The GDP price index in 1984 is 20, as calculated in part A.
- Therefore, the percentage increase in the price level between 1984 and 2005 = [(100 - 20) / 20] x 100 = 400%

C. To find the real GDP for 1984 and 2005, we can use the formula: real GDP = nominal GDP / GDP price index
- In 1984, nominal GDP = $100,000 and GDP price index = 20, so real GDP = $100,000 / 20 = $5,000
- In 2005, nominal GDP = $500,000 and GDP price index = 100, so real GDP = $500,000 / 100 = $5,000
- Therefore, the real GDP in 1984 and 2005 were both $5,000.

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Answer:

1. 5/(2+2)= 5/4= 1.25

2. 5/(2x2)= 5/4= 1.25

Step-by-step explanation:

3x5/12= 15/12= 1.25

=====================================================

Work Shown:

Let x and y be the two numbers.

We're given x = 162 and the variable y is unknown.

We're also given LCM = 1134 and HCF = 18

So,

LCM = (x*y)/HCF

1134 = 162*y/18

1134 = (162/18)y

1134 = 9y

9y = 1134

y = 1134/9

y = 126

The other number is 126

---------------------

Notice that

showing that 18 is the highest common factor (HCF) of the numbers 162 and 126. This partially confirms the answer.

Now let,

So,

We see that 1134 is in each list of multiples and the smallest such common item. So the lowest common multiple (LCM) of 162 and 126 is 1134. This helps fully confirm the answer.

Answer:

first odd number be x = - 73

second odd number be x + 2 = (- 73 + 2) = - 71

third odd number be x + 4 = (- 73 + 4) = - 69

Step-by-step explanation:

let the first odd number be x

second odd number be x + 2

third odd number be x + 4

Now, three consecutive odd integers whose sum is - 213.

i.e.,

(x) + (x + 2) + (x + 4) = - 213

Then,

(x) + (x + 2) + (x + 4) = - 213

x + x + 2 + x + 4 = - 213

3x + 6 = - 213

3x = - 213 - 6

3x = - 219

x = - 219/3

x = - 73

Thus, The value of x is - 73

Here,

first odd number be x = - 73

second odd number be x + 2 = (- 73 + 2) = - 71

third odd number be x + 4 = (- 73 + 4) = - 69

So

(x) + (x + 2) + (x + 4) = - 213

(- 73) + (- 73 + 2) + (- 73 + 4) = - 213

(- 73) + (- 71) + (- 69) = - 213

- 73 - 71 - 69 = - 213

- 213 = - 213

Hence, L.H.S = R.H.S

-TheUnknownScientist