A column in a building is subjected to the following service load effects:
Dead Load = 40 KN Wind Load = 36 KN Compression load
Roof Live Load = 22 KN Rain Load = 32 KN Compression load

If LRFD is used, determine the factored load (in KN) to be used in the design of the column.
If the resistance factor ϕ is 0.90, compute the required nominal strength in KN.

Answers

Answer 1

Given

Dead load = 40 KN

Wind load = 36 KN

Compression load Roof live load = 22 KN

Rain load = 32 KNCompression load

To determine Factored Load:

Service Load = DL+WL+LL+RL+CS

DL = Dead Load

= 40 KN

WL = Wind Load

= 36 KN

LL = Live Load

= 22 KN

RL = Rain Load = 32 KN

C = Compression Load

Factored Load = 1.2DL + 1.6WL + 1.6LL + 0.5RL + 0.9CS

= 1.2(40) + 1.6(36) + 1.6(22) + 0.5(32) + 0.9CS

Therefore, Factored Load = 180.8 KN

To determine the Required Nominal Strength, we have to use ϕϕ = Resistance Factor

Required Nominal Strength = Factored Load / ϕ

= 180.8 / 0.90

= 200.89 KN

Thus, the required nominal strength is 200.89 KN.

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Related Questions

4. How much voltage is there across a 100 mH inductor if the current is changing at 10.0 mA/s

Answers

1V voltage is there across a 100 mH inductor if the current is changing at 10.0 mA/s

The voltage across an inductor is given by the equation V = L(di/dt), where V is the voltage, L is the inductance, and (di/dt) is the rate of change of current with respect to time.

In this case, the inductance is 100 mH (millihenries), and the current is changing at a rate of 10.0 mA/s (milliamperes per second). Converting the inductance to henries (H), we get L = 0.1 H.

Plugging these values into the equation, we get:

V = L(di/dt) = (0.1 H)(0.010 A/s) = 0.001 V = 1 mV

Therefore, the voltage across the inductor is 1 mV or 0.001 V.

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when a metal reacts with a non-metal it forms what???​

Answers

Answer:

When metals react with non-metals, electrons are transferred from the metal atoms to the non-metal atoms, forming ions. The resulting compound is called an ionic compound.

:

I'll give brainlest
*the first pic is for Alberto and second for the mouse*
Question 1
Alberto created a graph to illustrate his trip. Answer the questions below.
A. How does Alberto's motion change at point B?
B. What is Alberto's speed from point C to point D?
C. What happens at point D? (1 point)

Question 2
Answer the question below about Smokey The Mouse.
A. Use inertia to explain how a balanced force will affect his motion. (Newton's 1st Law)
B. What are two ways Smoky can increase his speed? (Use Newton's 2nd Law to help you)
C. What is an example of an action and reaction at work in this picture? (Use Newton's 3rd Law to help you)

I'll give brainlest *the first pic is for Alberto and second for the mouse*Question 1Alberto created

Answers

Answer:

The mouse exerts a force on the ground and the ground exerts an equal and opposite reaction force on the mouse.

At point B, Alberto's distance covered increases with time, equal distance is covered in equal time interval. The speed increases uniformly. At the point C to D, the distance covered with time remains the same. At the point D, equal distance is no longer covered in equal time intervals.

According to the law of inertia, an object will remain at rest or in a state of uniform motion unless it is acted upon by an unbalanced force. This means that smokey mouse will continue moving uniformly unless a force acts on it.

From Newton's second law; F = ma and a = F/m. F = force , m= mass, a = acceleration. This implies that smokey mouse can increase its speed by;

Increasing the force acting on the mouse

Decreasing the mass of the mouse

Action and reaction is encountered as the mouse is walking. The mouse exerts a force on the ground and the ground exerts an equal and opposite reaction force on the mouse.

Explanation:

A stone of 0.5 kg mass is thrown with 5 m/s. Find the kinetic energy of the stone.​

Answers

Answer

the answer is 6.25

Explanation:

Here, the mass of the stone (m) = 0.5 kg, velocity at which it is thrown (v) = 5 m/s, The kinetic energy of the stone (KE) =? We have, Kinetic energy of the stone (KE) = \ (\frac12mv^21) = \(\frac120.5\times5^2\) = 6.25 Joules Hence, the kinetic energy of the stone (KE) is 6.25 joules. Hope it will be helpful

When a +0.00235 C charge
moves from point A to point B, its
electric potential energy increases
by 0.418 J. What is the potential
difference between A and B?
Include the correct sign, + or - .
(Unit = V)

Answers

Answer:177.87

Explanation:

. Una varilla de cobre de coeficiente de dilatación 1,4*10-5 °C -1 , tiene una longitud de 1.20 metros a una temperatura ambiente de 18 ˚C . ¿Cuál sera su longitud 100 ˚C

Answers

Answer:

La longitud de la varilla de cobre es de 1.201 metros a una temperatura de 100 °C.

Explanation:

Asumiendo que la varilla de cobre experimenta deformaciones muy pequeñas y que las deformaciones no longitudinales son despreciables con respecto a las deformaciones longitudinales, la deformación longitudinal de la varilla se estima mediante la siguiente fórmula:

\(l_{f} = l_{o}\cdot [1+\alpha \cdot (T_{f}-T_{o})]\) (1)

Donde:

\(l_{o}\) - Longitud inicial de la varilla, en metros.

\(\alpha\) - Coeficiente de dilatación, en \(^{\circ}C^{-1}\).

\(T_{o}\) - Temperatura inicial de la varilla, en grados Celsius.

\(T_{f}\) - Temperatura final de la varilla, en grados Celsius.

Si sabemos que \(l_{o} = 1.20\,m\), \(\alpha = 1.4\times 10^{-5}\,^{\circ}C^{-1}\), \(T_{o} = 18\,^{\circ}C\) y \(T_{f} = 100\,^{\circ}C\), entonces la longitud final de la varilla es:

\(l_{f} = (1.20\,m)\cdot \left[1 + \left(1.4\times 10^{-5}\,^{\circ}C^{-1}\right)\cdot (100\,^{\circ}C-18\,^{\circ}C)\right]\)

\(l_{f} = 1.201\,m\)

La longitud de la varilla de cobre es de 1.201 metros a una temperatura de 100 °C.

a wave wirh a period of 50 seconds is generated and the wave length is 2m calculate the speed​

Answers

Answer:

0.04 m / s

Explanation:

distance over time will get you your speed

what is the distance 9m) traveled by a butterfly with a speed of 0.97m/s and a flight time of 3400s?

Answers

We will have the following:

\(d=(0.97m/s)(3400s)\Rightarrow d=3298m\)

So, the butterfly traveled 3298 meters.

A 90-meter train travels at a constant speed of 10 meters per second. How long will it take to cross a 0.06 bridge?

Answers

Answer:

The time taken for the train to cross the bridge is 9.01 s

Explanation:

Given;

length of the train, L₁ = 90 m

length of the bridge, L₂ = 0.06 m

speed of the train, v = 10 m/s

Total distance to be traveled, = L₁ + L₂

                                                  = 90 m + 0.06 m

                                                   = 90.06 m

Time of motion = Distance / speed

Time of motion = 90.06 / 10

Time of motion = 9.006 s ≅ 9.01 s

Therefore, the time taken for the train to cross the bridge is 9.01 s

Two particles with charges +7e and -7e are initially very far apart (effectively an infinite distance apart). They are then fixed at positions that are 6.17 x 10-11 m apart. What is EPEfinal - EPEinitial, which is the change in the electric potential energy?

Answers

Two particles with charges +7e and -7e are initially very far apart (effectively an infinite distance apart). They are then fixed at positions that are 6.17 x 10-11 m apart.

Change in the electric potential energy is calculated as: EPEfinal - EPEinitial

Electric potential: The work done per unit charge in bringing a test charge from infinity to that point is called electric potential. It is denoted by V and its unit is Volt. The formula for electric potential is given as:

V = kq/r

Here, q = point charge k = Coulomb's constant r = distance between the point charge and the point at which potential is to be calculated

.Electric field: The space or region around a charged object where it has the capability to exert a force of attraction or repulsion on another charged object is called an electric field.

E = kq/r² Here, q = point charge k = Coulomb's constant r = distance between the point charge and the point at which potential is to be calculated.

EPE for a system of charges: Electrostatic potential energy of a system of charges is the work done in assembling the system of charges from infinity to that configuration or position.

EPE = 1/4πε * (q1q2/r)

Electrostatic potential energy of a system of two particles with charges +7e and -7e are initially very far apart (effectively an infinite distance apart) is given as:

EPEinitial = 1/4πε * (q1q2/r) = 1/4πε * (7e x -7e/∞) = 0J

Now, the particles are fixed at positions that are 6.17 x 10^-11 m apart.

EPEfinal = 1/4πε * (q1q2/r) = 1/4πε * (7e x -7e/6.17 x 10^-11 m) = -2.61 x 10^-18 J

Thus, the change in the electric potential energy is calculated as:

EPEfinal - EPEinitial= -2.61 x 10^-18 J - 0 J = -2.61 x 10^-18 J

Answer: The change in electric potential energy is -2.61 x 10^-18 J.

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Los barbijos de tela, a diferencia de los quirúrgicos, poseen una filtración de partículas de aproximadamente 0.000003979 [m]. Expresar dicho valor en notación científica, de tal forma que tenga solo dos decimales​

Answers

Answer:

El valor en notación científica es 3.98*10⁻⁶.

Explanation:

La notación científica es una manera rápida de representar un número utilizando potencias de base diez. Esta notación se utiliza para poder expresar muy fácilmente números muy grandes o muy pequeños.

Los números se escriben como un producto:

a*10ⁿ

donde:  

a es un número real mayor o igual que 1 y menor que 10, al cual se le agrega un punto decimal después de la primera cifra si se trata de un número que no es entero. n es un número entero, que recibe el nombre de exponente u orden de magnitud. Representa el número de veces que se desplaza la coma. Siempre es un número entero, positivo si se desplaza a la izquierda, negativo si se desplaza a la derecha.

Para escribir el número 0.000003979 en notación científica, se realizan los siguientes pasos:

Se mueve la coma decimal hacia la derecha tantos espacios hasta llegar a la derecha del primer dígito. Se escribe entonces este número, que será el coeficiente a en la expresión del producto anterior.   Se escribe la base 10 con el exponente igual a la cantidad de espacios que se mueve la coma. Este es un número negativo porque la coma se desplaza a la derecha.

Entonces, en este caso:

a= 3,979 ≅ 3,98n= -6

Entonces, el valor en notación científica es 3.98*10⁻⁶.

A vehicle traveling on wet or slick roads can begin to _________ as water forms a barrier between the road and the tires and traction is lost as the wheels start to ride on top of the water and not the road surface. a) skid b) hydroplane c) lose traction d) splash water on to the engine

Answers

Answer: B.) HYDROPLANE

Explanation: The term hydroplane can be used to refer to a condition which usually occur during a downpour or on surfaces covered by water. It occurs when water forms a barrier or comes in between the frictional grip which occurs between the road surface and the car tyres. The contact between the car tyres and the road surface is supposed to give adequate frictional support which prevents the car from skidding or skidding uncontrollably on the road surface. However, when water comes invetween the surface, traction is lost and skidding results due to very low Coefficient of friction between the road and Tyre which was supposed to provide a firm grip between the tyres and the road surface.

When a vehicle is traveling on wet or slick roads, hydroplaning can occur. The correct answer is b) hydroplane.

When a vehicle is traveling on wet or slick roads, hydroplaning can occur. Hydroplaning happens when a layer of water builds up between the tires of the vehicle and the road surface, leading to a loss of traction.

This loss of traction can cause the vehicle to skid or slide, making it difficult to control. The tires ride on top of the water rather than maintaining contact with the road, resulting in reduced traction and control of the vehicle.

Therefore, When a vehicle is traveling on wet or slick roads, hydroplaning can occur. The correct answer is b) hydroplane.

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what is anti-matter made of

Answers

HERE'S YOUR ANSWER

Explanation:

Antimatter is a material composed of so-called antiparticles. It is believed that every particle we know of has an antimatter companion that is virtually identical to itself, but with the opposite charge. For example, an electron has a negative charge.

HELP PLEASEEE
Two identical balls roll down opposite
sides of a fnctionless platform, which one will be going faster at the bottom?

HELP PLEASEEE Two identical balls roll down oppositesides of a fnctionless platform, which one will be

Answers

Answer: Ball #1

Explanation:

Since the platform is more inclined, it will allow the ball to roll down faster.

Ball two would accelerate the fastest because, it is being rolled down an inclined plane.

As the electric potential near the ground increases during a thunderstorm, a positive charge current can move up pointed objects, such as masts of ships, producing a luminous halo or glow known as ____.

Answers

Answer:

St. Elmo's Fire - well known to old time sailors

calculate the maximum increase in photon wavelength that can occur during compton scattering.

Answers

In Compton scattering, a photon collides with an electron and transfers some of its energy and momentum to the electron. As a result, the wavelength of the scattered photon can change. The maximum increase in wavelength occurs when the photon scatters at a 180-degree angle (backscattering).

a photon collides with an electron and transfers some of its energy and momentum to the electron. The equation that relates the change in wavelength (∆λ) to the initial wavelength (λ) and the scattering angle (θ) is given by:

∆λ = λ - λ'

where λ' is the wavelength of the scattered photon.

For backscattering (θ = 180 degrees), the maximum change in wavelength (∆λ_max) occurs. In this case, the equation simplifies to:

∆λ_max = 2λ

Therefore, the maximum increase in photon wavelength that can occur during Compton scattering is equal to twice the initial wavelength.

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Calculate the area of the plates of a 1 pF parallel plate capacitor in a vacuum if the separation of the plates is 0.1 mm. [ε0=8.85×10-12C2N-1m-2 ]Select one:6.2 m214.4 m211.3 m218.4 m2

Answers

Apply:

C = A e0 / d

Where:

C = capacitance = 1pf = 1 x10^-12 F

A = area

ε0 = 8.85×10^-12

1 pf = 1 x 10^-12 F

A = Cd / ε0 = 1 x 10^-12 ( 1 x 10^-4 ) / 8.85×10^-12 = 1.13 x10 ^-5 m^2

MISSED THIS? Read Section 8.5 (Pages 331 - 337) ; Watch KCV 8.5B, IWE 8.7. Calculate the frequency of the light emitted when an electron in a hydrogen atom makes each of the following transitions. Part A n=4→n=3 Express the frequency in inverse seconds. Part B n=5→n=1 Express the frequency in inverse seconds.

Answers

Explanation:

I don't know exactly how much money you have on the company because you're not helpful enough as your friends and coworkers

(a) The frequency of light emitted when an electron in a hydrogen atom undergoes a transition from n = 4 to n = 3 is approximately 2.466 × 10¹⁵ Hz (inverse seconds).

(b) The frequency of light emitted when an electron in a hydrogen atom undergoes a transition from n = 5 to n = 1 is approximately 3.288 × 10¹⁵ Hz (inverse seconds).

Determine the frequency (ν) of light?

The frequency (ν) of light emitted during a transition in a hydrogen atom can be calculated using the Rydberg formula:

ν = R_H * (1/n₁² - 1/n₂²)

Where R_H is the Rydberg constant (approximately 3.29 × 10¹⁵ Hz), n₁ is the initial energy level, and n₂ is the final energy level.

(a) For the transition from n = 4 to n = 3:

ν = R_H * (1/3² - 1/4²)

  = R_H * (1/9 - 1/16)

  = R_H * (16/144 - 9/144)

  = R_H * (7/144)

  ≈ 2.466 × 10¹⁵ Hz

(b) For the transition from n = 5 to n = 1:

ν = R_H * (1/1² - 1/5²)

  = R_H * (1 - 1/25)

  = R_H * (24/25)

  ≈ 3.288 × 10¹⁵ Hz

The Rydberg constant (R_H) is a fundamental constant in atomic physics that relates to the wavelengths of light emitted or absorbed during electronic transitions in hydrogen-like atoms.

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Suppose the energy required to freeze 0.250 kg of water were added to the same mass of water at an initial temperature of 1.0 °C. What would be the final temperature of the water?

Answers

The final temperature of the water at the given conditions is 2 ⁰C.

The given parameters:

Mass of the water, m = 0.25 kgInitial temperature of the water, t = 1 ⁰C

Apply the principle of conservation of energy to determine the final temperature of the water as follows;

\(Q _{cold} = Q _{warm}\\\\mc (t_i - t_f) = mc (t_f - t_i)\\\\mc(1- 0) = mc(t_f - 1)\\\\1 = t_f - 1\\\\t_f = 1+1 \\\\t_f = 2 \ ^0C\)

Thus, the final temperature of the water at the given conditions is 2 ⁰C.

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anyone know the answer?

anyone know the answer?

Answers

i think the answer is true but not sure

calculate the smallest value for the coefficient of friction necessary that would keep the block from moving

Answers

With the given values of W and d, we can find the smallest value for the coefficient of friction necessary to keep the block from moving.

To calculate the smallest value for the coefficient of friction necessary to keep the block from moving, we can use the formula for static friction:
static friction (fs) = coefficient of static friction (μs) × normal force (N)
Since we know the work done (200 J) and want to find the smallest value for the coefficient of friction (μs), we can use the work-energy theorem, which states:

Work = change in kinetic energy = 0 (since the block is not moving)
Work = force (F) × distance (d) × cos(θ)

200 J = μs × N × d × cos(θ)
Now, let's consider the forces acting on the block.

The weight of the block (W) is acting vertically downward, and the normal force (N) is acting vertically upward. In this case, the angle (θ) between the force and the direction of motion is 0 degrees,

so cos(θ) = 1.
To find the normal force (N), we can equate it to the weight of the block since the block is not moving vertically:
N = W
We need more information to solve for the coefficient of static friction (μs), such as the weight of the block (W) and the distance (d).

Once we have this information, we can substitute it into the equation and solve for μs:
200 J = μs × W × d
μs = 200 J / (W × d)

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Based on height calculations of Homo erectus fossils, biological anthropologists estimate that their average height was Group of answer choices more than 70% taller than Homo habilis. similar to that of australopithecines. tall, within the range of modern humans. short, with most being approximately three feet.

Answers

Homo erectus had a height similar to modern humans, marking a significant increase from Homo habilis and within the australopithecine range.

Based on height calculations of Homo erectus fossils, biological anthropologists estimate that their average height was within the range of modern humans. Homo erectus, an extinct species of early human, lived approximately 1.9 million to 143,000 years ago. Fossil evidence, including long bones and skeletal remains, provides insights into their physical characteristics.

Biological anthropologists estimate that Homo erectus was taller than their predecessor, Homo habilis, by more than 70%. Homo habilis, considered one of the earliest members of the human genus Homo, had a smaller stature. The height increase in Homo erectus suggests a significant evolutionary development.

Although the exact height of Homo erectus individuals can vary, estimations place their average height within the range of modern humans. Modern humans typically have an average height ranging from about 5 feet to 6 feet, depending on geographical and ethnic variations. This suggests that Homo erectus individuals were not excessively short or tall but exhibited a height similar to that of australopithecines, early hominin species.

Therefore, Homo erectus was estimated to have a height similar to that of modern humans, representing a significant increase compared to their predecessor Homo habilis, and falling within the range of australopithecines.

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I need help in this please

I need help in this please

Answers

The net force along the origin is zero in image (3).

What would make the net force at the origin to be zero?

We know that the image in the question shows us three charges that have been shown according to the diagram in the image. It is important that we note that the net force is the resultant force that is acting at the origin zero in each of the cases.

We would now have to look at the magnitudes of the charges in each of the cases so as to obtain the resultant force of zero at the origin. Thus we can see that in the case we have, the set up in (3) is such that the resultant at the origin would give a zero magnitude.

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A ball is thrown upward from the top of a building at an angle of 30.0° to the horizontal and with
an initial speed of 20.0 m/s. The point of release is 45.0 m above the ground. Neglect air resistance.
(i) How long does it take for the ball to hit the ground?
(ii) Find the ball’s speed at impact.
(iii) Find the horizontal range of the stone.

Answers

Answer:

See below

Explanation:

Vertical position = 45 +  20 sin (30) t  - 4.9 t^2

 when it hits ground this = 0

               0 = -4.9t^2 + 20 sin (30 ) t + 45

                0 = -4.9t^2 + 10 t +45 = 0     solve for t =4.22 sec

  max height is at  t= - b/2a = 10/9.8 =1.02

     use this value of 't' in the equation to calculate max height = 50.1 m

      it has  4.22 - 1.02 to free fall = 3.2 seconds free fall

           v = at = 9.81 * 3.2 = 31.39 m/s VERTICAL

      it will also still have horizontal velocity =  20 cos 30 = 17.32 m/s

        total velocity will be sqrt ( 31.39^2 + 17.32^2) = 35.85 m/s

Horizontal range = 20 cos 30  * t  =  20 *  cos 30  * 4.22 = 73.1 m

Please help me write binary ionic compound to number 1

Please help me write binary ionic compound to number 1

Answers

Answer:

Na+ca+CO=NACo^3

Explanation:

NA Burns violently with explosions that may spatter the material. Used for making gasoline additives, electric power cable, sodium lamps, other chemicals.

Take the acceleration due to gravity to be 9.81 ms −2
where needed 2. When a car, of mass 1200 kg, travels at a speed of v ms −1
, it experiences a resistance force of magnitude 30v newtons. The maximum power output of the engine is 69120 watts. (a) Show that the maximum constant speed of the car on a straight horizontal road is 48 ms −1
. (2 marks) (b) Find the maximum possible acceleration of the car when it is travelling at a speed of 40 ms −1
along a straight horizontal road. (3 marks) (c) Find the maximum possible speed of the car as it ascends a hill on a straight road which is inclined at an angle of 3 ∘
to the horizontal. (5 marks) Total marks for this question: 10

Answers

(a) The maximum constant speed of the car on a straight horizontal road is 48 m/s.

(b) The maximum possible acceleration of the car when it is traveling at a speed of 40 m/s along a straight horizontal road is 3.6 m/s^2.

(c) The maximum possible speed of the car as it ascends a hill on a straight road inclined at an angle of 3 degrees to the horizontal is 16.4 m/s.

(a) To determine the maximum constant speed of the car on a straight horizontal road, we need to balance the driving force provided by the engine and the resistance force acting against the car. The resistance force is given as 30v, where v represents the car's speed. The driving force is equal to the product of the car's mass (1200 kg) and its acceleration.

At maximum constant speed, the acceleration is zero. Therefore, the driving force is zero as well. Equating the driving force and resistance force, we have 30v = 0. Solving for v, we find v = 0. Thus, the maximum constant speed of the car is 48 m/s.

(b) To find the maximum possible acceleration of the car when it is traveling at a speed of 40 m/s on a straight horizontal road, we use the same equation as in part (a): 30v = m * a, where v is the car's speed, m is its mass (1200 kg), and a is the acceleration.

Substituting the given values, we have 30 * 40 = 1200 * a. Solving for a, we find a = 3.6 m/s^2. Therefore, the maximum possible acceleration of the car is 3.6 m/s^2.

(c) When the car ascends a hill inclined at an angle of 3 degrees to the horizontal, we need to consider the gravitational force acting against the car. The component of the car's weight parallel to the incline is given by mg * sinθ, where m is the mass (1200 kg), g is the acceleration due to gravity (9.81 m/s^2), and θ is the angle of inclination (3 degrees).

To maintain motion up the hill, the driving force provided by the engine must be greater than or equal to the sum of the resistance force and the component of the car's weight. Using the maximum power output of the engine (69120 watts), we can calculate the maximum possible speed of the car as it ascends the hill. Further calculations yield a maximum possible speed of 16.4 m/s.

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according to special relativity, one can travel at increased rates

Answers

According to special relativity, one can travel at increased rates. However, this is only possible when moving at very high speeds approaching the speed of light. When an object moves at high speeds, the time slows down, and the length of the object appears to be shortened.

These observations are known as time dilation and length contraction. Time dilation refers to the difference in the elapsed time measured by two observers, where one is stationary, and the other is moving at a constant velocity relative to each other. The faster the moving observer, the slower time appears to be for them. Length contraction, on the other hand, refers to the phenomenon where an object appears to be shorter in length when it's moving at high

This effect is more noticeable as the speed of the object approaches the speed of light. As a result, traveling at very high speeds can allow one to cover great distances in less time, which can be used for space exploration and other scientific research. However, it's worth noting that the effects of relativity are only noticeable at very high speeds, which are currently impossible to achieve with our current technology.

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If a 0.3% decrease in the price of a good causes its quantity supplied to decrease by 1%, then the supply is: A. Unit elastic B. Elastic C. Inelastic D. Perfectly inelastic

Answers

If a 0.3% decrease in the price of a good causes its quantity supplied to decrease by 1%, then the supply is C. Inelastic.

In this scenario, the supply of the good is considered inelastic. The elasticity of supply measures the responsiveness of the quantity supplied to changes in price. When the price of a good decreases, and the quantity supplied decreases by a larger percentage, it indicates that the supply is relatively unresponsive to price changes.

To determine the elasticity of supply, we compare the percentage change in quantity supplied to the percentage change in price. In this case, a 0.3% decrease in price results in a 1% decrease in the quantity supplied. Since the percentage change in quantity supplied (1%) is greater than the percentage change in price (0.3%), the supply is considered inelastic.

Inelastic supply means that producers are less responsive to price changes, and a small change in price leads to a proportionally smaller change in quantity supplied. In such cases, producers may find it challenging to adjust their output levels quickly in response to price fluctuations.

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Convert 400.0 nm to mm.

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0.0004 millimeter !!

Answer: 0.0004

Explanation: hope this helpsss ^-^

mention four physical properties of physics​

Answers

color (intensive)
density (intensive)
volume (extensive)
mass (extensive)
1. Density
2. Color
3. Volume
4. Mass
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