A city has a population of
110,000 and grows at 4%
every year. What will be
the population after 15
years?

a) Only the first statement is true. As the sample size N becomes large, the sample mean of IID random samples from a population becomes more precise and approaches the true population mean.

However, there is no direct relationship between the sample size and the distribution of the sample mean.
The second statement is only true if the population is normally distributed. If the population is not normal, the distribution of the sample mean may not be normal, and the central limit theorem may not apply. Therefore, option c) is not the correct answer. Option d) is also not correct as the first statement is true.

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Answer:

c.) a = 60

explanation:

This is the only work that is correctly shown, if you are doing edg, hope it helps!

Answer:

Option C.

Step-by-step explanation:

It is given that, a menu at a local diner has

Appetizers = 12

Entrees = 8

Choice of desserts = 4

We need to find the different meal combinations which are possible if you select one appetizer, one entree and one dessert form the menu.

Total ways to select an Appetizers = 12

Total ways to select an entrees = 8

Total ways to select a desserts = 4

Now,

Total combinations for different meal \(=12\times 8\times 4=384\)

Therefore, the correct option is C.

Answer:

see below

Step-by-step explanation:

the answer is c

Answer:

80k

Step-by-step explanation:

let the previous weight be x

88=x + 10%of x

88=x+(10/100)of x

8800=110x

8800/110=x

x=80k

Answer: Original weight = 80 kg

Step-by-step explanation:

Given:

Current weight = 88 Kg

Gain weight rate = 10%

Solve:

Original weight = Current weight / Gain rate

Original weight = (88) / (1 + 10%)

Original weight = 80 Kg

Hope this helps!! :)

Please let me know if you have any questions

Answer:

5/37

Step-by-step explanation:

There are 37 possible outcomes when rolling a 37-sided die, so the probability of rolling any one specific number is 1/37.

To find the probability of rolling any of the given numbers (35, 25, 33, 9, or 19), we need to add the probabilities of rolling each individual number.

Probability of rolling 35: 1/37

Probability of rolling 25: 1/37

Probability of rolling 33: 1/37

Probability of rolling 9: 1/37

Probability of rolling 19: 1/37

The probability of rolling any one of these numbers is the sum of these probabilities:

1/37 + 1/37 + 1/37 + 1/37 + 1/37 = 5/37

So the probability of rolling any of the given numbers is 5/37, which is approximately 0.1351 when rounded to four decimal places.

To solve this problem, we have to determine the 34.4% of 20. To find the x% of y, we can use the following expression:

Therefore, the 34.4% of 20 is:

Subtracting the above amount from20, we get:

Answer:

The cheese bill decreased this week by

The total cheese bill for this week is:

Answer:

$2.50tip

Step-by-step explanation:

12.50*0.20=2.50

The equation for the function, which is f(x) = -4x + 500 and is a linear function, is the answer to the given question based on the function.

A straight line on a graph is represented by a particular kind of mathematical function called a linear function. Two variables that are directly proportional to one another are modelled using linear functions. For instance, the distance-time relationship in a straight line motion is a linear function with speed as the slope.

Let's start by determining whether the function is exponential or linear. Given that Nick can write 120 words in 30 minutes, his word-per-minute rate is 120/30, or 4 words. In order to estimate how many words, he writes in x minutes, we can use this rate:

Write x words in x minutes and multiply by 4 = 4x

Since Nick wants to write 500 words per day, we can create an equation to roughly calculate how many words remain in his writing session after x minutes:

500 - 4x is the number of words remaining needed to meet the target.

Given that there is a constant pace of 4 words per minute between the number of words still needed and the amount of time left, this equation is linear. It can be expressed as a linear function with the formula f(x) = mx + b, where m denotes the slope (rate) and b the y-intercept (value at x=0).

Since Nick needs to write 500 words at the beginning of the writing session, the y-intercept is 500 and the slope is -4 (indicating that the rate of words still needed is falling at a rate of 4 words per minute):

f(x) = -4x + 500

As a result, the function's equation is f(x) = -4x + 500, indicating that it is a linear function.

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The values are;

1.Volume = 70 cm³

Area = 379. 7 cm²

2.  Volume = 1017. 36 cm³

Area = 565. 2 cm²

3.  Volume = 864 cm³

Area  = 93. 24cm²

4. Volume = 1200cm³

Area = 12√3cm²

We have that the volume of a triangular prism is expressed as;

1.

Volume = Base × height

Substitute the values, we have;

Volume = 14 ×5

Volume = 70 cm³

Area = bh + (s₁+ s₂+ s₃)l

Substitute the values as shown, we have;

Area = 14 ×12.12 + (14 + 14 + 14) 5

Multiply the values, we have;

Area = 169. 68 + 210

Area = 379. 7 cm²

2. Volume of the cylinder = πr²h = 3.14 × 6²×9

Volume = 1017. 36 cm³

Area of the cylinder = 2πrh + 2πr²

Area = 339. 12 + 226. 08

Area = 565. 2 cm²

3. Volume =3abh = 3× 8 ×6 × 6

Volume = 864 cm³

Area = 3√3/2a² = 2. 59 × 36 = 93. 24cm²

4. Volume = lwh = 10 × 10 × 12 = 1200cm³

Area = pq/2 = 12 ×2√3/2 = 12√3cm²

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If the perimeter of the isosceles triangle is 12 cm, then the base of the triangle (x), as well as the length of the triangle leg (x) is 4 cm.

An isosceles triangle is a type of triangle in which two sides have the same length. These two equal sides are referred to as the legs of the triangle, while the remaining side is known as the base.

The perimeter of a triangle is the sum of the lengths of all its sides. In this case, since the triangle is isosceles, the base and one leg have the same length (x), and the other leg also has the same length (x). Therefore, the perimeter of the triangle is 2x + x = 3x. Given that the perimeter of the isosceles triangle is 12 cm, then:

3x = 12

 x = 12/3

 x = 4

So, the base and legs of the isosceles triangle each have a length of 4 cm.

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Your question seems to be missing the value for the perimeter of the triangle, but I suppose the complete question was:

"The length of the base of an isosceles triangle is x. The length of a leg is x. The perimeter of the triangle is 12 cm. Find x."

Answer:

\(A=P (1 + \frac{r}n)} ^{nt}\)

A = 500(1 + .028/1)^ (3*1)

$543.19

Step-by-step explanation:

Answer:

r = 2

Step-by-step explanation:

Use cross products.

Set the cross products equal and solve for r.

r × 120 = 4 × 60

120r = 240

r = 2

Answer:

5th term will approximate 5461/64

Step-by-step explanation:

5th term will approximate 5461/64

64+16+4+1+0.25 = 85.25 ≈ 5461/64 = 85.33

The sentence written in the indicative mood is: "The team plays much better after a pep talk from their coach."

The grammatical mood known as the indicative is employed to state or inquire about facts.

The verb forms in the indicative mood show that the action or state described is actually occurring or has already occurred. For instance, the statement "I am walking to the store" is suggestive since it is a factual statement describing an action that is now occurring.

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We have shown that |g(x) - g(y)| < 12ε whenever |x - y| < δ. Since ε was arbitrary, this shows that g(x) is uniformly continuous on (0, 1).

A stronger version of continuity known as uniform continuity ensures that functions defined on metric spaces, such as the real numbers, only vary by a small amount when their inputs change by a small amount. Contrary to uniform continuity, continuity merely demands that the function act "locally" around each point. To clarify, this means that for any given point x, there exists a tiny neighbourhood around x such that the function behaves properly inside that neighbourhood.

For the function g(x) to be continuous we need to have any ε > 0, and  δ > 0 such that if |x - y| < δ, then |g(x) - g(y)| < ε for all x, y in (0, 1).

Now, g(x) is bounded as the parent function f(x) is bounded.

Suppose, (0, 1) such that  |x - y| < δ.

Thus, without generality we have:

|g(x) - g(y)| = |x(1-x)f(x) - y(1-y)f(y)|

= |x(1-x)(f(x) - f(y)) + y(f(y) - f(x)) + xy(f(x) - f(y))|

≤ x(1-x)|f(x) - f(y)| + y|f(y) - f(x)| + xy|f(x) - f(y)|

< x(1-x)4ε + y4ε + xy4ε (by the choice of δ)

= 4ε(x(1-x) + y + xy)

< 4ε(x + y + xy)

≤ 4ε(1 + 1 + 1) = 12ε

Hence, we have shown that |g(x) - g(y)| < 12ε whenever |x - y| < δ. Since ε was arbitrary, this shows that g(x) is uniformly continuous on (0, 1).

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Answer:

-20

Step-by-step explanation:

48 divided by -3 is -16 but you round up since its high enough and it goes to -20

a) Marginal PDF of X and marginal pdf of Y:fX(x) = 0.5x for 0 < x < 2.

b)The conditional PDF of Y given X = x is fY|X(y|x) = 1 / x for 0 < y < x < 2.

c)The conditional PDF of X given Y = y is fX|Y(x|y) = 1 / (2 - y) for 0 < y < x < 2.

d) E(X) = 4/3and E(Y)= 2/3

e) Var(X)= = 2/9 and Kar(K)= 2/9, Cov(X, Y) = 10/9

f)The correlation coefficient of X and Y is 5.

To find the marginal PDF of X, the joint PDF over the range of Y:

fX(x) = ∫[0 to 2] f(x, y) dy

Since the joint PDF f(x, y) = 1/2 for 0 < y < x < 2, the integral as follows:

fX(x) = ∫[0 to x] (1/2) dy

= (1/2) ×[y] evaluated from 0 to x

= (1/2) × (x - 0)

= 1/2 × x

= 0.5x, for 0 < x < 2

The conditional PDF of Y given X = x can be found using the joint PDF and the marginal PDF of X. The conditional PDF is given by:

fY|X(y|x) = f(x, y) / fX(x)

Given that f(x, y) = 1/2 for 0 < y < x < 2 and fX(x) = 0.5x for 0 < x < 2, substitute these values:

fY|X(y|x) = (1/2) / (0.5x)

= 1 / x, for 0 < y < x < 2

Similar to part (b), the conditional PDF of X given Y = y can be found using the joint PDF and the marginal PDF of Y. The conditional PDF is given by:

fX|Y(x|y) = f(x, y) / fY(y)

Given that f(x, y) = 1/2 for 0 < y < x < 2 and the marginal PDF of Y, fY(y) = ∫[y to 2] (1/2) dx, the integral:

fX|Y(x|y) = (1/2) / ∫[y to 2] (1/2) dx

= (1/2) / [(1/2) ×(2 - y)]

= 1 / (2 - y), for 0 < y < x < 2

E(X) = ∫[0 to 2] x × fX(x) dx

= ∫[0 to 2] x × (0.5x) dx

= 0.5 ∫[0 to 2] x² dx

= 0.5 × (1/3) × [x³] evaluated from 0 to 2

= 0.5 × (1/3) × (2³ - 0³)

= 0.5 × (1/3) × 8

= 4/3

E(Y) = ∫[0 to 2] y × fY(y) dy

= ∫[0 to 2] y × ∫[y to 2] (1/2) dx dy

= ∫[0 to 2] y × (1/2) × (2 - y) dy

= (1/2) × ∫[0 to 2] (2y - y²) dy

= (1/2) ×[(y²) - (1/3)y³] evaluated from 0 to 2

= (1/2) × [(2²) - (1/3)(2³) - 0]

= (1/2) × [4 - (8/3)]

= (1/2)× (12/3 - 8/3)

= (1/2) × (4/3)

= 2/3

e) Variances and Covariance:

Var(X) = E(X²) - [E(X)]²

Var(Y) = E(Y²) - [E(Y)]²

Var(X) = ∫[0 to 2] x² ×fX(x) dx - [E(X)]²

= ∫[0 to 2] x² × (0.5x) dx - (4/3)²

= 0.5 × ∫[0 to 2] x³ dx - (4/3)²

= 0.5 × (1/4) ×[x³] evaluated from 0 to 2 - (16/9)

= 0.5 × (1/4) × (2³ - 0³) - (16/9)

= 0.5 × (1/4) × 16 - (16/9)

= 2 - (16/9)

= 2/9

Var(Y) = ∫[0 to 2] y² × fY(y) dy - [E(Y)]²

= ∫[0 to 2] y² × ∫[y to 2] (1/2) dx dy - (2/3)²

= (1/2) × ∫[0 to 2] y² × (2 - y) dy - (2/3)²

= (1/2) ×[(2/3)y³ - (1/4)y²] evaluated from 0 to 2 - (4/9)

= (1/2) × [(2/3)(2³) - (1/4)(2²) - 0] - (4/9)

= (1/2) × [(16/3) - (16/4)] - (4/9)

= (1/2) ×[(16/3) - (12/3)] - (4/9)

= (1/2) × (4/3) - (4/9)

= 2/3 - 4/9

= 6/9 - 4/9

= 2/9

Cov(X, Y) = E(XY) - E(X)E(Y)

= ∫∫[0 to 2] xy × f(x, y) dy dx - (4/3)(2/3)

= ∫∫[0 to 2] xy × (1/2) dy dx - (8/9)

= (1/2) × ∫∫[0 to 2] xy dy dx - (8/9)

= (1/2) × [(1/2)x × ∫[0 to x] y² dy] evaluated from 0 to 2 - (8/9)

= (1/2) × [(1/2)x × (1/3)y³] evaluated from 0 to x, evaluated from 0 to 2 - (8/9)

= (1/2) × [(1/2)x × (1/3)x³ - 0] evaluated from 0 to 2 - (8/9)

= (1/2) × [(1/2)(2) × (1/3)(2³) - 0] - (8/9)

= (1/2) × [1/2 ×8 - 0] - (8/9)

= (1/2) × [4 - 0] - (8/9)

= (1/2) × 4 - (8/9)

= 2 - (8/9)

= 18/9 - 8/9

= 10/9

f) Correlation coefficient:

The correlation coefficient (ρ) of X and Y is given by:

ρ = Cov(X, Y) / sqrt(Var(X) × Var(Y))

Using the values

ρ = (10/9) / sqrt((2/9) × (2/9))

= (10/9) / (2/9)

= 10/2

= 5

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The answer is D) Yes, The graph passes the vertical line test

Given: Graph in the question along with options

A graph is said to represent a function if it passes the vertical line test.

According to the vertical line test, a vertical line when passed through a graph, if it touches it at more than one point, then the graph does not represent a function.

If the vertical line on passing through the graph, touches it at only one point so it is said to represent a function.

In this question, the graph passes the vertical line test so the answer is

D) Yes, the graph passes the vertical line test. ​

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The question is incomplete. Please see the complete question below

The candy shop made 3 1/18 pounds of chocolate they sold 1 1/4pounds how many pounds of chocolate do they have left

Answer:

15/8

Step-by-step explanation:

The shop made 3 1/8 pound of chocolate

They sold 1 1/4 of chocolates

Hence the number of chocolates left can be calculated as follows

3 1/8-1 1/4

= 25/8-5/4

= 15/8

Answer:

1. 1, 2, 3, 4, or 5

2. as long as it is -4, -5, -6, -7, and so on

Step-by-step explanation:

Power series solutions have a minimum radius of convergence of R of 10.0498 around the normal point x = 0 and 10 units around the normal point x=1.

A differential equation in mathematics is an equation that connects the derivatives of one or more unknown functions.

Applications often involve functions that reflect physical quantities, derivatives that depict the rates at which those values change, and a differential equation that establishes a connection between the three.

The given equation: \(\left(x^2-2 x+26\right) y^{\prime \prime}+x y^{\prime}-4 y=0\)

It is necessary to determine the power series solutions' minimal radius of convergence R around the typical points x = 0 and x = 1.

The separation between the ordinary point and the differential equation's singularity is now the minimal radius of convergence.

The polynomial's root, which is connected to the second derivative, is the singularity point.

The singularity points will be determined as follows:

\(\begin{aligned}& x^2-2 x+26=0 \\& x=\frac{-b \pm \sqrt{b^2-4 a c}}{2 a} \\& x=\frac{2 \pm \sqrt{(-2)^2-4 \times 1 \times 26}}{2} \\& x=1 \pm \sqrt{-100} \\& x=1 \pm 10 i\end{aligned}\)

In this case, x1 = 1+10i and x2 = 1-10i are the singularity sites.

The ordinary points at this time are z1 = 0+01 and z2 = 1+0i.

One can compute the minimum radius of convergence using the formula:

\(\begin{aligned}& r_1=\left|z_1-x_1\right| \\& =|0+0 i-1-10 i| \\& =\sqrt{101} \\& =10.0498 \\& r_2=\left|z_2-x_1\right| \\& =\sqrt{100} \\& =10\end{aligned}\)

Therefore, power series solutions have a minimum radius of convergence of R of 10.0498 around the normal point x = 0 and 10 units around the normal point x = 1.

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296 hot lunches were sold on Friday.

The number of hot lunches sold on Friday can be calculated by multiplying the total number of hot lunches by the relative frequency on Friday:

Hot lunches sold on Friday = 1,350 * 0.22 = 296

Relative frequency is a measure of the number of times an event occurs in a sample, expressed as a proportion of the total number of events. To find the number of hot lunches sold on Friday, we multiply the total number of hot lunches sold in the week by the relative frequency of Friday. This gives us the number of hot lunches sold on Friday, which is 296 in this case. Understanding relative frequency is important in statistics as it helps to summarize data and understand the distribution of events.

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The shape of a cross section that is perpendicular to the base of a triangular prism is a triangle.

A triangular prism is a three-dimensional shape with two parallel triangular bases and three rectangular faces connecting them.

When a cross-section is taken that is perpendicular to one of the bases, the shape of the cross-section is the same as the shape of that base, which is a triangle.

The base of the triangle will be the base of the triangular prism, and the height of the triangle will be the height of the triangular prism.

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The value of in the form y = f(x) by eliminating the parameter is y(t) = x - 2.

Identify the parameter that needs to be eliminated. Determine what type of parameter it is (independent, dependent, etc.). Determine how the parameter relates to the other variables in the equation.

Use algebraic manipulation techniques to eliminate the parameter. Check the final result to ensure that the parameter has been eliminated.

The expressions are x(t) = 3 + t² - 1 and y(t) = t².

We represent x(t) as x.

Now the expression is:

x = 3 + t² - 1

Simplify the expression

x = 2 + t²

Subtract 2 on both side, we get

t² = x - 2

Take square root on both side, we get

t = √x - 2

Now substitute the value of t in y(t) = t².

y(t) = (√x - 2)²

y(t) = x - 2

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The complete question is:

Express x(t) = 3 + t² - 1 and y(t) = t² in the form y=f(x) by eliminating the parameter. (express numbers in exact form. use symbolic notation and fractions where needed.)

Y =

Step-by-step explanation:

si me ayudas yo te ayudo

a)  The x-intercepts of the graph of f(x) are x = 2.5 and x = -1.

b) The coordinates of the vertex are (0.75, -5.125).

c) By using the x-intercepts and vertex obtained in Parts A and B, we can accurately depict the shape and positioning of the parabolic graph of f(x).

Part A: To find the x-intercepts of the graph of f(x), we set f(x) equal to zero and solve for x.

Setting f(x) = 0:

\(2x^2 - 3x - 5 = 0\)

To solve this quadratic equation, we can either factor it or use the quadratic formula. In this case, factoring is not straightforward, so let's use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

For our equation, a = 2, b = -3, and c = -5. Substituting these values into the quadratic formula:

x = (-(-3) ± √((-3)^2 - 4(2)(-5))) / (2(2))

x = (3 ± √(9 + 40)) / 4

x = (3 ± √49) / 4

x = (3 ± 7) / 4

This gives us two possible solutions:

x1 = (3 + 7) / 4 = 10/4 = 2.5

x2 = (3 - 7) / 4 = -4/4 = -1

Therefore, the x-intercepts of the graph of f(x) are x = 2.5 and x = -1.

Part B: To determine whether the vertex of the graph of f(x) is a maximum or minimum, we need to consider the coefficient of the x^2 term in the function f(x). In this case, the coefficient is positive (2), which means the parabola opens upward and the vertex represents a minimum point.

To find the coordinates of the vertex, we can use the formula x = -b / (2a). In our equation, a = 2 and b = -3:

x = -(-3) / (2(2))

x = 3 / 4

x = 0.75

To find the corresponding y-coordinate, we substitute x = 0.75 into the function f(x):

f(0.75) = 2(0.75)^2 - 3(0.75) - 5

f(0.75) = 2(0.5625) - 2.25 - 5

f(0.75) = 1.125 - 2.25 - 5

f(0.75) = -5.125

Therefore, the coordinates of the vertex are (0.75, -5.125).

Part C: To graph the function f(x), we can follow these steps:

Plot the x-intercepts obtained in Part A: (2.5, 0) and (-1, 0).

Plot the vertex obtained in Part B: (0.75, -5.125).

Determine if the parabola opens upward (as determined in Part B) and draw a smooth curve passing through the points.

Extend the curve to the left and right of the vertex, ensuring symmetry.

Label the axes and any other relevant points or features.

By using the x-intercepts and vertex obtained in Parts A and B, we can accurately depict the shape and positioning of the parabolic graph of f(x).

The x-intercepts help determine where the graph intersects the x-axis, and the vertex helps establish the lowest point (minimum) of the parabola. The resulting graph should show a U-shaped curve opening upward with the vertex at (0.75, -5.125) and the x-intercepts at (2.5, 0) and (-1, 0).

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Answer:

The y intercept of Function A is the same as the y intercept as function B

Step-by-step explanation:

they both have a y intercept of 2

y = mx + b

b is the y intercept

in the table all you have to look for is when x is 0