A circuit is wired with a power supply, a resistor and an ammeter (for measuring current). The ammeter reads a current of 24 mA (milliAmps). Determine the new current if the voltage of the power supply was ...increased by a factor of 3 and the resistance was held constant

Answer:

The correct answer is option A: 3.00 × 10^(-11) m.

Explanation:

To find the wavelength of a gamma ray with a frequency of about 10^19 s^(-1), we can use the equation:

wavelength = speed of light / frequency

Given:

Speed of light (c) = 3.00 × 10^8 m/s

Frequency (f) = 10^19 s^(-1)

Substituting the values into the equation:

wavelength = (3.00 × 10^8 m/s) / (10^19 s^(-1))

To simplify the expression, we can rewrite the denominator as (1 / 10^(-19)) s:

wavelength = (3.00 × 10^8 m/s) / (1 / 10^(-19)) s

To divide by a fraction, we multiply by its reciprocal:

wavelength = (3.00 × 10^8 m/s) × (10^(-19) s)

Applying the properties of exponents, we can add the exponents when multiplying with the same base:

wavelength = 3.00 × 10^(-11) m

Therefore, the wavelength of the gamma ray is approximately 3.00 × 10^(-11) m.

A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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Answer:

About 37.70 radians.

Explanation:

1 revolution = 2\(\pi\) radians

∴ 6 revolutions = (6)(2\(\pi\) radians)

6 revolutions = 37.6991 or ≈ 37.70 radians

The amount of work done by the gas is proportional to the pressure and the change in volume, as well as the efficiency of the process. If the pressure and volume are known, the work done by the gas can be calculated by multiplying these values by the efficiency of the process.

The amount of work done by a gas when it expands is proportional to the change in volume, pressure, and temperature. According to the first law of thermodynamics, the energy of a closed system is conserved, so the work done by the expanding gas is equal to the energy transferred from the gas to the environment in the form of work. Therefore, the work done by the gas is equal to the change in energy of the system. Assume that the process is 10% efficient. Then, only 10% of the energy available to the system is converted into work. This means that the remaining 90% of the energy is lost to the environment in the form of heat. As a result, the amount of work done by the gas expanding into the atmosphere is given by the formula

W = E x η, where W is the work done by the gas, E is the energy available to the system, and η is the efficiency of the process. The energy available to the system is determined by the difference between the internal energy of the gas before and after the expansion. The internal energy of a gas is determined by its temperature, pressure, and volume.

Assuming that the temperature and pressure are constant, the change in internal energy is proportional to the change in volume. Therefore, the energy available to the system is equal to the product of the pressure and the change in volume: E = P x ΔV, where P is the pressure of the gas and ΔV is the change in volume during the expansion. Substituting this equation into the formula for work, we get W = P x ΔV x η.

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Interpreting Graphics The velocity-versus-time graph for a shuttle bus moving along a straight path is shown in Figure 13., all the answer is attached.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

a) The time intervals during which the velocity of the shuttle bus is constant: 50 s to 150 s.

b) The time intervals during which the acceleration of the shuttlebus is constant: 500 s to 600s.

c) The value for the average velocity of the shuttle bus during time interval identified in b is: ( -3 +(-5))/2 =m/s = - 4 m/s.

d) The acceleration of the shuttle bus during time interval identified in b = ( -3 +(-5))/(600 - 500) m/s² = 0.02 m/s²

.e) The times at which the velocity of the shuttle bus is zero is : 200s to 300s.

f) The times at which the acceleration of the shuttle bus is zero is : 50s to 150s.

g) The slope of the graph reveals about the acceleration in each time interval that when it is positive the car is accelerated, when it is negative, the car is decelerated.

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(a) The time spent by the player in the top of 10 cm of this jump is 0.14 second.

(b) The time spent by the player in the bottom 10 cm of this jump is 0.38 second.

(c) The result shows that the player spends more time during ascent and decent because of greater distance.

The time taken for the player to jump 80 cm and back to ground is calculated as follows;

t = 2 ( √ ( 2h / g ) )

where;

t = 2 ( √ ( 2 x 0.8 / 9.8 ) )

t = 0.4 s

t = 0.8 second

The time spent by the player in 10 cm jump is calculated as follows;

t =  √ ( 2h / g )

t = √ ( 2  x 0.1 / 9.8 )

t = 0.14 s

From 10 cm at the bottom, the player has travelled 70 cm, and the time of motion of this player is calculated as follows;

t = √ ( 2 x 0.7 / 9.8 )

t = 0.38 second

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Elements of art are stylistic features that are included within an art piece to help the artist communicate. The seven most common elements include line, shape, texture, form, space, colour and value, with the additions of mark making, and materiality.

You would create a darker value if you shaded it, shading it makes it darker.

The instantaneous speed of the ant at t=8s is equal to the slope of the segment between t=7s and t=9s, which is 1.5m/s.

To find the instantaneous speed of the ant at time t=8s, we need to calculate the derivative of the displacement function with respect to time. Since the displacement of the ant is given by a piecewise function, we need to differentiate each segment of the function separately and then piece them together. From 0s to 4s, the displacement of the ant decreases linearly from 6m to 2m. The slope of this segment is -1m/s. From 4s to 7s, the displacement of the ant is constant at 2m. The slope of this segment is zero. From 7s to 9s, the displacement of the ant increases linearly from 2m to 5m. The slope of this segment is 1.5m/s. Finally, from 9s to 10s, the displacement of the ant is constant at 5m. The slope of this segment is zero.

Therefore, the instantaneous speed of the ant at t=8s is equal to the slope of the segment between t=7s and t=9s, which is 1.5m/s. This means that the ant is moving upwards at a constant speed of 1.5m/s at time t=8s. It's important to note that the instantaneous speed of the ant tells us how fast it's moving at a specific moment in time. It's not the same as the average speed over a given time interval, which would be calculated by dividing the total displacement by the total time elapsed.

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Answer:

B) negative reinforcement

Explanation:

Derrick goes to a party and has a bad time, which decreases his party going behavior. This is an example of negative reinforcement. Hence option B is correct.

According to the reinforcement hypothesis, "contingent consequences" of human activities lead to human behaviour. This means that when employees get the appropriate reinforcers, their conduct can change for the better, and bad behaviour can be eliminated.

Self-awareness, self-reflection, and self-regulation are the three key tenets of the self-regulation paradigm of human behaviour. Historically, rewards have correlated with self-regulation. Although the result may have an impact on the conduct, behaviour also need antecedents. Positive reinforcement, negative reinforcement, extinction, and punishment are the four different forms of reinforcement. The use of a positive reinforcer is known as positive reinforcement. In order to encourage the antecedent behavior from that, negative reinforcement is the technique of eliminating anything undesirable from the subject's environment.

Hence option B is correct.

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Answer:

c

Explanation:

after several days of rainy weather, because the road surface becomes waterlogged

With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.

When you increase the number of wire windings in the generator from 5 to 20, the effect on the light bulb will be a brighter illumination. The brightness of the light bulb is directly proportional to the number of windings in the generator.

By increasing the number of windings, you are increasing the amount of wire wrapped around the magnet. This results in a higher number of turns per unit length, leading to an increased magnetic flux passing through the wire coils.

According to Faraday's law of electromagnetic induction, a change in magnetic flux induces an electromotive force (EMF) in a conductor, which in this case is the copper wire. The induced EMF causes electric current to flow through the wire, creating a flow of electrons.

The 30-W light bulb requires a certain amount of electrical power to produce its specified brightness. With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.

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The options that would be a part of a force diagram for the attached image are:

A; A dot that represents the box

B; A vector labeled Fg, pointing straight down

E; A vector labeled Fs, pointing parallel to and up the ramp.

This is a simple force diagram of an item lying on an inclined plane.

The first step is to draw a dot in the center of the box, as here is where we will draw the other forces operating on the box.

Second, we must recognize the force of gravity (F_g), which is a vertical vector line drawn from that dot and whose perpendicular component assures that the box is pressing against the inclined plane.

Third, we can see that the box is moving down the slope, but it will face some friction in the other direction. As a result, we will draw a vector line parallel to the inclined plane from the dot to the left of the box. Frictional force (F_fs) will be shown by this line.

Fourth, there would be a normal force attempting to counteract the perpendicular component of gravity (F_g). This normal force is perpendicular to the perpendicular component of F_g. This is referred to as F_g•sin. We will draw a vector line perpendicular to the inclined plane starting from the dot to represent this normal force. F_n represents this normal force.

Looking at the possibilities, only Options A, B, and E correlate to the forces stated above.

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The required, it experiences a downward force due to gravity and a force due to air resistance.

Projectile motion is the movement of an entity projected into space. After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory.

Here,

When throwing a ball vertically upward, there is a displacement of about 1.0 m from the initial position of the hand to the position where the ball leaves the hand. The mass of the ball is 0.80 kg and it reaches a maximum height of about 20 m above the initial position of the hand. While the ball is in the hand after it leaves, it experiences a downward force due to gravity and a force due to air resistance.

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Answer:

66n

Explanation:

4376

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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The molecules of O2 that are  present in 3.90 L flask at  a temperature of 273 K and a pressure of 1.00 atm is 1.047 x 10^23 molecules  of O2

Step  1:  used the ideal gas equation to calculate the moles of O2

that is Pv=n RT  where;

P(pressure)= 1.00 atm

V(volume) =3.90 L

n(number of moles)=?

R(gas constant) = 0.0821 L.atm/mol.K

T(temperature) = 273 k

by  making n the subject of the formula by  dividing  both side by RT

n= Pv/RT

n=[( 1.00 atm x 3.90 L)  /(0.0821 L.atm/mol.k  x273)]=0.174  moles

Step 2: use the Avogadro's  law constant  to calculate  the number of molecules

that  is  according to Avogadro's law

                          1  mole =  6.02 x10^23  molecules

                            0.174 moles=? molecules

by  cross  multiplication

the number of  molecules

= (0.174  moles x  6.02 x10^23  molecules)/ 1 mole  =1.047 x 10^23 molecules of O2

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Any weapon that loads its bullet and propellant charge from the muzzle is referred to as a muzzleloader. This is separate from the more advanced and complex current breech-loading weapon designs.

Simply said, a muzzle loader is a firearm that loads through the muzzle and is generally lengthy. A spring-loaded arm that hits a replaceable piece of flint on a metal plate to produce sparks, which ignite the gunpowder and light the gun, is the firing mechanism known as a flintlock.

French artist and inventor Marin Le Bourgeoys, who flourished in the Renaissance from 1550 to 1634, is credited with creating the muzzle-loaded rifle.

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We push a car to the distance of 33.939m if we do 28000J work , exerting a force of 825N.

F = applied force

S = distance moved

=28000J/825N

=33.939meter

Thus, we can conclude that the distance moved by the car is 33.939m.

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An object need to move in a straight line in the same direction in equal intervals of time in order for total distance traveled and displacement to be equal.

the kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s is  6,000 J. Option C is correct answer.

The kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s can be calculated by using the formula:

K.E = 1/2 mv²

Where, K.E = Kinetic energy of the objectm = Mass of the objectv = Velocity of the object

Putting the given values in the above formula:

K.E = 1/2 mv²K.E = 1/2 × 30 kg × (20 m/s)²K.E = 1/2 × 30 × 400K.E = 6000 joules

The correct answer is C.

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The electric potential generated when traveling 140° is 10 V , under the condition that the length of the conductor is 5 cm, and it rotates perpendicular to the diameter of the circle of 2.7 cm.

The electric potential induced by a rotating conductor in a magnetic field is called the motional emf. The magnitude of the motional emf is derived and stated by the formula:
emf = B × L × w × sin(θ)
Here,
B = magnetic field strength,
L = length of the conductor,
w = angular velocity of the conductor,
θ = angle between the direction of motion and the magnetic field.

For this case,
we have
B = 672 T,
L = 5 cm = 0.05 m,
w = 0.1 rad/s concerning t < 2 s
w = 0.1 + 0.14 × (t - 2) rad/s for t >= 2 s ¹.
The angle traveled in 2 seconds is:
θ = w × t = 0.1 rad/s × 2 s = 0.2 rad
After that, it maintains a constant angular velocity so that at t = 3 s, it has traveled an additional:
theta = w × t = (0.1 + 0.14 × (3 - 2)) rad/s × (3 - 2) s = 0.24 rad
The total angle traveled up to this point is:
θtotal = 140° × pi / 180° + 0.2 rad + 0.24 rad = 1.17 rad
Therefore, the electric potential generated when traveling this angle is:
emf = B ×L × w ×sin(θtotal)
= 672 T × 0.05 m × (0.1 + 0.14 ×(3 - 2)) rad/s × sin(1.17)
≈ 10 V
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Answer:

i need help with the same question

Explanation:

If you have contacted a seller to report a problem with a product and you were ignored, it is best to contact your local consumer protection agency or better business bureau.

This is the final destination for goods and services and is the individual who purchases them for personal, family reasons etc and not for resale which is why they are referred to as buyer.

In cases where seller has been contacted over a problem with the product and ignores, then it is best to contact your local consumer protection agency or better business bureau so that appropriate action will be done and the issue sorted out.

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Explanation:

We have,

Mass of a baseball is 0.147 kg

Initial velocity of the baseball is 44.5 m/s

The ball is moved in the opposite direction with a velocity of 55.5 m/s

It is required to find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat.

Change in momentum,

\(\Delta p=mv-mu\\\\\Delta p=m(v-u)\\\\\Delta p=0.147\times ((-55.5)-44.5)\\\\\Delta p=-14.7\ kg-m/s\\\\|\Delta p|=14.7\ kg-m/s\)

Impulse = 14.7 kg-m/s

Therefore, the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat is 14.7 kg-m/s