The two points that also lie on the circle are:
A (-3,-4) and D (5,0)
Which points also ie on the circle?We know that a all the points on a circle are equidistant to the center of the circle, and in this case, the center is the origin (0, 0).
We know that the point (4, -3) lies on the circle, so the radius of the circle is:
R = √( (4 - 0)^2 + (-3 - 0)^2) = √25 = 5
So, any point that is at 5 units of the origin will also lie on the circle.
These points are:
A: (-3, -4)
R = √( (-3 - 0)^2 + (-4 - 0)^2) = √25 = 5
And the point D: (5, 0)
R = √( (5 - 0)^2 + (0 - 0)^2) = √25 = 5
So the correct options are A and D.
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Three point charges are positioned on the x axis. If the charges and corresponding positions are +32 uc at x = 0, +20 uc at x = 40 cm, and -60 uc at x = 60 cm, what is the magnitude of the electrostatic force on the +32-uc charge?.
Three-point charges are positioned on the x-axis. If the charges and corresponding positions are +32 uc at x = 0, +20 uc at x = 40 cm, and -60 uc at x = 60 cm, the magnitude of the electrostatic force on the +32-uc charge is 7.89 N.
To calculate this, the first step is to calculate the electric field produced by each charge at the position of the +32-uc charge. This can be done by using the equation E = k * q/r^2, where k is the electrostatic constant (8.99x10^9 Nm^2/C^2), q is the charge in question, and r is the distance from the charge. For the +20 uc charge, the electric field is 4.42 N/C. The same equation can be used for the -60 uc charge to find the electric field produced, which is -8.07 N/C.
Next, the electric field due to the two charges needs to be added together to find the total electric field at the position of the +32-uc charge. This is done by simply adding them together, which gives -3.65 N/C. Finally, the magnitude of the electrostatic force on the +32-uc charge can be calculated using the equation F = q * E, where q is the charge in question and E is the electric field. Substituting in the values gives F = +32 * (-3.65) = -115.2 N. The magnitude of this force can be calculated by taking the absolute value, which gives 7.89 N.
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Assume that each year the IRS randomly audits 30% of the tax returns. If a married couple has filed separate returns, answer the following questions. (a) What is the probability that both the husband and the wife will be audited? (b) What is the probability that only one of thern will be audited? (c). What is the probabkity that neither one of them will be audited? (d) What is the probability that at least one of them will be audited?
The problem entails calculating the probability for a scenario in which the IRS audits 30% of tax returns at random and a married pair has filed separate returns. Calculate the chances of both husband and wife being audited, just one of them being audited, neither of them being audited, and at least one of them being audited.
a) Probability that both the husband and the wife will be audited: (0.3)² = 0.09 or 9%
b) Probability that only one of them will be audited:
Probability of the husband being audited and the wife not being audited: (0.3)(0.7) = 0.21 or 21%Probability of the wife being audited and the husband not being audited: (0.7)(0.3) = 0.21 or 21%The probability that only one of them will be audited is the sum of the two probabilities which equals 0.42 or 42%.c) Probability that neither one of them will be audited: (0.7)² = 0.49 or 49%
d) Probability that at least one of them will be audited: This is the complement of the probability that neither one of them will be audited. So, the probability that at least one of them will be audited is 1 - 0.49 = 0.51 or 51%.
The relevant terms in this question are probability and statistics. To solve for the probability of each scenario, we used the formulas for independent probabilities and complements.
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Heyoooo! I need some help with math and hopefully asap <3
It's about substitution with negative numbers, it should be easy, just not for me. Thanks :D
Answer:
\(\displaystyle \frac{29}{6}\)
Step-by-step explanation:
\(\displaystyle 1+\biggr(-\frac{2}{3}\biggr)-(-m)\\\\\rightarrow 1-\frac{2}{3}+m\\\\\rightarrow \frac{1}{3}+\frac{9}{2}\\ \\\rightarrow \frac{2}{6}+\frac{27}{6}\\ \\\rightarrow \frac{29}{6}\)
On dividing -8016 by x, the value obtained is -16. Find the value of integer x.
Answer:
x=501
Step-by-step explanation:
so to find x we take -8016 divide by -16 which equal 501
The required value of x when dividing -8016, the value obtained is -16, is 501.
On dividing -8016 by x, the value obtained is -16. Find the value of integer
What is simplification?In mathematics to operate and interpret the function to make function simple or more understandable called simplification.
Here,
-16 = -8016/x
x = 8016/16
x = 501
Thus, the required value of x when dividing -8016, the value obtained is -16, is 501.
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hello can anyone please help with this.
Selina takes 1 and a half hours to cycle 12 miles.
What is her average cycling speed?
\(▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)
Given terms :
Distance covered (d) = 12 miles
Time taken (t) = 1.5 hour
Average speed :
\(v = \dfrac{d}{t} \)\(v = \dfrac{12}{1.5} \)\(v = 8 \: \ \: mph\)average speed = 8 mph
Answer:
8mph
Speed= Distance/Time
12/1.5= 8mph
Jeans are on sale for $16 per pair. How much will 4 pairs of jeans cost?
Answer:
4 pairs cost $64
Step-by-step explanation:
16*4=64$
Which of the following is a solution to Laplace's equation Vều = 0 on the annulus 1
A solution to Laplace's equation V(r, θ) = 0 on the annulus 1 < r < 2 is B) V(r, θ) = cos(θ).
Laplace's equation in polar coordinates is given by:
∇²V = (1/r) ∂/∂r (r ∂V/∂r) + (1/r²) ∂²V/∂θ² = 0,
where V(r, θ) is the potential function.
To find a solution on the annulus 1 < r < 2, we can assume a separable solution of the form V(r, θ) = R(r)Θ(θ), where R(r) and Θ(θ) are functions of r and θ, respectively.
Separating variables, we have:
(1/r) ∂/∂r (r ∂R/∂r) + (1/r²) R ∂²Θ/∂θ² = 0.
Considering the angular part, we can set Θ(θ) = cos(θ).
Substituting Θ(θ) = cos(θ) into the equation and rearranging, we get:
(1/r) ∂/∂r (r ∂R/∂r) + (1/r²) R (-sin(θ)) = 0.
Simplifying, we have:
(1/r) ∂/∂r (r ∂R/∂r) - (1/r²) R sin(θ) = 0.
To solve this equation, we can separate the radial part as follows:
(1/r) ∂/∂r (r ∂R/∂r) = (1/r²) R sin(θ).
The left-hand side is only a function of r, while the right-hand side is only a function of θ. Therefore, both sides must be constant. Let's call this constant k.
(1/r) ∂/∂r (r ∂R/∂r) = k.
Solving this radial equation, we find that R(r) = C₁ ln(r) + C₂, where C₁ and C₂ are constants.
Combining the solutions, we have V(r, θ) = (C₁ ln(r) + C₂) cos(θ), where C₁ and C₂ are constants.
The solution to Laplace's equation V(r, θ) = 0 on the annulus 1 < r < 2 is given by V(r, θ) = (C₁ ln(r) + C₂) cos(θ), where C₁ and C₂ are constants. Option B) V(r, θ) = cos(θ) corresponds to this solution when C₁ = 0 and C₂ = 1.
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8^2-12 1/2 ÷ 3 = solve
Answer: 62
The expression given below
\(t^2\text{ - 12w / x}\)Where t = 8, w = 1/2 and x = 3
To find the value of this expression, we need to substitute the value of t, w and x into the above expression
\(\begin{gathered} t^2\text{ - 12w / x} \\ (8)^2\text{ - 12(}\frac{1}{2})\text{ / 3} \\ (8)^2\text{ - }\frac{12}{2}\text{ / 3} \\ =\text{ 64 - 6/3} \\ =\text{ 64 - 2} \\ =\text{ 62} \end{gathered}\)Locate the discontinuities of the function. (Use n where appropriate if there are infinitely many discontinuities.)
y = ln(tan^2x)
x=________
To locate the discontinuities of the function y = ln(tan^2x), we need to find the values of x where the function is not continuous.
First, let's consider the domain of the natural logarithm, ln(x). It is defined only for positive values of x, so tan^2x must be greater than 0 for the function to be defined.
Next, let's consider the domain of tan(x). Tan(x) is undefined when its denominator, cos(x), is equal to 0. This occurs at x = (2n + 1)π/2, where n is an integer.
Since we have tan^2x, the square of tan(x) will always be non-negative. However, we need it to be positive (greater than 0) for ln(tan^2x) to be defined. Tan^2x will be equal to 0 when tan(x) is 0, which occurs at x = nπ, where n is an integer.
Thus, the discontinuities of the function y = ln(tan^2x) occur at two different sets of x values:
1. x = (2n + 1)π/2, where n is an integer, due to the undefined nature of tan(x).
2. x = nπ, where n is an integer, due to tan^2x being 0, which is not in the domain of ln(x).
There are infinitely many discontinuities because of the variable n.
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Olivia and Sam will randomly select mints from a jar that contains 7 blue mints and 3 orange mints.
Olivia selected a blue mint, replaced it back in the jar, and then selected an orange mint.
Sam selected a blue mint, did not replace it back in the jar, and then selected an orange mint.
Who had the highest probability?
Sam had the highest probability at 70%
Sam had the highest probability at 23.3%
Olivia had the highest probability at 70%
Olivia had the highest probability at 23.3%
The person with the highest probability is Sam with the highest probability at 23.3%
How to calculate the probability?From the information, Olivia and Sam will randomly select mints from a jar that contains 7 blue mints and 3 orange mints.
Olivia selected a blue mint, replaced it back in the jar, and then selected an orange mint. The probability will be:
= 7/10 × 3/10
= 21/100
= 21%
Sam selected a blue mint, did not replace it back in the jar, and then selected an orange mint. The probability will be:
= 7/10 × 3/9
= 21/90
= 23.3%
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Which of the following describes a square root of 41?
A.between 5 and 6
B.between 6 and 7
C.between 20 and 21
D.between 40 and 42
Answer:
the answer is b between 6 and 7
Step-by-step explanation:
i say this because the square root of 41 is 6.4031.
6.4031 is in between 6 and 7.
hope this helps :)
classify the triangle according to its SIDES and ANGLES.
Answer:
this is a right angled triangle
Step-by-step explanation:
It has a 90 degree angle
the hypotenuse is the longest
The other two sides adjacent to the right angle are perpendicular
It could also be called an isosceles right angled triangle
Answer:
Right angled and Isosceles
Step-by-step explanation:
Right angled because one corner of the triangle is marked with a square, which shows it is 90degrees.
Isosceles because 2 angles and 2 sides have been marked with similar lines and curves, which shows that they are equal in length. When 2 angles and 2 sides are equal, the triangle is isosceles.
Hope this helps.
Good Luck
Select the correct answer. Which expression is equivalent to the given expression?
Answer:
B
Step-by-step explanation:
2x times x = 2x²
2x times -6 = -12x
1 times x = x
1 times -6 = -6
= 2x² - 12x + x - 6
= 2x² - 11x -6
Mr. Garcia has 11 boys and 13 girls in his math class. He selects two students at random to demonstrate how they solved the day’s challenge assignment. What is the probability that both students chosen in a row are girls
Answer:
29%
Step-by-step explanation:
Amount of girls in his class: 13/24
13/24 x 13/24 = 169/576 or 0.2934...
Basically, 29%
in a plane, four circles with radii 1,3,5, and 7 are tangent to line l at the same point a, but they may be on either side of l. region s consists of all the points that lie inside exactly one of the four circles. what is the maximum possible area of region s?
Answer: Let us call the centers of the four circles C1, C3, C5, and C7, respectively, where the subscript refers to the radius of the circle. Without loss of generality, we can assume that the tangent point A lies to the right of all the centers, as shown in the diagram below:
C7
o-----------o
C5 / \ C3
/ \
o-----------------o
C1
|
|
| l
|
A
Let us first find the coordinates of the centers C1, C3, C5, and C7. Since all the circles are tangent to line l at point A, the centers must lie on the perpendicular bisector of the line segment joining A to the centers. Let us denote the distance from A to the center Cn by dn. Then, the coordinates of Cn are given by (an, dn), where an is the x-coordinate of point A.
Using the Pythagorean theorem, we can write the following equations relating the distances dn:
d1 = sqrt((d3 - 2)^2 - 1)
d3 = sqrt((d5 - 4)^2 - 9)
d5 = sqrt((d7 - 6)^2 - 25)
We can solve these equations to obtain:
d1 = sqrt(16 - (d7 - 6)^2)
d3 = sqrt(4 - (d7 - 6)^2)
d5 = sqrt(1 - (d7 - 6)^2)
Now, let us consider the region S that lies inside exactly one of the four circles. This region is bounded by the circle of radius 1 centered at C1, the circle of radius 3 centered at C3, the circle of radius 5 centered at C5, and the circle of radius 7 centered at C7. Since the circles are all tangent to line l at point A, the boundary of region S must pass through point A.
The maximum possible area of region S occurs when the boundary passes through the centers of the two largest circles, C5 and C7. To see why, imagine sliding the circle of radius 1 along line l until it is tangent to the circle of radius 3 at point B. This increases the area of region S, since it adds more points to the interior of the circle of radius 1 without removing any points from the interior of the other circles. Similarly, sliding the circle of radius 5 along line l until it is tangent to the circle of radius 7 at point C also increases the area of region S. Therefore, the boundary of region S must pass through points B and C.
Using the coordinates we obtained earlier, we can find the x-coordinates of points B and C as follows:
x_B = a - 2 - sqrt(9 - (d7 - 6)^2)
x_C = a + 6 + sqrt(9 - (d7 - 6)^2)
To maximize the area of region S, we want to maximize the distance BC. Using the distance formula, we have:
BC^2 = (x_C - x_B)^2 + (d5 - d3)^2
Substituting the expressions we derived earlier for d3 and d5, we get:
BC^2 = 32 - 2(d7 - 6)sqrt(9 - (d7 - 6)^2)
To maximize BC^2, we need to maximize the expression inside the square root. Let y = d7 - 6. Then, we want to maximize:
f(y) = 9y^2 - y^4
Taking the derivative of f(y) with respect to y and setting it equal to zero, we get:
f'(y) = 18y - 4y^3 = 0
This equation has three solutions: y = 0, y = sqrt(6)/2, and y = -sqrt(6)/2. The only solution that gives a maximum value of BC^2 is y = sqrt(6)/2, which corresponds to d7 = 6 + sqrt(6)/2.
Substituting this value of d7 into our expressions for d1, d3, and d5, we obtain:
d1 = sqrt(16 - (sqrt(6)/2)^2) = sqrt(55/2)
d3 = sqrt(4 - (sqrt(6)/2)^2) = sqrt(19/2)
d5 = sqrt(1 - (sqrt(6)/2)^2) = sqrt(5/2)
Using these values, we can compute the coordinates of points B and C as follows:
x_B = a - 2 - sqrt(9 - (sqrt(6)/2)^2) = a - 2 - sqrt(55)/2
x_C = a + 6 + sqrt(9 - (sqrt(6)/2)^2) = a + 6 + sqrt(55)/2
The distance between points B and C is then:
BC = |x_C - x_B| = 8 + sqrt(55)
Finally, the area of region S is given by:
Area(S) = Area(circle of radius 5 centered at C5) - Area(circle of radius 7 centered at C7)
= pi(5^2) - pi(7^2)
= 25pi - 49pi
= -24pi
Since the area of region S cannot be negative, the maximum possible area is zero. This means that there is no point that lies inside exactly one of the four circles. In other words, any point that lies inside one of the circles must also lie inside at least one of the other circles.
Step-by-step explanation:
By multiplying 5/3^4 by _________, we get 5^4
The missing Value, x, that when multiplied by 5/3^4 gives the result of 5^4 is 13125.
The missing value that, when multiplied by 5/3^4, gives the result of 5^4, we can set up the equation:
(5/3^4) * x = 5^4
To solve for x, we can simplify both sides of the equation. First, let's simplify the right side:
5^4 = 5 * 5 * 5 * 5 = 625
Now, let's simplify the left side:
5/3^4 = 5/(3 * 3 * 3 * 3) = 5/81
Now we have:
(5/81) * x = 625
To solve for x, we can multiply both sides of the equation by the reciprocal of 5/81, which is 81/5:
(81/5) * (5/81) * x = (81/5) * 625
On the left side, the fraction (81/5) * (5/81) simplifies to 1, leaving us with:
1 * x = (81/5) * 625
Simplifying the right side:
(81/5) * 625 = 13125
Therefore, the missing value, x, that when multiplied by 5/3^4 gives the result of 5^4 is 13125.
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A. 6
B. 7
C. 12
D. 24
Answer:
A
Step-by-step explanation:
If you count, the number is 12. Then divide that number by 2. You get 6.
[you divide by 2 because you need to find the average. i rlly don't know how to explain better]
Answer:
The answer is A.
6
How do write this in terms of sin θ?
Using trigonometric identities in terns of sinθ, tan²θsin²θ = sin⁴θ/(1 - sin²θ)
What are trigonometric identities?Trigonometric identities are mathematical equations that contain trigonometric ratios.
Given the trigonometric identity tan²θsin²θ, we desire to write it in terms of sinθ, we proceed as follows.
Since we have tan²θsin²θ (1)
Using the trigonometic identity 1 + tan²θ = sec²θ = 1/cos²θ
Making tan²θ subect of the formula, we have that
tan²θ = sec²θ - 1
= 1/cos²θ - 1
So, substituting this into the given equation, we have that
tan²θsin²θ = (1/cos²θ - 1)sin²θ
Now using the trigonometric identity sin²θ + cos²θ = 1
⇒ cos²θ = 1 - sin²θ
So, we have that
tan²θsin²θ = (1/cos²θ - 1)sin²θ
= (1/(1 - sin²θ) - 1)sin²θ
= [1 - (1 - sin²θ )]sin²θ/(1 - sin²θ)
= [1 - 1 + sin²θ )]sin²θ/(1 - sin²θ)
= [0 + sin²θ )]sin²θ/(1 - sin²θ)
= [sin²θ]sin²θ/(1 - sin²θ)
= sin⁴θ/(1 - sin²θ)
So, tan²θsin²θ = sin⁴θ/(1 - sin²θ)
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Amy had $80 to spend on a filter. She spent 20% of the money on a filter and paid $16 to a plumber to install it. What is the percentage of the money she is left with
Amy is left with 60% of the money she had initially.
Let's break down the problem step by step:
Amy had $80 to spend on a filter.
She spent 20% of the money on a filter, which is 0.20 * $80 = $16.
After purchasing the filter, she paid $16 to a plumber to install it.
So far, Amy has spent a total of $16 + $16 = $32.
To find out how much money Amy is left with, we subtract the amount she has spent from the initial amount she had:
$80 - $32 = $48
Amy is left with $48.
To determine the percentage of the money she is left with, we can calculate what portion of the initial amount she still has:
($48 / $80) * 100 = 60%
Therefore, Amy is left with 60% of the money she had initially.
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8. Use point-slope form to write the equation of a line that passes through the point (18, -3) with slope -1.
The equation of the line that passes through the point (18,-3) with slope -1 is y = -x+15.
According to the question,
We have the following information:
The line passes through the point (18,-3) with slope -1.
We know that the following formula is used to find the equation of the line passing through a point with the slope which is denoted by m:
(y-y') = m(x-x')
In this case, we have the following values:
m = -1
x' = 18 and y' = -3
Putting these values in the above formula:
y-(-3) = -1(x-18)
y+3 = -x+18
Subtracting 3 from both sides of the equation:
y = -x+18-3
y = -x+15
Hence, the equation of the line that passes through the point (18,-3) with slope -1 is y = -x+15.
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1.
In July they were traveling away from home and only used $19.24 worth of electricity.
Their solar panel generated $22.75 worth of electricity. What was their amount due in
July?
In July, despite traveling away from home, the individual's electricity consumption amounted to $19.24. However, their solar panel generated $22.75 worth of electricity. Therefore, their amount due for July would be -$3.51.
During July, the individual's electricity consumption was $19.24. This implies that their usage exceeded the electricity generated by their solar panel. The solar panel, on the other hand, generated $22.75 worth of electricity. To calculate the amount due, we need to subtract the generated electricity from the consumption.
$19.24 (electricity consumption) - $22.75 (electricity generated) = -$3.51
The negative sign indicates that the individual's solar panel generated more electricity than their actual consumption. In other words, they produced an excess of $3.51 worth of electricity. Consequently, they would not owe any payment for July but would have a credit of $3.51 that could be carried forward to subsequent months. This credit can help offset future electricity bills or be utilized in the form of a rebate, depending on the individual's agreement with their electricity provider.
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what's -5/1 + (-5/3)
Answer:
Fraction = -20/3 = -18 2/3Decimal = −6.66666666667Step-by-step explanation:
Just times the -5/1 by 3 on both sides and then
add both of the fraction numbers so you can get =
-20/3 in improper fraction or -18 2/3 in mixed number form
or the decimal = −6.66666666667 I hope this helps you, have a great day!
Hope this helps! <3
What kind of solution(s) you expect the following linear equations to have. Transform the equations into a simpler form if necessary.
x − = − x + 12x
One (unique) solution
One (unique) solution
No Solution
No Solution
Infinite Solutions
Answer:
No Solution
Step-by-step explanation:
X can not equal more than its self.
can someone help please
Answer:
1.6
Step-by-step explanation:
1/8 to the power of 732 divided by 8
A sample of a radioactive isotope had an initial mass of 610 mg in the 1990 and decays exponentially over time. A measurement in the year 1992 found that the sample's mass had decayed to 340 mg. What would be the expected mass of the sample in the year 1997, to the nearest whole number?
we get that the equation that models the situation is:
\(m=610\cdot k^t^{}\)when t=2. We get that
\(340=610\cdot k^2\rightarrow k=\sqrt[]{\frac{340}{610}}\approx0.75\)so we get that after 7 years ( 1997 )
\(m=610\cdot(\sqrt[]{\frac{340}{610}})^7\approx79\)Factor completely 81x8 − 1. (9x4 − 1)(9x4 1) (3x2 − 1)(3x2 1)(9x4 − 1) (3x2 − 1)(3x2 1)(9x4 1) (3x2 − 1)(3x2 1)(3x2 1)(3x2 1).
Answer:
(3x^2 - 1)(3x^2 + 1)(9x^4 + 1).
Step-by-step explanation:
Using the identity for the difference of 2 squares;
a^2 - b^2 = (a - b)(a + b)
we put a^2 = 81x^8 and b^2 = 1 giving
a = 9x^4 and b = 1, so:
81x^8 − 1 = (9x^4 - 1)(9x^4 + 1)
Applying the difference of 2 squares to 9x^4 - 1:
= (3x^2 - 1)(3x^2 + 1)(9x^4 + 1).
Answer:
The answer is (3x^2 - 1)(3x^2 + 1)(9x^4 + 1).
Step-by-step explanation:
use implicit differentiation to find an equation of the tangent line to the curve at the given point.
3x^2 + xy + 3y^2 = 7, (1, 1)
(ellipse)
y=
The equation of the tangent line to the ellipse 3x^2 + xy + 3y^2 = 7 at the point (1,1) is y = (-7/37)x + 44/37.
To find the equation of the tangent line to the ellipse given by the equation 3x^2 + xy + 3y^2 = 7 at the point (1,1), we can use implicit differentiation.
Taking the derivative of both sides with respect to x, we get:
6x + y + x(dy/dx) + 6y(dy/dx) = 0
Simplifying and solving for dy/dx, we get:
dy/dx = -(6x + y) / (x + 6y)
At the point (1,1), we have x=1 and y=1, so:
dy/dx = -(6(1) + 1) / (1 + 6(1)) = -7/37
Thus, the slope of the tangent line to the ellipse at (1,1) is -7/37.
To find the equation of the tangent line, we can use the point-slope form:
y - y1 = m(x - x1)
where (x1,y1) is the point of tangency, in this case (1,1), and m is the slope we just found. Plugging in the values, we get:
y - 1 = (-7/37)(x - 1)
Simplifying, we can rewrite this equation in slope-intercept form:
y = (-7/37)x + 44/37
Therefore, the equation of the tangent line to the ellipse 3x^2 + xy + 3y^2 = 7 at the point (1,1) is y = (-7/37)x + 44/37.
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factor: 18x²+39y-15=0
Answer: x = 6
y= 6x2/13 + 5/13
Step-by-step explanation: to solve for and y: Isolate the variable by dividing each side by factors that don't contain the variable
1 point
15.) Vincent pays $202 in advance on his account at the health spa. Each
time he uses the spa, $6 is deducted from the account. Write an equation
that represents the value remaining in his account after x visits to the spa.
Find the value remaining in the account after 18 visits. *
O V = 6 - 202x; $94
O V = 6 - 202x; $1,216
O V = 202 - 6x; $94
O V = 202 - 6x; $1,230
Answer:
O V=202-6x; $94
Step-by-step explanation:
202 needs to be placed before the 6, eliminating options 1 and 2. It can't be option 4 because thats more than 202, leaving us with option 3. Check you answer by replacing x with 18. O V=202-6(18) ->O V=202-108 -> 202-108=$94.