a child is guiding a toy airplane attached to a guide wire around in a circle. the plane circles with a period t. if the child pulls in the guide wire to half the original radius, while simultaneously adjusting the speed so that the period t remains constant, how has the centripetal acceleration changed? select one: a. the acceleration decreases by 2. b. the acceleration decreases by 4. c. the acceleration increases by 2. d. the acceleration increases by 4.

Answer:

A. 9.3m/s

Explanation:

Study Island.

The tension in each cable is approximately 49 N.

To find the tension in the cables, we can analyze the forces acting on the 10 kg mass in equilibrium. Since the mass is centered within the 4.0 m horizontal dimension, we can assume that the tension in each cable is equal.

Let's denote the tension in each cable as T. Since the mass is in equilibrium, the sum of the vertical forces acting on it must be zero.

Considering the vertical forces, we have:

T - T - mg = 0

Since the tension in each cable is equal and directed upwards, the vertical components cancel each other out. Therefore, we can rewrite the equation as:

-2T - mg = 0

We know that the mass (m) is 10 kg and the acceleration due to gravity (g) is approximately 9.8 m/s^2. Substituting these values into the equation, we get:

-2T - (10 kg)(9.8 m/s^2) = 0

Simplifying the equation, we have:

-2T - 98 N = 0

To solve for T, we isolate it on one side of the equation:

-2T = 98 N

T = 98 N / -2

T ≈ -49 N

The negative sign indicates that the tension in the cables is directed downward. However, tension is typically considered a positive quantity, so we can take the absolute value to obtain the magnitude of the tension.

Therefore, the tension in each cable is 49 N.

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The bullet will miss the target by a distance of 1.225 m.

The equations of motion can represent the relationship between the velocity (v and u), acceleration, time (t), and displacement (s) of a moving object.

The mathematical form of the equations of motions can be shown as:

\(v= u +at\\S=ut +\frac{1}{2}at^2\\ v^2-u^2=2aS\)

Given, the distance between the hunter and target, d = 140 m

The speed of the fired bullet, v = 280 m/s

The time taken by a bullet, t = d/v = 140/280 = 0.5 sec

From the equation of motion, find the missed distance:

S = ut + (1/2)gt²

S = 0 + (1/2)× 9.8×(0.5)²

S = 1.225 m

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At 310 degrees, the enzymes and sugars start to disintegrate and rearrange into rings that resemble molecules, which starts the maillard. These molecules' ring-like shapes reflect light, giving off a brown hue.

What is a straightforward explanation of molecules?

Pay attention to how it sounds. (MAH-leh-kyool) the smallest component of a molecule that possesses both its chemical and physical characteristics. One or maybe more atoms make up molecules.

How is a molecule created?

When a number of atoms come together and form bonds with one another, a molecule is created. Each atom shares an electron when a bond is formed between them. A molecule is created as a result of a covalent bond.

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Answer:hhahe

Explanation:

Your question doesn't look right, so lemme assume you meant this.

A heater marked 60w evaporate 6x 10^-³kg of boiling water in 60 seconds. What is the specific latent heat of vaporization of water in jkg?

so you can understand it better..

Latent heat of evaporation is the heat required required to change water to vapor at the same temperature.(100°C)

eg. water boils at 100°C and in presence of more heat it turns to vapor at that Same temperature.

This heat is know as latent heat of Vaporization.

it's give by H=mL

where L is the specific latent heat of vaporization.

The  specific latent heat of vaporization of water  is 6×10⁵ Joule/kg.

The heat or energy that is absorbed or released during a substance's phase change is known as latent heat. It might go from a solid to a liquid or from a liquid to a gas, or vice versa. Enthalpy, a characteristic of heat, is connected to latent heat.

Given parameters:

Mass of the water = 6 × 10⁻³ kg.

Power of the heater = 60 watts.

Time taken = 60 second.

Hence, total heat absorbed by the water = 60×60 joule = 3600 joule.

Hence, specific latent heat of vaporization of water =

total heat absorbed /mass of the water

= 3600/6 × 10⁻³ J/kg

= 6×10⁵ Joule/kg.

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Answer:

La presion a 40 °C es 1.05 atm.

Explanation:

Usando la ecuación ideal de los gases.

\(PV=nRT\)

Debemos recordar, que CNPT significa condiciones normales de presión y temperatura.

Para el primer estado tenemos:

\(P_{1}V_{1}=nRT_{1}\)

Donde:

Para el segundo estado:

\(P_{2}V_{2}=nRT_{2}\)

Donde:

Como ambas ecuaciones tienen el mismo valor de volumen podemos igualarlas:

\(\frac{nRT_{1}}{P_{1}}=\frac{nRT_{2}}{P_{2}}\)

n y R permanecen constantes, se puden cancelar.

\(\frac{T_{1}}{P_{1}}=\frac{T_{2}}{P_{2}}\)

Despejamos P(2).

\(P_{2}=\frac{P_{1}T_{2}}{T_{1}}\)

\(P_{2}=\frac{1*313}{298}\)

\(P_{2}=1.05\: atm\)

Espero te haya sido de ayuda!

Fixed payment is not an element of Installment credit. Option D is correct.

Installment credit:

It is type of credit in which burrower repay loan to lender in periodic small payments.

The repayment is usually fixed but burrower can give more than the monthly installment.

Therefore, fixed payment is not an element of Installment credit. Option D is correct.

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Answer:

all of the above.Explanation:

Answer:

im not sure but i think b. cannot withstand the pressure...

if not all the above.

Explanation:

Answer:

To summarize:

The weight of the box is 123.88 NThe net force acting on the box is 17 N (to the right)The acceleration of the box is 1.35 m/s^2 (to the right)

And the Free Body Diagram is:

\([box]^||54 N (applied force)|||v37 N (friction)\)

Explanation:

Given:

To calculate the weight of the box:

Free Body Diagram:

\([box]^||54 N (applied force)|||v37 N (friction)\)

Net force acting on the box:

To calculate the acceleration of the box:

The smallest possible shaft AE is having the diameter equal to 22nm or 22 nanometer, which can be calculated by using the formula for the torque transmitted by the shaft.

The smallest permissible diameter of shaft AE can be determined using the formula for torque transmitted by a solid shaft:

T = (π/16) × τ × d³

where T is the torque transmitted by the shaft, τ is the maximum shear stress, and d is the diameter of the shaft.

Given that:

T = 45 kW / (2π × 500 rpm) = 0.143 Nm,

τ = 50 MPa, and

that 30 kW is taken off at gear G and 15 kW is taken off at gear H, we can calculate the torque transmitted by gears G and H as follows:

\(T_G\) = 30 kW / (2π × 500 rpm)

= 0.095 Nm

\(T_H\) = 15 kW / (2π × 500 rpm) = 0.048 Nm

The torque transmitted by shaft AE can be calculated as follows:

\(T_{AE}\) = T + \(T_{G}\) + \(T_{H}\) = 0.143 + 0.095 + 0.048 = 0.286 Nm

Substituting these values into the formula for torque transmitted by a solid shaft and solving for d, we get:

d = [(16 × T_AE) / (π × τ)]¹/³

= [(16 × 0.286) / (π × 50)]¹⁾³ ≈ 22 mm

Therefore, the smallest permissible diameter of shaft AE is approximately 22 mm.

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Answer:

0 m/s

Explanation:

Average velocity is displacement over time.

v_avg = Δx / Δt

Displacement is the distance between the start and the finish.

The circumference of the track is:

C = 2πr

C = 2π (7 m)

C ≈ 44 m

The distance covered by the object is:

d = vt

d = (11 m/s) (8 s)

d = 88 m

So the object travels 2 circumferences, meaning it ends back where it started.  Therefore, the displacement is 0 m, and the average velocity is 0 m/s.

D, A mix of farm animals and hunted animals would minimize the environmentally damaging effect of soy.

This is because soy is often grown in environmentally unfriendly ways, and most soy products are fed to farm animals. By consuming fewer farm animals and more hunted animals, individuals can reduce their consumption of soy products and thereby reduce the environmental impact of soy production.

Additionally, reducing overall meat consumption and opting for plant-based alternatives can also have a positive impact on the environment.

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3.24 x \(10^{-2}\) N is the force acting on each charge.

We can use Coulomb's law to determine the magnitude and direction of the force on each charge. Coulomb's law states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them.

Let's assume that we are calculating the force on one of the charges located at a corner of the square. The distance between two adjacent charges is 0.1m, and the charge on each corner is 6.00mc, which is 6.00 x \(10^{-6}\) C.

Using Coulomb's law, we can calculate the magnitude of the force on one charge as:

F = kq₁q₂/r²

where k is the Coulomb constant (9 x \(10^{9}\) N m²/C²), q₁and q₂ are the charges, and r is the distance between the charges.

If we plug in the values, we get:

F = (9 x \(10^{9}\) N m²/C²) * (6.00 x\(10^{-6}\) C)² / (0.1m)²

F = 3.24 x \(10^{-2}\) N

So the magnitude of the force on each charge is 3.24 x \(10^{-2}\) N, and the direction of the force is towards the other charges located at the corners of the square. Since the charges are all the same, the direction of the force will be towards the center of the square.

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To balance the person's weight at a height of 0.397 m, both the person and the charged plate should have charges of approximately 22.6 microcoulombs (μC).

The electric force between two charged objects can be calculated using Coulomb's law: F = (k * |q1 * q2|) / r²

Where F is the force, k is the electrostatic constant (approximately 9 × 10^9 N·m²/C²), q1 and q2 are the charges on the objects, and r is the distance between them. In this case, the electric force should be equal to the weight of the person: F = m * g

Where m is the mass of the person (75.0 kg) and g is the acceleration due to gravity (approximately 9.8 m/s²). Setting these two forces equal, we have: (m * g) = (k * |q1 * q2|) / r²

Now, since both the person and the plate have equal charges, we can rewrite the equation as: (m * g) = (k * q^2) / r²

Rearranging the equation to solve for q, we get: q = √((m * g * r²) / k)

Substituting the given values:
q = √((75.0 kg * 9.8 m/s² * (0.397 m)²) / (9 × 10^9 N·m²/C²))

Calculating the value: q ≈ 2.26 × 10^-5 C

Converting to microcoulombs: q ≈ 22.6 μC

Therefore, to balance the person's weight at a height of 0.397 m, both the person and the charged plate should have charges of approximately 22.6 microcoulombs (μC).

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The maximum angle above the horizontal with which a projectile can be thrown can be found by considering the concept of range. The range of a projectile is the maximum horizontal distance it can cover before returning to the ground.

The range is maximum when the projectile is thrown at an angle of 45 degrees above the horizontal.

So, the maximum angle above the horizontal with which a projectile can be thrown is 45 degrees. It is worth noting that air resistance can affect the trajectory and the range of a projectile, but as per the problem statement, air resistance has been ignored.

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The formula used to determine the ball's speed before to colliding with the pendulum is Vb=Vb(mb,mp,V).

The primary indication of an object's position and speed is its velocity. It is the distance traveled by an item in one unit of time. A physical vector quantity called velocity must have both a magnitude and a direction in order to be defined. Speed is the scalar absolute value (magnitude) of velocity; it is a coherent derived unit whose quantity is measured in metres per second (m/s or ms1) in the SI (metric system).

The definition of magnitude is "how much of a quantity." The magnitude, for example, can be utilized for describing how the .

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Scientific sociology is one of the three methods of sociological investigation that fits the topic the best.

It is possible to define sociology as the scientific study of society, which includes a complete analysis of both internal and external elements that can have an impact on social structures and interaction patterns.

It should be noted that while the sociology field is very broad and full of opportunities that are required to complete the study that is being discussed in the work, this study focuses on social interaction and culture, which help to determine the things that can be used to learn more about the society.

In conclusion, of the three methods of sociological inquiry, scientific sociology is the most effective for the study of society.

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Answer:

The quantities which do not depend on other quantities is called fundamental qiantity. For eg; time,current,lwngth etc...

Answer:

About 250 Hz

Explanation:

People of All ages without a hearing impairment should be able to hear the 8000hz. People under 50 should be able to hear the 12,000hz and people under 40, the 15,000hz. Under 30s should hear the 16,000hz, and the 17,000hz is receivable for those under 24.

Answer: gravitational and buoyant force

Answer:

Assume that \(g =9.81\; \rm m\cdot s^{-1}\), and that the air resistance on the stone is negligible.

a.

Height of the stone: \(389.5\; \rm m\) (above the ground.)

Velocity of the stone: \(\left(-110.5\; \rm m \cdot s^{-1}\right)\) (the stone is travelling downwards.)

b.

Height of the stone: \(629.5\; \rm m\) (above the ground.)

Velocity of the stone: \(\left(-86.5\; \rm m \cdot s^{-1}\right)\) (the stone is travelling downwards.)

Explanation:

If air resistance on the stone is negligible, the stone would be accelerating downwards at a constant \(a = -g = -9.81\; \rm m \cdot s^{-2}\).

Let \(h_0\) denote the initial height of the stone (height of the stone at \(t = 0\).)

Similarly, let \(v_0\) denote the initial velocity of the stone.

Before the stone reaches the ground, the height \(h\) (in meters) of the stone at time \(t\) (in seconds) would be:

\(\displaystyle h(t) = -\frac{1}{2}\, g \cdot t^{2} + v_0 \cdot t + h_0\).

Similarly, before the stone reaches the ground, the velocity \(v\) (in meters-per-second) of the stone at time \(t\) (in seconds) would be:

\(v(t) = -g\cdot t + v_0\).

In section a., \(h_0 = 1000\; \rm m\) while \(v_0 = -12\; \rm m\cdot s^{-1}\) (the stone is initially travelling downwards.) Evaluate both \(h(t)\) and \(v(t)\) for \(t = 10\; \rm m \cdot s^{-1}\):

\(\begin{aligned} h(t) &= -\frac{1}{2}\, g \cdot t^{2} + v_0 \cdot t + h_0 \\ &= -\frac{1}{2}\ \times 9.81\; \rm m\cdot s^{-2}\times (10\; \rm s)^{2} \\&\quad\quad + \left(-12\; \rm m \cdot s^{-1}\right) \times 10\; \rm s + 1000\; \rm m \\[0.5em] &= 389.5\; \rm m \end{aligned}\).

Indeed, the value of \(h(t)\) at \(t = 10\; \rm m \cdot s^{-1}\) is greater than zero. The stone hasn't yet hit the ground, and both the representation for the height of the stone and that for the velocity of the stone are valid.

\(\begin{aligned} v(t) &= -g\cdot t + v_0 \\ &= -9.81\; \rm m\cdot s^{-2}\times 10\; \rm s - 12\; \rm m\cdot s^{-1} \\ &= -110.5\; \rm m \cdot s^{-1} \end{aligned}\).

The value of \(v(t)\) at \(t = 10\; \rm m \cdot s^{-1}\) is negative, meaning that the stone would be travelling downwards at that time.

In section b., \(h_0 = 1000\; \rm m\) while \(v_0 = 12\; \rm m\cdot s^{-1}\) (the stone is initially travelling upwards.) Evaluate both \(h(t)\) and \(v(t)\) for \(t = 10\; \rm m \cdot s^{-1}\):

\(\begin{aligned} h(t) &= -\frac{1}{2}\, g \cdot t^{2} + v_0 \cdot t + h_0 \\ &= -\frac{1}{2}\ \times 9.81\; \rm m\cdot s^{-2}\times (10\; \rm s)^{2} \\&\quad\quad + 12\; \rm m \cdot s^{-1} \times 10\; \rm s + 1000\; \rm m \\[0.5em] &= 629.5\; \rm m \end{aligned}\).

Verify that the value of \(h(t)\) at \(t = 10\; \rm m \cdot s^{-1}\) is indeed greater than zero.

\(\begin{aligned} v(t) &= -g\cdot t + v_0 \\ &= -9.81\; \rm m\cdot s^{-2}\times 10\; \rm s + 12\; \rm m\cdot s^{-1} \\ &= -86.5\; \rm m \cdot s^{-1} \end{aligned}\).

Similarly, the value of \(v(t)\) at \(t = 10\; \rm m \cdot s^{-1}\) is negative because the stone would be travelling downwards at that time.

The minimum coating thickness needed to ensure that light of wavelength 488nm and of perpendicular incidence will be reflected from the two surfaces of the coating with fully constructive interference is \(8.1 \times10^ {-8} m\)

We know that

\(L= \frac {(2m+1) \lambda }{4n}\)

To find the smallest coating thickness, we take m=0. Then,

\(L= \frac { \lambda }{4n}\)

\(L= \frac {488 \times 10^ {-9}}{4 \times 2}\)

\(L = 8.1 \times 10 ^{-8} m\)

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Answer: it can be different in the way which the forces and gravity happens to attract the different neutrinos and photos causing kinematics and have different condensed matter physic so their might also be different universes from this explanation.

Explanation:

To fully evaluate the effectiveness of a new battery toy, the following measurements should be taken.

1. Battery voltage:

Measure the voltage of the battery that powers the toy. This information helps determine the energy input into the toy.

2. Battery power:

Measure the current drawn from the battery while the toy is running. This measurement gives information about the toy's energy consumption.

3. Duration:

Measure how long the toy runs on battery. Indicates the period during which the energy conversion takes place.

Four. Energy consumption:

Calculate the toy's energy consumption by multiplying the battery voltage by the battery current and operating time. This measurement quantifies the energy the toy uses.

5. Output power:

Evaluate toy output. B. Other relevant indicators that characterize work done, speed, or intended function.

The information obtained from these measurements helps us assess the effectiveness of the toy by:

Efficiency is defined as the ratio of available output energy (or work) to input energy (or work). By calculating the energy used and considering the output of the toy, we can compare the energy input and energy output. If a toy is designed to perform a specific task, such as moving an object or emitting sound or light, we can measure how effectively it performs that task compared to the energy input. can be evaluated. The higher the energy output relative to the energy input, the more efficient the toy is, while the lower the energy output, the less efficient it is.

Also, by analyzing the voltage and current of the battery, you can determine the energy consumption of the toy. If a toy's energy consumption is high compared to its intended function, it may indicate inefficiency in the energy conversion process. Taking all these measurements together, we can make a comprehensive assessment and comment on the effectiveness of new battery-operated toys. 

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To assess the efficiency of the new battery-powered toy, you need to collect measurements of energy input and output, and calculate efficiency using a formula. The gathered information helps you comment on how effectively the toy utilizes the battery's energy.

To assess the efficiency of the new battery-powered toy, you would need to collect measurements related to its energy input and output. Specifically, you would need to measure the amount of energy the toy consumes from the battery (input) and the amount of work or useful energy it produces (output). With this information, you can calculate the efficiency of the toy using the formula Efficiency = (Output Energy/Input Energy) x 100%.

The information gathered will help you comment on the efficiency of the toy by providing quantitative data on how effectively the battery's energy is utilized. If the toy has high efficiency, it means it converts a large portion of the energy it receives into useful work or motion. On the other hand, a low efficiency suggests that a significant amount of energy is wasted as heat or in other non-useful forms. In summary, to assess the efficiency of the new battery-powered toy, you need to collect measurements of energy input and output. This information will allow you to calculate the toy's efficiency and make comments on how effectively it utilizes the battery's energy.

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65 mi/h would be the relative velocity between you and the truck.

Speed is the directional speed of an item moving as a sign of its pace of progress ready as seen from a specific casing of reference and as estimated by a specific norm of time. Speed is a principal idea in kinematics, the part of traditional mechanics that depicts the movement of bodies. It could sound convoluted, yet speed is fundamentally speeding in a particular course. It is a vector amount, and that implies we want both extent (speed) and bearing to characterize speed. The SI unit of it is meter each second (ms-1 ). In the event that there is a shift in extent or the course in the speed of a body the body is supposed to speed up.

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X-axis represents the value of a particular characteristic; characteristics of an organism can include such traits as size and color.

A typical sort of distribution for a variable is the bell curve, commonly referred to as the normal distribution. The normal distribution graph, which has a symmetrical bell-shaped curve, is what gave rise to the phrase "bell curve."

The highest point on the curve, or the top of the bell, denotes the most likely outcome in a set of data (its mean, mode, and median), while all other potential outcomes are symmetrically distributed around the mean, resulting in a downward-sloping curve on each side of the peak. The bell curve's standard deviation provides information about its width.

The x-axis represents a variable's value, while the y-axis provides information about the likelihood that we will see that value.

I understand the question you are looking for is this:

In a bell-shaped curve, the x-axis (horizontal direction) of the graph represents which of the following?

a. The value of a particular characteristic; characteristics of an organism can include such traits as size and color.

b. The number of individuals

c. Time

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