A cheetah is known to be the fastest mammal on Earth, at least for short runs. Cheetahs have been observed running a distance of 5.50 × 102 m with an average speed of 1.00 × 102 km/h.
How long would it take a cheetah to cover this distance at this speed?
Answers
The cheetah needs 197.8 seconds to complete the 5.50 *100 m distance.
The distance traveled divided by the time taken is the most popular formula for calculating average speed. The average speed is determined by dividing the whole distance by the total time required to complete the distance. The other calculation, provided you have the initial and final speeds, adds them together and divides by 2.20. calculating the time needed for a cheetah to travel 5.50 102 meters.
10 km/h average speed is equal to 10 / 3.6, or 2.78 m/s.
Dist. = 5.50 102
Time =?
average speed = time / distance
time=5.50 x 100/ 2.78
Time = 197.8 s
Therefore, it takes a cheetah 197.8 seconds to travel 5.50 102 meters.
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Related Questions
What is the energy of a single photon of light that has a frequency of 9. 28 x 1022 hz?.
Answers
The energy of a single photon of light that has a frequency of 9.28 × 10²² Hz is 6.15 × 10⁻¹³ Joule.
Photon energyPhoton energy is the energy radiated or absorbed by a single photon. The formula of photon energy is:
E = hν = hc/λ
Where
E = photon energy (Joule)h = Planck’s constant (6.626 × 10⁻³⁴ Js) ν = photon frequency (Hz)c = speed of light (m/s)λ = photon wavelength (m)Steps to calculate the energy of a single photon
Given:
ν = 9.28 × 10²² Hz
Asked:
E = ?
Answer:
E = hν
E = 6.63 × 10⁻³⁴ × 9.28 × 10²²
E = 61.53 × 10⁻¹²
E = 6.15 × 10⁻¹³ Joule
Thus, the energy of the single photon of light is 6.15 × 10⁻¹³ Joule.
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What other kind of simple machine is a special kind of lever?
Answers
saitama is the strongest
In going from one city to another, a car whose driver tends to get lost goes 30km North, 50km west, and 20km southeast Approximately how far apart are the cities?
Answers
ANSWER:
39.21 km
STEP-BY-STEP EXPLANATION:
To determine the answer we track each move just like this:
Coordinates at the start (city A): (0, 0)
Coordinates after going 30 km north: (0, 30)
Coordinates after going 50 km west: (-50, 30)
Southeast is a move down and to the right of 45°, so we calculate at each coordinate, like this:
\(\begin{gathered} d_e=20\cdot\cos45\degree=10\sqrt{2} \\ \\ d_s=20\cdot\sin45\operatorname{\degree}=10\sqrt{2} \\ \\ \text{ Therefore:} \\ \\ x=-50+10\sqrt{2}=-35.86 \\ \\ y=30-10\sqrt{2}=15.86 \\ \\ \text{ Coordinates at the start \lparen city B\rparen: \lparen-35.86, 15.86\rparen} \end{gathered}\)We calculate the distance between both points as follows:
\(\begin{gathered} d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ \\ \text{ we replacing} \\ \\ d=\sqrt{\left(-35.86-0\right)^2+\left(15.86-0\right)^2} \\ \\ d=\sqrt{1285.9396+251.5396}=\sqrt{1537.4792} \\ \\ d=39.21\text{ km} \end{gathered}\)The distance between both cities is 39.21 km
The table shows the mass of and acceleration due to gravity for several
planets in the solar system. If air resistance is ignored, on which planet would
a space probe with a mass of 250 kg have the highest speed after falling 25
m?
Planet
Mass, 1024 kg
Acceleration due to gravity
Venus
4.87
8.9
Earth
5.97
9.8
Uranus
86.8
8.7
Saturn
568
9
A Earth
B. Saturn
C. Uranus
D. Venus
Answers
C. Uranus
What is acceleration due to gravity?Acceleration due to gravity is the acceleration gained by an object due to gravitational force.
Its SI unit is m/s2. It has both magnitude and direction.
According to the question,
Planet would a space probe with a mass of 250Kg
Distance is 25m.
As
Mass does not affect the speed of falling objects, As there is only gravity acting on it.
The mass of Uranus is:
m=8.681×10²⁵kg
The radius of Uranus is: r = 2.556 \times
Hence , Uranus is the answer
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Answer: Uranus 8.7
Explanation:
Because mass does not effect the velocity of a falling object, only gravity effects it and time. The equation is change in Velocity= 9.8m/s^2 times t (for time). So, ignore the mass and choose the lowest acceleration in the chart if your question asks you for the lowest speed.
what 3 things are produced as a result of the fusion of two atoms
Answers
Answer:
Electron, proton and neutron
Explanation:
In each and every atom they are consist of electron, proton and neutron.
PLEASSSSSEE! PLEASE ANSWER!!! I AM DESPERATE AND THIS IS EXTEMELY URGENT! I NEED AN ANSWER ASAPPP!!!!
Answers
Answer:
most potential is someone in an airplane. second is position A, third is position c, fourth is position D, fifth is position B and least potential is a person standing on the ground.
Explanation:
hopefully you understand what I wrote
under which conditions do both convex and concave mirrors form virtual images state whether or not each can form a real image if the mirror can form a real image describe how this occurs
Answers
Answer:
Explanation:Concave mirrors can make a real image.when the object is away from the mirror it is called real image and when the object is closer to the mirror it is called virtual mirror.
A slide whistle can produce pitches ranging from 500 Hz to 4000 Hz approximately. When the slide whistle is producing a 510 Hz tone, what is the wavelength of that tone in air at standard conditions
Answers
Answer:
67.294cm
Explanation:
............
The slide whistle that is producing a 510 Hz tone, and the wavelength of that tone in the air at standard conditions is 0.5 meters.
What is wavelength?A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in consecutive cycles. The distance a wave travels in one unit of time is considered its speed.
The given frequency is 510 Hz tone.
Speed = distance/time
The faster the sound waves travel, the more distance they will cover in the same time period.
If the distance is 4000, the wave is 2000
The wavelength is the speed of air/ frequency
2000 / 4000 = 0.5 m
Therefore, the wavelength of that tone in the air at standard conditions is 0.5 meters.
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A baseball player hits a ball that soars high into the air. After the ball has left the bat, and while it is traveling upward, what is the direction of acceleration? Ignore air resistance...
Answers
The direction of acceleration of the baseball while it is traveling upward is downward.
This is because the force of gravity, which pulls the ball downward, is the only force acting on the ball once it leaves the bat. According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The net force acting on the ball is its weight due to gravity, which is equal to the mass of the ball times the acceleration due to gravity (9.8 m/s²) and acts in a downward direction. Since the weight is the only force acting on the ball while it is traveling upward, its acceleration is in the same direction as the force, which is downward.
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a lightbulb has a resistance of 240 v when operating with a potential difference of 120 v across it. what is the current in the lightbulb?
Answers
The current through the bulb is 0.5 Ampere.
How is the current in the light bulb calculated?
Given,
Resistance of the bulb = 240 Ω
Potential difference of the bulb, V = 120 V
According to Ohm's Law, I = V/R
Therefore, I = 120/240
I = 0.5 A
The current through the bulb is 0.5 Ampere.
What is Ohm's Law?Ohm's law states that the current through a conductor between two points is directly proportional to the voltage at the two points.The SI unit of electric resistance is the ohm (Ω). 1 Ω = 1 V/A.Ohm's law is important in describing electrical circuits because it relates voltage and current, and resistance regulates the relationship between the two.
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The 6 kg block is then released and accelerates to the right, toward the 5 kg block. The surface is rough and the coefficient of friction between each block and the surface is 0.3 . The two blocks collide, stick together, and move to the right. Remember that the spring is not attached to the 6 kg block. Find the speed of the 6 kg block just before it collides with the 5 kg
Answers
Assuming a 6 kg block is coupled to a spring with a 350 N/m spring constant, and that there is 0.5 m between the two blocks.
Solution:Use the formula
U=1/2kx2
U=1/23500.52
U=43.75 J
Utilizing the law of conservation of energy, KE = U - f.d, where f is the frictional force acting on
1/2 mv2 = 43.75 - mgd
1/2 ×6×v²= 43.75-0.3×6×9.8×0.5\s
v= √11.643
The spring constant is k, what is it?The "spring constant," denoted by the letter "k," is a figure that effectively indicates how "stiff" a spring is. A significant value of k indicates that more power is needed to extend it a given distance than would be necessary to stretch a less stiff spring the same distance.
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What challenges do scientists face in studying the Sun?
Answers
Answer:
Explanation:
The sun sends out solar wind constantly - charged particles that can degrade visual sensors and the skin of spacecraft, and the occasional blast of a solar flare, which can send out clouds of charged ions that can disrupt communications and electronics on board probes and satellites.
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An airplane travels 640 miles from topeka to houston in 3. 2 hours, going against the wind. The return trip is with the wind, and takes only 2 hours. Find the rate of the airplane with no wind. Find the rate of the wind.
Answers
When an airplane travels 640 miles from Topeka to Houston in 3. 2 hours, going against the wind. The return trip is with the wind and takes only 2 hours. Then the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr
Let Va is the velocity of the airplane
Va is the velocity of the wind
When flying against the wind then
(Va+Vw)*(3.2 hours) = 640
3.2Va + 3.2Vw = 640
3.2Vw = 640 - 3.2Va
Vw = 200 - Va----------------(1)
When flying with the wind:
(Va-V)*(2 hours) = 640km
2Va - 2Vw = 640
Va - Vw = 320 ----------------(2)
Putting the value of VW in equation (2) we get
Va - (200-Va) = 320
2Va = 320 +200
2Va = 520
Va = 260
Putting this value in equation (2)
Vw =Va - 360
Vw = 100
Therefore the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr
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A rock is thrown horizontally from the top of a 494.9 m high cliff on Earth near sea level with an initial velocity of 27.6. The ground below the cliff is level. How long, in seconds, will it take the rock to hit the ground below the cliff? Enter your answer at least to the nearest tenth of a second, but do not include units in your answer.
Answers
Answer:
Time 10.0 s
Explanation:
Given:
H = 494.9 m
V = 27.6 m/s
g = 9.8 m/s²
___________
t - ?
The fall time is found from the formula:
H = g·t² / 2
t = √ (2·H / g) = √ (2·494.9 / 9.8 ) ≈ 10.0 s
Attention! An extra given is speed. Find the distance from the base of the rock to the point where the stone fell:
L = V·t = 27.6·10.0 = 276 m
All of the following are basic components of a masonry woodburning fireplace except
A)
a throat.
B)
a heat circulator.
C)
a smoke shelf.
D)
a damper.
Answers
A masonry woodburning fireplace typically includes the following basic components:
A) a throat: The throat is the narrow opening above the firebox that connects it to the flue. It helps direct the flow of smoke and gases.
C) a smoke shelf: The smoke shelf is a horizontal ledge located at the back of the fireplace, just above the firebox. It helps collect and redirect falling debris and prevents downdrafts.
D) a damper: The damper is a movable metal plate located in the throat or flue. It can be opened or closed to control the airflow and regulate the intensity of the fire.
A heat circulator, on the other hand, is not typically a component of a masonry woodburning fireplace. It refers to a device or system used to circulate warm air throughout a room or building, but it is not directly related to the fireplace itself.
the hallway in kim's house is 4.63 m long. her kitchen is 0.0049 km long. which is longer, the hallway or the kitchen? how much longer?
Answers
By 0.27m, the kitchen is farther than the hallway. Because Kim's home's hallway is 4.63 metres long. The distance of her kitchen is 0.0049 kilometres. The distance is same in any velocity.
Distance is measured numerically or sporadically qualitatively. far apart certain things or points are. Distance in physics or common language can refer to a physical length or an assumption based on other factors. Purposes In disciplines that study human behaviour, such the social sciences, qualitative measurements are frequently used. The rate of change in an object's position relative to a frame of reference is called velocity, and it depends on time.
4.9m is equal to 0.0049 km;
the difference is equal to 4.9 - 4.63;
and the difference is equal to 0.27.
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find the focal length of contact lenses that would allow a farsighted person with a near point of 166 cm to read a book at a distance of 10.1 cm
Answers
The required focal length of the contact lenses for the farsighted person to read a book at a distance of 10.1 cm is approximately 9.52 cm. The focal length of the contact lenses that would allow a farsighted person with a near point of 166 cm to read a book at a distance of 10.1 cm is approximately 10.8 cm.
To find the focal length of contact lenses for a farsighted person with a near point of 166 cm to read a book at a distance of 10.1 cm, we can use the lens equation:
1/f = 1/do + 1/di
Where f is the focal length of the lenses, do is the distance of the object (the book) from the lenses, and di is the distance of the image (the book) from the lenses.
Since the person is farsighted, their eye cannot focus on nearby objects, so we can assume that the lenses will act as a converging lens to bring the book's image closer to their eye. Therefore, the value of di will be negative.
Let's plug in the given values:
do = 10.1 cm
di = -166 cm
f = ?
1/f = 1/do + 1/di
1/f = 1/10.1 cm + (-1/166 cm)
1/f = 0.0988 - 0.0060
1/f = 0.0928
f = 10.8 cm
Therefore, the focal length of the contact lenses that would allow a farsighted person with a near point of 166 cm to read a book at a distance of 10.1 cm is approximately 10.8 cm.
To correct farsightedness, converging lenses are used. The lens equation can help us find the focal length of the contact lenses needed:
1/f = 1/do + 1/di
where f is the focal length, do is the object distance (distance from the book), and di is the image distance (near point of the person).
In this case, do = 10.1 cm, and di = 166 cm. Plugging these values into the equation:
1/f = 1/10.1 + 1/166
Now, we solve for the focal length (f):
1/f = 0.09901 + 0.006024
1/f = 0.105034
f = 1/0.105034
f ≈ 9.52 cm
Therefore,The required focal length of the contact lenses for the farsighted person to read a book at a distance of 10.1 cm is approximately 9.52 cm.
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Blocks A and B oscillate at the ends of identical springs. The period of B’s oscillation is twice as long as that of A’s. How many times more massive is block B than block A?
Answers
The period of oscillation is the time it takes for an object to complete one full oscillation, and it is inversely proportional to the square root of the spring constant and directly proportional to the square root of the mass of the object. The period of oscillation is given by the formula T = 2π √(m/k) where T is the period, m is the mass of the object, and k is the spring constant.
Let's assume that the period of A's oscillation is T1 and the period of B's oscillation is T2. From the problem statement, we know that T2 = 2T1. Using the formula for the period of oscillation, we can write:
T2 = 2π √(m2/k) = 2 * 2π √(m1/k) = 2T1 = 2π √(m1/k)
Dividing the equation T2 = 2T1 by T1, we get T2/T1 = 2
So m2/m1 = (k*(T2/T1)^2) = (k*2^2) = 4k
Therefore, block B is 4 times more massive than block A.
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emptying a half-full cylindrical tank suppose the water tank in exercise 36 is half full of water. determine the work required to empty the tank by pumping the water to a level 2 m above the top of the tank. answer
Answers
The work required to empty the cylindrical tank that is half full of water by pumping the water to a level 2 m above the top of the tank is 19695.61897 J.
To determine the work required to empty the cylindrical tank that is half full of water by pumping the water to a level 2m above the top of the tank, the following steps can be followed:
Find the volume of the water in the tank as follows:
V = (πr²h)/2, where V is the volume of water, r is the radius of the cylindrical tank, and h is the height of water in the tank.
Substituting the values given in the question,
V = (π × (0.8 m)² × 1 m)/2 = 1.00530965 m³
Now find the mass of the water as follows:-
The density of water = 1000 kg/m³
Mass = Density × Volume = 1000 kg/m³ × 1.00530965 m³ = 1005.30965 kg
Next, find the potential energy of the water:-
PE = m*g*h, where m is the mass of the water, g is the acceleration due to gravity, and h is the height of the water above the top of the tank.
Substituting the values given in the question,
PE = 1005.30965 kg × 9.81 m/s² × 2 m = 19695.61897 J
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A track star runs 100 meters in 10 seconds. What is the star's average speed?
Answers
Answer:
10m/s
Explanation:
Answer: 10
Explanation: Because, 10*10= 100 or 100/10=10
please help!!! zoom in to read it clearly
Answers
Answer:
imma try nd help cuz i havent seen anybody answer so
1.sara
2.same for both
3.tom
Explanation:
Obtain the theoretical values of nodal voltages for the analysis circuit using Kirchhoff's Laws.
(V1,V2,V3,V4,V12,V23,V24,V34)
Answers
The theoretical values of nodal voltages using Kirchhoff's Laws can be used in the analysis of an electrocardiogram (ECG) to identify potential cardiac abnormalities and diagnose specific heart conditions by providing important information about the electrical activity of the heart.
The ECG measures the electrical activity of the heart by detecting the changes in voltage that occur during each heartbeat. The electrical activity of the heart can be modeled using Kirchhoff's Laws, which describe how current and voltage behave in an electrical circuit. Abnormalities in the electrical activity of the heart can be detected by analyzing the ECG waveform and comparing it to the theoretical values of nodal voltages.
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--The complete Question is, How can the theoretical values of nodal voltages using Kirchhoff's Laws be used in the analysis of an electrocardiogram (ECG) to identify potential cardiac abnormalities and diagnose specific heart conditions? --
a footballer took a penalty kick and ball moved with a velocity of 4mls, calculate the work done by the footballer if the mass of the ball was 40g
Answers
Answer:
Work done = 80 gm/s
Explanation:
Given:
Final velocity (v) = 4 m/s
Initial velocity (u) = 0 m/s
Mass of ball (m) = 40 g
Find:
Work done.
Computation:
Using work energy rule
Work done = Change in kinetic energy
Work done = 1/2[mv-mu]
Work done = 1/2[(40)(4) - (40)(0)]
Work done = 1/2[(40)(4)]
Work done = 80 gm/s
how does lightning interfere with radio wave communication?
Answers
Explanation:Lightning can affect radio waves in a number of ways. First, lightning can cause static interference on radio frequencies. This is because the electrical discharge from lightning can create electromagnetic fields that can disrupt radio signals. Second, lightning can also cause physical damage to radio equipment.
driving along a highway at 31.0 m/s when they hear the siren of a police car approaching them from behind. Edgar perceives the frequency as 1,341 Hz. The police car continues past them, but now Aharon and Edgar perceive the frequency as 1,324 Hz. What is the speed of the police car in meters per second? The speed of sound in air is 344 m/s. Please give your answer with one decimal place.
Answers
we can use the Doppler effect formula, which relates the frequency perceived by a stationary observer, the frequency emitted by the source, the speed of the source, and the speed of sound in the medium. The formula is:
f_observed = f_emitted * (v_sound ± v_observer) / (v_sound ± v_source)
In this case, Aharon and Edgar are stationary observers, and the police car is the moving source. Since the police car is moving towards them when they hear the higher frequency (1,341 Hz), we can write the equation as:
1,341 = f_emitted * (344 + 0) / (344 - v_police)
When the police car moves away from them, they hear the lower frequency (1,324 Hz), so the equation becomes:
1,324 = f_emitted * (344 + 0) / (344 + v_police)
Now, we have a system of two equations with two unknowns (f_emitted and v_police). Divide the first equation by the second equation to eliminate f_emitted:
(1,341 / 1,324) = (344 - v_police) / (344 + v_police)
Solving for v_police, we get:
v_police ≈ 8.6 m/s
So, the speed of the police car is approximately 8.6 meters per second.
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The mass of an unidentified rock is 15.5 grams. Students determine the volume of the rock by placing the rock in a cylinder with water. The students calculate the density of the rock. They determine the identity of the rock based on the density ranges in the table.
The students most likely have which type of rock?
Coal
Dolomite
Peridotite
Sandstone
Answers
Answer:
this density is in the range of Peridotite type rocks
Explanation:
In this graduated cylinder exercise we can directly read the volume of the rock
V = (35 - 30) cm³
V = 5 cm³
They also indicate the mass of the rock
m = 15.5 gr.
Density is defined as the ratio of mass to volume
ρ = 15.5 / 5
ρ= 3.1 gr /cm³
When checking the attached table this density is in the range of Peridotite type rocks
The type of rock the students mostly like have is Peridotite.
We'll begin by calculating the volume of the rock. This can be obtained as follow:
Volume of water = 30 mL
Volume of water + rock = 35 mL
Volume of rock =?Volume of rock = (Volume of water + rock) – (Volume of water)
Volume of rock = 35 – 30
Volume of rock = 5 mLFinally, we shall determine the type of rock the students have by calculating the density of the rock. This can be obtained as follow:Volume of rock = 5 mL = 5 cm³
Mass of rock = 15.5 g
Density of rock =?Density = mass / volume
Density of rock = 15.5 / 5
Density of rock = 3.1 g/cm³Comparing the density of the rock (i.e 3.1 g/cm³) with those given in table above, we can conclude that the rock is peridotiteLearn more: https://brainly.com/question/2040396
during a hard sneeze your eyes might shut for .50s. if you are driving a car at 70 mi/hr during such a sneeze, how far does the car move during that time
Answers
Answer:
About 50 ft.
Explanation:
There is a danger any time you take your eyes off the road. There is also a danger of distraction before and after a sneeze.
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Explain the image below in terms of Newton’s Laws.
Answers
The image given, is explained in terms of Newton's 1st law of motion.
What is Newton's 1st law of motion?Based on Newton's First Law of Motion (Inertia). An object at rest remains at rest, and an object in motion continues in motion at a steady speed and in a straight path until operated on by an unbalanced force.
Newton's first rule of motion states that if a pan of water were being moved along a track, the water would tend to keep moving ahead. However, the water will appear to splash to the right while it goes to the left. Space is nearly a perfect vacuum, devoid of both gravity and matter. Think about a satellite travelling 17,500 mph around the Earth. If a rock were to be launched from the satellite, it would orbit the earth adjacent to the satellite at a speed of 17,500 mph.
Here, in the given image, it is shown that the sofa is remain in the place unless a person forcefully move it from one place to another.
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A giraffe, standing 6.00 m tall, bites a branch off a tree to chew on the leaves
and lets the branch fall to the ground. How long does it take the branch to hit
the ground?
Answers
Answer:
1.11 s.
Explanation:
From the question given above, the following data were obtained:
Height (H) = 6 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =.?
The time taken for the branch to hit the ground can be obtained as follow:
H = ½gt²
6 = ½ × 9.8 × t²
6 = 4.9 × t²
Divide both side by 4.9
t² = 6/4.9
Take the square root of both side
t = √(6/4.9)
t = 1.11 s
Therefore, it will take 1.11 s for the branch to hit the ground.
If you ran at an average speed of 8 m/s, how long would it take you to run 200 meters?
Answers
200/8 = 25