a charged particle a exerts a force of 2.38 n to the right on charged particle b when the particles are 12.9 mm apart. particle b moves straight away from a to make the distance between them 18.2 mm. what vector force does particle b then exert on a?

One hypothesis for planetary differentiation is the process through which various layers with diverse chemical and/or physical features arise.

A planet's trajectory around a star, a natural satellite's path around a planet, or an artificial satellite's course around a space object or place, such as a planet, moon, asteroid, or Lagrange point, are examples of orbits in celestial mechanics.

A spacecraft, planet, moon, star, or other object travels on a curved route called an orbit when it is dragged by the gravity of another object.

The force of gravity is what pulls objects with mass in space. An orbit is a path an object follows as it travels around a certain location in space, such as the Moon's orbit of the Earth.

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Answer:

B. speed changes

Explanation:

As a light beam goes from air to glass, refraction occurs making it slow down, meaning the speed changes.

Answer:

A. true

Suppose A = probability of a day occurring on the weekend

B = probability of day occurring last half of weekend

A int B = 2/7 * 1/2 = 1/7

obviously a Sun can occur only 1/7 of the time

There is no god but Allah (SWT) and Prophet Muhammad (PBUH) is his messenger. This is a contain of confession of faith in Islam religion.

In language, اسلام comes from the word سَلَم  /سِلْم which means safe (as-salām), peace and tranquility, (al-shulhu wa al-amān), surrender (al-istislām), submission (al-khudlū'/al- id'zān), obedient (al-thā'ah). So, Islam means safety and peace because surrender is only to Allah SWT, who has no god but Him. Meanwhile, according to the term Islam is dīn or religion that originated from Allah SWT who was brought down through His Apostles, from the first Prophet: Adam as to the last Prophet: Muhammad saw for the benefit of mankind in this world and in the hereafter .

However, because divine (sky) religions have been changed by humans so that they are no longer original, the term Islam is only aimed at what was brought down by the Prophet Muhammad, namely something that was sent down by Allah SWT in the valid Al -Qur'an and al-Sunnah in the form of rules that contain orders, prohibitions and instructions for human welfare in this world and in the hereafter.

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The valid combinations are:

Total resistance for a circuit in series is R_T = R1 + R2 + R3 + ...

Question 1

To determine the valid combinations of resistors for a circuit with a total resistance of 21, find combinations where the sum of the individual resistances equals 21. Analyze each option:

5, 12, and 4:

Total resistance = 5 + 12 + 4 = 21 (Valid combination)

7, 7, and 7:

Total resistance = 7 + 7 + 7 = 21 (Valid combination)

3, 3, and 3:

Total resistance = 3 + 3 + 3 = 9 (Invalid combination)

5, 5, and 5:

Total resistance = 5 + 5 + 5 = 15 (Invalid combination)

Therefore, the valid combinations are:

5, 12, and 4

7, 7, and 7

Question 2:

Regarding the second question, the equation that calculates the total resistance for a circuit in series is:

R_T = R1 + R2 + R3 + ...

So, the correct option is:

R_T = R1 + R2 + R3 + ...

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The cooling rate of the object is 0.054.

Let's find the cooling rate (k) of an object using the given information. Ts = 10 °CTo = 110 °CT1 = 35 °Ct2 = 25 minutes. Now, the given formula is T = Ts + (To - Ts) e ^ -kt. Here, we know that the temperature drops from 110°C to 35°C, which is 75°C in 25 minutes. Now, we will substitute the values in the formula as follows:35 = 10 + (110 - 10) e ^ (-k × 25) => (35 - 10) / 100 = e ^ (-k × 25) => 25 / 100 = k × 25 => k = 0.054. Therefore, the cooling rate of the object is 0.054. Hence, option A is correct.

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This means that the roller coaster is decelerating at a rate of 8m/s² until it comes to a complete stop.

Decelerating is the process of slowing down or decreasing the speed of a vehicle, person, or object. It is the opposite of accelerating, which is the process of increasing speed. Deceleration can be caused by the force of friction from the road or other surfaces, or by reducing the amount of engine power or braking. Deceleration is necessary to safely slow down and stop a vehicle and to negotiate turns or curves in the road.

The acceleration of the roller coaster can be calculated using the equation
a = (Vf - Vi)/t, where Vf is the final velocity, Vi is the initial velocity, and t is the time taken for the change in velocity to occur.
In this case, Vf = 0m/hr, Vi = 80m/hr, and t = 10s.
Therefore, the acceleration of the roller coaster is -8m/s².
This means that the roller coaster is decelerating at a rate of 8m/s² until it comes to a complete stop.

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Answer:

The total she has to pay is R8500 plus the 5% interest.

PLEASE ADD BRAINEEST

19.778 J of the initial kinetic energy is transformed into potential energy as the sphere rolls up the incline.

Radius of the sphere = 0.15 m

Rotational inertia = 1: 0.040 \(kg /m^{2}\)

Inclination = 30 degrees

total kinetic energy = 20 J

(a) The total energy of the system at the initial position is:

E_i = K_i = 20 J

At the highest point, the kinetic energy will be zero. The potential energy is almost equal to the initial kinetic energy.

E_f = U_f = K_i = 20 J

The potential energy of the sphere at the highest point is calculated by:

U_f = mgh

h = (2/3) R (1 - cos(theta))

h = (2/3)(0.15 m)(1 - cos(30°)) = 0.0675 m

The final potential energy of the system is:

U_f = mgh

U_f = (1/2) mv_\(f^2\)

U_f = 20 J

K_f = (1/2)*(1)*(9.8 \(m/s^2\))*(0.0675 m)

K_f = 0.222 J

Therefore, the initial kinetic energy is converted into potential energy,

Delta K = K_i - K_f

Delta K  = 20 J - 0.222 J

Delta K = 19.778 J

Therefore we can conclude that 19.778 J of the initial kinetic energy is converted to potential energy as the sphere rolls up the incline.

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The amount of initial kinetic energy converted into rotational kinetic energy is 10 J.

When a hollow sphere rolls without slipping up an inclined surface, both translational and rotational motion contribute to its kinetic energy. The initial kinetic energy of the sphere is divided between its translational and rotational components. In this case, since the sphere rolls without slipping, the rotational kinetic energy is given by the equation 1/2 * I * ω^2, where I is the rotational inertia and ω is the angular velocity.

To find the amount of initial kinetic energy converted into rotational kinetic energy, we need to determine the angular velocity of the sphere. Since the sphere is rolling without slipping, the linear velocity v and angular velocity ω are related by the equation v = ω * R, where R is the radius of the sphere.

Given the radius of the sphere as 0.15 m, the rotational inertia as 0.040 kg•m^2, and the total initial kinetic energy as 20 J, we can use the equation for rotational kinetic energy and the relationship between linear and angular velocity to solve for the rotational kinetic energy.

First, we calculate the linear velocity using the equation v = ω * R:

v = ω * R

v = ω * 0.15 m

Next, we substitute the value of linear velocity into the equation for total kinetic energy to solve for the angular velocity:

20 J = 1/2 * I * ω^2 + 1/2 * m * v^2

Since the sphere is rolling without slipping, the linear velocity v can be written as v = ω * R:

20 J = 1/2 * I * ω^2 + 1/2 * m * (ω * R)^2

Now we substitute the given values and solve for ω:

20 J = 1/2 * 0.040 kg•m^2 * ω^2 + 1/2 * m * (ω * 0.15 m)^2

Simplifying the equation and solving for ω:

20 J = 0.020 kg•m^2 * ω^2 + 1/2 * m * (0.15 m)^2 * ω^2

20 J = 0.020 kg•m^2 * ω^2 + 0.01125 kg * ω^2

Combining like terms:

20 J = (0.020 kg•m^2 + 0.01125 kg) * ω^2

20 J = 0.03125 kg•m^2 * ω^2

Now, we isolate ω^2:

ω^2 = 20 J / 0.03125 kg•m^2

ω^2 ≈ 640

Finally, we take the square root of ω^2 to find the angular velocity ω:

ω ≈ √640

ω ≈ 25.3 rad/s

Now that we have the angular velocity ω, we can calculate the rotational kinetic energy:

Rotational kinetic energy = 1/2 * I * ω^2

Rotational kinetic energy = 1/2 * 0.040 kg•m^2 * (25.3 rad/s)^2

Rotational kinetic energy ≈ 10 J

Therefore, approximately 10 J of the initial kinetic energy is converted into rotational kinetic energy.

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W= F x D indicates the relationship between force, distance and work.

Work is defined as an activity in which one exerts force to do something. Work is also refers to an activity in which a person do something regularly to earn a livelihood. People looking for work, a particular task, duty, or assignment often being a part of some larger activity.

The definition of work in physics shows its relationship to energy. When work is done, energy is transferred from one place to another. Work is also known as the product of the force in the direction in which  displacement is covered and displacement.

So we can conclude that Work is the product of Force and Distance.

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Answer:

dont know

Explanation:

need points

The statement that is NOT true is: "the magnetic field lines always cross one another."

Magnetic field lines do not cross one other since they depict the direction of the magnetic field at every position in space. The crossing of two field lines would cause the magnetic field to have two opposite directions at the same spot, which is not possible.

The magnetic field's direction is determined by the orientation of the magnetic dipole moment at its source of starting.

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Answer:

A- The image of the moon on the waters surface is distorted.

Explanation:

Answer:

The Earth's gravity keeps the Moon orbiting us. ... This means gravity makes the Moon accelerate all the time, even though its speed remains constant.

Answer:

final velocity in km/h= 67.2km/h

Explanation:

Data

initial velocity (u)= 24km/h

from 36km/h = 10m/s

then 24km/h= u

hence,

\(u= \frac{24}{36} \times 10\)

u= 20/3 m/s

Time= 6s

Acceleration= 2m/s²

\(v = u + at\)

\(v = \frac{20}{3} + 2(6)\)

\(v = \frac{20}{3} + 12\)

\(v = \frac{56}{3} \)

final velocity = 56/3 m/s

From 10m/s=36km/h

56/3 m/s = V

V(km/h)=

\( \frac{56}{3} \times \frac{36}{10} \)

V(km/h)=67.2km/h

Refer to the attached image.

3. The force on charge q₁ is determined as 0.53 N.

4. The net electric force on q₁ is determined as 61.88 N

The magnitude of the force on q1 is calculated by applying Coulomb's law as shown below;

F = kq₁q₂/r²

where;

F = (9 x 10⁹ x 2 x 10⁻⁶ x 3 x 10⁻⁶ ) / (0.32²)

F = 0.53 N

4. The net force on charge 1 is due to force of charge 2 and charge 3.

F₁₂ = (9 x 10⁹ x 4 x 10⁻⁶ x 9 x 10⁻⁶ )/(0.12²)

F₁₂ = 22.5 N

F₁₃ = (9 x 10⁹ x 7 x 10⁻⁶ x 9 x 10⁻⁶ )/(0.12²)

F₁₃ = 39.375 N

F(net) = F₁₂ + F₁₃

F(net) = 22.5 N + 39.375 N

F(net) = 61.88 N

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The mass of the precipitate is 4.86 g.

We have to know that the equation of the reaction is the first way that we can be able to obtain the mass of the precipitate by the use of the stoichiometry of the reaction.

The equation of the reaction in this case is; AgNO3 + NaCl ---> AgCl + NaNO3. Then we are told that we have that.

Mass of the NaCl = 2 g

Number of moles =  2 g/58 g/mol

= 0.034 moles

Since the reaction is 1:1, we can see that the number of moles of the product is  2 g

Mass of the precipitate = 0.034 moles * 143 g/mol

= 4.86 g

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The value of the constant b in the drag force equation is approximately -3.270 x 10^-5 Ns/m.

To determine the value of the constant b in the drag force equation Fd = -bv for a 3 x 10^-5 kg raindrop with a terminal velocity of 9 m/s, follow these steps,

1. At terminal velocity, the drag force (Fd) is equal to the gravitational force acting on the raindrop (Fg). Therefore, Fd = Fg.

2. Calculate the gravitational force (Fg) acting on the raindrop:
Fg = mass (m) × gravitational acceleration (g)
Fg = (3 x 10^-5 kg) × (9.81 m/s^2) ≈ 2.943 x 10^-4 N

3. Now that we have the gravitational force (Fg), we can use it to determine the drag force (Fd), as they are equal at terminal velocity. So, Fd = 2.943 x 10^-4 N.

4. The drag force equation is Fd = -bv. We know Fd and the terminal velocity (v), so we can solve for the constant b:
2.943 x 10^-4 N = -b × (9 m/s)

5. To find the value of b, divide both sides of the equation by -9 m/s:
b = (2.943 x 10^-4 N) / (-9 m/s) ≈ -3.270 x 10^-5 Ns/m

The value of the constant b in the drag force equation is approximately -3.270 x 10^-5 Ns/m.

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Answer:

Cold Front. A side view of a cold front (A, top) and how it is represented on a weather map (B, bottom).

Warm Front. ...

Stationary Front. ...

Occluded Front.

Answer:

Front 3 is an occluded front. A cold air mass moves toward warmer air. The colder, heavier air pushes the warm air upward until it’s wedged between two cold air masses. Clouds can form from the lifting of the warm air.

Explanation:PLATO

Quantitative statistical analysis involves the use of numerical data to measure and analyze patterns and relationships, while qualitative statistical analysis involves the examination of non-numerical data to identify themes, patterns, and insights.

Qualitative research methods include gathering and interpreting non-numerical data. The following are some sources of qualitative data:

Interviews

Focus groups

Documents

Personal accounts or papers

Cultural records

Observation

In the course of a qualitative study, the researcher may conduct interviews or focus groups to collect data that is not available in existing documents or records. To allow freedom for varied or unexpected answers, interviews and focus groups may be unstructured or semi-structured.

An unstructured or semi-structured format allows the researcher to pose open-ended questions and follow where the responses lead. The responses provide a comprehensive perspective on each individual’s experiences, which are then compared with those of other participants in the study.

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Answer:

440kgm/s

Explanation:

Momentum= mass × velocity

= 110× 4

= 440kgm/s

Answer:

B

Explanation:

using f=ma

a=f/m

=4000/2000

=2 m/s2

The result of multiplying a particle's mass by its velocity is the fluctuation in momentum of a ball, which is 30 kg per second. Since momentum has both a magnitude and a direction, it is a vector quantity.

Almost every action that involves motion has momentum. It is an important tenet of physicsFor instance, if a team is moving forward and trying to stop, it will be difficult.

mv - mu, where u = 0 and v = 10 m/s, equals change in momentum.  Note that the ball moved from rest, therefore its initial velocity was zero (u = 0).

Momentum change is equal to mv mu, which is 3*10 - 3*0, or 30.

30 kg/s = change in momentum.

Momentum can be compared to the "power" a moving body has, or the amount of force it can exert on another body. For instance, a baseball that is thrown quickly (high velocity) and has a small bulk (big mass) can have the exact same momentum as a bowling ball that is travelling very slowly (low velocity).

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Answer: The size of the force varies inversely as the distance square between the two charges. Thus, if the distance between the two charges is doubled, the attraction or repulsion will become weaker and decrease to one-fourth of the original value. The size of the force shall be proportional to the value of each charge.

Explanation:

Hope This Helps!!! : )

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An airplane is flying with a velocity of 42 m/s at a standard altitude of 3 km. At a point on the wing, the airflow velocity is 88 m/s. The  pressure at the point on the wing is  \(P = 6.96 * 10^4 N/m^2\).

To calculate the pressure at a point on the wing, we can use Bernoulli's equation, which relates the pressure, velocity, and density of a fluid in steady, incompressible flow.

The equation is as follows:

P + 1/2 * ρ * \(V^2\) = constant

where P is the pressure, ρ is the density of the fluid, and V is the velocity of the fluid.

Given:

\(P_1 = 7.01 * 10^4 N/m^2\) (pressure at standard altitude)

ρ = \(0.909 kg/m^3\) (density of the fluid)

\(V_1 = 42 m/s\) (velocity of the airplane)

\(V_2 = 88 m/s\) (velocity at the point on the wing)

To find the pressure at the point on the wing, we can use Bernoulli's equation for the standard altitude and the point on the wing, and then solve for P:

\(P_1 + 1/2\) * ρ * \(V_1^2\) = \(P + 1/2\)  * ρ * \(V_2^2\)

Substituting the given values:

\(7.01 * 10^4 + 1/2 * 0.909 * 42^2 = P + 1/2 * 0.909 * 88^2\)

Simplifying the equation:

\(7.01 × 10^4 + 1/2 * 0.909 * 1764 = P + 1/2 * 0.909 * 7744\)

7.01 × 10^4 + 804.906 = P + 3526.242

\(P + 4329.148 = 7.01 *10^4\)

\(P = 7.01 * 10^4 - 4329.148\)

\(P = 6.96 * 10^4 N/m^2\)

Therefore, the pressure at the point on the wing is \(P = 6.96 * 10^4 N/m^2\)

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Answer:dam hold up

Explanation:

Answer:

i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii)  Find the value of k first: F = 400 + k(15^2)                                              k = 28/9    F = 400 +(28/9)(30^2) = 320

Explanation:

Answer:

A) Slower

Explanation:

    Less / low energy means less / slower speed.

Have a nice day!

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- Heather