The electric flux through the three visible sides of the rectangular prism is \(3.39 * 10^4 Nm^2/C.\).
Charge = 300.00 micro C =\(3.00 * 10^{-7} C\)
Prism dimensions = (2d) x (2d) x (2d)
d = 10cm
To find the electric flux through the 3 visible sides of the rectangular prism, we can use Gauss's Law. This law expresses that the electric flux through a sealed region is proportionate to the charge retained by the surface of the body.
The electric flux through this closed surface is calculated by:
phi = Q / epsilon_0
Q = \(3.00 * 10^{-7} C\)
psilon_0 = \(8.85 * 10^{-12} C^2/Nm^2.\)
The electric flux through the three visible sides of the rectangular prism is calculated as:
phi = \(3.00 * 10^{-7} C\) / \(8.85 * 10^{-12} C^2/Nm^2.\)
phi = \(3.39 * 10^4 Nm^2/C.\)
Therefore we can conclude that the electric flux through the three visible sides of the rectangular prism is \(3.39 * 10^4 Nm^2/C.\).
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A solar cell is designed to have a non-reflective coating of a transparent material whose index of refraction is 1.15. What minimum thickness of the film, in nm, for light with a wavelength of 410.74 nm?
ANSWER
\(\begin{equation*} 8.93*10^{-8}m \end{equation*}\)EXPLANATION
Parameters given:
Refractive index, n = 1.15
Wavelength of the light, λ = 410.74 nm
To find the minimum thickness of the non-reflective coating, apply the formula:
\(t_{min}=\frac{\lambda}{4n}\)Therefore, the minimum thickness of the non-reflective coating is:
\(\begin{gathered} t_{min}=\frac{410.74*10^{-9}}{4*1.15} \\ \\ t_{min}=8.93*10^{-8}m \end{gathered}\)That is the answer.
What is 10 °C in °F?
A person pushes a large block on a horizontal ice surface in a straight line to the right with constant speed, as shown above. The mass of the block is 10kg and frictional forces between the block and the ice are negligible. However, the block has a wide cross-sectional area such that air resistance acting on the block cannot be neglected. The opposite is true for the person: air resistance on the person is negligible, but the person’s shoes do not slip on the ice. The table shows the force exerted by the person on the block for several values of constant speed. Force of person’s push (N) Constant speed of block (m/s) ±0.05 20 1.25 40 2.51 60 3.73 80 5.00 (a) A student claims that the data show that the magnitude of the force of air resistance is proportional to the speed of the object, within experimental uncertainty. Use physics principles to explain whether the claim is correct. 0 / 10000 Word Limit Question 2 (b) As the person pushes the block, the person moves with the same constant speed as the block. Consider the scenario in which the person’s speed is 5.00 m/s. i. On the dot below, which represents the person, draw and label the forces (not components) exerted on the person. Each force must be represented by a distinct arrow starting on, and pointing away from, the dot. The figure presents a large dot. 0 / 10000 Word Limit Question 3 ii. The person now stops and releases the block. Determine the magnitude and direction of the block’s acceleration at the instant the block is released.
Newton's second law and graphical analysis allow to find the results for the questions about the air resistance force are:
A) The air resistance is proportional to the velocity because the graph of force vs velocity is linear.
B) In the adjoint we see the free body diagram on the man, where all the forces are in equilibrium.
C) The block acceleration is: a = - 0.03 m/s²
Part A
Newton's second law establishes a relationship between the net force and the product of the mass and the acceleration of the body
∑ F = m a
Where the bold letters indicate vectors, F is the forces, m the mass and the acceleration of the body.
Indicates that the only significant force is air resistance.
∑ F = \(f_{air\ resistence}\)
They give a table of force versus speed.
F (N) v (m / s)
0.05 20
1.25 40
2.51 60
3.73 80
In the attachment we make a graph of the force versus velocity and we see that it is a linear relationship, therefore the air resistance must be proportional to the value of the body, an expression can be:
f_{air\ resistence} = - b v
The results of the equation of the linear regression is:
f = 0.0615 v -1.19
For this case the term b found from the linear regression is
b = 0.0615 N s / m
Part 2
in the second attachment see a free body diagram of the force on the person
The normal force and weight are in balance.
The force applied by the person on the box (F) and there is a force applied by the box on the person (F '), are in equilibrium since the speed is constant, therefore the acceleration is zero.
Part 3
Indicate that the person stops, ask the acceleration of the block of mass 10 kg for the speed of 5 m / s.
Let's write Newton's second law for the x-axis.
f_{air\ resistence} = m a
- b v = m a
a = \(- \frac{b v}{m}\)
Let's calculate
a = \(- \frac{0.0615 \ 5}{10}\)
a = -0.03 m / a²
The negative sign indicates that the block is stopping.
In conclusion, using Newton's second law and graphical analysis we can find the results for the questions about the air resistance force are:
A) The air resistance is proportional to the velocity because the graph of force vs velocity is linear.
B) In the adjoint we see the free body diagram on the man, where all the forces are in equilibrium.
C) The block acceleration is: a = - 0.03 m / s²
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at a given instant in time, an 8-kg rock that has been dropped from a high cliff, experiences an upward force of air resistance of 12 n.note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part.what is the gravitational force on the rock? use g
The gravitational force on the rock is 78.4 Newtons.
At the given instant, the 8-kg rock experiences a gravitational force which can be calculated using the formula:
F_gravity = m * g
where m is the mass of the rock (8 kg) and g is the acceleration due to gravity (approximately 9.8 m/s²).
F_gravity = 8 kg * 9.8 m/s² = 78.4 N
So, the gravitational force on the rock is 78.4 Newtons.his net force causes the rock to accelerate downwards.
The concept of gravitational force is an important one in physics, as it plays a significant role in many natural phenomena. The force of gravity is responsible for the motion of celestial bodies, and it is also a key factor in determining the weight of objects on earth.
Understanding the principles of gravitational force can help us understand the behavior of objects in motion and can also help us develop technologies that are based on these principles.
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Acrane raises acrate with amass of 18 kg to a height of 20 mwh, potential energy
The potential energy of the crate raised by the crane is 3,528 joules. This is calculated using the formula: potential energy = mass * acceleration due to gravity * height. Here, the mass of the crate is 18 kg, acceleration due to gravity is approximately 9.8 m/s², and the height is 20 meters.
The potential energy of an object is determined by its mass, the acceleration due to gravity, and the height it is lifted to. In this case, the mass of the crate is given as 18 kg. The acceleration due to gravity is approximately 9.8 m/s² on Earth. The height to which the crate is raised is 20 meters.
Using the formula for potential energy: potential energy = mass * acceleration due to gravity * height, we can substitute the given values: potential energy = 18 kg * 9.8 m/s² * 20 m.
Simplifying the equation: potential energy = 352.8 kg·m²/s².
Therefore, the potential energy of the crate raised by the crane is approximately 352.8 joules (J).
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hows a 170 g hamster sitting on an 830 g wedge-shaped block. The block, in turn, rests on a spring scale. An extra-fine lubricating oil having μs=μk=0 is sprayed on the top surface of the block, causing the hamster to slide down. Friction between the block and the scale is large enough that the block does not slip on the scale.
The complete question with the scale is missing, so i have attached it.
Answer:
930 g
Explanation:
The block surface is frictionless, therefore, the only force that can possibly be applied to the block from the hamster will be the normal force.
Now, the force of gravity on the hamster acts downward and equals mg. Hence, The normal component will be;
F_n = mgcosθ.
Now, if we Assume that the scale does not respond to horizontal force component, the downward component of the normal force will be expressed as;
F_d = F_n(cosθ)
The scale measures the downward component.
Earlier, we saw that; F_n = mgcosθ
Thus; F_d = mgcosθ × cosθ
F_d = mg(cos²θ)
Now, when the friction was high, the measurement of the scale was;
(m+ M)g
Where ;
m = mass of hamster
M = mass of block
Therefore, when the friction is removed the scale measurement is;
mgcos²θ + Mg or (mcos²θ + M)g
But this is in units of Newton's.
Thus;
Measurement in kg is;
(mcos²θ + M)
We are given;
m = 170 g = 0.17 kg
M = 830 g = 0.83 kg
From the attached scale image,
θ = 40°
Thus;
Measurement = (mcos²θ + M) = ((0.17 cos²40) + 0.83) = 0.93 kg or 930g
A physics student walks 6 meters east, 4 meters north, then 9 meters
west. What is the student's magnitude of displacement from starting
position?
Answer:
5 m
Explanation:
Displacement is the straight-line distance from the starting point to the end point. Student ends up 4m north and 3m west from where he started. Use pythagorean theorem to solve for displacement (d).
d² = 3² + 4² = 25
d = \(\sqrt{25}\) = 5 m
Or, if you remember from geometry, a right triangle with legs of 3 and 4 has a hypotenuse of 5 (3-4-5 right triangle)
using your spectroscope, you observe a light source and see several strong, distinct lines. is this source continuous or discrete? given a line with a wavelength corresponding to 500 nm, calculate the energy of the emitted light.
With the aid of your spectroscope and E = (h*c)/wavelength, you can determine the energy of the emitted light to be 3.97 x 10-19.
What does a mean in terms of wavelength?mathematical representation The movement v (in the x direction), frequency f, and wavelength of traveling sinusoidal waves are frequently expressed mathematically as follows: where y is the value of the wave at any place x and time t, and A is the wave's amplitude.
What is the wavelength measurement unit?The symbol for the wavelength in the SI is typically m, or one metre. The multiples or fractions of something like a meter are also employed for measuring wavelength. Notably, when wavelengths are a significant attribute, exponential powers of 10 are employed. Shorter wavelengths are given as negative exponentials.
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A student makes a homemade resistor from a graphite pencil 5.00 cm long, where the graphite is 0.05 mm in diameter. The resistivity of the graphite is rho=1.38×10−5Ω/mrho=1.38×10−5Ω/m . The homemade resistor is place in series with a switch, a 10.00-mF uncharged capacitor and a 0.50-V power source. (a) What is the RC time constant of the circuit? (b) What is the potential drop across the pencil 1.00 s after the switch is closed?
Answer:
(a) RC time constant of the circuit is 6.9 × 10⁻⁶ ms
(b) The potential drop across the capacitor 1.00 s after the switch is closed is 0 V
Explanation:
The given parameters are
The length of the graphite pencil, L = 5.00 cm
The diameter of the graphite, D = 0.05 mm
The resistivity of the graphite, ρ = 1.38 × 10⁻⁵ Ω/m
The capacitance of the capacitor, C = 10.0 mF
The voltage of the power source, V = 0.50-V
(a) The RC time constant of the circuit, τ, is given as follows;
τ = R × C
Where;
R = The resistance of the graphite = L × ρ
C = The capacitance of the capacitor
∴ R = 5.00 cm × 1.38 × 10⁻⁵ Ω/m = 6.9 × 10⁻⁷ Ω
RC time constant of the circuit, τ = 6.9 × 10⁻⁷ Ω × 10.0 mF = 6.9 × 10⁻⁶ ms
RC time constant of the circuit, τ = 6.9 × 10⁻⁶ ms
(b) The potential drop after t = 1.00 s is given as follows;
\(i = \dfrac{V}{R} \cdot e^{-\dfrac{t}{R\cdot C} }\)
Where;
I = The current in the circuit
V = The voltage in the circuit = 0.50 V
R = resistance in the circuit = 6.9 × 10⁻⁷ Ω
C = The series capacitance = 10.0 mF
t = The time taken = 1.00 s
Plugging in the variable values, gives;
\(I = \dfrac{0.5}{6.9 \times 10^{-7}} \cdot e^{-\dfrac{1.00}{6.9 \times 10^{-7}\times 10.0 \ mF} } = 0\)
V(1) = I·R = 0 × R = 0
The potential drop across the capacitor 1.00 s after the switch is closed, V(1) = 0 V
Use the inteediate value theorem to prove the following claim. There is at least one number that is three greater than twice its fifth power. (Remember, whenever you apply a theorem, you must explain why its hypotheses are satisfied; it is not sufficient to merely assert that they are satisfied.)
The claim that there is at least one number that is three greater than twice its fifth power can be proven using the Intermediate Value Theorem.
To apply the Intermediate Value Theorem, we need to show that the function f(x) = \(2x^5\)+ 3 is continuous on a closed interval [a, b] and takes on both positive and negative values.
1. Continuity:
The function f(x) = \(2x^5\) + 3 is a polynomial function, and polynomial functions are continuous for all real numbers. Therefore, f(x) is continuous on the entire real number line.
2. Positive and Negative Values:
To show that f(x) takes on both positive and negative values, we can consider the limits of f(x) as x approaches positive and negative infinity:
- As x approaches positive infinity, the term \(2x^5\) dominates the function, and f(x) approaches positive infinity.
- As x approaches negative infinity, the term \(2x^5\) dominates the function, and f(x) approaches negative infinity.
Since f(x) approaches both positive and negative infinity as x approaches infinity and negative infinity respectively, it must take on all values in between, including positive and negative values.
By the Intermediate Value Theorem, since f(x) is continuous on the real number line and takes on both positive and negative values, there must exist at least one number c for which f(c) = 0. In other words, there is at least one number that is three greater than twice its fifth power.
In conclusion, by satisfying the hypotheses of the Intermediate Value Theorem, we can prove the claim that there is at least one number that is three greater than twice its fifth power.
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Using the solubility curvechoose all of the statements that are correct
Explanation:
where are the statements
How many degrees do you add to an underarm temperature.
What happens to gravitational potential energy as a rollercoaster moves down a hill? Question 4 options: It is converted to elastic potential energy It increases It is converted to kinetic energy It remains constant.
The gravitational potential energy as a rollercoaster converts to kinetic energy when it moves downhill.
What is kinetic energy?
The kinetic energy of an object or body is due to its motion. When the roller coaster moves downhill it accelerates, thus the gravitational potential energy as a rollercoaster converts to kinetic energy.
The gravitational potential energy of an object or body is due to its position above the ground.
Therefore, the gravitational potential energy as a rollercoaster converts to kinetic energy when it moves downhill.
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Tiny cell structure that carry out specific functions within the cell
Answer:
Organelles
Explanation:
I learned this in science.
how much heat energy is required to melt 520.5 g of hbr ? the molar heat of fusion of hbr is 2.41 kj/mol .
The amount of heat energy required to melt 520.5 g of HBr is 15,670 J or 6.88 kJ
The amount of heat energy required to melt 520.5 g of HBr would be 6.88 kJ. The molar heat of fusion of HBr is given as 2.41 kJ/mol.
Mass of HBr = 520.5 g
Molar mass of HBr = 80 g/mol
Number of moles = (mass/molar mass) = 520.5/80 = 6.50625 mol
Heat energy required to melt = Molar heat of fusion × Number of moles
Heat energy required to melt = 2.41 kJ/mol × 6.50625 mol = 15.67 kJ
But we have to convert kJ to J.
15.67 kJ = 15.67 × 1000 = 15,670 J
So, the amount of heat energy required to melt 520.5 g of HBr is 15,670 J or 6.88 kJ (rounded off to two decimal places).
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A student who weighs 460 N is wearing a backpack that weighs 73 N. The student is standing still on level ground. Give your answers to the following questions in newtons. Remember, enter only the number; don't try to enter the units.(a) What is the magnitude of the net force on the student?(b) What is the magnitude of the contact force on the student by the backpack?(c) What is the magnitude of the contact force on the student by the ground?
For the student who weighs 460 N and weirs a backpack that weighs 73 N, we have:
a) The magnitude of the net force on the student is 533 N.
b) The magnitude of the contact force on the student by the backpack is 73 N.
c) The magnitude of the contact force on the student by the ground is 533 N.
a) The magnitude of the net force on the student is given by the sum of forces in the vertical direction:
\( \Sigma F_{net} = W_{s} + W_{b} \)
Where:
\( W_{s}\): is the weight of the student = 460 N
\( W_{b}\): is the weight of the backpack = 73 N
Hence, the magnitude of the net force is:
\(\Sigma F_{net} = W_{s} + W_{b} = 460 N + 73 N = 533 N\)
b) The magnitude of the contact force on the student is equal to the normal force as follows:
\( F_{c} = N_{c} \)
Where:
\( N_{c} \): is the normal force on the student by the backpack
This normal force is opposite to the weight force:
\( F_{c} = N_{c} = -W_{b} = -73 N \)
Hence, the magnitude of the contact force on the student by the backpack is 73 N.
c) The magnitude of the contact force on the student by the ground is the normal force:
\( F_{n} = N_{g} \)
Where:
\(N_{g} \): is the normal force on the student by the ground
The normal force on the student by the ground is the opposite to the net force of point A, so:
\( F_{n} = -F_{net} = -533 N \)
Therefore, the magnitude of the contact force on the student by the ground is 533 N.
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(d) At certain frequency w silver has the index of refraction n = 0.006 and the extinction index K = 3.524. Estimate the approximate relationship of w, with respect to the plasma frequency wp for silver and calculate the reflectance. [5] (e) A certain intensity distribution of diffracted pattern produced by a remote, unknown aperture has been measured on a remote screen in an experiment. Describe how to reconstruct the aperture from this data.
The relationship between the plasma frequency wp and the refractive index
nwp² = n² + k²
The plasma frequency wp for a material is defined as the frequency at which its refractive index becomes equal to 1. Hence, for silver, at w = wp: 0.006 = sqrt(1 - k²) and 3.524 = kwp = wp*sqrt(1 - 0.006²)wp = 1.39 * 10^16 rad/sNow, let's calculate the reflectance. We know that the reflectance R of a thin film of thickness t on a substrate with refractive index n is given by
R = ((n² + k²) - 1)/(n² + k² + 1)
In the case of silver, we can assume that the film is so thin that the reflectance will be equal to that of the bulk material, which we can find from the refractive index. Hence,R = ((0.006² + 3.524²) - 1)/(0.006² + 3.524² + 1) = 0.995So the reflectance is approximately 0.995.e) The diffraction pattern produced by a remote aperture can be described using the Fourier transform of the aperture function.
If we know the intensity distribution of the diffraction pattern, we can use the inverse Fourier transform to obtain the aperture function. However, this process is not always straightforward, especially if the diffraction pattern has noise or the aperture is not a simple shape.To reconstruct the aperture from the diffraction pattern, we can use techniques such as phase retrieval or iterative algorithms. These methods involve making assumptions about the aperture and iteratively refining the aperture function until it matches the observed diffraction pattern. The specific algorithm used will depend on the details of the experiment and the aperture function being reconstructed.
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What is so unusual about plutos orbit
It has the lowest eccentricity of any planets orbit
It has an unexpectedly short orbital period
Its orbit is titled by 17 degrees relative to the other eight planets
It's orbital period is exactly twice that of Neptune's
The Circulatory System is made up of ?
A Blood and Lungs
B Heart and Blood Veins
C arteries, veins, and heart
What do you mean by focus in science
Which of the following is the clearest example of a neuronal membrane’s selective permeability?
a. The Na+-K+ pump only transports Na+ and K+ ions.
b. K+ ions can diffuse across the membrane more easily than Na+ ions.
c. Diffusion of K+ ions out of the neuron causes the membrane potential to become more negative.
d. The concentration gradient for Na+ ions is inward, but the concentration gradient for K+ ions is outward.
The clearest example of a neuronal membrane's selective permeability is an option (b) - K+ ions can diffuse across the membrane more easily than Na+ ions. This is because the membrane is more permeable to K+ ions than to Na+ ions.
This is due to the presence of potassium ion channels, which allow K+ ions to easily cross the membrane. On the other hand, the presence of sodium ion channels is limited, which makes it more difficult for Na+ ions to cross the membrane.
The selective permeability of the neuronal membrane is crucial for maintaining the proper functioning of the nervous system. It allows for the regulation of ion concentrations inside and outside the cell, which is essential for generating and transmitting electrical signals. This selective permeability is achieved through the presence of ion channels and transporters that selectively allow certain ions to pass through the membrane.
In summary, the clearest example of a neuronal membrane's selective permeability is the fact that K+ ions can diffuse across the membrane more easily than Na+ ions, due to the presence of potassium ion channels and the limited presence of sodium ion channels. Hence, b is the correct option.
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When a plane minor is placed horizontally on level ground at a distance of om from the foot of tower
the top of the tower and its image in the mirror subtend an angle of 90" at the eye. The height of the tower
a) 30m
b) 60m
c) 90 m
d) 120m
Answer:
b : 60m
Explanation:
when a plane mirror is placed horizontally on a level ground at a distance of 60m from the top of tower as shown in figure. a/c to question, The top of tower and its image in the mirror subtend an angle of 90° at the eyes. so, angle made by top of tower and horizontal line is 45° as
An apple is falling from a tree. Disregarding air resistance, which diagram shows the free-body diagram of the force
or forces acting on the apple?
Answer: Second choice (straight down arrow)
Explanation:
I just did it.
Disregarding air resistance, the diagram showing the free-body diagram of the force or forces acting on the apple is second one.
What is free falling?When an object is released from rest in free air considering no friction, the motion is depend only on the acceleration due to gravity, g.
Given is an apple is falling from a tree.
When apple is falling down, the gravity will attract the apple towards the center of the Earth. Air resistance is not considered, otherwise it would be acting upwards.
Normal force will not act as apple in not placed on any kind of surface.
So, the only force acting is force of gravity also called as weight of apple.
Thus, the free-body diagram of the force or forces acting on the apple is second one.
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Help quickly…
As a person travels due east, the altitude of the North Star
(1) decreases
(2) increases
(3) remains the same
East or west: it remains the same.
North: it increases.
South: it decreases.
At the North pole: it's straight up over your head.
At the equator: it's on the horizon, north of you.
South of the equator: it's below the horizon and you can't see it at all.
HELP PLZZZZZZZZ
3. Which of these does not have potential energy?
a. A book resting on the floor
b. A roller coaster at its maximum height
c. A bird flying in the sky
d. A basketball shot in the air
Answer:
a. A book resting on the floor
Explanation:
Potential energy is the energy stored in a object due to its position relative to some zero position. An object possesses gravitational potential energy if it is positioned at a height above/below the zero height.
A 1.0 kg ball traveling 20 m/s is caught by a catcher. In bringing the ball to rest, the mitt recoils for 0.01 s. The absolute value of the average force applied to the ball by the glove is:
The absolute value of the average force applied to the ball by the glove is 200 N The given quantities are,Mass of the ball, m = 1.0 kgInitial velocity of the ball, u = 20 m/sFinal velocity
The ball, v = 0 m/sTime taken to bring the ball to rest, t = 0.01 sThe average force applied on the ball to bring it to rest can be determined using the relation,F = m (v-u)/tSubstitute the values of m, v, u and t in the above relation to get,F = 1.0 × (0 - 20)/0.01Simplify the above expression to get,F = -200 N .
The negative sign indicates that the force applied is in the opposite direction of motion of the ball.The absolute value of the force is 200 N. Therefore, the absolute value of the average force applied to the ball by the glove is 200 N.
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draw the process and control scheme for this system if a constraint controller is used, such that when the smaller of two parallel control valves reached 100%, then the controller output is routed
Technique controllers keep the output of manner variables together with temperature, pressure, glide, or stage within a pre-set variety.
Manner controllers maintain the output of machine variables together with temperature, strain, glide, or degree inner a pre-set variety. They use feedback from sensors to discover any deviation from a setpoint and automatically alter output until parameters are again inside variety.
The challenge of a constraint control scheme is to push a target variable as a ways as viable in the preferred course. With distinctive phrases, The purpose variable shall obtain is relying on the goal most or minimal rate without violating some other boundaries.
Constraints are used to restrict the form of data which can go right into a table. This guarantees the accuracy and reliability of the data inside the desk. If there can be any violation among the constraint and the facts motion, the movement is aborted. Constraints may be column degree or table stage.
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Find the average speed of a car that is travelling 45 km in 5 hours. *
4 points
6 km/h
8 km/h
9 km/h
20 km/h
Answer:
9 km/h
Explanation:
Speed can be found using the following formula.
s=d/t
where d is distance and t is time.
The car traveled 45 kilometers in 5 hours.
d=45 km
t=5 h
Substitute these values into the formula
s=45 km/5 h
Divide 45 by 5
s=9 km/h
The average speed of the car is 9 kilometers per hour.
Solve the equation 2b-20=8
Answer:
B=14
Explanation:
2(14)-20=8
28-20=8
The magnetic field strength inside a current carrying coil will be greater if the coil encloses a(n): A. iron rod B. wooden rod C. glass rod. D. none of these E. vacuum.
The magnetic field strength inside a current carrying coil is directly proportional to the number of turns of wire in the coil and the magnitude of the current flowing through it. However, the presence of a magnetic material like iron inside the coil can significantly enhance the magnetic field strength.
This is because iron has high magnetic permeability, which means it can easily magnetize and demagnetize in response to an external magnetic field. Therefore, if the coil encloses an iron rod, the magnetic field strength inside the coil will be greater compared to the case when the coil encloses a wooden or glass rod.
A wooden or glass rod will not affect the magnetic field strength because they are not magnetic materials. The presence of a vacuum inside the coil will also not affect the magnetic field strength because a vacuum has no magnetic properties. Therefore, the correct answer to this question is option A, an iron rod.
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