The maximum temperature : a. 745 K
Further explanationGiven
Gas at 25°C(298 K) and at a pressure of 0.800 atm
Final pressure = 2 atm
Required
Final temperature
Solution
Gay Lussac's Law
When the volume is not changed, the gas pressure in the vessel is proportional to its absolute temperature
\(\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\)
Input the value :
T₂=(P₂T₁)/P₁
T₂=(2 atm x 298 K)/0.8 atm
T₂ = 745 K = 472 °C
an orbital is defined as a region of the most probable location of
Answer:
Electron
The three-dimensional region around the nucleus, an orbital, indicates the probable location of an electron. Describe the contributions of each of the following experimenters to our understanding of the atom. 1. Louis de Broglie hypothesized that electrons have wavelike properties.
Explanation:
Hope it helps
ABG results are: pH-7.5, PaCO2 32, HCO3 23. What acid/base imbalance does the nurse determine that this client has developed?
Based on the ABG results provided, the nurse can determine that the client has developed respiratory alkalosis. This is indicated by the elevated pH of 7.5 and the decreased PaCO2 of 32. Respiratory alkalosis occurs when there is a hyperventilation that causes the carbon dioxide level in the blood to decrease, leading to an increase in pH.
The HCO3 level of 23 is within normal range, indicating that metabolic compensation has not occurred yet. Possible causes of respiratory alkalosis include anxiety, pain, fever, hypoxia, or overuse of mechanical ventilation.
The nurse should identify the underlying cause and provide appropriate interventions to correct the acid-base imbalance and prevent further complications. These may include reducing anxiety, providing supplemental oxygen, or adjusting mechanical ventilation settings.
Close monitoring of the client's ABG results is essential to ensure effective management of their condition.
Based on the provided ABG results (pH-7.5, PaCO2 32, HCO3 23), the nurse can determine that the client has developed respiratory alkalosis. This is because the pH level is above the normal range of 7.35-7.45, indicating alkalosis, while the PaCO2 level is below the normal range of 35-45 mmHg, suggesting a respiratory cause. The HCO3 level remains within the normal range of 22-26 mEq/L, which further supports that the primary issue is respiratory rather than metabolic.
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Plants can provide the materials that animals use in cellular respiration, and animals can provide some of the materials that plants use for photosynthesis. The image below shows the relationship between photosynthesis and cellular respiration. According to the diagram, how does cellular respiration aid the process of photosynthesis?
It produces ATP.
It produces glucose.
It produces mitochondria.
It produces carbon dioxide
Answer:
it produce atp
Explanation:
.............
Cellular respiration is a metabolic process that occurs in the cells of an organism. Carbon dioxide from cellular respiration aids the process of photosynthesis.
What are cellular respiration and photosynthesis?Cellular respiration is a process that takes place in the organism's cell where the cellular oxygen or chemical energy gets utilized and converted to ATP and waste like carbon dioxide.
The carbon dioxide released by the organism in the atmosphere is used by plants in the process of photosynthesis. Photosynthesis is a process that utilizes carbon and water to form glucose and oxygen.
Therefore, cellular respiration supports the process of photosynthesis by option D. producing carbon dioxide.
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When kc decreases what happens to the molecules in terms of speed space and attractive force pls help
Kc decreases as the temperature in molecules increase.
How many total electrons must be transferred to form one formula unit of Al2O3?
To form one formula unit of Al2O3, a total of 12 electrons (6 from aluminum and 6 from oxygen) must be transferred.
The compound Al2O3, commonly known as aluminum oxide, is formed when two aluminum atoms and three oxygen atoms bond. To determine the number of total electrons that must be transferred to form one formula unit of Al2O3, we first need to find the number of electrons that are present in one formula unit of Al2O3.
Aluminum has an atomic number of 13, which means it has 13 protons and 13 electrons in a neutral atom. Each aluminum atom in Al2O3 contributes 3 electrons, and since there are two aluminum atoms in one formula unit of Al2O3, the total number of electrons contributed by aluminum atoms is 6.
Oxygen has an atomic number of 8, which means it has 8 protons and 8 electrons in a neutral atom. Each oxygen atom in Al2O3 contributes 2 electrons, and since there are three oxygen atoms in one formula unit of Al2O3, the total number of electrons contributed by oxygen atoms is 6.
Therefore, to form one formula unit of Al2O3, a total of 12 electrons (6 from aluminum and 6 from oxygen) must be transferred.
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A set of solubility data is given below.
What is the mass of the dry solute
recovered?
Sample
2
Temperature
(°C)
30.1
Boat Mass
(8)
0.730
Boat +
Solution (g)
0.929
Boat + Dry
(g)
0.816
Answer:
0.086
Explanation:
got it on acellus
The mass of the dry solute recovered from the given data is 0.086 g. Option C
To determine the mass of the dry solute recovered, we need to subtract the mass of the boat from the mass of the boat with the dry solute.
Given the data provided:
Boat Mass: 0.730 g
Boat + Solution: 0.929 g
Boat + Dry: 0.816 g
To find the mass of the dry solute, we subtract the boat mass from the boat + dry mass:
Mass of Dry Solute = (Boat + Dry) - (Boat Mass)
Mass of Dry Solute = 0.816 g - 0.730 g
Mass of Dry Solute = 0.086 g
Therefore, the correct answer is c) 0.086 g.
The mass of the dry solute recovered from the given data is 0.086 g. It is important to note that the mass of the dry solute is obtained by subtracting the mass of the boat from the mass of the boat with the dry solute, as the boat mass represents the weight of the empty boat or container used in the experiment.
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Use the solubility curve to match each scenario with its correct saturation level. All scenarios are in 100g of water.
The curve represents saturation. Below the curve, the water is unsaturated. Above the curve, water is supersaturated. This means that more solute is present than the water can contain.
The line of the solubility curve indicates that the solution is saturated. A saturated solution is defined as a solution in which 100 g of solute is dissolved in 100 g of water. Simulations below this line indicate unsaturated solutions.
The difference between unsaturated and saturated solutes can be determined by adding very small amounts of solute to the solution. In unsaturated solutes, solutes will dissolve, and solutes in saturated solutes will not dissolve. In saturated solutes, crystals will form very quickly around the added solute.
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10) Convert 0.075 km to mm.
hi <3
for this conversion, you need to multiply by 10^6
thus, your answer would be 75000 mm
hope this helps :)
How many moles of magnesium is 6.02 x 1022 atoms of magnesium?
Answer: 0.0500
Explanation:
Please help
in a test rn so id be greatly appreciated if u answered quickly!!
Answer:
Its the second answer.
Explanation:
Answer:
my best guess is B or C. first and last don't make sense. sorry i can't give u a straight answer lol
Explanation:
Gas molecules will move from an area of __________ partial pressure to an area of __________ partial pressure.
Gas molecules will move from an area of higher partial pressure to an area of lower partial pressure.
What does partial pressure allow?The partial pressure of a gas (e.g. carbon dioxide in the lungs) allows the movement of molecules during physiological processes.
For example, during gas exchange, oxygen and carbon dioxide move in the respiratory system and circulatory system due to differences in the partial pressure of these gases.
In conclusion, gas molecules will move from an area of higher partial pressure to an area of lower partial pressure.
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the change in mass of the sucrose membrane bag, compared to that of the glucose membrane bag. molar mass of glucose is 180g.mole and the molar mass of sucrose is 342g/mol
The change in mass of the sucrose membrane bag, compared to that of the glucose membrane bag, can be determined by considering the molar masses of glucose and sucrose. The molar mass of glucose is 180 g/mol, while the molar mass of sucrose is 342 g/mol.
Assuming that both membrane bags contain an equal number of moles, the glucose membrane bag will have a smaller mass change compared to the sucrose membrane bag. This is because the molar mass of glucose is smaller than that of sucrose. However, the specific mass change values cannot be determined without additional information such as the initial and final masses of the bags.
It is also worth noting that the permeability of the membrane and the conditions of the experiment may also affect the observed mass changes.
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When calculating specific heat, what does the variable 'Q'
represent?
A. Mass
B. Specific heat capacity
C. Latent heat
D. Thermal energy
Answer:
D.) Thermal energy
Explanation:
I got it correct on founders edtell
Determine the density in kg/m3 of liquid decanoic
acid at 550.4 K.
The density in kg/m³ of liquid decanoic acid at 550.4 K is about 790 kg/m³ or 0.79 g/cm³.
How to solve the problem:
To find out the density of liquid decanoic acid, we use the formula for density:
density = mass / volume
For a given quantity of decanoic acid, the mass of the decanoic acid will remain the same at different temperatures. However, as temperature increases, the volume of the decanoic acid will increase as well. This is because liquids generally expand when their temperature increases.
We therefore need to take the expansion of the liquid into account when calculating its density.
To do this, we use the following expression: density = mass / (volume at T)
where T is the temperature at which the volume is measured.
To find the volume of the liquid decanoic acid at a given temperature T, we need to know its volume at a reference temperature T0 and the coefficient of thermal expansion of the liquid.
The coefficient of thermal expansion of decanoic acid is about 0.00039 K^-1. This means that the volume of decanoic acid will increase by 0.039% for each degree Celsius increase in temperature above T0.
The reference temperature T0 for density measurements of decanoic acid is typically 20°C (293.15 K).
At this temperature, the density of decanoic acid is about 883 kg/m³.
To calculate the density of decanoic acid at 550.4 K, we first need to find its volume at this temperature.
We can do this using the following formula:
V(T) = V(T0) x [1 + α x (T - T0)]
where V(T) is the volume of the liquid at temperature T,
V(T0) is the volume of the liquid at temperature T0,
α is the coefficient of thermal expansion of the liquid,
and (T - T0) is the temperature difference between T and T0.
Substituting the values, we have:
V(550.4 K) = V(293.15 K) x [1 + (0.00039 K^-1) x (550.4 K - 293.15 K)]V(550.4 K)
= V(293.15 K) x [1 + 0.116]V(550.4 K)
= V(293.15 K) x 1.116
Now, we know that the density of decanoic acid is:
density = mass / V(T)
We can rearrange this to find the mass of the decanoic acid:
m = density x V(T)
Finally, substituting the values, we have:
density = 883 kg/m³ x [1 / (1 + 0.00039 K^-1 x (550.4 K - 293.15 K))]
density = 883 kg/m³ x [1 / 1.116]density = 790 kg/m³
The density in kg/m³ of liquid decanoic acid at 550.4 K is about 790 kg/m³ or 0.79 g/cm³.
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When heated, the alcohol inside a thermometer
expands
O contracts
Answer:
it expands
Explanation:
this is because when it get warmer it runs out of room and makes it got up the tube.
Which set of numbers will balance the following equations? 1's have been included for clarity.__Mn3N4 + __NaF --> __MnF4 + __Na3N a 1; 4; 1; 4 b 1; 4; 3; 2 c 1; 12; 3; 4 d 3; 2; 3; 2
ANSWER
Option C
EXPLANATION
Given that;
\(\text{ ----- Mn}_3N_4\text{ }+\text{ ---- NaF }\rightarrow\text{ ---- MnF}_4\text{ }+\text{ ---Na}_3N\)In the reaction above, we have the following data
At the reactants side;
3 atoms of manganese
4 atoms of nitrogen
1 atom of sodium
1 atom of fluorine
At the products side
1 atom of manganese
4 atoms of fluorine
3 atoms of sodium
1 atom of nitrogen
To balance the above equation, apply the law of conservation mass
Law of conservation of mass states that matter can neither be created nor destroyed but can e transformed from one formato another.
To balance the equation, 1 mole of Mn3N4 reacts with 12 moles of Na Tto give 3 moles of MnF4 and 4 moles of Na3N
So, the new equation becomes
\(\text{ Mn}_3N_4\text{ }+\text{ 12NaF }\rightarrow\text{ 3MnF}_4\text{ }+\text{ 4Na}_3N\)The following data can be deduced in the above equation
At the reactants side
3 atoms of Mn
4 atoms of N
12 atoms of Na
12 atoms of F
At the products side
3 atoms of Mn
12 atoms of F
12 atoms of Na
4 atoms of N
Looking atthe vabove data, the number of atoms of each element at the reactants side is equal to the number of atoms of same elements at the products side.
Hence, the correct answer is option Ce
u
Tungsten (W), Copper (Cu), and Iron (Fe) all belong to the same family, whose members are generally used as conductors of electricity. What family is this?
Answer:
Transition metals.
Explanation:
Conductor of electricity typically refers to any material or object that allow the conduction (transfer) of electric charge.
Tungsten (W), Copper (Cu), and Iron (Fe) all belong to the same family, whose members are generally used as conductors of electricity. This family is known as transition elements.
The transition elements refers to the chemical elements found in group III to XII (3-12) of the periodic table and typically has a d-orbitals (d subshell) that is partially filled with electrons.
Tungsten (W), Copper (Cu), and Iron (Fe) belongs to the family of transition metals.
Conductors of electricity are object or substance that conduct electricity. Currents can flow through them efficiently.
The Elements Tungsten (W), Copper (Cu), and Iron (Fe) all belong to the group/family called transition metals.
Transition metals forms one or more stable ions and they have incompletely filled d orbitals.
Generally, transition metals are good conductor of electricity. They are very good catalyst for chemical reaction.
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A method for determining the quantity of dissolved oxygen in natural waters requires a series of redox reactions. Balance the following chemical equations in that series under the conditions indicated.
The process of measuring the quantity of dissolved oxygen in natural water involves a series of redox reactions. The redox reaction sequence is as follows: First, the oxygen dissolved in the water is converted into hydroxide ions (OH-) by reaction with potassium hydroxide (KOH).KOH + O2 → KO2H + OH-
Then, the hydroxide ions produced in the previous step react with the iodide ions (I-) to form iodate ions (IO3-).
6OH- + 3I- → 3H2O + IO3-
Lastly, the iodate ions produced in the previous reaction react with ascorbic acid to form iodide ions and dehydroascorbic acid, an oxidation product of ascorbic acid.
H2C6H6O6 + IO3- + H2SO4 → I- + SO4-2 + C6H6O6 + H2O
This reaction is then titrated with a standardized sodium thiosulfate (Na2S2O3) solution to determine the amount of iodine produced by the reaction between iodate ions and ascorbic acid. The amount of iodine produced is equivalent to the amount of dissolved oxygen in the sample.
A redox reaction is a type of chemical reaction in which the oxidation states of atoms are changed. In a redox reaction, one reactant is oxidized, meaning it loses electrons, while the other reactant is reduced, meaning it gains electrons. The process of measuring the quantity of dissolved oxygen in natural water involves a series of redox reactions. The series of redox reactions involved in the process is as follows
:First, the oxygen dissolved in the water is converted into hydroxide ions (OH-) by reaction with potassium hydroxide (KOH).
KOH + O2 → KO2H + OH-
Then, the hydroxide ions produced in the previous step react with the iodide ions (I-) to form iodate ions (IO3-).
6OH- + 3I- → 3H2O + IO3-
Lastly, the iodate ions produced in the previous reaction react with ascorbic acid to form iodide ions and dehydroascorbic acid, an oxidation product of ascorbic acid.
H2C6H6O6 + IO3- + H2SO4 → I- + SO4-2 + C6H6O6 + H2O
This reaction is then titrated with a standardized sodium thiosulfate (Na2S2O3) solution to determine the amount of iodine produced by the reaction between iodate ions and ascorbic acid. The amount of iodine produced is equivalent to the amount of dissolved oxygen in the sample
The process of measuring the quantity of dissolved oxygen in natural water involves a series of redox reactions that convert dissolved oxygen into hydroxide ions, iodate ions, and iodide ions. The amount of iodine produced by the reaction between iodate ions and ascorbic acid is then determined by titration with a standardized sodium thiosulfate solution.
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Determine the phase of the substances at the given state using Thermodynamic Properties Tables (in Appendix B) a) water: 60∘C,60kPa b) water: 100∘C,60kPa− c) water: 100∘C,500kPa d) Water: 25∘C,120kPa
e) Ammonia: −25∘C,120kPa f) Ammonia: 25∘C,120kPa g) R-134a: −25∘C,120kPa h) R−134a:25∘C,120kPa
a) vapor, b) saturated liquid, c) saturated liquid, d) compressed liquid, e) compressed liquid, f) compressed liquid, g) compressed liquid, h) compressed liquid.
The phase of substances in different states using Thermodynamic Properties Tables (in Appendix B) is given below:
a) The phase of water at 60∘C and 60kPa is vapor.
b) The phase of water at 100∘C and 60kPa is saturated liquid.
c) The phase of water at 100∘C and 500kPa is saturated liquid.
d) The phase of water at 25∘C and 120kPa is compressed liquid.
e) The phase of ammonia at -25∘C and 120kPa is compressed liquid.
f) The phase of ammonia at 25∘C and 120kPa is compressed liquid.
g) The phase of R-134a at -25∘C and 120kPa is compressed liquid.
h) The phase of R-134a at 25∘C and 120kPa is compressed liquid.
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if there is no diethyl ether in the lab, what other solvent can you use as an alternative? select one: methanol ethyl acetate tetrahydrofuran water
While considering a good solvent alternative for diethyl ether, the best one will be ethyl acetate. It can be used for extraction due to its polarity and less toxicity.
Diethyl ether is one of the commonly used solvent in extraction process of non-polar or slightly polar organic compounds. This is because it does not have hydrogen bonding. So here methanol cannot be used as it has extensive hydrogen bonding and non-polar compounds might not dissolve.
Water also cannot be used because of its polar nature. So organic compounds does not dissolve. Tetrahydrofuran can be used as a solvent, but toxicity levels are higher compared to diethyl ether.
So the alternative that can be used is ethyl acetate, which is also widely used solvent in extraction of non-polar compounds. Also it has less toxicity compared to THF.
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Scenario
Lily had three children. Two of her children has blonde hair and one has dark hair. All of her children share the same father. Blonde hair is recessive (b) to dark hair (B) which is dominant
Prompt
What genotype in the mother and father could produce this outcome in the phenotypes of their
offspring? Write a scientific explanation that explains the genotype for Lily and her husband.
Claim: what is the genotype of mom and dad?
Evidence:
Reasoning
Claim: The genotype of the mother (Lily) is Bb, and the genotype of the father is BB.
Evidence:
1. Two of Lily's children have blonde hair, which is a recessive trait. This indicates that Lily carries the recessive allele for blonde hair (b).
2. Dark hair is the dominant trait, and Lily's husband is the biological father of all three children. Therefore, the father must carry at least one dominant allele (B) for dark hair.
3. All of Lily's children share the same father, so the father must have passed on the dominant allele for dark hair to each child.
4. Since Lily and her husband have three children, and two of them have blonde hair (recessive phenotype), it is likely that Lily is heterozygous for the hair color gene (Bb), while her husband is homozygous dominant (BB).
Reasoning:
Inherited traits are determined by alleles, or alternative forms of a gene. In this case, the gene for hair color has two alleles: B (dominant for dark hair) and b (recessive for blonde hair). The presence of blonde-haired children indicates that Lily carries the recessive allele (b) for hair color, as blonde hair is a recessive trait. Since all of Lily's children share the same father and two of them have blonde hair, it suggests that the father must have passed on the dominant allele (B) for dark hair to each child. This indicates that Lily's husband is homozygous dominant (BB) for the hair color gene. Therefore, the genotype of Lily is Bb, and the genotype of her husband is BB.
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List four greenhouse gases in the atmosphere. For each gas, describe its prevalence in the atmosphere, its natural sources, its human-induced sources, and how its concentration in the atmosphere might be changing.
Answer: Carbon Dioxide, Methane, Nitrous Oxide and Fuorinated Gases
Explanation:Carbon dioxide (CO2): Carbon dioxide enters the atmosphere through burning fossil fuels (coal, natural gas, and oil), solid waste, trees and other biological materials, and also as a result of certain chemical reactions (e.g., manufacture of cement). Carbon dioxide is removed from the atmosphere (or "sequestered") when it is absorbed by plants as part of the biological carbon cycle.
Methane (CH4): Methane is emitted during the production and transport of coal, natural gas, and oil. Methane emissions also result from livestock and other agricultural practices and by the decay of organic waste in municipal solid waste landfills.
Nitrous oxide (N2O): Nitrous oxide is emitted during agricultural and industrial activities, combustion of fossil fuels and solid waste, as well as during treatment of wastewater.
Fluorinated gases: Hydrofluorocarbons, perfluorocarbons, sulfur hexafluoride, and nitrogen trifluoride are synthetic, powerful greenhouse gases that are emitted from a variety of industrial processes. Fluorinated gases are sometimes used as substitutes for stratospheric ozone-depleting substances (e.g., chlorofluorocarbons, hydrochlorofluorocarbons, and halons). These gases are typically emitted in smaller quantities, but because they are potent greenhouse gases, they are sometimes referred to as High Global Warming Potential gases ("High GWP gases").
9 The change from the liquid phase to the gas phase caused by the addition of heat is called_
___
Answer:
Boiling
Explanation:
It's a phase transition from the liquid to gas once at or above the boiling temperature. Boiling is the rapid vaporization of a liquid once heated to its boiling point.
which type of orbitals overlap to form the sigma bond between c and o in h2c=o?
Sigma bond between carbon and oxygen in H2C=O is formed by the overlap of the sp2 hybrid orbital on carbon with one of the unhybridized p orbitals on oxygen. This sigma bond is responsible for sharing of electrons and covalent bonding between carbon, oxygen
Carbon in H2C=O undergoes sp2 hybridization, where one of the 2s orbitals and two of the 2p orbitals combine to form three sp2 hybrid orbitals. These sp2 hybrid orbitals are arranged in a trigonal planar geometry, with one of the orbitals directed towards the oxygen atom.
On the other hand, oxygen in H2C=O has one lone pair of electrons and two unhybridized p orbitals perpendicular to the plane of the molecule.
The sigma bond between carbon and oxygen is formed by the head-on overlap of the sp2 hybrid orbital on carbon with one of the unhybridized p orbitals on oxygen.
This overlap allows for the sharing of electrons and the formation of a sigma bond. The remaining two p orbitals on oxygen are perpendicular to the plane of the molecule and are involved in the formation of pi bonds.
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what building should represent the lysosome and why
Answer:
Food Processing Plant
Explanation:
The lysosomes contain digestive enzymes that break down large food particles into sugars and other simple substances that can be used more easily as does a food processing plant that processes large quantities of food entering the city into smaller packages that can be used more easily.
What mass of iron should be produced if 11.0g of aluminum react with 30.0g of iron (III) oxide?
The mass of iron produced when 11.0 g of aluminum reacts with 30.0 g of iron (III) oxide is approximately 10.48 grams.
To determine the mass of iron produced when 11.0 g of aluminum reacts with 30.0 g of iron (III) oxide, we need to balance the chemical equation and perform stoichiometric calculations.
The balanced chemical equation for the reaction between aluminum and iron (III) oxide can be written as follows:
2 Al + Fe₂O₃ → 2 Fe + Al₂O₃
From the balanced equation, we can see that 2 moles of aluminum react with 1 mole of iron (III) oxide to produce 2 moles of iron and 1 mole of aluminum oxide.
Convert the given masses of aluminum and iron (III) oxide into moles.
Using the molar mass of aluminum (26.98 g/mol) and iron (III) oxide (159.69 g/mol), we can calculate the number of moles for each substance.
Number of moles of aluminum = mass of aluminum / molar mass of aluminum
= 11.0 g / 26.98 g/mol
= 0.408 moles
Number of moles of iron (III) oxide = mass of iron (III) oxide / molar mass of iron (III) oxide
= 30.0 g / 159.69 g/mol
= 0.188 moles
Determine the limiting reactant.
To determine the limiting reactant, we compare the stoichiometric ratio of aluminum to iron (III) oxide. From the balanced equation, we see that 2 moles of aluminum react with 1 mole of iron (III) oxide.
Given that we have 0.408 moles of aluminum and 0.188 moles of iron (III) oxide, we can calculate the moles of iron that can be produced from each reactant.
Moles of iron from aluminum = 2 * 0.408 moles = 0.816 moles
Moles of iron from iron (III) oxide = 0.188 moles
Since the moles of iron from aluminum (0.816 moles) is greater than the moles of iron from iron (III) oxide (0.188 moles), we can conclude that iron (III) oxide is the limiting reactant.
Calculate the mass of iron produced.
To calculate the mass of iron produced, we use the molar mass of iron (55.85 g/mol) and the number of moles of iron from the limiting reactant.
Mass of iron = moles of iron from iron (III) oxide * molar mass of iron
= 0.188 moles * 55.85 g/mol
= 10.48 g
Therefore, the mass of iron produced when 11.0 g of aluminum reacts with 30.0 g of iron (III) oxide is approximately 10.48 grams.
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When 13.5 grams of methane (ch4) burns in 40.0 grams of oxygen, how many grams of water are formed?
22.5 grams H2O are formed when 13.5 grams of methane (ch4) burns in 40.0 grams of oxygen.
What is methane?
Methane, colourless, odourless gas that occurs abundantly in nature and as a product of certain human activities. Methane is the simplest member of the paraffin series of hydrocarbons and is among the most potent of the greenhouse gases. Its chemical formula is CH4.
Where do methane emissions come from?
According to the EPA, globally, 50 to 65% of total methane emissions come from the following human-caused activities:
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Section II: Observations and Conclusions
What charts, tables, or drawings would clearly show what you have learned in this lab?
Each chart, table, or drawing should have the following items:
An appropriate title
Appropriate labels
need help with lab!- earth and space seince 1
The Tables that clearly show what you have learned in this lab:
Centered on the page.Numbered in the order they appear in the text.Referenced in the order they appear in the text.Labeled with the table number and descriptive title above the table.Labeled with column and/or row labels that describe the data, including units of measurement.What is data?Data is described as a collection of discrete values that convey information, describing the quantity, quality, fact, statistics, other basic units of meaning, or simply sequences of symbols that may be further interpreted.
In most cases, we can also use a dichotomous key as it helps in the classification of objects by sorting it out with Yes and No questions, until every object is single.
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What would be the mass of 9.65x1025 molecules of water
2890 g H₂O
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Stoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
9.65 × 10²⁵ molecules H₂O (water)
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
Step 3: Convert
Set up: \(\displaystyle 9.65 \cdot 10^{25} \ molecules \ H_2O(\frac{1 \ mol \ H_2O}{6.022 \cdot 10^{23} \ molecules \ H_2O})(\frac{18.02 \ g \ H_2O}{1 \ mol \ H_2O})\)Divide/Multiply: \(\displaystyle 2887.63 \ g \ H_2O\)Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
2887.63 g H₂O ≈ 2890 g H₂O
Listed in the item bank are key terms expressions each of which is associated with one of the columns. Some terms may disable additional information when you click on them. Drag and drop each item into the correct column. Order does not matter.
Answer:
The correct answer is -
Prokaryotic unicellular -
Eubacteria - is the domain of unicellular organisms that has a prokaryotic cell
Archaebacteria - is one of the two domains of the prokaryotic organisms that are unicellular.
Eukaryotic multicellular (autotroph) -
Plantae - is the multicellular kingdom of the eukaryotic cells and as they produce their own food by photosynthesis called autotrophs.
protists - the autotrophic protists that are multicellular comes under algae, especially red algae.
Eukaryotic multicellular (heterotroph) -
Animalia - The Animalia kingdom is the kingdom of the heterotrophic eukaryotic organism that mostly has multicellular bodies. They depend on plants or other animals for their food.
Fungi - are mostly heterotrophic eukaryotic as they get their nutrient from other organisms are mostly multicellular.
Protist - some protists are heterotrophic as well.
Eukaryotic multicellular/unicellular (heterotroph/autotroph) -
Plantae
protists
Animalia
Fungi