Answer:
-48
Explanation:
Answer:
6.0
Explanation:
If this is the problem on Khan Academy, I had done this and this was the correct answer.
please convert it very very fast
Answer:
413.6
Explanation:
212 °C × 9/5 + 32 = 413.6 °F
A positively charged light metal ball is suspended between two oppositely charged metal plates on an insulating thread as shown below. After being charged once, the plates are disconnected from the battery. Describe the behavior of the ball. Please use 3 content related sentences. (
Answer:
The positive ball would go first to the negatively charged plate.
Explanation:
After which, it would hold a more negative charge. Due to the negative charge, it would travel towards the positive plate. Thereby, it would transfer negative electrons to the positive plate once more. In doing so, it would transfer positive protons to the negative plate. After which, it would hold more negative electrons and be drawn towards the positive plate once more. The Process would continue until the once-positive and once-negative became neutral ( and were discharged.) Additionally, the ball hanging on the insulator thread would also be neutral and discharged.
5. Whether you are standing, running or jumping Earth is exerting a gravitational force on you. This gravitational force is called an object's weight (W). Knowing this you can find the weight of an object if you know the mass because the acceleration will be 9.8 m/s2 due to gravities pull on the object. The equation to use then is: W = mass x acceleration. What is the weight of a 53 kg man?
Answer:
How we know, the equation is:
W = mg
Replacing according our data:
W = 53 kg × 9,8 m/s^2
Resolving:
W = 519,4 N
The weight of the object is of 519,4 Newtons.
A 0.530 kg object connected to a light spring with a spring constant of 18.5 N/m oscillates on a frictionless horizontal surface.
(a) Calculate the total energy of the system and the maximum speed of the object if the amplitude of the motion is 3.00 cm.
(b) What is the velocity of the object when the displacement is 2.00 cm?
(c) Compute the kinetic and potential energies of the system when the displacement is 2.00 cm.
a. The total energy of the system and the maximum speed of the object when the amplitude of the motion is 3.00 cm are 0.619 m/s.
b. The velocity of the object when the displacement is 2.00 cm will be 0.365 m/s.
c. The kinetic and potential energies of the system when the displacement is 2.00 cm will be 0.036 J.
a. The total energy of the system is the sum of the kinetic and potential energies. At the maximum amplitude, all the energy is in the form of kinetic energy, and at the equilibrium position, all the energy is in the form of potential energy. Therefore, the total energy of the system is given by:
E = 1/2 kA²
where k is the spring constant, and A is the amplitude of the motion. Substituting the given values, we get:
E = 1/2 (18.5 N/m) (0.03 m)² = 0.008325 J
The maximum speed of the object can be found using the conservation of energy, which states that the total energy of the system is constant. At the maximum amplitude, all the energy is in the form of kinetic energy, and at the equilibrium position, all the energy is in the form of potential energy. Therefore, we can write:
1/2 mv² = 1/2 kA²
where m is the mass of the object, v is the maximum speed of the object. Solving for v, we get:
v = √(k/m) A = √(18.5 N/m / 0.530 kg) (0.03 m) = 0.619 m/s
b. The velocity of the object when the displacement is 2.00 cm can be found using the conservation of energy. At any point in the motion, the total energy of the system is given by:
E = 1/2 kx² + 1/2 mv²
where x is the displacement of the object from the equilibrium position. At the point where x = 2.00 cm = 0.02 m, we know the potential energy of the system is:
U = 1/2 kx² = 1/2 (18.5 N/m) (0.02 m)² = 0.0037 J
Using conservation of energy, we can write:
1/2 mv² = E - U
Substituting the given values, we get:
1/2 (0.530 kg) v² = 0.008325 J - 0.0037 J
Solving for v, we get:
v = √(2(E - U)/m) = √(2(0.008325 J - 0.0037 J)/(0.530 kg)) = 0.365 m/s
c. The kinetic and potential energies of the system when the displacement is 2.00 cm can be found using the equations:
U = 1/2 kx² = 1/2 (18.5 N/m) (0.02 m)² = 0.0037 J
K = 1/2 mv² = 1/2 (0.530 kg) (0.365 m/s)² = 0.036 J
Therefore, the potential energy of the system at x = 2.00 cm is 0.0037 J, and the kinetic energy of the system at x = 2.00 cm is 0.036 J.
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Si un movil parte del reposo logrando una aceleracion de 5 metros por segundo al cuadrado durante 8 segundos calcular la velocidad final
Answer:
Velocidad final, V = 40 m/s
Explanation:
Dados los siguientes datos;
Aceleración = 5 m/s²
Velocidad inicial = 0 m/s (ya que comienza desde el reposo)
Tiempo = 8 segundos
Para encontrar la velocidad final, usaríamos la primera ecuación de movimiento;
\( V = U + at\)
Dónde;
V es la velocidad final. U es la velocidad inicial. a es la aceleración. t es el tiempo medido en segundos.Sustituyendo en la fórmula, tenemos;
\( V = 0 + 5*8 \)
\( V = 0 + 40 \)
\( V = 40 \)
Velocidad final, V = 40 m/s
A block requires an applied force of 20N to begin moving it to the right. What is the maximum static friction?
a. Less than 20 N
b. Exactly 20 N
c. Just over 20 N
d.Twice as much as the block's weight
Answer:
A.
Explanation:
Thats my answer
Please make me branlies answer
What is the electric potential, i.e. the voltage, 0.30 m from a point charge of 6.4 x 10-C?
Answer:
V = 192 kV
Explanation:
Given that,
Charge, \(q=6.4\times 10^{-6}\ C\)
Distance, r = 0.3 m
We need to find the electric potential at a distance of 0.3 m from a point charge. The formula for electric potential is given by :
\(V=\dfrac{kq}{r}\\\\V=\dfrac{9\times 10^9\times 6.4\times 10^{-6}}{0.3}\\\\V=192000\ V\\\\V=192\ kV\)
So, the required electric potential is 192 kV.
People should be more concerned about the global water budget than the local water budget.
True
Answer:
true
Explanation:
because global helps local
A student has focused the image of an object of height 3cm on a white screen using a concave mirror of focal length 12cm. If the distance of the object from the mirror is 18cm , find the values of the following:
(i) Distance if the image from the mirror
(ii) Height of the image
Need answer for this question
To find the values of the distance if the image is from the mirror,
Height of object, h = 3 cm
Distance of object from mirror, u = -18 cm (negative sign indicates that the object is placed on the left side of the mirror)
Focal length of mirror, f = -12 cm (negative sign indicates that the mirror is concave)
We can use the mirror formula to find the distance of the image from the mirror:
1/f = 1/u + 1/v
where v is the distance of the image from the mirror.
Substituting the values of u and f, we get:
1/-12 = 1/-18 + 1/v
Simplifying the equation, we get:
v = -36 cm (negative sign indicates that the image is formed on the left side of the mirror)
Therefore, the distance of the image from the mirror is 36 cm.
What is the Height of the image?To find the height of the image, we can use the magnification formula:
m = -v/u
where m is the magnification of the image.
Substituting the values of v and u, we get:
m = -(-36)/(-18) = 2
Since the magnification is positive, the image is upright and enlarged.
The height of the image can be found using the formula:
h' = m * h
where h' is the height of the image and h is the height of the object.
Substituting the values of m and h, we get:
h' = 2 * 3 = 6 cm
Therefore, the height of the image is 6 cm.
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the total energy of a system is 300j. if the potential energy is 40j what is the kinetic energy if the object started 300m above the ground?
Answer:
43.3 m/s.
Explanation:
Assuming the potential energy is due to the gravitational potential energy, we can use the conservation of energy to find the kinetic energy:
Total energy = Potential energy + Kinetic energy
Kinetic energy = Total energy - Potential energy
Kinetic energy = 300 J - 40 J = 260 J
However, we need to know the mass of the object to convert the kinetic energy to velocity. We can use the potential energy to find the mass:
Potential energy = mgh
40 J = m(9.81 m/s^2)(300 m)
m = 0.137 kg
Now we can use the kinetic energy to find the velocity:
Kinetic energy = (1/2)mv^2
260 J = (1/2)(0.137 kg)v^2
v^2 = (2*260 J) / 0.137 kg
v = 43.3 m/s (rounded to one decimal place)
Therefore, the kinetic energy is 260 J and the velocity of the object when it reaches the ground is 43.3 m/s.
When you heat water, it changes from-- *
A a gas to a liquid
B a liquid to a gas.
C a liquid to a solid
Answer:
Hi! It's B - liquid to a gas.
The speed formula is distance over time. True or false?
HELP ME ASAP
Answer: true
Explanation:
Answer:
the answer is true answer true
Urgent please!!!!!!!!!!!!!!!!!!!!!!
A program can only create one object of each class.
A. True
B. False
the force between the earth and the body which is at a distance r from the center of the earth is F. What must be this distance for the force to be doubled.
Answer:
Explanation:
The gravitational force between the earth and another body is F = -GM_em/r^2 r where G = 6.67 times 10^-11 Nm^2/kg^2 is the gravitational constant, M_e = 5.97 times 10^24 kg is the mass of the earth, m is the mass of the other body, and r is the position vector of the second body with respect to the centre of the earth.
Bethany feels as though she cannot enjoy flowers properly, as she has lost her sense of smell. Bethany has _______
Answer: Anthophobia
Explanation: A fear of flowers
Answer: Anosmia. It is the loss of smell.
Which of the following objects is composed mostly of wood?
A. Sweater
B. Tile
C. Pencil
D. Brick
❄ Hi there.
a pencil is composed mostly of wood.
Let's check if the other choices are right.
A. Sweaters are not made of wood
B. Tiles are not made of wood
C. Pencils are made of wood
D. Bricks are not made of wood
∴ the right choice is C.
❄
A student tries to measure the period of a pendulum that is already swinging
left and right. At the moment when the pendulum is fully to the left, she
counts 'One' and starts a stopwatch. She counts successive swings each time
that the pendulum returns to the left. When she counts ‘Ten' she stops the
stopwatch, and sees that it reads 12.0 s.
a. What was her mistake?
______________________________________________________________
b. What is the period of swing of this pendulum?
______________________________________________________________
c. In this particular experiment, explain the likely effect of her reaction time
on her answer.
Answer:
a. The student's mistake was that the student did not swing the pendulum and start the watch at the same time.
b. 1.2 s per swing.
c. The likely effect of her reaction time is that they will should subtract two seconds off the time.
Explanation:
The pupil made the error of not simultaneously starting the watch and swinging the pendulum.
What is pendulum?Pendulum is defined as a body that is suspended from a fixed point and moves back and forth while being pulled by gravity. The pendulum is used to gauge the gravitational pull because the force of gravity causes it to swing back toward its average position. A pendulum's time period can be used to tell the time because it is constant.
The swing of the pendulum is 1.2 sec. per swing. They should take two seconds off the timing due to her presumably slow reaction time. A pendulum's total time should be divided by the quantity of oscillations in order to determine its time period. When compared to a pendulum with a shorter string, the one back and forth cycle of a longer-stringed pendulum requires more time to complete.
Thus, the pupil made the error of not simultaneously starting the watch and swinging the pendulum.
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A projectile is fired vertically upward with an initial velocity of 190 m/s. Find the maximum height of the projectile
ANSWER
\(1841.84\text{ m}\)EXPLANATION
Parameteters given:
Initial velocity = 190 m/s
To find the maximum height, we apply the formula for the maximum height of a projectile:
\(H=\frac{u^2\sin ^2\theta}{2g}\)where u = initial velocity
θ = angle with the horizontal
g = acceleration due to gravity = 9.8 m/s²
From the question, the projectile is fired vertically upward. This means that the projectile will make a 90° angle with the horizontal.
Therefore, we have that the maximum height of the projectile is:
\(\begin{gathered} H=\frac{190^2\cdot\sin ^2(90)}{2\cdot9.8} \\ H=1841.84\text{ m} \end{gathered}\)Answer:
Height is equal to 1841.8367m
Explanation:
KE = GPE
Write out the formula
1/2(m)(v^2) = mgh
Fill it with the information you have
1/2(190^2) = (9.8)(h)
Solve
1/2(36100) = 9.8h
18050 = 9.8h
1841.83673 = h
Write the complete answer out
Maximum height is equal to 1841.8367m (meters)
what critical event transforms a protostar into a normal main-sequence star?
The critical event that transforms a protostar into a normal main-sequence star is the initiation of nuclear fusion in its core.
During the early stages of stellar evolution, a protostar forms from a collapsing cloud of gas and dust. Gravitational forces cause the material to come together, leading to the formation of a dense core. As the core continues to contract under its own gravity, it becomes increasingly hot and dense.
When the core reaches a critical temperature and density, the process of nuclear fusion begins. Nuclear fusion is the process by which lighter atomic nuclei combine to form heavier nuclei, releasing an enormous amount of energy in the process. In the case of a main-sequence star like our Sun, the primary fusion reaction is the conversion of hydrogen nuclei (protons) into helium nuclei. This reaction, known as the proton-proton chain, occurs in the star's core and releases vast amounts of energy in the form of light and heat.
The onset of nuclear fusion marks a significant transition in a protostar's life. As fusion reactions start to take place in the core, the release of energy counteracts the inward gravitational collapse of the star. This equilibrium between gravity and the outward pressure from nuclear fusion leads to a stable state known as the main sequence.
In the main-sequence phase, the star remains in a relatively stable state for a significant portion of its lifetime, which can range from millions to billions of years, depending on its mass. The main-sequence phase is characterized by a balance between the inward force of gravity and the outward pressure from the ongoing fusion reactions in the core. The energy generated by nuclear fusion sustains the star's luminosity and heat, allowing it to shine steadily.
It's important to note that the exact duration of a star's main-sequence phase depends on its mass. Higher-mass stars have shorter main-sequence lifetimes due to their higher luminosity and more rapid consumption of nuclear fuel.
In summary, the critical event that transforms a protostar into a normal main-sequence star is the initiation of nuclear fusion in its core. This process releases a tremendous amount of energy, counteracting the gravitational collapse of the protostar and leading to a stable state known as the main sequence. The main-sequence phase is characterized by a balance between gravity and the outward pressure from ongoing fusion reactions, and it defines a significant portion of a star's lifetime.
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A rollercoaster cart leaves point A at a speed of 4 m/s, passes through point B on the ground, and reaches point C at a speed of 6 m/s. The total mass of the cart assembly and the passengers are 300 kg,
(a) What is the total energy of the cart at point B?
(b) What is the height of point A?
a) the total energy of the cart at point B is 2400 Joules.
b) the height of point A is approximately 1.83 meters.
(a) To find the total energy of the cart at point B, we need to consider both its kinetic energy and potential energy.
The kinetic energy (KE) of the cart can be calculated using the formula:
KE = (1/2)mv^2
where m is the mass of the cart assembly and passengers, and v is the speed of the cart.
Given:
Mass (m) = 300 kg
Speed (v) = 4 m/s
Plugging in the values, we get:
KE = (1/2) * 300 kg * (4 m/s)^2
KE = 2400 J
Next, we need to calculate the potential energy (PE) of the cart at point B. Since point B is on the ground, we can take the reference level as the ground level, where the potential energy is zero.
Therefore, at point B, the potential energy of the cart is zero.
The total energy (E) of the cart at point B is the sum of its kinetic energy and potential energy:
E = KE + PE
E = 2400 J + 0 J
E = 2400 J
Therefore, the total energy of the cart at point B is 2400 Joules.
(b) To determine the height of point A, we can use the conservation of energy principle. At point A, the cart has potential energy (PE) and kinetic energy (KE).
The total energy (E) of the cart at point A is the sum of its kinetic energy and potential energy:
E = KE + PE
Since the cart is at rest at point A (initially), its kinetic energy is zero:
KE = 0
Therefore, the total energy (E) at point A is equal to the potential energy (PE):
E = PE
Given:
Total mass (m) = 300 kg
Speed at point A (v_A) = 0 m/s
Speed at point C (v_C) = 6 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Using the equation for potential energy:
PE = mgh
At point C, the cart has maximum kinetic energy and zero potential energy. Therefore, the total energy (E) at point C is equal to the kinetic energy (KE):
E = KE = (1/2)mv_C^2
Plugging in the values, we get:
E = (1/2) * 300 kg * (6 m/s)^2
E = 5400 J
Since energy is conserved, the total energy at point A is also 5400 J:
E = 5400 J
Equating the total energy at point A to the potential energy, we have:
PE = 5400 J = mgh
Rearranging the equation, we can solve for the height (h):
h = PE / (mg)
h = 5400 J / (300 kg * 9.8 m/s²)
h ≈ 1.83 meters
Therefore, the height of point A is approximately 1.83 meters.
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describe the motion of the moon in space to produce the different phases of the moon.
The motion of the moon in space to produce the different phases is the rotation and the revolution.
Rotation and revolution
The moon's rotation is characterized as the movement that this body performs on its own axis.
In addition, the moon also performs the movement of revolution, which is characterized as the movement of the moon around the Earth.
The revolution lasts approximately 28 days, and just like the rotation allows for the existence of 4 phases of the moon, every 7 days.
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In the Bohr theory of the hydrogen atom, an electron moves in a circular orbit about a proton, assume the radius of the orbit is 5.29 10-11 m. (a) Find the magnitude of the electric force exerted on each particle.
Answer:
\(F=9.06*10^{-8} N\)
Explanation:
We can use the Coulomb force
\(F=k\frac{q_{e}q_{p}}{r^{2}}\)
\(F=9*10^{9}\frac{|-(1.6*10^{-19})^{2}|}{(5.29*10^{11})^{2}}\)
\(F=9.06*10^{-8} N\)
The direction of the force is toward proton with respect to the electron reference coordinate and is in the direction of the electron in the proton system reference.
I hope it helps you!
A michelson interferometer is shown at right. The moving mirror is displaced a distance d. During this displacement, 250 interference fringe shifts are counted. The light being used has a wavelength of 632. 8 nm. Determine the mirror displacement d in nm.
The mirror displacement d is 317.12 nm. In a Michelson interferometer, interference fringes are created due to the interference of two beams of light.
A Michelson interferometer is a device used to measure small changes in the distance between two mirrors. It consists of a beam splitter, two mirrors, and a detector. One beam of light is split into two and travels to the mirrors, where they are reflected back towards the beam splitter. The two beams of light then recombine at the detector, creating an interference pattern.
When one of the mirrors is moved, the interference pattern shifts. The amount of shift depends on the distance moved and the wavelength of the light being used. By measuring the shift in the interference pattern, we can determine the displacement of the mirror.
In this problem, we are given that 250 interference fringe shifts were counted when the mirror was moved a distance d. The wavelength of the light being used is 632.8 nm.
Each interference fringe shift corresponds to a change in the path difference between the two beams of light by one wavelength. So, the total change in the path difference is 250 times the wavelength of the light:
250 × 632.8 nm = 158,200 nm
Therefore, the mirror displacement d is 158,200 nm. However, this displacement is in both directions (i.e., the mirror moved back and forth). To find the displacement in just one direction, we divide by 2:
d = 158,200 nm / 2 = 79,100 nm
Therefore, the mirror displacement d is 79,100 nm in one direction.
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of the four fundamental forces that act upon an aircraft in flight, which is of the least concern for a rocket in flight? thrust gravity drag lift
Of the four fundamental forces that act upon an aircraft in flight, drag is of the least concern for a rocket in flight. What is the rocket? A rocket is an aircraft that travels through space using rocket engines that thrust the rocket forward. The four fundamental forces that act upon an aircraft in flight are gravity, thrust, lift, and drag.
Drag is a force that opposes an object's motion through a fluid, such as air or water. The shape of a rocket's body and the use of smooth surfaces assist to minimize drag. Drag is less of a concern for a rocket in flight since they travel through a vacuum rather than air, unlike planes and other flying vehicles where drag plays a significant role. of the four fundamental forces that act upon an aircraft in flight, which is of the least concern for a rocket in flight? thrust gravity drag lift.
A rocket is an aircraft that travels through space using rocket engines that thrust the rocket forward. The four fundamental forces that act upon an aircraft in flight are gravity, thrust, lift, and drag. The shape of a rocket's body and the use of smooth surfaces assist to minimize drag. Drag is less of a concern for a rocket in flight since they travel through a vacuum rather than air, unlike planes and other flying vehicles where drag plays a significant role.
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A truck is traveling at 80 m/s and has 12,000 J of kinetic energy. What is the truck’s mass?
Answer:
3.75 kg
Explanation:
m=2xKE / v²
A 12 kg ball is rolling with a velocity of 10 m/s. How much kinetic energy does the ball have?
Answer:
kinetic energy = 1/2 x mass x velocty^2
1/2(12)(10^2)
600 N
hope that answers your question
Explanation:
fill in the blanks (grade8 physics)
Answer:
infra-red
molecules
vacuum
ionizing (?)
transmission
redirected
absorbed
emission
dark
emitter
reflectors
deflect
The physical quantity that cannot be defined in terms
physical quantities?
Define the term overload.
Answer:
Verb. Load with too great a burden or cargo.
"Both boats were overloaded and low in the water"
Noun. An excessive load or amount.
"an overload of stress"
Explanation:
Similar words are strain, excess, and overburden.
Have a good day and stay safe!
Which of the fillowing scenarios describle a car that is accelerating?
A. a car that is gradually coming to a stop?
B. a cor going, constant 50 mph on a straight road
C. a car that is changing lanes?
D. a car that is entering a highway from on entrance ramp?
Answer:
DDDDDDDDDDDDDDDDDDDDDDDDDDD