A car's velocity changes from 40 m/s to 30 m/s in 40 seconds. What is the
acceleration of the car?

Answer:

He is pink panther. How nerdy does he sound?

Explanation:

Answer:

c

Explanation:

speed=distance÷time

40÷10=4

The particle moves to the right through a potential difference of Vb-Va = 3.20×10^-19 J / q.

The particle, initially at rest, is acted upon only by the electric force and moves from point a to point b along the x axis, increasing its kinetic energy by 3.20×10^-19 J. To determine the direction and potential difference through which the particle moves, we can use the relationship between electric potential difference (V) and electric force (F) on a charged particle.

The electric potential difference between two points is defined as the work done per unit charge to move a particle from one point to the other. The work done on a charged particle by an electric force is given by the equation

W = Fdcos(theta)

where F is the electric force, d is the distance moved by the particle, and theta is the angle between the direction of the force and the direction of the displacement.

In this case, since the particle is only acted upon by the electric force and moves along the x-axis, the angle between the direction of the force and the direction of the displacement is 0, and the work done by the electric force is given by W = Fdx.

Therefore, the potential difference between point a and point b is given by Vb - Va = W/q, where q is the charge of the particle.

Given that the particle's kinetic energy increases by 3.20×10^-19 J and the work-energy principle states that work done on a particle is equal to the change in kinetic energy, we can say that the work done on the particle is equal to 3.20×10^-19 J.

Now, the direction of the force can be determined by the sign of the potential difference, since the electric force is given by

F = -q(dV/dx).

Given that the potential difference is positive, the electric force is negative, meaning that the force is directed opposite to the direction of motion of the particle, therefore the direction of motion is to the right.

Therefore, the particle moves to the right through a potential difference of Vb-Va = 3.20×10^-19 J / q.

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Answer:

Explanation:

equal in magnitude and opposite in direction

When turning, check all mirrors, do head checks and use back-up cameras if accessible. So the correct answer is option c.

Safely reversing a car while turning requires awareness of the surroundings. It emphasises monitoring all mirrors, which can reveal nearby vehicles and objects. Head checks over your shoulder are essential to find blind spots that may not be evident in the mirrors. Back-up cameras can further improve visibility and awareness.

Mirrors, head checks, and back-up cameras (if available) let drivers see their surroundings, identify risks, and make informed judgements while reversing and turning. This reduces collisions and improves manoeuvrability.

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Answer:

Explanation:

The formula for the magnitude of a vector is

\(B_{mag}=\sqrt{(-1.33)^2+(2.81)^2}\) and then round to the hundredths place:

3.11 m. Since we are in Q2, we can also find the direction of this vector:

\(tan^{-1}(\frac{2.81}{-1.33})=-64.7\) but since we are in Q2, we add 180 degrees to the result, getting the angle to be 115.3

Answer:115.33

Explanation:

Answer:

The vibrations from sound waves cause our ears to send signals to our brains to create sound. The speed of sound waves will determine the sound's pitch, or how high or low something sounds. Sound waves are important because they allow us to hear important messages and emergency signals to protect ourselves.

Explanation:

I hope this helps :)

Answer:

true

Explanation:

Answer: True

Explanation:

Answer:

1. they both act on an object in free fall

Explanation:

2. both help determine how fast the object will accelerate

To determine the rate of heat input required to operate a unit where all the heat goes into the water, we need additional information such as the specific heat capacity of water and the desired temperature change.

The rate of heat input can be calculated using the formula:

Rate of heat input = (Mass of water) x (Specific heat capacity of water) x (Temperature change per unit time). The mass of water is typically measured in kilograms (kg), the specific heat capacity of water is around 4.186 joules per gram per degree Celsius (J/g°C) or 4,186 joules per kilogram per degree Celsius (J/kg°C), and the temperature change per unit time is measured in degrees Celsius per second or degrees Celsius per hour, depending on the specific scenario. Once we have the desired temperature change and the time period over which the heat input is measured, we can use these values to calculate the required rate of heat input. Please provide the necessary information, such as the mass of water and the desired temperature change, for a more accurate estimation of the rate of heat input.

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The rotational inertia of the combined system about the center of the stick is Io + M * (L^2/16).

To calculate the rotational inertia of the combined system, we can use the parallel axis theorem. According to the parallel axis theorem, the rotational inertia of a system about an axis parallel to and a distance "d" away from an axis through its center of mass is given by:

I = I_cm + M * d^2

In this case, the rotational inertia of the stick about its center is Io, and we need to find the rotational inertia of the combined system when a particle of mass M is attached at the halfway point between the center and end of the stick.

Let's assume that the length of the stick is L. The distance from the center of the stick to the point where the particle is attached is L/4. Therefore, using the parallel axis theorem:

I_combined = Io + M * (L/4)^2

I_combined = Io + M * (L^2/16)

Hence, the rotational inertia of the stick is Io + M * (L^2/16).

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The rock has a height y at time t according to

y = 25 m + (60 m/s) sin(32°) t - 1/2 gt ²

where g = 9.8 m/s² is the magnitude of the acceleration due to gravity.

Solve for t when y = 0. The quickest way to do this is with the quadratic formula.

0 = 25 m + (60 m/s) sin(32°) t - 1/2 gt ²

t = (-(60 m/s) sin(32°) + √[(60 m/s)² sin²(32°) - 4 (25 m) (-1/2 gt ²)]) / 2

(ignoring the negative root because that would make t negative)

or approximately

t ≈ 7.2 s

When a car goes over a bump, the frequency of oscillations is determined by the mass of the car and the spring's compression.

The frequency of oscillations = 1/(2π) √(k/m)

Where,

k is the spring constant,

m is the mass.  

If the springs of a 1800 kg car, compress 4.6 mm when its 63 kg driver gets into the driver's seat,

the spring constant, k = F/x,

Where

F is the force applied to the spring,

x is the displacement of the spring.

We can substitute the given values

k = F/x= (mg)/x

where

m is the mass of the car and the driver,

g is the acceleration due to gravity.

We can find F by multiplying the displacement by the spring's stiffness or the spring constant, k.

Therefore, the force applied to the spring, F = kx.F = kx= (1.96 × 10⁴ N/m)(4.6 × 10⁻³ m)= 90.16 N

We can now substitute the calculated values in the formula for frequency,

1/(2π) √(k/m) = 1/(2π) √[(1.96 × 10⁴ N/m)/(1800 kg + 63 kg)] ≈ 0.352 Hz

Therefore, the frequency of oscillations when the car goes over a bump would be approximately 0.352 Hz.

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Answer: A

Explanation:

There is one important fact about magnetic fields. Magnetic fields are always perpendicular to the velocity of the particle, and the force acting on the particle. This is evident in the Lorentz force equation for magnetic fields, which states:

\(F=q(v x B)\)

The cross product between between the velocity and the magentic field forms a force vector that is perpendicular to both the velocity and the field. In our example, the electron is traveling to the left, and the force it feels is upwards. One thing to keep in mind now, is that the Lorentz force equation is for positively charged particles. Therefore, whatever result we obtain for the field, it is actually the opposite since our particle is negatively charged.

Point your thumb in the direction of the velocity, and point your palm in the direction of the force. Your fingers should be pointing towards yourself (the south). This would be correct for positive charges, but it is the opposite for negative charges. The magnetic field points away from your body, which is the north.

The acceleration of the eraser is 169.19 m/s².

A body travelling in a circle has centripetal acceleration. Due to the fact that velocity is a vector quantity (i.e., it has both a magnitude and a direction), when a body travels in a circle, its direction is continually changing, which causes a change in velocity, which results in an acceleration.

Given that angular velocity of the eraser: ω = 127 rpm

= 126×2π/60 radian/second

= 13.2 radian/second.

radius of the circle: r = 0.974 meter.

Hence, its centripetal acceleration is = ω²r

= 13.2×13.2×0.974 m/s²

=169.19 m/s².

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Answer:

A or D

Explanation:

Think of it like this to Same sided pole magnet the closer you get to the other magnet the harder it is able to touch now if she is experiencing air resistance it would be harder to fall,but at 1 second she will experice the most exploration because there will be no air resistance so as she fall she will gain speed

There are 38 dozens donuts needed to order to feed a school of 456 students.

There are 38 dozens of donuts you would need to order to feed a school of 456 students if each student eat one donut. We know that there are 12 units in one dozen so if we do the calculation of 456 divided by 12, we get 38. If each student receives one donut, 38 dozens of donut are required while on the other hand, if each student receives two donuts, then 76 dozens of donut are needed. If each student receives three donuts, then 114 dozens of donut are needed. If each student receives four donuts, 152 dozens of donut are needed.

So we can conclude that there are 38 dozens donuts needed to order to feed a school of 456 students.

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Explanation:

why do you think is important to study about that different forms of precolonial literature?

Answer:

It would be 2,500

Explanation:

The KE is 7,500 so the PE would be 2,500

total stopping distance is the distance a vehicle travels from the moment the driver applies the brakes until the vehicle comes to a complete stop. It consists of two main components: the thinking distance and the braking distance.

total stopping distance refers to the distance a vehicle travels from the moment the driver applies the brakes until the vehicle comes to a complete stop. It is composed of two main components: the thinking distance and the braking distance.

The thinking distance is the distance the vehicle travels during the driver's reaction time. It is the time it takes for the driver to perceive a hazard and apply the brakes. Factors that can affect the thinking distance include the driver's alertness, distractions, and the speed of the vehicle.

The braking distance is the distance the vehicle travels while the brakes are applied and the vehicle decelerates. It depends on factors such as the speed of the vehicle, the condition of the road, and the efficiency of the brakes.

Therefore, the total stopping distance is influenced by both the thinking distance and the braking distance. It is important for drivers to maintain a safe following distance and be aware of their vehicle's stopping capabilities to ensure they can stop in time to avoid collisions.

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Total stopping distance includes b. The distance the car travels during the driver's reaction time

The distance a car travels during the driver's reaction time and the distance it travels while the driver is braking are included in the total stopping distance. It's possible that a driver's foot isn't on the brake when they realise they need to stop the car. The car, for instance, is going at a constant speed.

The moment the driver realises that the vehicle needs to be stopped, his or her foot is moved to the brake pedal. The reaction distance is what we refer to as. The car slows down as soon as the brakes are deployed. The braking distance is the length of time needed to stop. Total stopping distance is calculated by summing reaction distance and braking distance.

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Complete Question:

Total stopping distance includes

a. The time period when it is at hault

b. The distance the car travels during the driver's reaction time

c. Distance travelled between the moment you first see a reason to stop to the moment you use the brake.

Answer:

Real Image

Explanation:

Images which are formed on the screen by the actual intersection of light rays are called real images.

Answer:

Explanation:

hope this helps you.

will give the brainliest!

follow ~Hi1315~

\({ \qquad\qquad\huge\underline{{\sf Answer}}} \)

By formula ;

" Force = Mass × Acceleration "

So, let's proceed ~

\(\qquad \sf  \dashrightarrow \: f = m \times a\)

\(\qquad \sf  \dashrightarrow \: f = 3 \times 8\)

\(\qquad \sf  \dashrightarrow \: f = 24 \: \: N\)

Therefore, the force required to throw that ball provided the given conditions will be 24 Newtons ~

To understand the questions, one should know the structure of an atom.

An atom is made up of some subatomic particles. These particles are positively charged, negatively charged and neutral particles.

The positive and negative charged particles neutralize the atom and the neutral subatomic particles are neutrons.

The answer to the questions are as follows:

1. The subatomic particle with no electrical charge is the "neutron".

2. The subatomic particle with a positive charge is the "proton".

3. The subatomic particle with a negative charge is the "electrons".

4. There are the same number of these two particles in an atom are "electrons" & "protons".

5. The atomic number is the same as the number of "protons" in an atom.

To sum up, an atom has different particles such as protons, electrons and neutrons. With protons being the positively charged, electrons are negatively charged and neutrons are neutral. Neutrons and protons are found in the nucleus and the electrons are spread around the nucleus.

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The length of the rubber band that the boy must use is 0.024 m or 24 mm.

To determine the length of the rubber band, we can use the formula for the potential energy stored in a stretched spring, which is also applicable to a stretched rubber band:

where U is the potential energy stored in the rubber band, k is the spring constant (or in this case, the rubber band constant), and x is the displacement of the rubber band from its natural length.

Since the rubber band is stretched by 0.25 of its natural length, the displacement x is 0.25 times the natural length of the rubber band.

We can solve for the rubber band constant k by using the formula for the velocity of a projectile launched by a spring (or in this case, a rubber band):

where v is the velocity of the projectile, m is the mass of the rubber band, M is the mass of the projectile, and k is the spring constant. We can rearrange this equation to solve for k:

k = (v² M) / (2 m)

We can now combine the two equations to solve for the length of the rubber band, L:

U = 1/2 k x²

U = 1/2 ((v² M) / (2 m)) (0.25 L)²

U = (v² M L²) / (32 m)

The potential energy stored in the rubber band must be equal to the kinetic energy of the projectile when it is launched:

U = 1/2 M v²

(v² M L²) / (32 m) = 1/2 M v²

L = ((16 m v²) / (k M))

L = ((16 m v²) / ((v² M) / (2 m) M))

L = √(32 m^2 / M)

L = (0.032 M)

Substituting the given values, we get:

L = √(0.032 * 0.006)

L = 0.024 m

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Answer:

The acceleration of an object can be calculated using Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. The equation is:

F = ma

where F is the force, m is the mass, and a is the acceleration.

So, if we know the mass of the object (m = 56 kg) and the force acting on it (F = 800 N), we can calculate the acceleration (a) by dividing the force by the mass:

a = F / m

a = 800 N / 56 kg

a = 14.28 m/s^2

So the acceleration is 14.28 m/s^2

The kinetic energy of plane is 10285000 J

Kinetic energy is defined as the energy possed by an object in motion. The mathematical representation of kinetic energy is given below:

Where:

KE is the kinetic energy

m is the mass of the object

v is the velocity of the object.

With the above formula, we can obtain kinetic energy of the plane as follow:

Mass (m) = 6800 kg

Velocity (v) = 55.0 m/s

KE = ½mv²

KE = ½ × 6800 × 55²

KE = 3400 × 3025

Therefore, the kinetic energy of plane is 10285000 J

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Answer:

Answer: KE = 9075 J

Explanation:

This can help u

The answer to the question is 1.125  Newton

Formula for electrostatic force is F = ( K q1 q2 )/ r²

where q1 and q2 represent the charges and r represents the distance between them and the value of K is 9 × 10⁹.

Total net force on q3 will be the summation of electrostatic force between q1 and q3 and electrostatic force between q2 and q3, as all the three charges are of same sign and lie in the same line.

Electrostatic force between q1 and q3

r will be 0.500 + 0.500 = 1 m

F = ( K q1 q3 )/ r²

F = ( (9 × 10⁹ ) x (5.00 x 10⁻⁶) x (5.00 x 10⁻⁶) )/ 1²

F₁₃ = 2.25  × 10⁻¹ N

Electrostatic force between q2 and q3

r will be 0.500 m

F = ( K q1 q3 )/ r²

F = ( (9 × 10⁹ ) x (5.00 x 10⁻⁶) x (5.00 x 10⁻⁶) )/ 0.5²

F = (225 × 10⁻³) / (25 × 10⁻²)

F₂₃ = 9 × 10⁻¹ N

Total force on q3 will be F₁₃ + F₂₃

Total force on q3 =  ( 2.25  × 10⁻¹ ) + (9 × 10⁻¹ ) N

Total force on q3 =  ( 2.25  × 10⁻¹ ) + (9 × 10⁻¹ ) N

Total force on q3 =  ( 11.25  × 10⁻¹ ) N

Total force on q3 =  1.125  N

Thus after solving we got the net force on q3 as 1.125  Newton

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Before the blocks are released, the direction of the force exerted by the hand on the block that will float .

The block is in rest when it is been held by the hands . Their is a gravitation force acting on the block due to its weight and that gravitational force is balanced by the normal force acted by the hand on the block . And the direction of the force exerted by the hand in the block will be upward .

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Answer:

1/2 M V0^2   = initial KE of rock

KEi = 2 / 2 ^ 10^2 = 100 J

Gain in height of rock = 60 + 40 = 100 m = H       (below starting point)

Gain in potential of rock = M g H = 2 * 9.8 * 100 = 1960 J

Total KE of rock = (100 + 1960) J = 2060 J

1/2 M V^2 = 2060     when rock lands

V^2 = 2060 m^2 / s^2

V = 45.4 m/s