A car travels at 15 m/s for 30 minutes. How far did it travel?

Answer:

depends the ancient humans or the start of the solar system

Explanation:

if its the humans the earth was in the middle of everything.

but the beginning of the solar system lets say when earth just formed the orbits where unstable and planet ending impacts happed a lot.

ill do the proto planetary disc too

the disc formed the gas giants first then the rockey  planets formed out of the disc  

Using Newtons law

\(\\ \sf\longmapsto Force=Mass\times Acceleration\)

\(\\ \sf\longmapsto Mass=\dfrac{Force}{Acceleration}\)

\(\\ \sf\longmapsto Mass=\dfrac{340}{3.8}\)

\(\\ \sf\longmapsto Mass=89.4kg\)

Answer:

protected under students first amendment rights

Explanation:

did the studyisland :)

Given :

A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m.

The force of friction between the refrigerator and the floor is 230 N.

To Find :

How much work has been performed by the mover on the refrigerator.

Solution :

Since, refrigerator is moving with constant velocity.

So, force applied by the mover is also 230 N ( equal to force of friction ).

Now, work done in order to move the refrigerator is :

\(W = Force\times distance\\\\W = 230 \times 8.1\ N\ m\\\\W = 1863\ N\ m\)

Hence, this is the required solution.

Answer:

\(30 \div 33750 = 0.008888\)

The voltage drop across the 10-ohm resistor is 10 volts. The result is obtained using the equations apply in series circuit and Ohm's law.

In series electrical circuit, the resistance, currents, and voltage can be determined as

Rs = R₁ + R₂ + R₃ + ....

I = I₁ = I₂ = I₃ = .....

V = V₁ + V₂ + V₃ + ...

A series circuit has

Find the voltage drop across the 10-ohm resistor!

In series, the applied voltage is the sum of each voltage. It means that the voltage depends on its resistance and current.

We count the total resistance.

R = R₁ + R₂

R = 10 + 20

R = 30 Ω

The current flow in the circuit can be determined using the equation in Ohm's law.

I = V/R

I = 30/30

I = 1 A

The current on each resistance is the same. So

I₁ = I₂ = I = 1 A

The voltage drop across the 10-ohm resistor is

V₁ = I₁R₁

V₁ = 1(10)

V₁ = 10 volts

Hence, across the 10-ohm resistor, the voltage is 10 volts.

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Answer:

A thumb only has one joint and two phalanges. The thumb is referred to as “the big finger".

Brainlist pls!

Answer:

amplitude

Explanation:

sound travel and it amplifies

Answer:

B.rate of convection

Explanation:

Answer:

The value  is  \(a = 6.676 \ m/s^2\)  

Explanation:

From the question we are told that  

  The length of the runways is  \(l =145 \ m\)

  The required ground of a small plane is  \(v = 44 \ m/s\)

Generally from kinematics equation

       \(v^2 = u^2 + 2as\)

Here u  is the initial speed of the plane which is 0 m/s

so

      \(44^2 = 0^2 + 2 * a* 145\)

=>  \(a = 6.676 \ m/s^2\)  

Answer:

The force the archer need to pull in order to achieve the height is approximately 101.8 N

Explanation:

By energy conservation principle, puling an elastic bow with a force, for a given distance, performs work which is converted to the potential energy of the arrow at height

The given parameters are;

The mass of the arrow, m = 45.0 grams = 0.045 kg

The distance the elastic bow is pulled, d = 65.0 cm = 0.65 m

The height at which the arrow is reaches, h = 150.0 meters

Let 'F', represent the force the archer need to pull in order to achieve the height

Work done, W = Force × Distance moved in the direction of the force

Therefore;

The work done in pulling the arrow, W = F × d

By energy conservation, we have;

The work done in pulling the arrow, W = The potential energy gained by the arrow, P.E.

W = P.E.

The potential energy gained by the arrow, P.E. = m·g·h

Where;

m = The mass of the arrow

g = The acceleration due to gravity = 9.8 m/s²

h = The height the arrow reaches

∴ by plugging in the values, P.E. = 0.045 kg ×9.8 m/s² × 150 m = 66.15 J

W = F × d = F × 0.065 m

Also, W = P.E. = 66.15 J

∴ W = F × 0.065 m = 66.15 J

F × 0.065 m = 66.15 J

F = 66.15 J/(0.65 m) = 1323/13 N ≈ 101.8 N

The force the archer need to pull in order to achieve the height, F ≈ 101.8 N.

Answer:

Motors convert electrical energy into mechanical energy

(A motor produces mechanical energy and a motor can be activated by electrical power from an outlet - ex. a refrigerator motor)

F = q V B = I L B    force produced by use of electrical energy

Answer:

Covalent Bond is found between the atoms of a molecule.

The magnitude of the net force on the conducting bar is 1.25 N.

The force on the bar can be calculated using the right-hand rule for magnetic fields. The direction of the magnetic field is from north to south pole, while the direction of the current is from the positive to negative terminal of the battery. The direction of the force is perpendicular to both the direction of the magnetic field and the direction of the current.

Using the right-hand rule, the force is pointing upwards out of the page. The magnitude of the force can be calculated using the following formula:F = BILwhere F is the force, B is the magnetic field strength, I is the current, and L is the length of the conducting bar.

Substituting the given values into the formula: F = BIL= (2.5 T) x (5.0 A) x (0.10 m)= 1.25 Nm

The magnitude of the net force on the conducting bar is 1.25 N.

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The angle θ is approximately 0.688°, and the angle θ' is approximately 1.988°.

To determine the angles θ and θ' in the given scenario, we can use Snell's Law, which relates the angles of incidence and refraction to the refractive indices of the media involved. Snell's Law can be stated as follows:

n₁ * sin(θ₁) = n₂ * sin(θ₂)

Where:

n₁ is the refractive index of the medium of incidence (in this case, air with a refractive index close to 1),

θ₁ is the angle of incidence,

n₂ is the refractive index of the medium of refraction (in this case, linseed oil with a refractive index of 1.48), and

θ₂ is the angle of refraction.

Let's solve for the unknown angles θ and θ' using the given information.

Given:

Angle of incidence θ = 1°

Refractive index of linseed oil n₂ = 1.48

We need to find the angle of refraction θ₂.

Using Snell's Law, we have:

n₁ * sin(θ₁) = n₂ * sin(θ₂)

Since the refractive index of air (n₁) is approximately 1, we can simplify the equation to:

sin(θ₁) = n₂ * sin(θ₂)

Plugging in the values:

sin(1°) = 1.48 * sin(θ₂)

We can now solve for θ₂:

θ₂ = arcsin(sin(1°) / 1.48)

Calculating this value, we find:

θ₂ ≈ 0.688°

Now, let's determine the angle θ'.

Given:

Angle of refraction θ₂ = 0.688°

Refractive index of linseed oil n₂ = 1.48

We need to find the angle of incidence θ'.

Using Snell's Law, we have:

n₂ * sin(θ₂) = n₁ * sin(θ')

Since the refractive index of air (n₁) is approximately 1, we can simplify the equation to:

n₂ * sin(θ₂) = sin(θ')

Plugging in the values:

1.48 * sin(0.688°) = sin(θ')

Solving for θ', we find:

θ' = arcsin(1.48 * sin(0.688°))

Calculating this value, we get:

θ' ≈ 1.988°

Therefore, the angle θ is approximately 0.688°, and the angle θ' is approximately 1.988°.

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Answer:

\(20\; \rm m \cdot s^{-1}\).

Explanation:

Because the track is level and frictionless, the net force on this car-load system will be zero in the horizontal direction. As a result, (by Newton's Second Law of mechanics,) the total momentum of this system in the horizontal direction will stay the same.

Momentum of the car-load system in the horizontal direction, before contact:

Combine the two parts to obtain: \(p(\text{system, before}) = 3.0 \times 10^{6}\; \rm kg \cdot m \cdot s^{-1}\).

Because the load stays on the car, the car and the load should have the same horizontal velocity after contact. Let \(v(\text{system})\) denote that velocity. Momentum of the system after contact:

Combine to obtain:

\(p(\text{system, after}) =1.5\times 10^{4}\; \rm kg \times (\mathnormal{v}(\text{system}))\).

Because the total momentum of the system will stay the same:

\(\begin{aligned}&1.5\times 10^{4}\; \rm kg \times (\mathnormal{v}(\text{system}))\\ &= p(\text{system, after}) \\&= p(\text{system, before}) \\ &= 3.0\times 10^{6}\; \rm kg \cdot m \cdot s^{-1}\end{aligned}\).

Solve for \(v(\text{system})\) to obtain:

\(v(\text{system}) = 20\; \rm m\cdot s^{-1}\).

In other words, the new velocity of the system would be \(20\; \rm m \cdot s^{-1}\).

Answer: v=1,56(m/s)

Explanation: Called: g(Gravity acceleration) =10\(m/s^{2} \\\)(or 9,8\(m/s^{2}\))

                                 h=1,2m  ;   t=1,3s

Because the coin fell freely, the velocity is calculated by the formula:

v=\(\sqrt{2gh}\)  (1)

besides, you have time to touch the bottom of the water is 1,3s:

t=\(\sqrt\frac{2g}{h} }\) (2)

(1) and (2) => v=1,56 (m/s)

Answer:

B

Explanation:

The correct answer is B on edge

(Looks like a flower with 3 petals with the most right petal covering the x-axis.)

Answer: Just pray for me, thank you.

4.3.11 QC

100% correct

1. Use the image to answer the question.

Select the equation that represents the graph.

Which table best represents the graph of the equation θ = 45°

Answers:

1. r= 4 which is C

2. A table

3. D (4.24, pi/4)

4. D Radius 1 and center (1,0)

5. B symmetrical about the vertical axis

Explanation: I did it!

When a beam of 11 keV X-rays illuminates a sample, the angles that will produce diffraction maxima of the first, second, and third order can be calculated using Bragg's law, which states that nλ = 2d sin(θ), where n is the order of diffraction, λ is the wavelength of the X-rays, d is the spacing between crystal lattice planes, and θ is the angle of incidence.

Bragg's law can be used to calculate the angles for diffraction maxima. For the first-order maximum (n = 1), we have λ = 2d sin(θ₁). Rearranging the equation, we get sin(θ₁) = λ / (2d). Substituting the values, with λ representing the wavelength of 11 keV X-rays (which can be converted to the corresponding wavelength), and the known spacing between lattice planes, we can solve for θ₁.

For the second-order maximum (n = 2), the equation becomes λ = 2d sin(θ₂). Solving for sin(θ₂) and substituting the values, we can find θ₂.

Similarly, for the third-order maximum (n = 3), we use λ = 2d sin(θ₃) to determine sin(θ₃) and find θ₃ by substituting the values.

By calculating these angles using Bragg's law, we can determine the angles that will produce diffraction maxima of the first, second, and third order for the given beam of 11 keV X-rays illuminating the sample.

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I dont see the question to this

Answer:

The correct answer would be B

Explanation:

I took the test and we use wind and turbines to create a renewable energy source.

It took 50 joules to push a crate 2.5 meters. With what force was the crate pushed?

Astronomers determine the composition of the Sun's outer layers using a technique called spectroscopy.

Spectroscopy involves analyzing the light emitted by the Sun and splitting it into its component colors, creating a spectrum. Each element produces a unique set of spectral lines when its atoms absorb or emit light. By comparing the observed spectral lines to known patterns from laboratory tests, astronomers can identify the elements present in the Sun's outer layers, such as hydrogen and helium.
This information, along with other data from space probes and computer simulations, helps scientists understand the composition and processes occurring in the Sun's outer layers.

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The particle moves to the right through a potential difference of Vb-Va = 3.20×10^-19 J / q.

The particle, initially at rest, is acted upon only by the electric force and moves from point a to point b along the x axis, increasing its kinetic energy by 3.20×10^-19 J. To determine the direction and potential difference through which the particle moves, we can use the relationship between electric potential difference (V) and electric force (F) on a charged particle.

The electric potential difference between two points is defined as the work done per unit charge to move a particle from one point to the other. The work done on a charged particle by an electric force is given by the equation

W = Fdcos(theta)

where F is the electric force, d is the distance moved by the particle, and theta is the angle between the direction of the force and the direction of the displacement.

In this case, since the particle is only acted upon by the electric force and moves along the x-axis, the angle between the direction of the force and the direction of the displacement is 0, and the work done by the electric force is given by W = Fdx.

Therefore, the potential difference between point a and point b is given by Vb - Va = W/q, where q is the charge of the particle.

Given that the particle's kinetic energy increases by 3.20×10^-19 J and the work-energy principle states that work done on a particle is equal to the change in kinetic energy, we can say that the work done on the particle is equal to 3.20×10^-19 J.

Now, the direction of the force can be determined by the sign of the potential difference, since the electric force is given by

F = -q(dV/dx).

Given that the potential difference is positive, the electric force is negative, meaning that the force is directed opposite to the direction of motion of the particle, therefore the direction of motion is to the right.

Therefore, the particle moves to the right through a potential difference of Vb-Va = 3.20×10^-19 J / q.

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Number of bright fringes = 7

To calculate the number of bright fringes (visible maxima) in a diffraction pattern, we can use the formula for the diffraction grating equation:

n * λ = d * sinθ

Where n is the order of the bright fringe, λ is the wavelength of light (520 nm), d is the distance between adjacent slits in the grating, and θ is the angle of the diffracted light.

First, we need to find the distance between adjacent slits (d). The grating has 600 lines/mm, so we can calculate d as:

d = 1 / 600 lines/mm = 1/600 mm = 1.6667 * 10^(-6) m

Now, we can find the maximum order (n_max) that is visible using the grating equation:

n_max * 520 * 10^(-9) m = 1.6667 * 10^(-6) m * sin90°
n_max = 1.6667 * 10^(-6) m / 520 * 10^(-9) m
n_max ≈ 3.2

Since n must be an integer, the maximum order is n = 3.

To find the number of bright fringes, we count the orders on both sides of the central maximum (n = 0). So, there are 2 * 3 + 1 = 7 bright fringes in total.

The correct answer is b) 7.

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F_net:-

Now

Apply Newton's second law

Answer:

b. between 2 s and 4 s

Explanation:

2-4 was both 3m/s

Answer:

soil

Explanation:

CORRECT

Answer:

soil

Explanation:

Hope this will help

Clouds of gas and dust as well as new star formation are typically seen in irregular and spiral galaxies.

The correct answer is option a and b.

Galaxies are vast collections of stars, gas, dust, and other material held together by gravity. The different types of galaxies are generally categorized based on their shape, which is determined by the distribution of stars and other material within them.

Irregular galaxies are so named because they have irregular shapes, lacking the symmetrical structure of spiral and elliptical galaxies. They often have chaotic, clumpy appearances and contain large amounts of gas and dust, which are the raw materials for new star formation.

Irregular galaxies are thought to form through interactions and mergers with other galaxies, which can disrupt their structure and trigger bursts of star formation.

Spiral galaxies, as the name suggests, have a spiral or disk-like structure with distinct arms that radiate out from a central bulge. These arms contain large amounts of gas and dust, which are the sites of ongoing star formation. Spiral galaxies are generally thought to be more stable than irregular galaxies, with the regular rotation of their disk-like structures helping to maintain their shape.

Therefore the correct answer is a and b.

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when you carry the 2 and add the 3 its Z

Degeneracy pressure stops the crush of gravity in all the following except a brown dwarf. The correct option is a.

Electron degeneracy pressure is a subset of the broader phenomenon of quantum degeneracy pressure.

The Pauli exclusion principle prevents two identical half-integer spin particles from occupying the same quantum state at the same time.

Electron degeneracy pressure, in particular, is what protects white dwarfs from gravitational collapse, as well as the Chandrasekhar limit (the maximum mass a white dwarf can attain) arises naturally as a result of electron degeneracy physics.

Thus, the correct option is a.

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