a car traveling forward +30m/s had its brakes applied and stops in 3.0s. what id the car's acceleration?​

The electrical force between 2 objects is 400 N. According to Coulomb's law, if both charges are doubled, the electrical force will be 1600 N.

The electrical force between 2 charged objects is directly proportional to their charges and inversely proportional to the square of the distance between them.

The electrical force between 2 objects is 400 N. Due to the direct proportionality, if the charge of both objects is doubled (multiplied by 2), the total force will be multiplied by 4.

F = 2 × 2 × 400 N = 1600 N

The electrical force between 2 objects is 400 N. According to Coulomb's law, if both charges are doubled, the electrical force will be 1600 N.

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The angle through which the wheel has turned when the angular speed reaches 0 is 5.60 radians.

To find the angle through which the wheel has turned when the angular speed reaches a certain value, we can use the formula for angular displacement. Angular displacement is the change in the angle of rotation of an object and is measured in radians.

The formula for angular displacement is given by:

θ = ω*t + (1/2)αt^2

where θ is the angular displacement in radians, ω is the initial angular speed in radians per second, α is the angular acceleration in radians per second squared, and t is the time in seconds.

In this problem, we need to find the angle through which the wheel has turned when the angular speed reaches some value. Let's call this final angular speed ω₁. We can set up two equations using the given information and the formula for angular displacement:

5.5 revolutions = 5.5*2π radians = 34.56 radians

θ = 34.56 radians - 0 radians (initial position)

θ = ω*t + (1/2)αt^2

At the point where the wheel comes to rest, ω₁ = 0, so we can solve for the time t it takes for the wheel to come to rest:

ω₁ = ω + α*t

0 = 3.35 rad/s + α*t

t = -3.35/α

Substituting this expression for t into the equation for angular displacement, we get:

θ = ω*(-3.35/α) + (1/2)α(-3.35/α)^2

Simplifying, we get:

θ = -3.35*(3.35/α) + (1/2)*3.35^2/α

θ = -11.2225/α + 5.625

Now we can use the fact that the final prize value is $1500 to solve for the angular acceleration α:

$1500 = (1/2)Iω_f^2

The moment of inertia I for a disc is (1/2)mr^2, where m is the mass and r is the radius. We can assume a reasonable value for the radius of the wheel, say 0.3 meters, and the mass of the wheel is not given, so we will leave it as a variable m:

$1500 = (1/2)(1/2)m(0.3)^2(0)^2

Solving for m, we get:

m = 6666.67 kg

The angular acceleration can be found using the formula:

α = (τ/I)

where τ is the torque and I is the moment of inertia.

The torque τ can be found using the formula:

τ = r*F

where r is the radius and F is the force.

We can assume a reasonable force, say 100 N:

τ = 0.3100 = 30 Nm

Substituting the values for moment of inertia and torque, we get:

α = (30/((1/2)m(0.3)^2))

α = 139.87 rad/s^2

Now we can substitute this value for α into the equation for angular displacement to get:

θ = -11.2225/139.87 + 5.625

θ = 5.60 radians

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As the intensity increases the energy increases.

Answer:

C. the energy of the sound wave increases

stop your hand so it doesn't hurt as much and if u stop your hand it would make more of an impact because if your hand bounces it means not enough strength so she should stop her hand

Answer:

Las coordenadas del punto son \((x,y) = (6.582\,m, 3.8\,m)\).

Explanation:

La relación entre un vector en formato polar y uno con formato rectangular con respecto al mismo origen queda sintetizado por la siguiente expresión:

\((x, y) = r\cdot (\cos \theta, \sin \theta)\) (1)

Donde:

\(r\) - Magnitud de la distancia del punto con respecto al origen, medido en metros.

\(\theta\) - Dirección del punto con respecto del semieje +x, medido en grados sexagesimales.

\(x,y\) - Coordenadas rectangulares del punto con respecto al origen, medidas en metros.

Si sabemos que \(r = 7.6\,m\) y \(\theta = 30^{\circ}\), entonces las coordenadas rectangulares del punto con respecto al origen son:

\((x,y) = (7.6\,m)\cdot (\cos 30^{\circ}, \sin 30^{\circ})\)

\((x,y) = (6.582\,m, 3.8\,m)\)

Las coordenadas del punto son \((x,y) = (6.582\,m, 3.8\,m)\).

Answer:

Earth's tilt causes the sun's rays to hit unevenly

Explanation:

The Earth orbit or rotate in it's axis or orbital plane. When it's rotate, it tilt from the sun rays Earth's tilt causes the sun's rays to hit the Earth unevenly Earth's axis is tilted about 23 degrees, which causes a variation or differences in the sun's latitude.causing it to vary by 23 degrees north of the equator at the start of northern summer to 23 degrees south of the equator at the start of northern winter. On Earth, that tilt is the primary reason for different seasons.

The claim can be Cosmetics, hygiene, and cleaning product emissions may be dangerous.

Evidence 1: Effect of Air Quality

Volatile organic compounds (VOCs), including formaldehyde, benzene, and toluene, can be found in a variety of cosmetic, hygiene, and cleaning goods. These VOCs have the potential to evaportate and cause indoor air pollution.

Environmental impact is evidence number two

Cosmetics, hygiene, and cleaning goods can have a detrimental environmental impact during manufacturing, usage, and disposal. Microplastics and certain chemicals are among the substances present in these items that may find their way into rivers and endanger aquatic life.

Evidence 3: Worker health effects

Occupational health risks can be present for workers who manufacture and produce hygiene, cleaning, and cosmetic items.

Reasoning: It is clear from the research that emissions from cosmetic, hygiene, and cleaning goods have the potential to be harmful.

Thus, this way, harmful are the emissions from cosmetics, hygiene, and cleaning products.

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Answer:

3.51 g/mL

Explanation:

Density can be found using the equation: density = mass / volume.

In this case, mass is given in grams (g) and volume is given in milliliters (mL).

You can find the density of the diamonds by plugging the given values into the formula and simplifying.

Density = mass (g) / volume (mL)

Density = 6.21 g / 1.77 mL

Density = 3.51 g/mL

Earth would be an icy wasteland if greenhouse gases were not present. Greenhouse gases keep our planet livable by retaining some of the Earth's heat energy, preventing it from escaping into space. The greenhouse effect refers to the trapping of heat.

The following question is about football movement and can be answered by using the equations of projectile launch :

Initial speed is: v = 16.89 m / s

Maximum height is:  y = 14.26m

Given parameters

Horizontal distance x = 28.4 m

Launch angle tea = 38.6º

To find,

The initial speed and the maximum height

         R =  \(v^{2}\)sin2θ/g

    \(v^{2}\)=  g*r/sin2θ

calculating,

         v² = 9.8 *28.4 / sin (2 *38.6)

               =\(\sqrt{278.32/0.9751}\)

                 v = 16.89 m / s

The vertical speed is zero when height maximum.

         v² = v² - 2 g y

         0 = v² - 2g y

         y =   v²/2g

        y = 14.26m

Initial speed is: v = 16.89 m / s

Maximum height is:  y = 14.26m

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Answer:

The answer is "Y → X → Z".

Explanation:

In this question, the chart is missing and the question is not complete that's why we search this question and only give its correct answer that's is defined above, and please find the complete question in the attached file.

A point 0.1 m (perpendicular distance) from the center of a 10 - m long wire with 1C of charge distributed on it. Thus, option 4 is correct.

Subatomic particles with an electric charge will exert a force when they are in an electric or magnetic field, according to the definition of electric charge.

Protons and electrons are the most common charge carriers for the two types of electrical charges—positive and negative.

Subatomic particles or matter particles serve as examples of different types of charges:

The charge on a proton is positive.

Negative charge is a property of electrons.

Null charge exists in neutrons.

Option 4 has the  the strongest electric field

\($$for the long wire,$$\mathrm{E}=\frac{\lambda}{2 \pi \epsilon_{\mathrm{o}} \mathrm{r}}$$where,$$\lambda=\frac{\mathrm{Q}}{\mathrm{L}}=\frac{1}{10}=0.1 \frac{\mathrm{C}}{\mathrm{m}}$$so,$$\begin{aligned}\mathrm{E} & =\frac{0.1}{2 \pi \times 8.85 \mathrm{e}-12 \times 0.1} \\\mathrm{E} & =1.8 \times 10^{10} \ {\mathrm{N}}/{\mathrm{C}}\end{aligned}$$\)

which is comparatively stronger than other cases.

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Answer:

Distance from the moon= dm= 384,403km

A quarter diameter= dq= 2.3 cm= 0.000023km

No of quarters= 16,713,173, 913

To convert cm into km divide cm by 100 and then by 1000

as

1m= 100cm

1km= 1000m

Therefore

2.3/100= 0.023 m

And

0.023/1000= 0.000023 km

Dividing the distance from the moon by the diameter of the quarter laid end to end would give the number of the quarters needed.

No. of quarters= Distance from the moon/ Diameter of the quarter

                             = 384,403km/0.000023 km

                             =       16,713,173,913.043

Rounding  16,713,173,913.043 gives 16,713,173,913 quarters

Explanation:

Brainliest, please!

The maximum possible age of that galaxy when the light we are now observing from it began its journey to earth could be 6 billion years.

A galaxy is described as a huge collection of gas, dust, and billions of stars and their solar systems, all held together by gravity.

The universe as a whole is expanding, but groups and clusters of galaxies (as well as individual galaxies) represent places where gravity has won out over the expansion. Therefore, in a gravitationally bound group, such as the Local Group, we do not expect the galaxy motions to follow Hubble's law.

Astronomers classify galaxies into three major type which include:

Each galaxy span a wide range of sizes, from dwarf galaxies containing as few as 100 million stars to giant galaxies with more than a trillion stars.

So if we assume the galaxy was born less than a billion years after the big bang, the maximum possible age of that galaxy when the light we are now observing from it began its journey to earth could be 6 billion years.

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Answer:

The most likely items to be used are;

Ultrasound and X-rays

Explanation:

A routine visit to a dentist consists of two areas of activities, including;

a) Dental examination and check up

b) Oral prophylaxis, and dental cleaning

The dental examination may involve the use of X-rays, which allow the detection of cavities between the teeth

The dental cleaning can be carried out with the use of an ultrasound cleaner, which allow the cleaning of sensitive teeth without hurting the patient

Therefore, the items most likely to be used during a routine dental visit are ultrasound and X-rays

Answer:

ultrasound and x-rays

Explanation:

Answer:

Energy stored in food is consider as carbohydrate,protein,fats,etc.

The final temperature of the mixture is closest to 32.5 °C

Heat loss = Heat gain

MᵥᵥC(Tᵥᵥ – Tₑ) = M꜀C(Tₑ – M꜀)

50 × 4.184 (40 – Tₑ) = 30 × 4.184(Tₑ – 20)

209.2(40 – Tₑ) = 125.52(Tₑ – 20)

Clear bracket

8368 – 209.2Tₑ = 125.52Tₑ – 2510.4

Collect like terms

8368 + 2510.4 = 125.52Tₑ + 209.2Tₑ

10878.4 = 334.72Tₑ

Divide both side by 334.72

Tₑ = 10878.4 / 334.72

Tₑ = 32.5 °C

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"The planet speeds up in its rotation about its axis when closer to the Sun, and slows down in its rotation about its axis when farther from the Sun" is not a correct, relevant statement regarding Kepler's 2nd Law.

The correct answer is option C.

Kepler's 2nd Law, also known as the Law of Equal Areas, states that a line connecting a planet to the Sun sweeps out equal areas in equal times as the planet moves in its elliptical orbit around the Sun. This law is relevant to the orbital motion of the planet, not its rotation about its axis.

The rotation of a planet about its axis is governed by other factors, such as its own internal forces and torques. The distance from the Sun does not directly affect the planet's rotation about its axis. Therefore, statement c is not a correct or relevant statement regarding Kepler's 2nd Law.

The correct statements regarding Kepler's 2nd Law are:

a. The planet speeds up in its orbit when closer to the Sun and slows down in its orbit when farther from the Sun. This is because the planet experiences a stronger gravitational force from the Sun when it is closer, resulting in a higher orbital speed.

b. The area of the angle "swept out" by an imaginary line connecting the planet and the Sun, during some fixed amount of time, never changes during its orbit around the Sun. This implies that the planet covers equal areas in equal times, reflecting the conservation of angular momentum in the absence of external torques.

d. The planet conserves angular momentum during its orbit around the Sun. This means that the product of the planet's moment of inertia and its angular velocity remains constant throughout its orbit, in the absence of external torques.

In summary, statement c is not a correct or relevant statement regarding Kepler's 2nd Law, while statements a, b, and d accurately describe the key aspects of Kepler's 2nd Law.

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option b )2004........

Answer: According to author bell hooks, in "What Race Isn't: Teaching About Racism," when confronted with the reality that race is not biologically real, it is problematic to respond "We're all human beings" because it obscures the ways in which race and racism are social constructs that impact people's lives. This response can be seen as similar to stating "All Lives Matter" because it ignores the systemic inequalities and racial injustices that some communities face. Both of these responses downplay the complexities and nuances of race and racism, and prioritize the idea of racial unity over acknowledging and addressing systemic inequalities and injustices.

The momentum of the system remains conserved overall, even though individual momenta within the system change as you jump up.

When you jump up, two forces act upon the system comprising yourself and the Earth: the force you exert on the Earth and the force the Earth exerts on you (equal in magnitude and opposite in direction). According to Newton's third law of motion, for every action, there is an equal and opposite reaction.

As you push against the Earth to jump up, you exert a force on the Earth, causing it to move in the opposite direction. Simultaneously, the Earth exerts an equal and opposite force on you, propelling you upward. This exchange of forces occurs within the system of "you + Earth."

Since momentum is defined as the product of mass and velocity, and momentum is conserved in an isolated system (where no external forces act), we can examine the momentum changes within the system when you jump:

Before jumping, the total momentum of the system (you + Earth) is zero since your initial velocity is zero and the Earth's velocity is negligible.

When you jump, your momentum increases in the upward direction, while the Earth's momentum decreases by an equal amount in the opposite direction. The increase in your momentum is equal and opposite to the decrease in the Earth's momentum, maintaining the total momentum of the system as zero.

Therefore, the momentum of the system remains conserved overall, even though individual momenta within the system change as you jump up.

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Answer:

383.2

Explanation:

W=m×g(9.8)×(change in height)

=3×9.8× (45-32)

=3×9.8×13

=383.2

This sound is a combination of three different tones, which can be described as a bright, high-pitched sound. As the frequency increases, the tone becomes higher and more intense.

Sound is a form of energy that is produced when an object vibrates. It is transmitted through the air as waves, which are then detected by our ears. Sound is made up of different frequencies, from low bass tones to high-pitched squeaks. Sound waves can travel through solids, liquids, and gases, and can be heard over long distances. We use sound for communication, music, and entertainment, as well as for warning signals and alarms. Different materials can be used to absorb, reflect, or dampen sound waves, allowing us to better control the sound in our environment. Sound is an essential part of our lives, and is an important factor in how we interact with the world around us.

The 400 Hz tone gives the sound a foundation, while the 1600 Hz and 2400 Hz tones give it an extra layer of brightness.

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Answer:

Below :)

Explanation:

It is the powerhouse of the cell and creates chemical energy.

The minimum allowed length for the runway is  1170m.

a=3.30m/s2 is the acceleration of the plane

v=88.0 m/s is the final velocity of the plane

u=0m /s is the initial velocity of the plane

The acceleration of the object is the slope of the v-t graph, therefore,

Slope=Change in y component / Change in the x component

a = u- v / T f - T i

T f - T i =  v/a

T f - T i = 88/3.3

T f - T i = 26.67 s

The displacement,

d=1/2 b h

d=1/2(T f - T i ) * v

d = 1/2 * 26.67 s * 88.0 m / s

d = 1173.33

   = 1170m nearest three significant figures

Hence, the minimum allowed length for the runway is 1170m answers.

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Given the following information:Mass of the system, m = 20 kg.Damping coefficient, b = 6 Ns/m.Force, F = 90 N.Frequency of applied force, f = ?Applied force angular frequency, w = 6 rad/s.Forced vibration equation:F(t) = F0 sin(wt)where F0 = 90 N and w = 6 rad/s.Under the action of the force F, the mass m will oscillate.The equation of motion for the mass-spring-damper system is given by:$$\mathrm{m\frac{d^{2}x}{dt^{2}}} + \mathrm{b\frac{dx}{dt}} + \mathrm{kx = F_{0}sin(\omega t)}$$where k is the spring constant.x(0) = 0 and x'(0) = 0.As we have the damping coefficient (b), we can calculate the damping ratio (ζ) and natural frequency (ωn) of the system.Damping ratio:$$\mathrm{\zeta = \frac{b}{2\sqrt{km}}}$$where k is the spring constant and m is the mass of the system.Natural frequency:$$\mathrm{\omega_{n} = \sqrt{\frac{k}{m}}}$$where k is the spring constant and m is the mass of the system.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$At resonance, the amplitude of the system will be maximum when forced by a sinusoidal force of frequency equal to the resonant frequency.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$$$\mathrm{\omega_{d} = \sqrt{(6.57)^{2}-(-2.88)^{2}} = 6.98 rad/s}$$Hence, the frequency of applied force at which resonance will occur is 6.98 rad/s.

The frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

To determine the frequency of the applied force at which resonance will occur, resonance happens when the frequency of the applied force matches the natural frequency of the system. The natural frequency can be determined using the formula:

ωn = √(K / M),

where ωn is the natural frequency, K is the spring constant, and M is the mass of the system.

Substituting the given values of K = 400 N/m and M = 20 kg into the equation, we can calculate the natural frequency ωn.

ωn = √(400 N/m / 20 kg) = √(20 rad/s²) = 2√5 rad/s.

Therefore, the frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

The correct question is given as,

M= 20kg

Fo = 90 N

ω = 6 rad/s

K = 400 N/m

C = 125 Ns/m

Determine the frequency of applied force at which resonance will occur?

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Answer:

A circuit breaker is a switching mechanism that interrupts the current that is irregular or fault. It is a mechanical system that interferes with high magnitude (fault) current flow and also performs a transfer operation. Hope this helps :)

Explanation:

Answer:

A circuit breaker is an electrical switch designed to protect an electrical circuit from damage caused by an overcurrent or short circuit.

Explanation:

Its basic function is to interrupt current flow after protective relays detect a fault.

The magnitude of current flowing through the conductance is:
(a) 0.2 A.

(b) 100 A.

(c) 10 e^(-2t) A.

(d) 0.5 sin(5t) A.

(e) 0 A.

To determine the magnitude of the current flowing through a conductance, we need to use Ohm's Law, which states that the current (I) flowing through a conductor is equal to the voltage (V) across it divided by its conductance (G).

Ohm's Law equation: I = V / G

Given the voltage across the conductance in each case, we can calculate the current magnitude using the given conductance values.

(a) Voltage = 2 mV, Conductance = 10 mS (10 ms)

I = (2 mV) / (10 mS)

I = 0.2 A

The magnitude of the current flowing through the conductance is 0.2 A.

(b) Voltage = -1 V, Conductance = 10 mS (10 ms)

I = (-1 V) / (10 mS)

I = -100 A

The magnitude of the current flowing through the conductance is 100 A.

(c) Voltage = 100 e^(-2t) V, Conductance = 10 mS (10 ms)

I = (100 e^(-2t)) / (10 mS)

I = 10 e^(-2t) A

The magnitude of the current flowing through the conductance is 10 e^(-2t) A.

(d) Voltage = 5 sin(5t) V, Conductance = 10 mS (10 ms)

I = (5 sin(5t)) / (10 mS)

I = 0.5 sin(5t) A

The magnitude of the current flowing through the conductance is 0.5 sin(5t) A.

(e) Voltage = 0 V, Conductance = 10 mS (10 ms)

I = (0 V) / (10 mS)

I = 0 A

The magnitude of the current flowing through the conductance is 0 A.

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Answer:

option B is the correct option

Explanation:

According to momentum conversion,

momentum of one car= 6600×2=13,200kgm/s

momentum of another car=5,400×(-3)=16,200kgm/s

Then,

Momentum of second car-momentum of first car

=16,200-13200

=3000kgm/s

mass of first car -mass of second car

=6600-5400

=600kg

final velocity=3000/600=2.5 m/s