A car of mass 900kg starting from rest has a constant acceleration of 3.5m/s² . calculate it's momentum after it has travelled a distance of 40m​

The number of times times larger is the United States water consumption PER PERSON compared to the World water consumption PER PERSON is 100 to 175 gallons of water

Every day, the average American uses 100 to 175 gallons of water. We use almost 4 trillion cubic meters of freshwater annually on a global scale! In some areas, agriculture can use up to 90% of the available freshwater.

Although the water resources in the United States are enormous, they are not limitless. Given that the average American's water footprint, or the total amount of water consumed directly and indirectly, is about twice that of the rest of the world, it is extremely important to save and safeguard this water.

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The equation that relates the forces acting on person to the acceleration of the person in elevator is as : N - mg = ma

An influence that causes the motion of object with mass to change it's velocity is called force.

The equation that relates forces acting on the person to acceleration of the person in elevator is: N - mg = ma

N is normal force exerted on the person by the elevator floor, m is mass of the person, g is acceleration due to gravity, and a is acceleration of the elevator.

This equation is derived from Newton's second law of motion, which states that net force acting on object is equal to its mass times its acceleration. In this case, net force acting on the person is the difference between normal force N and force of gravity mg, which is equal to ma, the product of person's mass and acceleration of the elevator.

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Answer:

Heres on ex.

When the driver of a bus applies brake suddenly, the lower part of the body comes to rest as the bus comes to rest but, the upper part of the body continues to move forward due to inertia of motion.

Explanation:

Answer:

the ans is D.... good luck

Answer:

D-Enhancing memory

Explanation:

Answer:

The value is  \(m = 69.24 \ kg\)

Explanation:

From the question we are told that

   The value of the external force is  \(F = 59.0 \ N\)

    The magnitude of the astronaut's acceleration is  \(a = 0.852 \ m/s\)

Generally Newton's Second Law of Motion from the mass of the astronauts is mathematically represented as

            \(m = \frac{F}{a}\)

=>         \(m = \frac{59 }{0.852 }\)

=>         \(m = 69.24 \ kg\)  

Answer:

(a) To calculate the energy in electron volts of an electron with a de Broglie wavelength of 400 nm, we can use the de Broglie wavelength equation:

λ = h / p

where λ is the de Broglie wavelength, h is Planck's constant (6.626 x 10^-34 J s), and p is the momentum of the particle. We can rearrange this equation to solve for the momentum:

p = h / λ

Plugging in the given de Broglie wavelength, we get:

p = (6.626 x 10^-34 J s) / (400 x 10^-9 m)

= 1.6565 x 10^-24 kg m/s

To calculate the kinetic energy of the electron, we can use the formula:

KE = p^2 / (2m)

where m is the mass of the electron (9.109 x 10^-31 kg). Plugging in the momentum we just calculated, we get:

KE = (1.6565 x 10^-24 kg m/s)^2 / (2 x 9.109 x 10^-31 kg)

= 1.423 x 10^-17 J

Finally, we can convert this energy from joules to electron volts (eV) using the conversion factor 1 eV = 1.602 x 10^-19 J:

KE = 1.423 x 10^-17 J / (1.602 x 10^-19 J/eV)

= 88.8 eV

Therefore, the energy in electron volts of an electron with a de Broglie wavelength of 400 nm is 88.8 eV.

(b) To calculate the energy in electron volts of a photon with a wavelength of 400 nm, we can use the formula:

E = hc / λ

where E is the energy of the photon, h is Planck's constant, c is the speed of light (299,792,458 m/s), and λ is the wavelength of the photon. Plugging in the given wavelength, we get:

E = (6.626 x 10^-34 J s) x (299,792,458 m/s) / (400 x 10^-9 m)

= 4.965 x 10^-19 J

Finally, we can convert this energy from joules to electron volts using the conversion factor 1 eV = 1.602 x 10^-19 J:

E = 4.965 x 10^-19 J / (1.602 x 10^-19 J/eV)

= 3.10 eV

Therefore, the energy in electron volts of a photon with a wavelength of 400 nm is 3.10 eV.

Explanation:

The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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(a) The work done by the 150 N force is 877.5 Joules.

(b) The coefficient of kinetic friction between the crate and the surface is approximately 0.437.

To answer this problem, we must take into account the work done by the applied force as well as the work done by friction.

(a) The applied force's work may be estimated using the following formula:

Work = Force * Distance * cos(theta)

where the force is 150 N and the distance is 5.85 m. Since the force is applied horizontally and the displacement is also horizontal, the angle theta between them is 0 degrees, and the cosine of 0 degrees is 1.

As a result, the applied force's work is:

Work = 150 N * 5.85 m * cos(0) = 877.5 J

So, the work done by the 150 N force is 877.5 Joules.

(b) Frictional work is equal to the force of friction multiplied by the distance. The work done by friction is identical in amount but opposite in direction to the work done by the applied force since the crate travels at a constant speed.

The frictional work may be estimated using the following formula:

Work = Force of Friction * Distance * cos(theta)

The net force applied on the crate is zero since it is travelling at a constant pace. As a result, the friction force must be equal to the applied force, which is 150 N.

Thus, the work done by friction is:

Work = 150 N * 5.85 m * cos(180) = -877.5 J

Since the work done by friction is negative, it indicates that the direction of the frictional force is opposite to the direction of motion.

The coefficient of kinetic friction may be calculated using the following equation:

Friction Force = Kinetic Friction Coefficient * Normal Force

The normal force equals the crate's weight, which may be computed as:

Normal Force = mass * gravity

where the mass is 35.0 kg and the acceleration due to gravity is approximately 9.8 m/s^2.

Normal Force = 35.0 kg * 9.8 m/s^2 = 343 N

Now, we can rearrange the equation for the force of friction to solve for the coefficient of kinetic friction:

Force of Friction = coefficient of kinetic friction * Normal Force

150 N = coefficient of kinetic friction * 343 N

coefficient of kinetic friction = 150 N / 343 N ≈ 0.437

As a result, the kinetic friction coefficient between the container and the surface is roughly 0.437.

In summary, the work done by the 150 N force is 877.5 Joules, and the coefficient of kinetic friction between the crate and the surface is approximately 0.437.

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The net force applied to the car is 41300 Newtons.

The net force applied to an object can be determined using Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

In this case, the mass of the racing car is given as 700 kg, and the acceleration is 59 m/s². We can use the equation F = m * a, where F is the net force, m is the mass, and a is the acceleration, to calculate the net force.

Substituting the given values into the equation, we have:

F = 700 kg * 59 m/s²

F = 41300 N

Therefore, the net force applied to the car is 41300 Newtons.

The net force represents the overall force acting on the car, which is responsible for its acceleration. In this scenario, the car is experiencing a net force of 41300 N, which is causing it to undergo uniform acceleration of 59 m/s².

This force is the result of various factors, such as the engine power, aerodynamic forces, and the interaction between the tires and the road surface.

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Answer:

150000 is the answer to the question

Only weigh is a force. force is mass multiplied by acceleration. weight is the mass plus the gravitational force acting on it.          

The difference between mass and weight is that mass is a measure of inertia and weight is a measure of force. We  use both of these terms interchangeably but this is not quite correct.

Mass can be defined as how much a material an object is made up of. so considering the smallest particles we can say that the number of protons, neutrons, and electrons in an object is a simply the measure of its mass. Mass, can be referred as  both a property of an object and a measure of an object's resistance to acceleration.  kilograms and grams is the unit of mass.

The weight of an object can be referred as the force acting on it because or due  to gravity. That is, the gravitational interactions between bodies and masses, and when they interacts with the Earth, that force will be considered as the weight. its Unit is Newtons.

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The true statement is that the acceleration in the first two seconds is 6 m/s^2.

The term acceleration is defined as the rate of change of velocity with time. The graph as shown is a velocity time graph. The graph shows the changes that occur in the velocity over a given time interval.

Now  we have;

Initial velocity = 0 m/s

Final velocity = 12 m/s

Time taken = 2s

Acceleration = 12 - 0/2

= 6 m/s^2

Thus the true statement is that the acceleration in the first two seconds is 6 m/s^2.

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The charge required for the fixed point charge is approximately \(4.8032 * 10^{-10} C\).

The electrostatic force between the fixed point charge and the electron is equal in magnitude to the gravitational force between the electron and the Earth, so we can set these two forces equal to each other and solve for the charge of the fixed point charge.

Electrostatic force between two point charges is given by Coulomb's law:

\(F = k * q1 * q2 / r^2\)

The gravitational force between two masses is given by Newton's law of gravitation:

\(F = G * m1 * m2 / r^2\)

Setting these two forces equal to each other and solving for q2, we get:

\(k * q1 * q2 / r^2 = G * m_e * m\_earth / r^2\)

Solving for q2, we get:

\(q2 = G * m_e * m\_earth / k\)

Substituting the given values, we get:

\(q2 = (6.67430 * 10^{-11} N * m^2 / kg^2) *\\ (9.10938356 *10^{-31} kg) *\\ (5.9722 *10^{24} kg) / (8.98755 * 10^9 N * m^2 / C^2)\)

\(q2 = 4.8032 * 10^{-10} C\)

Therefore, the charge required for the fixed point charge is approximately \(4.8032 * 10^{-10}\)C.

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Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Situations that illustrate the conservation of mechanical energy is (d) Both a and b.

According to the principle of mechanical energy conservation, a system's entire mechanical energy is conserved, meaning that energy cannot be generated or destroyed and can only be internally transformed from one form to another provided the forces acting on the system are conservative in nature.

(a) Sometimes referred to as a dissipative force, air resistance contributes to a loss in the total amount of mechanical energy. So, if friction and air resistance are balanced, the total mechanical energy will be conserved. Hence, friction and air resistance balanced is an example of conservation of mechanical energy.

(b) The pendulum bob's height above the tabletop changes continuously as it swings back and forth, which affects its speed. Potential energy is lost as the height drops, whereas kinetic energy is gained simultaneously. However, the bob's total potential and kinetic energy are always constant. There is a conservation of all mechanical energy. There is only a change from kinetic to potential energy; there is neither a gain nor a loss of mechanical energy (and vice versa).

(c) Let's assume that an external force exerted on an object over a certain distance causes the object's total mechanical energy to change. The item gains mechanical energy if the external force (or nonconservative force) exerts positive work. Energy is gained in a quantity equal to the work done on the object. The item loses mechanical energy if the external force (or nonconservative force) exerts negative work. Hence, energy is not conserved.

Both (a) and (b) illustrate the conservation of energy.

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A group of students are eating in the cafeteria. As they eat, the students break down the molecules in the food, which releases the energy. They are releasing the stored chemical energy within the food, enabling their bodies to perform various activities and functions.

The correct answer is option A.

The form of energy stored in food is chemical energy. Chemical energy is a type of potential energy that is stored in the bonds between atoms and molecules within substances. When food is consumed, it undergoes a process called digestion, where complex molecules such as carbohydrates, proteins, and fats are broken down into simpler molecules such as glucose, amino acids, and fatty acids. These molecules are then further broken down through cellular respiration, a biochemical process that occurs in cells, to release energy.

During cellular respiration, the bonds within the molecules of food are broken, and their stored chemical energy is converted into a more readily usable form of energy called adenosine triphosphate (ATP). ATP is a molecule that acts as a cellular energy currency, providing energy for various cellular processes. This energy is essential for the functioning of cells, tissues, and organs in the body.

So when a group of students are eating in the cafeteria they break down the molecules in the food, which releases the energy and chemical energy is stored in the food.

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Answer: when a circuit is completed (it allows the flow of electrons which causes the light bulb to produce light).

Explanation:

A circuit is described as an electrical setup that is consists of a light bulb, a switch, a wire, a battery which is arranged to allow the flow of electric current. The major components of the electrical circuit includes:

--> The BATTERY which is the source of voltage to the circuit,

--> the WIRE which is the conductive path,

--> the LIGHT BULB which is the load that needs electrical power to operate and

--> the SWITCH which is the controller.

When a circuit is COMPLETED when electrons can flow from one end of a battery all the way around, through the wires, to the other end of the battery. Along its way, it will carry electrons to electrical objects that are connected to it like the light bulb and make it to produce light.

There are different types of electric circuit which are designed to create a conductive path of current or electricity. They include:

--> closed circuit

--> open circuit

--> short circuit

--> parallel circuit

--> series circuit.

The amount of matter or stuff a thing contains essentially determines its mass. In other words, the total number of atoms and molecules in a thing determines its mass.

Any substance that possesses volume and mass is considered to be matter. Every one of the many-particle kinds has a distinct mass and size.

Atoms are the minuscule constituent parts of matter. Matter exists in three different states. Gas, liquid, and solid.

The electron, proton, and neutron are the three types of material particles that are most well-known.

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ANSWER

4Fe+ 3O2 → 2Fe2O.

EXPLANATION

iron (Fe) combines with oxygen (O2) to form rust, or iron oxide (Fe2O3). The equation for this reaction is: 4Fe+ 3O2 → 2Fe2O.

Answer:

p = 60.6N*s

Explanation:

v_f = v_0+a*t

a = (v_f-v_0)/t

a = (1.8m/s)/2.35s

a = 0.77m/s²

F = m*a

F = (25kg+8.5kg)*0.77m/s²

F = 25.8N

^p = F*t

p = 25.8N*2.35s

p = 60.6N*s

The magnitude of the electric field between the plates of the capacitor is 19.47 V/m.

To find the magnitude of the electric field between the plates of the given capacitor, we can use the formula for electric field in a parallel plate capacitor. The electric field (E) between the plates of a parallel plate capacitor is given by the equation:

E = V/d

Where V is the voltage applied to the capacitor and d is the separation between the plates. In this case, the voltage applied is 11.8 V and the separation between the plates can be calculated using the area (A) and the dielectric constant (k) of the mylar film. The capacitance (C) of a parallel plate capacitor is given by the equation:

C = €0 * (A/d)

Where €0 is the permittivity of free space.

Rearranging the above equation, we can solve for d:

d = €0 * A / C

Substituting the given values, we have:

d = (8.854 × 10^(-12) F/m) * (3.10 × 10^(-4) m^2) / (56.4 × 10^(-12) F)

Simplifying the expression, we find:

d = 0.606 m

Now, substituting the values of V and d into the equation for electric field, we get:

E = (11.8 V) / (0.606 m)

E = 19.47 V/m

Therefore, the magnitude of the electric field between the plates of the capacitor is 19.47 V/m.

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When a rectangular loop of wire has area A it is placed perpendicular to a uniform magnetic field B and spun around one of its sides at frequency f the maximum induced emf is  2πBAf

A magnetic field could be understood as an area around a magnet, magnetic material, or an electric charge in which magnetic force is exerted.

The maximum induced emf is 2πBAf when a rectangular wire loop of area A is spun around one of its sides at frequency f, perpendicular to a uniform magnetic field B.

therefore the correct answer is option C

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Your question seems incomplete, the complete question is as follows

A rectangular loop of wire has area A. It is placed perpendicular to a uniform magnetic field B and then spun around one of its sides at frequency f. The maximum induced emf is:

A. BAf

B. 4πBAf

C. 2πBAf

D. 2BAf

Answer:

Action and reaction are equal in magnitude and opposite in direction but they do not balance each other because they act on different objects so they don't cancel each other out.

hope this will help you more

Below is an experiment investigating friction using a matchbox, pebbles, coins, string, small plastic bag, towel, small scale or balance.

Procedure:

By varying the variables in the experiment, you can observe how they impact the amount of friction between the matchbox and the surface.

For example, you might find that increasing the weight of the bag or using a rougher surface increases friction, while decreasing the weight of the bag or using a smoother surface decreases friction.

Friction is a force that opposes motion between two surfaces that are in contact. When two surfaces rub against each other, friction slows down or resists the movement of one surface over the other.

Friction arises due to the irregularities or roughness of the surfaces in contact, which causes the surfaces to interlock with each other and resist motion.

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The motorcycle had covered a distance of 16 meters in half the total time.

a) To calculate the acceleration, we can use the formula:

a = (v - u) / t

where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.

Given:

u = 0 m/s (initial velocity)

v = ? (final velocity)

t = 4 s (time)

s = 64 m (distance)

Using the equation of motion:

s = ut + 1/2at^2

We can rearrange the equation to solve for acceleration:

a = 2s / t^2

a = 2(64) / (4)^2

a = 128 / 16

a = 8 m/s^2

Therefore, the acceleration of the motorcycle is 8 m/s^2.

b) To find the final velocity, we can use the formula:

v = u + at

v = 0 + (8)(4)

v = 32 m/s

Therefore, the final velocity of the motorcycle is 32 m/s.

c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:

s = ut + 1/2at^2

32 = 0 + 1/2(8)t^2

16 = 4t^2

t^2 = 4

t = 2 s

Therefore, the motorcycle had covered half the total distance at 2 seconds.

d) To calculate the distance covered in half the total time, we use the formula:

s = ut + 1/2at^2

s = 0 + 1/2(8)(2)^2

s = 0 + 1/2(8)(4)

s = 0 + 16

s = 16 m

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The theory states that deviance results not only from what people do but also from how others respond to those actions are labeling theory. Hence, the option B is correct.

This theory states that deviance and conformity result not so much from what people do but also from how others respond. It is called labeling theory. Eg: Skipping school, and underage drinking.

It also suggests that any deviance results in how society responds to certain behaviors. It defines the behavior of human beings influenced by other members of society.

It also notes that a person is made to act in a negative way by the manner in which society identifies him. If a person is identified as a criminal then he involves in the criminal activities.

Conflict theory refers to the theory linking deviance to social inequality. Anticipating the consequences of a person's behavior is control theory.

Hence, the correct option is B) labeling theory.

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Answer:

Tolerance: \(\pm 10\%\)

Explanation:

Resistor Color Codes

Resistor Color Coding uses colored bands to quickly identify the resistive value or resistors and its percentage of tolerance.

Since the question does not provide a specific color table, we'll use the table attached below.

The colors of the resistor shown in the question are:

First band: orange

Second band: blue

Third band: brown

Fourth band: silver

The colors relate to the following numbers respectively:

3, 6, 10Ω, \(\pm 1\%\)

The first two colors form the number 36

The third color is the multiplier: 36*10Ω = 360Ω

And the fourth color is the tolerance or the possible variation of the resistance \(\pm 1\%\)

Resistance: 360Ω

Tolerance: \(\pm 10\%\)