a car is driven 1.5 kilometers west in 2 minutes. what is the velocity in m/s?

Answer:

If the car is initially travelling at u m/s, then the stopping distance d m travelled by ... the speed of the car at the instant the brakes are applied. ... Common usage will force us to depart from this later in the notes. ... The history of these equations is not absolutely clear, but we do have some ... Newton (1642–1727) and Leibniz.

Explanation:

hope this helped

Answer: green car and red car

Explanation:

Answer:

it is white car for the first question and for the second it goes green slowest and white fastest red is in the middle

Sunita will see red when she looks at a red lamp via a red filter. The same red lamp will seem dark if she views it via a green filter.

This is so that only red light may travel through the red filter, which absorbs all other hues of light. The bulb will therefore appear to be red because the red filter will only let through red light, blocking all other colors of light.

This is so that only green light may travel through the green filter, which absorbs all other hues of light. The lamp emits red light, which the green filter prevents from passing through, therefore when seen through the green filter, the bulb will be invisible and appear to be black.

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Answer:

Matter, Force

Explanation:

In scientific contexts, mass is the amount of "matter" in an object (though "matter" may be difficult to define) whereas weight is the force exerted on an object by gravity. Objects on the surface of the Earth have weight, although sometimes the weight is difficult to measure.

Jacob reports that as he varies the charge on the left particle, he observes that the force between the two particles changes.

Specifically, when the charge on the left particle is positive, the force between the two particles is attractive, and when the charge on the left particle is negative, the force between the two particles is repulsive. This is because opposite charges attract and like charges repel. As the magnitude of the charge on the left particle increases, the force between the two particles increases as well. The force of attraction is strongest when the charges on both particles are the same, and the force of repulsion is strongest when the charges on the particles are opposite.

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340.14 \(\frac{meters}{second}\)= \(\frac{m}{s}\)          ☆                ☆                ⭐︎           ★             ★           ★            ★                ★

                            ☆               ★                     ★                    ☆              ★             ★        ☆          ⭐︎                        ★               ☀︎                   ✏☆                        ☽          ☂︎           ☔︎                

Meters per second is the unit that we get after dividing meters per seconds.

That's the unit we get after dividing distance by time.

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Answer:

dude if any body could answer that they deserve a Nobel prize because the formula to solve that would require the exact measurement of hadar or as commonly known beta centauri

Explanation:

While there is no direct relationship between speed and thinking distance, higher speeds can result in longer thinking distances due to the increased reaction time needed by the driver.

The relationship between speed and thinking distance is not a direct one, as thinking distance is primarily influenced by the driver's reaction time rather than the actual speed of the vehicle. Thinking distance refers to the distance traveled by a vehicle during the driver's reaction time after perceiving a hazard.

However, there is an indirect relationship between speed and thinking distance in the sense that higher speeds generally result in longer thinking distances. When a vehicle is traveling at a higher speed, the driver needs more time to process information, make decisions, and react to potential hazards. Therefore, a higher speed can lead to a longer thinking distance.

It is important to note that thinking distance is just one component of the total stopping distance, which also includes braking distance. Braking distance is directly influenced by the speed of the vehicle. Higher speeds require longer braking distances to bring the vehicle to a stop.

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Total internal reflection occurs when a light ray hits a surface with a high refractive index at an angle larger than the critical angle. Thus, light will undergo total internal reflection only when it is refracted from a dense medium to a less dense medium at an angle greater than the critical angle.

The total internal reflection is when light waves are reflected back inside a medium instead of passing through it. The phenomenon occurs when the incident angle is greater than the critical angle that is required for the medium. Total internal reflection happens due to the changing of the speed of light when moving from one medium to another.

When a light ray goes from a more dense medium to a less dense one, it bends away from the normal, which is perpendicular to the surface. If the angle of incidence is too large, the ray never goes into the other medium but instead is reflected off the surface of the denser medium back into the original medium. This is referred to as total internal reflection.

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Answer:

High current flow

Explanation:

Generally , the measuring instruments used by technician also have some resistance, though its value is very low  . So when high current is present in the circuit , that current also passes through the instrument which creates a good potential drop across the instrument . So the external voltage used in the circuit measures less voltage .

Answer:

\(V_y = 16.44\ m/s\)

\(V_y = 7.32\ m/s\)

Explanation:

Given

\(\theta = 24\)

\(Velocity\ (V) = 18m/s\)

Required

Determine the vertical and horizontal components

The vertical (Vy) and horizontal (Vx) components is calculated as thus:

\(V_x = Vcos\theta\)

\(V_y = Vsin\theta\)

Calculating Vertical Components:

\(V_y = Vsin\theta\)

\(V_y = 18 * sin24\)

\(V_y = 18 * 0.40673664307\)

\(V_y = 7.32125957526\)

\(V_y = 7.32\ m/s\) --- Approximated

Calculating Horizontal Components:

\(V_x = Vcos\theta\)

\(V_x = 18 * cos24\)

\(V_x = 18 * 0.91354545764\)

\(V_x = 16.4438182375\)

\(V_x = 16.44\ m/s\) --- Approximated

Answer:

2ms-2

Explanation:

F = ma

a = F/m

= 0.5 / 0.25

= 2ms-2

Answer 2m/s^2

Explanation:

mass=0.25kg

Force =0.5N

Acceleration=force/ mass

Acceleration=0.5/0.25

Acceleration=2

Acceleration =2m/s^2

Answer: One example of a body-centered crystal is iron, which has a BCC (body-centered cubic) crystal structure. In a BCC structure, the atoms are arranged in a cube with one atom in the center of the cube and eight atoms at the corners. In this diagram, the circles represent iron atoms. The large circle at the center of the cube is an iron atom that is shared by eight adjacent unit cells. The smaller circles at the corners of the cube are individual iron atoms that are not shared by adjacent unit cells. The diagonal of the cube is the body diagonal, which passes through the center of the cube and connects opposite corners.

Explanation:

Answer:

techtonic

Explanation:

No, the acceleration of a fluid particle is not necessarily zero in steady flow. In steady flow, the fluid properties at any point in the fluid remain constant over time, meaning that the fluid flow rate, velocity, and pressure do not change with time.

However, this does not necessarily mean that the acceleration of individual fluid particles within the flow is zero. According to the continuity equation of fluid mechanics, the rate of fluid flow through any given area in the flow must remain constant in steady flow.

This means that if the cross-sectional area of a pipe carrying fluid decreases, the fluid velocity must increase to maintain a constant flow rate. As the fluid velocity changes, the acceleration of individual fluid particles can also change in response to the changing velocity.

In addition, the Navier-Stokes equations, which describe the motion of fluid particles, include terms for acceleration, which can be non-zero in steady flow if the fluid velocity is changing at a given point.

Therefore, even in steady flow, the acceleration of a fluid particle can be non-zero if there is a change in the fluid velocity at a given point. In summary, while steady flow implies that the fluid properties do not change over time.

It does not necessarily mean that the acceleration of individual fluid particles within the flow is zero. The acceleration can be non-zero if there is a change in the fluid velocity at a given point.

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Answer:

This is because it is derived from newtons and metres as shown in the expression;

Explanation:

\(pressure = \frac{force}{area} \\ P= \frac{F}{A} \\ P= \frac{newtons}{ {m}^{2} } \\ = pascals\)

Answer:

Unit of pascal is called derived unit because it involves three fundamental units i.e.meter,kg,and second.

Explanation:

formula of pascal=kg/m/s^2

Answer:

The volume of water displaced by the raft is 0.233 m³

Explanation:

The question relates to Archimedes' principle which states that the buoyant force experienced by an object immersed in a fluid is equal to the weight of (the force of gravity on) the displaced fluid

The given parameters are;

The combined mass of the person and the raft, m = 233 kg

The liquid on which the raft is located = Water

The density of water, \(\rho _{water}\) = 1000 kg/m³

Weight = Mass, m × g

Where;

m = The mass of the object

g = The acceleration due to gravity = 9.8 m/s²

Given that the raft is on the surface of the water (floating), the buoyant force is equal to the combined weight of the person and the raft = 233 kg

The combined weight of the person and the raft, \(W_{combined}\) = 233 kg × 9.8 m/s² = 2,283.4 N

Therefore;

The buoyant force = 2,283.4 N = The weight of the water displaced

The mass of the water displaced, \(m_{water}\), = 2,283.4 N/(9.8 m/s²) = 233 kg

Density = Mass/Volume

The volume of water displaced by the raft = The mass of the water displaced/(The density of the water) = 233 kg/(1,000 kg/m³) = 0.233 m³.

Answer:

the volume displaced by the raft = 0.233 m3

Explanation:

correct for Acellus

The tension in the screw must be adjusted to 6270 Newtons in order for the transverse wave to make 525 vibrations per second with a wavelength of 3.13 cm.  

The formula for the tension in a screw is: T = 2πWL

Where T is the tension, W is the angular frequency (vibrations per second), and L is the length of the screw.

To find the tension, you need to know the wavelength and the frequency of the transverse wave. The wavelength is given as 3.13 cm, and the frequency is given as 525 vibrations per second.

To solve for the tension, you can rearrange the formula to solve for T:

T = 2πWL

T = 2π(525)(3.13)

T = 6270 Newtons

So the tension in the screw must be adjusted to 6270 Newtons in order for the transverse wave to make 525 vibrations per second with a wavelength of 3.13 cm.  

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Answer:

p1 v1 / t1 = p2 v2 / t2 <- Combined Gas Law

Explanation:

p1= first pressure

p2 = second pressure

v1= first volume

v2= second volume

t1= first temperature

t2= second temperature

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Answer:

C. unlikely to combine with other elements.

Explanation:

In Chemistry, electrons can be defined as subatomic particles that are negatively charged and as such has a magnitude of -1.

Valence electrons can be defined as the number of electrons present in the outermost shell of an atom. Valence electrons are used to determine whether an atom or group of elements found in a periodic table can bond with others. Thus, this property is typically used to determine the chemical properties of elements.

Noble gases are chemical elements with eight valence electrons and as such have a full octet. Some examples are argon, neon, etc.

Hence, the full octet makes the gas (neon) unlikely to combine with other elements.

The largest voltage the battery can have without breaking the circuit at the supports is 626.71 V.

The magnetic field on a current-carrying conductor is determined by the flow of current through the conductor and the distance from the carrier.

Voltage is the pressure exerted by an electrical circuit’s power source through a conducting loop to push charged electrons (“current”) through an electrical circuit to perform a function, such as turning on a light.

Given,

The length of the metal bar = 54.0 cm or 0.54 m

mass of the bar = 740 g or 0.74 kg

magnetic field acting perpendicular to the bar = 0.450 T

resistance  = 26.0

Let the maximum potential in the battery be V and the current in the circuit be I. So

V= IR

V = 26×I

I = V/21

For the rod to be in its position the magnetic force on the rod must be equal to the weight. So

magnetic force = weight

B×I×L = mg

0.45 × V/21 × 0.54 m =  0.74 × 9.8

V = 626.71 V

Thus the largest voltage the battery can have without breaking the circuit at the supports is 626.71 V.

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If your car gets 37.4 miles per gallon, it is approximately equivalent to 15.89 kilometers per liter.

To convert miles per gallon (mpg) to kilometers per liter (km/L), we can use the conversion factors of 1 mile ≈ 1.60934 kilometers and 1 gallon ≈ 3.78541 liters.

Given that the car gets 37.4 miles per gallon, we can calculate the equivalent in kilometers per liter.

First, we convert miles to kilometers by multiplying 37.4 mpg by 1.60934 km/mile, which gives us approximately 60.07 km/gallon.

Next, we convert gallons to liters by dividing 60.07 km/gallon by 3.78541 L/gallon, resulting in approximately 15.89 km/L.

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To determine the work done on the object from 0s to 5s, a student can use the equation ΔK = (1/2)mv², where ΔK is the change in kinetic energy of the object, m is its mass, and v is its velocity.

Since the velocity of the object is changing with time, the student can use the equation ΔK = (1/2)mΔv², where Δv is the change in velocity of the object from 0s to 5s. To find Δv, the student can read the initial velocity, v0, from the y-axis at 0s and the final velocity, vf, from the y-axis at 5s. Then, Δv = vf - v0.

Substituting the values of Δv and m into the equation ΔK = (1/2)mΔv², the student can calculate the change in kinetic energy of the object from 0s to 5s. This change in kinetic energy represents the work done on the object during this time interval.

Using the given values in the problem, the mass of the object is 2 kg. The initial velocity, v0, can be read from the y-axis at 0s, which is approximately 0 m/s. The final velocity, vf, can be read from the y-axis at 5s, which is approximately 4 m/s.

Therefore,

Δv = vf - v0

     = 4 m/s.

Substituting these values into the equation,

we get

ΔK = (1/2)(2 kg)(4 m/s)²

      = 16 J.

Therefore, the work done on the object from 0s to 5s is 16 J.

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Answer:

B Newton's second law

Explanation:

An empty grocery cart is easier to move because there is less mass in an empty cart compared to a full cart. Newton's second law state that an object's acceleration depends on the mass of the object and the force applied.

Answer:

Explanation:

The most important thing to remember about parabolic motion in physics is that when an object reaches its max height, the velocity right there at the highest point is 0. Use this one-dimensional motion equation to solve this problem:

v = v₀ + at and filling in:

0 = v₀ + (-9.8)(4.0) **I put in 4.0 for time so we have more than just 1 sig fig here**

0 = v₀ - 39 and

-v₀ = -39 so

v₀ = 39 m/s

The work was done by the force on the block of 2 kg with an acceleration gravity of  9.81 \(m/s^2\) and at an angle of \(29^o\) 42.83 J.

When an object is moved over a distance by an external force, at least some of that force must be applied in the direction of the displacement. This is known as work in physics. Work may be estimated if the force acting along the path is constant by multiplying the length of the path by the component of the force acting along the path.

To express this formally, the work W is equal to the force f times the length d, or W = fd. The work is W = fd cos if the force is applied at an angle to the displacement.

Given:

The mass, m = 2 kg,

The acceleration, g = 9.81 \(m/s^2\),

θ = angle between block and surface kinetic friction = μ

Calculate the work done by the formula given below,

\(W_{fy}\) = F sinθ

\(W_{fy}\) =  (\(mgsin\)θ)/ (sinθ -  μ * cosθ)

Substitute the values

\(W_{fy}\)  = \((2*9.81 sin29^{o} )/sin29^o - 0.30cos29^o\)

\(W_{fy}\)  = 42.83 J

Therefore, the work done by the force on the block of 2 kg with an acceleration gravity of  9.81 \(m/s^2\), and at an angle of \(29^o\) is 42.83 J.

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