A car has a crumple zone that is 0.80 m (80 cm) long. In this car, the distance from the dummy to the steering wheel is 0.50 m. The car has a mass of 1,600 kg and the dummy has a mass of 75 kg. At the time of the crash, the car has a speed of 18 m/s. Based on the work-energy theorem, what is the smallest possible force that the dummy could experience during the crash

Answer:

Ultraviolet rays from sun are very harmful from skin and can cause sunburn and skin diseases especially ultraviolet B rays. A sunscreen  lotion act as a protection barrier on the skin that restrict the direct contact of UV rays with skin and filter the harmful rays to enter the skin.

Radiotherapy is a medical therapy use to treat cancer. Radiotherapy commonly uses x-rays and gamma rays because they are high-energy particles or waves that kills or destroys the cancer cells.

Sunscreen lotion is able to filter this damaging ultraviolet radiation and prevent it from damaging the skin.

The sun reaches us from outer space brings ultraviolet rays to us. Ultraviolet rays are known to have some damaging effects on the skin. One way to protect our skin from this damaging ultraviolet rays is to use sunscreen lotion which is able to filter this damaging ultraviolet radiation and prevent it from damaging the skin.

X-rays and gamma rays are used in radiotherapy because they are light energy rays which are able to penetrate and destroy malignant cells in the body.

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Refraction is when light travels from one medium to another

This is studied by considering the light as ray.

Here as the ray travels from one medium to another, its speed changes.

However, the frequency of the waves which depend on the source will not change in the other medium as well. So frequency does not change in refraction. But wavelength changes when light undergoes refraction.

Interference and Diffraction are studied treating light as wave. And both of these are basically superposition of waves

In interference, light from two coherent sources interfere with each other and the resulting wave pattern is the subject of interference.

While in diffraction, secondary wavelets emerging from the original wave's different parts is considered. The supersposition of these secondary wavelets is basically diffraction.

In both of these interference and diffraction, speed, wavelength and frequency all remains same as the speed and therefore wavelength depends only on the medium

Reflection involves the change in direction of a wave as it bounces off a barrier. Wave refraction involves the change in direction of a wave as it passes from one medium to another. Diffraction involves the change of direction of a wave as it passes around an opening or barrier in its path.

Reflection is the process of reflecting light when it hits an in-plane medium. Refraction is the process of changing the path and bending light as it passes through a material. Hence, this is the main difference between reflection and refraction.

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For our four-wire resistors (shown in the image below), terminals 1 and 4 are used to measure current.

The four-wire approach makes use of four test leads, one pair of which is used to measure the voltage across the resistor Rmeas and the other pair is used to measure the injected current. The device only measures the voltage that develops across the resistance because there is no current flowing through the sense lead.

Two wires connect the sensing element to the monitoring device on both sides of the sensing element in a four-wire RTD configuration. The measurement current is delivered by one set of wires, and the voltage drop across the resistor is measured by another set.

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Answer:

a.

Explanation:

i did a quizz for it im sorry if im wrong

The aircraft will lose height if no adjustments are made because it is moving from an area of comparatively lower air pressure to one of relatively greater air pressure.

How does pressure impact an aircraft's performance?

Air pressure is what gives airplanes their ability to generate lift. Air travels more quickly on top of an airplane's wings than it does on its underside due to the form of the wing. According to Bernoulli's Principle, air that is traveling more slowly has a greater air pressure than air that is moving more quickly.

What are the three elements that have an impact on an aircraft's performance?

Due to their impact on density, altitude, temperature, and humidity have a significant impact on how well an airplane performs. There is no general principle.

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The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Answer:

P = 84.1 MPa

Explanation:

       \(P = \rho * g * h (1)\)

       where ρ = density of salt water (in Kg/m³),

       g = acceleration due to  gravity  (in m/s²)

       h = height of the column of water.

      \(P = \rho * g * h = 1023.6kg/m3*9.8m/s2*8380m = 84.1 MPa (2)\)

Answer:

2as=v2-u2

2000=v2

V=44

V=u+at

44/10=t

T=4.4seconds

Answer:

A

Explanation:

hope this helps

They travel a horizontal distance of 4.17 m from the exit point before hitting the water.

Energy cannot be created or destroyed, according to the law of conservation of energy. However, it is capable of change from one form to another.

height of the slid: h = 3.1 m

horizontal movement above swimming pool: s = 1.4 m

Let the horizonal speed of the people at the end of the  water slide= v

Using energy conservation

mgh = 1/2 mv²

v = √(2gh)

Again time taken for falling s = 1.4 m under gravitation:

t = √(2s/g)

Hence, the horizontal distance  travelled = speed × time

= √(2gh)×√(2s/g)

= √(4hs)

= √(4 × 3.1 × 1.4)

= 4.17 m.

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To determine the magnitude of the lift force ⃗ and the force of air resistance ⃗ acting on the jet, we need to resolve the weight ⃗ and the forward thrust ⃗ into their horizontal and vertical components.

The weight ⃗ can be resolved into two components:

- the vertical component, Wsin(30°), acting downward

- the horizontal component, Wcos(30°), acting to the left

The forward thrust ⃗ can also be resolved into two components:

- the vertical component, Tsin(30°), acting upward

- the horizontal component, Tcos(30°), acting to the right

Since the jet is flying at a constant speed, the lift force ⃗ must be equal in magnitude to the weight component acting downward, Wsin(30°). Therefore, the magnitude of ⃗ is 86,500 Nsin(30°) = 43,250 N.

The force of air resistance ⃗ is equal in magnitude to the horizontal component of the weight, Wcos(30°), minus the horizontal component of the forward thrust, Tcos(30°). Therefore, the magnitude of ⃗ is (86,500 Ncos(30°)) - (103,000 Ncos(30°)) = -8,715 N, where the negative sign indicates that the force of air resistance is acting in the opposite direction to the motion of the jet.

Therefore, the magnitude of the lift force ⃗ is 43,250 N and the magnitude of the force of air resistance ⃗ is 8,715 N.

Using Einstein's famous equation E=mc², where E is the energy released in a nuclear reaction and is 11.25 meV, it is possible to compute the energy released in a nuclear reaction.

Remember that 1 eV is the amount of kinetic energy that an electron or proton gains when a 1 volt potential difference acts upon them. E = QV is the equation for energy when considering charge and potential difference. Hence, 1 eV equals (1.6 x 10-19 coulombs)/(1 volt) = 1.6 x 10-19 Joules.

When comparing the reactant's starting mass to the products' final mass, which is 6.32 x 10 -27 kg, the mass difference is:

Δm = final mass - initial mass

Δm = 6.32×10⁻²⁷kg - 6.30x10⁻²⁷kg

Δm = 2x10⁻²⁹kg

Using the equation E=mc², we have:

E = Δm * c²

E = 2x10⁻²⁹kg * (3.0x10⁸m/s)²

E = 1.8x10⁻¹²J

We can use the conversion factor to express the energy released in terms of electronvolts (eV): 1 eV = 1.6x10⁻¹⁹J:

E(eV) = E / (1.6x10⁻¹⁹J/eV)

E(eV) = 1.8x10⁻¹²J / (1.6x10⁻¹⁹J/eV)

E(eV) = 11.25 meV

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Answer:

a = 2.22 [m/s^2]

Explanation:

First we have to convert from kilometers per hour to meters per second

\(40 [\frac{km}{h}]*[\frac{1h}{3600s}]*[\frac{1000m}{1km}] = 11.11 [m/s]\)

We have to use the following kinematics equation:

\(v_{f}= v_{i}+(a*t)\)

where:

Vf = final velocity = 11.11 [m/s]

Vi = initial velocity = 0

a = acceleration [m/s^2]

t = time = 5 [s]

The initial speed is taken as zero, as the car starts from zero.

11.11 = 0 + (a*5)

a = 2.22 [m/s^2]

Refer to the attachment.

Answer:

The change in the mass of box = 0.01 kg

Volume of air in the polythene bag = Volume of air in the rigid box

Therefore, Volume of air in the box = 0.008 m^3

Now, Density = Mass/ Volume

=> Density = 0.01 / 0.008 = 1.25 Kg / m^3

Explanation:

I looked it up

\(\huge{ \mathfrak{ \underline{question : }}}\)

A body weighing 250 grams was dropped from a helicopter flying at an altitude of 100 meters. Determine the potential energy of this body.

\( \huge{ \mathfrak{given : }}\)

\(\huge{ \mathfrak{ \underline{ Answer \: \: ✓ }}}\)

\( \boxed{ \mathbf{potential \: \: energy = mgh}}\)

potential energy = 250 joules

\( \#TeeNForeveR\)

Answer:

therefore, the correct answer is Option D.

Explanation:

a. 4×2=8kgm/s

b. 0.15×10=1.5kgm/s

c. 1.6×10³×0.5=800kgm/s

d. 2×950=1900kgm/s.

hope this helps you

Answer:

Explanation:

Initial velocity is 18 m/s horizontal.

Time for the car to hit the ground.

t = √(2h/g) = √(2(60) / 9.8) = 3.5 s

The car will land 3.5(18) = 63 m from the base of the cliff.

Answer:

The answer is a fixed pulley

Answer:

h = 0.288m

Explanation:

Assume

\(v_1\) = Speed of Sue

\(v_2\) = Speed of Chris immediately after the push

Sue's KE = \(\frac{1}{2} mv_1\ ^2 = 26 v_1 \ ^2\)

now she swings this is converted into gravitation at PE of

mg n = 52 × 9.8 × 0.65  

= 331.24

\(26v_{1}\ ^2\) = 331.24

So, \(v_1 = 3.569\)

They started at rest by conservation of momentum in case of push off the magnitude of sue momentum and it is equal to the magnitude of Chris momentum in the opposite or inverse direction

\(m_1v_1 = m_2v_2\)

\(52 \times 3.569 = 78 \times v_2\)

\(v_2 = 2.380\)

Chris kt = \(\frac{1}{2} \times 78 \times 2.380^2\)

= 220.827

220.827 = mgh

So, h = 0.288m

The pressure in the hot can will be 27756 mmHg.

The spray can is used until empty and only the propellent gas is left.

The pressure of the gas is 1344 mmHg and the temperature is 23° C.

The can is thrown into the fire of temperature 475° C. The volume of the gas is constant.

Now, we can write the relation,

P₁/T₁ = P₂/T₂

P₁ and T₁ are initial pressure and temperature while P₂ and T₂ are initial pressure and temperature

Now, putting values,

1344/23 = P₂/475

P₂ = 27756 mmHg.

So, the new pressure in the hot can will be 27756 mmHg.

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Answer:

(a) the magnitude of the vector sum of the two club head forces acting on the golf ball is 3041.38 N

(b) the direction of this resultant force is 10.5° to the horizontal

Explanation:

Please find the attached document for explanation

Answer:

Explanation:

The change in potential is then defined as the negative of the work done by that force. ... You can't have work done by gravity AND a change in gravitational potential energy. You have to do it one way or the other. This means that the most important step in solving work-energy problems is choosing a system.

the phenomenon is An object that has potential energy can transfer that energy into kinetic energy when the object begins to move, due to its mass or position. For example, a person jumping on a trampoline has potential energy when they reach the peak of a jump, and their force changes direction from upward to downward.

The constant acceleration of the train is 50/9 m/s².

The two balls will collide at a height of approximately 10.204 meters above the ground.

Using the kinematic equations of motion, we have:

distance = initial velocity * time + 1/2 * acceleration * time^2

For the first phase of acceleration, the initial velocity is zero, the time is 5 minutes = 300 seconds, and the distance traveled is unknown. So we have:

d1 = 0 + 1/2 * a * (300)^2

For the second phase of constant speed, the initial velocity is v, the time is 5 minutes = 300 seconds, and the distance traveled is also unknown. So we have:

d2 = v * 300

For the third phase of deceleration, the initial velocity is v, the time is also 5 minutes = 300 seconds, and the distance traveled is again unknown. So we have:

d3 = v * 300 + 1/2 * (-a) * (300)^2

The total distance traveled is the sum of these three distances:

distance = d1 + d2 + d3 = 1/2 * a * (300)^2 + v * 600 - 1/2 * a * (300)^2 = v * 600

Since the total distance traveled is given as 10 km = 10000 m, we have:

v * 600 = 10000

Solving for v, we get:

v = 10000/600 = 50/3 m/s

Now we can use the second equation above to find a:

d2 = v * 300 = (50/3) * 300 = 5000 m

Therefore, the constant acceleration of the train is:

a = 2 * (5000 - 1/2 * a * (300)^2) / (300)^2 = 50/9 m/s^2

The constant acceleration of the train is 50/9 m/s^2.

Problem 2: The height of the first ball dropped is given as 10m. Let's assume the height of the collision point is h meters above the ground.

Using the kinematic equation for free fall, we have:

h = 10 + 1/2 * g * t^2

where g is the acceleration due to gravity, which is approximately 9.81 m/s^2, and t is the time it takes for the second ball to reach the collision point after being thrown upwards.

The initial upward velocity of the second ball is 10 m/s, and we know that at the collision point, its velocity will be zero, since it will have reached its maximum height and will be momentarily at rest before falling back down.

Using the kinematic equation for motion with constant acceleration, we have:

0 = 10 + (-g) * t

Solving for t, we get:

t = 10/g = 10/9.81 seconds

Substituting this value of t into the first equation, we get:

h = 10 + 1/2 * 9.81 * (10/9.81)^2

Simplifying, we get:

h = 10.204 m

The two balls will collide at a height of approximately 10.204 meters above the ground.

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Answer:

If the present earth is squeezed to the size of moon, the acceleration due to gravity will be increased by about 14 times since, acceleration due to gravity is inversely proportional to the square of radius if mass is constant.

The speed of the car just after the gravel is loaded is 2.8m/s.

An isolated system experiences a change in momentum to zero when the starting and final velocities are equal. The reactions between the particles are separated from the surroundings. Momentum is conserved, so we use the rule of conservation of momentum, which is expressed by the equation

   \(P_{f}\)=\(P_{i}\)(1)

Railway is frictionless due to isolated mechanism. The thing travels at a momentum p-based speed while having mass. m

An object's bulk and velocity v are combined to form a vector.Equation of the form gives the velocity.

\(p=mv\)

Using expression p into equation (1)

\(m_{f}v_{f}\)=\(m_{i}v_{i}\)(2)

The final mass of a car is its original mass plus the mass of the gravel added. A car has an initial mass of.10000Kg  preliminary pace is

\(m_{f}\)=10000Kg+4000Kg=14000Kg

initial speed 4m/s

the final speed should be found after solving the equation(2) for \(v_{f}\)

\(v_{f}\)=\(\frac{m_{i}v_{i} }{m_f} }\)=\(\frac{10000Kg(4m/s)}{1400Kg}\)=2.8m/s

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Explanation:

Introduction to the quantum mechanical model of the atom: Thinking about electrons as probabilistic matter waves using the de Broglie wavelength, the Schrödinger equation, and the Heisenberg uncertainty principle. Electron spin and the Stern-Gerlach experiment. 

Answer:

Explanation:

the lowest points of a transverse wave are called the troughs what is the wavelength of a wave traveling through a rope if the distance from one crest to the next is 1 meter a. 2 m

4. Low points are called troughs

5. Medium: substance through which a wave can travel

Answer:

A game of darts is inelastic because the dart and board touch but don't bounce off. All the other options have two objects interacting then parting from eachother

Explanation:

Hope this helps, have a great day! :)

The speed of the roller coaster at the bottom of the hill if the track was frictionless is 34.04 m/s.

Given that the weight of the roller coaster is 2000 kg and the initial vertical drop of the ride is 59.3 m. We are to find the speed of the roller coaster at the bottom of the hill if the track was frictionless.We know that the roller coaster will lose potential energy due to the vertical drop. Assuming there is no friction, the potential energy will be converted into kinetic energy at the bottom of the hill.Considering the conservation of energy between the potential and kinetic energy, we can set the initial potential energy equal to the final kinetic energy. We can use the formula to calculate potential energy, which is PE = mgh where m = 2000 kg, g = 9.8 m/s², and h = 59.3 m. Therefore,PE = 2000 kg × 9.8 m/s² × 59.3 m = 1,157,924 JWe can use the formula to calculate kinetic energy, which is KE = 1/2mv² where m = 2000 kg and v is the final velocity. Therefore,KE = 1/2 × 2000 kg × v².The total energy remains constant as we know there is no friction. Therefore the final kinetic energy will be equal to the initial potential energy,1,157,924 J = 1/2 × 2000 kg × v²v² = (2 × 1,157,924 J) / 2000 kgv² = 1157.924v = √1157.924v = 34.04 m/s.

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