A car goes from 20 m/s to 70 m/s in 4 seconds, what is its acceleration?

Atom A has 10 protons, 12 neutrons, and 10 electrons, while Atom B has 10 protons, 10 neutrons, and 12 electrons.

Atom A and Atom B are not isotopes of each other. Isotopes are atoms of the same element that differ in the number of neutrons but have the same number of protons. In this case, Atom A and Atom B have different numbers of protons, which means they are not isotopes of each other.

The number of protons determines the element, and since Atom A and Atom B have different numbers of protons, they belong to different elements.

Isotopes, on the other hand, have the same number of protons but differ in the number of neutrons.

This variation in the number of neutrons gives isotopes different atomic masses while retaining the same chemical properties.

However, Atom A and Atom B do not fulfill this criterion, so they cannot be considered isotopes of each other.

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Answer:

A game of darts is inelastic because the dart and board touch but don't bounce off. All the other options have two objects interacting then parting from eachother

Explanation:

Hope this helps, have a great day! :)

Answer:

B

Explanation:

Answer:

Soil will loosen due to vast networks of underground tunnels.

The dynamic viscosity of oxygen at 40°C and 160 kPa is 64.17 × 10⁻⁶ Pa.s.

The dynamic viscosity of a fluid is equal to its kinematic viscosity multiplied by its density.

Given:

Kinematic viscosity of oxygen at 40°C and 160 kPa = 0.104 stokes

Density of oxygen at 40°C and 160 kPa = (160000 Pa / 0.2598 kPa.m³) = 616.55 kg/m³ (using ideal gas law)

Using the formula:

Dynamic viscosity = Kinematic viscosity * Density

We get:

Dynamic viscosity of oxygen = 0.104 stokes * 616.55 kg/m³ = 64.17 × 10⁻⁶ Pa.s

Therefore, the dynamic viscosity of the oxygen at 40°C and 160 kPa is 64.17 × 10⁻⁶ Pa.s.

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The normal force on the block of steel of mass 11.1Kg at constant speed is 108.8 N.

Mass of steel block = 11.1 Kg

Normal force on the block = Force exerted by the surface on the block

= mass × acceleration due to gravity

= m × g

Taking the value of g as 9.8 m/s

= 11.1 × 9.8

= 108.78 N

By converting the answer to one decimal place, round the value to

= 108.8 N

Thus, the normal force on the block of steel by the Teflon surface round to one decimal place is 108.8 N.

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Answer:

its the third one

Answer:

Explanation:

To find the resultant of two velocity vectors, we can use vector addition. Given two velocity vectors v1 and v2, their resultant vector vR can be found by adding the two vectors:

vR = v1 + v2

The angle that the resultant moves with the first vector can be found using trigonometry. If we let theta be the angle between v1 and vR, then we can use the following formula:

tan(theta) = (vR_y / vR_x)

where vR_x is the x-component of the resultant vector and vR_y is the y-component of the resultant vector.

Alternatively, we can use the dot product to find the angle between the two vectors. The dot product of two vectors is defined as:

v1 . v2 = |v1| |v2| cos(theta)

where |v1| and |v2| are the magnitudes of the vectors and theta is the angle between them. Solving for theta, we get:

theta = acos((v1 . v2) / (|v1| |v2|))

where acos is the inverse cosine function.

To summarize:

Find the resultant vector vR by adding the two velocity vectors v1 and v2: vR = v1 + v2

Find the angle theta between v1 and vR using either the tangent formula or the dot product formula:

a. tan(theta) = (vR_y / vR_x)

b. theta = acos((v1 . v2) / (|v1| |v2|))

Taking half of the given length and pulling it to a length of 2L as before, the frequency obtained by vibrating in the basic method is 6fo. option(ii)

When a bow vibrates in its fundamental mode with a length of 2L, the frequency is denoted as f. Now, let's consider the scenario where half of the given length (L) is pulled to a length of 2L.

In the fundamental mode of vibration, the frequency is inversely proportional to the length of the vibrating object. Therefore, if the length of the bow is halved to L, the frequency would double to 2f.

When this new length of L is pulled to a length of 2L, we need to determine the frequency obtained in the fundamental mode.

Since the frequency is inversely proportional to the length, we can use the inverse relationship to find the new frequency.

If the original frequency was 2f at length 2L, when the length is reduced to L, the new frequency would be (2f)/(2L) = f/L.

Now, if this length of L is stretched to 2L again, the new frequency in the fundamental mode would be (f/L) * (2L) = 2f. option(ii)

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False. E=hf, where h is Planck's constant, c is the speed of light, f is the frequency, and is the wavelength; and E=hc/, where E is directly proportional to frequency and inversely proportional to wavelength.

With respect to the wavelength of the radiation, photon energy is inversely proportional.

Two formulas can be used to determine a photon's energy: E = h f is a formula that can be used if the photon's frequency is known. This equation, sometimes known as Planck's equation, was created by Max Planck.

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We are given –

As we know –

↠K.E = 1/2 mv ²

↠ 15.6 = 1/2 × 5.5 × v ²

↠15.6 = 2.75 v ²

↠2.75v ² =15.6

↠v ² = 5.67

↠v=√5.67

↠v = 2.381 m/s

The acceleration due to gravity (g) on Earth varies across different locations due to factors like latitude, altitude, and local geology. Despite these variations, a standardized average value of g is commonly used for practical purposes.

The value of acceleration due to gravity (g) does indeed vary from place to place on the surface of the Earth. This variation occurs due to several factors that influence the gravitational field strength experienced at different locations. The following factors contribute to the variation in the value of g:

1. Latitude: The Earth is not a perfect sphere but an oblate spheroid, flattened at the poles and bulging at the equator. As a result, the distance from the center of the Earth to the surface is slightly greater at the equator than at the poles. This variation in distance affects the gravitational force and results in a slightly lower value of g at the equator compared to the poles.

2. Altitude: The distance from the Earth's center to a specific location affects the gravitational pull experienced at that location. As altitude increases, moving away from the Earth's surface, the gravitational force decreases, leading to a lower value of g.

3. Local Geology: The distribution of mass within the Earth's crust can cause gravitational variations. Areas with denser materials, such as mountains or regions with underground mineral deposits, may experience slightly higher values of g due to the increased gravitational pull from the additional mass.

4. Topography: Variations in the shape and composition of the Earth's surface, such as variations in mountains, valleys, and ocean trenches, can cause local gravitational anomalies. These anomalies can result in slight variations in the value of g at different locations.

It is important to note that while the variation in g exists, it is relatively small and does not significantly impact daily activities. In most practical applications, a standard average value of g (approximately 9.8 m/s²) is used for simplicity and convenience.

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Answer:

C: Mass of body

Explanation:

Upthrust is defined as the upward force that a liquid will exert on a body floating atop it.

Now, Formula for upthrust is;

Upthrust = density of liquid × volume of the body × acceleration due to gravity.

From the formula, we can see that upthrust depends on density, volume and acceleration due to gravity.

Thus, looking at the options, the one that doesn't apply is mass of body.

A rock is thrown horizontally from a bridge with a velocity of 5 m/s and hits the water below in 2.2 seconds therefore the height of the bridge is 11m.

This is referred to as a scalar quantity that refers to "how much ground an object has covered" during its motion. Height on the other hand is the measurement of an item in the vertical direction,

We should also note that velocity = distance/time

Velocity = 5m/s

time = 2.2s

Therefore 5m/s = d/2.2s

d = 5m/s × 2.2s = 11m

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Diameter = 4200 m

T = 24700 \(\pi\) time for A to also catch B

N = 1.39 \(*\) 24700 \(\pi\) / (4200 \(\pi\)) = 8.2 laps

A will create 8 but not 9 rounds before catching B.

Speed exists distance travelled per unit time. It exists scalar quantity.

Given: diameter = 4200 m

\(V_a\) = 5000 m / 3600 s = 1.39 m/s

(\(V_a - V_b\)) 60 = 10

\(V_b = V_a\) - 0.167 = 1.22 m/s

(\(V_a - V_b\)) T = 4200 \(\pi\)

where T exists time for A to complete 1 more lap

0.17 T = 4200 \(\pi\)

T = 24700 \(\pi\) time for A to also catch B

N = 1.39 \(*\) 24700

\(V_a\) = 5000 m / 3600 s = 1.39 m/s

(\(V_a - V_b\)) 60 = 10

\(V_b = V_a\) - 0.167 = 1.22 m/s

(\(V_a - V_b\)) T = 4200 \(\pi\)  

where T exists time for A to complete 1 more lap

0.17 T = 4200 \(\pi\)

T = 24700 \(\pi\) time for A to also catch B

N = 1.39 \(*\) 24700 \(\pi\) / (4200 \(\pi\)) = 8.2 laps

A will create 8 but not 9 rounds before catching B.

Therefore, the correct answer is option (ii) 8.

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Answer:

343.4 N    ( 340 N if using two significant digits)

Explanation:

If you are just asking for the normal force for a mass on flat, 0° surface

  normal force =   mg =   35 * 9.81 = 343.4 N

A scientific theory is a well-tested and widely accepted view that best explains certain scientific observations.

A scientific theory is a comprehensive and coherent explanation of a set of phenomena based on empirical evidence. It is not just a guess or speculation, but rather a well-supported and well-tested explanation that has been subjected to rigorous testing and scrutiny by the scientific community. Scientific theories are supported by a large body of evidence, and they can be used to make predictions and guide further research.

Scientific theories are an important part of the scientific method, which is a systematic approach to gaining knowledge and understanding about the natural world. Theories play a critical role in helping scientists make sense of their observations and in developing new ideas and hypotheses.

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ANSWER: 234.4 m and 2.5 seconds

EXPLANATION:

1. List what we have.

\(v_f = 72 km/h=20 m/s\)

\(v_i = 54 km/h = 15 m/s\)

\(a = 2 m/s^2\)

2. Find time first.

\(t = \frac{v_f - v_i}{a}\)

\(t = \frac{20 - 15}{2}\)  

\(t= 2.5\) seconds

2. Then find the distance.

\(s = v_i t \frac{1}{2} a t^2\)

\(s = (15)(2.5)\frac{1}{2} (2)(2.5)^2\)

\(s = 234.4\) m

btw, I'm not good at physics AT ALL so this is just me guessing and trying to help

Answer:

128

Explanation:

Answer:

54 degrees

Explanation:

Answer:

Role of government in regulating production

Explanation:

The role of government in regulating show , provides the legal and social framework, uphold competition, provides public goods and services.

The community's role in conserving and enhancing common-property resources is well known.

In extra, its role in helping market growth by its power to execute trade agreements among transacting parties belonging to the community network is stressed.

Thus, it provides the legal and social framework, maintains competition, and provides public goods and services.

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The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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Explanation:

The tangential speed of Andrea is given by :

\(v=r\omega\)

Where

r is radius of the circular path

ω is angular speed

The merry-go-round is rotating at a constant angular speed. Let the new distance from the center of the circular platform is r'

r' = 2r

New angular speed,

\(v'=r'\omega'\\\\v'=(2r)\omega\\\\v'=2r\omega\\\\v'=2v\)

New angular speed is twice that of the Chuck's speed.

In order to determine which of the two solutions of salt water is more concentrated, we need to first understand what concentration means and how it is measured. Concentration refers to the amount of solute dissolved in a given amount of solvent. It is typically measured in units of mass per volume, such as grams per liter (g/L) or milligrams per milliliter (mg/mL). so The second solution is more concentrated

When comparing the concentration of two solutions, the one with a higher concentration has more solute dissolved in the same amount of solvent. Therefore, in the picture provided, we can determine which solution is more concentrated by looking at the relative amounts of solute in each solution.If the solutions have the same concentration, then they must have the same amount of solute dissolved in the same amount of solvent. From the picture, we can see that both solutions are in the same size container and have the same amount of solvent (water) in them. Therefore, we can conclude that they have the same concentration of salt.The amount of solute dissolved in a solution can be increased by either adding more solute or by reducing the amount of solvent. If we were to add more salt to one of the solutions, we would increase the concentration of that solution. Alternatively, if we were to evaporate some of the water from one of the solutions, we would reduce the amount of solvent and increase the concentration of that solution.

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The waveform of a signal is the shape of its graph as a function of time in the domains of electronics, acoustics, and allied sciences, regardless of its time and magnitude scales or any shift in time.  

Thus, Waveforms with periodic variations are those that recur consistently at set intervals.

The phrase is typically used in electronics to describe periodically changing voltages, currents, or electromagnetic fields. It is typically used in acoustics to describe constant periodic sounds caused by changes in air pressure or other media.

In these situations, the signal's frequency, amplitude, or phase shift have no bearing on the waveform, which is a characteristic. Additionally, non-periodic signals like chirps and pulses can be referred to by this name.

Thus, The waveform of a signal is the shape of its graph as a function of time in the domains of electronics, acoustics, and allied sciences, regardless of its time and magnitude scales or any shift in time.  

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The tangential acceleration of the short player's ball is twice the tangential acceleration of the tall player's ball.

The ball of the shorter player experiences twofold of the ball of the taller player's tangential acceleration. The reason behind this is that the magnitude of the tangential acceleration correlates directly with the radius of the circle.

The ball belonging to the smaller player is positioned nearer to the elbow, resulting in a decreased radius. It can be deduced from this statement that the ball of the short player experiences twice the magnitude of tangential acceleration compared to the ball of the tall player.

The answer is: ashort = 2atall

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The Complete Question

A short tennis player hits a ball that is r meters from their elbow with an angular acceleration a. A tall tennis player hits a ball with the same angular acceleration where the ball is 2r from their elbow. How does the tangential acceleration of the short player's ball Ashort compare with the tall player's ball a tall? Choose 1 answer: ashort 2atall ashort Otall ashort 1 atall 2

The  acceleration, tension of the cord between the 3.5 and 1 block, and the force excreted on the 2 block from the 1 block is 12.6 N.

To solve this problem, we need to apply Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

We can start by finding the acceleration of the system. Since the surface is frictionless, there are no horizontal forces acting on the blocks except for the tension in the string. Thus, we can write:

F - T = (m1 + m2 + m3) * a

where F is the force acting on the 3.5 kg block, T is the tension in the string between the 3.5 kg and 1 kg blocks, and a is the acceleration of the system. Substituting the values given in the problem, we get:

46 N - T = (1 kg + 2 kg + 3.5 kg) * a

46 N - T = 6.5 kg * a

Next, we need to find the tension in the string between the 3.5 kg and 1 kg blocks. This tension is the same throughout the string, so we can use the same equation we used to find the acceleration:

T - m1 * g = m1 * a

where g is the acceleration due to gravity (9.8 m/s^2). Substituting the values given in the problem, we get:

T - 1 kg * 9.8 m/s^2 = 1 kg * a

T = 1 kg * (a + 9.8 m/s^2)

Now, we can substitute this expression for T into the first equation we derived to get:

46 N - 1 kg * (a + 9.8 m/s^2) = 6.5 kg * a

Simplifying and solving for a, we get:

a = 2.84 m/s^2

Now that we know the acceleration of the system, we can find the force exerted by the 1 kg block on the 2 kg block. Since there are no horizontal forces acting on the 2 kg block, this force is equal in magnitude and opposite in direction to the force exerted by the 2 kg block on the 1 kg block. Thus, we can write:

F1-2 = -m2 * a

where F1-2 is the force exerted by the 1 kg block on the 2 kg block. Substituting the values given in the problem, we get:

F1-2 = -2 kg * 2.84 m/s^2

F1-2 = -5.68 N

Therefore, the force exerted by the 1 kg block on the 2 kg block is 5.68 N, directed to the left.

Finally, we can use the equation we derived earlier for the tension in the string to find the tension between the 3.5 kg and 1 kg blocks. Substituting the value we found for a, we get:

T = 1 kg * (2.84 m/s^2 + 9.8 m/s^2)

T = 12.6 N

Therefore, the tension in the string between the 3.5 kg and 1 kg blocks is 12.6 N.

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Doppler ultrasound would be most useful in detecting a blockage in a heart artery.

By monitoring the rate of change in pitch, a Doppler ultrasound may calculate how quickly blood flows (frequency). A sonographer with training in ultrasound imaging applies pressure to your skin with a tiny, hand-held instrument (transducer) roughly the size of a bar of soap across the area of your body being scanned, moving from one place to another as required.

As an alternative to more invasive treatments like angiography, which involves injecting dye into the blood arteries to make them visible on X-ray images, this test may be performed.

Your doctor may use a Doppler ultrasound to assess for artery damage or to keep track of specific vein and artery therapies.

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The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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It would take approximately 1.33 x 10^8 seconds (or about 42 years) for a light signal from Earth to reach Proxima Centauri. For a spacecraft traveling at 0.0001c, it would also take about 42 years to reach Proxima Centauri.

To calculate the time it takes for a light signal to travel from Earth to Proxima Centauri, we can use the formula:

Time = Distance / Speed

Given:Distance to Proxima Centauri = 4.0 x 10^13 km (convert to meters by multiplying by 10^3, as 1 km = 10^3 m)

Speed of light (c) = 3 x 10^8 m/s

Converting the distance to meters:

Distance = 4.0 x 10^13 km * 10^3 = 4.0 x 10^16 m

Using the formula, we can calculate the time it takes for the light signal to travel:

Time = Distance / Speed = (4.0 x 10^16 m) / (3 x 10^8 m/s)

Time ≈ 1.33 x 10^8 seconds

To calculate the number of years it would take for a spacecraft traveling at a speed of 0.0001c to reach Proxima Centauri, we need to divide the distance by the speed of the spacecraft.

Speed of spacecraft (v) = 0.0001c = 0.0001 * 3 x 10^8 m/s = 3 x 10^4 m/s

Time = Distance / Speed = (4.0 x 10^16 m) / (3 x 10^4 m/s)Time ≈ 1.33 x 10^12 seconds

To convert seconds to years, divide the time by the number of seconds in a year:

Number of years ≈ (1.33 x 10^12 seconds) / (3.1536 x 10^7 seconds/year)

Number of years ≈ 42 years

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