A BS 88 Part 2 fuse can safely clear short-circuit faults up to 80 kA. a) True b) False

Answer:

\(\fbox {3.6kW}\)

Explanation:

Formula used :

\(\boxed {P = F \times v} \leftarrow \rightarrow \boxed {P = \frac{F \times S}{t}}\)

Given :

⇒ F = 6 × 10³ N

⇒ S = 18 m

⇒ t = 30 s

Solving :

⇒ P = 6 × 10³ × 18 / 30

⇒ P = 2 × 100 × 18

⇒ P = 3600 W

⇒ P = 3.6kW

Answer:

ok

Explanation:

Acceleration is defined as the rate of change of velocity.

Acceleration = (Change in velocity) / time taken

Acceleration = (Final velocity - initial velocity) / time

As the object velocity changes by the same amount in each second, it means the acceleration is constant.

The apparent path of the Sun, relative to the stars on the celestial sphere, over the course of a year. It is the orbit of the earth extended to the celestial sphere is called ecliptic.

The celestial sphere is an imaginary sphere that surrounds the Earth, used by astronomers to describe the positions and movements of celestial objects such as stars, planets, and galaxies. The concept of the celestial sphere was introduced by ancient Greek astronomers, who believed that the stars were fixed on a giant sphere that surrounded the Earth.

This sphere was thought to rotate around the Earth, creating the illusion of the stars moving across the sky. The celestial sphere is divided into 88 constellations, each containing stars that are visible from Earth. The celestial sphere has several important reference points, such as the celestial equator, which is the projection of Earth's equator onto the sphere, and the ecliptic, which is the path of the Sun across the sky throughout the year.

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The slip at maximum torque is 0.0141,  the input current at maximum torque is 2.819 A, and the power factor at maximum torque is 0.9992, the maximum torque is 229.4 Nm and the resistance that must be added is 0.0031 ohm.

To calculate the values requested for the given motor, we will use the following formulas:

(a) Slip at maximum torque:

The slip at maximum torque can be calculated using the formula:

Slip at maximum torque (s_max) = (R1 + R'2) / (sqrt(R1^2 + (Xeq + Xm)^2))

Given:

R1 = 0.225 ohm

R'2 = 0.235 ohm

Xeq = 1.43 ohm

Xm = 31.8 ohm

Substituting the values into the formula, we get:

s_max = (0.225 + 0.235) / sqrt(0.225^2 + (1.43 + 31.8)^2)

     = 0.46 / sqrt(0.050625 + 1030.4929)

     ≈ 0.0141

Therefore, the slip at maximum torque is approximately 0.0141.

(b) Input current and power factor at maximum torque:

To calculate the input current and power factor at maximum torque, we need to use the concept of the Thevenin equivalent circuit.

Thevenin equivalent parameters:

Vth = 2200 V

Rth = (R1 || R'2) + Rm

Zth = Rth + jXeq

Where "||" denotes parallel resistance.

First, let's calculate Rth:

Rth = (R1 || R'2) + Rm

    = (0.225 * 0.235) / (0.225 + 0.235) + 780

    ≈ 779.8 ohm

Now, let's calculate Zth:

Zth = Rth + jXeq

    = 779.8 + j1.43

    ≈ 779.8 + j1.43 ohm

The input current (Iin) can be calculated as:

Iin = Vth / |Zth|

    = 2200 / |779.8 + j1.43|

    ≈ 2200 / 779.9

    ≈ 2.819 A

The power factor (PF) can be calculated as the cosine of the angle of Zth:

PF = cos(angle(Zth))

  = cos(arctan(1.43 / 779.8))

  ≈ 0.9992

Therefore, the input current at maximum torque is approximately 2.819 A, and the power factor at maximum torque is approximately 0.9992.

(c) Maximum torque:

The maximum torque (T_max) can be calculated using the formula:

T_max = (3 * Vth^2 * R'2) / (ωs_max * (Rth + R'2)^2)

Where ω is the angular frequency (2πf) and f is the frequency.

Given:

Vth = 2200 V

R'2 = 0.235 ohm

Rth = 779.8 ohm

s_max = 0.0141

f = 60 Hz

Substituting the values into the formula, we get:

T_max = (3 * 2200^2 * 0.235) / (2π * 60 * 0.0141 * (779.8 + 0.235)^2)

      ≈ 229.4 Nm

Therefore, the maximum torque is approximately 229.4 Nm.

(d) To achieve maximum torque at starting, the rotor resistance (R'2) needs to be increased. The additional resistance required (R_add) can be calculated using the formula:

R_add = (s_max * R1) / (1 - s_max)

where s_max is the slip at maximum torque.

Given:

R1 = 0.225 ohm

s_max = 0.0141

Substituting the values into the formula, we get:

R_add = (0.0141 * 0.225) / (1 - 0.0141)

      ≈ 0.0031 ohm

Therefore, the resistance that must be added to the rotor windings (per phase) to achieve maximum torque at starting is approximately 0.0031 ohm.

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Answer: Hot

Explanation: Scientist use the color of starts to determine how hot the surface temperature is.

2.97×10^6 m  is the total distance traveled (in m) by a point 9.00 cm from the axis of rotation of the ultracentrifuge.

\(\theta=\)3.29×10^7 rad

r= 9cm= 0.09 m

distance = \(\theta \cdot r\)

distance =3.29×10^7 rad×0.09 m

distance =2.97×10^6

Distance is the length between two locations or things, independent of direction. Since distance is a scalar property, it only takes into consideration the total magnitude and ignores the start and finish positions. Since distance is a scalar attribute, it can only have a positive or zero value; it cannot have a negative value.

The most common unit of measurement for distance is the meter (m), while larger distances can also be stated in kilometers (km), while smaller distances can be expressed in centimeters (cm) or millimeters (mm). When calculating distance, the letter D is often used to represent the distance traveled.

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Answer: 80 mph

Explanation:

Answer:

2)Innate, or nonspecific, immunity is the defense system with which you were born. It protects you against all antigens. Innate immunity involves barriers that keep harmful materials from entering your body. These barriers form the first line of defense in the immune response.

3)The first line of defence (or outside defence system) includes physical and chemical barriers that are always ready and prepared to defend the body from infection. These include your skin, tears, mucus, cilia, stomach acid, urine flow, 'friendly' bacteria and white blood cells called neutrophils.

4)The second line of defense is nonspecific resistance that destroys invaders in a generalized way without targeting specific individuals: Phagocytic cells ingest and destroy all microbes that pass into body tissues. For example macrophages are cells derived from monocytes (a type of white blood cell).

5)The adaptive defense consists of antibodies and lymphocytes, often called the humoral response and the cell mediated response. The term 'adaptive' refers to the differentiation of self from non-self, and the tailoring of the response to the particular foreign invader.

6)Innate immunity is comprised of different components including physical barriers (tight junctions in the skin, epithelial and mucous membrane surfaces, mucus itself); anatomical barriers; epithelial and phagocytic cell enzymes (i.e., lysozyme), phagocytes (i.e., neutrophils, monocytes, macrophages), inflammation- .

8)Types of phagocytes

In humans, and in vertebrates generally, the most-effective phagocytic cells are two kinds of white blood cells: the macrophages (large phagocytic cells) and the neutrophils (a type of granulocyte)

Answer:

The force of gravity causes the raindrops to accelerate.

We know that all the objects within the neighborhood of the Earth are attracted due to Earth's gravitation.

We will see that the correct option is:

"The force of gravity causes the raindrops to accelerate."

Now, let's talk a little bit about raindrops.

As clouds face a cold front, the gas phase may return to liquid phase, in this process the density of the water increases, thus the amount of mass per unit of volume increases, and as the water is denser than air, the raindrop falls down.

Why it falls down?

Due to gravitational force.

Remember second Newton's law:

F = m*a

Force equals mass times acceleration.

Thus, if we have a force, we also have an aceleration. So the relation between gravity and raindrops is that gravity is the thing that accelerates the rain drops, and this is why the rain drops fall down.

The correct option is the last one:

"The force of gravity causes the raindrops to accelerate."

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The skydiver is moving at a speed of 30.0 m/s, downward acceleration is 6.27 m/s2. At a speed of 50.0 m/s, the diver experiences an upward-directed of 784 N. the diver's drag force at 30.0 m/s283N speed

Acceleration is the general term for anything that alters velocity. Since velocity depends on both speed and direction, there are only two ways to accelerate: by either changing your speed and your direction, or both.

Acceleration. Velocity is used to express the displacement change. Acceleration is the term for the rate of change on velocity. Considering it has also a magnitude and a direction, the quantity v is the velocity. Acceleration is a vector quantity since it is just the rate at which velocity changes.

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The work done by the gravitational force is given by:Wg = mgl sinθ.The net work done by all forces is given by:Wnet = Wg - W= mgl sinθ - ∫(3/2) µmg cosθ - (1/2) mg sinθ ds.Wnet = mgl sinθ - [(3/2) µmg cosθ + (1/2) mg sinθ] s.The minus sign in the integral comes from the fact that the frictional force is opposite to the displacement direction.

A ring of mass m and radius r is released on an inclined plane as shown in the figure. If the coefficient of friction is µ = tanθ, then find the following (see diagram below):a) During a displacement 1, the acceleration of the ring.b) During a displacement 2, the acceleration of the ring, µg case.c) The work done by the force of friction, mgl sinθ µcosθ.a) For displacement 1:By using Newton's second law, F = ma where F is the net force acting on the ring and a is the acceleration of the ring, we get:1.

The component of the weight force acting on the inclined plane:mg sinθ down the plane.2. The normal force N is perpendicular to the plane.3.

The frictional force f opposing the motion.4. The tangential force T causes the ring to roll without slipping.We can see that T is the only force that causes the ring to roll down the incline. Thus, we use torque equation:T = Iα, where T is the tangential force, I is the moment of inertia of the ring, and α is the angular acceleration of the ring. Since the ring is rolling without slipping, we can relate a and α through the equation:a = rα.Substituting this into the torque equation, we get:T = Ia/r.For a solid ring, I = 1/2mr². Thus,T = ma/2.Using the conditions of motion for rolling without slipping, we get:T - f = ma/2. (1)The direction of the frictional force f is up the plane, i.e. opposite to the motion of the ring. Thus,f = µN = µmg cosθ.The direction of the tangential force T is down the plane, i.e. in the direction of motion of the ring. Thus,T = mg sinθ.

The direction of the acceleration a is down the plane, i.e. in the direction of motion of the ring. Thus,a = g sinθ.Substituting these into equation (1), we get:mg sinθ - µmg cosθ = ma/2. (2)Thus, the acceleration of the ring during displacement 1 is given by:a = 2g sinθ/3.b) For displacement 2:By the same reasoning as in (a), the net force acting on the ring is given by:f = mg sinθ - µmg cosθ - ma/2.The direction of the frictional force f is up the plane, i.e. opposite to the motion of the ring. Thus,f = µN = µmg cosθ.The direction of the tangential force T is down the plane, i.e. in the direction of motion of the ring. Thus,T = mg sinθ.

The direction of the acceleration a is down the plane, i.e. in the direction of motion of the ring. Thus,a = g sinθ - µg cosθ.Substituting these into the equation for the net force, we get:f = mg sinθ - µmg cosθ - m(g sinθ - µg cosθ)/2f = (3/2) µmg cosθ - (1/2) mg sinθ.(3)Thus, the acceleration of the ring during displacement 2 is given by:a = (3/2)g µ sinθ.(4)c) The work done by the force of friction:During the displacement 1, the force of friction does no work since it is perpendicular to the displacement direction.During the displacement 2, the work done by the force of friction is given by:W = ∫f ds = ∫(3/2) µmg cosθ - (1/2) mg sinθ dswhere s is the displacement distance along the plane.

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Answer:

traping

Explanation:

Answer:

B. Trapping

Explanation:

The statement"Mental and emotional health can be improved through exercise." is a true statement

Option A is correct

Exercise is simply defined as the act of putting patience into practice, action, or practice. Regular physical activity can help you strengthen your muscles and increase your endurance.

In conclusion, Mental and emotional health can be improved through exercise.

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Answer:   True.           Exercise is not only good for physical health but also mental and emotional health. It helps in reducing stress, anxiety, depression, and boosting self-esteem, cognitive function, and overall mood. Regular exercise can lead to the release of endorphins that promote feelings of happiness and well-being. Hence, mental and emotional health can be improved through exercise.

Explanation:

i took the test

Answer:

Explanation:

Since work = magnitude of the force times the displacement, then

W = 43.0(5.00) so

W = 215 N*m

To solve this, we must be knowing each and every concept related to fundamental force. Therefore,  215 Nm is the work done on a bookshelf being pulled 5.00 m at an angle of 37.0° from the horizontal.

Nature is governed by four fundamental or universal forces. All stuff in the universe would disintegrate in the absence of these forces. Any pull or push that causes an item to change its physical condition is referred to as force (in terms of motion or deformity).

Mathematically, the formula for work can be given as

work = force × displacement× cos(Θ)

W = F × D × cos(Θ)

force= 43.0 N

Θ=37.0°

displacement=5.00 m

substituting all the given values in the above equation, we get

W =  43.0  × 5.00  × cos(37.0°)

W = 215 Nm

Therefore,  215 Nm is the work done on a bookshelf being pulled 5.00 m at an angle of 37.0° from the horizontal.

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A 10 kg box is pulled across a level floor, where the coefficient of kinetic friction is 0.35. The horizontal force is required for an acceleration of 2.0 m/s2 will be 54.3 N

Newton’s second law states that the acceleration of an object depends upon two variables – the net force acting on the object and the mass of the object.  The acceleration of the body is directly proportional to the net force acting on the body and inversely proportional to the mass of the body.

equation of motion will be

F(net) =  mass * acceleration

F - fr = m * a

where

F = force by which the box is moving

fr = force due to friction

m = mass of the object

a = acceleration by the object is moving

F = fr + m * a

  = (mu * N) + ma                                          where N = mg

  = (mu * mg) + ma

  = (0.35 * 10 * 9.8) + 10 * 2

  = 54.3 N

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Answer:

Explanation:

According to snell's law the incident normal and refracted ray at the point of incidence all lie in the same plane

Given

incident angle i= 60°

refracted angle r= ?

index of refraction u= 1.53.

Applying the formula

\(u= \frac{sine (i)}{sine( r)}\)

solving for r

\(1.53=\frac{ sine (60)}{ sine( r)}\\\1.53= \frac{0.866}{ sine( r)} \\\ sine( r)= \frac{0.866}{1.53} \\\sine(r)= 0.566\\\r= sine^-0.566\\\r= 34.47\)

r= 34.47°

A charge of -1e would be present in an antibaryon made up of two antiup quarks and one anti-down quark. Option 2 is correct.

When the matter is put in an electromagnetic field, it has an electric charge, which causes it to experience a force. A positive or negative electric charge can exist.

The complete question is

"An antibaryon composed of two antiup quarks and one anti down quark would have a charge of

(1) +1e

(2) −1e

(3) 0e

(4) −3e"

An antibaryon composed of two antiup quarks and one anti-down quark would have a charge of  −1e.

Hence,option 2 is correct.

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The relationship between Cmax and Cmin is that **Cmax is equal to 2 times Cmin**.

The **largest possible equivalent capacitance** (Cmax) that can be made by combining two identical capacitors with capacitance C is obtained when the capacitors are connected in parallel.

When capacitors are connected in parallel, the total capacitance is equal to the sum of the individual capacitances. Therefore, Cmax = C + C = 2C.

On the other hand, the **smallest possible equivalent capacitance** (Cmin) is obtained when the capacitors are connected in series.

When capacitors are connected in series, the reciprocal of the total capacitance is equal to the sum of the reciprocals of the individual capacitances. Mathematically, 1/Cmin = 1/C + 1/C. Simplifying this expression gives 1/Cmin = 2/C. Taking the reciprocal of both sides yields Cmin = C/2.

Therefore, the relationship between Cmax and Cmin is that **Cmax is equal to 2 times Cmin**.

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Answer:

54,000

Explanation:

Answer:

It takes just a little bit over a year

Explanation:

Because Earth takes one year to orbit the Sun, So the Sun takes one year to make a complete circuit of the ecliptic. The Sun moves a little less than 1° eastward every day therefore it would be about 382 days (says scientist or less than that)

The center of gravity of Venus and Mars is not affected by specific features like the equatorial bulge. The center of gravity is a fundamental concept related to the overall mass distribution and gravitational forces within a celestial body.

The term "center of gravity" refers to the point in an object where the total weight is evenly distributed and the object can balance. In the context of the question, the term suggests that there is a specific object or feature that is found at the center of gravity of Venus but not Mars.

The answer to the question is the Venusian "central bulge" or "equatorial bulge." Venus is a planet that rotates on its axis, causing it to flatten slightly at the poles and bulge at the equator. This bulge creates an uneven distribution of mass, resulting in a different center of gravity compared to Mars.

The central bulge of Venus is caused by the planet's slow rotation and its thick atmosphere. The dense atmosphere exerts pressure on the planet's surface, contributing to the equatorial bulge. In contrast, Mars has a thinner atmosphere and a slower rotation, which does not result in a significant central bulge.

To summarize, the feature that is found at the center of gravity on Venus but not on Mars is the equatorial bulge or central bulge caused by Venus' rotation and atmosphere.

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The freezing point of the solution is - 3.53°C, when the concentration of the solute is 8.1 gm and water is 100gm.

The temperature at which a liquid turns into a solid under normal atmospheric pressure is known as the freezing point. A melting point, on the other hand, is the temperature at which a solid turns into a liquid at ordinary atmospheric pressure. The temperature at which solid and liquid phases coexist in equilibrium is a more precise definition of the freezing point. The temperature at which a substance melts (or freezes) at one atmosphere of pressure is known as the normal freezing point.

The amount of solute contained in a specific amount of solution is the substance's concentration. The number of moles of solute in 1 L of solution, or molarity, is used to express concentrations.

The concentration of Solute = 8.1gm and water = 100 gms, α = 0.9

We know that,

ΔTf = i(Kf)m

      = 1 + (n-1)α × 1.86 × 8.1/80 × 100/100

ΔTf = 1.91.861 = 3.53°C.

now, the freezing point of the solution = 0 - 3.53 = -3.53°C.

Hence, the freezing point of the solution is - 3.53°C, when the concentration of the solute is 8.1 gm and water is 100gm.

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The lower mass limit of 0.08 solar masses for main-sequence stars is due to the conditions required for nuclear fusion to occur. Nuclear fusion is the process in which hydrogen atoms combine to form helium, releasing energy in the process.

Main-sequence stars generate energy through the fusion of hydrogen into helium in their cores. This process, known as hydrogen burning, occurs when the temperature and pressure in the core are high enough to overcome the electrostatic repulsion between hydrogen nuclei.
Objects with a mass below 0.08 solar masses, known as brown dwarfs, do not have sufficient mass to create the necessary core conditions for hydrogen fusion. The gravitational pressure in the core of such an object is not strong enough to raise the temperature to the required level for fusion to begin. Consequently, these low-mass objects do not shine like main-sequence stars and are considered substellar.
In contrast, main-sequence stars with masses above 0.08 solar masses have enough gravitational pressure in their cores to sustain hydrogen fusion, which produces the energy that makes them visible as stars. This lower mass limit is essential in distinguishing main-sequence stars from substellar objects and understanding the different mechanisms by which these celestial bodies generate energy.

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Answer: B

Explanation: Yes it is b, because the lightbulb won’t matter just the circuit and flow of the cable.

A battery operating a large flashlight produces a current of 2 amperes in a light bulb that has a resistance of 4 ohms. The voltage of the battery is option c) 8 volts.

To determine the voltage of the battery, we can use Ohm's Law, which states that voltage (V) is equal to the product of current (I) and resistance (R), i.e.,

V = I × R.

In this case, the current is given as 2 amperes and the resistance is given as 4 ohms. Plugging these values into Ohm's Law, we have V = 2 A × 4 \(\Omega\) = 8 volts.

Therefore, the correct answer is c) 8 volts.

The voltage of a battery represents the electric potential difference it provides to the circuit. In this scenario, the battery is operating the flashlight, and the light bulb acts as the resistance in the circuit.

The current flowing through the bulb is determined by the battery's voltage and the resistance. With a current of 2 amperes and a resistance of 4 ohms, the voltage required to sustain this current is 8 volts.

It's important to note that the voltage of the battery is not solely dependent on the current or the resistance. It is the combination of these factors that determines the voltage required to drive the desired current through the circuit.

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↪Nucleons include protons and neutrons. All the positive charge of an atom is contained in the nucleus, and originates from the protons. Neutrons are neutrally-charged. Electrons, which are negatively-charged, are located outside of the nucleus.

☆...hope this helps...☆

_♡_mashi_♡_

The nucleus of an atom of any chemical element comprises three (3) distinct subatomic particles and these are:

An atom simply refers to the smallest, basic (fundamental) and indivisible unit which comprises the matter that forms all chemical elements.

Based on scientific information, the nucleus of an atom of any chemical element comprises three (3) distinct subatomic particles and these include the following;

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Answer:

Ans:

Explanation:

MA=L/E=500N/200N=5/2

VR=ED/LD=60cm/20cm=3

Thus, Efficiency=(Ma*100%)/VR=83.34%

Answer:

9.0 m/s/s

Explanation:

Given the following data;

Initial velocity = 10 m/s

Final velocity = 55 m/s

Time = 5 seconds

To find the average acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

\(Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}\)

Substituting into the equation;

\(a = \frac{55 - 10}{5}\)

\(a = \frac{45}{5}\)

Acceleration, a = 9.0 m/s²

Therefore, the average acceleration of the motorcycle is 9 meters per seconds square because it's experiencing a uniform velocity or motion.

Because different visible light colors have distinct wavelengths and barely varying refractive indices, the wavelength of the light influences the angle of refraction.

For instance, you cannot tell the difference when white light passes through a flat piece of glass because it is so slight.

The reflected beam will always be refracted at the same angle that it impacted the surface since light will then continue to go through the same medium and at the same speed.

A periodic wave's wavelength is its spatial period, or the length over which its shape repeats. It is a property of both travelling waves and standing waves as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two nearby crests, troughs, or zero crossings.

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