A boy with mass 25 kg climbs into a small tree. He sits on a branch that is 2.0 m above the ground. What is his gravitational potential energy with respect to the ground?

The current through a wire change if the wires resistance is increased in the following ways;

The relationship between resistance and the area of the cross section of a wire is inversely proportional. Resistance also depends on the material of the conductor.

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(a) The magnitude of the tangential acceleration of a point on the edge of the turntable is 0.290 m/s².

(b) The time it takes the turntable to come to rest is 48.3 s.

(c) The number of revolutions the turntable makes before stopping is 4.79 revolutions.

(d) The magnitude of the torque exerted on the turntable is 0.116 Nm.

(e) The magnitude of the frictional force is 0.116 N.

(f) The magnitude of the initial angular momentum of the turntable is 0.056 kg m²/s.

(a) The tangential acceleration can be calculated using the formula a = α × r, where α is the angular acceleration and r is the radius of the turntable. Given α = -0.580 rad/s² and r = 0.20 m (half of the diameter), we find a = 0.290 m/s².

(b) The time it takes for the turntable to come to rest can be determined using the equation vf = vi + at, where vf is the final velocity (zero in this case), vi is the initial velocity (28.0 rad/s), a is the acceleration (-0.580 rad/s²), and t is the time. Rearranging the equation, we have t = (vf - vi) / a = -28.0 rad/s / (-0.580 rad/s²) = 48.3 s.

(c) The number of revolutions the turntable makes before stopping can be found using the equation θ = ωi × t + 0.5 × α × t², where θ is the angle in radians, ωi is the initial angular velocity, t is the time, and α is the angular acceleration. Since ωi = 28.0 rad/s, α = -0.580 rad/s², and t = 48.3 s, we can calculate θ = 4.79 revolutions.

(d) The magnitude of the torque exerted on the turntable can be determined using the equation τ = I × α, where τ is the torque, I is the moment of inertia, and α is the angular acceleration. The moment of inertia for a disk rotating about its axis is given by I = (1/2) × m × r², where m is the mass of the disk and r is its radius. Substituting the given values, we find τ = 0.116 Nm.

(e) The magnitude of the frictional force can be calculated using the equation f = m × a, where f is the force, m is the mass, and a is the acceleration. Substituting the given values, we find f = 0.116 N.

(f) The magnitude of the initial angular momentum of the turntable can be calculated using the equation L = I × ω, where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity. Substituting the given values, we find L = 0.056 kg m²/s.

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The amount of charge that can be placed on a capacitor depends on the capacitance, which is determined by the area of each plate.

The capacitance of a capacitor is given by the formula:

C = ε0 * (A / d)

Where:

C is the capacitance,

ε0 is the permittivity of free space (a constant value),

A is the area of each plate,

d is the separation between the plates.

To determine the amount of charge, we can rearrange the formula as:

Q = C * V

Where:

Q is the amount of charge,

V is the voltage across the capacitor.

Given that the area of each plate is 7.3 cm², we can use this information to calculate the capacitance. However, the question does not provide the voltage or any other information required to calculate the amount of charge accurately. Without knowing the voltage or other relevant parameters, it is not possible to determine the exact amount of charge that can be placed on the capacitor.

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One may calculate the spreading rate on one side of a mid-ocean ridge by dividing the distance by the time (Distance/Time = Rate). This is known as a half-spreading rate. Multiply it by two to get the spreading rate in its entirety on both sides of the ridge.

It spreads 2 to 5 cm (8 to 2 inches) every year and forms an ocean trench about the size of the Grand Canyon. The East Pacific Rise, on the other hand, is a core that is quickly expanding. It spreads by around 6 to 16 cm per year (3-6 inches).

Seafloor spread occurs at mid-ocean ridges, where new oceanic crust is produced by volcanic activity and then gradually moves away from the ridge.

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Answer:B

Explanation:

Answer:

1.6 m/s²

Explanation:

Weight equals mass times acceleration due to gravity.

F = mg

14.4 N = (9 kg) g

g = 1.6 m/s²

You should give him the Brainliest.

Given the data from the question, the heat gained by the water, the rate of energy transfer and the initial temperature of the iron are:

A. The energy gained by the water is 37656 J

B. The average rate of energy transfer from

the iron sphere to the water is 125.52 J/s (Watts)

C. The initial temperature of the iron

sphere is 65.4° C

Q = MCΔT

Q = 3000 × 4.184 × 3

Q = 37656 J

Power = energy / time

Power = 37656 / 300

Power = 125.52 J/s (Watts)

Q = CT

37656 = 576 × T

Divide both side by 576

T = 37656 / 576

T = 65.4° C

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Answer:

I believe that the answer is B) False

Physical properties such as color, shape, size, weight, odor, melting point, boiling point, and density can be observed without destroying the substance.

Physical properties are characteristics of a substance that can be observed and measured without changing the substance's chemical composition. Examples of physical properties include color, density, hardness, melting point, boiling point, and electrical conductivity. These properties are determined through experiments and/or observations. Physical properties can be used to identify and classify a material. They can also be used to differentiate between different forms of the same material, such as different allotropes of the same element. Physical properties are also important for understanding how materials interact with each other and how they respond to the environment.

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The pieces of information which are necessary to describe an object's motion simply is position, direction, and speed.

The correct answer choice is option b.

Motion simply refers to the process which is concerned with changes a body or object makes with time in a function of speed, position and direction. In order words, the movement of a body with respect to time is what we call motion.

That being said, we usually describe motion in physics in different quantities such as

In conclusion, it can be deduced from all said and done above that motion changes an object or body with time.

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The resistance is directly proportional to the temperature. Then resistance of platinum at 100°C IS 2.5 Ω. Then, the when the resistance becomes 9.61 ohms is 384°C. Then, the resistance at 45°C is 1.1 ohms.

Resistance in a material is the hindrance to electric current. The resistance through a material depends on the electric voltage, temperature and current.

The resistance is directly proportional to the temperature.

then given R1/T1 = R2/T2

Given the resistance at 100 °C is 2.5 ohms .

R2 = 9.6 ohms

then, T2 = R2 T1/R2

T2 = (9.6 ohms × 100°C)/2.5 ohms = 384°C.

Then, the resistance at 45 degree Celsius is calculated as follows;

R2 = (2.5 ohms × 45)/100°C = 1.1 ohms.

Therefore, the resistance of platinum at 45°C is 1.1 ohms.

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Answer: overjustification

Explanation:

The overjustification effect is a situation that occurs when an incentive like prizes or money or prizes leads to the reduction in an individual's intrinsic motivation that is necessary in performing a task.

In this case, because the children are motivated by money, when the take doesn't involve money anymore, they may not be willing to do it.

The maximum stress in the wire is 2.0 × 10⁷ N/m², and  the minimum cross-sectional area of the wire is 1.0 × 10⁻¹ m² or 100 mm².

The maximum stress will be given by the formula:

stress = force/area

From Hooke's law, we know that stress is proportional to strain:

stress = Young's modulus × strain

Therefore, we can write:

Young's modulus × strain = force/area

Rearranging for stress, we get:

stress = (force/area) / strain

We are given that the strain must not exceed 4.0 × 10⁻⁴, and the force is 8.0 kN. We also know that the Young's modulus is 2.1 × 10¹¹ Pa. So we can substitute the values into the equation:

stress = (8.0 × 10³ N) / (area × 4.0 × 10⁻⁴)

= 2.0 × 10⁷ N/m²

We can rearrange the formula for stress to give:

area = force / (stress × strain)

Substituting the values we know, we get:

area = (8.0 × 10³ N) / (2.0 × 10⁷ N/m² × 4.0 × 10⁻⁴)

= 1.0 × 10⁻¹ m²

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Answer:

Formula

divide the pressure value by 100000

What is the definition of one pascal of pressure?

A pascal is a pressure of one newton per square metre, or, in SI base units, one kilogram per metre per second squared. ... For example, standard atmospheric pressure (or 1 atm) is defined as 101.325 kPa. The millibar, a unit of air pressure often used in meteorology, is equal to 100 Pa.

Answer:

its the lorry

Explanation:

The kinetic energy of the truck will be, 5625000 kg m/s and the kinetic energy of the bullet will be 156250 kg m/s. So the kinetic energy of the lorry will be higher than the kinetic energy of the Bullet.

Kinetic energy is a type of energy that a particle or an object possesses as a result of its motion. By exerting a net force on an item, work is done, which transfers energy; as a result, the object accelerates and obtains kinetic energy.

A moving item or particle's ability to move depends on both its mass and velocity. This is known as kinetic energy. Translation (or movement along a path from one location to another), rotation about an axis, vibration, or any combination of motions are examples of possible types of motion.

According to the question,

K.E of the lorry: 1/2 (4500)(50)²

K.E of the lorry = 5625000 kg m/s.

K.E of the bullet: 1/2(0.05)(250)²

K.E of the bullet = 156250 kg m/s

Hence, the kinetic energy of the lorry is greater than the kinetic energy of the bullet.

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Answer:

F = 1250000 N

Explanation:

If you have 50,000 S, by 25 M. It would be calculated to 1,250,000 N.

Answer: At several different levels, scientific awareness will enhance the quality of life, from the routine functioning of our daily lives to global issues. In energy, conservation, agriculture, health, transportation, communication, security, economics, recreation, and discovery, science informs public policy and personal decisions.

Explanation:

Hope This Helps! : )

Answer:

When several resistors are connected in series, the total resistance equals the sum of the individual resistors. In series combination, the current is same through each resistor.

1)   V=  60 volt

Total resistance R = R₁ + R₂

                              = 20 + 10

                              = 30 Ω

2) Ohms law states that,

           \(\sf I =\dfrac{V}{R}\\\\\\I = \dfrac{60}{30}\\\\I = 2 \ A\)

3) Voltage around 10 Ω resistor,

          V₂ = I R₂

             = 2 * 10

              = 20 volt

___________________________________________________

4) Total current = 1 A

5) Total voltage = 8 volt

6) Voltage around R₁ is V₁

              R₁ = 2 Ω  ; I = 1 A

              V₁ = IR₁

                   = 1 * 2

                   = 2 volt

7) Resistance 2:

        Total resistance = R

        Total voltage = V = 8 volt

        Total current = I = 1 A

                  \(\sf R = \dfrac{V}{I}\\\\\\ R = \dfrac{8}{1}\\\\\)

                  R = 8 Ω

               R₁ + R₂ = 8 Ω

                2 + R₂ = 8

                      R₂  = 8 - 2

                      R₂ = 6 Ω

8)Voltage around R₂:

                  \(\sf V_2 = IR_2\\\\V_2 = 1*6\\\\\)

                  V₂ = 6 volt

9) Total R = 8 Ω

_________________________________________________

10) Total V = 12 volt

11)  Total R = 8 + 8

                 = 16 Ω

12) Total current I,

                \(\sf I = \dfrac{V}{R}\\\\I = \dfrac{12}{16}\\\\I = 0.75 \ A\)

13) Voltage at each resistor:

           V₁ = I*R₁

               = 0.75 * 8

               = 6 volt

         V₂ = I*R₂

              = 0.75 * 8

             = 6 volt

_______________________________________________________

     14) Total R =   40 + 20

                       = 60 Ω  

15) To find V₁, first find total voltage.

           I = 2 A ;  R = 60 Ω  

           V = IR    

              = 2 * 60

               = 120 V

        V₁ + V₂  =V

        V₁ + 80 = 120

                V₁ = 120 - 80

                 V₁ = 40 volt              

If you are at latitude 59° north of the earth's equator, the angular distance from the northern horizon up to the north celestial pole will be 59 degrees.

The celestial pole is a star located at the Earth's poles. If you stand at any of Earth's poles, you will observe the North Stars directly overhead. The star is fixed in the sky's position; it neither rises nor sets. However, as you travel from the equator toward the pole, the angular distance between the star and the northern horizon increases.The angular distance from the northern horizon up to the north celestial pole is the observer's latitude. That means, for an observer located at a point of latitude 59 degrees N, the north celestial pole is 59 degrees above the horizon (the observer is in the Northern hemisphere).

Therefore, the angular distance from the northern horizon up to the north celestial pole is 59 degrees. This means that, if you stand at a point of latitude 59 degrees N, you will observe the north celestial pole 59 degrees above the northern horizon. This phenomenon happens because the Earth rotates on its axis, which makes the stars appear to rotate around the celestial pole.

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The force between a pair of cars in a train undergoing constant acceleration is much more significant compared to the forces between other cars in the same train.

The hypothesis on how the force between a pair of cars in a train undergoing constant acceleration compares to the forces between other cars in the same train is detailed below.

As the cars in a train undergo constant acceleration, the force between a pair of cars is more significant than the forces between other cars in the same train. This is due to the fact that as the acceleration increases, the force between a pair of cars increases because the car at the back is pushed forward while the car in front is pulling backward, and as a result, there is an increase in the force acting between the two cars.

                                    However, the forces between other cars in the same train are not as significant as the force between a pair of cars because there is no direct contact between them, and hence the force is much less. The greater the acceleration, the greater the force acting between a pair of cars in the train, while the force acting between other cars remains negligible.

Therefore, the force between a pair of cars in a train undergoing constant acceleration is much more significant compared to the forces between other cars in the same train.

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The force the magnetic field exerts on the particle is 0.072 N with velocity

Charge q = 8 μC is moving with a velocity v = [31 +43] x 106 m/s. If the charge enters a magnetic field B=0.4k T, then the magnitude of the magnetic force (in N) on the charge is given by

F = q x v x B

Given thatq = 8 μC

                   = 8 x 10-6 C

Velocity v = [31 +43] x 106 m/s

                = [31,000,000 + 43,000,000] m/s

                = [74,000,000] m/s

Magnetic field B = 0.4k T

                           = 0.4 x 103 T

TeslaSubstituting these values in the above equation, we get

F = (8 x 10-6) x (74 x 106) x (0.4 x 103)

F = 2.95 N

Therefore, the magnitude of the magnetic force (in N) on the charge is 2.95 N.

Another problem:

Given that a particle with a charge of 5.0 C travels at 2.0 m/s and encounters a magnetic field of 0.0100 T that makes an angle of 46.0 with respect to the x-axis in the xy-plane. We need to find the force the magnetic field exerts on the particle.

The force F on the particle is given by:

F = q x v x B x sin(θ)Where q is the charge of the particle, v is the velocity of the particle, B is the magnetic field and θ is the angle between the velocity of the particle and the magnetic field.

F = 5.0 C x 2.0 m/s x 0.0100 T x sin(46.0)

F = 0.072 N

Therefore, the force the magnetic field exerts on the particle is 0.072 N.

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The angular velocity of the coil is ω = 2.55\(rads^{-1}\).

Angular velocity is the rate at which an object rotates or rotates about an axis or the rate at which the angular displacement between two bodies changes. In the figure, this shift is represented by the angle θ between the line of one body and the line of the other body. The face area is calculated by multiplying the rib height by the fin length.

calculation:-

number of turns = 16

side length = 14 cm = 0.14 m

Magnetic field strength B = 0.040T

Emf produced = 34mV = 0.034 V

angular velocity = w×16× 0.14 ×0.034/0.040

= 2.55 m/ rad.

Face Velocity is the air velocity over the face of the coil. This angular rate describes how fast AC waveform cycles, and you should understand that a full cycle is equal to 2π radians. This does not necessarily represent the actual shaft speed of the alternator that produces AC power. There is an important relationship between angular velocity and frequency, given by the equation: Angular velocity is equal to frequency multiplied by the constant 2pi.

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The given object weighs 10 N on Earth's surface. We have to determine the weight of the same object on a planet that has one-tenth the Earth's mass and one-half the Earth's radius. The formula for weight is given by;W = mgWhere, W = Weight of the objectm = Mass of the objectg = Acceleration due to gravityFirst, let's find the value of g for the planet whose radius and mass are given.

The formula for g is given by;g = GM / r²Where, G = Gravitational constantM = Mass of the planetr = Radius of the planetFrom the given values, Mass of the planet = 1/10th of the Earth's mass = 5.97 x 10²⁴ / 10 = 5.97 x 10²³ kgRadius of the planet = 1/2 of the Earth's radius = 6.38 x 10⁶ / 2 = 3.19 x 10⁶ mSubstituting the given values in the formula;

g = GM / r²g = (6.67 x 10⁻¹¹) (5.97 x 10²³) / (3.19 x 10⁶)²g = 1.05 m/s²Now we can find the weight of the object on the given planet.W = mgW = 10 (1.05)W = 10.5 NTherefore, the weight of the given object on the planet that has one-tenth the Earth's mass and one-half the Earth's radius is 10.5 N.

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Answer:

 α = 2.13 10⁻⁵ C⁻¹    ,  the closest material is ALUMINUM

Explanation:

The expression for thermal expansion is

          ΔL = α L₀ ΔT

temperatures are

         ΔT = 85 - 10 = 75 ° C

the length of the rod is L₀ = 125 m and L_f = 125.20 m

        ΔL = 125.20 - 125 = 0.20 m

        α = \(\frac{1}{L_o} \frac{\Delta L }{\Delta T}\)

        α = \(\frac{ 1}{125} \ \frac{0.20 }{75}\)

        α = 2.13 10⁻⁵ C⁻¹

When reviewing the table, the closest material is ALUMINUM

Answer:

b.

Explanation:

-vesign shows the lens is CONCAVE

f=1/power

Asterisms are smaller, recognizable shapes formed by stars within a constellation or spanning multiple constellations. They can take the form of familiar objects or geometric shapes.

All stars within well-defined regions of the sky are members of constellations. These constellations are a way to organize and divide the celestial sphere into recognizable patterns.

The star in Taurus is designated Alpha Tauri, which means it is considered the brightest star in that particular constellation. Patterns of stars in the night sky are called asterisms.

Asterisms are smaller, recognizable shapes formed by stars within a constellation or spanning multiple constellations. They can take the form of familiar objects or geometric shapes.

While there are 88 official constellations recognized by the International Astronomical Union, there are countless asterisms that astronomers and stargazers observe and appreciate within these constellations.

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All stars within well-defined regions of the sky are members of constellations. The star in Taurus is designated Alpha Tauri. Patterns of stars in the night sky are called asterisms and are part of one or more constellations.

The International Astronomical Union (IAU) recognizes 88 constellations. These constellations are well-defined areas in the sky that contain groups of stars forming recognizable patterns. Some of the most famous constellations include Orion, Ursa Major (the Big Dipper), and Cassiopeia.

Asterisms, on the other hand, are smaller, distinct patterns formed by stars within a constellation or across multiple constellations. These patterns may be easily recognizable and have cultural or historical significance. For example, the Big Dipper is an asterism within the Ursa Major constellation.

In total, there are 15 asterisms that are officially recognized by the IAU. These include the Big Dipper, the Little Dipper, the Northern Cross, and the Summer Triangle.

Constellations and asterisms help astronomers navigate the night sky and locate specific celestial objects. They provide a way to organize and identify stars and other celestial bodies.

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Answer: Friction force

Happy To help ;)

Explanation:

Answer:

insulator

Explanation:

it keeps heat in not moves it

The far point of the eye is approximately 1.54 meters.

To find the far point of an eye follow these steps:

1. Determine the focal length of the lens: The optical power (P) of a lens is the inverse of its focal length (f) in meters. So, P = 1/f or f = 1/P.

2. Calculate the focal length: Given the optical power of -0.65 D, the focal length can be calculated as f = 1/-0.65 ≈ -1.54 meters. A negative sign indicates that the lens is a diverging lens, which is commonly prescribed for myopia or nearsightedness.

3. Find the far point: For a person with myopia, the far point is the distance at which they can see clearly without any corrective lenses. The far point can be found using the lens formula, which is 1/f = 1/u + 1/v, where 'f' is the focal length, 'u' is the object distance (distance of the object from the lens), and 'v' is the image distance (distance of the image formed from the lens).

Since the far point is the maximum distance at which the person can see clearly without corrective lenses, the image formed by the lens should be at infinity (v = ∞). So the formula becomes:

1/f = 1/u + 1/∞
1/f = 1/u

4. Calculate the object distance (u): Since we know the focal length (f), we can calculate the object distance (u) using the formula:

u = 1/(1/f) = 1/(1/-1.54) ≈ -1.54 meters

So, the far point of the eye is approximately 1.54 meters. Note that the negative sign indicates that the far point is a virtual point located behind the lens.

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False.With instability, rising air will be buoyant due to an uplifting force.

Instability in the atmosphere occurs when the environmental lapse rate (the rate at which temperature decreases with increasing altitude) is greater than the adiabatic lapse rate (the rate at which temperature decreases as air rises). This creates an environment where parcels of air that are warmer than the surrounding air can rise on their own, without the need for additional uplifting forces such as orographic lifting or frontal boundaries. The buoyancy of the rising air is driven by the temperature differences between the parcel and its surroundings. This buoyancy allows the air to continue rising until it reaches a level of stability or encounters other atmospheric conditions that hinder its upward motion.

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