A box full of charged plastic balls sits on a table. The electric force exerted on a ball near one upper corner of the box has components 1.2 x 10^-3 N directed north, 5.7 x 10^-4 N directed east and 2.2 x 10^-4 N directed vertically upward. The charge on this ball is 110 nC.
If this ball were replaced with one that has a charge of -50nC , what would be the force components exerted one the replacement ball?
F north=?
F east=?
F up=?
Answers
We have that the values for F north, F east, F up are
\(F_N=1.09090909*10^{-5}\)\(F_E=5.18181818*10^{-6}\)\(F_E=2*10^{-6}\)
From the Question we are told that
electric force \(F_1 = 1.2 x 10^{-3} N(N)\)
electric force , \(F_2=5.7 x 10^{-4} N(E)\)
electric force , \(F_3=2.2 x 10^{-4} N (U)\)
charge on this ball one \(q_1= 110 nC.\)
charge on this ball two \(q_2= -50 nC.\)
Generally the equation for the F north is mathematically given as
\(F_N=\frac{F_1}{q_1}\\\\F_N=\frac{ 1.2 * 10^{-3} )}{110}\)
\(F_N=1.09090909*10^{-5}\)
For F East
\(F_E=\frac{F_2}{q_1}\\\\F_E=\frac{5.7 x 10^-4 }{110}\)
\(F_E=5.18181818*10^{-6}\)
For F UP
\(F_U=\frac{F_3}{q_1}\\\\F_U=\frac{2.2 x 10^-4 }{110}\)
\(F_E=2*10^{-6}\)
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Related Questions
which of the following best describes pseudoscience?
Answers
Answer:
The answer is A
Explanation:
Answer:
implausible or untestable scientific claims
An air puck of mass m1 = 0.21 kg is tied to a string and allowed to revolve in a circle of radius R = 0.9 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass of m2 = 1.0 kg is tied to it (see the figure below). The suspended mass remains in equilibrium while the puck on the tabletop revolves.
Answers
The speed of the puck is 3.67 m/s.
To find the speed of the puck, we can use the concept of centripetal force. The tension in the string provides the necessary centripetal force to keep the puck moving in a circle. At the same time, the tension in the string also supports the weight of the suspended mass.
Using Newton's second law, we can write two equations of motion: one for the puck and one for the suspended mass. For the puck, the net force acting on it is the tension in the string, which is equal to the centripetal force required to keep it moving in a circle. Thus, we can write:
= m1 * v^2 / R
where T is the tension in the string, v is the speed of the puck, and R is the radius of the circle.
For the suspended mass, the net force acting on it is its weight minus the tension in the string, which must be zero since the mass is in equilibrium. Thus, we can write:
T = m2 * g
where g is the acceleration due to gravity.
Combining these two equations, we can solve for the speed of the puck:
v = sqrt(T * R / m1) = sqrt(m2 * g * R / m1)
Substituting the given values, we get:
v = sqrt(1.0 kg * 9.81 m/s^2 * 0.9 m / 0.21 kg) = 3.67 m/s
Therefore, the speed of the puck is 3.67 m/s.
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Select the correct answer.
Which of Newton's laws explains why your hands get red when you press them hard against a wall?
ОА.
Newton's law of gravity
OB.
Newton's first law of motion
O c.
Newton's second law of motion
OD.
Newton's third law of motion
Answers
Answer:
D. Newton's third law of motion
Chemical A and Chemical B react in an exothermic reaction. What can be known about what will happen when Chemical A and Chemical B are mixed together?
The old substance will need more energy to break its chemical bonds than the new substance will release.
More energy will be released from the old substance than the new substance will release to form its chemical bonds.
The color will change as a result of the reaction.
The substance will bubble as a result of the reaction.
Answers
In an exothermic reaction, more energy will be liberated from the old substance than the new substance will liberate to form its chemical bonds. Therefore, option B is correct.
What is an exothermic process?An exothermic process can be described as a thermodynamic reaction that emits energy from the system to the surrounding in the form of heat, light, or sound.
In chemical reactions, the bond energy is converted into thermal energy. In exothermic reactions, the reaction takes place in the form of the kinetic energy of molecules. The electronic transition of electrons from one energy level to another leads light to be released.
The energy of the reactants is more than the energy of the products in the exothermic reaction. The energy liberated by reactants will be more than the energy required for the new bonds to be formed in the products.
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How many phase conductors are installed between the switch and the light fixture shown in the figure? A. Four
B. Three
C. Two
D. Five
Answers
Answer:
TWO
Explanation:
Compare the rate of loss of heat from a metal sphere at 827°C with the rate of loss of heat from the same sphere at 427°C,if the temperature of the surrounding is 27°C
Answers
Answer:
The rate of heat loss from the metal sphere at 827°C is twice the rate of heat loss from the same sphere at 427°C.
Explanation:
The rate of heat loss from an object can be determined using Newton's law of cooling, which states that the rate of heat loss is proportional to the temperature difference between the object and its surroundings. Mathematically, this is expressed as...
\(Q = k \Delta T\)
Where...
"Q" is the heat loss/gain"k" is the constant of proportionality which is the cooling constant "ΔT" is the change in temperature\(\hrulefill\)
For the sphere at 827°C:
\(\Delta T_1= 827\°C - 27\°C \\\\\Longrightarrow \boxed{\Delta T_1=800\°C}\)
For the sphere at 427°C:
\(\Delta T_2= 427\°C - 27\°C \\\\\Longrightarrow \boxed{\Delta T_2=400\°C}\)
Assuming that the cooling constant k remains constant, we can compare the rates of heat loss.
\(\dfrac{Q_1}{Q_2} =\dfrac{\Delta T_1}{\Delta T_2}\\\\\Longrightarrow \dfrac{Q_1}{Q_2} =\dfrac{800\textdegree C}{400\textdegree C} =\boxed{2}\)
Thus, the rate of heat loss from the metal sphere at 827°C is twice the rate of heat loss from the same sphere at 427°C when the temperature of the surroundings is 27°C.
Which choice has the least thermal energy?
A swimming pool full of cool water
b all the water in Earth's oceans
C cup of hot cocoa
d bathtub full of warm water
Answers
Answer:it’s c a cup of hot cocoa
Explanation:
Answer:
c, cup of hot cocoa
Explanation:
it might seem like the hot cocoa is the hottest, but because the substance is so small, it has the least thermal energy
A projectile is launched with an initial velocity of 60.0 m/s at an angle of 30.0° above the horizontal. How far does it travel?
A) 152 m
B) 160 m
C) 184 m
D) 318 m
Answers
Answer:
D
Explanation:
The range is how far the projectile can go;
R = U^2sin2A/g
Where U is the initial velocity
A is the angle of inclination
=60^2sin2(30)/10 = 3600 sin60 / 10
= 311.8m
The exact answer should 312m
A projectile is launched with an initial velocity of 60.0 m/s at an angle of 30.0° above the horizontal it travel 312m.
What is velocity?When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
The range is how far the projectile can go;
R = U^2sin2A/g
Where U is the initial velocity
A is the angle of inclination
=60^2sin2(30)/10 = 3600 sin60 / 10
= 311.8m
A projectile is launched with an initial velocity of 60.0 m/s at an angle of 30.0° above the horizontal it travel 312m.
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An athlete exerts 3000 W of power when he takes 10.2 s to run the race. How much WORK does the athlete do?
Answers
Answer:
30600 J
Explanation:
Work = Power* Time
=30600 J
What kinds of materials generally have the lowest specific heats?
Answers
Answer:
Iron and lead generally have low specific heats.
A boy throws a ball straight up into the air. It reaches the highest point of its flight after 4 seconds. How fast was the ball going when it left the boy's hand?
Answers
The ball's exit velocity from the boy's hand was 39.4 m/s.
The time it took the ball to reach its highest point is 4 seconds, which is the explanation.
Use the first equation of motion, v = u + gt, to determine the ball's initial velocity when it left the boy's hand.
Initial velocity (v) is used here. terminal velocity is u. t is the amount of time, and g is the gravitational acceleration, with a value of 9.8 m/s2.
At its highest point, the ball's final velocity, v, equals zero.
When the supplied values are substituted in the equation above, we get 0=u-9.8m/s2.
Therefore, the ball's exit velocity from the boy's hand was 39.4 m/s.
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A 1200 kg car moving +13.7 m/s makes
an elastic collision with a 3200 kg truck,
initially at rest. What is the velocity of the
car after the collision?
(Unit = m/s)
Remember: right is +, left is -
Answers
When a car collides with another object, the total momentum of the system before and after the collision must be conserved. Momentum, on the other hand, is a product of mass and velocity. To find the velocity of a car after a collision, we must first consider the initial momentum of the system before the collision and compare it to the final momentum after the collision.
The total momentum of the system before the collision is calculated as follows:P_initial = m_car x v_carP_initial = 1200 kg x 13.7 m/sP_initial = 16,440 kg*m/s Since the two cars stick together after the collision, their final velocity is the same. Let's suppose the final velocity of the cars after the collision is v_f. Then:P_final = (m_car + m_obstacle) x v_fwhere m_obstacle is the mass of the object the car collided with. Because the car is at rest after the collision, we can assume that the velocity of the object it collided with is zero. Therefore:P_final = m_car x v_fP_final = 1200 kg x v_fThe momentum of the system after the collision must be equal to the momentum of the system before the collision. That means:P_initial = P_final16,440 kg*m/s = 1200 kg x v_fv_f = 13.7 m/s - (16,440 kg*m/s / 1200 kg) v_f = 13.7 m/s - 13.7 m/s v_f = 0 m/sTherefore, the car will come to a stop after the collision.For such more question on velocity
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A uniform solid cylindrical flywheel has a mass of 50 kg and a radius of 40 cm. The flywheel begins to rotate faster with an acceleration of 1.5 rad/s2. The kinetic energy of the flywheel after 1 minute of rotation is:
A. 16.2 KJ
B. 180 KJ
C. 40.5 KJ
D. 32.4 KJ
Answers
The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)
How do I determine the kinetic energy?We'll begin by obtaining the velocity of the flywheel. This is shown below:
Radius (r) = 40 cm = 40 / 100 = 0.4 mAcceleration (a) = 1.5 rad/s² = 1.5 × 0.4 = 0.6 m/s²Time (t) = 1 minute = 1 × 60 = 60 sVelocity (v) = ?v = at
v = 0.6 × 60
v = 36 m/s
Finally, we shall determine the kinetic energy of the flywheel. Details below:
Mass (m) = 50 KgVelocity (v) = 36 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 50 × 36²
KE = 25 × 1296
KE = 32400 J
Divide by 1000 to express in KJ
KE = 32400 / 1000
KE = 32.4 KJ
Thus, the kinetic energy is 32.4 KJ (Option D)
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Plz help The momentum of a baseball changes dramatically when struck by a bat.Momentum of the ball is not conserved. The best explanation for this is that
Answers
Answer:
The answer is C the ball is not in a closed system and experience an impulse.
Explanation:
What is TRUE about the use of drawings at a crime scene?
O A. Drawings are no longer used because photography is more precise.
OB. Only when a camera is not immediately available should a sketch be made.
O c.
It is common practice for investigators to make a sketch of a crime scene.
OD. Investigators are trained in how to make a quality finished sketch of a scene.
Answers
Answer:
A. Drawings are no longer used because photography is more precise.
Explanation:
It is common practice for investigators to make a sketch of a crime scene.
Creating sketches of crime scenes is a common practice among investigators, as it provides valuable visual documentation that complements photographs and written notes. While photography is an important tool for capturing detailed and precise information, sketches offer unique advantages that contribute to the overall understanding of the crime scene.
Sketches can provide a clear and organized representation of the spatial relationships, distances, and dimensions within the crime scene. They can accurately depict the layout of the area, the position of evidence, the location of key objects, and other relevant details that may not be fully captured by photographs alone.
Additionally, sketches allow investigators to emphasize specific features or elements that are essential to the case. This can aid in explaining the sequence of events, the movement of individuals or objects, and other dynamic aspects of the crime scene.
While digital photography is widely used today, sketches remain valuable for scenarios where a camera may not immediately be available, when capturing certain angles or perspectives is challenging, or when highlighting specific details is necessary.
Investigators are trained in creating accurate and detailed sketches that adhere to professional standards. This includes ensuring accurate measurements, using appropriate scale ratios, labeling key features, and maintaining object proportions. Sketched crime scene diagrams are often included in official investigative reports and court proceedings to provide a comprehensive visual representation of the crime scene, enhancing the communication of information among investigators, legal professionals, and jurors.
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In a double-slit arrangement the slits are separated by a distance equal to 150 times the wavelength of the light passing through the slits. (a) What is the angular separation between the central maximum and an adjacent maximum
Answers
Complete Question
In a double-slit arrangement the slits are separated by a distance equal to 150 times the wavelength of the light passing through the slits. (a) What is the angular separation between the central maximum and an adjacent maximum? (b) What is the distance between these maxima on a screen 57.9 cm from the slits?
Answer:
a
\(\theta = 0.3819^o\)
b
\(y = 0.00386 \ m\)
Explanation:
From the question we are told that
The slit separation is \(d = 150 \lambda\)
The distance from the screen is \(D = 57.9 \ cm = 0.579 \ m\)
Generally the condition for constructive interference is mathematically represented as
\(dsin (\theta ) = n * \lambda\)
=> \(\theta = sin ^{-1} [\frac{n * \lambda }{ d } ]\)
where n is the order of the maxima and value is 1 because we are considering the central maximum and an adjacent maximum
and \(\lambda\) is the wavelength of the light
So
\(\theta = sin ^{-1} [\frac{ 1 * \lambda }{ 150 \lambda } ]\)
\(\theta = 0.3819^o\)
Generally the distance between the maxima is mathematically represented as
\(y = D tan (\theta )\)
=> \(y = 0.579 tan (0.3819 )\)
=> \(y = 0.00386 \ m\)
During the race competitors work against air resistance.
The work done against air resistance by the winner of the race was 3 360 000 J
Calculate the average air resistance acting on the winner of the race.
Answers
To calculate the average air resistance acting on the winner of the race, we need to use the formula:
Work = Force * Distance
In this case, the work done against air resistance is given as 3,360,000 J. However, we do not have the distance traveled or the time taken to complete the race.
Without knowing the distance or time, it is not possible to calculate the average air resistance. Additional information, such as the speed or any other relevant data, would be required to determine the average air resistance.
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Your question is incomplete, but your full question can be:
During the race competitors work against air resistance. The work done against air resistance by the winner of the race was 3,360,000 J. Calculate the average air resistance acting on the winner of the race.
i forgot to add the number before
it’s 75 for the water
Answers
Answer:
Explain
Explanation:
A bus took 8 hours to travel 639 km. For the first 5 hours, it
travelled at an average speed of 72 km/h. What was the
average speed for the remaining time of the journey?
Answers
Answer:
93
Explanation:
A stone whirled at the end of a rope 30cm long makes 5revs. Find the linear speed?
Answers
The stone moves at a linear speed of 9.42 m/s.
How is linear velocity determined?Where v stands for speed, d for distance, and t for time, the equation for linear velocity is v = d/t. The SI unit for linear velocity is the metre per second, abbreviated as m/s (ms-1).
The circumference of the circle the stone traces and the distance the stone travels in one revolution are equal.
C = 2πr
where r is the rope's length. If we substitute r = 30 cm, we obtain:
C = 2π(30 cm) ≈ 188.5 cm
As a result, one revolution of the stone moves it approximately 188.5 cm.
The stone moves a total of five times, covering the following distance:
d = 5(188.5 cm) = 942.5 cm
v = d/t
Let's say the stone makes 5 revolutions in t seconds. The linear speed is then:
v = d/t = 942.5 cm/t
To obtain the answer in milliseconds, we can convert the quantities to metres and seconds:
v = 9.425 m/t
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Mary and Sally are in a foot race (see the figure). When Mary is 22 m m from the finish line, she has a speed of 4.0 m/s m / s and is 5.0 m m behind Sally, who has a speed of 5.0 m/s m / s . Sally thinks she has an easy win and so, during the remaining portion of the race, decelerates at a constant rate of 0.32 m/s2 m / s 2 to the finish line. (Figure 1) Figure1 of 1 Part A What constant acceleration does Mary now need during the remaining portion of the race, if she wishes to cross the finish line side-by-side with Sally?
Answers
The rate at which velocity decreases with respect to time is known as deceleration.
Initially moving at 5 m/s
Initially, Mary was moving at 4 m/s.
Sally's acceleration is -0.4 m/s2.
Mary's acceleration should be a.
Sally is (22-5) meters away from the goal.
22-5= 5t+1/2 is the result of applying the second equation of motion to the remaining portion of Sally's race (-0.4)
²
The inverse of the aforementioned equation is 0.2t2-5t+17=0.
You obtain t= 20.4s by solving the quadratic equation above.
Consider the lower amount since the larger value represents the period of time during which Sally continues to slow down and returns to the finish line.
As a result, Sally finished the last leg of the race in 4.06 seconds.
Mary needs to finish the final 22 meters of the race in 4.06 seconds in order for Sally and she to cross the finish line simultaneously.
22= V mt+ 1/2at2 is derived from the second equation of motion.
calculating a= 0.70 m/s2
Mary should therefore accelerate at 0.70 m/s2.
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If your mass is 72 kg, your textbook's mass is 3.7 kg, and you and your
textbook are separated by a distance of 0.33 m, what is the gravitational
force between you and your textbook? Newton's law of gravitation is
Gm;m2 The gravitational constant G is 6.67 x 10-11 N·m2/kg2.
F gravity
O A. 4.94 x 10-7N
B. 2.45 x 103 N
O C. 5.38 x 10-8N
O D. 1.63 x 10-7N
Answers
Answer:
The answer is 1.63 x 10 -7 N
Explanation:
An appropriate solution is 1.63 x 10 -7 N
Gravitational pressure method: F=G{frac{m_1m_2}{r^2}}
Newton's law of gravitation is Gm;m2
The gravitational regular G is 6.67 x 10-11 N·m2/kg2.
What is gravitational pressure?
Definitions of gravitational pressure. The force of attraction among all masses inside the universe; especially the appeal of the earth's mass for bodies close to its floor.
What law is Newton's regulation of gravitation?Newton's regulation of typical gravitation states that two bodies in an area pull on every other with a force proportional to their hundreds and the space among them. For large objects orbiting each other—the moon and Earth, for instance—means they without a doubt exert important force on each other.
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How is the acceleration of a falling object calculated
Answers
Answer:
F=w=ma OR by using equations of motions vf=vi-at : a=vf-vi/t eq 1 s=vit+1/2at squre eq 2 2as=vf squre - vi squre eq 3
Explanation:
where m is the mass of falling body , f is the weight is the force acting down ward , vf is the final velocity, vi is the inetial velocity , t is the time and s is the distance covered by a body.
No matter how far you stand from a mirror, your image appears erect. The mirror
may be:
a) plane
b) concave
c) convex
d) both a) and c).
Answers
Answer:
The answer to this question is option “d” that is either plane or convex.
Explanation:
The mirror can be either a plane mirror or a convex mirror, it cannot be concave.
In a convex mirror, one will always get the virtual size and smaller erect images of the objects seen reflected on it.
In a plain mirror, one can see the real size.
Answer:
d
Explanation:
plan and convex mirrors make ur image to be erect but concave is based on the object distance but the image will erect focal length and pole, have a great day!!!
If a spring extends by 3 cm when a 4 N weight is suspended from it, find the extension
when the weight is changed to
(a) 8 N
(b) 10 N
(c) 14
Answers
B - 7.5cm
C - 10.5cm
Describe what causes the planets to stay in orbit around the Sun
Answers
Answer:
Gravitional pull or gravity
Explanation:
Its that simple
The force required to pull the cork out of the top of a wine bottle is in the range of 220 to 380 N . What range of forces F is required to open a wine bottle with the bottle opener shown in (Figure 1)
Answers
The ranges of forces required to open a wine bottle with bottle opener as per shown in the figure is 25.1 N to 45.57 N
What is Force?In physics, a strain is an effect with the ability to alter the velocity of an object. A force can influence a surplus object's velocity to alter or rise. To describe force, a pushing or a pulling makes intuitive sense. Forces have both size and direction, since they are vector quantities. It is measured in newtons using the SI system (N). The symbol for force is the letter F.
Balancing moment (r x F) about left end:
Net torque = (9 mm x F(cork) - ((9 + 70) F) = 0
F = ( 9 / 79) F(cork)
F = 0.114 F(cork)
Range of F(cork) = 220 N to 400 N
F = [0.114(220) to 0.114(400)] = 25.1 N to 45.57 N
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explanations for energy transformations within a system of chemical energy of ice skating
Answers
During ice skating, there are several energy transformations that occur within the system, involving the chemical energy stored in the body and its conversion into other forms of energy.
The skater's body possesses chemical energy stored in the form of carbohydrates and fats obtained from food. This chemical energy is converted into mechanical energy as the skater's muscles contract and generate force to propel themselves forward on the ice. The chemical bonds in the molecules of carbohydrates and fats are broken, releasing energy that powers muscular movement.
As the skater glides on the ice, friction comes into play. The mechanical energy of the skater is transformed into thermal energy due to the interaction between the skate blades and the ice surface. Some of the mechanical energy is dissipated as heat due to friction, causing the ice to melt slightly beneath the blades.
This thermal energy contributes to the increase in the temperature of the ice and the surrounding environment. There may be sound energy produced as the skate blades interact with the ice. When the skater pushes off the ice or performs certain movements, vibrations are created, leading to the emission of sound waves.
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mass=8 kg ,spring constant= 200 N/m , length of spring= 3 cm , Vi=0 What is the velocity when the displacement is 2 and when -1.5?
Answers
Answer:
Therefore, the velocity of the mass when the displacement is -1.5 cm is 0.121 m/s.
Explanation:
To calculate the velocity of the mass attached to a spring with the given parameters, we can use the principle of conservation of energy. At the maximum displacement (2 cm), all the potential energy stored in the spring is converted into kinetic energy of the mass. Therefore, we can write:
1/2 * m * v^2 = 1/2 * k * x^2
where m is the mass of the object, v is the velocity of the object, k is the spring constant, and x is the displacement of the mass from the equilibrium position.
Substituting the given values, we get:
1/2 * 8 kg * v^2 = 1/2 * 200 N/m * (0.02 m)^2
Solving for v, we get:
v = sqrt((0.02 m)^2 * 200 N/m / 8 kg) = 0.2 m/s
Therefore, the velocity of the mass when the displacement is 2 cm is 0.2 m/s.
Similarly, at a displacement of -1.5 cm, we can use the same equation to calculate the velocity:
1/2 * 8 kg * v^2 = 1/2 * 200 N/m * (-0.015 m)^2
Solving for v, we get:
v = sqrt((-0.015 m)^2 * 200 N/m / 8 kg) = 0.121 m/s (rounded to three decimal places)
which one is odd copper,plastic,rubber
Answers
Answer:
It's plastic.
trust me it's plastic, i've rad it somewhere.
All of them have something that's not like the others.
-- Rubber is the only one on the list that has two repeated letters.
-- Plastic is the only one on the list thagt has no repeated letters.
-- Plastic is the only one on the list that has no 'r' in its name.
-- Copper is the only one on the list that is an element, not a compound.
-- Copper is the only good electrical conductor on the list.
-- Plastic is the only one on the list with more than six letters in its name.
-- Rubber is the only one on the list with no 'p' in its name.
-- Plastic is the only one on the list that doesn't end in "-er".